1 ex. 6 solve: multiply by common denominator 2(x – 2) = 3x – (x)(x – 2) 2x – 4 = 3x – x 2...
TRANSCRIPT
1
Ex. 6 Solve: 12
32
xx
)2)((1)2)((2
3)2)((
2
xxxx
xxx
xMultiply by common
denominator
2(x – 2) = 3x – (x)(x – 2)
2x – 4 = 3x – x2 + 2x
x2 – 3x – 4 = 0
(x – 4)(x + 1) = 0
x = 4, – 1
2
Ex. 7 Solve: |x2 – 3x| = –4x + 6
x2 – 3x = –4x + 6–(x2 – 3x) = –4x + 6
x2 + x – 6 = 0
(x + 3)(x – 2) = 0
x = -3, 2
|(-3)2 - 3(-3)| = -4(-3) + 6
18 = 18 so -3 good
|(2)2 - 3(2)| = -4(2) + 6
2 = -2 so 2 not good
–x2 + 3x = –4x + 6
0 = x2 – 7x + 60 = (x – 6)(x – 1)
x = 6, 1
|(6)2 - 3(6)| = -4(6) + 6
18 = -18 so 6 not good
|(1)2 - 3(1)| = -4(1) + 6
2 = 2 so 1 good
3
Ex. 8 A ski club chartered a bus for a skit trip at a cost of $480. In an attempt to lower the bus fare per skier, the club invited nonmembers to go along. After five nonmembers joined the trip, the fare per skier was decreased by $4.80. How many club members are going on the trip?
(Cost per skier)(# of skiers) = cost of trip
(480/x – 4.80) (x + 5) = 480
x
x8.4480 (x + 5) = 480
(480 – 4.8x)(x + 5) = 480x
480x + 2400 – 4.8x2 – 24x = 480x
– 4.8x2 – 24x + 2400 = 0
x2 + 5x – 500 = 0
(x – 20)(x + 25) = 0
x = 20, -25
4
Compound Interest
• A= future value
• P = present value
• r = interest rate
• n = times compounded / year
• t = years
*
1n t
rA P
n
5
Ex. 9 When you were born, your grandparents deposited $5000 in a long-term investment in which the interest was compounded quarterly. Today, on your 25th birthday, the value of the investment is $25,062.59. What is the annual interest rate for this investment?
254
41500059.062,25
r
100
410125.5
r
4
10125.5 1001 r
4101625.1
r
401625.
r
r065.0
%5.6r