e on so 1 Cau 1:Nhng loi hp cht hu c mch h no ng vi cng thc tng qut CnH2nO. A. Ru khng no n chc B. Anehit no C. Xeton D. Tt c u ng Cau 2:Cn bng hai phng trnh phn ng sau bng phng php in t : KClO3 + HCl Cl2 + KCl + H2O; Cc h s theo th t cc cht lnlt l: A. 2,3,3,1,3B. 1,3,3,1,3 C. 2,6,3,1,3D. 1,6,3,1,3 Cau 3: T khi hi ca mt anehit X i vi hiro bng 28. Cng thc cu to ca anehit l: A. CH3CHOB. CH2=CH-CHO C. HCHOD. C2H5CHO Cau 4: Cho 8,8 gam mt hn hp gm 2 kim loi 2 chu k lin tip thuc phn nhm chnh nhm II tc dng vi dung dch HCl d cho 6,72 lt kh hiro iu kin tiu chun, H=100%.Hai kim loi l: A. Be v Mg B. Ca v Sr C. Mg v Ca D. Sr v Ba Cau 5: C mt hp cht hu c n chc Y, khi t chy Y ta ch thu c CO2 v H2O vi s mol nh nhau v s mol oxi tiu tn gp 4 ln s mol ca Y. Bit rng: Y lm mt mu dung dch brom v khi Y cnghp hiro th c ru n chc.Cng thc cu to mch h ca Y l: A. CH3-CH2-OHB. CH2=CH-CH2-CH2-OH C. CH3-CH=CH-CH2-OHD. CH2=CH-CH2-OH . Cau 6: Cho phan ng Na2SO3 +KMnO4 + H2O co san pham la: A.Na2SO4, KOH, K2MnO4, B.SO3 MnO2, KOH C. Na2SO4, MnO2, KOHD. Cac chat khac Cau 7: Mot chat hu c X cha C, H, O ch cha mot loai chc cho 2,9gX phan ng vi dung dch AgNO3/NH3 d thu c 21,6g Ag. Vay X co the la:A. HCHO B. OHC CHO C. CH2(CHO)2 D. CH3 CHO Cau 8: Pha loang 25ml H2SO4 96% (d=1,839g/ml) vi H2O thanh 0,5ltdung dch co nong o mol la: A. 0,45 MB. 0,9 M C. 1,2 M D. 2,5 M Cau 9: Khi cho 0,56 lt (kc) kh HCl hap thu vao 50ml dung dch AgNO3

8% (d=1,1g/ml). Nong o % HNO3 thu c la:A. 6,3% B. 1,575% C. 3% D. 3,5875% 1Cau 10: Hai hydrocacbon A, B la ong ang ke tiep co t khoi hi so vi H2 bang 12,65. Vay A, B co the la: A. CH4, C2H6 B. C2H4 , C3H6 C. C2H2 , C3H4D. C3H4, C4H6 Cau 11:Cho 3g hon hp gom 3 kim loai ng trc H2 trong day hoat ong hoa hoc phan ng het vi H2SO4 d, thu c 1,008 lt H2 (kc). Co can dung dch thu c mg ran. Vay m co the bang: A. 7,32gB. 5,016gC. 2,98g D. Ket qua khac Cau 12:Hon hp X gom: C3H8, C4H10 co t khoi oi vi H2bang 25,5. Thanh phan % theo so mol la: A. 20 va 80 B. 50 va 50C. 25 va 75D. Ket qua khac Cau 13: X la nguyen to nhom VA. Cong thc hidroxit (trong o X the hien so oxi hoa cao nhat) nao sau ay la khong ung :A. HXO3B. H3XO3C. H4X2O7D. H3XO4 Cau 14: So snh tnh axit ca cc cht sau y: CH2Cl-CH2COOH (1), CH3COOH (2),HCOOH (3), CH3-CHCl-COOH (4) A. (3) > (2) > (1 ) > (4)B. (4) > (2) > (1 ) > (3) C. (4) > (1) > (3). > (2)D. Kt qu khc Cau 15: ot chay 1,68 lt hon hp CH4, C2H4 (kc)co M =20 ; thu x gam CO2. Vay xbang : A. 6,6gB. 4,4g C. 3,3gD. Ket qua khacCau 16: ot chay Chat hu c A co mCO2: mH2O = 1,833.Vay CTCT cua A la: A. C3H7OH B. CH3 O C2H5

C. Glyxerin D. a,b,c eu ung. Cau 17: ot chayankan X co mol X : mol O2 = 2 : 13.Khi CrackingX se thu c toi amay olefin ? A. 1B. 2C. 3D. 4 Cau 18: Hydrocacbon co %H = 14,29va khong co ong phan se co CTPT la: A. C2H4B. C4H10C. C3H6 D. a,c eu ung Cau 19:ot chay hydrocacbon A co mCO2: mH2O =4,889. Vay CTTN cua A la: A. (CH2)nB. (C2H6)n C. (CH3)nD. (CH)n Cau 20: Hai cht hu c X v Y u n chc l ng phn ca nhau. t chy hon ton 5,8 gam hnhp X v Y cn 8,96 lt oxi (ktc) thuc kh CO2 v hi nc theo t l VCO2 : Vhi H2O = 1 : 1 (o cng iu kin). Cng thc n gin ca X v Y l:A. C2H4O B. C3H6OC. C4H8O D. C5H10OCau 21:Khi dan mot luong kh clo qua dung dch KOH loang nguoi thu c san pham co cha: A. KClO B. KClO2 C. KClO3 D . Khong phan ng Cau 22: Khi cho Cl2 vao dung dch Ca(OH)2 ta thu c clorua voi. Vay2cong th cua clorua voi la: A. Ca(OCl)2 B. CaOCl2

C. CaCl2 va Ca(OCl)2 D. b,c eu ung Cau 23: ot ru A. Dan het sam pham chay vao bnh ng ddCa(OH)2

d; thay co 3 gam ket tua va khoi lng bnh tang 2,04 gam. Vay A la: A. CH3OH

B. C2H5 OH C. C3H7OHD. C4H9OHCau 24: Hoa tan het 1,62g bac bang axit nong o 21% ( d=1,2 g/ml) ; thu oc NO.The tch dung dch axitnitrictoi thieu can phan ngla : A. 4mlB. 5mlC. 7,5mlD. Gia tr khac Cau 25:Mot oxit kim loai:x yMO trong o M chiem 72,41% ve khoi lng . Kh hoan toan oxit nay bang CO, thu c 16,8 gam M. Hoa tan hoan toan lng M nay bang HNO3 ac nongthu c 1 muoi va x mol NO2.Vay x co gia tr nao? A. 0,45B.0,6 C.0,75 D. 0,9 Cau 26: Hn hp X gm 2 axit no: A1 v A2. t chy hon ton 0,3mol X thu c 11,2 lt kh CO2 (ktc). trung ha 0,3 mol X cn 500ml dung dch NaOH 1M. Cng thc cu to ca 2 axit l:a. CH3COOH v C2H5COOHc. HCOOH v HOOC-COOH b. HCOOH v C2H5COOHd. CH3COOH v HOOC-CH2-COOH Cau 27: Cho 1,152g hon hp Fe, Mg vao 0,1 lt dung dch AgNO3. Khi phan ng xong thu c 5,792g hon hp 2 kim loai . Vay % Mg la: a. 58,34% b. 41,66% c. 72,2%d. Ket qua khac Cau 28: Cho24,8 gam hn hp gm 1 kim loi kim th v oxit ca n tc dng vi dung dch HCl dthu c 55,5g mui khan.Kim loaitren se la: a.Cab. Sr c. Bad. MgCau 29: Co 3 chat ran Ba(HCO3)2, Mg(HCO3)2, (NH4)2CO3 k hieu A, B, C.Lay chat B nung thu chat ran B1. Cho B1 vao H2O thu dung dch B2. Vay:A. B la Mg(HCO3)2 , ddB2 la Mg(OH)2 B. B la Ba(HCO3)2, ddB2 Ba(OH)2 C. B la Ba(HCO3)2, ddB2 BaCO3

D. B la Mg(HCO3)2 , ddB2 MgCO3Cau 30: 30g hon hp Cu, Fe tac dung u vi 14lt kh Cl2 (kc). Vay %Cu theo khoi lng : A. 45% B. 60%C. 53,33% D. 35,5% Cau 31: t chy hn hp 2 ru ng ng c s mol bng nhau, ta thu c khi CO2 v hi nc c t l s mol: nCO2 : nH2O = 2 : 3.3 Cng thc phn t 2 ru ln lt l:A. CH4O v C3H8OB. C2H6O v C3H8O C. CH4O v C2H6O D. C2H6O v C4H10O Cau 32: Cho 2,8g bot Fe va 2,7g bot Al vao dung dch co 0,175molAg2SO4 . Khi phan ng xong thu c x gamhon hp 2 kim loai. Vay x la:A. 39,2g B. 5,6g C. 32,4gD. Ket qua khac Cau 33: Dung dch A gm HCl, H2SO4c pH = 2. trung ha hon ton 0,59 gam hn hp 2 amin n chc no bc 1 (c s C khng qu 4) phi dng 1 lt dung dch A. CTPT 2 amin : A. CH3NH2 v C4H9NH2B. CH3NH2 v C2H5NH2

C. C3H7NH2 D. C4H9NH2 v CH3NH2 hoc C2H5NH2

Cau 34: Cho phan ng : C4H6O2 + NaOH B + D;D + Z E + Ag B co the ieu che trc tiep c t CH4 va C2H6.Vay B co the la: A. CH3COONa B. C2H5COONaC. a, b eu ungD. a, b eu sai Cau 35: Hai cht hu c A, B u c cng thc phn t C3H4O2. Cho 0,1 molmi cht tc dng vi NaOH d, ta ln lt thu c cc mui natric khi lng tng ng l 9,4g; 6,8g. CTCT ca A v B : A. CH3COOH v HCOOCH3 B. CH2=CH=COOH v HCOOH=CH2 C. C2H5COOH v CH3COOCH3

D. Cac cong thc khacCau 36:Cho 9,4g K2O vao 200g dung dch KOH 5,6% thu dung dch A x%. Vay x la: A. 8%B. 9,6%C. 10,7%D. Ket qua khac Cau 37:Tron V1 lit dung dch H2SO4co pH = 3vi V2 lit dung dch NaOH co pH = 12 e c dung dch copH =4, th ty leV1: V2 co gia tr nao? A. 9:11B. 101:9C. 99:101D. Ty le khac Cau 38: t chy hon ton 1,52 gammt ru X thu c 1,344 lt CO2

(ktc) v 1,44 gam H2O. Cng thc phn t ca X l: A.C3H8O2 B. C3H8O3C. C4H8O2 D. C5H10O2 Cau 39: Dn hai lung kh clo i qua hai dung dch KOH: dung dch mtlong v ngui, dung dch hai m c un nng ti 100oC. Nulng mui KCl sinh ra trong hai dung dch bng nhau th t l th tch clo i qua hai dungdch KOH bng bao nhiu ?A. 5/6B. 5/3 C. 8/3D. 10/3Cau 40: Cho 2,4 gam mt hp cht hu c X tc dng hon ton vi dungdch AgNO3 d trong NH3 thuc 7,2 gam Ag. CTCT ca X: A. CH3CHOB. C2H5CHOC. HCHOD. C3H7CHO Ti liu do Trung tm luyn thi i hc CLC Vnh Vin cung cp 4 e on so 2 Cau 1: Cho m g hon hp gom 3 kim loai ng trc H2 trong day hoat ong hoa hoc phan ng het vi H2SO4 d, thu c 1,008 lt H2 (kc). Co can dung dch thu c 7,32 g ran. Vay m co the bang: A. 3gB. 5,016g C. 2,98gD. Ket qua khac Cau 2:Cho hn hp Z gm 2 ru c cng thc CxH2x+2O v CyH2yO bit: x + y - 6 v y x 1. Cng thc phn t hai ru l: A. C3H8O v C5H10O B. CH4O v C3H6O C. C2H6O v C4H8OD. C4H10O v C6H12O Cau 3: Trong CuFeS2 co:A. So oxi hoa cua Fe, Cu lan lt bang +2 , +2 B. So oxi hoa cua Fe, Cu lan ltbang +3, +2 C. So oxi hoa cua Fe, Cu lan ltbang +2, +1 D. A, B,C eu saiCau 4: Cho 8,8 gam mt hn hp gm 2 kim loi 2 chu k lin tip thucphn nhm chnh nhm II tc dng vi 120 ml dung dch HCl 1M,c6,72 lt (kc) kh hiro Hai kim loi l:A. Be v Mg B. Ca v Sr C. Mg v CaD. A, B eu ung Cau 5: C mt hp cht hu c n chc Y, khi t chy Y ta ch thu c CO2 v H2O vi s mol nh nhau v s mol oxi tiu tn gp 4 ln s mol ca Y. Bit rng: Y lm mt mu dung dch brom v khi Y cng hp hiro th c ru n chc. Cng thc cu to mch h ca Y l: A. CH3-CH2-OH B. CH2=CH-CH2-CH2-OH c. CH3-CH=CH-CH2-OH d. CH2=CH-CH2-OH . Cau 6: Cho p R + HNO3 + HCl X+ NO + H2O; Vi R la kim loaiVayX la: A. R(NO3)n B.RCln C. R(NO3)n ; RClnD. A,B,C sai Cau 7: M2(CO3)n+ HNO3 ac Muoi X+ NO2 + H2O+ CO2 (1). Vay M la : A. Zn B. Cu C.FeD. Al

Cau 4: FeS2+ A FeSO4 + H2S +S(1). Vay A la : A.H2SO4 (loang)B. H2SO4 (ac) C. A, B eu ungD. A, B eu saiCau 5:e nhan biet NaHCO3 va NH4HSO4ta co the dung: A. ddHCl B. ddBa(OH)2 C. ddNaOH D. A, B, C eu cCau 6: ChohhA; Ag, Cu Fe phan ng het vi HNO3; thu c hhG:NO, NO2; thay lng nc tang 7,2 gam. 1So mol HNO3 tham gia p bang: A. 0,35 mol B. 0,25 mol C. 0,2 mol D. Gia tr khac Cau 7:Ket luan nao ung?/. ccNc/|O2 cc l|nh cczc. B. /|(OH)3,Zn(OH)2 |c ccc cczc |Ucng l|nh. C. Trong hp chat O luon co so oxi hoa bang -2 D. Phenc|cc khc ncng |cm Uy l|m hcc cc. Cu 8:Cho phan ng CnH2n + KMnO4 + H2OMnO2 + KOH +X.Vay X: A . Phan ng c vi Cu(OH)2 B.Glicol C.ieu che c axit axetic D.Tat ca eu ung. Cau 9: Co cc phn ng:(1) Fe3O4 + HNO3 ; (2) FeO + HNO3 (3) Fe2O3 + HNO3 ; (4) HCl + NaAlO2 + H2O (5) HCl + Mg ; (6) Kim loai R + HNO3 Phn ng no l phn ng oxi ha kh:A. 1,2,4,5,6 B. 2,6,3C. 1,4,5,6 D. 1,2,5,6 Cau 10:Cc ccc chcl: CU(1),HC| (2),ccKNO3(3),ccleSO4 (5); ccle2(SO4 )3 (6); O2(7) fU ccc chcl lren cc lhe lcc nh|eU nhclcUcc:/.

2 pUng

B.3 pUngC. 4pUng D. 5 pUng

Cau 11:Chc ccl/| vcc cUng c|ch hcn hcp:NcNO3 , NcNO2, NcOH e ccc phcn Ung nh|eU nhclccng: /.TB. 2 C. 3D.G|c lr| khcc Cau 12:Cho bit qu trnh no di y l s oxi hoa ? A. MnO42- Mn2+ C. C6H5-NO2 C6H5-NH2 B.SO42- SO2 D. A, B, C eu saiCau 13: t chy a mol mteste no ; thu c x mol CO2 v y mol H2O.Bit x - y = a. Cng thc chung ca este: A. CnH2n-2O2 B. CnH2n-4O6

C. CnH2n-2O4 D. CnH2nO2 Cau 14: M tac dng vi HNO3 : M + HNO3 M(NO3)2 +2x N2 +3x NO + H2O 1.Ty khoi hi cua hh G: (N2; NO) so vi Hydro se bang: A. 16,75B. 14,6C. 17D. Gia tr khac2. He so can bang lan lt la: A. 17, 66, 17, 4, 3, 33B. 17, 66, 17, 2, 3, 33 C. 29, 64, 29, 1,3 , 32D. 29, 72, 29, 4, 6, 36 Cau 15: Mt anhit n no c %O=36,36 v khi lng. Tn gi ca anhitny l: A. PropanalB. 2-metyl propanalC. EtanalD. Butanal Cau 16: Dung dch A:0,1mol M2+ ; 0,2 mol Al3+; 0,3 molSO42-va conlai la Cl-. Khi co can ddAthuc 47,7 gamran.2 Vay M se la: A. MgB. FeC. Cu D. Kim loai khac Cau 17:R-NO2 +Fe +H2OFe3O4 +R-NH2 Cc h s theo th t cc cht ln lt l: A. 4,9,4,3,4 B. 4,8,4,3,4C. 2,4,2,3,4D. 2,3,2,3,4 Cau 18:Cho p X++ H+ M2+ + NO +H2O.3NO Cc h s theo th t cc cht ln lt l: A. 3,4,8,3,4,4B. 3,2,8,3,2,4 C. 3,6,8,3,6,4D. 3,8,8,3,8,4 Cau 19: Mot chat hu c A cha C,H,O co % O =37,21. A co the la: A. CH3OHB. C3H8O C. C4H9OH D. C3H8O3

Cau 20: Nhng loi hp cht hu c mch h no ng vi cng thc tng qut CnH2nO. A. Ru khng no n chc B. Anehit no C. Xeton D. Tt c u ngCau 21:(CnH2n1COO)3CmH2m1la CTTQ cua Este sinh bi :A. Ru no, 3 chc va axit n chc cha no co1 lkC=C B. Ru cha no co 1 lkC=C, 3 chc Va axit 3 chc C. Ru 3 chc, co 2 lk vaaxit n chc co1 lkC=C D. A,B, C eu sai.Cau 22: CffC cUc Estesinhbi axit n nova ong ang benzen la: A.CnH2n-6O2 B.CnH2n8O2

C.CnH2n - 4 O2D. CnH2n -2O2. Cau 23: (A) la este n chc, mach C h vaco: 9C Om m : 8 = . Co tat ca bao nhieu CTCTcua (A)co the co: /.3 B. 4 C. 5D. Cau 24: Cho NO2 p vi NaOH d, thu c ddA. Cho Al vao ddA; thuc hh gom 2 kh . Vay 2 kh la: A. H2,NO2 B. NH3, CO2 C. NO,NO2 D. A,B eu ung Cau 25: Este A co% O = 44,44. Vay A co CTPT la: A.C6H4O4B . C6H8O4C.C6H!2O4 D.C6H!4O4 Cau 26:Hoa tan het hhA:0,1 mol Zn; 0,2 mol Ag; 0,3 mol Fetrong ddHNO3; thu c dung dch B khong cha NH4NO3 va hon hp G gom:0,01 mol N2Ova0,03 mol NO. Vay so mol HNO3can pco the bang: A. 1,35 mol B. 1,3 molC. 1,25 molD. 1,15 mol Cau 27: / chUc C,H,O cc O = 53,33. Kh| / pU vc Nc vc vc| NcHCO3

cc ly |e mc|/: mc| H2 = T:T vc mc|/: mc| CO2 = T:T . Vcy CfPfcUc / |c: /. C2H4O2B. C3HO3 C. C4H8O3 D. C5HTO4

Cau 28: Cho 1,8 gam mot axit (A) n chc p het vi NaHCO3. Dan het kh thu c vao bnh ddKOH d; thay khoi lng chat tan trong bnh tang 0,78 gam. Vay (A ) co CTCT: 3 /.C2H5 COOH B.C3H7COOH C.CH3COOH D. Ccng lhUc khccCau 29: ot ru A. Dan het sam pham chay vao bnh ng ddCa(OH)2

d; thay co 3 gam ket tua va khoilng bnh tang 2,04 gam. Vay A la A. CH4O B. C2H6 O C. C3H8OD. C4H10OCau 30: Ba cht hu c X, Y, Z cng cha C, H, O. Khi t chy mi cht lng oxi cn dng bng 9 ln lt oxi c trong mi cht tnh theo s mol v thu c CO2, H2O c t l kt lng tng ng bng 11: 6. th hi mi cht u nng hn khng kh d ln (cng nhit , p sut). Cng thc n gin nht ca X, Y, Z l: A. (C2H6O)n B. (C4H10O)nC. (C3H8O)n D. Kt qu khc Cau 31: Cho 4 cp oxi ha kh sau: Fe2+/Fe; Fe3+/Fe2+; Cu2+/Cu; 2H+/H2

Th t tnh oxi ha tng dn ca cc cp trn: A. Fe2+/Fe < 2H+/H2 < Cu2+/Cu < Fe3+/Fe2+ B. Fe3+/Fe2+ < 2H+/H2 < Cu2+/Cu < Fe2+/Fe C. Fe2+/Fe < 2H+/H2 < Cu2+/Cu < Fe3+/Fe2+

D. Fe2+/Fe < Cu2+/Cu < 2H+/H2 < Fe3+/Fe2+ Cau 32: Hn hp X gm 2 axit no: A1 v A2. t chy hon tona mol X thu c 11,2 lt kh CO2 (ktc). trung haamol X cn 500ml dung dch NaOH 1M. Cng thc cu to ca 2 axit l: A. CH3COOH v C2H5COOH B. HCOOH v HOOC-COOH C. HCOOH v C2H5COOH D. CH3COOH v HOOC-CH2-COOH Cau 33: Mt ankanol X c 60% cacbon theo khi lng trong phn t. Nucho 18 gam X tc dng ht vi Na th th tch kh H2 thot ra ( iukin chun) l:A. 1,12 lt B. 2,24 lt C. 3,36 lt D. 4,46 ltCau 34: Cho s chuyn ha sau: Cl2 A B C A Cl2.Trong A, B, C l cht rn v u cha nguyn t clo.Cc cht A, B, C l:A. NaCl; NaOH v Na2CO3 C. CaCl2; Ca(OH)2 v CaCO3 B. KCl; KOH v K2CO3 D. C 3 cu A, B v C u ng Cau 35: Co ddA: HF 0,1M va NaF 0,1 M; Biet: pH cua ddAse co bang: 46, 8.10 ; log 6, 8 0, 83= Ka= A. 2,17B.3,17 C. 3,3 D. 4,2Cau 36:Co ddA:3NH0,1 M va 4NHCl0,2M 1. Vi hang so ien ly cua: 4NH+455.10NHK += . pH se co gia tr nao? A. 4B.5 C. 9D. 10 2. Vi hang so ien ly cua: 3NH391/ 5.10NHK= .pH sebang: A. 12B.11 C. 10 D. 9 4Cau 38:un nng 11,5g ru etylic xc tc H2SO4 c 140oC thu c a gam cht hu c. Khi hiu xut 75% a bang : A.9,2500gB. 13,8750gC. 6,9375gD. 18,5000g Cau 39: X cha C, H, O co MX = 60 vC. X co so ong phan phan ng c vi NaOH bang: /.TB. 2 C. 3 D.4Cau 40: Ket luan nao ung ? A. RX la dan xuat halogenC . a,b eu ungB. RX la esteD. a,b eu sai. Tai lieu cung cap bi TT luyen thi H chat lng cao Vnh Vien 5e on so 3 Cau 1: t chy hon tonXthu c403,2ml CO2 (ktc) v 0,270 gam H2O. X tc dng vi dung dch NaHCO3 v vi natri u sinh ra cht kh vi s mol ng bng s mol X dng. Cng thc cu to ca X l: A. HO-C4H6O2-COOH B. HOOC-(CH2)5-COOH C. HO-C3H4-COOH D. HO- C5H8O2-COOH Cau 2:Hoa tan het 3,8 gam oxit can 100ml dung dch hon hp: Ba(OH)2 0,15M,KOH 0,2M . Vayoxit co the la: A. Al2O3 B. Cr2O3. C. ZnO.

D. PbOCau 3: 1,68 lt hon hp A: CH4, C2H4 (kc)co KLPTTB bang 20. otchay hoan toan hhA; thu x gam CO2. Vay xbang : A.3,3gB. 4,4g C . 6,6g D. Ket qua khacCau 4: Cau hnh e cua nguyen X thuoc Chu K 4 co 1 e oc than se la: A. 1s2 2s2 2p6 3s2 3p63d5 4s2 4p5 B.1s2 2s2 2p6 3s2 3p6 4s2 4p5

C. 1s2 2s2 2p6 3s2 3p63d10 4s2 4p5 D.1s2 2s2 2p6 3s2 3p6 4s2 4p6 5s2 5p5

Cau 5: Tron 100ml dung dch H2SO4 0,4M vi 200ml dung dch NaOH 0,4M thu dung dch muoi co pH la: A. 0 B. 7 C.12D. pH >7 Cau 6: Tron 100 ml dung dch HCl vi 150 ml dung dch KOH thu dungdch ch co H2O, KCl. Tron 150 ml dungdch HCl vi 150 ml dungdch KOH thu dung dch co: A. H2O, KClB. H2O, KCl, KOHC. H2O, KCl, HClD. H2O, KCl, HCl,KOH Cau 7: Trn 100ml dung dch Ba(OH)2 0,5M vi 100ml dung dch KOH 0,5M ,c dung dch X. Nng mol/l ca ion OH- trong dung dch la: 12 A.0,25MB. 0,75MC. 0,5MD. 1,5M Cau 8: Co 3 hydrocacbon co cung so cacbon mot chat trong so o la (CH3)n.Vay 3 chat o la: A. C4H12, C4H8, C4H10 B. C2H2, C2H4, C2H6 C. C6H18, C6H12, C6H10D. Tat ca eu saiCau 9:Khi the 1 lan vi Br2 tao 4 san pham. Vay ten goi la: A. 2,2 dimetyl pentan.C. 2,3dimetylbutan B. 2,3metyl pentan. D. 2,2 dimetyl butan Cau 10: : Co P 3S + 6KOH 2K2S + K2SO3 + 3H2O A.phan ng tren la t oxi hoa kh. B. phan ng tren la phan ng trao oi. C. phan ng tren co S la chat kh va KOH la chat oxi hoa. D. A, B, C eu sai Cau 11: Cho hh:AO, B2O3 vao dd MOH c dung dchtrong suot cha: /. l/O2 vc l(BO2)2B. l2/O2 ,lBO2 vc B2O3 C. l2/O2 ,lBO2vc lOH D. l2/O2 vc l2BO2 Cau 12: / chUc C,H,O cc O = 53,33. Kh| / pU vc Nc vc vc| NcHCO3

cc ly |e mc|/: mc| H2 = T:T vc mc|/: mc| CO2 = T:T . Vcy CfPfcUc / |c: /. C2H4O2B. C3HO3 C. C4H8O3 D. C5HTO4

Cau 13: Cho 1,8 gam mot axit (A) n chc p het vi NaHCO3. Dan het kh thu c vao bnh ddKOH d; thay khoi lng chat tan trong bnh tang 0,78 gam. Vay (A ) co CTCT: /.C2H5 COOH B.C3H7COOH C.CH3COOH D. Ccng lhUc khccCau 14: Cho cc hp cht hu c sau: (1)etandiol 1,2; (2)propandiol 1,3;(3) propandiol 1,2;(4) glixerin. Cc cht no l ng phn ca nhau: C.1,2 B. 1,4 C. 2,3 D. 1,2,3 Cau 15: Vi cong thc C3H8O co theieu che c nhieu nhatbaonhieu ete A. 1B. 2 C. 3D. 4 Cau 16:Cho 0,336 lit SO2 (kc)p vi 200ml dd NaOH; thu c 1,67 g muoi. Nong o ddNaOH em p la: A. 0,01MB.0,1 MC. 0,15 MD. 0,05 M Cau 17:Mot chat hu c X cha C, H, O ch cha mot loai chc cho 2,9g X phan ng vi dung dch AgNO3/NH3 d thu c 21,6g Ag. Vay X co the la:A. HCHOB. OHC CHO C. CH2(CHO)2 D. CH3 CHO Cau 18: Pha loang 25ml H2SO4 96% (d=1,839g/ml) vi H2O thanh 0,5lt dung dch co nong o mol la: A. 0,45 MB. 0,9 M C. 1,2 MD. 2,5 M Cau 19: Khi cho 0,56 lt (kc) kh HCl hap thu vao 50ml dung dch AgNO3

8% (d=1,1g/ml). Nong o % HNO3thu c la: A. 6,3%B. 1,575%C. 3%D. 3,5875% Cau 20: Nguyen t cua mot nguyen toX co 9 obitan va co 2 electron oc than. Nguyen t X co trong quang nao? A. Synvinit B. olomit C. Manhetit D. Mica Cau 21: Hoa tan het 1,52 gam oxit can 100ml dd hh: Ba(OH)2 0,025M,KOH 0,15M . Vayoxit co the la: A. Al2O3 B. Cr2O3. C. ZnO.

D. PbOCau 22: Trong cac phan ng sau: (1):Zn + CuSO4(2): AgNO3 + KBr (3):Na2CO3 + H2SO4 (4): Mg + H2SO4 Phan ng nao la phan ng trao oi A. Ch co 1, 2B. Ch co 2,3C. Ca 4 pD. Ch co 1, 4 Cau 23: Cho hh: AO, B2O3 vao ncthu c ddX trong suot cha: /. /(OH)2, B(OH)3 B. /(OH)2, B2O3 C. /(OH)2, /3(BO2)2D. /(OH)2, /(BO2)2 Cau 24: Hp cht hu c Z p vi dung dch AgNO3 /NH3 ( d) thu c 2 muoi X, Y. Cho X, Y tc dng vi dung dch NaOH uthu c kh v c A. X pvi dd H2SO4thu c kh vo c B. 34 1. Cac kh A, B l: A. CO2, SO2 B. H2, N2 C. SO2 , H2D. CO2, NH3 2. Z co the la: A. HCOO-NH4 B. (CH2O)nC. HOCCHO D. A,B eu ung Cau 26: un ru (A) vi HBr,thu c chat hu c (B) co %Br = 58,4.(A) la: A.C2H5OHB.C3H7OHC.C4H9OH D.CH2=CH-CH2OHCau 27: t chy hon ton mt chat hu c A nhiu ln axit thu c4,032lt kh CO2 (o ktc) va 2,7 gam nc. CTN A la: A. (C2H3O2)nB. (C4H7O2)n C. (C3H5O2)n D. (C2H4O2)n Cau 28: un ru etylic vi H2SO4 ccc, T7cC, lhU cUcc hh hc| / gcm 4 chcl kh|. Vcy hh/ cc: A.C2H4, H2Ohi, H2 , CO2 C. C2H4, H2Ohi, H2, SO2 B. C2H4, H2Ohi, SO2, CO2D. A,B,C u sai.Cau 29:Cho s phn ng: CH=CH X Y CH3COOH cc cht X,Y theo th t l: A.CH3CHO, CH3CH2OHB. CH2=CH2, CH3CH2OH C. C2H5Cl, C2H5OH D. A,Bng. Cau 30 :t chy hon ton 0,09g este n chc B thu c 0,132g CO2 v0,054g H2O. CTPT ca B l: A.C2H4O2 B. C3H6O2

C. CH2O2D. C4H8O2 Cau 31: Co 5 dung dch ng trong cac lo mat nhan : BaCl2, NH4Cl, (NH4)2SO4, NaOH, Na2CO3. Ch dung quy tm ta nhan biet c: A. BaCl2 B. NaOH C. BaCl2, Na2CO3 , N aOH D. Nhan biet c tat ca Cau 32: Bnh co mg bot Fe, nap Cl2 d vao bnh. Khi phan ng xong chatran trong bnh tang 106,5g. Vay m la: A. 28gB. 14g C. 42gD. 56g Cau 33: R-CH2OH + KMnO4 R-CHO +MnO2 +KOH + H2O Cc h s theo th t cc cht ln lt l: A. 6,2,3,3,3,3B. 3,2,3,2,2,2C. 6,2,6,2,2,2D. 4,2,4,2,2,2 Cau 34 :Cho 0,125 mol oxit kim loai phan ng het vi HNO3; thu uc NO va ddBcha mot muoi duy nhat. Co can dung dch B thu c 30,25 gam ran. Vay oxit co the la: A. Fe2O3B. Fe3O4

C. Al2O3 D. FeO Cau 35: Co 4 lo mat nhan : Etanol, ddGlucoz, Glyxerin, Etanal. Neu ch dung 1hoa chat lamthuoc th e nhan biet cac chat tren th tachon: A. Na kim loai B. ddAgNO3/NH3 C. Cu(OH)2D. CuO Cau 36: Cho cac chat sau: (1) Etyl oxalat;(2): Caprolactam;(3): Glucoz(4): Tinh bot(5): Saccaroz (6):Mantoz (7): Fuctoz Nhng chat co phan ng thuy phan la: A. 1, 3 va 4,6B.1, 2, va 5,6,7 C. 1, 2,4, va 6 D. 3,2 va 5,6 Cau 37: Chc ccc phcn Ung: D ( mcl |cc| cUcng)2, ,oHO H tA++ + B /+ H2,oNi tE (clc|l hcy crc|lc|),B+ H2,oNi tE /. G|Ucczc B. lrUclczc C. SccccrczcD. lcnlczc Cau 38: CcU h|nh e c phcn |cp ngcc| cUc X2|c 3p. X |c: /. C B.S|C. SD. O Cau 39: Cho 1,52g hon hp 2 ru n chctac dunghet vi Na dthu 2,18g muoi. Vay hai ru la: A. CH3OH, C2H5OH B. C3H7OH, C4H9OHC. C2H5OH, C3H7OH D. C3H5OH, C4H7OH Cau 40:o manhaxit tang dan theo th t: A.C2H5COOH, C3H7COOH, CH3COOH, HCOOH B.CH3COOH, C3H7COOH, C2H5COOH, HCOOH 56C. C3H7COOH, C2H5COOH, CH3COOH, HCOOH D. HCOOH, CH3COOH, C2H5COOH, C3H7COOH Tai lieu cung cap bi trung tam luyen thi Vnh Vien e on so 4 Cau 1: Axitacrylic(CH2=CH-COOH)ccngthcchungl:A.(C2H3COOH)nB.C2nH3nCOOHC.CnH2n1COOHD.CnH2nCOOH Cau 2: Cc cht c th c|eU chetrc tipX (C, H, O) cc O = 34,78 |c /.CH2= CH2 B. (CH2O)n C. C2H4O D. c, c, c ceU cUng Cau 3: /) |c cncehyl cc O =37,2T. (/) cc lhec|eU che : /. C2H4(OH)2B. C3H(OH)2C. C4H8(OH)2D. CH3OHCau 4:K2Cr2O2 + C6H12O6 + H2SO4 Cr2 (SO4)3 +CO2 +K2SO4 +H2O Cc h s theo th t cc cht ln lt l: A. 4,2,8,2,3,1,1B. 4,1,16,4,6,4,2,2C. 2,1,8,2,3,2,1,1 D. 8,2,8,2,4,4,2,2 Cau 5: t chy hon ton mt chcl hu c A nhiu ln axit thu c1,344 lt kh CO2 (o ktc) v 0,9 gam nc. CTN A l: A. (C2H3O2)nB. (C4H7O2)n C. (C3H5O2)n D. (C2H4O2)n Cau 6: Cac axit khong lam mat mau ddBr2 co the la: A. (C2H3O2)n B. (C4H7O2)n

C. (C3H5O2)n D. /,B,C ceU cUng Cau 7: Cht X cha cc nguyn t C, H, O trong oxi chim 53,33% v khi lng. Khi t chy X u thu c s mol nc bng smol X; bit 1 mol X phn ng va ht vi 2mol Ag2O trong dung dch amoniac. X la: A. CH3CHOB. C2H5CHO C. H-CHO D. OHC-CH=CH-CHOCau 8: Andehitacrylic(CH2=CH-CHO)ccngthcchungl:A.(C2H3CHO)nB.C2nH3nCHOC.CnH2n1CHOD.CnH2nCHOCau 9: fhUy phcn X cUcc cn phcm gcm g|Ucczc vc frUclczc. X |c: A.Saccaroz B.Mantoz C. Tinh botD. Xenluloz Cau 10: Hoa tan m gam hhA:Cu, Ag trong ddhh: HNO3, H2SO4; thu c ddB cha 7,06 gam muoi va hhG: 0,05 mol NO2; 0,01 mol SO2 .Khoi lng hhA bang: A.2,58B.3,06C.3,00 D. Gia tr khac Cau 11:X cha C, H, O co MX = 60 vC. X co so ong phan phan ngc vi NaOHbang: A.1B. 2 C. 3D. 4 Cau 12:un 6,96 gam ruAvi 10,4 gam CuO (d). Saup thu c motandehyt n chc B va8,48 gam ran. CTPT A; B se la: A. CH3OH, H-CHO B. CH2=CH-CH2OH, CH2=CH-CHO C. C2H5OH, CH3 CHOD. C3H7OH, C3H7-CHO Cau 13: Cho12,1gamhnhp2kimloiA,Bchatr(II)khngitcdngvidungdchHCltora0,2molH2.Haikimloil:A.Mg,CaB.Mg,ZnC.Fe,ZnD.Ba,FeCau 14: C 4 dung dch trong sut, mi dung dch ch cha mt loi cation v mt loi anion. Cc loi ion trong c 4 dung dch gm Ba2+, Mg2+, Pb2+, Na+, SO4 2-, Cl-, CO32-, NO3-. Trong 4 dung dch o co 2 dd chua cac ion sau: A.; C. 3NO 2; ; Cl Na Mg+ + 232;3; ; NO Na Pb CO + + B. ;D.A vc C 42SO 2; ; Cl Na Ba+ +Cau 15: Chc pU: MClO3 + HCl Cl2 + MCl + H2O; Cc h s theo th t cc cht ln lt l: A. 2,3,3,1,3B. 2,6,3,1,3 C . 1,3,3,1,3D. 1,6,3,1,3 Cau 16:Trong mt cc nc cha a mol Ca2+, b mol Mg 2+, c mol Cl- v d mol HCO3 - Biu thc lin h gia a, b, c, d l:A. a+b=c+dB. 3a+3b=c+dC. 2a+2b=c+dD. Kt qu khc Cau 17: Hcc lcn helmgcm hh/: lg, CU, le lrcng HNO3 , lhU cUcc ,8 ||l NO 2 (ckc) vc cUng c|ch B chUc 3,8 gcm mUc|. Vcy m cc g|c lr|: /. T,32g C.T, 3g C. T,2g D. T,8g Cau 18: Cc ccc chcl: CU(1), H2SO4 (2),ccCU(NO3)2(3), ccleSO4 (5); ccle2(SO4 )3 (6); O2(7) fU ccc chcl lren cc lhe lcc nh|eU nhclcUcc: /.2 pUng

B.3 pUng C. 4pUng

D. 5 pUng Cau 19: Chc 2,4g hcn hcp gcm: lg,le, /|phcn Ung hel vc| HC| cU, lhU cUcc V ||l H2 (ckc) vc 5,85 gcm hh mUc| . Vcy V cc lhe ccng: /. ,T25B. ,8TC. ,84D. Kel Uc khcc Cau 20: Chc2,3g hcn hcp gcm: lg, le, /|phcn Ung hel vc| H2SO4 , HC|, lhU cUcc T,8 ||l H2 (ckc). Cc ccn cc lhU cUcc mg rcn. Vcy m cc lhe ccng: /. 7,32gB. 5,TgC. 2,8g D. Kel Uc khcc Cau 21: Hcc lcn hh/: ,Tmc| CU2S, ,5mc| leS2 lrcng HNO3, lhU cUccccB. Chc cc Bc(NO3)2 cU vcc ccB. ScU pU e lhU cUcc ccc nh|eU gcmkel lUc?/. 34,5 gB.4,g C.4,75g D. G|c lr| khcc Cau 22: frcn Tg cc/gNO3 T7 vc| 2 g ccle(NO3)2 T8, lhU cUcccUng c|ch / cc khc| |Ucng r|eng ccng T,44 g]m|. Vcy lhe l|ch cUng c|ch e ccng: /.2 m| B. 25m| C.27,4m|D. 275 m| Cau23:.fhemm|vccTm|cc/ccpH=.pHcUccclhUcUcce ccng:/. B.TTC. TD.8 Cau 24Chc m gcm BcO vcc nUcc cUcc 2 m| cc / cc pH = T3. Vcy m e ccng: /. T,53B.T5,3 C.,T8 D.G|c lr| khcc Cau 25: Chc ,T mc| leC|3 lcc cUng hel vc| cc Nc2CO3 cU, Se lhU cUcc : /. T,7 gcm kel lUc .C. TT, gcm kel lUcB. 2,2 gcm kel lUcD. , gcm kel lUc Cau 26:Ket luan nao ung?/. ccNc/|O2 cc l|nh cx|l. B. /|, Cr, Zn |c ccc k|m |cc| |Ucng l|nh. C. Trong hp chat O luonco so oxi hoa bang -1 D. Phenc|cc khc ncng |cm Uy l|m hcc cc. Cau 27: Chcl X (C, H, O) cc O=34,78 . Cc cht c th c|eU che lrc liep X |c: /. C2H5 OCO CH3 B. HOC2H4COONc C. CHT2OD. /, B, C ceU cUcc Cau 28: X co tong so proton va notron nho hn 35 va co tong ai soso oxi hoa dng ln nhat va hai lan so oxi hoa am nho nhat bang 1. X co the la:A. Cl B. SC. P

D. Si Cau 29: Khi nhiet phan NaNO3 thu c : A. Na, O2, N2 B. NaNO2, O2 C. Na2O, N2 D Na2O, NO2, N2 Cau 30: FeS2 + HNO3 N2Ox + X. Vay X co the la: A. Fe(NO3)3 + S + H2OC. Fe(NO3)2 + S + H2O B. Fe(NO3)2 + H2S + H2OD. Fe3+, SO42-, H2O Cau 31: Cho p Cu + KNO3 + HCl X+ NO + H2O;X la: A.Cu(NO3)2 B.CuCl2 C. Cu(NO3)2 ; CuCl2D. A,B,C ung Cau 32: Tm cau sai trong cac cau sau:A. Gia hai cap oxi hoa- kh phan ng xay ra theo chieu chat oxi hoamanhnhat se oxi hoa chat kh manh nhat tao ra chat oxi hoa yau hn va chat kh yeu hn B. Phan ng oxi oa kh la phan ng trong o co s cho va nhan electron C. Qua trnh oxi hoa la qua trnh nhng electron qua trnh kh la qua trnh nhan electron D. Khi tron chat oxi hoa vi chat khse xay ra phan ng oxi hoa kh Cau 33: FeS2+ H2SO4( loang) FeSO4 + H2S + A (1). Vay A la : A. SO2 B. SC. Fe2(SO4)3 D. A, B, C eu saiCau 34: Conhieu nhat bao nhieu phan ng co dang : BaCl2+ ? NaCl + ? A. 3B. 4C. 5 D. 6

Cau 35: Cho p FeS2 + HNO3 + HCl X + H2SO4 + NO + H2O; X la: A.FeSO4 B.Fe(NO3)3C. FeCl2 D. FeCl3

Cau 36: Ket luan nao ung?/. ccNc2CO3 khcng|cm cc| mcU Uy l|m . B. /|, Zn |c ccc k|m |cc| |Ucng l|nh. C. Trong hp chat H luon co so oxi hoa bang +1 D. fcch nUcc G|yxer|ne lcc cn phcmcc khc ncng lrcngCu 37: Trongccaxitsau,axitphnngcviZntorakhH2l:A.HCl,H2SO4

mcC.HCllong,H2SO4long

B.HNO3

long,H2SO4

longD.HClvHNO3

Cu 38: Mantozo v tinh bt u c phn ng A.vi dung dch NaClB. Thu phn trong mi trng axit C. trng gngD. Mu vi it Cu 39: ddHClcthphnngcvinhngchtnotrongccchtsau:A.Cu,CuO,Ba(OH)2,AgNO3,CO2C.Qutm,Cu,CuO,Ba(OH)2

B.NO,AgNO3,CuO,Zn,qutmD.Ba(OH)2,AgNO3,CuO,Zn,qutmCu 40: Trong s cc loi t sau: (1)[ - NH (CH2)6 NH OC (CH2)4 CO - ]n (2)[-NH-(CH2)5-CO-]n (3)[C6H7O2(OOC-CH3)3]n T thuc loi si poliamit l: A.(1), (3)B. (1), (2)C. (1),(2),(3)D. (2), (3) Tai lieu cung cap bi TT luyen thi H CLC Vnh Vien e On So5 Cau 1: ot chaychat hu c, mach h X thu 1,008 lit CO2 (kc) va 1,08gam H2O. Vay X la: A. C3H8O B. C4H8OC. C2H6 O D. C4H10O Cau 2: Hoa tan hhA: 0,1mol Cu2S, 0,05mol FeS2 trong HNO3; thu c ddB. Cho dd Ba(OH)2 dvao ddB. Sau p se thu c bao nhieu g ket tua? A. 34,95 g B.46,6gC.46,75g D. 61,75 g Cau 3: Tm phat bieu sai A. Xycloankan la hydrocacbon noB.ankin la hydrocacbon co hai lien ketC.Ch co anken ot chay th mol CO2 =mol H2OD. axittac dung c AgNO3/NH3 Cau 4: Izopren (2-metyl butadien 1,3) tac dung vi Br2 (1:1 mol) tao c A. 1 san phamB. 2 san pham C. 3 san phamD. 4 san pham Cau 5: ot het chat hu c A. Dan het sam pham chay vao bnh ng dd Ba(OH)2 d; thay co 5,91 gam ket tua va khoi lng bnh tang 1,86gam. Vay A la: A. CH2O B. C2H6O C. C3H8O D. C4H10O Cau 6:Nguyen t euco Z khong qua 20 va co 2 ecletron oc than la: A. C, S ,OB. N,P , S C. Si, O, S,lD. A, C eu ung Cau 7: Cho m gamhon hp gom: Mg, Fe, Alphan ng het vi HCl;thu c 0,896 lt H2 (kc) va 5,856 gam hh muoi . Vay mco the bang: A.3,012B.3,016C.3,018 D. Ket qua khac Cau 8:Andehitno,nchcccngthcchunglCnH2n+1CHO.Vyandehitno,haichcccngthcchungl:A CnH2n+1(CHO)2B CnH2n1(CHO)2

C CnH2n(CHO)2D R(CHO)2

Cau 9: Ccchtcthc|eU chelrc l|pchcl X (C, H, O) co % O = 53,33% la: A.CH2= CHCl

B. C2H6OEdited by Foxit ReaderCopyright(C) by Foxit Software Company,2005-2006For Evaluation Only. C. C2H6O2 D. A, B, C eu ung Cau 10: Cho hn hp cht hu c mch h c cng thc phn t C3H6O2 hp cht c th l:A. Axit hay este n chc no. B. Xeton hai chc no C. Anehit hai chc no D. Ru hai chc cha no c 1 lin kt i Cau 11: Dn hai lung kh clo i qua hai dung dch KOH: dung dch mt long v ngui, dung dch hai m c un nng ti 100oC. Nu lng mui KCl sinh ra trong hai dung dch bng nhau th t l th tch clo i qua hai dung dch KOH bng bao nhiu ? /. 5]B. 5]3 C. 7]3D. T]3 Cau 12: Chc 2,24| CO2 (ckc) hcp lhU hccn lccn cc| T5 m| cUng c|ch NcOH Tl khc| |Ucng hcn hcp mUc| lcc lhcnh |c : /T4,2BT2,4C T5,3 D . T3,7 Cau 13: CfPf ncc cU ccy |c khcng cUng /C3HO2NBC5HTTNC.C7HT8N3C|DCnH2n 2C|2l Cau 14: cl chcy mcl |Ucng cm|n ccc nhcl cUcc 8,8g CO2, 7,2g H2O vc 2,24|N2 (ckc). /m|n lren cc ccng lhUc: / CH3NH2 BC2H4(NH2)2 CC2H7NH2 DCcng lhUc khcc Cau 15: Tnginosaivicngthctngng: /. H2N CH2 COOH: g||x|n B. CH3 CHNH2 COOH: /|cn|n C. HOOC CH2 CH2 CH(NH2) COOH : /x|l g|Ulcm|c D. H2N CH2 CH2 CH2 CH2 CH(NH2) COOH :||z|n Cau 16:Hc| |cn ccn ngUyen lU X2+ vc Y ceU cc ccU h|nh e nhU ccU h|nh e cUc ngUyen lU TNe. Vcy c p lrcng X2+ vc Y |cn |Ucl |c : /T4 vc 8BT2 vc C T vc TD8 vc TT Cau 17: Tchnc2ruA,Blintip, ch c T cnken cUy nhl ./ ,Bl: /. CH3OH ,C2H5OH B.PU ely||c,PU nprcpy||c C .PU nprcpy||c ,PUncUly||cD. PU lerlcUly||c , nprcpy||c Cau 18 :Hcn hcp kh| X gcm (C3H8 vc C4HT) cc l| khc| cc| vc| H2 |c 25,5. fhcnh phcn lhe l|ch |c : / 5 vc 5B 25 vc 75C 45 vc 55D 2 vc 8 Cau 19 :frcng cUng c|ch /|2(SO4)3 |ccng cc chUc , mc| lh| cUng c|ch cc cc chUc: 24SO / ,2 mc| /|2(SO4)3B,4 mc| /|3+

CT,8 mc| /|2(SO4)3D Cc /vc B ceU cUng Cau 20:phnbitccchtalanin,axitglutamicvmetylamin,chcndng: /. CU(OH)2, lc B. phenc|phlc|e|n C. DUng cch Nc2CO3 D. CU l|m Cau 21 Cc ccc nh|eU |cc| kh| lhU cUcc kh| chc ccc hcc chcl rcn hcy cUng c|ch cU ccy phcn Ung vc| nhcU : /| , leS , HC| , NcOH , (NH4)2CO3 ? / .TB.3C. 4 D. 2 Cau22: Chc T,8 gcm hn hp 2 rU / ,Btcdng Nc vc , lhU c T7,4gammuiNa.SmolkhH2thotral: /.,T5 mc|B. T,5 mc|C.3 mc|D. 3,2 mc| Cau23: Chohnhpgm0,1molphenolv0,1molaxitaxetictcdnghontonvi300mlddBr21M.ChoddsauphnngtcdngviddNaOH0,2M.SmlddNaOHcnl: /.2 B.2C.TD.T Cau24: Cho8gamhnhpgmMg,Cutcdngvi20gamddHClcC%=36,5%,thuc0,1molkhH2.KhilngCutronghnhpl:/.Nhiunhtl5,6gam B.ll nhl 2,4 gcm C.2,4 gcmD.5, gcm Cau 25 :AndehitAccngthcnguynl(C4H6O)n.AtcdngH2(Ni,t0),thucruB.ChoBtcdngNadthnH2=nB.TA,muniuchthytinhplexiglat,cntnhtmyphnng?(ccchtkhcc) /. 2 phn ng B.3 phn ngC.4 phn ng D.5 phn ng Cu26: l chy ml hn hp cc ng ng cc cneh|l lc lhU c: mc| CO2 = mc| H2O lh| | | cy ng ng:/./neh|l n chc nc B./neh|l v|ng ncC./neh|l hc| chc ncD.C /, B, C U ngCu27: HnhpAgm3kimloiCu,X,Fe.tchrickimloiXrakhihnhpA,mkhnglmthayikhilngX,dng1hachtduynhtlmuinitratst.VyXl: /./gB.PcC.ZnD./| Cu28: Hcp chcl hUU cc / cc 2 |cc| nhcm chUc, mc nhcmCOOH gcp 3 |cn nhcm OH. B|el rcng / cc CfN |c (CH8O7)n. CfCf lhU gcn cUc / |c : /.C3H4(COOH)3(OH)B.CH(COOH)(OH)2 C.CHT(COOH)(OH)3D.Khcng xcc c|nh cUcc Cu29: HnhpAgm3chtrn.ChdngddNaOHd,unnng,tchcchtckhilngphntlnnht.3chtrnl:/./|2O3 ,le2O3 ,S|O2B./|2O3 ,le2O3 ,lgO C.BcO ,leO, /|2O3 D.CUO, /|2O3 ,ZnO Cu30: Chohnhp2kimloiMg,ZntcdngvidungdchCuSO4,chnhp2muivhh2kimloi,l:/.lgSO4 , ZnSO4 , CU ,ZnB.lgSO4 , ZnSO4 ,CU,lg C.CUSO4 ,ZnSO4 , CU ,lg D.CUSO4 ,ZnSO4 , lg ,Zn Cu31:KhiunnngmtrunchcAviH2SO4ctrongiukinnhitthchhpthucsnphmBctkhihisoviAl0,7.VycngthccaAl:A .C3H7OH B.C2H5OHC.C3H5OHD.C4H7OHCu32:tchyhtamolmtaminoaxitAc2amolCO2v2,5amolH2O.Accngthcphnt:A.C2H5NO4 B.C2H5N2O2 C.C2H5NO2 D.C4H10N2O2

Cu33:HpchtYldnxutchaoxicabenzen,khilngphntcaYbng108v.C. Y khcng lcc cUng NcOH , nhUng lcc cUng Nc Ccng lhc cU lc cc Y |c : A.C6H5OHB.p-CH3C6H4OH C.C6H5-CH2-OH D.KtqukhcCu34: HnhpAgmAl2O3voxitkimloiMXOY.ChokhH2d,nungnngAqua,cchtrn.ChochtrnquadungdchNaOHd,nktthc,crnB.ChoBtanhttrongddHCld,khngckhthotra.MXOYl:A.CuOB.MgO C.ZnO D.Fe3O4

Cu35:Trongphnng:3Cl2+6KOHKClO3+3H2OA.Cl2lchtkh,KOHlchtoxiho B.Cl2valchtoxihovalchtkhC.Cl2lchtoxiho,KOHlchtkhD.Khcng cc chcl khU ,chcl cx| hccCu36:PhntchmtaminoaxitA,choktqu:54,9%C,10%H,10,7%NvMX=131.CngthcphntcaXl:A.C6H13O2N B.C4H14ON2 C.C6H15O2N D.KtqukhcCu37: CcchtnodiyutcdngviNa?A.C3H5OH,C2H6O,PhenolB.Phenol,rubenzylic,benzenC.Phenol,ruetylic,propanonD.C2H5OH,C3H5OH,H2OCu38:HnhpAgm3chtrn.ChdngdungdchH2SO4longd,tchcchtckhilngphntnhnht.3chtrnl:A.BaO,CuO,Al2O3B.Al2O3,Fe2O3,MgO C.Al2O3,Fe2O3,NaOH D.Al2O3,Fe2O3,SiO2Cu39:ChoMgtcdngvidungdchhnhp2muiCuSO4,FeSO4,c2muiv2kimloi.l:A.FeSO4,CuSO4,Cu,Fe B.MgSO4,FeSO4,Cu,FeC.MgSO4,CuSO4,Cu,MgD.MgSO4,FeSO4,Mg,FeCu40:HnhpXgm3ruA,B,D,trongB,Dl2rungphn.tchyhonton0,04molXthuc0,07molCO2.Vycngthcphntcaccrulnltl:A.CH4OvC3H8OB.CH4OvC3H6OC.CH4OvC3H4OD.C2H6O,C3H8OGV.NguynTnTrungTTluynthiihcCLCVnhVin

e on so 6 Cu1:ot hoan toan hon hp X gom:etan, propan thu c san pham co 2 2: 11:CO H OV V 15 = .Thanh phan % theo so mol tng ng la:a. 20 va 80b. 50 va 50c. 25 va 75d.75 va 25Cu2:Tnhchthohcchungcakimloil: a.Dbkhb.Khboxiho c.Dthamgiaphnng d.DboxihoCu3:ChtnocthoxihoZnthnhZn2+: a.Fe b.Al3+ c.Ag+ d.Mg2+

Cu4:Tdyinhocakimloitasuyra: a.Kalidboxihonht b.IonK+dbkhnht c.Au3+ctnhoxihomnhnht d.avcCu5:Cpnokhngckhnngxuraphnng a.DungdchCu(NO3)2vdungdchNaOH b.NunghnhpFevZnO c.DungdchZnCl2vdungdchNaOH d.Na2CO3vdungdchHClCu6:DungdchFeSO4clntpchtCuSO4.Chtnosauycthloibtpcht: a.BtFed,loc b.BtAld, loc c.BtCudlocd.TtcusaiCu7:KhinhngmtlZnvodungdchCo2+,nhnthycmtlpCophbnngoilZn.KhinhnglPbvodungdchmuitrnthkhngthychintnggxayra.Nuspxpcccpoxihokhcanhngkimloitrntheochiutnhoxihocacatontngdnthcchspxpnosauylng? a.Zn2+/ZnCu2+/Cu>Fe2+/Fe d.TtcusaiCu9:Hoa tan het 1,62g bac bang dd HNO3 21% ( d=1,2g /ml) , giaiphong NO duy nhat .The tch dung dch axit can lay la : a. 4mlb. 5mlc. 7,5md. 10 ml

Cu10: ot chay mot ru c mot so mol nc gap oi so mol CO2.Ru a cho la : A. Ru etylic C. Glyxerin B. Etylenglycol D. Ru metylicCu11:KhiinphnhnhpdungdchNaClvCuSO4,nudungdchsaukhiinphnhotanAl2O3thngxyratrnghpnosauy: a.NaCld b.NaCldhocCuSO4d c.CuSO4d d.NaClvCuSO4b

inphnhtCu12:KhicholungkhHydrro(cd)iquangnghimchaAl2O3,

FeO,CuO,MgOnungnngnkhiphnngxyrahonton.Chtrncnlitrongngnghimgm: a.Al2O3,FeO,CuO,Mg b.Al2O3,Fe,Cu,MgO c.Al,Fe,Cu,Mg d.Al,Fe,Cu,MgOCu13:Bcclnngkimloi,dngphngphphohcnosauythucAgtinhkhin: a.NgmhnhpAgvCutrongdungdchAgNO3. b.NgmhnhpAgvCutrongdungdchCu(NO3)2

c.NgmhnhpAgvCutrongdungdchHCl. d.NgmhnhpAgvCutrongdungdchH2SO4cnng.Cu14:Trong phan t anilin, nhom NH2 anh hng en vong benzennh the nao : a. Lam tang mat o electron cua nhan benzenb. Lam giam mat o electron cua nhan benzen c. Khong anh hng d. Tat ca eu saiCu15:NgmmtvtbngCuckhilng20gtrong100gdungdchAgNO34%.KhilyvtrathkhilngAgNO3trongdungdchgim17%.Khilngvtsauphnnglbaonhhiu: a.10,76g b.21,52g c11,56g d.20,68gCu16: Cho 2a mol NO2 vao dd chaa mol Ba(OH )2 . Them tiep vai giotdd phenolphthalein vao bnh pse thay: a. Khong mau o b. Luon khong mau c. Luon comauo d. o Khong mau Cu17:Cho4gamhhA:FeS2vCu2SphnnghtviH2SO4cthuc24,48litkh(KC).Ty le moltng ngca2muil:a.2:1b.1:2c.3:1d.1:3Cu18:Hglntpchtlkm,thit,ch.Dnghochtnosauyloitpcht: a.DungdchZn(NO3)2 b.DungdchHgSO4

c.DungdchPb(NO3)2 d.KhngtchcHgvHglchtlng

Cau 18: Pha loang 25ml H2SO4 96% (d=1,839g/ml) vi H2O thanh 0,5lt dung dch co nong o mol la: a. 0,45 M b. 0,9 M c. 1,2 Md. 2,5 M Cau 19: Khi cho 0,56 lt (kc) kh HCl hap thu vao 50ml dung dch AgNO3 8% (d=1,1g/ml). Nong o % HNO3 thu c la: a. 6,3% b. 1,575% c. 3%d. 3,5875% Cau 20: Hydrocacbon ch co 2 ong phan la: a.C2H6 b. C4H1c. C3H d. a,b eu ung Cau21: 30g hon hp Cu, Fe tac dung u vi 14 lt kh Cl2 (kc). Vay %Cu theo khoi lng : a. 45%b. 60% c. 53,33%d. 35,5% Cau 22: ien phan dung dch NiSO4 cc tr vi I=2A thu 2,36g kim loai cc am, hieu suat ien phan la 80%.Vaythi gian ien phan la (cho Ni=59) a. 3860 giay b. 4825 giayc. 7720 giayd. Ket qua khac Cau 23: 3 hydrocacbon co cung so cacbon . Mot chat trong so o la (CH3)n. Vay 3 chat o la: a. C4H12, C4H8, C4H10 b. C2H2, C2H4, C2H6 c. C6H18, C6H12, C6H10d. Tat ca eu sai Cau24:BenzenkhongphanngviBr2trongdungdchnhngphenollai lam mat mau dung dch brom nhanh chong, v : a) Phenol co tnh axit b) Tnh axit cua phenol yeu hn ca axit cacbonic c) Do anh hng cua nhom -OH,cac v tr otho va para trong phenol giau ien tch am, tao ieu kien de dang cho tac nhan Br+ tan cong vao cac v tr tren.3d) Phenol khong phai la mot dung moi hu c tot hn nh benzen. Cu 25: Trong s cc tn gi sau: 3 metyl butan (1); 2,3 dimetyl butan (2);3,3 dimetylbutan (3) V 2,3,3 trimetyl butan (4), ten gi ng l: a.(1) b. (2)c. (1) (2) v (4)d. C 4 u ng Cu 26: Cc cht ng phn l: a.Cc cht c cng cng thc phn t c cu to khc nhau b. Cc cht lun lun c s cacbon bng nhau c. Cc cht c cng phn t lng d, Tt c u ng Cu 27: 1,2 g cht hu c A (C, H, O) qua ng CuO, un nng thu c m gam H2O 1.76g CO2 v ng CuO gim 1,28g th m gam H2O l: a.0,72gb. 0,36gc. 1,08gd. Tt c u sai Cu 28: T khi i vi H2 ca hn hp gm hi 2 ru n c mol bng nhau l 22,5. Vy 2 ru l: a.C2H5OH, C3H7OHb. CH3OH, C3H7OH c. CH3, C4H9OHd. CH3OH, C3H5OH Cu 29: Cho 2,48g hn hp C3H7OH v ru a X chc tc dng Na d thu 0,672 lt H2. Vy X l: a.C2H5OHb. C3H5OH c. C4H9OHd. CH3OH Cu 30: Ru n chc A c %khi lng oxi l 32. Cht A c iu cht anehit X. Vy X l: a.CH3CHOb. HCHO c. CH2 = CH CHOd. Cht khc Cu 31: Vi C2H6O2 th cht ny l: a.ru no 2 chcb. Anehit no 2 chc c. este no n chcd. Tt c u ng Cu 32: Este X n chc tc dng NaOH thu 9,52g Natri fomiat v 8,4gru . Vy X l: a.metyl fomiat b. etyl fomiat c. propul fomiatd. butyl fomiat Cu 33: Cho 3.52g cht A C4H8O2 tc dngvo 0,6 lt dung dch NaOH 0,1M. Sau phn ng c cn dung dch thu 4,08g cht rn. Vy A l: a.C3H7COOHb. HCOOC3H7 c. C2H5COOCH3d. CH3COOC2H5 Cu 34: A l C3H6O2 v B l C2H4O2 tc dng dung dch NaOH thu 1 mui v 1 ru. Vy A, B l: 4a. A l axit, B l esteb. A l este, B l axit c. a, b u ngd. a, b u sai Cu 35 : Vn tc ca phn ng : A+B= Cs tng ln bao nhiu ln khitng nhit phn ng t 25oC ln 100oC bit rng khi nhit tngln 25o thvn tc phn ng tng ln 3 ln a)9 lnb)12 ln c)27 ln d)81 ln Cu 36 : Ho tan hon ton 1,9 gam hn hp gm Fe , Mg v Al bng dung dch H2SO4 longva thu c 1,344 lit H2 (kc). Khi lngmui khan thu ckhi c cn dung dch sau phn ngl . a)7,66 gam b)7,78 gam c)8,25 gamd)Khng tnhc v thiu d kinCu 37 : Hn hp X gm 2 kim loi A, B (iu c ho tr khng i) . Chia X thnh 2 phn bng nhau: Phn 1: ho tan trong dung dch cha HCl v H2SO4 , kim loi tan ht ,thu c 3,36 H2 (kc)Phn2: ho tan ht trong HNO3 long thu c V lt (kc) khNO. Gi tr ca V l : a)2,24b)3,36c)4,48d)5,6 Cu 38 : Cho lung kh CO i qua ng s cha m gam hn hp Al2O3vFe3O4t nng. Sau phn ng thy cn li 14,14 gam cht rn . Kh ra khi ng s c hp th hon ton vo dung dch Ca(OH)2dthu c 16 gam kt ta .Gi tr ca m l :a)18,82b)19,26c)16,7d)Tt c iu sai Cu 39 : Ho tan hon ton 0,54 gam Al vo trong 200 ml dung dch X chaHCl 0,2Mv H2SO40,1 M thu c dung dch Y . Th tch dung dch NaOH 2Mcn cho vo dung dch Y lng kt ta thu c ln nht l : a)40mlb)60mlc)80mld)Tt c iu saiCu 40 : A l dung dch NaOH c pH = 12; B l dung dch H2SO4 c pH = 2. phn ng vi V1 lt dung dch A cn V2 lt dung dch B. Quan hgia V1 v V2 l: a.V1 = V2 b. V1 = 2V2c. V2 = 2V1d. Tt c u sai GV. Nguyn Tn Trung TT luyn thi i hc CLC Vnh Vin 5e on so 7 Cu 1: V tr kim loi kim a.Thuc nhm IA trong bng HTTH b. Thuc nhm IIA trong bng HTTH c. Thuc nhm IB trong bng HTTH d. Thuc nhm IIIA trong bng HTTH Cu 2: Mt s c im v cu to ca nguyn t kim loi l: a.Bn knh tng i ln so vi. b. S electron ho tr t (t 1 n 3) so vi phi kim c. in tch ht nhn ln d. a v b ng. Cu 3: Cu hnh electron lp ngoi cng ca Na v Na+ tng ng l: a.3s1 v 3s2b. 3s1 v 2p6 c. 2p6 v 3s1d. 3p1 v 2p6 Cu 4: em ien phan dd NaCl, KCl ,co 1 it phenolphthalein , thay: a. dd khong mau hoa thanh ob. dd khong mau hoa thanh Xanh c. dd luon khong mau d. dd luon co mau hong Cu 5: Nhung thanh nhom co khoi lng m gamvao dd hh: Fe(NO3)2,Cu(NO3)2. Sau 1thi gian lay thanh nhom ra, thay cokhoi lngbang n ( n>m). Dungdch sau cha cation: a. Al3+b. Al3+ va Cu2+ c. Al3+,Fe2+va Cu2+ d. a, c eu ung Cu 6:Trung hoa 4,2 gam chat beocan 3 ml ddKOH 0,1 M . Ch so axit cua chat beo o bang: a. 3.b. 4. c.5d. 6. Cu 7: Khi cho kim loai kiem vao dung dch CuSO4 th: a.Kim loai kiem phan ng vi Cu2+ b.Kim loai kiem phan ng vi CuSO4 ay kim loai Cu ra khoi dung dch c.Phan ng ongthi vi ca CuSO4 va nc 1d. Kim loai kiem phan ng vi nc trc cho kiem, sau o kiem setac dung vi CuSO4 Cu 8: Tnh cht ho hc chung ca kim loi l: a.D b khb. D b oxi ho c. D tham gia phn ng d. Nng lng ion ho cao Cu 9: Nhom c ieu che bang cach: a. ien phan dd AlCl3

b. ien phan nong chay Al2O3 c. ien phan nong chay AlCl3d. Dung cacbon kh Al2O3 nhiet o cao Cu 10: Da vo dy in ho, ta nhn thy: a.Kali d b oxi ho nht. b. ion K+ d b kh nht c. Au3+ c tnh oxi ho mnh nht. d. a v c ng. Cu 11: Co 5 dung dch ng trong cac lo mat nhan : Ba(NO3)2, NH4NO3, NH4-HSO4, NaOH, K2CO3. Ch dungquy tm ta nhan biet c: a. 2 dung dch b. 3dung dch c.4dung dchd. 5 dung dch Cu 12: Trong phan t anilin, nhom NH2 anh hng en vong benzen the nao : a. Lam tang mat o electron cua nhan benzen b. Lam giam mat o electron cua nhan benzen c. Khong anh hng d. Tat ca eu sai Cu 13: Cho (A) cha C, H, O tac dung vi vi 240 ml dd MOH 1M th pxay ra va u. Co can dung dch sau phan ng thu c phan hi ch co nc va phan ran chamuoi. ot het muoi , thu cH20 , CO2 va 16,56 g M2CO3.M co the la: a.Na b. Kc. Li d. Ca A,B,C eu ungCu 14: Trong cac hon hp chat sau. Chat nao co nhiet o soi cao nhat: a. C2H5OH b. CH3CHO c. C6H5OHd. CH3COOH Cu 15:Phn bit 3 dung dch: H2N CH2 CH3COOH, CH3COOH, C2H5 NH2

ch cn dng mt thuc th l: 2a.natri kim loi b. Dung dch HCl c. dung dch NaOHd. Qu tm Cu 16: Cht khng c kh nng tham gia phn ng trng hp l: a.toluenb. Stiren c. Caprolactamd. a va c Cu 17: Duthcvthuhtllipittrngthilngdo: a Chachyugcaxitbono b Chachyuaxitbokhngno c TrongphntcgcGlyxrin d ChaaxitbotdoCu 18: Almt -aminoaxitchchamtnhmaminovmtnhmcacboxyl.Cho10,68gamAtcdngviddHCldtathuc15,06gammui.VyActhl: a..Caprolactamb .Alanin cGlixin d.AxitglutamicCu 19: T 1kg CaCO3 ieu che c may lt C3H8 (kc), biet qua trnh ieu che tien hanh theo s o sau: CaCO3 CaO;CaO C2H2 = % 90 H = % 75 HC2H2 C4H4 ; C4H4 C4H10;C4H10 C3H8 = % 60 H = % 80 H = % 95 Ha. V = 34,47 ltb. V = 36,6 lt c. V = 48,8 ltd. 56 lit Cu 20; 21; 22: (A) la -amino axit no ( co 1 nhom amino va 2 nhom cacboxyl) 0,01 mol (A) p uvi ddHCl, co can c1,835 g muoi B. 20.M(A) co gia tr: a. 91b. 147.c. 145 d. 87 21.The tch dd NaOH 1M can p het muoi: a.20 b.30 c.200 d.300 (ml) 22. Vay A co the la: a. Glixin b. Alanin c. Axit Glutamicd. Axit - amino caproic Cu 23,24: ot 1 hydrocacbon (A) thay the tch oxi can ot bang 3/2 the tch CO2. Biet (A) khong co ong phan. 23.(A) co the ieu che trc tiep: a. Andehtyt axetic b. Ru etylic c. Etylenglycol d. a, b, c eu ung 24.T A P.V.CcoSo phan ng t nhat bang: a. 2b. 4c. 6d. 7 Cu 25: Trong cac hp chat sau ay. Chat nao lam phenolphtalein thanh3mau o:a. HCOOHb. CH3CH2OHc. C6H5OHd. CH3NH2 Cu 26: Trung hoa 4,2 gam chat beocan 3 ml ddKOH 0,1 M . Ch so axit cua chat beo o bang: a. 3.b. 4. c.5d. 6. Cu 27: Khi xa phonghoa 2,52gam mot chat beocan 90ml ddKOH 0,1 M. Ch soxa phongcua chat beo o bang: a.200b.188c.20d. 504 Cu 28: 1,2 g cht hu c A (C, H, O) qua ng CuO, un nng thu c m gam H2O 1.76g CO2 v ng CuO gim 1,28g th m gam H2O l: a.0,72gb. 0,36gc. 1,08gd. Tt c u sai Cu 29: T khi i vi H2 ca hn hp gm hi 2 ru n c mol bng nhau l 22,5. Vy 2 ru l: a.C2H5OH, C3H7OHb. CH3OH, C3H7OH c. CH3, C4H9OHd. CH3OH, C3H5OH Cu 30: Cho 2,48g hn hp C3H7OH v ru a X chc tc dng Na d thu 0,672 lt H2. Vy X l: a.C2H5OHb. C3H5OH c. C4H9OHd. CH3OH Cu 31: Ru n chc A c %khi lng oxi l 32. Cht A c iu ch t anehit X. Vy X l: a.CH3CHOb. HCHO c. CH2 = CH CHOd. Cht khc Cu 32: Vi C2H6O2 th cht ny l: a.ru no 2 chcb. Anehit no 2 chc c. este no n chcd. Tt c u ng Cu 33: Este X n chc tc dng NaOH thu 9,52g Natri fomiat v 8,4gru . Vy X l: a.metyl fomiat b. etyl fomiat c. propul fomiatd. butyl fomiat Cu 34: Cho 3.52g cht A C4H8O2 tc dngvo 0,6 lt dung dch NaOH0,1M. Sau phn ng c cn dung dch thu 4,08g cht rn. Vy A l: a.C3H7COOHb. HCOOC3H7 c. C2H5COOCH3d. CH3COOC2H5 Cu 35: A l C3H6O2 v B l C2H4O2 tc dng dung dch NaOH thu 1 mui v 1 ru. Vy A, B l: a. A l axit, B l esteb. A l este, B l axit c. a, b u ngd. a, b u sai 4Cu 36: Ho tan hon ton 0,54 gam Al vo trong 200 ml dung dch X cha HCl 0,2Mv H2SO40,1 M thu c dung dch Y . Th tch dung dch NaOH 2Mcn cho vo dung dch Y lng kt ta thu c ln nht l : a)40mlb)60mlc)80mld)Tt c iu saiCu 37 : A l dung dch NaOH c pH = 12; B l dung dch H2SO4 c pH = 2. phn ng vi V1 lt dung dch A cn V2 lt dung dch B. Quan h gia V1 v V2 l: a.V1 = V2 b. V1 = 2V2c. V2 = 2V1d. Tt c u sai Cu 38: in phn 200 ml dung dch mui M(NO3)2 0,1M trong bnh inphn vi in cc tr n khi c kh thot ra trn catt th ngng in phn thy thu c 1,28g kim loi trn catt. Khi lng nguyn tca kim loi M l: a.56b. 64c. 65d. Tt c u sai Cu 39: phn bit 2 kh SO2 v CO2 c th dng: a.Dung dch Ca(OH)2b. Dung dch Ba(OH)2 c. Dung dch Br2d. a, b ng Cu 40: Trong cc phn ng ho hc m Fe2+ tham gia, vai tr ca Fe2+ lunlun l a.Cht kh b. Cht oxi ho c. C th l cht kh hoc cht oxi ho tu phn ng d. Tt c u sai GV. Nguyen Tan Trung TT luyen thi ai hoc CLC Vnh Vien 5HNG DAN GIAI E SO 1 Cau 1: ieu kien can e co ru khong no n chc; Andehit no; xeton trong CnH2nO a thoa. Nen chon ap an D Cau 2: Dung phng phap loai tr de dang suy c ap an ung la D Cau 3: Vi %C = 37,5 ta de dang thay X: CH4O. Nen chon ap an ung la D Cau 4: T 28, 80, 3 29, 30, 3hhHn mol M = = = ap an ung la CCau 5: ot Y co mol CO2 = mol H2O A sai va Y co dang CnH2nO co24. 3O Yn n n = = ap so D Cau 6: Vi ap an A,D2, 9501 21, 6.4 108AM= = ap an ung la B Cau 8:[ ]2 425.1, 839.96100.980, 9( )0, 5sauHSO M = =ap an BCau 9: Ta co nHCl = 0,025 mol = 0.0258 3nAgNO HCl het mddsau = mHCl + - mAgCl 3mAgNO dd = 52,325 g 63.0, 025%32, 3253CddNO = . 100% = 3%ap an ung la CCau 10: Chon ap an A V 12, 65.2 25, 2 Mhh = = hon hp co CH4

Cau 11: Ta co cong thc : V mmuoi = mklp+ 96 . 2Hn mmuoi = 3 + 96 . 1, 00822, 4 = 7,32 g ap an : A Cau 12: T t khoi hi ta nham c t le mol co trong X nh quy tac: C3H8447 C4H10587 511 73 8174 10nCHnCH = = ap an : B Cau 13: So oxi hoa cao nhat = so th t nhomB sai vH33X+ O3 ap an : B Cau 14:ap an : D CH4 ; 0,05 mol Cau 15: Dedang nham c hh C2H4 ; 0,025 mol =1.0,05 + 2. 0,025 = 0,1 mol 2nCO=0,1 . 44 = 4,4 g 2mCO ap an : B Cau 16: Ta co 222.COHOnCH n=SoSo Theoe co22mCOmHO = 1,8333 44.218.2nCOnHO = 1,8333 CTTQ A : C3H8Oz De thay Z 3 ap an : DCau 17: PCnH2n+2 + 3 12n +O2 n. CO2 + (n+1) H2OTa co : 2nXnO = 1 23 13 1 132nn= =++2 n = 4X: C4H10 ap an : B Cau 18: Vi % H = 14,29 CTN : (CH2)nCnH2n2Can nh:CnH2n khong co ong phan khi n = 2 ap an : A Cau 19: Tng t cau 16 CTN : (CH)n ap an : DCau 20: Dethay ap an hp l : B Cau 21: Can nh t0 CaO ClO3- + Cl- + H2O

2Cl OH+ ClO- + Cl- + H2O ap an : ACau22: ap an : D Cau 23:Ta co2nCO=31003nCaCO == 0,03 2, 04 0, 03.44182nHO== 0,04 322. 82nCOCH nHO = =SoSo ap an : C Cau 24: P: 3Ag + 4HNO33AgNO3 + NO + 2H2O Ta co: 34 41, 62. . 0,3 3 108HNO Agn n = = = 02 30, 02.63.1000 510.1, 2.21ddHNOV m = = l ap an: B Cau 25: Vi %M = 72,41 Oxit: Fe3O4M: Fe Ta co: Fe + 6HNO3 Fe(MO3)3 +3NO2 + 3H2O nNO = 3.nFe= 0,9 ap an: D Cau 26: atA1: CxHy(COOH)za mol A2CxHy(COOH)zb mol T d kien esuy c: ax + bx = 0 x = x = 0 ap an: CCau 27: Phan ng gi y Mg + 2AgNO3 2 Ag + Mg(NO3)2Fe + 2AgNO3 2Ag + Fe(NO3)23 Sau p con hai kim loai o la: Ag, Fe Mg: het T %Mg nMgp mAg sinh raVi 5,792g hh kim loai suy c ap an: B (Ket qua khac c thay bang mot gia tr > 58,34%) Cau 28: Bo sung them t le mol cua oxit va kim loai la 1:1 Ta de dang suy c ap an: A Cau 29: De thay ap an hp li: B Cau 30: Lap he 2 phng trnh ap an: CCau 31: T e 13CH =sosoap an: A Cau 32: P2Al + 3Ag2SO4 6Ag + Al2(SO4)3(1) Fe + Ag2SO42Ag + FeSO4(2)2 kim loai thu c la Ag, Fe Al het nAl p = 0,1 mol(1) 30,1 0,1522 4(1)n mAgSO= = ol 0,175 0,15 0, 0252 4(2)nAgSO= =x= 0,175.2.108+0,025.56=39,2g ap so: ACau 33: Ta nham c 0, 5959min0, 01Mhha= = ap an: D Cau 34: Chon dapanC Cau 35: ap an: C Cau 36:Ta co the nham nhanh nh s o ng cheo hoac giai nh sau: 29, 40,194KOn m = = ol

2 22 KO HO KOH + (1) Theo (1) va e ta co :

200 5, 6(0,1 2 56)100% 100 10, 7200 9, 4ddC += += ap an: C Ti liu do Trung tm luyn thi i hc CLC Vnh Vin cung cp 4AP AN E SO 2 Cau 1:Ap dung cong thc: m = m +96.nH kimloai pmuoi21, 008m = a = 7, 32- 96. = 3gkimloai p22, 4 ap an: A Cau 2:Vi x + y = 6 214xx yy= = ap an: A Cau 3:Nghiem hp l la A Do +2 +2 -2 +1+3 -2CuFeS hoac CuFeS2 2Cau 4:De thay n = 2.n = 0, 6 mol nH HCl p HCl b2 hon hp kim loai het 8, 829, 330, 3Mhh = = Hon hp kim loai:Mg, Ca ap an: A Cau 5:Do 2 2n nCO HO=Va e co mot nguyen t O Y: C H On2nPhan ng:3n - 1 C H O + n2n 2 2 22O nCO nH + OO(1) Theo (1) va e ta co: 2 2n nO H= 3 142n =ap an: D3 n = Cau 6:1De thay ap an hp l: B Cau 7:M thoa cong thc (1) la kim loai a hoa trKim loai hp l: Fe ap an: C Cau 8:ap an hp l la A Cau 9:De thay (3), (4) khong la phan ng oxi hoa kh ap an: D Cau 10:ap an hp l: D Cau 11:De thay ap an hp l: C Cau 12: Qua trnh oxi hoa la qua trnh cho electron ap an: D Cau 13:at CTTQ este: a mol 2CH Oz nnTheo e co: x y = a . .2mn a a a = m = 2n 2 CTTQ este no thoa e la C Cau 14: 28.2 30.314, 62(2 3 )2x xdhhGx xH+= =+ ap an: B Cau 15: T %O = 36,36 16.1004436, 36MAndehyt = = ap an: C Cau 16: T nh luat bao toan ien tch 0, 2 n mClol = Ta co:m = M.0,1+ 0, 2.27+ 0, 3.96 +35, 5.0, 2 = 47, 7ran M = 64 M: Cu ap an: C 2Cau 17: Dung phng phap loai tr kiem tra so nguyen t sat 2 ve ap an: A Cau 18: De thay ap an: B Cau 19: T %O = 37,21 Cong thc nguyen t A: (C2H3O)n Theo e suy nghiem hp l n = 2 ap an: C Cau 20: Tng t cau 1 e so 1 Cau 21: De thay ap an hp l: A Cau 22: CTTQ cua este sinh bi axit n no va ong ang phenol: 2 8CH Oz nn ap an: B Cau 23: (A): 2CHOx y T mC : mO = 9: 8 (A): 3 2CHOy De thay y ch co the bang: 6; 4; 2 ap an; B Cau 24:De thay phan ng trong th nghiem nay co H2 ap an: A Cau 25: T cac phng an tra li Este A co 4 nguyen t O va 6 nguyen t C So H = 16.4.10012.6 16.4 844, 44 = ap an: B Cau 26: Ta co: n = nHNO N trong HNO3 p 3 p= 0,1.2 + 0,2.1+ 3.0,3 + 0,01.2 + 0,03 = 1,35 ap an: A Cau 27:3Vi %O = 53,33 A: (CH2O)n T t len : (1)n =1H A p2:1:1Va(2) COn : n =1A p2(1), (2) A co 1 nhom- COOH1 nhom- OH ap an: B Cau 28: Theo e ta co ( )1, 8600, 7826MA = = (A): CH3COOH ap an: C Cau 29: De dang thay: 0, 032nCO= 2, 04 0, 03.440, 04182nHO= =nCOSo C2=So H 2.nH O2 ap an: C Cau 30: V: 12 2n nCO HO1: 6 = 2 2n nCO HO> X, Y, Z co lien kettrong phan t ap an: D Cau 31:Theo day the ien hoa ap an: A hoac C Cau 32: Don = nCO NaOH p2 So C trong A1, A2 eu bang 0 ap an: B Cau 33: T %C = 60 X:3 7C HOH4 1 18. .22, 4 3, 32 602nH= = 6 ap an: DCau 34: Phng an D sa lai eu sai ap an: D Cau 35: Trong dung dch A co [H+]=[ ][ ].aHFkNaF =6,8.10-4 pH = 3,17 Cau 36: 1. Tng t cau 35 pH = 4 ap an: A 2. [OH-] =3.34NHkNHNHCl = 0,1 19 1. .10 100, 2 50 = pH = 4 Cau 38:

11, 5 1 7574 6, 937546 2 100a = = ap an : C Cau 39:X la axit hoac este. Vi MX = 6O X: CH3COOH HCOOCH3 ap an : B Cau 40:-RX la dan xuat halogen -ac biet RX con c xem la este vo c khi c ieu che t ROH va HX ap an: C Tai lieu cung cap bi TT luyen thi H chat lng cao Vnh Vien 5HNG DN GII 3 Cu 1:Ta c: nCOso C 0, 018 32= =so H 2.n 2.0, 015 5H O2=ap an: D Cau 2: Theo e oxit cn tm l oxit lng tnh nOxit p =12-OH pnMoxit = 3, 815210, 052= Oxit: Cr2O3 p n: B Cau 3: T KLPTTB v th tch hn hp ta d dng thay 0, 025 ; 0, 054 4 4n nCH CH= =1.0, 05 2.0, 025 0,12n mCO = + = ol p n: B Cau 4: B,D sai v khong co phan lp 3d A sai v khng c lp 3d cha bo ho p n: C Cau 5: D thy phn ng xy ra va dung dch sau phn ng c mi trng trung tnh pH = 7 p n: B Cau 6: Theo th nghim 1. Phn ng xy ra va Th nghim 2 HCl cn d p n: C Cau 7: [OH]-sau= 2.0, 05 0.05.1000 0, 75100 100+=+ p n: B Cau 8: Vi (C3H3)n c iu kin tn ti 0 < 3n 2.n+2 n2 p n: B Cau 9: De thay ch co phng an A la hp l. Cau 10: Theo e: 0 2S S S + +4Phan ng e cho la phan ng t oxi hoa kh ap an: A Cau 11: Theo e AO,B2O3 la oxit lng tnh; MOH la hydroxit kim loai kiem San pham ung: M2AO2, MBO2 va co the con MOH ap an: C Cau 12: Vi %O = 53,33 Cong thc nguyen A: (CH2O)n C, D sai T t le mol cua hai th nghiem tren A co 1 nhom (-COOH) va 1 nhom (-OH) ap an: B Cau 13: De thay 0, 780, 03262n n moA CO= = = l ( )1, 8600, 03MA = = (A): CH3COOH ap an: CCau 14: Cac chat ong phan phai co cung CTPT ap an: C Cau 15: C3H8O co CTPT: CH3- CH2 CH2 OH CH3 CH OH CH3 Co nhieu chat 3 ete ap an: C Cau 16: Phan ng chuan b: SO2 + NaOH NaSHO3(1) x xx SO2 + 2NaOHNa2SO3 + H2O(2) y2yy Theo (1) (2) ta co he phng trnh n = x + y = 0,15SO2m =104x +126y =16, 7Muoi x= 0,1 ; y=0,05 ap an: B Cau 17: Ta co:0, 2 n mAg = ol24Neu:n : n =1:Xp AgMX = 29 n : n =1:Xp Ag 0, 05 = nXp MX = 2, 9580, 05 = ap an: B Cau 18: 25.1, 839.960, 92 498.100.0, 5HSO = = ap an: B Cau 19: Ta co: nHCl = 0,025 0, 0253nAgNO >Phan ng:HCl+AgNO3AgCl + HNO3 (1) 0,025 0,025 0,025 T (1) de dang C%ddHNO3 = 3% ap an: C Cau 20: Theo e X co the la S hoac Si ap an: D Cau 21: De thay 1n = n-OH p oxit p2 1, 5215210, 022Moxit = = ap an: B Cau 22: (1),(4) la phan ng oxi hoa kh ap an: B Cau 23: e c dung dch trong suot AO, B2O3 phai tan het B2O3 : Oxit lng tnh ap an: D Cau 24: 1.Theo e X: (NH4)2CO3 2 kh: NH3, CO2 ap an: D 2.De thay HCOONH4; HCHO phan ng vi dung dch AgNO3/NH3(NH4)2CO3 ap an: D (khi n=1) Cau 25: T cac phng an tra li B: R Br T %Br = 58,4 R = 57 B: C4H9 ap an: C Cau 27: Co cach giai tng t cau 1 Cau 28: P: H SO 2 4o170 CC H OH C H + H O2 2 5 4 292Phan ng phu: 6 2 65 2 2 4 2 2CHOH HSO CO SO HO + + + hon hp hi: CO2, SO2, hi H2O, C2H4 ap an: B Cau 29: Ta co s o hp l: 3 2 5 3HC CH CH CHO CH OH CH COOH Hoac 2 2 2 5 3HC CH CH CH CH OH CH COOH ap an: DCau 30: Ta de dang chng minh cn = n .SoCOot2C So C = nCOM0, 003este 2= =n 0, 09 30ot Do so C nguyen, ap an: BCau 31: Dung quy tm ta nhan biet c tat ca cac chat ap an: D Cau 32: Ta co p: 32 32Fe Cl FeCl + (1) Theo (1) thay: 1 mol Fe phan ngmran tang: 3. 35,3g 106, 5.563.35, 5m = ap an: D Cau 33: Dung phng phap loai tr e kiem tra nhanh cac he so can bang ap an: B Cau 34: Can nh: Oxit KL + HNO3 NO KL: la kim loai a hoa tr va hoa tr kim loai trong oxit phai thap A, C: sai Neu oxit la FeO th: FeO Fe(NO3)3 (1) 0,125 mol 0,125 mol (1) Mran = 0,125 x 242 = 30,25 g ap an: D Cau 35: Ta dung Cu(OH)2 se nhan biet c tat ca ap an: C Cau 36: Can nh Glucoz, Fructoz: khong thuy phan ap an: B Cau 37: De thay A, B la Glucoz, FructozD: Saccaroz ap an: C Cau 38: Theo e ZX = 16 X: S ap an: C Cau 39:Nh phng phap tang giam khoi lng2,18-1, 52n = = 0, 03hh ru p22mol1, 52M = = 50, 67hh ru0, 03 ap an: C Cau 40: Kh thu c la SO2 phan ng cua SO2 vi dung dch Br2 2 2 2 22 2 SO Br HO HBr HSO + + +4V Br2 d ap an: C Tai lieu c cung cap bi TT luyen thi H CLC Vnh Vien HNG DAN GIAI E 4 Cau 1:Ta co CTTQ axit 2 2 2( )n n a m mCH COOH+ Day ong ang cua axit CH2=CH-COOHCo a= 1 va m= 1 CTTQ : 2 1CH COOHnnap an : C Cau 2:De thay X (C,H,O) co % O= 34,78 la C2H5OH Vi C2H4Oco CTCT : CH3CHO se ieu che c C2H5OH Khi n = 6 Hp chat (CH2O)6 co the la Gluz nen ieu che c ru etylic ap an : D Cau 3:X : C,H,O co % O = 37,21 CT nguyen X : (C2H3O)n ; V so H = so chan Nghiem hp l: C4H6O2 ap an : A Cau 4: Dung phng phap loai tr ta de dang suy ap an: D Cau 5:Ta co nCOSo C2=So H 2.nH O2= 35 ap an : C Cau 6:A :( )5 3 2 2 4C H O C H COOHnn n n n nCan nh : Trong goc hydrocacbon co So H= 2So Cgoc no hoa tr 2 Cla axit noH (COOH)n 2n 4nTng t vi B, C ap an: D Cau 7: Vi %O = 53,33 X: (CHO)n2 ap an: C Cau 8: Tng t cau 1 ap an: C Cau 9: Ch co saccaroz thuy phan sinh Glucoz va Fructoz ap an: A Cau 10: Ta co cong thc + - 23 41m = m + 62 n 96 nKLp e nhan cua NO e nhan cua SOmuoi2- m=3 gam ap an: CCau 11: X: ( C, H, O) co M=60 phan ng c vi NaOH se co CTPT: C2H4O2

ap an: B Cau 12: Ta co: m6, 96ruM = = =Ru10, 4 - 8, 48nru1658 ap an: BCau 13: Ta co:n = n =H hhklp20, 212,160, 50, 2Mhhkl = =e bai cho KL co hoa tr khong oi ap an: B Cau 14: De thay ap an C la hp l Cau 15: De thay ap an: B Cau 16: Nh LBTT ap an: C Cau 17: Co:m = m +62.nKLp e nhanmuoi0, 896m = 3, 68 - 62 =1, 2gKLp22, 4 ap an: C Cau 18: ap an: D Cau 19: Ta co: m = m + 71 nKLp Hmuoi2 5, 856- 2, 4V = 22, 4H712 ap an: D Cau 20: Ta co:m = m +96.nKLp Hmuoi21, 008m = 2,3+96ran22, 4 ap an: D Cau 21: Ta co s o hp thc va phan ng (1) 22CuS SO440,1 0,1(mol) 222 FeS SO (2) 0,05 0,1(mol) (3) 2 24 4Ba SO BaSO+ + (1), (2), (3) ap an: B Cau 22: P: 3 3 2 3 3( ) ( ) AgNO FeNO FeNO Ag + + (1) 0,1 mol 0,2 mol 0,1 mol 100 + 200 -108.0,1V = = 200dd1, 446Sau (ml) ap an: A Cau 23: De thay ap an la: D Cau 24: BaO + H2O = Ba2+ + 2OH- -11 200.10n = . =0,001 mol2 1000BaO ap an: A Cau 25: Ta co s o: 3( ) FeCl Fe OH3 (1) (1)10, 7( )3mFe OH= ap an: A Cau 26: ap an hp l A Cau 27: X (C, H, O) co %O = 34,78 X: C2H6O ap an: D Cau 28: Gi y 13 22otNaNO NaNO O +2 ap an: B Cau 30: San pham cua phan ng e cho phai co SO42- ap an: D Cau 31: Theo inh luat bao toan nguyen to ap an: B Cau 32: ap an ung la: D V tron chat kh manh vi chat oxi hoa manh th phan ng mi co the xay ra c. Cau 33: P Gi y 2 2 4 4 2FeS + H SO FeSO + H S + Sloang ap an: B Cau 34: De thay phan ng e cho la phan ng cua muoi vi muoi ap an: D Cau 35: De thay ap an la D. Cau 36: ap an D la ung nhat Cau 37: De thay ap an hp l la CV: A: co H2SO4 ac B, D co HNO3 Cau 38: De thay dap an hp l la B Cau 39: V CO2, NO, Cu khong phan ng vi HCl ap an: D Cau 40: De thay ap an hp l la B Giang vien Nguyen Tan Trung (TT luyen thi ai hoc CLC Vnh Vien) Hng dan giai e so 5 Cu 1: Dng cng thc: = CO2 H2 O S:A Cu 2: Cnnh: 31 2 24;HNOS S SO+ Ta c s nhm:FeS2 Fe3++2SO42-(1) 0,05mol 0,05mol0,1mol Cu2S Cu2++SO42-(2) 0,1mol0,1mol0,1mol BaSO4: 0,2mol (1), (2), => Kt ta gm: Fe(OH)3: 0,05mol Cu(OH)2: 0,1mol mkt ta = 233.0,2 + 107.0,05 + 98. 0,1= 61,75 S: D Cu 3: Mi hp cht hu c c 1 lin kt t u c nCO2 = nH2O S: B Cu 4: 2 metyl butadien 1,3 CH2 = C HC CH2to c 3 sn phm cng vi Br2 theo t l 1:1 CH3 S: C Cu 5: Ta nhm c nCO2 = nBaCO3 = = 0,03mol nH2O = = 0,03mol CO2 = H2O S:A Cu6: Vi Z 20 nguyn t c 2 electron c thn c cu hnh e phn lp ngoi cng l: 2p2 ; 2p4; 3p2; ;3p4 Nguyn t: C, Si, O, S S: D Cu7:Cn nh: Kim loi phn ng vi HCl c mMui = mKL p + 71.n H2 mKL p = 5,865 71.= 3,016 S: B Cu 8:CTTQ: (*)CnH2n + 2 - 2a m(CHO)m a = 0 Anehitno2chcc: m = 2 (*) => CTTQ: CnH2n(CHO)2 => S:C Cu 9: Ta nn nh: CH3COOH X(C, H, O) %O=53,33 => CTN: (CH2O)n Theo =>X: C2H4O2 vi C2H4O2 c 3 cng thc phn t:HCOO CH3 CH2 CHO OH Ch c C2H6O l tho iu kin bi (C2H5OH CH3COOH) ap an : C Cu 10: DthyC3H6O2c1linktnnchcp analthomn Cu 11: nhit thng Cl2+ 2KOH KClO + KCl + H2O nhit cao 3Cl2 + 6KOH KClO3 +5KCl + 3H2O Theo => S: B

Cu12: P: CO2+NaOH=NaHCO3 (1)x x xCO2+2NaOH=Na2CO3+H2O (2)y 2y yCO2=x+y=0,1 x=0,1C =>

NaOH=x+2y=0,15y=0,05mMui=84x+106y=13,7gS:DCu13: ViCxHyOzNtClu

0S:ACu19:n= n=0,2molAl2(SO4)3SO42- S:ACu20:Alanin:khngimuqutmS:DCu21:AlphnngviHCl;ddNaOHH2

FeSphnngviHClH2S(NH4)2CO3NH3;CO2

S:CCu22: nH2= =0,3S:CCu23:Dthyht,CH3COOHcnnguynddsaugm:CH3COOH:0,1molHBr:0,3molVddNaOH=2000mlS:ACu24:nHClb= =0,2mol TacnHClp=2.nH2=0,2molHCl:htnMgp=nH2=0,1molmCu80,1.24=5,6S:ACu25:nH2=nB=>B:nchcA:AnhytnA:C3H5CHOcCTCT:CH2=CCHOCH3

Siuch:AnehytAxitEsteThutinhS:BCu26:nCO2=nH2OAnehytc1linktAnhytln,noS:ACu27:TheoXpingsauFeX:AgCu28:ChcActlsC:sH:sO=6:8:7S:ACu29:ACu30: ChonAdo2kimloi:Cu,ZnCu31:DodB/A=0,7S:CCu34:ACu35:BCu36:CxHyOzNtcx:y:z:t= : : : X:y:z:t=6:13:2:1A:C6H13O2NS:ACu37:Benzen,propanolkhngtcdngviNaS:DCu38:Chon DvH2SO4khngphnngcviSiO2

Cu39:ChcsaccarozothuphnchoglucozovfructozoS:ACu40:C3H6O ch c 1 ng phn chc ruS C trung bnh = = 1,75 CO2 hhX Hn hp: CH4O v C3H8O S: AGV.NguynTnTrungTTluynthiihcCLCVnhVin

Hng dan giai e so 6 Cau 1:Ta co cong thc nham nhanh:2 22CO CO( ) H OV n2x 3y 11V n 3x 4y 15+= = =+hi(*) Vi x,y (mol) lan lt la so mol cua etan va propan. T (*) de dang suy c: x:y=1:3 ap an: c Cau 2:Kim loai co tnh chat chung la tnh kh ap an: dCau 3:Zn phan ng c vi cac ion kim loai loai ng sauZn ap an: cCau 4: De thay d la ap an hp l nhat Cau 5:Fe + ZnOKhong phan ng Cac phan ng con lai xay ra c ap an: b Cau 6: Cu + CuSO4Khong phan ng -Dung nhom th se b lan Al2(SO4)3 ap an: C (Dung Fe ay Cu roi loc) Cau 7: Theo e co: Zn + Co2+ Co + Zn2+ 2Zn + / Zn < Co2+/ Co Con Pb + Co2+ Khong phan ng Co2+/ Co < Pb2+/ PbVay th t hp l: a Cau 8: De thay ap an ung la: a Cau 9:3Ag + 4HNO3 3AgNO3 + NO + 2H2O(1) (1)=> n HNO3 = nAg = x VddHNO3 cn = = = 5(ml) ap an: b Cau 10: V=> S H = 4 s C => Ru: CH3OH 2H O COn 2n =2 ap an: d Cau 11: Ta co ptp: p dd2NaCl + CuSO Cu+ Cl + Na SO (1)(Ctr,mn) 4 2 2 4-Sau (1) con NaCl: neu ien phan tiep se thu c dd co NaOH -Sau (1) con CuSO4: Neu ien phan tiep se thu c H2SO4 -Al2O3 tan trong NaOH va H2SO4 ap an: d Cau 12: -oi vi phan ng nhiet luyen: MgO, Al2O3: khong phan ng . ap an: b Hieu suat p at 100%, H2 d Cau 13: Ta co p : Cu + 2 AgNO3 Cu(NO3)2 +2Ag (1) ap an: a Cau 14: Do nhom(- NH2) la nhom ay e, nen lam tang mat o e tren nhan benzen. ap an: a Cau 15: T e bai ta co khoi lng AgNO3 p bang: 4 g

3AgNO17m 4100 = = giam 0, 68g Khoi lng vat bang ong tang 0,68 gam m 0, Vattan 68g g ap an: d Cau 16: Ta co p: 4 NO2 + 2 Ba(OH)2 Ba(NO3)2 + Ba(NO2)2 +2 H2O(1) 2a mola mol (1)suy ra c p vua u dd sau: cha Ba(NO3)2 ,Ba(NO2)2 ap an: a ( MT baz lam dd phenolphtalein t khong mauhoa thanh o) Cau 17: :FeS2-11e Fe3+ + 2SO2 (1) x 11x2x(mol) Cu2S -8e 2Cu2++ SO2 (2) y8yy(mol) SO42-+ 2eSO2 (3) 2[0,2-(2x+y)][0,2-(2x+y)] (10, (2), (3) va LBTTta co he phng trnh: 120x + 160y = 4x =0,02 11x + 8y = 2[0,2-(2x+y)]y = 0,01 Cu 18: [H2SO4] = = 0,9 ap an : a ap an : b Cu 19: nHCl = 0,025mol; nAgNO3 > 0,025mol C% ddHNO3 = . 100 = 3% ap an : c ap an : d Cu 20: D thyCu 21: Cu: xmol Theo ta c: Fe: ymol 64x + 56y = 30x = 0,25 =>x + y =y = 0,25 %Cu =.100 = 53,33 ap anCu 22: Ta c t = . = 4825 (giy) Cu 23: a, c khng c hydrcacbon c= : c ap an ap an : b : b Cu 24: De thay ap an c la hp ly.Cu 25: Chon b Cu 26: Chon a Cu 27: Ong CuO giam la mO2 p => LBTKL 1,2 + 1,28 = m H2O + 1,76 => mH2O = 0,72g. Chon a 45 902A BA BM MM M M+= = + = Cu 28 CH3OH va C3H5OH. Chon d Cu 29: CH3OH < 3 741, 33 M C H OH = < . CHon b Cu 30: Ru la CH3OH andehitHCHO. Chon b Cu 31: Chon c Cu 32:HCOOH + NaOH HCOONa + ROH 0,140,14 (mol ) => ROH = 8, 4600,14 =C3H7OH.Chon c Cu 33: mol A = 3, 520, 0488mol =mol NaOH d = 0,02 => 0,04 (RCOONa) + 0,02 x 40 = 4,08 RCOONa = 82CH3COONa => A la CH3COOC2H5. Chon d Cu 34:Chon b A: CH3COOCH3 va B CH3COOH Cu 35:T 25 en 100oC tang 75% = 3x 25 Vay van toc tang 33 =27 lan chon ap an c Cu 36:H2SO4 SO42- + H2 0,060,06 M ran = 1,9+ m SO42- = 7,66g. Chon ap anCu 37:Kim loaiX+nH+ 2nH2

x 42x= 0,15 =>n x=0,3 x 1eN+5+ 3e NO x n xn x 3nx=0,1 => V (NO) = 2,24 (l) chon a Cu 38:CO + O CO2 => mol CO2 = mol CaCO3 = 0,16 m trc = m sau + 16. 0,16 = 16,7g chon c Cu 39:mol Al = 0, 540, 0227 =mol H+ = 0,08 ta co Al +3H+ Al3+ + 32H2 0,020,060,02 Dd Y (H+ d0,02; Al3+ 0,02) H+ +OH- H2O 0,020,02 Al3+ + 3OH- Al(OH)3 mol OH- = 0,08mol => V=0, 082 = 0,04 (l) chon a Cu 40:pH = 12 => pOH = 2 => [OH]- =10-2

mol OH- = 10-2 v1 pH = 2 => [H+] =10-2 => mol H+ = v2. 10-2 => v1 = v2 chon a GV. Nguyn Tn TrungTT luyn thi i hc CLC Vnh Vin Hng dan giai e so 7 Cau 1: Kim loai kiem: Li, Na, K Rb, Cs thuoc phan nhom IA. ap an : a Cau 2: ap an hp l: d Cau 3:Cau hnh e cua Na(Z =11): 1s2 2s2 2p6 3s1 Na 1e Na+ Cau hnh e cua Na+: 1s2 2s2 2p6 ap an: cCau 4: Phenolphtalein: khong mau va ch oi mau trong moi6 trng baz De thay dd sau ien phan co MT baz ap an: a Cau 5:Khi nhung thanh nhom vao dd muoi sat va muoi ong thi khoi lng thanh nhom luon tang, do o n > m la hien nhien. Theo qui luat tao san pham ap an: dCau 6: Cong thc tnh ch so axit: Ch so axit 3KOH ( trung )n 5m =p hoaChat beo6 10 ap an: b Cau 7: De thay ap an hp l:d Cau 8: Tnh chat chung cua kim loai: Tnh kh (de b oxi hoa) ap an: b Cau 9: phng an hp l: b Cau 10: K de b oxi hoa nhat, Au3+ de b kh nhat ap an: d Cau 11:De dang nhan biet ddBa(NO3)2 ( khong oi mau qu tm) Dung dd Ba(NO3)2 nhan biet c 2 chat trong nhom lam qu tm hoa xanh. Dung hh: Ba(NO3)2 va ddNaOH nhan biet c 2 dd con lai. ap an: d Cau 12: Nhom (_NH2) la nhom ay e, nen lam tang mat o e tren nhan benzen ap an: a Cau 13:Theo e ta co s o hp thc: 2 MOHM2CO3 M:K 0,24 mol 0,12 mol ap an: b Cau 14: De thay axit co nhiet o soi cao nhat ap an: d Cau 15: H2N CH2 CH3COOH: co MT trung tnh ;CH3COOH: co tnh axit;C2H5 NH2 : baz ap an: d Cau 16:ieu kiene co ptrung hp: Hp chat hu c phai co C co no oi hay noi ba hoac co vong cha lk kem ben Vay b, c trung hp c. ap an: aCau 17: Chatbeo long do cac axit beo khong khong no tao thanh ap an : b Cu 18: Ta de dang tnh c MA nh sau:

A10, 68M 815, 06 10, 6836, 5=9 = ap an : b Cu 19: Cn nh : Vi cac qua trnh:A BH1 ,;H2B D HnX Y Hieu suat chung AY : H= H1.H2Hn Theo e ta co s o hp thc:90% 75% 60% 80% 95%3 2 2 4 4 4 101 1CaCO CaO C H C H C H C H2 2 3 812 (*) Theo(*)trntasuyc :3 8 3C H CaCO1n n 0, 9 0, 75 0, 6 0, 8 0, 952= = 1,539 mol 3 8C HV =1,539 . 22,4 = 34,47Lit S : a Cau 20: P: H2N R (COOH)2 + HCl NH3Cl R (COOH)2 (1) (A)(B) (1)MA = 1,83536, 5 1470, 01 = ap an: b Cau 21: NH3Cl R (COOH)2 + 3NaOH NH2 R (COONa)2 + NaCl + 2H2O(2) (1), (2) nNaOH = 0,03 mol ap an: b Cau 22: Trong cac phng an tra li ch co oxit glutamit la thoa ieu kien e bai ap an : c Cau 23: T phan ng chay ta nham thay: 432 422x ynOn xCO+= = y=2x A: CxH2x V A khong co ong phan A: CH2 = CH2 ap an: d Cau 24: T CH2 = CH2 co the ieu che P.V.C nh 2 phan ng CH2 = CH2 + Cl2otCH2 = CHCl + HCl CH2 = CHClot ,pxt( - CH2 CHCl - )n ap an : a Cau 25: Trong moi trng axit; moi trng trung tnh th phenol phatalein khong oi mau Trong moi trng baz; moi trng trung tnh th phenol phatalein t khong mau hoa thanh o ap an : d Cau 26: Ch so axit c xac nhbang so mg KOHCan trung hoa axit beo t do co trong 1 gam chat beo 356 10 nKOHp trung hoaCh soaxit =mChat beo 3 0,1356 1010004 = Ch soaxit =4,2 ap an : b Cau 27: Ch so xa phong bang so m KOH Can xa phong 1 gam chat beo 356 10 nKOHp xa phong Ch soxa phong =mChat beo 90 0,1356 101000200 = Ch soxa phong =2,52 ap an: a Cau 28: Ong CuO giam la mO2 p => LBTKL 1,2 + 1,28 = m H2O + 1,76 mH2O = 0,72g. ap an: a Cau 2 9: 45 902A BA BM MM M M+= = + =CH3OH va C3H5OH. ap an: d M3 741, 33 C H OH = < Cau 30:CH3OH ROH = 8, 4600,14 =C3H7OH. ap an: dCau 34:mol A = 3, 520, 0488mol = mol NaOH d = 0,02 => 0,04 (RCOONa) + 0,02 x 40 = 4,08 RCOONa = 82CH3COONa => A la CH3COOC2H5

ap an: dCau 35 :A: CH3COOCH3 va B CH3COOH Cau 36 :mol Al = 0, 540, 0227 = mol H+ = 0,08 ta co Al +3H+ Al3+ + 32H2 0,020,06 0,02 Dd Y (H+ d0,02; Al3+ 0,02) H+ + OH- H2O 0,020,02 Al3+ + 3OH- Al(OH)3 mol OH- = 0,08mol => V=0, 082 = 0,04 (l) ap an: a Cau 37:pH = 12 => pOH = 2 => [OH]- =10-2

mol OH- = 10-2 v1 pH = 2 => [H+] =10-2 => mol H+ = v2. 10-2 => v1 = v2 ap an: aCau 38:Kim loai la Cu ap an: b Cau 39:Dd Br2 lam mat , mau SO2 ap an: c Cau 40: Ket qua c GV. Nguyen Tan Trung TT luyen thi ai hoc CLC Vnh Vien