acids/bases notes one unit eleven
DESCRIPTION
Acids/Bases Notes One Unit Eleven. Pages 541-549. Properties of Acids Properties of Bases Structure of Bases Neutralization Reactions Lab Acid/Base Properties Next Class. Part I Effect of acids and base on indicators. - PowerPoint PPT PresentationTRANSCRIPT
Acids/Bases Notes One Unit Eleven
Properties of Acids Properties of BasesStructure of Bases Neutralization ReactionsLab Acid/Base Properties Next Class
Pages 541-549
Part I Effect of acids and base on indicators• 1. Stand 3 clean, dry test tubes in the test tube rack. Add
about 2 mL of 6M HCl to one of the test tubes, 2 mL of 6M HC2H3O2 to a second tube, and 2 mL of 0.5 M NaOH to the third tube. CAUTION: Handle these chemicals with care. Test each solution first with red litmus paper and then with blue litmus paper.
• 2. Test each solution with pH paper.• 3. Add 1 drop of phenolphthalein to each solution. Discard
the solutions as instructed. Clean and rinse the test tubes.
Part IV Neutralization• 1. Using a clean dropper pipette, add 10 drops of
1.0M HCl and 1 drop of phenolphthalein to a test tube. Test with pH paper.
• 2. Using a second dropper pipette, add 0.5M NaOH drop-by-drop. After the addition of each drop, swirl the test tube gently mix the contents. Count the total number of drops of NaOH needed to cause a color change. Once a color change is observed, test the mixture with pH paper. Number of drops of 0.5M NaOH to neutralize 10 drops of 1.0M HCl _________. pH of neutral solution:_________
Lime Water Test For CO2
Zinc with hydrochloric acid
Metals With Acid
Questions on Lab
• 5. What type of reaction occurs between a metal and an acid? Write a general equation for this type of reaction.
• Single• M+ A------->H2+ salt• 6. Explain the difference in reaction rates of a given metal with two
different acids. • HCl is a strong acid. It makes more H3O+1. More H3O+1 means
faster reaction.• 7. Write a balanced equation for the reaction between CO2 gas and lime
water, Ca(OH)2. What is the name of the milky precipitate that forms?• Ca(OH) 2 + CO2 ------>CaCO3+ H2O• 8. Explain the difference in the volumes (number of drops) of HCl and
NaOH required to produce a neutral solution in Part 4 of this experiment.
• 10 drops to 20 drops means the base is half the concentration.
Notes One Unit ElevenProperties of Acids
Properties of Bases
Structure of Bases
Neutralization Reactions
Properties of AcidsSour taste.
warhead
React with “active” metals produce H2. Al, Zn, and Fe
React with carbonates, producing CO2 and H2O.
Marble, baking soda, chalk, limestone.
Change color of vegetable dyes.cabbage juice / On the top
cabbage juice / baking soda (left)
cabbage juice / vinegar (right).
Acidsacid - proton donor (H+1)
strong vs. weak acids
strong - lots of (H+ )
weak - very little (H+ )
HCl is a strong acidMuriatic acid is
hydrochloric acid.Making Bleach.Making PVC pipe.Making Table Salt.Human stomach acid.Cleaning steel.Neutralize bases in
chemical plants. Chrome tanning leather.
HNO3 is a strong acid
Explosives Fertilizers etc.Nitrate salts To make H2SO4
Etching copper, brass, bronze
Dyes, perfumesPurification of Ag, Au, Pt
Properties of BasesAlso known as alkali.( Li, Na, K, Rb, Cs, Fr)
Taste bitter.caffeineoften poisonous.
Solutions feel slippery.
Change color of vegetable dyes.Different color than acid.
Red litmus turns blue.React with acids to form salt and
water(Neutralization).Acid + base salt +water
Common Base Features
Most ionic bases contain OH-1 ions.
NaOH (drain cleaner)
Some contain CO32- ions.
CaCO3(in Tums)
NaHCO3 (baking soda)
Molecular bases contain structures that react with H+.
Mostly amine groups(-NH2).
Neutralization Reactions
acid + base salt + water
Double-displacement
Some make CO2 and H2O
Acid+carbonate Salt +Water+Carbon DioxideAcid+Base Salt +WaterAcid+Metal Salt +Hydrogen
Acid Reactions
Acid and CarbonateAcid+
Na2CO3 CarbonateSalt+ Water+Carbon Dioxide
HNO3+ NaNO3 + H2O + CO22 1 2 1 1
H+1 NO3-1 Na+1 CO3
-2
NaNONaNO33
=Sodium Nitrate=Sodium Nitrate( )_( )_NaNa+1+1 NONO33
-1-11111
Salt ?Salt ?
Acid and BaseAcid+
KOH Base Salt + Water
H2SO4+ KK22SOSO44 + H2O 1 2 1 2
H+1 SO4-2 K+1 OH-1
KK22SOSO44
=Potassium Sulfate=Potassium Sulfate( )_( )_KK+1+1 SOSO44
-2-21122
Salt ?Salt ?
Acid and MetalAcid+
Mg(s) Metal Salt + Hydrogen
H2SO4 + MgMgSO4 + H2(g)1 1 1 1
H+1 SO4-2 Mg(s)
MgMgSO4
= Magnesium Sulfate= Magnesium Sulfate
( )_( )_MgMg+2+2 SO4-2
2222
Salt ?Salt ?
Titration Example One
NaOH(aq)+ HCl(aq) NaCl(aq) + H2O(l)
0.000599 m HCl x1 m NaOH
1 m HCl=
1 1 1 1
What is the molarity of a NaOH solution, if 12.01 mL is required to titrate 5.99 mL of 0.100 M HCl?1. Balance the equation.
2. Find moles used of known solution.
3. Calculate moles used of unknown (titrant).
4. Calculate the molar concentration of the titrant.
MxV=n0.00599L = 0.100M x 0.000599m HCl
n/V=M0.000599m NaOH ÷0.01201L= 0.0499M NaOH
0.000599m NaOH
Notes Two Unit Eleven -Text Pages 550-558
Self Ionization of Water
Brönsted-Lowrey Acid-Base Theory
Arrhenius TheoryPages 550-558
Self Ionization of Water
• Water is and acid and a base at the same time…amphoteric
• H2O(l) + H2O(l) H3O+ + OH-
• Mass Action Expression• Kw = [H3O+][OH-] • Or Kw = [H+][OH-] • Kw = 1.0 x 10-14
Brönsted-Lowrey Acid-Base Theory• Acid - proton donor • Base - proton acceptor• Acid-Conjugate Base / Base-Conjugate Acid
• HCl(aq) + H2O(l) Cl−1(aq) + H3O+1(aq)
• NaF(aq) + H2O(l) HF(aq) + NaOH(aq)
• OH−1(aq) + H2O(l) H2O(l)+ OH−1(aq)
• NH3(aq) + H2O(l) NH4+1(aq) + OH−1(aq)
A CB
A
A
CB
CB
CB
A
CAB
B
B
B
CA
CA
CA
H+1
Arrhenius Theory• Bases form OH- ions in water.• Acids form H+ ions in water.
Arrhenius theory
• HCl(aq) H+1(aq) + Cl−1(aq)
• HF(aq) H+1(aq) + F−1(aq)
• NaOH(aq) Na+1(aq) + OH−1(aq)
• NH3(aq) +H2O(aq) NH4+1(aq) + OH−1(aq)
Polyprotic Acids• More than one proton to donate.
• H2CO3(aq) H+1(aq) + HCO3-1(aq)
• HCO3-1(aq) H+1(aq) + CO3
-2(aq)
• H2SO4 H+1(aq) + HSO4−1(aq)
• HSO4−1 H+1(aq) + SO4
−2(aq)
Notes Three Unit Eleven
Titration
Pages 574-578
Titration• Titration is a technique to determine
the concentration of an unknown solution.
• Titrant (unknown solution) • Phenolphthalein identifies the
Endpoint.
Titration Endpoint• Add 10mL of HCl and three drops phenolphthalein to the flask.• Add about 8mL base, swirl and add the rest of the base using
increasingly faster spins of the valve.(?????)
Titration-Acid Volume
• Acid Burette
• Initial Reading?
• 1.98mL
• Final Reading?
• 7.97mL
• Volume Used?
• 5.99mL
Titration-Volume of Base Used.
• Base Burette
• Initial Reading?
• 0.00mL
• Final Reading?
• 12.01mL
• Volume Used?
• 12.01mL
Titration Example Two• Lactic acid Concentration of Sauerkraut
• For Joe’s final in chemistry, he was asked to find the concentration of lactic acid in homemade sauerkraut.
• He did not have any home made sauerkraut.
• Therefore, Joe was left to make the home made sauerkraut.
• He looked on line and found the following recipe.
Clean and Quarter 35lb of Fresh Cabbage
Shred the Cabbage into a Crock
Add 3 Tbsp salt per 5 pounds of cabbage.
Mix salt and cabbage.
Pack the cabbage into a
crock and weight it down.
It should be fermented in one month.
Titration Example Two
NaOH + HC2H4OHCO2 NaC2H4OHCO2 + H2O
0.0899m NaOHx1m HC2H4OHCO2
1 m NaOH=
1 1 1 1
What Is the molarity of a sauerkraut juice if 10.0 mL is titrated using 89.9 mL of 1.00 M NaOH?1. Balance the equation.
2. Find moles used of known solution.
3. Calculate moles used of unknown (titrant).
4. Calculate the Molar Concentration of theTitrant.
MxV=n1.00M x 0.0899L = 0.0899m NaOH
n/V=M0.0899m HC2H4OHCO2÷0.01201L =
M=0.0899M HC2H4OHCO2
0.0899m HC2H4OHCO2
M
Titration Example Three
Ba(OH)2(q) + HCl(aq BaCl2(aq)+ H2O(l)
0.00463 m HCl x1 m Ba(OH)2
2 m HCl=
1 2 1 2
What is the volume of a 0.0622M Ba(OH)2 solution, if it is titrated using 43.8 mL of 0.1057 M HCl?1. Balance the equation.
2. Find moles used of known solution.
3. Calculate moles used of unknown (titrant).
4. Calculate volume of titrant.
MxV=n0.1057M x 0.0438L= 0.00463m HCl
n/M=V0.00234m Ba(OH)2 ÷0.0622M = 0.0376M Ba(OH)2
0.00232 m Ba(OH)2
Lab B Titration Results
Calculations• For each trial, calculate the molarity of the NaOH
solution using the relationship• Conclusion and Question• 1. How reproducible were the results of your four
trials?
Trial #1 Trial #2 Trial #3 Trial #4
HCl NaOH HCl NaOH HCl NaOH HCl NaOH
Intial reading 0.01 0.21 11.06 21.10 21.21 31.35 31.34 42.00
Final reading 11.05 11.27 21.00 31.54 31.33 42.07 38.95 49.99
Volume used 11.04 11.60 9.94 10.44 10.21 10.72 7.61 7.99
Table a
Conclusions continued
• 2. Define these terms: standard solution; titration; endpoint.
• Standard Solution: When the concentration of a solution is known to a high degree of accuracy and precision.
• titration: When the concentration of an acid or base is determined by neutralizing it.
• endpoint: The point where you actually stop a titration, usually because an indicator has changed color. This is different than the "equivalence point" because the indicator might not change colors at the exact instant that the solution is neutral.
Notes Three Unit Eleven
Weak Acid/Base
pH Scale
Calculating pHPages 559-567
Which acid is stronger?
6M HCl 6M HC2H3O2
zinc
magnesium
iron
copper
Weak Acids and Bases
• A weak acid
• little H+1
• A weak base
• little OH-1
• [H+] or [OH-] from a Keq.
pH = -log[H+1]pH is a measure of the amount of hydrogen in a solution. It is based on the water.
pH Scale
0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 Acid BaseNeutral
1M HCl 1M NaOHAmmonia Cleaner
Blood
WaterMilk
Stomach Acid
Lemon Juice
Vinegar
pH +pOH =14 pH +pOH =14
pH of strong acid
•Find the pH of a 0.15 M Find the pH of a 0.15 M solution of Hydrochloric solution of Hydrochloric acidacid
•pH = - log 0.15pH = - log 0.15•pH = - (- 0.82)pH = - (- 0.82)•pH = 0.82pH = 0.82
pH of a strong Base
•What is the pH of the What is the pH of the 0.0010 M NaOH solution?0.0010 M NaOH solution?
•pOH = - log (0.0010)pOH = - log (0.0010)
•pOH = 3pOH = 3
•pH = 14 – 3 = 11pH = 14 – 3 = 11pH +pOH =14 pH +pOH =14
Ionization Constants for Ionization Constants for Acids/Bases Acids/Bases
Calculating pH (pH=-log[H+1])The Ka for nitrous acid is 4.5 x 10-4. Calculate the [H+1] and pH in 0.15 M nitrous acid solution.
HNO2 NO2-1 + H+1
[HNO2 ] [NO2-1] [H+1]
Bef
ΔAt
[HNO2][H+1][NO2
-1]Ka=
-x +x +x0.15-x x x
0.15 0 0
Ka= [0.15][x][x]
= 4.5 x 10-4
X=[0.0082M]
1) Balanced Equation
2) Mass Action Expression3) What do we know?
4) Calculate the [H+1] and pH.
Very small
= [H+1] pH=-log[ ]0.0082M
pH=-log[H+1]
= 2.09
4.5 x 10-4
1.5 x 10-1
Calculating Concentrations Using Ka
The Ka for benzoic acid is 6.5 x 10-5. (a) Calculate the concentrations of C6H5COO-1 and H+ in a 0.10 M benzoic acid solution. (b) Calculate pH.
C6H5COOH C6H5COO-1 + H+1
[C6H5COOH] [C6H5COO-1] [H+1]
Bef
ΔAt
[C6H5COOH][H+1][C6H5COO-1]
Ka=
-x +x +x
0.10-x x x
0.10 0 0
Ka= [0.10][x] [x]
= 6.5 x 10-5
X=[0.0025M]
1) Balanced Equation
2) Mass Action Expression3) What do we know?
4) Calculate the [H+1] and pH.
Very small
= [H+1]pH=-log[ ]0.0025M = 2.60
6.5 x 10-5
1.0 x 10-1
End