analisis difraksi sinar-x (x-ray diffraction...
TRANSCRIPT
![Page 1: Analisis Difraksi Sinar-X (X-Ray Diffraction Analysis)file.upi.edu/.../Bab_3_Teknik_Diffraksi_XRD.pdfAnalisis Difraksi Sinar-X (X-Ray Diffraction Analysis) Crystal Structure Ideal](https://reader031.vdocuments.site/reader031/viewer/2022021512/5af7089e7f8b9a4d4d91356b/html5/thumbnails/1.jpg)
Analisis Difraksi Sinar-X
(X-Ray Diffraction Analysis)
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Crystal Structure
Ideal Crystal: Mengandung susunan atom/ion secara periodik
Direpresentasikan oleh titik kisi
Sekelompok atoms yang membentuk titik kisi
Basis
LATTICE = Kisi susunan titik dalam ruang yang memiliki lingkungan
identik antara satu dengan lainnya
CRYSTAL STRUCTURE = Susunan atom (kelompok atom) yang
berulang .
It can be described by associating with each lattice point a group of
atoms called the MOTIF (BASIS)
Reading: Ashcroft 4-7
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{R = n1 a1 + n2 a2 + n3 a3}
Translational
vector
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Primitive Cell: simplest cell, contain one lattice point
Not necessary have the crystal symmetry
UNIT CELL = The smallest component of the crystal, which when
stacked together with pure translational repetition reproduces the
whole crystal
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Conventional cell vs. Primitive Cell
Reflecting the symmetry
Different Basis
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5 Kisi Bravais dalam 2D
P P NP
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Square a=b =90
Rectangular a b =90
Centered
Rectangular
a b =90
Hexagonal a=b =120
Oblique a b 90
5 Kisi Bravais dalam 2D
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Translational
vector
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Definition:
Bravais Lattice: an infinite array of discrete points with an
arrangement and orientation that appears exactly the same from
whichever of the points the array is viewed.
Name Number of Bravais lattices Conditions
Triclinic 1 (P) a1 a2 a3
Monoclinic 2 (P, C) a1 a2 a3
= = 90
Orthorhombic 4 (P, F, I, A) a1 a2 a3
= = = 90
Tetragonal 2 (P, I) a1 = a2 a3
= = = 90
Cubic 3 (P, F, I) a1 = a2 = a3
= = = 90
Trigonal 1 (P) a1 = a2 = a3
= = < 120 90
Hexagonal 1 (P) a1 = a2 a3
= = 90
= 120
3D: 14 Bravais Lattice, 7 Crystal System
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Kisi FCC
Logam Cu memiliki kisi face-centered cubic
Atom-atom identik terletak pada sudut dan pada bagian muka kisi
Jenis Kisi adalah type F
also Ag, Au, Al, Ni...
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BCC Lattice
-Fe merupakan sebuah kisi body-centered cubic
Atom-atom Identik terletak pada sudut dan body center (nothing at face centers)
Lattice type I
Also Nb, Ta, Ba, Mo...
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Simple Cubic Lattice
Caesium Chloride (CsCl) is primitive cubic
Different atoms at corners and body center. NOT body centered, therefore.
Lattice type P
Also CuZn, CsBr, LiAg
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FCC Lattices
Sodium Chloride (NaCl) - Na is much smaller than Cs
Face Centered Cubic
Rocksalt structure
Lattice type F
Also NaF, KBr, MgO….
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Diamond Structure: two sets of FCC Lattices
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One 4-fold axes
Why not F tetragonal?
Tetragonal: P, I
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Example
CaC2 - has a rocksalt-like structure but with
non-spherical carbides
2-C
C
Carbide ions are
aligned parallel to c
c > a,b
tetragonal symmetry
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Orthorhombic: P, I, F, C
C F
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Another type of centering
Side centered unit cell
Notation:
A-centered if atom in bc plane
B-centered if atom in ac plane
C-centered if atom in ab
plane
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Unit cell contentsCounting the number of atoms within the unit cell
Many atoms are shared between unit cells
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Atoms Shared Between: Each atom counts:
corner 8 cells 1/8
face center 2 cells 1/2
body center 1 cell 1
edge center 4 cells 1/4
lattice type cell contents
P 1 [=8 x 1/8]
I 2 [=(8 x 1/8) + (1 x 1)]
F 4 [=(8 x 1/8) + (6 x 1/2)]
C 2 [=(8 x 1/8) + (2 x 1/2)]
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e.g. NaCl
Na at corners: (8 1/8) = 1 Na at face centres (6 1/2) = 3
Cl at edge centres (12 1/4) = 3 Cl at body centre = 1
Unit cell contents are 4(Na+Cl-)
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(0,0,0)
(0, ½, ½)
(½, ½, 0)
(½, 0, ½)
Fractional Coordinates
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Cs (0,0,0)
Cl (½, ½, ½)
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Density Calculation
AC NV
nA
n: number of atoms/unit cell
A: atomic mass
VC: volume of the unit cell
NA: Avogadro’s number
(6.023x1023 atoms/mole)
Calculate the density of copper.
RCu =0.128nm, Crystal structure: FCC, ACu= 63.5 g/mole
n = 4 atoms/cell, 333 216)22( RRaVC
3
2338/89.8
]10023.6)1028.1(216[
)5.63)(4(cmg
8.94 g/cm3 in the literature
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Crystallographic Directions And Planes
Lattice Directions
Individual directions: [uvw]
Symmetry-related directions: <uvw>
Miller Indices:
1. Find the intercepts on the axes in terms of the lattice
constant a, b, c
2. Take the reciprocals of these numbers, reduce to the
three integers having the same ratio
(hkl)
Set of symmetry-related planes: {hkl}
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Crystal Structures [OGN 21.2]• Body-centered cubic
(BCC)
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(100) (111)
(200) (110)
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2
222
2
1
a
lkh
dhkl
For cubic system
Lattice spacing
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Crystal Structure Analysis
X-ray diffraction
Essence of diffraction: Bragg Diffraction
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LightInterference fringes Constructive
Destructive
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Bragg’s Law
For cubic system:
But no all planes have the
diffraction !!!
sin2
sinsin
hkl
hklhkl
d
dd
QTSQn
222 lkh
adhkl
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• X-ray diffraction from a crystal: Bragg’s Law
sin2 hkldn
222 lkh
adhkl
X-Ray Diffraction
n: order of
diffraction peak
dhkl: interplanar
spacing
(hkl): Miller
indices of plane
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Crystal Structures [OGN 21.2]• Body-centered cubic
(BCC)
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/hchE
35KeV ~ 0.1-1.4A
Cu K 1.54 A
Mo:
X-Ray Diffraction
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(200)(211)
Powder diffraction
X-Ray
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Phase purity.In a mixture of compounds each crystalline phase present will contribute to
the overall powder X-ray diffraction pattern. In preparative materials
chemistry this may be used to identify the level of reaction and purity of the
product. The reaction between two solids Al2O3 and MgO to form MgAl2O4
may be monitored by powder X-ray diffraction.
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•At the start of the reaction a mixture of Al2O3 and MgO will produce an X-
ray pattern combining those of the pure phases. As the reaction proceeds,
patterns (a) and (b), a new set of reflections corresponding to the product
MgAl2O4, emerges and grows in intensity at the expense of the reflection
from Al2O3 and MgO. On completion of the reaction the powder diffraction
pattern will be that of pure MgAl2O4.
•A materials chemist will often use PXRD to monitor the progress of a
reaction.
•The PXRD method is widely employed to identify impurities in materials
whether it be residual reactant in a product, or an undesired by-product.
•However the impurity must be crystalline.
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The powder diffraction patterns and the
systematic absences of three versions of
a cubic cell. Comparison of the observed
pattern with patterns like these enables
the unit cell to be identified. The
locations of the lines give the cell
dimensions.
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Observable diffraction
peaks
222 lkhRatio
Simple
cubic
SC: 1,2,3,4,5,6,8,9,10,11,12..
BCC: 2,4,6,8,10, 12….
FCC: 3,4,8,11,12,16,24….
222 lkh
adhkl
nd sin2
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Ex: An element, BCC or FCC, shows diffraction peaks at 2 :
40, 58, 73, 86.8,100.4 and 114.7.
Determine:(a) Crystal structure?(b) Lattice constant?
(c) What is the element?
2theta theta (hkl)
40 20 0.117 1 (110)
58 29 0.235 2 (200)
73 36.5 0.3538 3 (211)
86.8 43.4 0.4721 4 (220)
100.4 50.2 0.5903 5 (310)
114.7 57.35 0.7090 6 (222)
2sin222 lkh
a =3.18 A, BCC, W
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