spring 2015. horizontal alignment geometric elements of horizontal curves superelevation design...
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HORIZONTAL ALIGNMENT
Spring 2015
Horizontal Alignment
Geometric Elements of Horizontal Curves
Superelevation Design
Transition or Spiral Curves
Sight Distance
PC PT
Simple Curve
Circular Curve
Tangent
Point of Curvature Point of Tangency
SC
ST
Curve with Spiral Transition
Circular Curve
Tangent
Tangent to Spiral
Spiral to Tangent
Spiral
TS
Spiral to Curve
CS
Curve to Spiral
Design Elements of Horizontal Curves
Deflection Angle
Deflection Angle
( )2IT RTan=
Also known as Δ
Design Elements of Horizontal Curves
5729.58D
R=
Larger D = smaller Radius
100I
LD
=
Design Elements of Horizontal Curves
E=External Distance
M=Length of Middle Ordinate
Design Elements of Horizontal Curves
LC=Length of Long Cord
Basic Formulas
20.01
1 0.01 15
e f V
ef R
+=
-
Where,
e = superelevation
f = side friction factor
V = vehicle speed (mph)
R = radius of curve (ft)
2
0.0115
Vf e
R= -
Basic Formula that governs vehicle operation on a curve:
Basic Formulas
Where,
e = superelevation
f = side friction factor
V = vehicle speed (mph)
R = radius of curve (ft)
( )
2
minmax max15 0.01
VR
e f=
+
Minimum radius:
Minimum Radius with Limiting Values of “e” and “f”
2
maxd
Ve f
gR
Superelevation DesignDesirable superelevation:
for R > Rmin
Where,
V= design speed in ft/s or m/s
g = gravity (9.81 m/s2 or 32.2 ft/s2)
R = radius in ft or m
Various methods are available for determining the desirable superelevation, but the equation above offers a simple way to do it. The other methods are presented in the next few overheads.
Method 1:◦ Superelevation and side friction are directly
proportional to the inverse of the radius (straight relationship between 1/R=0 and 1/R =1/Rmin)
Method 2:◦ Side friction is such that a vehicle traveling
at the design speed has all the acceleration sustained by side friction on curves up to those requiring fmax
◦ Superelevation is introduced only after the maximum side friction is used
Methods for Estimating Desirable Superelevation
Method 3:◦ Superelevation is such that a vehicle traveling at the
design speed has all the lateral acceleration sustained by superelevation on curves up to those required by emax
◦ No side friction is provided on flat curves◦ May result in negative side friction
Method 4:◦ Same approach as Method 3, but use average running
speed rather than design speed◦ Uses speeds lower than design speed◦ Eliminate problems with negative side friction
Method 5:◦ Superelevation and side friction are in a curvilinear
relationship with the inverse of the radius of the curve, with values between those of methods 1 and 3
◦ Represents a practical distribution for superelevation over the range of curvature
◦ This is the method used for computing values shown in Exhibits 3-25 to 3-29
e = 0 ema
x
Reciprocal of Radius
Sid
e F
rictio
n F
acto
r Five Methods
fmax
M2 M1
M3
M5
M41/R
f
Important considerations:◦ Governed by four factors:
Climate conditions Terrain (flat, rolling, mountainous) Type of area (rural vs urban) Frequency of slow-moving vehicles
◦ Design should be consistent with driver expectancy
◦ Max 8% for snow/ice conditions◦ Max 12% low volume roads◦ Recurrent congestion: suggest lower than 6%
Design of Horizontal Alignment
Method 1Centerline
Method 2Inside Edge
Method 3Outside Edge
Method 4Straight Cross Slope
In overall sense, the method of rotation about the centerline (Method 1) is usually the most adaptable
Method 2 is usually used when drainage is a critical component in the design
In the end, an infinite number of profile arrangements are possible; they depend on drainage, aesthetic, topography among others
Which Method?
Median width
Pivot points
Example where pivot points are important
Bad design
Good design
15 ft to 60 ft
The superelevation transition consists of two components:◦ The superelevation runoff: length needed to
accomplish a change in outside-lane cross slope from zero (flat) to full superelevation
◦ The tangent runout: The length needed to accomplish a change in outside-lane cross slope rate to zero (flat)
Transition Design Control
Transition Design Control
Tangent Runout
Transition Design Control
Superelevation Runoff
Transition Design Control
Transition Design Control
http://techalive.mtu.edu/modules/module0003/Superelevation.htm
Minimum Length ofSuperelevation Runoff
Minimum Length ofSuperelevation Runoff
= relative gradient in previous overhead
Minimum Length ofSuperelevation Runoff
Values for n1 and bw in equation
Minimum Length ofTangent Runout
See Exhibit 3-32 for values of Lt and Lr
Superelevation RunoffLocation: 1/3 on curve
Location: 2/3 on tangent
Superelevation Runoff
All motor vehicles follow a transition path as it enters or leaves a circular horizontal curve (adjust for increases in lateral acceleration)
Drivers can create their own path or highway engineers can use spiral transitional curves
The radius of a spiral varies from infinity at the tangent end to the radius of the circular curve at the end that adjoins the curve
Transition Curves -Spirals
Transition Curves -Spirals
Need to verify for maximum and minimum lengths
Transition Curves
Superelevation runoff should be accomplished on the
entire length of the spiral curve transition
Equation for tangent runout when Spirals are used:
The sight distance is measured from the centerline of the inside lane
Need to measure the middle-ordinate values (defined as M)
Values of M are given in Exhibit 3-53 Note: Now M is defined as HSO or Horizontal
sightline offset.
Sight distance on Horizontal Curve
Example ApplicationIncluded for your benefit
e = 0emax (for the design speed)
Reciprocal of Radius
Sid
e F
rictio
n F
acto
rSelection of fdesign and edesign (Method 5)
fmax (for the design speed)
fdesign
1/R
f
e = 0emax
Reciprocal of Radius
Sid
e F
rictio
n F
acto
rSelection of fdesign and
edesign
fmax
fdesign
Rf = V2/(gfmax)
Ro = V2/(gemax)
R0: f = 0, e = emax
Rmin = V2/[g(fmax + emax)]
1/R
f
e = 0
emax (for the design speed)
Reciprocal of Radius
Sid
e F
rictio
n F
acto
rSelection of fdesign and
edesign
fmax (for the design speed)
fdesign
fdesign = α(1/R)+β(1/R)2
α = fmaxRmin[1-{Rmin/(R0-Rmin)}]
β = fmaxRmin3/(R0-Rmin)
1/R
f
Superelevation Design for High Speed Rural and Urban Highways
Example:
Design Speed: 100 km/h
fmax = 0.128
emax = 0.06
Question?
What should be the design friction factor and design superelevation for a curve with a radius of 600 m?
1. Compute Rf, R0, and Rmin:
Rf = V2/(gfmax) = 27.782 / (9.81 x 0.128) = 615 m
R0 = V2/(gemax) = 27.782 / (9.81 x 0.06) = 1311 m
Rmin = V2/[g(fmax + emax)] = 27.782 / [9.81(0.128+0.06)]
Rmin = 418 m
e = 0
emax = 0.06 Sid
e F
rictio
n F
acto
rSelection of fdesign and edesign
(example)
fmax = 0.128
fdesign
1 / 1311 1 / 615 1 / 418 1/R
f
2. Compute α and β:
α = 0.128 x 418 x [1 – 418 / (1311 – 418) ] = 28.45 m
β = 0.128 x 4183 / (1311 – 418) = 10502 m2
3. Compute fdesign and edesign :
First, estimate the right-hand side of equation for designing superelevation
e + f = V2/(gR) = 27.782 / (9.81 x 600) = 0.131
Then,
fdesign = 28.45 / 600 + 10502 / 6002 = 0.076
edesign = 0.131 – 0.076 = 0.055 (< emax = 0.06)
e = 0
emax = 0.06 Sid
e F
rictio
n F
acto
r
fmax = 0.128
fdesign
1 / 1311 1 / 615 1 / 418
1 / 600
0.076
Selection of fdesign and edesign
(example)
1/R
f
Selection of fdesign and edesign
(example)
R=600 ft
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