descomplicamaterial.descomplica.com.br/projetos-especiais/aula4... · 2016. 7. 4. · 𝑃𝑜...
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![Page 1: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/1.jpg)
![Page 2: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/2.jpg)
![Page 3: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/3.jpg)
![Page 4: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/4.jpg)
![Page 5: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/5.jpg)
![Page 6: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/6.jpg)
![Page 7: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/7.jpg)
![Page 8: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/8.jpg)
![Page 9: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/9.jpg)
![Page 10: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/10.jpg)
![Page 11: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/11.jpg)
![Page 12: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/12.jpg)
![Page 13: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/13.jpg)
![Page 14: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/14.jpg)
![Page 15: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/15.jpg)
![Page 16: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/16.jpg)
![Page 17: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/17.jpg)
![Page 18: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/18.jpg)
![Page 19: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/19.jpg)
𝐼 =𝑃𝑜𝑡𝑇𝑜𝑡𝑎𝑙
𝐴
𝑃𝑜𝑡𝑇𝑜𝑡𝑎𝑙 = 𝐼. 𝐴 = 1000 𝑥 9,0 = 9,0 𝑥 10³ 𝑊
𝜂 =𝑃𝑜𝑡Ú𝑡𝑖𝑙
𝑃𝑜𝑡𝑇𝑜𝑡𝑎𝑙
![Page 20: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/20.jpg)
𝑃𝑜𝑡Ú𝑡𝑖𝑙 = 𝜂. 𝑃𝑜𝑡𝑇𝑜𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥 10³ 𝑊
𝜏𝑇𝑜𝑡𝑎𝑙 = 𝛥𝐸𝑐𝑖𝑛 =𝑚
2(𝑉2 − 𝑉0
2)
𝜏𝑇𝑜𝑡𝑎𝑙 =200
2𝑥 (30)2 = 9,0 𝑥 104 𝐽
𝑃𝑜𝑡Ú𝑡𝑖𝑙 =𝜏𝑇𝑜𝑡𝑎𝑙
𝛥𝑡
𝛥𝑡 =𝜏𝑇𝑜𝑡𝑎𝑙
𝑃𝑜𝑡Ú𝑡𝑖𝑙
= 9,0 𝑥104
2,7𝑥 103 = 33𝑠
ω
ω
ω ω
![Page 21: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/21.jpg)
𝑣1 = 𝑣2
𝜔2 = 𝜔3
𝑣1 = 𝑣2 = 𝜔2𝑅2 → 𝜔2 =𝑣1
𝑅 2
𝑣3 = 𝜔2𝑅3
𝑣3 = 𝑣1𝑅3/𝑅2
𝑣1 = 𝑣3
𝜔2 = 𝜔3
𝑣1 = 𝑣3 = 𝜔3𝑅3 → 𝜔3 =𝑣1
𝑅 3
𝑣2 = 𝜔3𝑅2
𝑣2 = 𝑣1𝑅2/𝑅3
𝑅2 < 𝑅3
𝑇 = 2 𝜋 √(𝐿/𝑔)
![Page 22: Descomplicamaterial.descomplica.com.br/projetos-especiais/Aula4... · 2016. 7. 4. · 𝑃𝑜 Ú𝑡𝑖𝑙 = 𝜂.𝑃𝑜 𝑇 𝑡𝑎𝑙 = 0,30 𝑥 9,0 𝑥 10³ = 2,7 𝑥](https://reader036.vdocuments.site/reader036/viewer/2022062403/6050b15c83946c4256440746/html5/thumbnails/22.jpg)