albert comerma (pi)
TRANSCRIPT
Advanced Analog Building Blocks
Differential amplifiers
Albert Comerma (PI)([email protected])
Course web
SoSe 2017
• Next lectures after holidays:• 25.5 → lecture Friday 26th
• 15.6 → lecture Friday 16th
Should we proceed as normal days (attendance)?
Run some more cadence lab on one of those days?
IntroductionAmplifier configurations
Miller EffectDifferential amplifier key elementsThe Differential Pair
Introduction: Miller Effect
i1 = v1−v2Z = v1+Kv1
Z = 1+KZ v1
v1i1
= Z1+K = 1
(1+K)Cs
i2 = v2−v1Z =
v2+v2K
Z =1+ 1
KZ v2
v2i2
= Z1+ 1
K
= 1
(1+ 1K )Cs
C1 = (1 + K )CC2 =
(1 + 1
K
)C
for K >> 1→ C1 >> C , C2 ≈ C
Caution!
Miller effect is usually calculated forK(w) at medium frequencies.Extrapolation to high frecuenciesproduces error.
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 1 / 13
IntroductionAmplifier configurations
Miller EffectDifferential amplifier key elementsThe Differential Pair
Introduction: Differential amplifier key elements
• Two terminals input (differential).
• Flexibility in configuration / feedback options (OPamp).
• Commmon mode: DC voltage present at both inputs.
• Differential input: small signal present at input: V+ − V−• Common Mode Rejection Ratio, CMRR: immunity to changes in
common mode.
• Power Supply Rejection Ratio, PSRR: immunity to changes in powersupply.
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 2 / 13
IntroductionAmplifier configurations
Miller EffectDifferential amplifier key elementsThe Differential Pair
The Differential Pair: circuit basics
• Usually a difference of voltages need to be amplified.
Assuming both in saturation:V1 = V2 → ID1 = ID2 = Ib
2
V1 >> V2 → ID1 ≈ Ib → ID2 ≈ 0
Differential voltage:Vd = V1 − V2
Common-mode:
Vc = V1−V22
V1 = Vc + Vd2
, V2 = Vc − Vd2
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IntroductionAmplifier configurations
Miller EffectDifferential amplifier key elementsThe Differential Pair
The Differential Pair: small signal analysis
• Intrinsic gain in differential mode.
Av1 = vd1vd
= −gm1rds12
Transconductance amplifier (voltage to current conversion);
g1 = id1vd
= gm12
Caution!
Devices must be kept in saturation.
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 4 / 13
IntroductionAmplifier configurations
Active loadTelescopic cascodeFolded cascode N inputFolded cascode P input
Amplifier configurations: active load
Av1 = vo1vd
= −gm1(rds1//rds3)2
= −gm12(go1+go3)
Assuming M1 = M2,M3 = M4 thengm1 = gm2, go1 = go2, go3 = go4 the
differential gain is;
Avd = vo2−vo1vd
= −gm1go1+go3
Caution!
VG must guarantee that ID3 + ID4 = Ib
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 5 / 13
IntroductionAmplifier configurations
Active loadTelescopic cascodeFolded cascode N inputFolded cascode P input
Amplifier configurations: common mode gain
• Intrinsic gain in differential mode.
Neglecting the current flow in rds1;
Avc1 = vo1vc≈ −gm1rds3
1+2gm1rb
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 6 / 13
IntroductionAmplifier configurations
Active loadTelescopic cascodeFolded cascode N inputFolded cascode P input
Amplifier configurations: CMRR
CMRR =∣∣∣ Avd
Avc1
∣∣∣ = −go3(1+2gm1rb)2(go1go3
If go1 = go3,CMRR ≈ gm1rb2
CMRR
Increasing the differential pair transconductance or rb, the CMRRraises!.
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 7 / 13
IntroductionAmplifier configurations
Active loadTelescopic cascodeFolded cascode N inputFolded cascode P input
Amplifier configurations: assymetric
• Current mirror ensures currents are the sameand half Ib
Avd ≈ gm1go2+go4
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 8 / 13
IntroductionAmplifier configurations
Active loadTelescopic cascodeFolded cascode N inputFolded cascode P input
Amplifier configurations: assymetric frequency response
C1 = CGD1 + CBD1 + CGS3 + CGS4 + CBD3
C2 = CGD2 + CBD2 + CGD4 + CBD4 + CL
R1 = 1gm3
,R2 = 1go2+go4
Then (with gm1 ≈ gm2):
Av ≈ gm12
R2ω2s+ω2
(1 + gm4R1ω1
s+ω1
)where ω1 = 1
R1C1, ω2 = 1
R2C2
Av = Av (0)
(s
ω′1
+1
)(
sω1
+1)(
sω2
+1)
Av (0) = gm1R22
(1 + gm4R1) ≈ gm1go2+go4
, ω′1 = ω1(1 + gm4R1) ≈ 2ω1
A pole-zero pair is obtained, with the zero at double frequency of the pole.The dominant pole is: ω2 = go2+go4
C2c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 9 / 13
IntroductionAmplifier configurations
Active loadTelescopic cascodeFolded cascode N inputFolded cascode P input
Telescopic cascode amplifier
VB ,VBCN ,VBCP are DC biasvoltages generated externally toset stauration opperation point.
• Gain: Ad = (gmrds )2
2
• Cuttoff frequency: ωt = gm1CL
(other poles also)
• Output swing: VDD − 5Veff
(Veff = VGS − VTH)
Low Gain, Low output swing butfast and low power.
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 10 / 13
IntroductionAmplifier configurations
Active loadTelescopic cascodeFolded cascode N inputFolded cascode P input
Folded cascode N input
• Slower
• Wider outputswing
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 11 / 13
IntroductionAmplifier configurations
Active loadTelescopic cascodeFolded cascode N inputFolded cascode P input
Folded cascode N input
• Gain: Ad = (gmrds )2
2
• Cuttoff frequency: ωt = gm1CL
(other poles also)
• Output swing VDD − 4Veff
• Wider output swing
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 12 / 13
IntroductionAmplifier configurations
Active loadTelescopic cascodeFolded cascode N inputFolded cascode P input
Folded cascode P input
c©[email protected] Advanced Analog Building Blocks: Differential amplifiers 13 / 13