3.cpp&dbms record

8/10/2019 3.Cpp&Dbms Record

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C++

PROGRAMMING

1


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PROGRAM NO: 1

DATE: 13/05/2014

STUDENT SURVEY

Students in a college were surveyed about how many days a week they eat fast-food. Write

a program to help analyze the result of the survey. Initially the program prompts how many input

values there are, it then reads in the specified number of values, and counts how many answers are

day a week, 1 day a week, etc. !inally the result is displayed in a table, each row showing the

number of days, the number of students that eat fast-food that many days a week, and what

percentage they constitute of the total number of students surveyed. "n e#ample running session

might look like follows $you don%t have to align the table columns&'

(ow many input values are there' )

*nter number of days' +

*nter number of days'




ays Students /ercentage$0&

1 +

1

+ 1 +

+

)

2

1 +

CLASS DIAGRAM

+


3/110

PROGRAM

3include4iostream5

using namespace std6

class survey

7

private'

int n,count89:6

public'

survey$&

7

n;6

for$int i;6i496i6

cin55ch6

switch$ch&

7

case ' count8:


4/110

case +' count8+:Invalid choice?n>6

break6

=

i6

for$int i;6i496i44i44>?t>44count8i:44>?t?t>44t6

=

cout44>?n>6

=

=6

int main$&

7

survey s16


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s1.find$&6

s1.display$&6

return 6

=

OUTPUT

)


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PROGRAM NO: 2

DATE: 13/05/2014

PASSING ARRAY OF OBJECTS

Ereate a class student with rollno, name and marks of subects. Dead the student details,

find total and percentage and display the details

CLASS DIAGRAM

PROGRAM

3include4iostream5


class student

7

private'

int m1,m+,m,roll,total6

char name8+:6

float per6public'

void read$&

7

cout44>?n*nter the roll no' >6

cin55roll6

cout44>?n*nter the name' >6

cin55name6

2


7/110

cout44>?n*nter mark1,mark+ and mark' >6

cin55m155m+55m6

total;m144total6

cout44>?n/ercentage' >44per44>?n>6

=

int percentage$student s8:,int n&

7int sid6

float ma#6

for$int i;6i4n6i


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return sid6

=

=6

int main$&

7

student S181:6

int n,r6

cout44>?n*nter the no'of students' >6

cin55n6

for$int i;6i4n6i


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OUTPUT

J


10/110

PROGRAM NO: 3

DATE: 13/05/2014

INLINE FUNCTION

Ereate a inline function to find the sum of first n odd numbers

CLASS DIAGRAM

PROGRAM

3include4iostream5

3include4math.h5


class sum

7

private'

int n6

public'

void getdata$&

7

cout44>*nter the limit' >6

cin55n6

=

inline int oddsum$&

7

int s6

s;pow$n,+&6

cout44>SBK; >44s6

cout44>?n>6

=

1


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=6

int main$&

7

sum s16

s1.getdata$&6

s1.oddsum$&6

return 6

=

OUTPUT

11


12/110

PROGRAM NO: 4

DATE: 20/05/2014

CONSTRUCTOR

Bsing constructor find sum of + integers $use default, parameterized constructor&

CLASS DIAGRAM

PROGRAM

3include4iostream5


class constructor

7

int a,b,sum6

public'

constructor$&

7

a;6

b;6

cout44>Lalue of a' >44a44>?n>6

cout44>Lalue of b' >44b6

sum;6

=

constructor$int i,int &

7

a;i6

b;6

cout44>Lalue of a' >44a44>?n>6

cout44>Lalue of b' >44b6

1+


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=

int add$&

7

return a?nefault constructor called?n>6

constructor c16

cout44>?nSum' >44c1.add$&6

cout44>?n?n/arameterised constructor called?n>6constructor c+$),)&6

cout44>?nSum' >44c+.add$&44>?n>6

return 6

=

OUTPUT

1


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PROGRAM NO: 5

DATE: 20/05/2014

TOLL BOOTH

Implement the toll booth . When a car is a paycar, increment count by one and increment

money by 1. If car is not a paycar,increment count by one. Eount will represent number of cars

passed by.

CLASS DIAGRAM

PROGRAM

3include4iostream5


class tollbooth

7

int totMcar6

int amt6

public'

tollbooth$&'totMcar$&,amt$&

7=

void display$&

7

cout44>?nAotal car passed' >44totMcar6

cout44>?nAotal "mount '>44amt44>?n>6

=

void payingcar$&

7

totMcar;totMcar


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amt;amt6

1)


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cin55ch6

=

return 6

=

OUTPUT

12


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else

consonantMcount44consonantMcount44>?n>6

=

=6

char count''str81:6

int count''vowelMcount;6

int count''consonantMcount;6

int main$&

7count c6

c.getdata$&6

count''putdata$&6

return 6

=

OUTPUT

19


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PROGRAM NO: !

DATE: 03/0/2014

BAN" ACCOUNT

efine a class bank"ccountT. Include the following members. Write a program in E


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private'

string name6

int accno6

unsigned long int bal6

public'

bankaccount$&

7

cout44>?n*nter the name' >6

cin55name6

cout44>*nter the account number' >6

cin55accno6

bal;6=

int get$&

7

return accno6

=

void display$&

7

cout44>?nCame' >44name44>?n>6

cout44>Ualance' >44bal44>?n>6

=

void deposit$&

7

int amt6

cout44>?n*nter amount to deposit' >6

cin55amt6

bal;bal"mount depositedPPP?n>6

=

void withdraw$&

7

int amt6

+


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cout44>?n*nter the amount to be withdrawn' >6

cin55amt6

if$bal4; RR bal4amt&

cout44>?nCo sufficient balancePPP?nWithdrawing not possible?n>6

else

7

bal;bal-amt6

cout44>"mount withdrawnPPP?n>6

=

=

bankaccount transfer$bankaccount b1&

7int amt6

cout44>?n*nter the amount you want to transfer' >6

cin55amt6

if$amt5b1.bal&

cout44>Co sufficient amount to transfer?n>6

else

7

bal;bal"mount successfully transferredPPP?n>6

=

return b16

=

=6

int main$&

7

bankaccount b1,b+6

int a;1,ch,ac1,ac+6

while$a;;1&

7

cout44>?nNptions?n1.eposit?n+.Withdraw?n.Aransfer?n.isplay?n*nter the

+1


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choice' >6

cin55ch6

switch$ch&

7

case 1'

cout44>*nter the account number' >6

cin55ac16

if$b1.get$&;;ac1&

b1.deposit$&6

else if$b+.get$&;;ac1&

b+.deposit$&6

elsecout44>?n"ccount doesnQt e#ist?n>6

break6

case +'

cout44>*nter the account number'>6

cin55ac16

if$b1.get$&;;ac1&

b1.withdraw$&6

else if$b+.get$&;;ac1&

b+.withdraw$&6

else

cout44>?n"ccount doesnQt e#ist?n>6

break6

case '

cout44>*nter the account number from which you want to transfer' >6

cin55ac16

cout44>*nter the account number to which u want to deposit' >6

cin55ac+6

if$b1.get$&;;ac1 VV b+.get$&;;ac+&

b1;b+.transfer$b1&6

else if$b+.get$&;;ac1 VV b1.get$&;;ac+&

b+;b1.transfer$b+&6

++


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else

cout44>?n"ccount doesnQt e#ist?n>6

break6

case 'b1.display$&6

b+.display$&6

break6

case )' e#it$&6

break6

default' cout44>?nInvalid choice?n>6

=

cout44>/ress 1 to continue else press ' >6

cin55a6=

return 6

=

OUTPUT

+


24/110

+


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+)


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PROGRAM NO: #

DATE: 03/0/2014

COMPLE$ NUMBER ADDITIONEomple# number addition using friend function

CLASS DIAGRAM

PROGRAM

3include4iostream5


class comple#

7

float real,image6

public'

void get$&

7

cout44>*nter real and imaginary part' >6

cin55real55image6

=

void display$&

7

cout44real44>44image44>?n>6

=

friend comple# sum$comple#,comple#&6

=6

comple# sum$comple# c1,comple# c+&

7

comple# c6

+2


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c.real;c1.real6

a.get$&6

cout44>?nSecond comple# number?n>6

b.get$&6

c;sum$a,b&6cout44>Sum of comple# numbers'>6

c.display$&6

return 6

=

OUTPUT

+


28/110

PROGRAM NO: %

DATE: 10/0/2014

TRANSLATE THE GIVEN SENTENCE TO PIG LATIN

Write an interactive program that prompts the user to input a valid sentence containing at

least two letters and ending in a period. Bse getline$cin,sentence&6 to read the sentence. Bse string

functions. Aranslate the given sentence to /ig atin and display it.

CNA*' Bse functions to make your code as efficient and as organized as possible. Eorrectness is

the most important element, however, points will be given for the Xuality of your code.

Ahe /ig atin system works as follows'

Y Words that start with a vowel $", *, I, N, B& simply have >W"@> appended to the end of the

word.

Y Words that start with a consonant have the first consonant letter moved to the end of the word and

>"@> is appended.

Incorporate the following features and special case functionality'

Y Eorrect upper case and lower case formatting.

Y "ssume Words consist of alphabetic characters only $"-Z and a-z&.

Y "ll punctuation, numerals, symbols and whitespace should not be modified.!or e#ample'

Input'

Nutput'

Ahese awful french fries are getting cold.

(esetay awfulway renchfay riesfay areway ettinggay oldcay.

CLASS DIAGRAM

+9


29/110

PROGRAM

3include 4string.h5

3include 4iostream5


class convert

7

int worden6

char lowMcase,ch6

string word,first,newWord6

public'

bool isLowels$char #&

7

lowMcase ; tolower $#&6

if $lowMcase ;; QaQ &

return true6

else if $lowMcase ;; QeQ &

return true6

else if $ lowMcase;; QiQ &

return true6

else if $lowMcase ;; QoQ &

return true6

else if $lowMcase ;; QuQ &

return true6

else

return false6=

void changeine $string line&

7

while $line.length$& P;&

7

worden ; line.find$Q Q&6

if $worden 5&

+J


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void nonLowel$char begin, string end&

7

newWord;end6

cout44newWord44> >6

=

=6

int main$&

7

convert c6

char ch6

string word, first, line6

cout 44endl6cout 44 >*nter a string or, blank to e#it.?n>6

cout 44 >Ahis program will output the words in /ig atin.?n>6

cout 44endl6

getline$cin,line&6

cout 44endl6

while $line.length$&P; &

7

c.changeine$line&6

cout44endl6

cout44endl6

cout 44 >*nter a string or, blank to e#it.?n>6

cout 44 >Ahis program will output the words in /ig atin.?n?n>6

cout 44endl6

getline$cin,line&6

=

return 6

=

1


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OUTPUT

+


33/110

PROGRAM NO: 10

DATE: 10/0/2014

ALLOCATING MEMORY DYNAMICALLY

"llocate memory for students dynamically and search for a particular student using rollno.

CLASS DIAGRAM

PROGRAM

3include4iostream5

3include4stdlib.h5


class student

7

int rolno6

char name8+:6

char grade6

public'

void read$&

7

cout44>?n*nter roll number' >6

cin55rolno6

cout44>*nter name' >6

cin55name6

cout44>*nter Frade' >6

cin55grade6

=

void display$&

7


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cout44>?nDN Co ' >44rolno6

cout44>?nC"K* ' >44name6

cout44>?nFD"* ' >44grade6

=

int search$int r&

7

if$rolno;;r&

return 16

else

return 6

=

=6main$&

7

int r,f,n,ch;16

cout44>*nter number of students>6

cin55n6

student Hs8n:6

do

7

cout44>?nNptions?n1.D*"?n+.S*"DE(?n.IS/"@ ?n.*[IA?n*nter your

choice' >6

cin55ch6

switch$ch&

7

case 1'for$int i;6i4n6i44i6


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cin55r6

f;6

for$int i;6i4n6i6

cout44>etails of student?n>6

s8i:-5display$&6

break6

= =

if$f;;&

7

cout44>?n DN CN CNA !NBC>6

=

break6

case 'for$int i;6i4n6i44$i


36/110

OUTPUT

2


37/110


38/110

PROGRAM NO: 11

DATE: 1!/0/2014

OPERATOR OVERLOADING&STRING

Ereate a class string class which contains + strings as its data members .Nverload Q6cin55s16

cout44>*nter the second string' >6

cin55s+6

=

void operator;;$int a&

7

if$strcmp$s1,s+&;;&

9


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cout44>?nStrings are eXual?n>6

else

cout44>?nStrings are not eXual?n>6

=

void operator?nStrings after concatination' >44str6

=

void operator4$int a&7

if$strcmp$s1,s+&4&

cout44>?n!irst string is smaller?n>6

else

cout44>?nSecond string is smaller?n>6

=

void operator5$int a&

7

if$strcmp$s1,s+&5&

cout44>?n!irst string is greater?n>6

else

cout44>?nSecond string is greater?n>6

=

=6

int main$&

7

string1 ob6

int n;16

ob.getdata$&6

ob;;n6

ob


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ob4n6

ob5n6

cout44>?n>6

return 6

=

OUTPUT


41/110

PROGRAM NO: 12

DATE: 1!/0/2014

OPERATOR OVERLOADING & DISTANCE

Ereate a class istance with feet and inches as data members. Nverload Q feet and >44inches44> inches?n>6

=

istance operator


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istance temp6

temp.inches;inches


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inches;i6

=

istance operator,$istance d1&

7

istance temp6

temp.feet;d1.feet6

temp.inches;d1.inches6

return temp6

=

=6

main$&

7float f,i6

cout44>?n*nter first distance' >6

cin55f55i6

istance d1$f,i&6

cout44>*nter second distance' >6

cin55f55i6

istance d+$f,i&6

istance d;d1!irst distance' >6

d1.display$&6

cout44>?nSecond distance' >6

d+.display$&6

cout44>?nd16

d.display$&6

if$d1;;d+&

cout44>?nd1 is eXual to d+>6

else

cout44>?nd1 is not eXual to d+>6

d1?nd16

d1.display$&6


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d1$1,+&6

cout44>?nd1$1,+&; >6

d1.display$&6

d;$d1,d+&6

cout44endl44>d;$d1,d+& ' >6

d.display$&6

=

OUTPUT


45/110

PROGRAM NO: 13

DATE: 01/0!/2014

INHERITANCE

Ereate a class counter with a count variable initialized to zero and a function to increment

the counter and another function to display it.create another class which inherits class counter and

it contains a function which decrements the count. When an employee enters into office, count is

incremented and when employee goes out, count is decremented. Write a program to implement

this functionality.

CLASS DIAGRAM

PROGRAM

3include4stdlib.h5

3include4iostream5


class base

7

protected'

int count6

public'

base$&'count$&

7=

void increment$&

)


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7

count6

cin55c6

switch$c&

7

case 1'

d1.increment$&6

d1.display$&6

break6

case +'

d1.dercement$&6

2


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d1.display$&6

break6

case '

e#it$&6

=

cout44>?n/ress 1 to continue else press ' >6

cin55ch6

=

while$chP;&6

return 6

=

OUTPUT


48/110

PROGRAM NO: 14

DATE: 01/0!/2014

VIRTUAL FUNCTIONS& SHAPE CLASS

Ereate a base class shape. Aake two data members of double types to compute the area of

different shapes. erive two classes% triangle and rectangle from the base shape. Include

constructors in every class to initialize the obects. Include one pure virtual function

computeMarea$& to compute area. Bsing these classes, write a c


49/110

y;6

=

shape$double a,double b&

7

#;a6

y;b6

=

virtual double computeMarea$&;6

=6

class triangle'public shape

7

public'triangle$double a,double b&'shape$a,b&7=

double computeMarea$&

7

return $$#Hy&G+&6

=

=6

class rectangle'public shape

7

public'

rectangle$double a,double b&'shape$a,b&7=

double computeMarea$&

7

return #Hy6

=

=6

int main$&

7

int op,ch;16

double a,b6

shape Hs6

cout44>?n*nter base and height of a triangle' >6

J


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cin55a6

cin55b6

triangle t$a,b&6

s;Vt6

cout44>?n"rea of triangle' >44s-5computeMarea$&44>?n>6

cout44>?n*nter length and breadth of rectangle' >6

cin55a6

cin55b6

rectangle r$a,b&6

s;Vr6

cout44>?n"rea of rectangle' >44s-5computeMarea$&44>?n>6

return 6=

OUTPUT

)


51/110

PROGRAM NO: 15

DATE: 0#/0!/2014

TRY&CATCH

Write a program that will read the denominator and numerator and if denominator is zero

throw an e#ception with message denominator cannot be zeroT

CLASS DIAGRAM

PROGRAM

3include4iostream5


class *#ception

7

float a,b,c6

public'

void read$&

7

cout44>*nter two numbers' >6

cin55a55b6

=

void divide$&7

try

7

if$b;;&

throw$b&6

else

7

)1


52/110

c;aGb6

cout44>Desult' >44c44>?n>6

=

=

catch$float&

7

cout44>enominator cannot be zeroPPP?n>6

=

=

=6

int main$&

7*#ception e6

e.read$&6

e.divide$&6

return 6

=

OUTPUT

)+


53/110

PROGRAM NO: 1

DATE: 0#/0!/2014

BUBBLE SORT USING FUNCTION TEMPLATEImplement bubble sort using function template

CLASS DIAGRAM

PROGRAM

3include4iostream5

3include4stdio.h5

3include4stdlib.h5


template 4class t5

class bubble

7

t a8+):6

public'

void get$int&6

void sort$int&6void display$int&6

=6

template 4class t5

void bubble 4t5''get$int n&

7

int i6

cout44>*nter the array elements'>6

)


54/110

for$i;6 i4n6i6

for$i;6i4n6i6

=

template 4class t5void bubble 4t5''sort$int n&

7

int i,6

t temp6

for$i;6i4n6i


55/110

7

cout44>?nUubble sort?n>6

cout44>?nNptions?n1.Integer?n+.!loating /oint?n.Eharacter?n.*#it?n*nter your

choice' >6

cin55ch6

switch$ch&

7

case 1'

7

cout44>?nInteger Sort?n>6

bubble4int5 b16

cout44>*nter the size of array' >6cin55n6

b1.get$n&6

b1.sort$n&6

b1.display$n&6

break6

=6

case +'

7

cout44>?n!loating /oint Sort?n>6

bubble4float5 b+6

cout44>*nter the size of array' >6

cin55n6

b+.get$n&6

b+.sort$n&6

b+.display$n&6

break6

=6

case '

7

cout44>?nEharacter Sort?n>6

bubble4char5 b6

))


56/110

cout44>*nter the size of array' >6

cin55n6

b.get$n&6

b.sort$n&6

b.display$n&6

break6

=6

case '

e#it$&6

default'

cout44>Invalid Ehoice?n>6return 6

=

=

=

)2


57/110

OUTPUT

)


58/110

PROGRAM NO: 1!

DATE: 14/0!/2014

CLASS TEMPLATE

Write a class template to represent a generic array. Include member functions to perform

the following tasks'

1. Ao initialize the array

+. Ao modify the value at a given position in the array.

. Ao multiply by an element in a given location with a scalar value

. Ao display the elements in the array.

CLASS DIAGRAM

PROGRAM

3include4iostream5

3include4stdlib.h5


template4class A5class myarray

7

A arr8+:6int n,pos6

public'

void read$&

7

cout44>?n*nter the size of array' >6

cin55n6

cout44>?n*nter the elements' >6

)9


59/110

for$int i;6i4n6i6

cin55b6

arr8pos-1:;b6

cout44>?nKodified "rray>6

=

=

void multiply$&

7

cout44>?n*nter the position' >6

cin55pos6

if$pos5n&

cout44>?nCo such position?n>6

else

7

int b6

cout44>?n*nter the element to be multiplied' >6

cin55b6

arr8pos-1:;bHarr8pos-1:6

cout44>?nKultiplication done?n>6

=

=

)J


60/110

void display$&

7

for$int i;6i4n6i6

=

=6

int main$&

7

int ch,c,a6

myarray4int5m16

myarray4double5m+6

do7

cout44>?nNptions?n1.Integer?n+.ouble?n.*#it?n*nter your choice' >6

cin55c6

switch$c&

7

case 1'

do

7

cout44>?nInteger?n>6

cout44>?nNptions?n1.Initialize?n+.Kodify?n.Kultiply with a

value?n.isplay?n).*#it?n*nter your choice' >6

cin55ch6

switch$ch&

7

case 1'm1.read$&6

break6

case +'m1.modify$&6

break6

case 'm1.multiply$&6

break6

case 'm1.display$&6

2


61/110

break6

=

=

while$chP;)&6

break6

case +'

cout44>?nouble?n>6

do

7

cout44>?nNptions?n1.Initialize?n+.Kodify?n.Kultiply with a

value?n.isplay?n).*#it?n*nter your choice' >6

cin55ch6switch$ch&

7

case 1'm+.read$&6

break6

case +'m+.modify$&6

break6

case 'm+.multiply$&6

break6

case 'm+.display$&6

break6

=

=

while$chP;)&6

break6

case ' e#it$&6

=

cout44>/ress 1 to continue else press ' >6

cin55c6

=

while$cP;&6

=

21


62/110

OUTPUT

2+


63/110

2


64/110

2


65/110

2)


66/110

PROGRAM NO: 1#

DATE: 14/0!/2014

FILE PROGRAM

E


67/110

if$ch;;Q Q&

c


68/110

PROGRAM NO: 1%

DATE: 15/0!/2014

EMPLOYEE DB

Implement *mployee db. Ahe db should hold details of *mplyee$I,name,address,phno&.

1. "dd a *mployee

+. Bpdate a employee records.

. Search a employee.

. elete a employee.

CLASS DIAGRAM

PROGRAM

3include4iostream5

3include4fstream5

3include4string.h5


class employee7

int id6

char phnno8+:6

char name8+:6

char addr8+:6

public'

void add$&6

29


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void display$&6

void update$&6

void del$&6

void search$&6

int menu$&6

=6

main$&

7

int n6

employee e6

n;e.menu$&6

switch$n&7

case 1 ' e.add$&6 break6

case + ' e.del$&6 break6

case ' e.update$&6 break6

case ' e.display$&6 break6

default' cout44>Ahankyou?n>6

=

=

int employee''menu$&

7

int a6

cout44>?nKain Kenu?n>6

cout44>?n1."dd?n+.elete?n.Bpdate?n.isplay?n).*[IA?n>6

cout44>*nter your choice' >6

cin55a6

return$a&6

=

void employee''add$&

7

ofstream f6

employee t6

2J


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int #;16

f.open$>empdb>,ios''appRios''binary&6

while$#;;1&

7

cout44>*nter the id' >6

cin55t.id6

cout44>*nter the name' >6

cin55t.name6

cout44>*nter the phone number' >6

cin55t.phnno6

cout44>*nter the address' >6

cin55t.addr6f.write$$char H&Vt,sizeof$t&&6

cout44>?nDecord Successfully "dded PP>6

f.close$&6

cout44>?n/ress 1 to add more record' >6

cin55#6

=

main$&6

=

void employee''del$&

7

int #;1,flag;,eid6

employee t6

ofstream f16

ifstream f+6

while$#;;1&

7

flag;6

cout44>*nter the id to be deleted' >6

cin55eid6

f1.open$>temp>,ios''appRios''binary&6


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f+.open$>empdb>,ios''appRios''binary&6

while$f+.read$$char H&Vt,sizeof$t&&&

7

if$eidP;t.id&

f1.write$$char H&Vt,sizeof$t&&6

else

flag;16

=

f1.close$&6

f+.close$&6

remove$>empdb>&6

rename$>temp>,>empdb>&6if$flag;;1&

cout44>Decord is successfully deleted?n>6

else

cout44>Decord not found?n>6

cout44>?n/ress 1 to delete another record else /ress ' >6

cin55#6

=

main$&6

=

void employee''update$&

7

int #;1,eid6

int flag;6

ofstream f16

ifstream f+6

employee t6

while$#;;1&

7

flag;6

f1.open$>temp>,ios''appRios''binary&6

f+.open$>empdb>,ios''inRios''binary&6

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cout44>*nter the id to be modified' >6

cin55eid6

while$f+.read$$char H&Vt,sizeof$t&&&

7

if$eidP;t.id&


else

7

cout44>*nter the new name' >6

cin55t.name6

cout44>*nter the new place' >6

cin55t.addr6cout44>*nter the new phone no' >6

cin55t.phnno6


flag;16

=

=

f1.close$&6

f+.close$&6

remove$>empdb>&6

rename$>temp>,>empdb>&6

if$flag;;1&

cout44>Decord is successfully updated?n>6

else

cout44>Decord is not found?n>6

cout44>/ress 1 to update another record *lse press ' >6

cin55#6

=

main$&6

=

void employee''search$&

7

+


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ifstream f6

int flag;,s6

employee t6

cout44>?n*nter id ' >6

cin55s6

f.open$>empdb>,ios''inRios''binary&6

f.seekg$&6

while$f.read$$char H&Vt,sizeof$t&&&

7

if$s;;t.id&

7

flag;16t.display$&6

break6

=

=

if$flag;;&

cout44>*ntry Cot !ound PPP?n>6

f.close$&6

=

void employee''display$&

7

ifstream f6

int flag;6

employee t6

cout44>*A"IS "D*PPP?n>6

f.open$>empdb>,ios''inRios''binary&6

f.seekg$&6

while$f.read$$char H&Vt,sizeof$t&&&

7

flag;16

cout44>?n------------------------------?n>6

cout44>Id '>44t.id6


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cout44>?nCame '>44t.name6

cout44>?n/hone number '>44t.phnno6

cout44>?n"ddress '>44t.addr44>?n>6

=

if$flag;;&

cout44>?n !I* IS *K/A@?n>6

f.close$&6

main$&6

=


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OUTPUT

)


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2


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PROGRAM NO: 20

DATE: 15/0!/2014

PASSING FILE NAME AS ARGUMENTS

/assing file name as arguments, put even numbers in one file and odd numbers in another

file.

CLASS DIAGRAM

PROGRAM

3include4iostream5

3include4fstream5

3include4string5


class evenodd7

public'

void find$char Hfn1,charHfn+&

7

int i,n,a8+:6

char ch6

cout44>?n*nter the limit' >6cin55n6

cout44>?n*nter the elements' >6

for$i;6i4n6i


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for$i;6i4n6i6

else

f+44a8i:44> >6

=

f1.close$&6

f+.close$&6

f1.open$fn1,ios''in&6

f+.open$fn+,ios''in&6

f1.close$&6f+.close$&6

=

=6

int main$int argc,char Hargv8:&

7

evenodd ev6

ev.find$argv81:,argv8+:&6

cout44>?n>6

return 6

=

OUTPUT

9


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DATABASE MANAGEMENT

SYSTEM

J


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'UESTION 1

DATE: 13/05/2014

C()*) ,) -.. *) * ***6) 7*) 6)*8 * *6)( ,)

-.. 9)()6;

9


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E&R DIAGRAM

CREATING DATABASE

database1;5 create database sea6

ED*"A* "A"U"S*

database1;5 ?c sea

SS connection $cipher' (*-DS"-"*S+)2-S(", bits' +)2&

@ou are now connected to database >sea> as user >user1>.

TABLE DESCRIPTION

B.*:

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6)* -(.? .*@

S*.(6:

6)* -(.? 6*.(6@

9+


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R)6)()6:

6)* -(.? ()6)()6@

'UERIES

1. ist sid, sname of all Sailors

6)*


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+.ist sailors whose rating is less than )

6)*


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2. ist the name of sailors who reserve a red boat

6)*


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'UESTION 2

DATE: 20/05/2014

A 7.)) *?66. ***6) ,*6 ,) -.. *)6:

C.(6)*?)8 8 (*.8 . .- 6)*6 8 . .- 6)68 F))/S)?8 )*(?)

D)*(?)N.8 N*?)8 . .- 7.(6)

S) 8 *?)8 7.(6)8 S)?)6)(8 A()66

H.6)7.(6)8 . .- (..?68 .77)8 F))/?.,

F))R)?68 7.(6)8 6)?)6)(8 *)

E&R DIAGRAM

92


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CREATING DATEBASE

database1;5 create database college6

ED*"A* "A"U"S*

database1;5 ?c college


@ou are now connected to database >college> as user >user1>.

TABLE DESCRIPTION

C.)):

7.)) -(.? 7.(6)@

9


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D)*(?):

7.)) -(.? )*(?)@

S):

7.)) -(.? 6)@

99


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H.6):

7.)) -(.? ,.6)@

F))R)?:

7.)) -(.? -))R)?@

9J


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'UERIES

1. !ind the course with id +.

7.))


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). Write a function that accepts the course name and displays the no of seats available.

7.))


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. Ereate a trigger to restrict the entry to the hostel if rooms are all filled.

7.))


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'UESTION 3

DATE: 03/02/2014

M.) ?ID8 )8 K)*(8 ()7.( - Ahe movie with id mI has a title, a release year and

a director

R)))( (ID8 *?) - Ahe reviewer with id rI has a name

R* (ID8 ?ID8 6*(68 (*D*) - Ahe reviewer rI gave the movie mI a number

of stars rating $1-)& on a certain ratingate.

E&R DIAGRAM

CREATING DATABASE

database1;5 create database movies6

ED*"A* "A"U"S*

database1;5 ?c movies


@ou are now connected to database >movies> as user >user1>.

J


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TABLE DESCRIPTION

M.)6:

?.)6 -(.? ?.)@

R)))(:

J


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?.)6 -(.? ()))(@

R*:

?.)6 -(.? (*@

J)


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. Write a trigger which will display error message when you are deleting a row from

movie table.

?.)6


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'UESTION 4

DATE: 10/0/2014

S)(66: ))(8 6*?): 6(8 *()66: 6(

P*(6: ))(8 *?): 6(8 7..(: 6(

C**.6: ))(8 : ))(8 7.6: ()*

E&R DIAGRAM

CREATING DATABASE

database1;5 create database shop6

ED*"A* "A"U"S*

database1;5 ?c shop


@ou are now connected to database >shop> as user >user1>.

JJ


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TABLE DESCRIPTION

S)(6:

6,. -(.? 6)(6@

P*(6:

1


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6,. -(.? *(6@

C**.:

6,. -(.? 7**.@

11


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'UERIES

1. !ind the names of suppliers who supply some red part.

6,.


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). !ind the pids of parts supplied by every supplier at less than \+

6,.


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6,.= )@

6,.= **) 69@

CREATE FUNCTION

6,.


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'UESTION 5

DATE: 1!/0/2014

F,6$flno' integer, from' string, to' string, distance' integer, departs'

time, arrives' time&

A(7(*-$aid' integer, aname' string, cruisingrange' integer&

C)(-)$eid' integer, aid' integer&

E?.K))6$eid' integer, ename' string, salary' integer&

$Ahe ma#imum distance from a base that the fuel capacity of a ship or aircraft

will allow it to travel and then return safely at cruising speed' a fuel capacity of ++gallons should give a cruising range of around + miles&

E&R DIAGRAM

1)


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CREATING DATABASE

database1;5 create database airport6

ED*"A* "A"U"S*

database1;5 ?c airport


@ou are now connected to database >airport> as user >user1>.

TABLE DECRIPTION

F,6:

*(.( -(.? -,6@

12


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A(7(*-6:

*(.( -(.? *(7(*-@

E?.K))6:

*(.( -(.? )?.K))6@

1


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C)(-):

*(.( -(.? 7)(-)@

'UERIES:

1. !ind the eids of pilots certified for some Uoeing aircraft.

*(.(


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. !ind the details of all the aircraft.

*(.( -(.? *(7(*-@

. Identify the flights that can be piloted by every pilot whose salary is more than \1,. $(int'

Ahe pilot must be certified for at least one plane with a sufficiently large cruising range.&

*(.(


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*(.(

3.cpp&dbms record

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