analisis pondasi pbrs
TRANSCRIPT
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ANALISIS PONDASI
Desain Pondasi Cerucuk
Tipe Pondasi :1) Tipe A ( 1,4,13,16)) Tipe ! (,3,",#,$,1,14,1")3) Tipe C (6,%,1&,11)
Dari 'asi oupu *oin reaksi
diperoe' :
Pondasi Tipe A
Kedalamaan tiang (df ) = 3,4 m
Hasil Data sondir :
Nilai qc = 4D di!a"a# tiang, $arena dipancang sedalam
tana# $eras ma$a diam!il qc pada $edalaman pancang
Niai +c1 (4D dia-a' ian. )
Kedalaman
(m)
Nilai $on%s (&)
($g'cm) 3,4
/enis P (k.) 0(k.2)
0(k.2)
A *++,*3
43-,*
3-,
. /-,3
4+-,/3
4**,4+
& +,+
4**, 4/,-
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0ata 1 rata nilai
$on%s
Nilai qc = + 2 D = + 2 + = *4 cm
Tae 1&2 Niai +c (#D diaas ian. )
Kedalaman
(m)
Nilai $on%s (&)
($g'cm)3,4 3, 3 +
,+ 4* -
0ata 1 rata nilai$on%s /
Nilai qc (qc qc)' = *3,- $g'cm
Nilai 5HP = $g'cm
Diameter tiang pancang (D) = + cm
6%as tiang = 7 8 34 8 D
= -*-4 cm
Keliling tiang pancang (K) = 3,4 2 D
= 3,4 2 + = -,3 cm
.erat tiang = 6%as 8 d 8 γ
= -,*-4 cm 8 3,4 cm 8
$g'cm3
= /, $g
As%msi !erat poer plat ( 9) = 8 *4+/3 $g
= *4+,/3 $g
Ptotal = P .erat tiang .erat poer
plat
= (*++,*3 /,
*+,+*) $g
= /-3-,* $g
= /-,3-* ton
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a) Per'iun.an daa dukun. pondasi sau ian.K%at End Bearing ' %%ng tiang (;P)
;% =(0,25× π × D2 )×(qc )
3 8
K x JHP5
=(0,25×π ×82 )×(163,5)
3 x 25,13 x200
5=¿ 3/44,//
$g = 3,/4- ton
) Per'iun.an kapasias ian. .rup
Data 1 data perencanaan tiang gr%p
Direncana$an tiang gr%p dengan $oneng#it%ng !e!an ma$sim%m tiang pada $elompo$ tiang
Pma8 =
P
n
My x X max
n y x X 2
Mx x y max
n x x y2
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8ma8 = ,- m
?ma8 = ,3 m
Σ 8 = (4 8 8 ,-) (4 8 8 ,3) (4 8 8 ,) = ,+ m
Σ ? = (* 8 8 ,3) (* 8 8 ,) = ,4 m
P = /-, 3-* $g
>8 = 4,3-* tonm
>? = 3,-3 tonm
Pma8 = P
n My x X max
n y x X 2
Mx x y max
n x x y2
Pma8 =75,0356
24 4,3526 x0,5
4 x2,8 3,9539 x 0,3
6 x 1,4
Pma8 = 3,4-+ ton
.e!an ?ang diterima tiang ma$sim%m = 3,4-+ ton @ da?a
d%$%ng tiang
;%lt = n 8 ;iin 8
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>enent%$an Te!al Poer Plat- As%msi te!al poer plat (#t) = mm- Te!al efe$tif poer plat (d) = #t 1 d
= 1 /-= - mm
->enent%$an $eliling penampang $ritis (!o):!o = 4 (#c d)
= 4 ( 4 -)= -3
- A$si geser d%a ara#:
>enent%$an nilai ФVc :
!c =hc
bc =
400
400=1
• c =1
6
(1+
2
bc
)√ f c
' . bo . d
=1
6 (1+ 21 )√ 25 5300 -= -*,- $N
• c =1
12 ( α . dbo +2)√ f c'
.bo . d
Dimana E= 3
=1
12 ( 30 x 9255300 +2)√ 25 5300 -= 4/+,/3 $N
• c3= 0,33√ f c' .bo .d
= 0,33√ 25 5300 -
= ++,- $N
Diam!il nilai c ter$ecil = ++,- $N
ФVc : = ,* 8 ++,- = 4+-3,4/- $N
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>enent%$an T%langan Pile &ap Ara# F:
>omen
d8 = #t 1 ds 1 G Dt
= 1 /- G -
= ,- mm
= ,- m
d8 1 ,- !c d
,- 1 ,-4 - mm
/,- mm - mm
>% = 3- Nmm
>omen Nominal
>n = M u
Ф =39529100
0,8=¿ 443/- Nmm
3 0asio T%langan >inim%m
ρmin=1,4
fy =
1,4
270=¿ ,-
4 0asio T%langan ma$sim%m ρmaks = ,/- ρb
ρmaks
= ,/-
+⋅
⋅⋅
)600(
600'85,0 1
fy fy
fc β
= ,34*
- Koefesien $eta#anan
Rn = Mn
b .d2=
49411375
1200 x 9252 = ,4+ N'mm
* 0asio t%langan perl%
)f 0,85.
21(1
'.85,0'
c
n
perlu
R
fy
fc−−= ρ
= ,/+44
perl u ρ
@ ρmin
ma$a dipa$ai ρ=0,0052
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/ 6%as T%langan perl% (As)
As = I!d8
=,- ,-
= -/--,--* mm
Dico!a t%langan D = - mm
%mla# t%langan ?ang dipa$ai:
n = s !"#$u
s%u$
=5755,556
490,8734=12 !%a#
s %u$an&an = n (
s %u$¿
= -+,4+ mm
J?arat : s %u$an&an s !"#$u
-+,4+3 mm -/--,--* mm CCC
Aman
+ 5ara$ t%langan %tama(s)
s =
s%u$ .
s !"#$u
=490,8734 .1200
5755,556
= 3,/ mm
Diam!il ara$ t%langan J = mm
ce$ ara$ antar t%langan:
J @ - mm
@ - mm CC Aman
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Ta!el P total
TipePondasi
As%msiPoer plat
($g)
P total(ton)
A *+,+*3/-,3-
-+
. /,-3,3
+
& +,//,
-+
Ta!el Kapasitas
TipePondasi
P total 5%mla
#tiang
Pma$s
; %lt Ket
Tipe A/-,3-
-+4 3,4-+
+,+/4*
L$
Tipe . ,3+
3 3,* ,3433
L$
Tipe &,
-+3* 3,--/
34,+
L$
Ta!el Dimensi pilecap
TipePondasi p(m) l (m)
A , ,+
. , & , ,
Ta!el Titi$ pondasi
TipePondasi
.an?a$titi$
P >8 >?
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A 4*++,
*343-,
*3-,
. +/-,
34+-,
/34**,
4+
& 4+
,+
4**,
4/,
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Ta!el Hasil per#it%ngan Pen%langan Pilecap
Tipe Pondasi Te!alPilecap
T%langandipa$ai
A D-
. D-
& D-