47559624 design of two way slabs usd 1

8/13/2019 47559624 Design of Two Way Slabs USD 1

1/3

Project No. Sheet 1 of 3

Calculated By: Reviewed By:

Client:

Project Name:

Design Title

Design of Two-Way Slabs:

Slab Dimensions :

LS = 3.5 mLl= 5 m

1 Total Load Combination:

(1)

W = 23.875 T/Sq.m

(2)WS= 19.252 T

(3)WL= 4.623 T

2 Calculation of Moments:

I. Short Span

a. Mid Span:

MS= (9/128)WS.LS (4)

MS= 16.583 T.m

b. Support:

MOS= (1/8)WS.LS (5)

MOS= 29.480 T.m

II. Long Span

a. Mid Span:

ML= (9/128)WL.LL (4)

ML= 8.126 T.m

b. Support:

MOL= (1/8)WL.LL (5)

MOL= 14.445 T.m3 Calculation of Reinforcement Bars:

I. Short Span

a. Mid Span:

d = (MS/14b) (6) "d" is effective depth of the Slab.d = 34.416 cm "b" is breadth of the Design Strip (100cm).

D = d+a (7) "D" is the Overall Depth of the Slab.a = 5 cm "a" is thickness of the Concerete Cover of the Slab.

D = 39 cm

Then D = 40 cm

fc' = 200 Kgf/Sq.m

fy= 2800 Kgf/Sq.m

= 0.9= 0.028

= dfy/(0.85fc') (8) = 18.447

AS= MS/(fy(d-(/2))) (9)

AS= 21.381 cm Diameter (mm) Area (cm)

As% = (0.20.8)%bd (10) 10 0.786

0.2%(bd) As%min

= 8 cm 12 1.131

0.8%(bd) As%max

= 32 cm 14 1.540

Then AS= 21.381 cm

Diameter () 10 12 14

Nos. 27 19 14

Then Use, 20 12

M. Harris

Standard Rebar Specs.

Two Way Slabs:The ratio of (L L/L s)As%max

Use As and if As


2/3



Client:

Project Name:

Design Title

a. Support:

d = (MOS/14b) (6)d = 45.888 cm

D = d+a (7)a = 5 cm

D = 51 cm

Then D = 55 cm

f'c= 200 Kgf/Sq.m

fy= 2800 Kgf/Sq.m

= 0.9= 0.028

= dfy/(0.85f'c) (8) = 25.365

AS= MOS/(fy(d-(/2))) (9)

AS= 27.645 cm

As% = (0.20.8)%bd (10)

0.2%(bd) As%min

= 11 cm 0.8%(bd) As%

max= 44 cm

Then AS= 27.645 cm


Nos. 35 24 18

Then Use, xx 12

II. Long Span

a. Mid Span:

d = (ML/14b) (6)d = 24.091 cm

D = d+a (7)a = 5 cm

D = 29 cm

Then D = 40 cm

f'c= 200 Kgf/Sq.m

fy= 2800 Kgf/Sq.m

= 0.9= 0.028

= dfy/(0.85fc') (8) = 18.447

AS= ML/(fy(d-(/2))) (9)

AS= 10.477 cm

As% = (0.20.8)%bd (10)

0.2%(bd) As%min= 8 cm 0.8%(bd) As%

max= 32 cm

Then AS= 10.447 cm


Nos. 13 9 7

Then Use, 10 12

DESIGN OF SLAB 1

Notes:Company Name & Logo

M. Harris

Design of Two Way Slabs

Ultimate States Design

2

11/23/2013Programmed By:

Mohammad Harris WAHEB


3/3



Client:

Project Name:

Design Title

a. Support:

d = (MOL/14b) (6)d = 32.122 cm

D = d+a (7)a = 5 cmD = 37 cm

Then D = 40 cm

f'c= 200 Kgf/Sq.m

fy= 2800 Kgf/Sq.m

= 0.9= 0.028

= dfy/(0.85f'c) (8) = 18.447

AS= MOL/(fy(d-(/2))) (9)

AS= 18.626 cm

As% = (0.20.8)%bd (10)

0.2%(bd) As%min

= 8 cm

0.8%(bd) As%max

= 32 cm

Then AS= 18.626 cm


Nos. 24 16 12

Then Use, xx 12

Company Name & Logo

M. Harris

Notes:

DESIGN OF SLAB 1

Design of Two Way Slabs

Ultimate States Design

3

11/23/2013Programmed By:

Mohammad Harris WAHEB

47559624 design of two way slabs usd 1

Documents