6 新东方罗勇整理 1989 1997年ap calculus自由问答题及答案1

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APCalculus AB

APCalculus BC

Free-Response Questions

and Solutions

1989 1997

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Notes about AP Calculus Free-Response Questions

The solution to each free-response question is as it appeared on the scoringstandard from the AP Reading. Other mathematically correct solutions are possible.

Scientific calculators were permitted, but not required, on the AP Calculus Exams in1983 and 1984.

Scientific (nongraphing) calculators were required on the AP Calculus Exams in 1993and 1994.

Graphing calculators have been required on the AP Calculus Exams since 1995. From1995-1999, the calculator could be used on all 6 free-response questions. Since the 2000Exams, the free-response section has consisted of two parts -- Part A (questions 1-3)requires a graphing calculator and Part B (questions 4-6) does not allow the use of acalculator.


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1989 AB1

Let f be the function given by .f(x)=x 3 7x+ 6

(a) Find the zeros of f .

(b) Write an equation of the line tangent to the graph of f at x = 1.

(c) Find the number c that satisfies the conclusion of the Mean Value Theorem for f on

the closed interval [1 .,3]

Copyright 2003 by College Entrance Examination Board. All rights reserved.

Available at apcentral.collegeboard.com

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1989 AB1

Solution

(a) ( )

( )( )(

3 7 6

1 2

1, 2, 3

f x x x

x x x

x x x

= +

= += = =

)3

2

(b) ( )

( ) ( )

( )

23 7

1 4, 1 1

12 4 1

or

4 8

or

4 8

f x x

f f

y x

x y

y x

=

= =

= +

+ =

= +

(c)( ) ( )

( )2

3 1 12 06

3 1 2

3 7

13

3

f f

c f c

c

= =

= =

=

6



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1989 AB2

Let R be the region in the first quadrant enclosed by the graph of y= 6x+ 4 , the line, and they-axis.y= 2x

(a) Find the area of R .

(b) Set up, but do not integrate, an integral expression in terms of a single variable for

the volume of the solid generated when Ris revolved about thex-axis.

(c) Set up, but do not integrate, an integral expression in terms of a single variable for

the volume of the solid generated when Ris revolved about they-axis.



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1989 AB2

Solution

(a)

( )

2

0

2

3/ 2 2

0

Area 6 4 2

1 2 6 46 3

64 8 204

9 9 9

x x dx

x x

= +

= +

= =

(b) Volume aboutx-axis

V = ( )2

2

06 4 4x x dx +

or

V = ( )2

0

326 4

3x dx

+

(c) Volume abouty-axis

V = ( )2

04 22 6x x + dx

or

V =

4 24 2 2

0 2

42 6y ydy dy



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1989 AB3

A particle moves along thex-axis in such a way that its acceleration at time t for t isgiven by . At time , the velocity of the particle is v and its

position is

0a( t)= 4cos(2t) t= 0 (0) = 1

x(0) = 0 .(a) Write an equation for the velocity of the particle.v(t)

(b) Write an equation for the position (t) of the particle.

(c) For what values of t , 0t , is the particle at rest?



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1989 AB3

Solution

(a) v t ( )

( )

( )

( )

4cos2

2sin2

0 1 1

2sin 2 1

t dt

v t t C

v C

v t t

=

= +

= =

= +

(b) ( )

( )

( )

( )

2sin 2 1

cos2

0 0 1

cos 2 1

t t dt

t t t

x C

x t t t

= +

= + +

= =

= + +

C

(c) 2sin 2 1 0

1sin 2

2

7 112 ,

6 6

7 11,

12 12

t

t

t

t

+ =

=

=

=



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1989 AB4

Let fbe the function given by2

( )4

xf x

x=

.

(a) Find the domain of f .

(b) Write an equation for each vertical asymptote to the graph of f .

(c) Write an equation for each horizontal asymptote to the graph of f .

(d) Find ( ) .f x



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1989 AB4

Solution

2 or 2

or 2

x

x

< >

>

(a)

(b) x x 2, 2= =

(c)2

2

m 14

lim 14

1, 1

x

x

x

x

x

x

y y

=

=

= =

li

(d)

( )( )

( )

1/ 22 2

2

22

2

2

3/ 22

14 4

2

4

44

4

4

4

x x x

f xx

xx

x

x

x

=

=

=

2



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1989 AB5

The figure above shows the graph of f , the derivative of a function f . The domain of fis the set of all real numbers xsuch that .10 x 10

(a) For what values of xdoes the graph of fhave a horizontal tangent?

(b) For what values of x in the interval does fhave a relative maximum?

Justify your answer.

( 10,10)

(c) For value of xis the graph of fconcave downward?



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1989 AB5

Solution

(a) ( )horizontal tangent 0

7, 1, 4, 8

f x

x

=

=

(b) Relative maxima at because1, 8x= f changes from positive to negative atthese points

(c)

( ) ( )

concave downward decreasing

3, 2 , 6,10

f f



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1989 AB6

Oil is being pumped continuously from a certain oil well at a rate proportional to the

amount of oil left in the well; that is,dy

dt

=ky, where y

,000,000

is the amount of oil left in the

well at any time t . Initially there were 1 gallons of oil in the well, and 6 years

later there were 500 gallons remaining. It will no longer be profitable to pump oil

when there are fewer than 50,000 gallons remaining.

,000

(a) Write an equation for y , the amount of oil remaining in the well at any time t .

(b) At what rate is the amount of oil in the well decreasing when there are 600,000

gallons of oil remaining?

(c) In order not to lose money, at what time t should oil no longer be pumped from the

well?



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1989 AB6

Solution

(a)kt

dy

kydt

y Ce=

= or

1

1ln

kt C

dyk dt

y

y kt C

y e +

= = + =

6 6

1

6

6

ln 26 66 6

0 10 , ln

10

16

2

ln 2

6

10 10 2

kt

k

t t

t C C

y e

t e

k

y e

= = =

=

= =

=

= =

10

(b) 5

5

5

ln 26 10

6

10 ln 2

Decreasing at 10 ln 2 gal/year

dyky

dt= =

=

4 6

2

(c) 5 10 10

ln20

ln20

ln 2

6

ln206 6log 20

ln 2

ln206 years after starting

ln 2

kte

kt

t

= =

= =

=



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1989 BC1

Let f be a function such that f (x)= 6x+ 8 .

(a) Find f(x) if the graph of f is tangent to the line 3 .2 at the point (0, 2)x y = (b) Find the average value of (x) on the closed interval [ 1 .,1]



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1989 BC1

Solution

(a) ( )

( )

( )

( )

2

3 2

3 2

3 8

0 3

3

4 3

2

4 3

f x x x C

f

C

2

f x x x x

d

f x x x x

= + +

==

= + + +

=

= + +

d

(b)( )

( )1

3 2

1

1

4 3 2

1

14 3 2

1 1

1 1 4 32

2 4 3 2

1 1 4 3 1 4 32 2

2 4 3 2 4 3 2

2

3

x x x dx

x x x x

+ +

= + +

= + + + +

=



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1989 BC2

Let R be the region enclosed by the graph of y= x

2

x 2 +1, the line x= 1, and the x-axis.

(a) Find the area of R .

(b) Find the volume of the solid generated when Ris rotated about they-axis.



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1989 BC2

Solution

(a)

1 2

2

01

20

1

0

Area

11

11

arctan

14

xdx

x

dxx

x

=

+=

+

=

=

(b)

( )

12

2

0

1

20

12

2

0

Volume 21

21

12 ln

2 2

1 ln 2

xx dx

x

xx dx

x

xx

= +

= +

= +

=

1

or

( )

( )

1/ 2

0

1/ 2

0

Volume 11

2 ln 1

1 ln 2

y dyy

y y

=

= +

=



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1989 BC3

Consider the function fdefined by f(x)=ex cosx with domain [0 ., 2 ]

(a) Find the absolute maximum and minimum values of (x).

(b) Find the intervals on which fis increasing.

(c) Find thex-coordinate of each point of inflection of the graph of f .



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1989 BC3

Solution

(a) ( )

[ ]

( )

sin cos

cos sin

50 when sin cos , ,

4 4

x x

x

f x e x e x

e x x

f x x x x

= +

=

= = =

0

4

5

4

2

x

( )

/ 4

5 / 4

2

1

2

2

2

2

f x

e

e

e

Max: 2 52

; Min:2

/ 4e e

(b)

4

0

25

4

++( )f x

Increasing on5

0, , , 24 4

]

(c) ( ) [ ] [

( )

sin cos cos sin

2 sin

0 when 0, , 2

x x

x

f x e x x e x x

e x

f x x

= +

= = =

Point of inflection at x =



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1989 BC4

Consider the curve given by the parametric equations3 2 32 3 and 12x t t y t= = t

(a) In terms of t , finddy

dx.

(b) Write an equation for the line tangent to the curve at the point where t= 1.

(c) Find thex- andy-coordinates for each critical point on the curve and identify eachpoint as having a vertical or horizontal tangent.



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1989 BC4

Solution

(a)

( )(

( )

)

2

2

2 2

2 2

3 12

6 6

2 23 12 4

6 6 2 2 2 1

dyt

dtdx

t tdt

t tdy t t

dx t t t t t t

=

=

+ = = =

(b) x y

( )

5, 11

3

4

311 54

or

3 29

4 4

4 3 29

dy

dx

y x

y x

y x

= =

=

= +

= +

+ =

(c) ( )

( )( )

( )

( )

, type

2 28,16 horizontal

0 0,0 vertical

1 1, 11 vertica

2 4, 16 horizontal

t x y

l



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1989 BC5

At any time t 0 , the velocity of a particle traveling along thex-axis is given by the

differential equationdx

dt

10x= 60e4t.

(a) Find the general solution x(t)for the position of the particle.

(b) If the position of the particle at time t= 0 is x= 8 , find the particular solution x(t) for the position of the particle.

(c) Use the particular solution from part (b) to find the time at which the particle is at

rest.



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1989 BC5

Solution

(a) Integrating Factor:10

10dt

te e =

( )

( )

10 4 10

10 6

4 1

60

10

10

t t t

t t

t t

dxe e e

dt

0

e e C

t e C

=

= +

= + e

or

( )

( )

10

4

4 4

10 4

4 10 60

10

10

t

h

t

p

t t

t t

x t Ce

x AeAe Ae e

A

x t Ce e

=

= =

=

=

4t

2(b)

( ) 10 48 10;

2 10t t

C C

x t e e

=

=

=

(c)10 4

10 4

20 40

20 40 0

1ln 2

6

t t

t t

dxe edt

e e

t

= =

=

or

( )4 10

4 10 4

10 10 2 60

0 100 20 601

ln 26

t t

t t t

dxe e e

dt

e e e

t

+ =

+ ==

4t



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1989 BC6

Let f be a function that is everywhere differentiable and that has the following properties.

(i) f(x+h) = f( )+f(h)f(x)+f(h) for all real numbers h and x .

(ii) f( )> 0 for all real numbersx .

(iii) f (0) = 1.

(a) Find the value of f(0) .

(b) Show that f(x)=1

f(x) for all real numbers x .

(c) Using part (b), show that f( +h) = f(x)f(h) for all real numbers h and x .

(d) Use the definition of the derivative to find ( ) in terms of ( )f x f x .



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1989 BC6

Solution

(a)

( ) ( ) ( ) ( )( ) ( )

Let 0

0 00 0 00 0

x h

f ff ff f

= =

+= + = =+

1

(b)

( ) ( ) ( ) ( )

( ) ( )

( ) ( )( )

Let 0

00

0

1Use 0 1 and solve for

h

f x ff x f x

f x f

f f xf x

=+

+ = = +

= =

or

Note that( ) (0

( 0)( ) (0)

)f x ff x

f x f

+ + =+

is the reciprocal off(x).

(c) ( ) ( ) ( )

( ) ( )

( ) ( )

( ) ( )

( ) ( )

( ) ( )

1 1

f x f hf x h

f x f h

f x f hf x f h

f h f x

f x f h

++ =

+

+=

+=

(d) ( ) ( ) ( )

( ) ( ) ( )

( ) ( )

( ) ( ) ( )

0

0

0

lim

lim

1lim

0

h

h

h

f x h f xf x

h

f x f h f x

h

f hf x

h

f x f f x

+ =

=

=

= =



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1990 AB1

A particle, initially at rest, moves along the x-axis so that its acceleration at any time

t 0 is given by The position of the particle whena(t)=12t2 4. t=1 is x(1)= 3 .

(a) Find the values of t for which the particle is at rest.

(b) Write an expression for the position x(t)of the particle at any time t 0 .

(c) Find the total distance traveled by the particle from t= 0 to t= 2 .

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1990 AB1

Solution

(a) v t ( )

( )

( )

3

3

2

4 4

4 4 0

4 1

Therefore 0, 1

t t

v t t t

t t

t t

=

= == =

= =

0

(b) ( )

( )

( )

4 2

4

4 2

2

3 1 1 2 1

3 1

42 4

x t t t C

x C

C

Cx t t t

= +

= = +

=

== +

(c) (0) 4

(1) 3

(2) 12

Distance 1 9 10

x

x

x

===

= + =

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1990 AB2

Let fbe the function given by f(x)= ln x

x1

.

(a) What is the domain of f?

(b) Find the value of the derivative of f at x= 1.

(c) Write an expression for 1 1( ), where denotes the inverse function of .f x f f

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1990 AB2

Solution

(a) 01

0 and 1 0 1

0 and 1 0 0

0 or 1

x

x

x x x

x x x

x x

>> > < < < >

>

=


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1992 BC5

The length of a solid cylindrical cord of elastic material is 32 inches. A circular cross

section of the cord has radius1

2

inch.

(a) What is the volume, in cubic inches, of the cord?

(b) The cord is stretched lengthwise at a constant rate of 18 inches per minute.Assuming that the cord maintains a cylindrical shape and a constant volume, at

what rate is the radius of the cord changing one minute after the stretching begins?Indicate units of measure.

(c) A force of 2x pounds is required to stretch the cord xinches beyond its naturallength of 32 inches. How much work is done during the first minute of stretching

described in part (b)? Indicate units of measure.


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1992 BC5

Solution

(a)

2

2 1 32 82

h = = = V r

( ) ( )

2

2

2

0 2 ;

at 1, 50 and

so 8 50,

2so

5

2 2Therefore 0 2 50 18

5 572

4025

9 in/min

125

dV dr dhrh r

dt dt dt

t h

r

r

dr

dtdr

dt

dr

dt

= = +

= =

=

=

= + = +

=

(b)

or

( )

2

1

2

2

1

2

88 , so

1 8 8Therefore

2

at 1, 50 so

1 8 818

2 50 2500

9in/min

125

V r h r h

dr dh

dt h h dt

t h

dr

dt

= = =

= = =

=

=

(c)18

18 2 2

00

Work 2 18

324 in-pounds

27 foot-pounds

x dx x= = =

==


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1992 BC6

Consider the series1

np ln(n)n= 2

, where p 0.

(a) Show that the series converges for p > 1.

(b) Determine whether the series converges or diverges for p = 1. Show your analysis.

(c) Show that the series diverges for 0p < 1.


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1993 AB1

Let f be the function given by , where kis a constant.f(x)=x 3 5x 2 + 3x+k

(a) On what intervals is f increasing?

(b) On what intervals is the graph of fconcave downward?

(c) Find the value of kfor which f has 11 as its relative minimum.


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1993 AB1

Solution

(a) ( )

( )( )

( )

23 10 3

3 1 3

10 at and 3

3

f x x x

x x

f x x x

= +

=

= = =

0

s

f is increasing on and on [3 , )1

(b) ( ) 6 1f x x =

sign of f +

ign of f

,3

++

1

3

3

5

3

The graph is concave down on

5

, 3

(c) From (a), f has its relative minimum atx = 3, so

( ) ( ) ( ) ( )3 3 5 3 3 3

9 11

20

3 2f k

k

k

= + +

= + ==


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1993 AB2

A particle moves on thex-axis so that its position at any time is given by

.

t 0x(t) = 2te t

(a) Find the acceleration of the particle at .t= 0(b) Find the velocity of the particle when its acceleration is 0.

(c) Find the total distance traveled by the particle from .t= 0 to t= 5


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1993 AB2

Solution

(a) v t ( ) ( )

( ) ( )( ) ( )

2 2

2 2 2

0 0 2 2 4

t t

t t

x t e te

a t x t e e te

a x

= =

= = += = =

t

(b) ( ) ( )

( ) ( ) ( )2

2

2 2 0

2

2 2 2 1

2

0.271

tx t e t

t

x v e

e

= =

= = =

=

2

(c) ( ) ( ) ( )

( )

( )

( ) 5

2 1

1

0 0

21 0.736

105 0.067

tv t e t

t

x

xe

xe

= = =

==

=

=

0x t

5

2 2 10Distance

1.404

e e e= +


8/10/2019 6 1989 1997 AP Calculus 1

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1993 AB3/BC1

Consider the curve and chord ABjoining the points

on the curve.

y2 = 4+x ( 4 ,0 ) and ( 0 ,2 )A B

(a) Find the x- and y-coordinates of the point on the curve where the tangent line is

parallel to chord AB .

(b) Find the area of the region R enclosed by the curve and the chord AB .

(c) Find the volume of the solid generated when the region R, defined in part (b), is

revolved about thex-axis.


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1993 AB3/BC1

Solution

(a)2 1

ope of4 2

AB= =sl

( )B 0, 2

( )A 4, 0

Method 1:1 1

4 ; ;22 4 2 4

so 3, 1

dyy x

dx x x

x y

= + = =+ +

= =

1

Method 2:1

2 1; so 2 1 and 1, 32

dyy y y x

dx

= = = =

(b)

Method 1: ( )

( ) ( )

0 03/ 2 2

44

3/ 2

1 2 14 2 4

2 3 4

2 16 44 4 8 4

3 3 3

2x x dx x x x

+ + = +

= + = =

Method 2: ( ) ( )2

32

2 2

00

2 4 43

8 44

3 3

yy y dy y =

= =

Method 3:0

4

164 ; Area of triangle 4

3

16 4Area of region 43 3

x dx

+ = =

= =


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1993 AB3/BC1

Solution, continued

(c)

Method 1: ( )0

22

4

0

2

4

14 2

2

14 2

4

16 88 8.378

3 3

4

x x dx

x x x d

+ +

= + + +

= =

x

Method 2: ( ) ( )

22

0

8

2 2 4 4 3y y y dy

=

Method 3: ( )

( )

( ) ( )

020 2

44

2

4 42

0 16 8 8

1 1Volume of cone 2 4

3 3

16 8Volume 8

3 3

xx dx x

+ = +

= + =

= =

= =

6


8/10/2019 6 1989 1997 AP Calculus 1

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1993 AB4/BC3

Let fbe the function defined by f( )= ln(2 + sinx) for 2.

(a) Find the absolute maximum value and the absolute minimum value of f . Show theanalysis that leads to your conclusion.

(b) Find thex-coordinate of each inflection point on the graph of f . Justify youranswer.


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1993 AB4/BC3

Solution

(a) ( )

[ ]

1cos ;

2 sin

3In , 2 , cos 0 when ;2

f x xx

x x

=+

= =

( )

( )

( )

ln 2 0.693

ln 2

ln 1 0

=

=

2

3

2

( )f xx

absolute maximum value is ln 2

absolute minimum value is 0

(b) ( ) ( )( )

( )

( )

( )

2

2

sin 2 sin cos cos

2 sin

2sin 1;

2 sin

10 when sin

2

7 11,

6 6

x xf x

x

x

x

f x x

x

+ =

+

=

+

= =

=

x

up

sign off

concavity

+

down down7

6

211

6

7 1and

6 6x

= 1 since concavity changes as indicated at these points


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1993 AB5y

x

( )1,1

O

1

21

Note: This is the graph of the derivative off ,not the graph off .

The figure above shows the graph of f , the derivative of f . The domain of fis the set

of all x such that 0< < 2.

(a) Write an expression for f (x) in terms of x .

(b) Given that f(1) , write an expression for= 0 f(x) in terms of x .

(c) In thexy-plane provided below, sketch the graph of y= f(x) .

O2 1 1 2

2

1

1

2

x



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1993 AB5

Solution

( )

( )

if 0 1

2 if 1 2

or

1 1 if 0

x xf x

x x

f x x x

< = ( ) lnv t t t t = 1= (1) 6.x =

(a) Write an expression for the acceleration of the particle.

(b) For what values of tis the particle moving to the right?

(c) What is the minimum velocity of the particle? Show the analysis that leads to yourconclusion.

(d) Write an expression of the position ( )x t of the particle.



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1994 AB 4

(a) ( ) ( )1

ln 1 lnv t t t t

t

= = + =a t

(b) ( )

( )

ln 0

ln 1 0

v t t t t

t t

t e

= >

>

>

(c) v t ( ) ln 0

1

t

t

= =

=

0 +

01

vt

minimum velocity is v ( )1 1=

( )

( )

2 2 2

2 2

2 2

(d) ln

1 1 1ln

2 4 2

1 3ln ;

2 4

36 1 0

4

27;

4

1 3ln

2 4

t t t dt

t t t t C

t t t C

x C

C

x t t t t

= +

= +

= = +

=

= +

27

4



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1994 AB 5-BC 2

A circle is inscribed in a square as shown in the figure above. The circumference of thecircle is increasing at a constant rate of 6 inches per second. As the circle expands, thesquare expands to maintain the condition of tangency. (Note: A circle with radius rhas

circumference and area )2C= r 2A r=

(a) Find the rate at which the perimeter of the square is increasing. Indicate units ofmeasure.

(b) At the instant when the area of the circle is square inches, find the rate ofincrease in the

25area enclosed between the circle and the square. Indicate units of

measure.



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1994 AB 5-BC 2

(a) 8

8

6 2

3 24; inches/second

7.639 inches/second

dP dRdt dt

dC dR

dt dt

dR dP

dt dt

=

=

= =

= =

P R

R

(b) Ar

( )

( )

( )

( )

2 2

2

2

2

2

ea 4

Area8 2

4 2

Area of circle 25

5

Area 12030 inches /second

30 4 inches /second

8.197 inches /second

R R

d dR dRR R

dt dt dt

dRR

dt

R

R

d

dt

= =

=

= ==

=

=



8/10/2019 6 1989 1997 AP Calculus 1

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1994 AB 6

Let for 0 3 .20

( ) sin( )x

F x t dt= x

(a) Use the trapezoidal rule with four equal subdivisions of the closed interval [0 to

approximate .

,1]

(1)F

(b) On what intervals is Fincreasing?

(c) If the average rate of change of Fon the closed interval [1 is k, find

in terms of k.

,3]3

2

1sin( )t dt



8/10/2019 6 1989 1997 AP Calculus 1

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1994 AB 6

(a) F t( ) ( )

( )

12

0

2 2 2

2 2

1 sin

1 0 1 1 1 3sin 0 2sin 2sin 2sin sin1

4 2 4 2 4

0.316

dt=

+ + + +

(b) ( ) ( )

( )

2

2

sin

0 when 0, , 2 ,...

0, , 2

x

F x x

x

=

= =

=

F x

320x

++F

Fis increasing on 0, and on 2 ,3

(c)

( ) ( ) ( )

( )

32

1

32

1

sin3 1

2 2

sin 2

t dtF Fk

t dt k

= =

=



8/10/2019 6 1989 1997 AP Calculus 1

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1994 BC 3

A particle moves along the graph of y = cosx so that thex-coordinate of acceleration isalways 2. At time t= 0 , the particle is at the point ,1( and the velocityvector of the particle is ( ).

)0,0

(a) Find thex- and y-coordinates of the position of the particle in terms of t.

(b) Find the speed of the particle when its position is ( ).4,cos4



8/10/2019 6 1989 1997 AP Calculus 1

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1994 BC 3

(a) x t( ) ( )

( ) ( )( ) ( )

( )

( ) ( )

2

2

2

2 2

0 0 0; 2

, 0

cos

x t t C

x C x t t

x t t k x k

x t t

y t t

= = +

= = == + = =

= +

= +

(b) dy= ( )

( )

( ) ( )( )

( )

2

2 2

22 2

2 2 2 2

2 sin

2 2 sin

4 4 sin

t tdt

dx dys t

dt dt

t t t

t t t

+

= +

= + +

= + +

( ) ( )

2 2

2

when 4, 4; 4

4 4 4 4 sin 4

2.324

x t t

s

= + = =

= +



8/10/2019 6 1989 1997 AP Calculus 1

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8/10/2019 6 1989 1997 AP Calculus 1

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1994 BC 4

(a) ( ) ( )

( )

( ) ( )

26 ; 2

1 2

5 2( 1) or 2

7int : int : 7

2

1 7 491 7

2 2 4

f x x f x x

f

y x y x

x y

A

= =

=

= = +

= =

7

(b) ( ) ( )2

22

( ) 2 ; 6 2

6

int: int: 62

f w w y w w x

w

x y ww

= =

+

+

w

( ) ( )

( ) ( )( )( ) ( )

( ) ( )( )

22

22 2

2

2 2

6

4

4 2 6 2 4 6

16

0 when 6 3 6 0

2

w

w

w w w wA w

w

A w w w

w

+=

+ + =

= + =

=

A w

A w

620

+



8/10/2019 6 1989 1997 AP Calculus 1

142/206

1994 BC 5

Let f be the function given by .f(x) =e2x2

(a) Find the first four nonzero terms and the general term of the power series for f(x)

about x = 0.

(b) Find the interval of convergence of the power series for (x) about x = 0. Showthe analysis that leads to your conclusion.

(c) Let g be the function given by the sum of the first four nonzero terms of the power

series for f(x) about x = 0. Show that f(x)g(x) < 0.02 for 0.6 x 0.6 .



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1994 BC 5

(a)

( )2

2 3

24 62 2

12 3! !

1 24 81 2 2 3! !

nu

n n n

x

u u ue u

n

xx xe x n

= + + + + + +

= + + + +

(b) The series for converges forue u < <

So the series for converges for 22xe 22x< <

And, thus, for < <

Or

( ) ( )

( ) ( )

1 2 11

1

2

2

1 2 !lim lim

1 ! 1 2

2lim 0 1

1

n nn

n

n n nn nn

n

xa n

a n x

xn

+ +++

=

+

= =

6 新东方罗勇整理 1989 1997年ap calculus自由问答题及答案1

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