1.2 calculus powerpoint
TRANSCRIPT
1.2:Rates of Change & Limits
Learning Goals:
©2009 Mark Pickering
•Calculate average & instantaneous speed•Define, calculate & apply properties of limits•Use Sandwich Theorem
Important Ideas•Limits are what make calculus different from algebra and trigonometry•Limits are fundamental to the study of calculus•Limits are related to rate of change•Rate of change is important in engineering & technology
Theorem 1Limits have the following properties:
lim ( )x c
g x M
lim ( )x c
f x L
if &then:
lim ( ) ( )x c
f x g x L M
1.
Theorem 1Limits have the following properties:
lim ( )x c
g x M
lim ( )x c
f x L
if &then:
lim ( ) ( )x c
f x g x L M
2.
Theorem 1Limits have the following properties:
lim ( )x c
g x M
lim ( )x c
f x L
if &then:
lim ( ) ( )x c
f x g x L M
3.
Theorem 1Limits have the following properties:
lim ( )x c
f x L
ifthen:
lim ( )x c
k f x k L
4.
& k a constant
Theorem 1Limits have the following properties:
lim ( )x c
g x M
lim ( )x c
f x L
if &then:
( )lim , 0( )x c
f x L Mg x M
5.
Theorem 1Limits have the following properties:
lim ( )x c
f x L
if &
6.
r & s areintegers, then:
lim ( )x c
rrssf x L
Theorem 1Limits have the following properties:if where k is a
7.constant, then:lim ( ) lim
x c x cf x k k
( )f x k
(not in your text as Th. 1)
Theorem 2For polynomial and rational functions:
lim ( ) ( )x c
f x f c
( ) ( )lim , ( ) 0( ) ( )x c
f x f c g cg x g c
a.b.
Limits may be found by substitution
ExampleSolve using limit properties and substitution:
2
3lim 2 3 2x
x x
Try ThisSolve using limit properties and substitution:2
2
4lim3x
x xx
6
ExampleSometimes limits do not exist. Consider:
3
2
3lim2x
xx
If substitution gives a constant divided by 0, the limit does not exist (DNE)
ExampleTrig functions may have limits.
2
lim(sin )x
x
Try This
2
lim(cos )x
x
2
lim(cos ) cos 02x
x
ExampleFind the limit if it exists:3
1
1lim
1x
xx
Try substitution
ExampleFind the limit if it exists:3
1
1lim
1x
xx
Substitution doesn’t work…does this mean the limit doesn’t exist?
Important Idea3 21 ( 1)( 1)
1 1x x x xx x
2 1x x and
are the same except at x=-1
Important Idea
The functions have the same limit as x-1
Procedure1.Try substitution2. Factor and cancel if
substitution doesn’t work
3.Try substitution againThe factor & cancellation
technique
Try ThisFind the limit if it exists:
2
3
6lim
3x
x xx
5Isn’t th
at
easy?Did you think calculus
was going to be
difficult?
Try ThisFind the limit if it exists:
22
2lim4x
xx
14
Try ThisFind the limit if it exists:
2
3
6lim
3x
x xx
The limit doesn’t existConfirm by graphing
DefinitionWhen substitution results in a 0/0 fraction, the result is called an indeterminate form.
Important IdeaThe limit of an indeterminate form exists, but to find it you must use a technique, such as factor and cancel.
Try ThisFind the limit if it exists:
2
1
2 3lim
1x
x xx
-5
Try ThisGraph and
3
111
xY
x
22 1Y x x on the
same axes. What is the difference between these graphs?
3 1( )
1x
f xx
Why is there a “hole” in the graph at x=1?
Analysis
ExampleConsider3 1
( )1
xf x
x
for ( ,1) (1, ) and
( ) 4f x
for x=13
1
1lim
1x
xx
=?
Try ThisFind: if
1lim ( )x
f x
2( ) 2, 1f x x x
( ) 1, 1f x x
1lim ( ) 3x
f x
Important IdeaThe existence or non-existence of f(x) as x approaches c has no bearing on the existence of the limit of f(x) as x approaches c.
Important IdeaWhat matters is…what value does f(x) get very, very close to as x gets very,very close to c. This value is the limit.
Try ThisFind:
f(0)is undefined; 2 is the limit
2( )
1 1x
f xx
0lim ( )x
f x
Find:
( ) 1, 0f x x
Try This( ) , 0
1 1x
f x xx
f(0) is defined; 2 is the limit
21
0lim ( )x
f x
Try ThisFind the limit of f(x) as x approaches 3 where f is defined by:
2 , 3( )
3 , 3x
f xx
3lim ( ) 2x
f x
Try ThisGraph and find the limit (if it exists):
3
3lim
3x x DNE
Theorem 3: One-sided & Two Sided limits
if lim ( )x c
f x L
(limit from right)
andlim ( )x c
f x L
(limit from left)
then lim ( )x c
f x L
(overall limit)
Theorem 3: One-sided & Two Sided limits
(Converse)if lim ( )
x cf x L
(limit from
right)andlim ( )x c
f x M
(limit from left)
then lim ( )x c
f x
(DNE)
ExampleConsider
3 1( ) , 1
1x
f x xx
What happens at x=1?
x .75 .9 .99 .999
f(x)
Let x get close to 1 from the left:
Try ThisConsider
3 1( ) , 1
1x
f x xx
x 1.25 1.1 1.01
1.001
f(x)
Let x get close to 1 from the right:
Try ThisWhat number does f(x) approach as x approaches 1 from the left and from the right?
3
1
1lim 3
1x
xx
Try ThisFind the limit if it exists:
0limx
xx
DNE
ExampleFind the limit if it exists:
0
1lim sinx x
Example1.Graph using a friendly window:
1sin
x
2. Zoom at x=03. Wassup at x=0?
Important Idea
If f(x) bounces from one value to another (oscillates) as x approaches c, the limit of f(x) does not exist at c:
Theorem 4: Sandwich (Squeeze) Theorem
Let f(x) be between g(x) & h(x) in an interval containing c. Iflim ( ) lim ( )
x c x cg x h x L
lim ( )x c
f x L
then:f(x) is “squeezed” to L
ExampleFind the limit if it exists:
0
sinlim
Where is in radians and in the interval,2 2
ExampleFind the limit if it exists:
0
sinlim
Substitution gives the indeterminate form…
ExampleFind the limit if it exists:
0
sinlim
Factor and cancel doesn’t work…
ExampleFind the limit if it exists:
0
sinlim
Maybe…the squeeze theorem…
Exampleg()=1
h()=cos
sin( )f
Example
0lim1 1
0
lim cos 1
&therefore…
0
sinlim 1
Two Special Trig Limits
0
sinlim 1
0
1 coslim 0
Memoriz
e
ExampleFind the limit if it exists:
0
tanlimx
xx
0 0
sin 1lim lim 1 1 1
cosx x
xx x
ExampleFind the limit if it exists:
0
sin(5 )limx
xx
0 0
sin(5 ) sin(5 )lim 5 5 lim 5 1 5
5 5x x
x xx x
Try ThisFind the limit if it exists:
0
3 3 coslimx
xx
0
Lesson CloseName 3 ways a limit may fail to exist.
Practice1. Sec 1.2 #1, 3, 8, 9-18, 28-38E (just find limit L), 39-42gc (graphing calculator), 43-45