acids & bases i. properties of acids & bases-_____ taste ____ and produce a _______...
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Acids & Bases
I. Properties of Acids & Bases -_____ taste ____ and produce a _______ sensation to the touch
Hydrangea – the color varies depending on the relative acidity or basicity of the soil
-______ acid and ________ acid, (also known as _______ __), are _____ _____ responsible for the _______ of ______ and other ______, while ______ ____ makes _______ taste ____, and in our body, the unpleasant ________ and _______ _________ produced by our _____ is due to ___________ ____ in our ________
acids sourburning
citric ascorbicVitamin C
weak acidstartness citrus
fruits
sournessburning sensation
vomit hydrochloricacid stomach
acetic acidvinegar sour
Acids & Bases
I. Properties of Acids & Bases -because _____ ____ and _______ ________, (and all ______ ______ are made of _______), in ______, they are often used as a _______
acids burn denatureproteins living things
proteins naturedefense
-____, ____, ______, and ______ all use ______ ____ to ______ themselves, while the human _______ is guarded against _______
by ___________ ____, the human ______ is guarded against _______ by ______ ____ (produced by _____- _________ _______ of the genus ___________), and even human ____ is guarded by ____ ____ in our _____
bees ants nettles onionsformic acid defend
stomach bacteriahydrochloric acid
vagina bacterialactic acid
sugar fermenting bacteriaLactobacillus
skin uricacid sweat
Stinging Nettle
Acids & Bases
I. Properties of Acids & Bases -_____ react with ______, especially the more ______ ______, to produce ________ ___
acids metalsactive metals
hydrogen gas
2HCl (aq) 1ZnCl2 (aq)1Zn (s) + 1H2 (g)+
6HNO3 (aq) 2Al(NO3)3 (aq)2Al (s) + 3H2 (g)+
-_____ react with _________ and ________ _________ to produce ______ _______
acids carbonateshydrogen carbonatescarbon dioxide
2HCl (aq) 1CaCl2 (aq)1CaCO3 (s) + 1H2O (l)+
HC2H3O2 (aq) 1NaC2H3O2 (aq)1NaHCO3 (s) + 1H2O (l)+
1CO2 (g)+
1CO2 (g)+
They don’t justtaste “chalky”,
they are chalk!
Acids & Bases
I. Properties of Acids & Bases
Write the balanced thermochemical equation for the reaction that occursbetween:
1. Magnesium and Nitric acid
2. Aluminum and Sulfuric acid
3. Calcium carbonate and Hydrobromic acid
4. Potassium Hydrogen carbonate and Hydrochloric acid
2HNO3 (aq) 1Mg(NO3)2 (aq)1Mg (s) + 1H2 (g)+
3H2SO4 (aq) 1Al2(SO4)3 (aq)2Al (s) + 3H2 (g)+
2HBr (aq) 1CaBr2 (aq)1CaCO3 (s) + 1H2O (l)+ 1CO2 (g)+
1HCl (aq) 1KCl (aq)1KHCO3 (s) + 1H2O (l)+ 1CO2 (g)+
Acids & Bases
I. Properties of Acids & Bases
A. Safety:
1. Hypothesis: Which common household materials are acids or bases?
2. Prediction:
3. Gather Data:
The acids and bases used in this lab are mildly corrosive and cause irritation of the skin, eyes, and mucous membranes. Avoid contact. Use caution. Goggles mandatory.
B. Procedure:
1. Using a pipette, place 3 or 4 drops of each solution in a separate test well of a microplate.
Acids & Bases
I. Properties of Acids & Bases
3. Gather Data:
B. Procedure:
2. Test each liquid with litmus paper. Record results.
3. Test each liquid with 2 drops of phenolphthalein. Record results.
Great Value™
Glass
Cleaner
Chlorox®
Bleach
Sprite® Hy-Vee®
Vinegar
Parson’s®
All-Purpose Cleaner
Hy-Vee®
Orange
Juice
Litmus
Color
(blue or pink)
Phenolphthalein
Color
(clear or pink)
Acid or Base
Acids & Bases
II. Ions in Solutions of Acids & Bases -the relative amounts of ____ and ____ ions in ________ _______ determine the _______ ______, _______, or ________ of the ________
H+
OH- aqueoussolutionrelative aciditybasicity neutrality
Red tulip changes color in varying pH
Purple iris changes color in varying pH
solution
-an _______ _______ that contains more ___ than ____ is an ______ _______
aqueous solutionH+ OH-
acidic solution
-an _______ _______ that contains more ____ than ___ is an _____ _______
aqueous solutionOH- H+
basic solution
-an _______ _______ that contains _____ amounts of ___ and ____ is _______
aqueous solutionequal
H+ OH- neutralhttp://bradley.bradley.edu/~campbell/demopix5.html
Acids & Bases
II. Ions in Solutions of Acids & Bases -_______ ________ that are neither ______ or _____ are _______, but _____ is _______ because it is ____ an ____ and a ____ at the same time, containing _____ amounts of ___ and ____
aqueous solutionsacids bases
neutral waterneutral both
acid baseequal
H+ OH-
Purple carnation changes color in varying pH
Peony changes color in varying pH
http://bradley.bradley.edu/~campbell/demopix5.html
-because of its _______, _____ ___________:
polaritywater self-ionizes
1H2O(l) 1H+ (aq) + 1OH-
(aq)
-but the ___ forms a _______ _____ with a ______ _____ ________, producing the __________ ____
H+ covalentbond another watermoleculehydronium ion
2H2O(l) 1H3O+(aq) + 1OH-
(aq)
Acids & Bases
III. The Arrhenius Model of Acids and Bases
-according to ______ _________, an ____ is a ________ that contains ________ and _______ to produce ________ ____ in _______ _______
Svante August Arrhenius1859 - 1927
Svante Arrheniusacid substancehydrogen ionizeshydrogen ions aqueous solution
-according to _________, ________ ________ is an _____
Hydrogenchloride
Arrheniusacid
1HCl (g) 1H+ (aq) 1Cl-
(aq)+
-according to _________, a _____ is a ________ that contains a _________ _____ and _________ to produce _________ _____ in _______ ________
Arrhenius basesubstance hydroxidegroup dissociateshydroxide ions aqueous solution
-according to _________, ________ _________ is a _____
Arrhenius Sodiumhydroxide base
1NaOH (s) 1Na+ (aq) 1OH-
(aq)+
Acids & Bases
IV. The Brønsted –Lowry Model of Acids and Bases
Johannes Nicolaus Brønsted1879 - 1947
Thomas Martin Lowry1874 - 1936
-according to ________-______, an _____ is a _________-____ ______ and a _____ is a ________- ____ ________
Brønsted Lowryacid hydrogen ion
donor basehydrogen ion acceptor
1H2O (l) 1H3O+(aq)1HX (aq) + 1X-
(aq)+Acid Base Conjugate
AcidConjugate
Base
-the _____, ______, _________ in _____ and _______ a ________ ____ to a ______ ________, which acts as a _____ by ________ the ________ ____
acid HX (aq) dissolveswater donates
hydrogen ion watermolecule base
accepting hydrogen ion
-a ____ that has ________ a ___ now has the ability to ______ a ___, and so becomes an _____; the _________ _____
base accepted H+
donateH+ acid
conjugate acid
Acids & Bases
IV. The Brønsted –Lowry Model of Acids and Bases
-according to ________-______, a _________ ____ is the ______ produced when a ____ accepts a ________ ___ from an ____
Brønsted Lowryconjugate acid species
basehydrogen ion acid
1H2O (l) 1H3O+(aq)1HF (aq) + 1F-
(aq)+Acid Base Conjugate
AcidConjugate
Base
-a _________ ____ is the ______ that is left over from the ____ after it donates a ________ ____
conjugate base speciesacid
hydrogen ion
Playing Hacky Sack in Zurich, Switzerland http://zurichdailyphoto.blogspot.com/2007/04/hacky-sack.html
How is playing Hacky Sack Like ConjugateAcid-Base Pairs?
Player passing Footbag
Footbag
Player receiving Footbag
Conjugate acid
Acid
Hydrogen ion
Base
Conjugate base
Player who passed Footbag
Player who received Footbag
Acids & Bases
IV. The Brønsted –Lowry Model of Acids and Bases
Label the acid, base, conjugate acid, and conjugate base in the following:
1H2O (l) 1NH4+
(aq)1NH3 (aq) + 1OH- (aq)+
1H2O (l) 1H3O+(aq)1HBr (aq) + 1Br-
(aq)+
1H2O (l) 1HCO3-(aq)1CO3
2- (aq) + 1OH- (aq)+
1H2O (l) 1H3O+(aq)1HSO4
- (aq) + 1SO42-
(aq)+
AcidBase ConjugateAcid
ConjugateBase
Acid Base ConjugateAcid
ConjugateBase
AcidBase ConjugateAcid
ConjugateBase
Acid Base ConjugateAcid
ConjugateBase
Substances that can act asboth an acid and a baseare called amphoteric,
as water is in these examples.
Acids & Bases
V. Monoprotic & Polyprotic Acids -____ and ___ are _____ according to the _________ _____ because they both contain _________ and they both donate a ________ ___ to an _______ ________
HCl HF acidsArrhenius
modelhydrogen
hydrogen ion aqueoussolution
Chemical burns caused by Hydrofluoric acid
-both ____ and ___ are also __________ _____ because each donates only ____ _________ ___ per ________
HCl HFmonoprotic acids
onehydrogen ion molecule
-_____ (______ _____), ______ (_________ _____), ____ (____________ _____), and _________ (______ or ________ _____) are other __________ ______
HNO3 Nitric acid HClO4
Perchloric acid HBrHydrobromic acid
CH3COOH aceticethanoic acidmonoprotic acids
CH
H
H
CO
O
H
Even though acetic acid has 4 hydrogenatoms, only 1 of the 4 has a polar enough
bond to be ionizable. The other 3 arepractically nonpolar bonds.
http://www.emedicine.com/emerg/topic804.htm
Acids & Bases
V. Monoprotic & Polyprotic Acids
CH
H
C
C
H
C
C
C
H
H
H
Benzene has 6 hydrogen atoms, but none of the covalent bonds
are polar enough to be ionizable,so benzene is not an acid at all.
-_____ that donate _____ than ____ _________ ___ are called _________
acids moreone hydrogen ionpolyprotic
-______(_______ _____) and ______(________ _____) are both _______ _____, while ______ (__________ ____) and ______ (______ _____) are both _________ ______
H2SO4
H2CO3
Sulfuric acidCarbonic acid
diprotic acidsH3PO4 Phosphoric acidH3BO3 Boric acid
triprotic acids
SO
O
O
OH
H
PO
O
O
OH
H
H
Sulfuric acid contains 2highly polar ionizable
covalent bonds
Phosphoric acid contains 3 highly polar ionizable
covalent bonds
Acids & Bases
V. Monoprotic & Polyprotic Acids -__________ _____ donate more than ____ ________ ____ to _______ _______ in more than ___ step
polyprotic acidsone hydrogen ion
aqueous solutionone
1H2O (l) 1H3O+(aq)1H3PO4 (aq) + 1H2PO4
- (aq)+
1H2O (l) 1H3O+(aq)1H2PO4
- (aq) + 1HPO42-
(aq)+
1H2O (l) 1H3O+(aq)1HPO4
2- (aq) + 1PO43-
(aq)+
-the ________ ____ __________ ____ donates __ ________ ____ in __ steps:
triprotic acid3 hydrogen ions
3
Phosphoricacid
PO
O
O
OH
H
H
Acids & Bases
V. Monoprotic & Polyprotic Acids
Write the steps for complete ionization of the following polyprotic acids:
H2Se (aq)
H3AsO4 (aq)
H2SO3 (aq)
H2O (l) H3O+(aq)+ 1HSe-
(aq)+
H2O (l) H3O+(aq)HSe- (aq) + Se2-
(aq)+
H2O (l) H3O+(aq)+ H2AsO4
- (aq)+
H2O (l) H3O+(aq)H2AsO4
- (aq) + HAsO42-
(aq)+
H2O (l) H3O+(aq)HAsO4
2- (aq) + AsO43-
(aq)+
H2O (l) H3O+(aq)+ HSO3
1- (aq)+
H2O (l) H3O+(aq)HSO3
1- (aq) + SO32-
(aq)+
Acids & Bases
VI. Acid & Base Anhydrides -__________ are _______ that form _____ and _____ when added to ______
anhydrides oxidesacids baseswater
1H2O (l) 1H2CO3 (aq)1CO2 (g) +
1H2O (l) 1HNO3 (aq)2NO2 (g) + + 1HNO2 (aq)
1H2O (l) 1H2SO3 (aq)1SO2 (g) +
1H2O (l) 1H2SO4 (aq)1SO3 (g) +
-______ of ___________ elements produce _____ in _______ _______, while ______ of ________ elements produce _____ in _______ ________
oxides nonmetallicacids aqueous solution
oxides metallicbases aqueous solution
1H2O (l) 1Ca2+ (aq)1CaO (s) + + 2OH-
(aq)
1H2O (l) 1Mg2+ (aq)1MgO (s)+ + 2OH-
(aq)
Acids & Bases
VII. Strength of Acids -______ _____ are _____ that ______ _________
strong acids acids ionizecompletely
1H2O (l) 1H3O+ (aq)1HCl (aq) + + 1Cl-
(aq)
-____ (___________ _____), ______ (__________ _____), _____ (______ ____), ____ (____________ _____), ______ (________ _____), and ___ (___________ _____) are all ______ _____
HCl Hydrochloric acid HClO4
Perchloric acid HNO3 Nitric acidHBr Hydrobromic acid H2SO4
Sulfuric acid HI Hydroiodicacid strong acids
-______ _____ are _____ that ______ only ________
weak acids acids ionizepartially
HC2H3O2 (aq) H2O (l) H3O+(aq)+ C2H3O2
- (aq)+
-________ (______ _____), ______ (________ _____), ___ (___________ ____), ______ (_____ _____), and _____ (___________ ____) are _____ _____
HC2H3O2 Acetic acid H2CO3
Carbonic acid HF Hydrofluoricacid H3BO3 Boric acid HCNHydrocyanic acid weak acids
Hydrofluoric acid is considered a weak acid because it doesn’t ionize
completely; it is expected to be a strong acid, because it is so corrosive, but its corrosiveness is due to the chemical reactivity of its anion, the fluoride ion.The strongest acids, the carborane
superacids, are a million times strongerthan concentrated sulfuric acid, but not
at all corrosive because the anion tothe acid is so unreactive.
Acids & Bases
VII. Strength of Acids -according to ______________, the ____ on the _______ side of the ________ _______ produces a ________ ____ on the ________ side of the _______ _______ by _______ a ________ ___
Brønsted-Lowry acidreactant forward reaction
conjugate base productforward reaction donating
hydrogen ion
1H2O (l) 1H3O+(aq)1HX (aq) + 1X-
(aq)+Acid Conjugate
Base
-if the ____ is a ______ ____, then its _________ ____ is _____, that is, if the ____ readily _______ a ________ ___, then its ________ ____ is not very good at ________a ________ ___, or holding on to one, while a ____ ____, which is not very good at _______ a ________ ___ has a ______ ________ ____
acid strong acidconjugate base weakacid donates hydrogen ion
conjugate baseaccepting hydrogen ion
weak aciddonating hydrogen ion
strong conjugate base
Acids & Bases
VII. Strength of Acids
-the __________ ________ __________ for the _________ of ____________ _____ is:
equilibrium constant expressionionization Hydrocyanic acid
Keq = [H3O+]1
[HCN]1
[CN-]1
[H2O]1
-the ___________ of ______ _____ is considered to be _______, and so can be _________ with ___ to give the _____ _________ _______, or ___
concentration liquid waterconstant
combined Keq acidionization constant Ka
Ka = [H3O+]1
[HCN]1
[CN-]1
1HCN (aq) 1H2O (l) 1H3O+(aq)+ 1CN-
(aq)+
-the _________ ________ for ___________ _____ is:
ionization equation Hydrocyanicacid
Acids & Bases
VII. Strength of Acids
Write ionization equations and acid ionization constant expressions for the following acids:
H2O (l) H3O+(aq)HClO2 (aq) + ClO2
- (aq)+
HNO2 (aq)
HIO (aq)
Ka = [H3O+]1
[HClO2]1
[ClO2-]1
H2O (l) H3O+(aq)+ NO2
- (aq)+
Ka = [H3O+]1
[HNO2]1
[NO2-]1
H2O (l) H3O+(aq)+ IO-
(aq)+
Ka = [H3O+]1
[HIO]1
[IO-]1
Acids & Bases
VIII. Strength of Bases-______ _____ are _____ that _________ _________
strong bases bases dissociatecompletely
1Na+ (aq)1NaOH (s) + 1OH-
(aq)
-______ (_______________), _____ (_________________), ______ (_________ _________), _____ (_______________), _______ (________________), and ______ (_______________) are all ______ _____
NaOH Sodium hydroxide KOHPotassium hydroxide
-______ _____ are _____ that ________ only ________
weak bases bases dissociatepartially
-________ (___________), ________ (__________), ____ (________), and ________ (______) are all _____ ______
CH3NH2
RbOH Rubidiumhydroxide CsOH Cesium hydroxideCa(OH)2 Calcium hydroxide Ba(OH)2Barium hydroxide strong bases
CH3NH2 (aq) H2O (l) CH3NH3+
(aq)+ OH- (aq)+
methylamine C2H5NH2
ethylamine NH3 ammoniaC6H5NH2 aniline weak bases
Acids & Bases
VIII. Strength of Bases
-the ____ __________ ________ __________ for the _________ of ___________ is:
acid ionization constantexpression ionizationhexylamine
Kb = [OH-]1
[C6H13NH2]1
[C6H13NH3+]1
1C6H13NH2 (aq) 1H2O (l) 1OH-(aq)+ 1C6H13NH3
+ (aq)+
-the ________ ________ for __________ is:ionization equation hexylamine
Base ConjugateAcid
Acid ConjugateBase
CH
H
H
C
H
H
C
H
H
C C
H
H
H
H
C
H
H
N
H
H
Hexylamine
Acids & Bases
VIII. Strength of Bases
Write ionization equations and base ionization constant expressions for the following bases:
H2O (l) OH-(aq)C3H7NH2 (aq) + C3H7NH3
+ (aq)+
CO32-
(aq)
HSO3- (aq)
Kb = [OH-]1
[C3H7NH2]1
[C3H7NH3+]1
H2O (l) OH-(aq)+ HCO3
- (aq)+
Kb = [OH-]1
[CO32-]1
[HCO3-]1
H2O (l) OH-(aq)+ H2SO3 (aq)+
Kb = [OH-]1
[HSO3-]1
[H2SO3]1
Acids & Bases
IX. Ion Product Constant for Water -the ________ ________ for ______ is:
ionization equationwater
H2O (l) OH-(aq)H2O (l) + H3O+
(aq)+
Base ConjugateAcid
Acid ConjugateBase
-the ________ ________ can be simplified to:
ionization equation
H2O (l) OH-(aq) H+
(aq)+
-the __________ _______ __________ is:
equilibrium constantexpression
Keq = [OH-]1
[H2O]1
[H+]1
Acids & Bases
IX. Ion Product Constant for Water -since _____ is a ______, its _____________ is equal to its _______, which is _______ at a _______ ___________ and ________, so the __________ _______ _________ can be simplified by __________ both sides by ______, creating the ___ _______ _______ ___ _____, ___
water liquidconcentrationdensity constant
constant temperaturepressure equilibriumconstant expression
multiplying[H2O]
ion product constant forwater Kw
Kw = [OH-]1 [H+]1
-at _____, the ____- _________ of _____ produces ____ = _________ and a ______ = _________, so ___ = _______
298 K self ionizationwater [H+]
1 x 10-7 M [OH-]
1 x 10-7 M Kw 1 x 10-14
Kw = (1 x 10-7)1 (1 x 10-7)1
Kw = 1 x 10-14
Acids & Bases
IX. Ion Product Constant for Water
What is the concentration of the hydroxide ion in an aqueous solution with a hydrogen ion concentration of 1 x 10-5 M? Is the solution acidic, basic, or neutral? Kw = [H+][OH-]
1 x 10-14 = [OH-](1 x 10-5)
[OH-] = 1 x 10-9 M
The solution is acidic, because the [H+] is greater (104) than the [OH-]
What is the concentration of the hydrogen ion in an aqueous solution with a hydroxide ion concentration of 1 x 10-3 M? Is the solution acidic, basic, or neutral? Kw = [H+][OH-]
1 x 10-14 = [H+](1 x 10-3)
[H+] = 1 x 10-11 M
The solution is basic, because the [OH-] is greater (108) than the [H+]
Acids & Bases
X. pH (pondus hydrogenii)
Søren Sørensen1868 - 1939
-in 1909, _____ ________ developed the ___ (________ _________) _____ as a way of conveniently expressing the ___________ of _____ and _____
Søren SørensenpH potential hydrogen scale
concentration acids bases
pH = -log [H+]
What is the pH of water?
pH = -log [H+]
pH = -log (1 x 10-7)
pH = 7.0
What is the pH of an aqueous solution inwhich the [H+] = 1.0 x 10-2 M?
pH = -log [H+]
pH = -log (1.0 x 10-2)
pH = 2.00
The number ofdecimal places inthe pH is equal to
the number of significant digits
in the [H+]1 sig. fig. in [H+],
1 decimal place in pH
2 sig. figs. in [H+],2 decimal place in pH
Acids & Bases
A. Safety:
1. Hypothesis: What is the relationship between the concentration of an acid and its pH?
2. Prediction:
3. Gather Data:
The acids used in this lab are corrosive and cause irritation and damage to the skin, eyes, and mucous membranes. Avoid contact. Use caution. Goggles mandatory.
B. Procedure: Serial Dilution
1. Using a pipette, place 10 drops of 1.0 M HCl in test well 1A of a microplate.
X. pH (pondus hydrogenii)
Acids & Bases
3. Gather Data:
B. Procedure:
2. Rinse the pipette, and transfer 1 drop of acid solution from test well 1A to test well 2A, and add 9 drops of distilled water.
3. Repeat Step 2, transferring 1 drop of acid solution from test well 2A to test well 3A and adding 9 drops of distilled water .
4. Repeat Step 2 six more times, each time transferring 1 drop of acid solution from the previous test well and adding 9 drops of distilled water.
X. pH (pondus hydrogenii)
Acids & Bases
3. Gather Data:
B. Procedure:
5. Test the pH in each well with pH indicator paper. Record.
6. Test the pH in each well with 1 drop of universal indicator solution. Record.
Test
Well
Number
A1 A2 A3 A4 A5 A6 B1 B2
[H+]
Concentration
pH
paper
pH
Universal
Indicator
X. pH (pondus hydrogenii)
Acids & Bases
4. Analyze Data:
A. What is [H+] in test well A4? ________________.
B. What is [H+] in test well A6? ________________.
C. What is the theoretical pH in test well A2? _______________.
D. What is the theoretical pH in test well B2? _______________.
A. Each step in the serial dilution ____________ the concentration of the hydrogen ion by a factor of _______ and __________ the pH by a factor of _______
5. Draw Conclusions:
E. The color of pH paper in test well A1 was _______, indicating an approximate pH of _______.
F. In test well A2 universal indicator was ________ in color.
X. pH (pondus hydrogenii)
Acids & Bases
XI. pOH (potential Hydroxide) -the _______, or ________, of a _______ can be expressed by the ____, or ________ _________:
basicity alkalinitysolutionpOH potential Hydroxide
pOH = -log [OH-]
What is the pOH of water?
pOH = -log [OH-]
pOH = -log (1 x 10-7)
pOH = 7.0
What is the pOH of an aqueous solution inwhich the [OH-] = 1.00 x 10-6 M?
pOH = -log [OH-]
pOH = -log (1.00 x 10-6)
pOH = 6.000
What is the pH of an aqueous solutionin which the [OH-] = 1.0 x 10-3 M?
pOH = -log [OH-]
pOH = -log (1.0 x 10-3)
pOH = 3.00
Kw = [OH-][H+]
= (1 x 10-7)(1 x 10-7)
=
1 x 10-14
14 pH + pOH
pH = 11.00
Acids & Bases
XI. pOH (potential Hydroxide)
What is the pH and the pOH of an aqueous solution with a hydroxide ion concentration of 1.0 x 10-6 M? Is the solution acidic, basic, or neutral?
What is the pH and the pOH of an aqueous solution with a hydroxide ion concentration of 6.5 x 10-4 M? Is the solution acidic, basic, or neutral?
What is the pH and the pOH of an aqueous solution with a hydrogen ion concentration of 3.6 x 10-9 M? Is the solution acidic, basic, or neutral?
pOH = -log [OH-]
pOH = -log (1.0 x 10-6)
pOH = 6.00
=14 pH + pOH
pH = 8.00
basic
pOH = -log (6.5 x 10-4)pOH = 3.19
pH = 10.81basic
pH = -log (3.6 x 10-9)pH = 8.44
pOH = 5.56basic
Acids & Bases
XI. pOH (potential Hydroxide)
What is the hydrogen ion concentration and the hydroxide ion concentration of a person’s blood that has a pH of 7.40 at 298 K?
What is the hydrogen ion concentration and the hydroxide ion concentration of an aqueous solution that has a pH of 2.37 at 298 K?
What is the hydrogen ion concentration and the hydroxide ion concentration of an aqueous solution that has a pH of 11.05 at 298 K?
pH = -log [H+]
7.40 = -log [H+]
[H+] = 4.0 x 10-8 M
=14 7.40 + pOH
6.60 = -log [OH-]
[OH-] = 2.5 x 10-7 M
2.37 = -log [H+]
[H+] = 4.3 x 10-3 M
11.63 = -log [OH-]
[OH-] = 2.3 x 10-12 M
Multiply [H+][OH-]to check your answer
(4.3 x 10-3)(2.3 x 10-12)=Kw
11.05 = -log [H+]
[H+] = 8.9 x 10-12 M
2.95 = -log [OH-]
[OH-] = 1.1 x 10-3 M
Multiply [H+][OH-]to check your answer
(8.9 x 10-12)(1.1 x 10-3)=Kw
Acids & Bases
XII. Calculating pH of Strong Acids and Strong Bases
What is the pH of a 1.0 M HI solution?
1H+ (aq)1HI (aq) + 1I-
(aq)
1.0 M 1.0 M 1.0 M
pH = -log [H+]
pH = -log (1.0)
pH = 0.00
What is the pH of a 0.050 M HNO3 solution?
1H+ (aq)1HNO3 (aq) + 1NO3
- (aq)
0.050 M 0.050 M 0.050 M
pH = -log [H+]
pH = -log (0.050)
pH = 1.30
What is the pOH of a 2.4 x 10-5 M Mg(OH)2 solution?
1Mg2+ (aq)1Mg(OH)2 (s) + 2OH-
(aq)
2.4 x 10-5 M 2.4 x 10-5 M 4.8 x 10-5 M
pOH = -log [OH-]
pOH = -log (4.8 x 10-5)
pOH = 4.32
pH = 9.68
Acids & Bases
XIII. Calculating pH of Weak Acids and Weak Bases
What is Ka of a 0.100 M formic (methanoic) acid solution with pH 2.38?
1HCOO-(aq)1HCOOH (aq) 1H+
(aq)+
Ka = [HCOO-]
[HCOOH]
[H+]
pH = -log [H+]
2.38 = -log [H+]
[H+] = 4.2 x 10-3 M
0.100 M 4.2 x 10-3 M 4.2 x 10-3 M
[HCOO-] = 4.2 x 10-3 M
[HCOOH] = 4.2 x 10-3 M0.100 M -
[HCOOH] = 0.0042 M0.100 M -
[HCOOH] = 0.096 M
Ka = (4.2 x 10-3 )
(0.096 )
(4.2 x 10-3 )
Ka = 1.8 x 10-4
Acids & Bases
XIII. Calculating pH of Weak Acids and Weak Bases
What is Ka of a 0.220 M arsenic acid solution with pH 1.50?
1H2AsO4-(aq)1H3AsO4 (aq) 1H+
(aq)+
Ka = [H2AsO4-]
[H3AsO4]
[H+]
pH = -log [H+]
1.50 = -log [H+]
[H+] = 3.2 x 10-2 M
0.220 M 3.2 x 10-2 M 3.2 x 10-2 M
[H2AsO4-] = 3.2 x 10-2 M
[H3AsO4] = 3.2 x 10-2 M0.220 M -
[H3AsO4] = 0.032 M0.220 M -
[H3AsO4] = 0.188 M
Ka = (3.2 x 10-2 )
(0.188 )
(3.2 x 10-2 )
Ka = 5.4 x 10-3
Acids & Bases
XIII. Calculating pH of Weak Acids and Weak Bases
What is Ka of a 0.0400 M chlorous acid solution with pH 1.80?
1ClO2-(aq)1HClO2 (aq) 1H+
(aq)+
Ka = [ClO2-]
[HClO2]
[H+]
pH = -log [H+]
1.80 = -log [H+]
[H+] = 1.6 x 10-2 M
0.0400 M 1.6 x 10-2 M 1.6 x 10-2 M
[ClO2-] = 1.6 x 10-2 M
[HClO2] = 1.6 x 10-2 M0.0400 M -
[HClO2] = 0.016 M0.0400 M -
[HClO2] = 0.024 M
Ka = (1.6 x 10-2 )
(0.024 )
(1.6 x 10-2 )
Ka = 1.1 x 10-2
Acids & Bases
XIII. Calculating pH of Weak Acids and Weak Bases
What is Ka of a 1.000 M propanoic acid solution with pH 2.43?
1C3H5O2-(aq)1HC3H5O2 (aq) 1H+
(aq)+
Ka = [C3H5O2-]
[HC3H5O2]
[H+]
pH = -log [H+]
2.43 = -log [H+]
[H+] = 3.7 x 10-3 M
1.000 M 3.7 x 10-3 M 3.7 x 10-3 M
[C3H5O2-] = 3.7 x 10-3 M
[HC3H5O2] = 3.7 x 10-3 M1.000 M -
[HC3H5O2] = 0.0037 M1.000 M -
[HC3H5O2] = 0.9963 M
Ka = (3.7 x 10-3 )
(0.9963 )
(3.7 x 10-3 )
Ka = 1.4 x 10-5
Acids & Bases
XIV. Neutralization -when an ____ and a ____ _____, the resulting _______ has _________ that are characteristic of _______ an ____ or a ____
acid base reactsolution properties
neither acid base
-a ____________ _______ is a ______- ___________ _______ in which an ____ and a ____ react in _______ ________ to produce a ____ and _____
neutralization reaction doublereplacement acidbase aqueous solutionsalt water
reaction
2HCl (aq) 1MgCl2 (aq)1Mg(OH)2 (aq) + + 2H2O (l)
Milk of Magnesiais a Magnesium hydroxide
suspension used toneutralize stomach acid
base acid salt water
-a ____ is an _____ _________ made up of the ______ from the ____ and the _____ from the ____
salt ionic compoundcation base anion
acid
-the ___ _____ ________ for a ____________ _______ is:
net ionic equation neutralizationreaction
H+ (aq)OH- (aq) + H2O (l)
Acids & Bases
XIV. Neutralization
Write the complete balanced thermochemical equations for the followingneutralization reactions and name the products:
Nitric acid + Cesium hydroxide
Hydrobromic acid + Calcium hydroxide
Sulfuric acid + Potassium hydroxide
1HNO3 (aq) 1CsNO3 (aq)1CsOH (aq)+ + 1H2O (l)
baseacid Cesium nitrate water
2HBr (aq) 1CaBr2 (aq)1Ca(OH)2 (aq)+ + 2H2O (l)
acid base Calcium bromide water
2KOH (aq) 1K2SO4 (aq)1H2SO4 (aq) + + 2H2O (l)
acid base Potassium sulfate water
electronic pH meter
Acids & Bases
XV. Titration -a _______is a method for determining an ________ ____________ of a solution by _______ a ______ ______ of a _______ solution of ______ ____________
titration unknownconcentration reacting knownvolume different knownconcentration
-to find the ________ ___________ of a ______ ______ of ____ solution, you can ______ the solution with a ______ ______ of an ____ solution of ______ ____________
unknown concentration knownvolume base titrate
known volume acidknown concentration
1 mL HCl sol. x 1 L HCl sol.______________1000 mL HCl sol.
= 0.001 mole NaOHx 1 mole HCl___________1 L HCl sol.
x 1 mole NaOH_______________1 mole HCl
1HCl (aq) 1NaCl (aq)1NaOH (aq)+ + 1H2O (l)
baseacid salt water
M = 0.001 mole NaOH_______________10 mL NaOH sol.
x 1000 mL NaOH sol._______________1 L NaOH sol.
= 0.1 M NaOH
Acids & Bases
XV. Titration
What is the molarity of a CsOH solution if 30.0 mL of the solution isneutralized by 26.4 mL of 0.250 M HBr solution?
26.4 mL HBr sol. x 1 L HBr sol.______________1000 mL HBr sol.
= 0.00660 mole CsOHx 0.250 mole HBr___________1 L HBr sol.
x 1 mole CsOH_______________1 mole HBr
1HBr (aq) 1CsBr (aq)1CsOH (aq)+ + 1H2O (l)
M = 0.00660 mole CsOH_______________30.0 mL CsOH sol.
x 1000 mL CsOH sol._______________1 L CsOH sol.
= 0.220 M CsOH
What is the molarity of a nitric acid solution if 20.00 mL of the solution is neutralized by 43.33 mL of 0.1000 M KOH solution?
43.33 mL KOH sol. x 1 L KOH sol.______________1000 mL KOH sol.
= 4.333 x 10-3 mole HNO3x 0.1000 mole KOH______________1 L KOH sol.
x 1 mole HNO3_______________1 mole KOH
1HNO3 (aq) 1KNO3 (aq)1KOH (aq)+ + 1H2O (l)
M = 4.333 x 10-3 mole HNO3_______________20.00 mL HNO3 sol.
x 1000 mL HNO3 sol._______________1 L HNO3 sol.
= 0.2167 M HNO3
Acids & Bases
XV. Titration -during the course of a _______, a known _______ of a _______ of known ___________ is added until the __________ _____ is reached, at which the _______ of ______ of ____ equals the _______ of ______ of _____
titration volumesolution concentration
equivalence pointnumber moles H+ numbermoles OH-
-corresponding closely with the __________ _____ is the ___ _____, at which the ________ changes _____
Adding indicator Titrating End Point
equivalence pointend point indicator
color
Acids & Bases
XVI. Buffered Solutions -_______ are _________ that _____ changes in ___
buffers solutions resistpH
-a ______ is a _______ of a _____ ____ and its _________ ____
buffer mixture weak acidconjugate base
HF (aq) H+ (aq) + F-
(aq)
H+ Adding an acid,raising [H+]
HF (aq) H+ (aq) + F-
(aq)
Equilibrium shifts to the left,lowering [H+]
H2O (l) H+ (aq) + OH-
(aq)
OH- Adding a base,raising [OH-]
H2O (l) H+ (aq) + OH-
(aq)
Equilibrium shifts to the left,lowering [OH-]
Human blood is buffered bythe weak acid carbonic acid(H2CO3) and its conjugatebase, hydrogen carbonate
(HCO3-)
Weak acid Conjugate base
Acids & Bases
XVI. Buffered Solutions -a ______ can also be a _______ of a _____ ____ and its _________ ____
buffer mixtureweak base conjugate acid
NH3 (aq) NH4+
(aq) + OH- (aq)
OH- Adding a base,raising [OH-]
Weak base Conjugate acid
+ H2O (l)
NH3 (aq) NH4+
(aq) + OH- (aq)+ H2O (l)
Equilibrium shifts to the left,lowering [OH-]
H2O (l) H+ (aq) + OH-
(aq)
H+ Adding an acid,raising [H+]
H2O (l) H+ (aq) + OH-
(aq)
Equilibrium shifts to the left,lowering [H+]
Acids & Bases
XVI. Buffered Solutions
What is the pH of buffer system made by mixing equal amounts of H2PO4
- and HPO42-?
H2PO4- (aq) H+
(aq) HPO42-
(aq)+
Ka = [H+]
[H2PO4-]
[HPO42-]
6.2 x 10-8 = [H+]
[H2PO4-]
[HPO42-]
6.2 x 10-8 = [H+](6.2 x 10-8)=pH -log
pH = 7.21