02a one sample t-test
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The One-Sample t-TestAdvanced Research Methods in Psychology
- lecture -
Matthew Rockloff
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A brief history of the t-test Just past the turn of the nineteenth century, a
major development in science was fermenting
at Guinness Brewery.
William Gosset, a brewmaster, had invented a
new method for determining how large a
sample of persons should be used in the
taste-testing of beer. The result of this finding revolutionized
science, and – presumably - beer.
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In 1908 Gosset published his
findings in the journal Biometrika
under the pseudonym „student.‟This is why the t-
test is often called
the „student‟s t.‟
A brief history of the t-test(cont.)
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A brief history of the t-test(cont.)
Folklore: Two stories circulate for the reason whyGosset failed to use his own name.
1: Guinness may have wanted to keep their
use of the „t-test‟ secret. By keeping Gossetout of the limelight, they could also protecttheir secret process from rival brewers.
2: Gosset was embarrassed to have his name
associated with either: a) the liquor industry,or b) mathematics.
But seriously, how could that be?
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Thus ???“Beer is the cause of –
and solution to –
all of life's problems.” (Homer Simpson)
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When to use the one-sample t-test One of the most difficult aspects of
statistics is determining which procedure to
use in what situation.
Mostly this is a matter of practice.
There are many different rules of thumb
which may be of some help.
In practice, however, the more youunderstand the meaning behind each of the
techniques, the more the choice will become
obvious.
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Example problem 2.1 Example illustrates the calculation of
the one-sample t-test.
This test is used to compare a list of values to a set standard.
What is this standard?
The standard is any number we choose. As illustrated next, the standard is
usually chosen for its theoretical or
practical importance.
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Example 2.1 (cont.)
Intelligence tests are constructed such that
the average score among adults is 100
points.
In this example, we take a small sample of
undergraduate students at Thorndike
University (N = 6), and try to determine if the
average of intelligence scores for allstudents at the university is higher than 100.
In simple terms, are the university
students smarter than average?
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Example 2.1 (cont.)
The scores obtained from the 6 studentswere as follows:
XPerson 1: 110Person 2: 118
Person 3: 110
Person 4: 122Person 5: 110
Person 6: 150
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Example 2.1 (cont.)
Research Question
On average, do the population of
undergraduates at Thorndike
University have higher than averageintelligence scores (IQ 100)?
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Example 2.1 (cont.)
First, we must compute the mean (or average) of this sample:
In the above example, there is some newmathematical notation. (See next slide)
1206
150101221110181101
n =
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Example 2.1 (cont.)
First, a symbol that denotes the mean
of all Xs or intelligence scores.
120
6
150101221110181101
n
=
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Example 2.1 (cont.)
The second part of the equation shows
how this quantity is computed.
120
6
150101221110181101
n
=
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Example 2.1 (cont.)
The sigma symbol ( ) tells us to sum
all the individual Xs.
120
6
150101221110181101
n
=
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Example 2.1 (cont.)
Lastly, we must divide by „n‟,
that is: the number of observations.
120
6
150101221110181101
n
=
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Example 2.1 (cont.)
Notice, these 6 people have higher than
average intelligence scores (IQ 100).
120
6
150101221110181101
n
=
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Example 2.1 (cont.)
However, is this finding likely
to hold true in repeated samples?
What if we drew 6 different people from
Thorndike University?
A one-sample t-test will help answer this
question.
It will tell us if our findings are „significant‟,or in other words, likely to be repeated if we
took another sample.
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110118
110
122
110150
120120
120
120
120120
-10- 2
-10
2
-1030
1004
100
4
100900
Example 2.1 (cont.)
Computing the sample variance
2)(
3.201)( 2
2
n
s x
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110118
110
122
110150
120120
120
120
120120
-10- 2
-10
2
-1030
1004
100
4
100900
Example 2.1 (cont.)
Computing the sample variance
2)(
3.201)( 2
2
n
s x
3.201
)( 2
2
n
s x
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Example 2.1 (cont.)
Computing the sample variance
To get the third column we take eachindividual „X‟ and subtract it from themean (120).
We square each result to get the fourthcolumn.
Next, we simply add up the entire
fourth column and divide by our original sample size (n = 6).
The resulting figure, 201.3, is the
sample variance.
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Example 2.1 (cont.)
Computing the sample variance
Important:All sample variances
are computed this way!We always take the mean;
subtract each score from the mean;
square the result;sum the squares;and divide by the sample size
(how many numbers, or rows we have).
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Now that we have the mean (X = 120) and
the variance ( ) of our sample, we
have everything needed to compute whether
the sample mean is „significantly‟ above theaverage intelligence.
In the formula that follows, we use a new
symbol mu ( ) to indicate the populationstandard value ( = 100 ) against which we
compare our obtained score (X = 120).
Example 2.1 (cont.)
Computing the sample variance
3.2012
x s
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Example 2.1 (cont.)
Computing the sample variance
152.3
16333.201
100120
1
2
n s
t
x
Our sample has „n = 6‟ people, so the degrees of
freedom for this t-test are:
dn = n – 1 = 5This degrees of freedom figure will be used later
in our test of significance.
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And now for somethingcompletely different …
Let’s take a break from computations, and talk about ‘ the big picture’
Now comes the conceptually tricky part.
Remember that a normal bell-curvedistribution is a chart that showsfrequencies (or counts).
If we measured the weight of four maleadults, for example, we might find thefollowing:
Person 1 = 70 kg, Person 2 = 75 kg, Person 3= 70 kg, Person 4 = 65 kg
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The ‘big picture’
Person 1 = 70 kg, Person 2 = 75 kg, Person
3 = 70 kg, Person 4 = 65 kg
Plotting a count of these „weight‟ data,
we find a normal distribution:
Count 2 X
1 X X X
65 70 75 kg
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The ‘big picture’ (cont.)
As it turns out, the „t‟ statistic has its own distribution, just like any other variable.
Let‟s assume, for the moment, that the mean IQ of thepopulation in our example is exactly 100.
If we repeatedly sampled 6 people and calculateda „t‟ statistic each time, what would we find?
If we did this 4 times, for example, we might find:
Count 2 X
1 X X X
- 1 0 1 t - statistic
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The ‘t’ statistic (cont.)
Most often our computed „t‟should be around 0. Why?Because the numerator, or top part of
the formula for t is: .
If our first sample of 6 people is trulyrepresentative of the population, then
our sample mean should also be 100,and therefore our computed t shouldbe (see next slide)
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0
1
100100
2
n
s
t
x
The ‘t’ statistic (cont.)
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The ‘t’ statistic (cont.)
Of course, our repeated samplesof 6 people will not always have
exactly the same mean
as the population.
Sometimes it will be a little higher, andsometimes a little lower.
The frequency with which we find a t larger than 0 (or smaller than 0) is exactly what thet-distribution is meant to represent
(see next slide)
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The ‘t’ statistic (cont.)
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In our GPA example, the actual „t‟ thatwe calculated was 3.152, which iscertainly higher than 0.
Therefore, our sample does not looklike it came from a population with amean of 100.
Again, if our sample did come fromthis population, we would most oftenexpect a computed „t‟ of 0
Read this part over and over,and think about it. This is the tricky bit.
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The ‘t’ statistic (cont.)
How do we know when
our computed „t‟ is
very large in magnitude? Fortunately, we can calculate how
often a computed sample „t‟ will be far
from the population mean of t = 0based on knowledge of the
distribution.
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The ‘t’ statistic (cont.)
The critical values of the t-distribution show
exactly how often we should find computed
„t‟s of large magnitude.
In a slight wrinkle, we need the degrees of
freedom (df = 5) to help us make this
determination.
Why? If we sample only a few people our computed „t‟s are more likely to be very
large, only because they are less
representative of the whole population.
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And now, back to the computation…
We need to find the „critical value‟ of
our t-test.
Looking in the back of any statisticstextbook, you can find a table for critical
values of the t-distribution.
Next, we need to determine whether weare conducting a 1-tailed or 2-tailed t-test.
Let‟s refer back to the research question:
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Example 2.1 (again)
Research Question
On average, do the population of
undergraduates at Thorndike
University have higher than averageintelligence scores (IQ 100)?
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Example 2.1 (cont.)
This is a 1-tailed test, because we are askingif the population mean is „greater ‟ than 100.
If we had only asked whether the
intelligence of students were „different‟ fromaverage (either higher or lower) then the testwould be 2-tailed.
In the appendixes of your textbook, look atthe table titled, „critical values of the t-
distribution‟. Under a 1-tailed test with an Alfa-level of
and degrees of freedom df = 5, and youshould find a critical value (C.V.) of t = 2.02.
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Example 2.1 (cont.)
Is our computed t = 3.152greater than the C.V. = 2.02?
Yes!Thus we reject the null hypothesis and live happily ever after.
Right?
Not so fast.What does this really mean?
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Example 2.1 (still)
We assume the null hypothesis when
making this test.
We assume that the population meanis 100, and therefore we will most often
compute a t = 0.
Sometimes the computed „t‟ might be abit higher and sometimes a bit lower.
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What does the ‘critical value’ tell us?
Based on knowledge of the distributiontable we know that 95% of the time, inrepeated samples, the computed „t‟
statistics should be less than 2.02.
That‟s what the critical value tells us.
It says that when we are sampling 6 personsfrom a population with mean intelligencescores of 100, we should rarely compute a„t‟ higher than 2.02.
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What happens if
we do calculate a ‘t’ greater than 2.02?
Well, we can be pretty confident that our
sample does not come from a population
with a mean of 100!
In fact, we can conclude that the population
mean intelligence must be higher than 100.
How often will we be wrong in this
conclusion? If we do these t-tests a lot, we‟ll be wrong
5% of the time. That‟s the Alfa level (or 5%).
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Statistical inference
You should notice that the conclusion
makes an inference about the population of
students from Thorndike University based
on a small sample.
This is why we call this type of a test
„statistical inference.‟ We are inferring something about the
population based on only a sample of
members.
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Example 2.1 Using SPSS
First, variables must be setup in the variable
view of the SPSS Data Editor as detailed in
the previous chapter:
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Example 2.1 Using SPSS (cont.)
Next, the data must be entered in the data view of the SPSS Data Editor:
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Instructionsfor the Student Version of SPSS
If you have the student version of
SPSS, you must run all procedures
from the pull-down menus. Fortunately, this is easy for the one-
sample t-test.
First select the correct procedure from
the „analyze‟ menu see next slide
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The ‘analyze’ menu
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The ‘test variable’
Next, you must move the „test variable‟, in thiscase IQ, into the right-hand pane by pressingthe arrow button and change the „test-value‟
to 100 (our standard for comparison). Lastly, click „OK‟ to view the results:
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Instructions forFull Version of SPSS (Syntax Method)
An alternate method for obtaining the sameresults is available to users of the full-version of SPSS.
This method, known as „syntax‟, isdescribed here, because many common anduseful procedures in statistics are onlyavailable using the syntax method.
Users of the student version may wish to
skip ahead to „Results from the SPSSViewer.‟
To use syntax, first you must open thesyntax window from the „file‟ menu:
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The ‘file’ menu
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SPSS syntax
The following is generic syntaxfor the one-sample t-test:
t-test testval= TestValue
/variables= TestVariable.
The SPSS syntax above requires that yousubstitute two values.
First, you need the „ TestValue‟ againstwhich you are judging your sample.
In example 2.1, this standard is „100.‟
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TestVariable
Next, you must substitute the „ TestVariable,‟
as shown below:
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Results from SPSS Viewer
After selecting „Run – All‟ from the menu, the
results will appear in the SPSS output window:
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SPSS calculations
When using SPSS, we no longer have acritical value to compare our calculatedt-value.
Instead, SPSS calculates an exactprobability value associated with the „t.‟
As a consequence, when writing the resultswe simply substitute this exact value, rather
than using the less precise „p < .05‟ (per our hand-calculations above).
Notice that SPSS calls p-values „Sig.,‟ whichstands for significance.
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SPSS calculations NOTE: SPSS only gives us the
p-value for a 2-tailed t-test.
In order to convert this value into a one-tailed test, per our example, we need todivide this „sig (2-tailed)‟ value in half (e.g., .033/2=.02, rounded).
Why?
In short, one-tailed t-tests are twice aspowerful, because we simply assume thatthe results cannot be different in thedirection opposite to our expectations.
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Conclusions in APA Style
Focusing attention on the bold
portion of the output, we canre-write our conclusion in APA style:
The mean intelligence score of
undergraduates at Thorndike University
(M = 120) was significantly higher thanthe standard intelligence score (M =
100), t(5) = 3.15, p = .02 (one-tailed).
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Big t Little p ?
Remember from a previous session thatevery t-value that we might calculate isassociated with a unique p-value.
In general, t-values which are large inabsolute magnitude are desirable, becausethey help us to demonstrate differencesbetween our computed mean value and the
standard. Values of t that are large in absolute
magnitude are always associated with smallp-values.
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Significance According to tradition in psychology,
p-values which are lower than .05 aresignificant, meaning that we will likely
still find differences if we collectedanother sample of participants.
When using SPSS we are no longer
confronted with a „critical value.‟Instead, we can simply observe thatthe p-value is less than „.05.‟
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Accepting the null hypthosis
The conclusion as to whether to rejectthe null hypothesis will be the same ineach circumstance; whether computed
by-hand or by-computer.
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The One-Sample t-Test
Advanced Research Methods in Psychology
Week 1 lecture
Matthew Rockloff
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