1 universal model of gr an attempt to systematize the study of models in gr

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1 UNIVERSAL MODEL OF GR An attempt to systematize the study of models in GR

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Page 1: 1 UNIVERSAL MODEL OF GR An attempt to systematize the study of models in GR

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UNIVERSAL MODEL OF GR

An attempt to systematize the study of models in GR

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SCOPE

1. Generic model

Determine the minimum number:

- of variables

- of equations relating these variables

which are sufficient to describe all models in GR.

2. Classify/quantify the constraints which are used to select a specific model in GR.

3. Determine general classes of GR models.

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Modeling GR

The generic model of GR consists of the following parts:

- Background Riemannian space (gab)

– Kinematics (ua)

– Dynamics (Gab=kΤab)

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VARIABLES• Each part of the generic model is specified by means of variables

and identities / conditions among these variables.• - Space time: gab,Γα

bc i.e. metric, connection.Identities: Bianchi - Symmetries of curvature tensor, Gab

;b=0• Kinematics: ua,ua;b → ωab,σab,θ, ua;bub (1+3)Ricci identity to ua. Integrating conditions of ua;b.

Propagation and Constraint equations (1+3)• Dynamics: Physical variables observed by ua for Tab (1+3)

– Matter density μ– Isotropic pressure p– Momentum transfer / heat conducting qa

– Anisotropic stress tensor πab

Bianchi Identity: Gab;b=0 → Tab

;b=0. Conservation equations via field equations. These are constraints. No field equations. (1+3)

What it means 1+3?

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Conclusion: The generic/universal model

• Variables– gab

– ua, ua;b → ωab, σab, θ, ua;b ub

– μ, p, qa,πab

• Identities / constrains– Bianchi (symmetries of curvature tensor)– Ricci (propagation and constraint eqns)

– Bianchi (conservation equation, Gab;b=0 )

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GENERIC MODEL

GEOMETRYgab

Bianchi identities

DYNAMICSμ, p, qa,πab

Conservation Law

• KINEMATICS• ua, • ωab, σab, θ, ua;b ub

• propagation eqns • constraint eqns

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Specifying a model

• Generic model has free parameters. More constraints required.

• Types of additional assumptions– Specify four-velocity – observers (1+3)– Symmetries

• Geometric symmetries – Collineations• Dynamical symmetries

– Catastatic equations (matter constraints) – Other; Kinematical or dynamical or geometric

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1+3 decomposition

• Every non-null four-vector defines a 1+3 decomposition.

• Projection operator:

• Decomposition of a vector:

• Decomposition of a 2-tensor

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Examples of 1+3 decomposition

• Kinematical variables:

• Physical variables

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Types of matterConservation equations

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Propagation and Constrain eqnsKinematics – Ricci identity on ua

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Propagation and Constrain eqnsThe physics

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Symmetries - Collineations

General symmetry structure:– Lie Derivative [Geometric object] = Tensor

Collineations:

They are symmetries in which the geometric object is defined in terms of the metric e.g. Γa

bc,Rab,Rabcd,etc.

Form of a Collineation:

Lie Derivative [gab, Γabc,Rab,Ra

bcd,etc] = Tensor

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Examples of collineations

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Collineation tree

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Generic collineation

• All relations of the form:

LX[gab, Γabc,Rab,Ra

bcd,etc]

can be expressed in terms of LXgab. E.g.

This leads us to consider LXgab as the generic symmetry. Introduce symmetry parameters ψ,Hab via the identity:

LXgab=2ψgab+2Hab, Haa=0

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Expressing collineations in terms of the parameters ψ,Ha

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Symmetries and the field equations

• Write field equations as: Rab=k[Tab-(1/2)Tgab]

• Then: LXRab=kLX [Tab-(1/2)Tgab]• The LXRab → f(ψ,Hab, and derivatives)• The rhs as LX(μ, p, qa,πab)Equating the two results we find the field

equations in the universal form, that is:

LXμ= fμ (ψ,Hab, derivatives)

LXp= fp (ψ,Hab, derivatives) etc.

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The 1+3 decomposition of symmetries of field equations

• Example: Collineation ξa=ξua

• To compute the rhs use field eqns and 1+3 decomposition (Note: ). Result:

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To compute the lhs (use the collineation identity and symmetry parameters):

1+3 decomposition:

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Field equations in 1+3 decomposition (to be supplemented by conservation eqns)

• uaub term:

• uahcb term:

• had

hcb term:

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The string fluid

• Definition:

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Physical variables and conservation equations

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• Example of string fluid: The EM field in RMHD approximation with infinite conductivity and vanishing electric field

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Additional assumptions

• ξa=ξua is a symmetry vector

• Symmetry/kinematics:

• Further assumptions required or stop!– Specify ξa to be RIC defined by requirement:

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Kinematical implications of Collineation

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Dynamical implications of the Collineation i.e. field equations. An equation of state still

needed!

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Second approach – Example Tsamparlis GRG 38 (2006), 311

and cyclically for the Tyy, Tzz.

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Specification of ua 1+3 Kinematics

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Physical variables I

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Physical variables II

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Select model: String fluid

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Specification of physical variables

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The final field equations

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ΤHE RW MODEL (K≠0)

• Symmetry assumptions– Spacetime admits a gradient CKV ξα which is

hypersurface orthogonal. Define cosmic time t with ξα =δa

0.

– The 3-spaces are spaces of constant curvature K≠0

These imply the metric: ds2=-dt2+S(t)dσK2

KINEMATICS:

Choice of observers: u_a=S-1/2 (1,0,0,0)

Kinematic variables:

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Geometry implies Physics

• Einstein equations imply for the Tab.

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In order to determine the unknown function S(t) we need one more equation. This is an equation of state. Without it the problem is not deterministic.Note: The RW model is based only on geometrical assumptions and the choice of observers! The equation of state can be both a math or a physical assumption.

Physical variables: 1+3 of Tab

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The model of a rotating star in equilibrium

• Symmetry assumptions– Two commuting KVs ∂t (timelike), ∂φ

(spacelike) which are surface forming etc

Metric: Stationary axisymmetric metric

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KINEMATICS

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DYNAMICS

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All physical variables are ≠0. Therefore the fluid for these observers is a general heat conducting anisotropic fluid. We have three unknown functions (the α,β,ν) hence we need three independent dependent constraints / equations.In the literature (See ``Rotating stars in Relativity’’ N. Stergioulas www.livingreviews.org for review and references) they assume:

Perfect Fluid ↔ qa=0, πab=0

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Inconsistency of assumption

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Assume further πab=0