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Created byProfessor William Tam & Dr. Phillis

Chang Ch. 19 - 1

Chapter 19Chapter 19

Condensation and Condensation and Conjugate Addition Conjugate Addition

Reactions of Carbonyl Reactions of Carbonyl CompoundsCompounds

More Chemistry of EnolatesMore Chemistry of Enolates

Ch. 19 - 2

1. Introduction Carbonyl condensation reactions.

● Claisen condensation:O

ORR'

O

ORR'

H

O

OR

O

R'

R'ROH +

+1. NaOR

2. H3O+

https://www.concursolutions.com

An carbon anion(enolate) from oneester attacks the carbonyl of the other.

Ch. 19 - 3

O

HR'

O

HR'

H

OH

H R'

O

HR'

R'

R'

O

H

+Base

(addition)

"condensation"

+OH H

●Aldol addition and condensation:

An carbon anion(enolate) from oneattacks the carbonylof the other followedby dehydration.

Ch. 19 - 4

O

R

O

R

H

Nu

1. Nu

2. H3O+

Conjugate addition reaction: e.g. to an alkene conjugated to a carbonyl.

A nucleophile (could be an enolate) attacksthe carbon of the unsaturated carbonyl.Where Nu: is an enolate it is called a Michael addition.

Ch. 19 - 5

2. The Claisen Condensation: A Synthesis of -Keto Esters

O

R'OR

O

R'

H HOR

O

OR

O

H R'

R'

+

+ROH

1. NaOR

2. H3O+

An carbon anion(enolate) from oneester attacks the carbonyl of the other.

Ch. 19 - 6

Mechanism:●Step 1

O

R'OR

H H

OR+ ROH+

O

ORR'

H

O

ORR'

H

Base removes an hydrogenforming an enolate from oneester.

Ch. 19 - 7

O

ORR'

O

OR

R'H

+

Mechanism:●Step 2

O

OR

O

H R'

R'

RO

O

OR

O

H R'

R'RO +

The enolate attacks the carbonyl of another esterwith loss of -OR.

Ch. 19 - 8

O

OR

O

H R'

R'

OR(pKa ~ 9)

Mechanism:●Step 3

O

OR

O

R'

R'+

ROH

(pKa ~ 16)

Ch. 19 - 9

O

OR

O

R'

R'

O

OR

O

R'

R'

O

OR

O

R'

R'

Ch. 19 - 10

Mechanism:●Step 4

O

OR

O

R'

R'

H O

H

H

+

(rapid)

O

OR

O

R'

R'H

(keto form)

OH

OR

O

R'

R'(enol form)

Ch. 19 - 11

Claisen condensation:

●An Acyl Substitution:(nucleophilic addition-elimination reaction).

●Useful for the synthesis of -keto esters.

Ch. 19 - 12

Claisen condensation:● Esters that have only one

hydrogen do not undergo the usual Claisen condensation.

O

OMe

HThe carbon has only one hydrogen does not undergo the Claisen condensation using RO- (alkoxide). Use LDA, a stronger base, see slide 23. This is because an ester with only one

hydrogen will not have an acidic hydrogen when step 3 is reached, and step 3 promotes the favorable equilibrium that ensures the forward reaction.

e.g.

Ch. 19 - 13

Examples of Claisen condensation:

O

OMe(1) 2

NaOMeO

OMe

O

+ MeOH

H3O+O

OMe

O

H

Ch. 19 - 14

Examples of Claisen condensation:

O

OEt(2) 2

NaOEtO

OEt

O

+ EtOH

O

OEt

O

H

H3O+

Ch. 19 - 15

2A.2A. Intramolecular Claisen Condensations:Intramolecular Claisen Condensations:The Dieckmann CondensationThe Dieckmann Condensation

Intramolecular (cyclic) Claisen condensation:● Dieckmann condensation.● Useful for the synthesis of five-

and six-membered rings.MeO

O O

OMe

O

OMe

O

1. NaOMe

2. H3O+

12

3

4

5

67

12

3

4

5

6 7

Ch. 19 - 16

O

OMe

O

Mechanism:

OMeMeO

O O

OMe123

4

5

67

H OMe

O

12

34

5

6

7

OMe

OO

OMe

O

OMe2

3

4

5

6 7 1

O

OMe

OH

OMe

O

OMe

O

O HH

H(This favorableequilibrium drives the reaction)

Ch. 19 - 17

Other examples:

EtO

O

OEt123456

O

1. NaOEt

2. H3O+ OEt

OO

(1)

12

34

56

Ch. 19 - 18

Other examples:

(2)MeO

O

OMe

O Me

1. NaOMe

2. H3O+

OMe

OO

MeOMe

OO

Me

not

Why?

Ch. 19 - 19

2B.2B. Crossed Claisen CondensationsCrossed Claisen Condensations Crossed Claisen condensations are

possible when one ester component has no hydrogens and, therefore, is unable to form an enolate ion and undergo self-condensation.

O

OMe

O

OMe

O

OMe

O1. NaOMe

2. H3O++

(no -hydrogen)

Ch. 19 - 20

Mechanism:

O

OMe

H

OMe+

O

OMe+ MeOH

O

OMe

O

OMe

O

OMe

O

OMe

O

H

Ch. 19 - 21

Mechanism:

O

OMe

O

H

(This favorable equilibriumdrives the reaction)

OMe

O

OMe

O

H O H

H

O

OMe

O

Ch. 19 - 22

Other examples:

O

OEtO

OEt

O

OEt

O

1. NaOEt

2. H3O+

+

(1)

(no hydrogen)

(2) O

MeO OMe

O

OMe+

1. NaOMe

2. H3O+

O

MeO OMe

O

(no carbon)

Ch. 19 - 23

Recall: esters that have only one hydrogen cannot undergo

Claisen Condensation by using sodium alkoxide.

However, they can be converted to the -keto esters by reactions that use very strong bases such as lithium diisopropyamide (LDA). LDA is strong enough to retain the anion.

Ch. 19 - 24

O

OMe

O

OMe

O

OMe

Cl

O

LDA

THF

O

Ch. 19 - 25

3. -Dicarbonyl Compounds by Acylation of Ketone Enolates

O

HH

O O

OO

NaNH2

Et2OO

Ph OMe

(kineticenolate)

slightly more acidic

Ch. 19 - 26

Intramolecular example:

Ha

O

Hb O

OMe

Hc

1234567

1. NaOMe

2. H3O+

O O

12

3 4

56

7

●The product was formed by deprotonation of Hb, the enolate formed at C5 and then adding to C1. A five membered ring is more stable than a seven membered ring.

Ch. 19 - 27

● Questions:i. Give the structure of the

product by deprotonation of Ha, and adding the resulting enolate (at C7) to C1. Explain why this product is not formed.

ii. Give the structure of the product by deprotonation of Hc, and adding the resulting enolate (at C2) to C6. Explain why this product is not formed.

Ch. 19 - 28

4. Aldol Reactions: Addition of Enolates and Enols to Aldehydes and Ketones

O

H

OH

H

O10% NaOH

H2O, 5 oC2

The product contains both an aldehyde and an alcohol functional group.

Therefore: aldol addition

Ch. 19 - 29

4A.4A. Aldol Addition ReactionsAldol Addition Reactions Mechanism of the aldol addition:

O

H

O

HH

HO

O

H

O

H+ H2O

O

H

OHO H

O

H

OH

+ HO

Shown on slide 3.

Ch. 19 - 30

4B.4B. The Retro-Aldol ReactionThe Retro-Aldol Reaction

Mechanism for reverse aldol:

OOH OHO

H2O2

OO

HO

HOO O

O

+

HO HO

+HO

Ch. 19 - 31

4C.4C. Aldol Condensation Reactions: Aldol Condensation Reactions: Dehydration of the Aldol Addition Dehydration of the Aldol Addition ProductProduct

Dehydration of the aldol product.●Base catalyzed aldol

condensation:O

H

OH

HOH

O

H+ H2O + OH

Aldol product.

This dehydration is easier than normal because the double bond is conjugated with the carbonyl.

Ch. 19 - 32

4C.4C. Acid-Catalyzed AldolAcid-Catalyzed AldolCondensationsCondensations

O

2H3O

+ O

+ H2O

Ch. 19 - 33

Mechanism:

O

H O H

H

+O

H

H

OH2 OH

OH

OH

OHO OH2

HH2O:

O

+ H2O

+ H3O+

Followed by dehydration of the aldol product.

Ch. 19 - 34

4E.4E. Synthetic Applications of AldolSynthetic Applications of AldolReactionsReactions

Aldol additions and aldol condensations:● Important methods for carbon-

carbon bond formation.● Useful synthesis for:

-hydroxyl carbonyl compounds

-unsaturated carbon compounds

Ch. 19 - 35

RH

OAldehyde

OH O

HR

base

Aldol

R

RH

OHOHNaBH4

1,3-diol

R

O

HR

-unsaturatedaldehyde

HA, -H2O

R

OH

R

R

Allylicalcohol

LiAlH4

OH

R

R

Saturatedalcohol

H2/Nihigh

pressure

O

HR

Aldehyde

H2, Pd-C

R

Ch. 19 - 36

5. Crossed Aldol Condensations

O

H H

O

H H

O OH

OH

H

O

OH OOOH

+HOH2O

+

+ +

Works best when onereactant does not havean hydrogen.

Ch. 19 - 37

5A.5A. Crossed Aldol Condensations Crossed Aldol Condensations Using Weak BasesUsing Weak Bases

O

H

O

+

O

HO

OOH

H

aldoladdition

dehydration

No hydrogen

Ch. 19 - 38

O

H H

O

H

O

HH

OH

H

Na2CO3 (aq)+

No hydrogen

Ch. 19 - 39

O O Li

5B.5B. Crossed Aldol Condensations UsingCrossed Aldol Condensations UsingStrong Bases: Lithium Enolates and Strong Bases: Lithium Enolates and Directed Aldol ReactionsDirected Aldol Reactions

Directed Aldol Synthesis using a strong base, iPr2NLi (LDA).

O

H

OLDA, THF

-78 oC

O

H

O OHH2O

Ch. 19 - 40

The use of a weaker base under protic conditions:

● Results in formation of both kinetic and thermodynamic enolates,

● Therefore, a mixture of crossed aldol products.

Ch. 19 - 41

O O O

O

HO OH O

OH

1.2. H2O

(Thermodynamicenolate)

(Kineticenolate)

HO

proticsolvent

+

Ch. 19 - 42

Suggest a synthesis of the following compound using a directed aldol synthesis.O OH

O OH

●Retrosynthetic analysis:

disconnection

O

O

+

Ch. 19 - 43

Synthesis:

O O

LDA

O Li

O

H1.

2. H2O

O OH

Ch. 19 - 44

6. Cyclizations via AldolCondensations

Intramolecular Aldol condensation:● Useful for the synthesis of five-

and six-membered rings.● Using a dialdehyde, a keto

aldehyde, or a diketone. e.g. O

H

OHO

O

Ch. 19 - 45

O

H

O

HcHbHa

12345678

O

H

O

(Ha)

(path a)

123456

78

OH

O 1

2

3

45

6

78

H2O

(-H2O)O

(not formed)

Ch. 19 - 46

O

H

O

HcHbHa

12345678

O

H

O

(Hb)

(path b)

12345

678

H2O

1

2

34

5

6

78

O

OH

(-H2O)

O

Ch. 19 - 47

O

H

O

(Hc)

(path c)

12

34567

8

O

H

O

HcHbHa

12345678

H2O

12

34

5

67

8

H

OHO

(-H2O)

(not formed)

H

O

Ch. 19 - 48

●Although three different enolates are formed, cyclization usually occurs with an enolate of the ketone adding to the aldehyde.

O

R R

O

R H

<

(Ketones are less reactive

toward nucleophiles)

(Aldehydes aremore reactive

toward nucleophiles)

Path c is least favorable.

Ch. 19 - 49

●Path b is more favorable than path a because six-membered rings are thermodynamically more favorable to form than eight-membered rings.

●Likewise, five-membered rings form far more readily than seven-membered rings.

Ch. 19 - 50

7. Additions to -Unsaturated Aldehydes and Ketones

O

+

Nu

O OHH2O

Nu

simple addition(1,2-addition)

Nu

OH2O

conjugate addition(1,4-addition)

O

HNu

Nu

Ch. 19 - 51

OH O

PhMgBrEt2O

2. H3O+

H

Ph

Ph+

(82%)(simple addition)

(18%)(conjugate addition)

O

1.Stronger Nu: attacks the C=O.

Ch. 19 - 52

O

nucleophiles attack the carbonyl carbon or the carbon

O

O

Ch. 19 - 53

Conjugate addition of HCN:

O O

H

CNCN

EtOH, AcOH

NCOCN

H+

Weaker Nu: attacks to the C=O.

Ch. 19 - 54

O O

H

EtNHEtNH2

H2O(keto form)

Conjugate addition of an amine:

EtNH2

ONEt H

H

OHEtNH(enol form)

Ch. 19 - 55

O O

(Michael Addition Mechanism)

7A.7A. Conjugate Additions of Enolates: Conjugate Additions of Enolates: Michael AdditionsMichael Additions

O

H

O O

O

NaOMe (cat.)MeOH

2.

1.

MeO

O

O

H OMe

Ch. 19 - 56

Other examples of Michael additions:MeOOC

MeOOC

OEt

O

O

OEtMeOOC

COOMe

1. NaOMe, MeOH

2.

(1)

(2)

O

OMe COOMe

O

OMe

O

COOMe

O1. NaOMe, MeOH

2.

Ch. 19 - 57

7B.7B. The Robinson AnnulationThe Robinson Annulation

O

O

O

OO

NaOH, MeOHO

O

O

(Michaelconjugateaddition)

(Aldol condensation)

Base(-H2O)

Ch. 19 - 58

Mechanism of the Robinson Annulation:O

H

O

O

O

O

O

OOH

O

(Micheal addition)

MeO H

O

O

O

H

HO

O

O

O

Ch. 19 - 59

MeO H

O

O

O (intramolecularAldol

condensation)O

O

O

OHH

O

O

O

O

(dehydration)

HO

Mechanism of the Robinson Annulation:

Ch. 19 - 60

8. The Mannich Reaction

O O

H H

O

NEt2

Et2NH

H2O

+ +

HCl

+A 1o or 2o amine reacts with formaldehyde to form an imine (schiff base). The enol then reacts with the imine.

Mannich base

Ch. 19 - 61

O

H HEt2NH

OH

NH H

Et Et

OH

NH H

Et Et

HHCl

(-HOH)

NEt Et

H HO

NEt2

H HO OH

HCl

+

Mechanism of the Mannich Reaction:

The imine reacts with an enol producing a Mannich base.

Ch. 19 - 62

Other examples of the Mannich Reaction:

(1)

O O

NEt2

O

H HEt2NH

HCl+ +

(2)

O O

H HNH

O

N+ +

HCl

Ch. 19 - 63

O

ROEt

R

O

O

OEtR

[*]O

OEtR

9. Summary of Important Reactions

1. NaOEt,

2. H3O+

[*] =

Claisen Condensations:

O

Ph OEt

R

O

O

Ph OEt

[*]

ROEt

O

OEtO

O

EtO OEt[*]

ROEt

O

O H

O

H OEt

[*]

O

EtOOEt

O

ROEt

O

OO

OEt

[*]

Ch. 19 - 64

Aldol Condensations:

O

HR

O

HR

NaOH, H2O

O

HR

OH

R

O

HR

R

(-H2O)

O

R' R'

1. LDA, THF, -78oC

2.

3. NH4Cl

O

HR

R' OHR'

Ch. 19 - 65

Simple & Conjugate (Michael) additions:

O

R

OH

R'

1. R'MgBr, Et2O

2. H3O+

R(simple addition:major product)

NaCNEtOH, AcOH

O

R

CN

H

O

R

NH

H

R' R'NH2

O

R

MeOH, NaOMe

O

O

Ch. 19 - 66

Mannich reaction:O

R

O

H HNH

R''

R'

+ +

H+

O

R NR'

R''

H H

Ch. 19 - 67

END OF CHAPTER 19

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