1.7 giải tích mạch
DESCRIPTION
giải tích mạchTRANSCRIPT
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ECA - Ch1.7 1
1.7 Cac phep bien oi tng ng mach
1.7.1 Gii thieu :
n gian hoa s o bang cach dung cac luat bien oi, bao toan u,i phan mach con lai.
Co y ngha thc tien ln . Cho li giai nhanh chong .
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ECA - Ch1.7 2
1.7.2 Bien oi nguon ly tng :
n
td kk 1
e e=
=
Nguon ap noi tiep :
e1
e2
en
etd
Xet dau :
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ECA - Ch1.7 3
1.7.2 Bien oi nguon ly tng :
n
td kk 1
J J=
= Jtd
Nguon dong song song :
J1 J2 Jn
Xet dau :
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ECA - Ch1.7 4
1.7.2 Bien oi nguon ly tng :
Lu y :
e = e1 = e2e1 e2 Khong ton tai neu e1 e2 .
Khong ton tai neu J1 J2 .
J1J2
J = J1 = J2
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ECA - Ch1.7 5
1.7.2 Bien oi nguon ly tng :
Nguon ap song song nhanh :
e
e
J
J
Nguon dong noi tiep nhanh :
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ECA - Ch1.7 6
1.7.3 Bien oi tng ng mach ien tr
a) ien tr noi noi tiep :
b) ien dan noi song song :
n
eq kk 1
R R=
=
n
eq kk 1
G G=
=
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ECA - Ch1.7 7
V du: Tng ng mach ien tr
Hai ien tr noi song song :
1 2eq
1 2
R RRR R
= +
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ECA - Ch1.7 8
c) Bien oi ien tr noi Y- :
1 2( )
12 23 31
( )Y node
R R to nodeRR R R = + +
1 2 1 3 3 2
( )Y
R R R R R RRR facing node
+ +=
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ECA - Ch1.7 9
1.7.4 Mach chia ap
a) Mach gom 2 ien tr :
b) Mach gom N ien tr :
11
1 2
Ru uR R
= +2
21 2
Ru uR R
= +
kk N
ii 1
Ru uR
=
=
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ECA - Ch1.7 10
1.7.5 Mach chia dong
b) Mach gom N ien tr :
Fk 0
k
Ri iR
=
21 0
1 2
Ri iR R
= + 12 01 2
Ri iR R
= +
a) Mach gom 2 ien tr :
i0
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ECA - Ch1.7 11
1.7.6 Mach nguon tng ng
Su E R .i= S
1i J uR
=
SE R .J= Hai mang mot ca la tng ng neu thoa :
Cho 2 mang mot ca (la 2 mach nguon thc) :
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ECA - Ch1.7 12
Source Transformation :
(a) Independent source transform
(b) Dependent source transform
The arrow of the current source is directed toward the positive terminal of the voltage source.
The source transformation is not possible when R = 0 for voltage source and R = for current source.
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ECA - Ch1.7 13
1.7.7 Lu y khi dung bien oi tng ng
Phan mach b bien oi khong c cha tn hieu b phu thuoc.
Ch bien oi neu ta di tn hieu b phu thuoc o i ni khac.