back projection reconstruction for ct, mri and nuclear medicine

Post on 03-Jan-2016

61 Views

Category:

Documents

3 Downloads

Preview:

Click to see full reader

DESCRIPTION

Back Projection Reconstruction for CT, MRI and Nuclear Medicine. F33AB5. CT collects Projections. Introduction Coordinate systems Crude BPR Iterative reconstruction Fourier Transforms Central Section Theorem Direct Fourier Reconstruction Filtered Reconstruction. - PowerPoint PPT Presentation

TRANSCRIPT

Back Projection Reconstruction

for CT, MRI and Nuclear Medicine

F33AB5

CT collects Projections

• Introduction• Coordinate systems• Crude BPR• Iterative reconstruction• Fourier Transforms• Central Section Theorem• Direct Fourier Reconstruction• Filtered Reconstruction

To produce an image the projections are back projected

Crude back projection

• Add up the effect of spreading each projection back across the image space.

• This assumes equal probability that the object contributing to a point on the projection lay at any point along the ray producing that point.

• This results in a blurred image.

Crude v filtered BPR

90

360

Crude BPR Filtered BPR

Sinograms

r

r

Stack up projections

Solutions

• Two competitive techniques– Iterative reconstruction

• better where signal to noise ratio is poor

– Filtered BPR • faster

• Explained by Brooks and di Chiro in Phys. Med. Biol. 21(5) 689-732 1976.

Coordinate system

• Data collected as series of – parallel rays, at

position r, – across projection

at angle .

• This is repeated for various angles of .

Detec

tor,

trans

lated

X-ra

y tu

be, t

rans

late

d

X-ray beam

Sample

r

s

Attenuation of ray along a projection

• Attenuation occurs exponentially in tissue.

(x) is the attenuation coefficient at position x along the ray path.

dxxeII

)(

0

Definition of a projection• Attenuation of a ray at position r, on the

projection at angle , is given by a line integral.

• s is distance along the ray, at position r across the projection at angle .ds s)(r, =

ds )(x, =

IIln = ) ,p(r 0

yDet

ecto

r, tra

nslat

ed

X-ra

y tu

be, t

rans

late

d

X-ray beam

Sample

r

s

Coordinate systems• (x,y) and (r,s) describe the distribution of

attenuation coefficients in 2 coordinate systems related by .

• where i =1..M for M different projection orientations• angular increment is = /M.

x

y r (along projection)

S (along ray path)

tube

detectorii yxr sincos

Crude back projection• Simply sum effects of back-

projected rays from each projection, at each point in the image. ) ,p(r = y)(x, i

M

1=i

*

) ,ysin+(xcos p = y)(x, iii

M

1=i

*

Crude back projection

• After crude back projection, the resulting image, *(x,y), is convolution of the object ((x,y)) with a 1/r function.

Convolution

• Mathematical description of smearing. • Imagine moving a camera during an

exposure. Every point on the object would now be represented by a series of points on the film: the image has been convolved with a function related to the motion of the camera

Iterative Technique

• Guess at a simulated object on a PxQ grid (j, where j=1PxQ),

• Use this to produce simulated projections

• Compare simulated projections to measured projections

• Systematically vary simulated object until new simulated projections look like the measured ones.

• For your scanner calculate jj(r,i), the path length through the jth voxel for the ray at (r,i)

j need only be estimated once at the start of the reconstruction,

j is zero for most pixels for a given ray in a projection

1 2 3 4

16

5 6 7 8

1211109

13 14 15

j=02=0.17=1.2

• The simulated projections are given by:

j is mean simulated attenuation coefficient in the jth voxel.

jij

QP

ji r ),( = ) ,(r

1

1 2 38 9 4

7 6 5

1415

6

16 17 2

6

2118

27

6

27

6

27

6

Object and projections

15 15 15

1019

109

1513

First ‘guess’

From Physics of Medical Imaging by Webb

To solve• Analytically, construct P x Q simultaneous

equations putting (r,i) equal to the measured projections, p(r,i):

•– this produces a huge number of equations – image noise means that the solution is not exact and the

problem is 'ill posed’

• Instead iterate: modify j until (r,i) looks like the real projection p(r,i).

jj

ji i

)(r, = )(r, p

Iterating• Initially estimate j by projecting data

in projection at = 0 into rows, or even simply by making whole image grey.

• Calculate (r,i) for each i in turn.

• For each value of r and , calculate the difference between (r,) and p(r,).

• Modify i by sharing difference equally between all pixels contributing to ray.

21/3

71/3

61/3

22/3

72/3

62/3

16

5

16 17 12

1015

122/3

Next iteration

27

6

27

6

27

6

15 15 15

1513

First ‘guess’

1 2 38 9 4

7 6 5

Object

1 2 38 9 4

7 6 5

1415

6

16 17 2

6

2118

1019

10

Fourier Transforms

• Imagine a note played by a flute.

• It contains a mixture of many frequency sound waves (different pitched sounds)

• Record the sound (to get a signal that varies in time)

• Fourier Transforming this signal will give the frequencies contained in the sound (spectrum)

Time Frequency

Fourier transforms of images

• A diffraction pattern is the Fourier transform of the slit giving rise to it

kkxx

kkyy yy

xx

FTFT

Central Section theorem• The 1D Fourier transform of a

projection through an object is the same as a particular line through 2DFT of the object.

• This particular line lies along the conjugate of the r axis of the relevant projection.

kkxx

kkyyyy

xx

FTFT

Projection

Direct Fourier Reconstruction

• Fourier Transform of each projection can be used to fill Fourier space description of object.

y

x

ky

kx

Fp(r,1)

Fp(r,2)

InverseFourierTransform

Direct Fourier Reconstruction

• BUT this fills in Fourier space with more data near the centre.

• Must interpolate data in Fourier space back to rectangular grid before inverse Fourier transform, which is slow.

Relationship between object and crude BPR

results• Crude back projection from above:

• Defining inverse transform of projection as:

• then

, d ) ,ysin+p(xcos = y) ,(x o

*

dk,e )(k, F = ) ,p(r ikr2p

-

ddk |k|

[k] e ) ,(k F = y)(x, )ysin+ik(xcos2

p

-o

*

• The right hand side has been multiplied and divided by k so that it has the form of a 2DFT in polar coordinates – k conjugate to r k conjugate to r

– the integrating factor is kdrd dxdy

ddk |k|

[k] e ) ,(k F = y)(x, )ysin+ik(xcos2

p

-o

*

• Crude back projected image is same as the true image, except Fourier amplitudes have been multiplied by (magnitude of spatial frequency)-1

.

– Physically because of spherical sampling. – Mathematically because of changes in

coordimates.

k

)(k,F = )k,k(Fp

yx*

Filtered BPR

• Multiplying 2 functions together is equivalent to convolving the Fourier Transforms of the functions.

• Fourier transform of (1/k) is (1/r)• Multiplying FT of image with 1/k is

same as convolving real image with 1/r

• ie BPR has effect we supposed.

Filtered BPR

• Therefore there are two possible approaches to deblurring the crude BPR images:

• Deconvolve multiplying by f (1/f x f = 1) in Fourier domain.

• Convolve with Radon filter in the image domain, to overcome effect of being filtered with 1/r by crude BPR.

top related