find the indicated z score:.8907 0 z = 1.23. find the indicated z score:.6331 z 0 z = – 0.34.3669

Find the indicated z score:

Find the indicated z score:

.8907

0 z = 1.23

Find the indicated z score:

.6331

z = – 0.34

.3669

Find the indicated z score:

.3560

0 z = 1.06

.8560

Find the indicated z score:

.4792

z = 0– 2.04

.0208

Find the indicated z score:

0 z =

.4900

2.33

Find the indicated z score:

z = 0

.005

– 2.575

Find the indicated z score:

If area A + area B = .01, z = __________

A B

– z 0 z

2.575 or 2.58

= .005

Application of Determining z Scores

The Verbal SAT test has a mean score of 500 and a standard deviation of 100.

Scores are normally distributed. A major university determines that it will accept

only students whose Verbal SAT scores are in the top 4%. What is the minimum

score that a student must earn to be accepted?

...students whose Verbal SAT scores are in the top 4%.

Mean = 500, standard deviation = 100

= .04.9600

z = 1.75

The cut-off score is 1.75 standard deviations above the mean.

Application of Determining z Scores

Mean = 500, standard deviation = 100

= .04.9600

z = 1.75

The cut-off score is 500 + 1.75(100) = 675.