2-3. arithmetic and geometric sequences
TRANSCRIPT
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9.2 – Arithmetic Sequences and Series
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An introduction…………
1, 4, 7,10,13
9,1, 7, 15
6.2, 6.6, 7, 7.4
, 3, 6
− −
π π + π +
Arithmetic Sequences
ADD
To get next term
2, 4, 8,16, 32
9, 3,1, 1/ 3
1,1/ 4,1/16,1/ 64
, 2.5 , 6.25
− −
π π π
Geometric Sequences
MULTIPLY
To get next term
Arithmetic Series
Sum of Terms
35
12
27.2
3 9
−
π +
eometric Series
Sum of Terms
62
20/3
85/64
9.75π
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!ind the ne"t four terms of #9, $2, 5, …
Arithmetic Se%uence
2 9 5 2 7− − − = − − =7 is referred to &s the common difference 'd(
)ommon *ifference 'd( # +h&t +e A** to et ne"t term
-e"t four terms……12, 19, 26, 33
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oc&u&r of Se%uences 'niers&(
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
d common difference
→( )
( )
n 1
n 1 n
nth term of &rithmetic se%uence
sum of n terms of &rithmetic se%uen
& & n 1 d
nS & &
2
ce
= + −
= +
→
→
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ien &n &rithmetic se%uence +ith 15 1& 38 &nd d 3, find & .= = −
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
d common difference→
"
15
38
-A
$3
( )n 1& & n 1 d= + −
( ) ( )38 " 1 15 3= + − −
80
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63!ind S of 19, 13, 7,...− − −
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
d common difference→
$19
63
"
6
( )n 1& & n 1 d= + −
( ) ( ) 19 6 1 353
3 6= + −=
−
353
( )n 1 nn
S & &2
= +
( )63 63 3 3S2
19 5−= +
63 1 1S 052=
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n 1!ind n if & 633, & 9, &nd d 24= = =
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
d common difference→
9
"
633
-A
24( )n 1& & n 1 d= + −
( )633 9 21" 4= + −
633 9 2 244"= + − 27
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1 29!ind d if & 6 &nd & 20= − =
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
d common difference→
$6
29
20
-A
"( )n 1& & n 1 d= + −
( )120 6 29 "= + −−
26 28"=13
"14
=
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!ind t+o &rithmetic me&ns et+een #4 &nd 5
$4, , , 5
1& !irst term→n& nth term→
nS sum of n terms→
n numer of terms→
d common difference→
$4
4
5
-A"
( )n 1& & n 1 d= + −
( ) ( )15 4 4 "= + −−" 3=
The t+o &rithmetic me&ns &re #1 &nd 2, since #4, $1, 2, 5
forms &n &rithmetic se%uence
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!ind three &rithmetic me&ns et+een 1 &nd 4
1, , , , 4
1& !irst term→n& nth term→
nS sum of n terms→
n numer of terms→
d common difference→
1
5
4
-A"
( )n 1& & n 1 d= + −
( ) ( )4 1 "15= + −3
"4
=
The three &rithmetic me&ns &re 7/4, 10/4, &nd 13/4
since 1, 7/4, 10/4, 13/4, 4 forms &n &rithmetic se%uence
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!ind n for the series in +hich 1 n& 5, d 3, S 440= = =
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
d common difference→
5
"
440
3
( )n 1& & n 1 d= + −
( )n 1 nnS & &2
= +
( ) 5 31"= + −
( )"
40 42
5= +
( )( )12
"440 5 5 " 3= + + −
( )" 7 "440
2
3=
+
( )880 " 7 3"= +20 3" 7" 880= + −
16
r&:h on :ositie +indo+
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The sum of the first n terms of an infinite sequence
is called the nth partial sum.
1(
2n n
nS a a= +
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Example !. "ind the 1#$th partial sum of the arithmetic sequence% #%
1!% 2&% '(% )9% *
1 # 11 # 11 !a d c= = → = − = −
11 !n
a n= − ( )1#$ 11 1#$ ! 1!))a→ = − =
( ) ( )1#$1#$
# 1!)) 1!)9 12'%!2
S = + = =
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Example &. An auditorium has 2$ ro+s of seats. There are 2$ seats in
the first ro+% 21 seats in the second ro+% 22 seats in the third ro+% and
so on. ,o+ man- seats are there in all 2$ ro+s
1 2$ 1 19d c= = − =
( ) ( )1 2$1 2$ 19 1 '9na a n d a= + − → = + =
( ) ( )2$2$
2$ '9 1$ #9 #9$2
S = + = =
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9.' – eometric Sequences and Series
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1, 4, 7,10,13
9,1, 7, 15
6.2, 6.6, 7, 7.4
, 3, 6
− −
π π + π +
Arithmetic Sequences
ADD
To get next term
2, 4, 8,16, 32
9, 3,1, 1/ 3
1,1/ 4,1/16,1/ 64
, 2.5 , 6.25
− −
π π π
Geometric Sequences
MULTIPLY
To get next term
Arithmetic Series
Sum of Terms
35
12
27.2
3 9
−
π +
eometric Series
Sum of Terms
62
20/3
85/64
9.75π
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oc&u&r of Se%uences 'niers&(
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
r common r&tio→
( )
n 1
n 1
n
1
n
nth term of eometric se%uence
sum of n terms of eometric se%u
& & r
& r 1S
r 1
ence
−→ =
− =
−
→
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!ind the ne"t three terms of 2, 3, 9/2, , ,
3 # 2 s. 9/2 # 3… not &rithmetic
3 9 / 2 31.5 eometric r 2 3 2= = → → =
3 3 3 3 3 3
2 2 2
92, 3, , , ,
2
9 9 9
2 2 2 2 2 2
× × × × × ×
92, 3, , ,
27 81 243
4 8,
2 16
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1 9
1 2;f & , r , find & .
2 3= =
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
r common r&tio→
1/2
"
9
-A
2/3
n 1
n 1& & r −=
9 11 2
"2 3
− =
8
8
2"
2 3=
×
7
8
2
3= 128
6561=
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!ind t+o eometric me&ns et+een #2 &nd 54
$2, , , 54
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
r common r&tio→
$2
54
4
-A"
n 1
n 1& & r −=
( ) ( )14
54 2 " −
−=3
27 "− =3 "− =
The t+o eometric me&ns &re 6 &nd $18, since #2, 6, $18, 54
forms &n eometric se%uence
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2 4 1
2!ind & & if & 3 &nd r
3− = − =
$3, , ,
2Since r ...
3=
4 83, 2, ,
3 9
− −− −
2 4
8 10
& & 2 9 9
− −
− = − − =
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9!ind & of 2, 2, 2 2,...
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
r common r&tio→
"
9
-A
2
2 2 2r 2
22= = =
n 1
n 1& & r −=
( ) 9 1
" 2 2−
=
( )8
" 2 2=
" 16 2=
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5 2;f & 32 2 &nd r 2, find &= = −
, , , ,32 2
1& !irst term→n& nth term→
nS sum of n terms→
n numer of terms→
r common r&tio→
"
5
-A
32 2
2−n 1
n 1& & r −=
( )
5 1
32 2 " 2−
−=
( )4
32 2 " 2= −
32 2 "4=
8 2 "=
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7
1 1 1!ind S of ...
2 4 8+ + +
1& !irst term→
n& nth term→
nS sum of n terms→
n numer of terms→
r common r&tio→
1/2
7
"
-A
11
184r 1 1 2
2 4
= = =
( )n1n
& r 1S
r 1
− =−
71 1
2 2"
1
2
1
1
− =−
71 1
2 2
1
2
1 − =
−
63
64=
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Section 12.3 # ;nfinite Series
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1, 4, 7, 10, 13, …. ;nfinite Arithmetic -o Sum
3, 7, 11, …, 51 !inite Arithmetic ( )n 1 nn
S & &
2
= +
1, 2, 4, …, 64 !inite eometric ( )n1
n
& r 1S
r 1
−=
−
1, 2, 4, 8, … ;nfinite eometric
r > 1
r ? $1
-o Sum
1 1 13,1, , , ...3 9 27
;nfinite eometric$1 ? r ? 1
1&S1 r
= −
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!ind the sum, if :ossie1 1 1
1 ...2 4 8
+ + + +
1 1
12 4r 11 2
2
= = = 1 r 1 @es→ − ≤ ≤ →
1& 1S 211 r
12
= = =− −
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!ind the sum, if :ossie 2 2 8 16 2 ...+ + +
8 16 2r 2 2
82 2= = = 1 r 1 -o→ − ≤ ≤ →
- SB
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!ind the sum, if :ossie2 1 1 1
...3 3 6 12
+ + + +
1 1
13 6r 2 1 2
3 3
= = = 1 r 1 @es→ − ≤ ≤ →
1
2& 43S
11 r 31
2
= = =− −
2 4 8
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!ind the sum, if :ossie2 4 8
...7 7 7
+ + +
4 8
7 7r 22 4
7 7
= = = 1 r 1 -o→ − ≤ ≤ →
- SB
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!ind the sum, if :ossie5
10 5 ...2
+ + +
5
5 12r 10 5 2
= = = 1 r 1 @es→ − ≤ ≤ →
1& 10S 2011 r
12
= = =− −
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The Councin C& Droem # ersion A
A & is dro::ed from & heiht of 50 feet. ;t reounds 4/5 of
itEs heiht, &nd continues this :&ttern unti it sto:s. Fo+ f&r
does the & tr&e50
40
32
32/5
40
32
32/5
40S 45
50
41
0
155
4= =
−+
−
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The Councin C& Droem # ersion C
A & is thro+n 100 feet into the &ir. ;t reounds 3/4 of
itEs heiht, &nd continues this :&ttern unti it sto:s. Fo+ f&r
does the & tr&e
100
75
225/4
100
75
225/4
10S 80
100
4 4
31
0
1
03
= =−
+−
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Sim& -ot&tion
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C
n
n A&
=∑
DDGH C-*
'-BCGH(
IJGH C-*
'-BCGH(
S;BA'SB ! TGHBS( -TF TGHB
'SGKG-)G(
4
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( ) L
4
1
L 2=
+∑ ( )21= + ( )2 2+ + ( )3 2+ + ( )24+ + 18=
( )7
4&
2&=∑ ( )( )42= ( )( )2 5+ ( )( )2 6+ ( )( )72+ 44=
( )nn 0
4
0.5 2=
+
∑ ( )00.5 2= + ( )10.5 2+ + ( )20.5 2+ + ( )30.5 2+ + ( )
40.5 2+ +
33.5=
n 0 1 2
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0
n
36
5=
∞ =
∑0
36
5
13
65
+
23
65
+ ...+
1&S1 r = − 6 153
15
= =−
( )2
"
3
7
2" 1=
+∑ ( )( ) ( )( ) ( )( ) ( )( )2 1 2 8 1 2 9 1 ...7 2 123= + + + + + + + +
( ) ( )n 1 n2n 1
S & & 152
3
2
747
− += + = + 527=
19
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( )1
9
4
4 3=
+∑ ( )( ) ( )( ) ( )( ) ( )( )4 3 4 5 3 4 6 3 ...4 4 319= + + + + + + + +
( ) ( )n 1 n1n 1
S & & 192
9
2
479
− +
= + = + 784=
H it i i t ti 3 6 9 12
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He+rite usin sim& not&tion 3 M 6 M 9 M 12
Arithmetic, d 3
( )n 1& & n 1 d= + −( )n& 3 n 1 3= + −
n& 3n=
4
1n
3n=
∑
H i i i i 16 8 4 2 1
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He+rite usin sim& not&tion 16 M 8 M 4 M 2 M 1
eometric, r N
n 1
n 1& & r
−
= n 1n
1& 16
2
− =
n 1
n
5
1
116 2
−
= ∑
H it i i t ti 19 18 16 12 4
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He+rite usin sim& not&tion 19 M 18 M 16 M 12 M 4
-ot Arithmetic, -ot eometric
n 1
n& 20 2 −= −
n 1
n
5
1
20 2 −
=−∑
19 M 18 M 16 M 12 M 4 $1 $2 $4 $8
3 9 27
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He+rite the foo+in usin sim& not&tion3 9 27
...5 10 15
+ + +
-umer&tor is eometric, r 3
*enomin&tor is &rithmetic d 5
-BGHATH ( )n 1
n3 9 27 ... & 3 3
−
+ + + → =
*G-B;-ATH ( )n n5 10 15 ... & 5 n 1 5 & 5n+ + + → = + − → =
S;BA -TAT;- ( )
1
1
n
n 5n
3 3 −∞
=∑