3301 lab 4

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    Introduction

    Because soil is used to bear loads in civil engineering, determining the compressibility of a soil is

    important. It can be determined by applying loading to a soil and measuring how much the soil deformed

    over a period of time with various magnitudes of loads. This test is usually performed on clay, however,

    in this laboratory, coarse sand is used.

    The sample will be placed in a metal ring and the deformation will be calculated versus the load rather

    than the time to demonstrate the drainage effects of the soil.

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    Sample Calculations

    To determine the initial height of the specimen, the distance from the top of the sand to the top of the cell

    ring, Hr is subtracted from the height of the rings. Hd.

    === 63.22.270 dr HHH

    24.57mm

    The vertical displacement is simply the value obtained from the dial gage.

    The height of the specimen after loading and unloading can be calculated by subtracting the vertical

    displacement from the initial height of the specimen.

    426.24144.57.240 === HHH

    mm

    The height of the solids is defined by the following equation:

    =

    ===

    3

    2

    2

    981066.206362.4

    )81.916114(.

    m

    Nm

    s

    mkg

    AG

    mg

    AG

    WH

    wsws

    ss

    19.05 mm

    Where Hs is the height of the solids, Ws is the weight of the solids, A is the area of the oedometer cell, Cs

    is the specific gravity of the soil, yw is the unit weight of water, m is the mass of the soil, and g is the

    acceleration due to gravity.

    The height of the voids can be calculated by subtracting the height of the solids from the height of the soil

    specimen, H.

    == sv HHH

    24.426 19.05 = 5.376 mm

    The void ratio, e, of the soil sample can be computed by dividing the height of the voids by the height of

    the solids.

    ===

    05.19

    376.5

    s

    v

    H

    He

    .2822

    The compression index can be found by plotting the void ratio versus the vertical stress on a logarithmic

    scale and finding the slope of the linear portion of the graph. Using the information from the graph and

    the following equation, the compression index, Cc, can be determined.

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    0507.)120/480log(

    225.256.

    )/log( 12

    12=

    =

    =

    kPakPa

    eeCc

    E1 and e2 are two void ratios and s1 and s2 are the corresponding stresses.

    The coefficient of consolidation, Cv, can be calculated for a consolidation test with a one load increment

    using the square root of time method. Deformation of the sample is plotted against the square root of

    time, and graphic constructions are added to determine t90.

    Using the plot, t90 is approximately 3.24. Using the table in Fundamentals of Geotechnical Engineering,

    T90 is .848.

    =+

    =+

    =4

    74.19838.22

    4

    0 ininHHH

    f

    dr

    10.28 in

    min/65.27

    28.10

    )24.3(848.

    2

    2

    9090

    mmc

    c

    H

    tcT

    v

    v

    dr

    v

    =

    ===

    ==mm

    cmmmcv

    100

    1

    sec60

    min1

    min65.27

    2

    .0046 cm2/sec

    To find T50, the now known cv value can be plugged into the previous equation.

    dayst

    t

    mm

    t

    H

    tcT

    dr

    v

    23.5

    sec452579

    )1028.10(

    0046.197.

    50

    50

    2

    50

    2

    5050

    =

    =

    ===

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    Results

    Table 4.1 Raw Data

    Mass Stressdialreading displacement Height

    Height ofVoids Void Ratio

    [kg] [kPa] [mm] [mm] [mm] [mm] [%]

    1 30 0.144 0.144 24.426 5.376 0.282

    2 60 0.382 0.382 24.188 5.138 0.270

    4 120 0.596 0.596 23.974 4.924 0.258

    2 60 0.562 0.562 24.008 4.958 0.260

    1 30 0.508 0.508 24.062 5.012 0.263

    2 60 0.55 0.55 24.02 4.97 0.261

    4 120 0.652 0.652 23.918 4.868 0.256

    8 240 0.916 0.916 23.654 4.604 0.242

    16 480 1.234 1.234 23.336 4.286 0.225

    Figure 4.1 Void Ratio versus log-stress

    Table 4.2 Coefficient of Compression

    Cc 0.0507

    Figure 4.2 Square Root of Time Fitting Method

    Table 4.3 Coefficient of Consolidation and t50

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    Hdr 10.28 mm

    Cv 0.004 cm2/sec

    t90 3.24 min

    t50 5.23 days

    Analysis

    With the compression index being small, the soil will work well for the materials needed for the dam

    project. This soil will not compress much with respect to the load that it will have to withstand. Even

    after loading and unloading, the settlement was minimal. From figure 4.1 it can be seen that the

    displacement is minimal in relation to the stress that is applied. The consolidation index was found usingthe data from the loading versus time. The graph turned out as expected.

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    References

    University of Minnesota, Civil Engineering, 2008, 1D Compression. Pages 35-38, Soils ! Laboratory

    Manual.

    Das, Braja M. Fundamentals of Geotechnical Engineering. Toronto, Ontario, Canada. Nelson, 2005.

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    Soil Mechanics

    Department of Civil Engineering

    University of Minnesota

    Minneapolis, MN

    55455

    Date

    Geoproject Incorporated

    2300 Arapahoe Avenue

    Minneapolis, MN 55455

    Dear Dr. Bojan Guzina,

    This letter is in response to your request for the compression index of the sand and the coefficient of

    consolidation for the clay that could be used in the proposed earth dam project.

    In order to determine the compression index, an ELE Oedometer was used to calculate the displacement

    in relation to the load. To determine the coefficient of consolidation, the square root of time method wasused.

    The compression index was found to be 0.0507. The coefficient of consolidation was found to be 0.004

    cm2/sec. If a 70kPa surcharge load is applied to the sand, the maximum displacement is 1.234 mm,

    which is less than the allowable 10 mm deformation. The time to reach 50% consolidation in the clay, or

    t50, is 5.23 days. Because the life of the dam is 5 years, it is important that the soil be able to withstand

    the loading without too much displacement. To determine if the rate of settlement of the clay is sufficient

    for this project, the

    From these results, it can be determined that the sand would be sufficient to use in the dam project. The

    compression index is small meaning that the soil will be able to withhold a large amount of stress withoutdeforming too much. The consolidation test was performed to determine the coefficient of consolidation.

    The value determined in this lab is reasonable.

    It was our pleasure to work with you and your associates on this matter and we look forward to the

    further design of this project.

    Sincerely,

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    XXXXXX