25.0 m monopole comparative study

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    FAST PLANETS ENGINEERING DESIGN

    Project Name:

    Designed by: FCFalgui Date:

    ANALYSIS OF MONOPOLE

    SECTION 1Analysis Criteria:

    Determine Wind Pressures

    H = 45 m Heightof Monopole

    V = 39 m/s Basic Design Wind speed for the structure

    GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2

    To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts

    SECTION PROPERTIES

    h = 33.84 m Section base elevation

    L = 11.28 m Length of section

    DB = 0.752 m Bottom Diameter of Section

    DM = 0.655 m Midpoint Diameter of Section

    DT = 0.558 m Top Diameter of Section

    CALCULATIONS

    y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase

    y1 = 2.744830998 m

    y2 = [(2DM + DB)/3*(DM + DB)]*(L/2) Center of A2 of Section from base

    y2 = 2.755195451 m

    A1 = (DT + DM)*(L/2)/2

    A1 = 3.42066 sqm Area of Top Section

    A2 = (DM + DB)*(L/2)/2

    A2 = 3.96774 sqm Area of Bottom Section

    z1 = h + L/2 + y1 Distance of center of A1 to base of section

    z1 = 42.224831 m

    z2 = h + y2 Distance of center of A2 to base of section

    z2 = 36.59519545 m

    Kz1 = (z1/10)^2/7 Exposure Coefficient at A1

    Kz1 = 1.509145143 1 < Kz < 2.58

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    Kz1 = 1.509 Input Value

    Kz2 = (z2/10)^2/7 Exposure Coefficient at A2

    Kz2 = 1.448691431 1 < Kz < 2.58

    Kz2 = 1.448 Input Value

    qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1

    qz1 = 1406.950857

    qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2

    qz2 = 1350.076104

    F1= GH*qz1*A1

    F1 = 8133.463876 N

    F1 = 8.133463876 kN

    F2= GH*qz2*A2

    F2 = 9052.909124 N

    F2 = 9.052909124 kN

    F1*z1 = 343.4341376 kN-m

    F2*z2 = 331.2929788 kN-m

    z equivalent = (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti

    z equivalent = 39.25942468 m

    qzequivalent = (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section

    qzequivalent = 1376.407812 kPa

    Kzequivalent = (zequivalent/10)^2/7 Equivalent Exposure of the Section

    Kzequivalent = 1.478072444

    GH*qzequivalent*AT = 17186.37

    C = (Kzequivalent^0.50)*V*Dp

    C = 28.64507602 > 8.7 Table 1

    CF = 0.72 Input value as per Table 1

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    ONSULTANTS

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    on to its base

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    FAST PLANETS ENGINEERING DESIGN C

    Project Name:

    Designed by: FCFalgui Date:

    ANALYSIS OF MONOPOLESECTION 2

    Analysis Criteria:

    Determine Wind Pressures

    H = 45 m Heightof Monopole

    V = 39 m/s Basic Design Wind speed for the structure

    GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2

    To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts

    SECTION PROPERTIES

    h = 22.79 m Section base elevation

    L = 11.05 m Length of section

    DB = 0.929 m Bottom Diameter of Section

    DM = 0.834 m Midpoint Diameter of Section

    DT = 0.74 m Top Diameter of Section

    CALCULATIONS

    y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase

    y1 = 2.707507 m

    y2 = [(2DM + DB)/3(DM + DB)]*(L/2) Center of A2 of Section from base

    y2 = 2.712881 m

    A1 = (DT + DM)*(L/2)/2

    A1 = 4.348175 sqm Area of Top Section

    A2 = (DM + DB)*(L/2)/2

    A2 = 4.870288 sqm Area of Bottom Section

    z1 = h + L/2 + y1 Distance of center of A1 to base of sectionz1 = 31.02251 m

    z2 = h + y2 Distance of center of A2 to base of section

    z2 = 25.50288 m

    Kz1 = (z1/10)^2/7 Exposure Coefficient at A1

    Kz1 = 1.381901 1 < Kz < 2.58

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    Kz1 = 1.381 Input Value

    Kz2 = (z2/10)^2/7 Exposure Coefficient at A2

    Kz2 = 1.306672 1 < Kz < 2.58

    Kz2 = 1.306 Input Value

    qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1

    qz1 = 1287.607

    qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2

    qz2 = 1217.679

    F1= GH*qz1*A1

    F1 = 9461.872 N

    F1 = 9.461872 kN

    F2= GH*qz2*A2

    F2 = 10022.46 N

    F2 = 10.02246 kN

    F1*z1 = 293.531 kN-m

    F2*z2 = 255.6015 kN-m

    z equivalent (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti

    z equivalent 28.18329 m

    qzequivalent (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section

    qzequivalent 1250.663 kPa

    Kzequivalent (zequivalent/10)^2/7 Equivalent Exposure of the Section

    Kzequivalent 1.34452

    GH*qzequivalent*AT = 19484.33

    C = (Kzequivalent^0.50)*V*Dp

    C = 26.61903 > 8.7 Table 1

    CF = 0.72 Input value as per Table 1

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    ONSULTANTS

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    FAST PLANETS ENGINEERING DESIGN C

    Project Name:

    Designed by: FCFalgui Date:

    ANALYSIS OF MONOPOLESECTION 3

    Analysis Criteria:

    Determine Wind Pressures

    H = 45 m Heightof Monopole

    V = 39 m/s Basic Design Wind speed for the structure

    GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2

    To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts

    SECTION PROPERTIES

    h = 12.04 m Section base elevation

    L = 10.75 m Length of section

    DB = 1.1 m Bottom Diameter of Section

    DM = 1.01 m Midpoint Diameter of Section

    DT = 0.917 m Top Diameter of Section

    CALCULATIONS

    y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase

    y1 = 2.644266 m

    y2 = [(2DM + DB)/3(DM + DB)]*(L/2) Center of A2 of Section from base

    y2 = 2.649289 m

    A1 = (DT + DM)*(L/2)/2

    A1 = 5.178813 sqm Area of Top Section

    A2 = (DM + DB)*(L/2)/2

    A2 = 5.670625 sqm Area of Bottom Section

    z1 = h + L/2 + y1 Distance of center of A1 to base of sectionz1 = 20.05927 m

    z2 = h + y2 Distance of center of A2 to base of section

    z2 = 14.68929 m

    Kz1 = (z1/10)^2/7 Exposure Coefficient at A1

    Kz1 = 1.220041 1 < Kz < 2.58

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    Kz1 = 1.22 Input Value

    Kz2 = (z2/10)^2/7 Exposure Coefficient at A2

    Kz2 = 1.116127 1 < Kz < 2.58

    Kz2 = 1.116 Input Value

    qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1

    qz1 = 1137.495

    qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2

    qz2 = 1040.647

    F1= GH*qz1*A1

    F1 = 9955.576 N

    F1 = 9.955576 kN

    F2= GH*qz2*A2

    F2 = 9972.892 N

    F2 = 9.972892 kN

    F1*z1 = 199.7016 kN-m

    F2*z2 = 146.4947 kN-m

    z equivalent (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti

    z equivalent 17.37194 m

    qzequivalent (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section

    qzequivalent 1086.876 kPa

    Kzequivalent (zequivalent/10)^2/7 Equivalent Exposure of the Section

    Kzequivalent 1.17092

    GH*qzequivalent*AT = 19928.47

    C = (Kzequivalent^0.50)*V*Dp

    C = 19.90435 > 8.7 Table 1

    CF = 0.72 Input value as per Table 1

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    FAST PLANETS ENGINEERING DESIGN C

    Project Name:

    Designed by: FCFalgui Date:

    ANALYSIS OF MONOPOLESECTION 4

    Analysis Criteria:

    Determine Wind Pressures

    H = 45 m Heightof Monopole

    V = 39 m/s Basic Design Wind speed for the structure

    GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2

    To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts

    SECTION PROPERTIES

    h = 0 m Section base elevation

    L = 11.85 m Length of section

    DB = 1.269 m Bottom Diameter of Section

    DM = 1.168 m Midpoint Diameter of Section

    DT = 1.067 m Top Diameter of Section

    CALCULATIONS

    y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase

    y1 = 2.917875 m

    y2 = [(2DM + DB)/3(DM + DB)]*(L/2) Center of A2 of Section from base

    y2 = 2.921574 m

    A1 = (DT + DM)*(L/2)/2

    A1 = 6.621188 sqm Area of Top Section

    A2 = (DM + DB)*(L/2)/2

    A2 = 7.219613 sqm Area of Bottom Section

    z1 = h + L/2 + y1 Distance of center of A1 to base of sectionz1 = 8.842875 m

    z2 = h + y2 Distance of center of A2 to base of section

    z2 = 2.921574 m

    Kz1 = (z1/10)^2/7 Exposure Coefficient at A1

    Kz1 = 0.965475 1 < Kz < 2.58

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    Kz1 = 1 Input Value

    Kz2 = (z2/10)^2/7 Exposure Coefficient at A2

    Kz2 = 0.703593 1 < Kz < 2.58

    Kz2 = 1 Input Value

    qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1

    qz1 = 932.373

    qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2

    qz2 = 932.373

    F1= GH*qz1*A1

    F1 = 10433.07 N

    F1 = 10.43307 kN

    F2= GH*qz2*A2

    F2 = 11376.02 N

    F2 = 11.37602 kN

    F1*z1 = 92.25836 kN-m

    F2*z2 = 33.23588 kN-m

    z equivalent (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti

    z equivalent 5.754217 m

    qzequivalent (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section

    qzequivalent 932.373 kPa

    Kzequivalent (zequivalent/10)^2/7 Equivalent Exposure of the Section

    Kzequivalent 0.853937

    GH*qzequivalent*AT = 21809.09

    C = (Kzequivalent^0.50)*V*Dp

    C = 38.45403 > 8.7 Table 1

    CF = 0.72 Input value as per Table 1

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    ONSULTANTS

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    FAST PLANETS ENGINEERING DESIGN C

    Project Name:

    Designed by: FCFalgui Date:

    ANALYSIS OF MONOPOLESECTION 5

    Analysis Criteria:

    Determine Wind Pressures

    H = 25 m Height of Monopole

    V = 39 m/s Basic Design Wind speed for the structure

    GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2

    To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts

    SECTION PROPERTIES

    h = 0 m Section base elevation

    L = 0 m Length of section

    DB = 0 m Bottom Diameter of Section

    DM = 0 m Midpoint Diameter of Section

    DT = 0 m Top Diameter of Section

    CALCULATIONS

    y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase

    y1 = 0 m

    y2 = [(2DM + DB)/3(DM + DB)]*(L/2) Center of A2 of Section from base

    y2 = 0 m

    A1 = (DT + DM)*(L/2)/2

    A1 = 0 sqm Area of Top Section

    A2 = (DM + DB)*(L/2)/2

    A2 = 0 sqm Area of Bottom Section

    z1 = h + L/2 + y1 Distance of center of A1 to base of section

    z1 = 0 m

    z2 = h + y2 Distance of center of A2 to base of section

    z2 = 0 m

    Kz1 = (z1/10)^2/7 Exposure Coefficient at A1

    Kz1 = 0

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    Kz2 = (z2/10)^2/7 Exposure Coefficient at A2

    Kz2 = 0

    qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1

    qz1 = 0

    qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2

    qz2 = 0

    F1= GH*qz1*A1

    F1 = 0 N

    F1 = 0 kN

    F2= GH*qz2*A2

    F2 = 0 N

    F2 = 0 kN

    F1*z1 = 0 kN-m

    F2*z2 = 0 kN-m

    z equivalent (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti

    z equivalent #DIV/0! m

    qzequivalent (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section

    qzequivalent #DIV/0! kPa

    Kzequivalent (zequivalent/10)^2/7 Equivalent Exposure of the Section

    Kzequivalent #DIV/0!

    GH*qzequivalent*AT = #DIV/0!

    C = (Kzequivalent^0.50)*V*Dp

    C = #DIV/0! > 8.7 Table 1

    CF = 0.72 Input value as per Table 1

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    ONSULTANTS

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    FAST PLANETS ENGINEERING DESIGN C

    Project Name:

    Designed by: FCFalgui Date:

    ANALYSIS OF MONOPOLESECTION 5

    Analysis Criteria:

    Determine Wind Pressures

    H = 45 m Heightof Monopole

    V = 39 m/s Basic Design Wind speed for the structure

    GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2

    To satisfy Section 2.3.9.3 , Calculate pressures on each section using two parts

    SECTION PROPERTIES

    h = m Section base elevation

    L = m Length of section

    DB = m Bottom Diameter of Section

    DM = m Midpoint Diameter of Section

    DT = m Top Diameter of Section

    CALCULATIONS

    y1 = [(2DT + DM)/3(DT + DM)]*(L/2) Center of A1 of Section from midbase

    y1 = 0 m

    y2 = [(2DM + DB)/3(DM + DB)]*(L/2) Center of A2 of Section from base

    y2 = 0 m

    A1 = (DT + DM)*(L/2)/2

    A1 = 0 sqm Area of Top Section

    A2 = (DM + DB)*(L/2)/2

    A2 = 0 sqm Area of Bottom Section

    z1 = h + L/2 + y1 Distance of center of A1 to base of sectionz1 = 0 m

    z2 = h + y2 Distance of center of A2 to base of section

    z2 = 0 m

    Kz1 = (z1/10)^2/7 Exposure Coefficient at A1

    Kz1 = 0

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    Kz2 = (z2/10)^2/7 Exposure Coefficient at A2

    Kz2 = 0

    qz1 = 0.613*Kz1*v^2 Velocity Pressure at A1

    qz1 = 0

    qz2 = 0.613*Kz2*v^2 Velocity Pressure at A2qz2 = 0

    F1= GH*qz1*A1

    F1 = 0 N

    F1 = 0 kN

    F2= GH*qz2*A2

    F2 = 0 N

    F2 = 0 kN

    F1*z1 = 0 kN-m

    F2*z2 = 0 kN-m

    z equivalent (F1*z1 + F2*z2)/(F1+ F2) Equivalent Distance of the center of the Secti

    z equivalent #DIV/0! m

    qzequivalent (F1 + F2)/(1.69*(A1 + A2) Equivalent Velocity Pressure of Section

    qzequivalent #DIV/0! kPa

    Kzequivalent (zequivalent/10)^2/7 Equivalent Exposure of the SectionKzequivalent #DIV/0!

    GH*qzequivalent*AT = #DIV/0!

    C = (Kzequivalent^0.50)*V*Dp

    C = #DIV/0! > 8.7 Table 1

    CF = 0.72 Input value as per Table 1

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    ONSULTANTS

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    on to its base

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    FAST PLANETS ENGINEERING DESIG

    Project Name:

    Designed by: FCFalgui Date:

    ANALYSIS OF MONOPOLE

    Analysis Criteria:

    Determine Wind Pressures

    H = 45 m Heightof Monopole

    V = 39 m/s Basic Design Wind speed for the structure

    GH = 1.69 Gust Response of Monopole as per Section 2.3.4.2

    Qualifying Criteria for Force Coefficient, CF for Cantilevered Tubular pole Structures as per Se

    C = iz^0.50)*V*Dp

    C = 0 > 8.7 Table 1

    CF = 0.72 Input value as per Table 1

    F = qz*GH*CF*AR

    OTM = F*zequivalent

    SUMMARY

    SECTION AG AR GH*qZ*AG F zequivalent OTM

    1 7.3884 7.61005 17186.373 12.7454 39.2594247 500.378

    2 9.2184625 9.49502 19484.32864 14.4496 28.1832913 407.237

    3 10.849438 11.1749 19928.46839 14.779 17.3719445 256.739

    4 13.8408 14.256 21809.09209 16.1736 5.75421661 93.0665

    5 0 0 0 0 0 0

    6 0 0 0 0 0 0

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    CONSULTANTS

    ction 2.3.5.2