afm objective 1.01. polynomials have more than one term: ◦ 2x + 1 ◦ 3x 2 + 2x + 1 the fancy...
TRANSCRIPT
Polynomial FunctionsAFM Objective 1.01
Polynomials have more than one term:◦ 2x + 1◦ 3x2 + 2x + 1
The fancy explanation:◦ f(x) = anxn + an-1xn-1 + …+ a2x2 + a1x + a◦ Ex: 4x3 + 3x2 + 2x + 1
Simply put: the addition and subtraction of terms with different exponents going from largest to smallest
Polynomial Functions
Polynomial functions are named by their degrees
The largest exponent is the degree of the function
Polynomial Functions
4x3 + 3x2 + 2x + 1
This has a degree of 3
Leading Term:◦ The term with the highest exponent
◦ This function has a degree of 3
◦ By knowing the leading term we can analyze a function without graphing it
*The highest exponent may not be written first in the function!!
Polynomial Functions
4x3 + 3x2 + 2x + 1
What are the degrees of the following polynomial functions?
1. 3x5 – 2x4 + 9x – 2
2. -6x3 + 2x2 – 7x + 10
3. 2x11 + 5x6 – 3x2
4. 4x2 + 5x4 – 2x3 + x – 5
Quick Quiz 1
What are the degrees of the following polynomial functions?
1. 3x5 – 2x4 + 9x – 2
2. -6x3 + 2x2 – 7x + 10
3. 2x11 + 5x6 – 3x2
4. 4x2 + 5x4 – 2x3 + x – 5
Quick Quiz 1
Degree of 5
Degree of 3
Degree of 11
Degree of 4
Certain polynomial functions have similar qualities.
We will use the Leading Term to analyze the behavior of a function
For simplicity sake we will just use the function f(x) = axn
Polynomial Functions
If a is positive and n is an odd number what kind of equations will you get?◦ 2x◦ 4x3
◦ 7x5
Here’s an example:
axn
Here’s another example: Notice how the
straight line and this line both point down on the left and up on the right
The have the same “end behavior”
axn
All equations that have a positive a and odd n have the same end behavior
axn
If a is negative and n is odd it will change the end behavior (ex: -2x3)
axn
If a is positive and n is an even number what kind of equations will you get?◦ 2x2
◦ 4x4
◦ 7x6
Here’s an example: Notice that both
ends point the same way, up!
axn
All equations where a is positive and n is an even number will have the same end characteristics:
axn
If a is negative and n is an even number it will change the end behavior
Here’s an example: Notice that both
ends still point the same way but down
axn
All equations where a is negative and n is an even number the end behavior will be:
axn
What is the end behavior of the following functions?
1. f(x) = 3x3
2. f(x) = 4x6 – 2x2 + 1
3. f(x) = -3x2 + 2x – 5
4. f(x) = 4x – 5x5 + 3x3
Quick Quiz 2
What is the end behavior of the following functions?
1. f(x) = 3x3
2. f(x) = 4x6 – 2x2 + 1
3. f(x) = -3x2 + 2x – 5
4. f(x) = 4x – 5x5 + 3x3
Quick Quiz 2
Turning Points:◦ Where the graph changes direction
Turning Points
Turning Point
◦ It goes from increasing to decreasing or the other way around
This is a cubic (x3) function and it has 2 turning points
Turning Points
Turning Point
This is also a cubic (x3) function
Turning Points
Notice there are no Turning Points!
This function never changes it’s direction
*Cubic (x3) functions can have up to 2 Turning Points
This is a quartic (x4) function
Turning Points
Turning Point
This is also a quartic (x4) function
Turning Points
Notice there is just one Turning Point!
This function only changes direction once
*Quartic (x4) functions can have up to 3 Turning Points
If you look at the exponent on the Leading Term you can analyze up to how many Turning Points there can be
Turning Points
axn Has up to n – 1 turning points
Up to how many possible turning points do the following functions have?
1. 3x5 – 2x4 + 9x – 2
2. -6x3 + 2x2 – 7x + 10
3. 2x11 + 5x6 – 3x2
4. 4x2 + 5x4 – 2x3 + x – 5
Quick Quiz 3
Up to how many possible turning points do the following functions have?
1. 3x5 – 2x4 + 9x – 2
2. -6x3 + 2x2 – 7x + 10
3. 2x11 + 5x6 – 3x2
4. 4x2 + 5x4 – 2x3 + x – 5
Quick Quiz 3
4
2
10
3
A zero is the x value when the function crosses the x-axis
Zeros
Zeros This is a quartic
(x4) function Notice it has 4
zeros
This is also a quartic (x4) function
Zeros
Zeros Notice it has only
2 zeros The others are
“imaginary”*Quartic functions
can have up to 4 real zeros
If you look at the exponent on the Leading Term you can analyze up to how many Zeros there can be
Zeros
axn Has up to n real zeros
Remember that when a line crosses the x-axis, the y value is zero.
Any point that is (x, 0) is a “zero” or x-intercept
You can find some of the zeros by solving the equations
Zeros
Example: Determine all the real zeros for
This is a cubic function so it can have up to 3 real zeros
First set the function equal to zero (y is zero)
We need to factor to find the solutions
Zeros
x3 – 5x2 + 6x
Find a common factor and pull it out Factor what’s left inside the parenthesis
Zeros
x3 – 5x2 + 6x = 0x(x2 – 5x + 6) = 0x(x – 2)(x - 3) = 0
Set each part of the function equal to zero Solve each one for x
Zeros
x(x – 2)(x - 3) = 0x - 3 = 0x – 2 = 0x = 0
x = 0, 2, 3
Example 2: Determine all the real zeros for
We know this will have up to 4 real zeros Also, this equation is in quadratic form since
we can write it like:
Zeros
x4 – 8x2 + 15
(x2)2 – 8(x2) + 15
Two x2’s One x2 A #
In order to factor this properly we can replace the x2’s with the letter u
We now have an equation we can factor!
Zeros
(x2)2 – 8(x2) + 15(u)2 – 8(u) + 15
Factor u2 – 8u + 15
Remember, u is equal to x2
Plug x2 in for u
Zeros
(u)2 – 8(u) + 15(u – 3)(u - 5)
(x2 – 3)(x2 - 5)
Solve each one for x
Zeros
x2 – 5 = 0x2 – 3 = 0
x2 = 3 x2 = 5
x = ±
x = ±
Determine all the real zeros for
This can have up to 4 real zeros
Factor out the GCF first (always take the negative with the first number)
Zeros
-x4 – x3 + 2x2
-x2(x2 + x – 2)
Factor inside the parenthesis
Set everything equal to zero
Zeros
-x2(x2 + x – 2)-x2(x + 2)(x – 1)
Solve each part for x
Zeros
-x2 = 0
-x2(x + 2)(x – 1)
-1 -1x2 = 0x = ± 0
Notice that you have two answers of zero
This is called “Multiplicity”
Multiplicity- when you have a repeated zero (answer)
Zeros
x = ± 0
Solve each part for x
Zeros
x + 2 = 0 x – 1= 0
x = -2 x = 1