1. twice the cube of a number 2. the square of a number decreased by ten 3. the sum of three times a...
TRANSCRIPT
1. Twice the cube of a number2. The square of a number decreased by
ten3. The sum of three times a number and
seven4. Seven less than one third a number5. Three times the sum of a number and
seven6. If n represents an odd integer, what Is
the next consecutive odd integer
Algebra II 1
Literal Equations
Algebra II
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5Algebra II
1. 3x – 2y = 10
-2y = -3x + 10
y = 3/2x – 5
2. ½x + 3y = 5
3y = - ½x + 5
y = - 1/6x + 5/3
3. 10 = 3x – ¾ y
-3x + 10 = - ¾y
4x – 40/3 = y
4. 4x + 8y = 17
8y = -4x + 17
y = -1/2x + 17/8
Algebra II 6
5. 6x – 5y = 13
y = 6/5x – 13/5
6. 2/3x + 3/2y = 10
y = -4/9x + 20/3
7. 4/3x – 2y = 12
y = 2/3 x – 6
8. 3x – 8y = 4
y = 3/8x – ½
Algebra II 7
Ax + By = C
is solved for Cin terms of A, x, B, and y
½bh = A
Is solved for Ain terms of b and h.
Algebra II 8
1. What is P = 2L + 2w solved for? In terms of?
Solved for P in terms of L and W
2. What is C = 2πr solved for? In terms of?
Solved for C in terms of r
3. What are you finding in A = (b)(h)? In terms of?
Finding A in terms of b and h
4. What are you finding in b = A/h ? In terms of?
Finding b in terms A and hAlgebra II 9
1. If A = c, 3tfind t in terms of A and c. A = c 3t A = (3t)(c) A = 3tc A = t 3c
2. If 3L + 2W = 6, find w in terms of L.
3L + 2W = 6
2w = -3L + 6
w = -3/2 L + 3
Algebra II 10
3. If c = 4a2, find a in terms of c.
4. If A = πrL + πr2,
Find L in terms of A and r.
A - πr2 = πrL
A - πr2 = Lπr
A – r = L πr
Algebra II 11
5. If E=mc2, find m in terms of c and E.
6. If V = 1/3πr2h, find r in terms of V and h.
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7. If find p in terms of m, L, and q.
8. If A = 1/2bh, find h in terms of A and b.
A = ½bh
2A = bh
2A = h b
13Algebra II
1. Solve for y: 5x + 2/3 y = 102. Solve for x. 3x - 4y = 123. Solve for r in terms of V and
h: V = 4/3πr2h
14Algebra II
Literal Equations
Algebra II
What is P in terms of right now? L and W
What should you replace? LW = L + 3W – 3 = L
P = 2L + 2WP = 2(w – 3) + 2wP = 4w – 6
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What is A in terms of right now? b and h
What should you replace? Bb = 3h
A = ½bhP = ½ (3h)(h)P = 3/2 h2
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What is V in terms of right now? r and h
What should you replace? hr = 1/2h2r = h
V = 1/3πr2hV = 1/3πr2(2r)V = 2/3πr3
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What is the Area in terms of now? r
What should you replace? RC = 2πrR = C/2π
A = π(r)2
A = π(C/2π)2
A = C/(4π)
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What is the Area in terms of now? b and h
What should you replace? H
A = ½ bhA = ½ b(√3/2)bA = √3b2/4
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h=d V=πr2h What is V in terms of now?
Radius and height What should we replace?
Height h=d h=2rV=πr2hV=πr2(2r)V=2πr3
21Algebra II
h=5 + 3r S=2πrh + 2πr2
What is S in terms of now? Radius and height
What should we replace? Height
h=5+3r S= 2πrh + 2πr2
S= 2πr(5 + 3r) + 2πr2
S= 10πr + 6πr2 +2πr2
S= 10πr + 8πr2
22Algebra II
1. Solve for y: 1/3 x + 2/5 y = 10.
1. Given 4n + 1/2 m = 12, find m in terms of n.
2. If the area of a square can be found by A = s2 and the perimeter of a square can be found by p = 4s, find area of a square (A) in terms of its perimeter (p).
23Algebra II