02 zxr10-bc-en-ip network basics (ip addressing and subnetting)-2-ppt-201105 32

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    Objectives

    Upon completion of this course, you will beable to:

    Know about IP address classification and calculation

    Be familiar with subnet and mask

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    Contents

    IP Address Classification

    Subnet and IP Address Calculation

    VLSM

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    IPv4 Address Function

    Uniquely and logically identifies end stations

    Packet forwarding is based on IP address

    172.17.0.2172.17.0.1

    SA DAHDR DATA

    10.13.0.1 192.168.1.1

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    IP Address

    32 bits

    255 255 255 255Maximum

    Network Host

    128

    64

    32

    168421

    11111111 11111111 11111111 11111111

    10101100 00010000 01111010 11001100

    Binary

    172 16 122 204Decimal

    Binary

    1 8 9 16 17 24 25 32

    128

    64

    32

    168421

    128

    64

    32

    168421

    128

    64

    32

    168421

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    Classification

    Class A:

    Class B:

    Class C:

    Class D: Multicast Address

    Class E: Reserved for Research

    Network Host Host Host

    Network Network Host Host

    Network Network Network Host

    8 bits 8 bits 8 bits 8 bits

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    1Class A:

    Bits:

    0NNNNNNN Host Host Host8 9 16 17 24 25 32

    Range (1-126)

    Class B: 10NNNNNN Network Host HostRange (128-191)

    Class C: 110NNNNN Network Network Host

    Range (192-223)

    Class D: 1110MMMM Multicast Group Multicast Group Multicast Group

    Range (224-239)

    Valid Network Numbers

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    Reserved IP Address

    Network 127.0.0.0

    Network 0.0.0.0

    All0hostaddress

    All1hostaddress

    Host 255.255.255.255

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    Default Subnet Mask

    Class ofAddress

    Size ofnetwork part

    Size of hostpart

    Default mask

    A

    B

    C

    8

    16

    24

    24

    16

    8

    255.0.0.0

    255.255.0.0

    255.255.255.0

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    Contents

    IP address classification

    Subnet and IP address calculation

    VLSM

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    Addressing Without Subnets

    172.16.0.0 172.17.2.0

    172.19.0.0

    172.18.0.0

    Subnet mask: 255.255.0.0

    A

    B

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    Addressing With Subnets

    172.16.1.0 172.16.2.0

    172.16.3.0

    172.16.4.0

    Subnet mask: 255.255.255.0

    A

    B

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    Subnet Mask And Prefix

    172 16 0 0

    255 255 0 0

    255 255 255 0

    Network Host

    Subnet Host

    11111111 11111111 00000000 00000000

    Network Host

    Network

    DefaultSubnet

    Mask

    IPAddress

    8-bitSubnet

    Mask

    Also written as /16 where 16 represents the number of 1sin the mask.

    Also written as /24 where 24 represents the number of 1sin the mask.

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    Address Formats When Subnetting

    Subnet

    Network Subnet Host

    Network Subnet Host

    Network Host

    Class A:

    Class B:

    Class C:

    8 24-x x

    16 16-x x

    x24 8-x

    172.16 2 160

    Network Host

    . .

    Subnet

    . .255.255 255 0

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    Conversion between Binary and Decimal

    128

    64

    32

    168421

    11111111 11111111 11111111 11111111

    10101100 00010000 01111010 11001100

    172 16 122 204

    1 8 9 16 17 24 25 32

    128

    64

    32

    168421

    128

    64

    32

    168421

    128

    64

    32

    168421

    Weight:

    172=128+32+8+4 128+64+8+4=204

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    Boolean AND

    0 AND 0 yields 0

    0 AND 1 yields 0

    1 AND 0 yields 0

    1 AND 1 yields 1

    0 1 1 0

    0 0 1 1

    0 0 1 0

    Boolean AND

    Rules Example

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    How Many Hosts And Subnets

    Process:

    Step 1:The class rules define the network part.

    Step 2:The mask binary 0s define the host part.

    Step 3:What is left over defines the size of subnet part

    Step 4:Number of subnets=2number-of-subnet-bits

    Step 5:Number of hosts per subnet=2number-of-host-bits-2

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    172 16 0 0

    00000000 00000000

    87654321

    Network Host

    00000001

    11111111 1111111111111110

    ...

    ...

    00000011

    11111101

    123

    254255

    256-

    ...

    2

    254

    N

    2N-2= 28-2 = 254

    ...

    10000000

    Subnet mask:

    255.255.255.0

    Subnet

    87654321

    00000001

    11111110

    Example

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    Converting table

    1 0 0 0 0 0 0 0 = 128

    1 1 0 0 0 0 0 0 = 192

    1 1 1 0 0 0 0 0 = 224

    1 1 1 1 0 0 0 0 = 240

    1 1 1 1 1 0 0 0 = 248

    1 1 1 1 1 1 0 0 = 252

    1 1 1 1 1 1 1 0 = 254

    1 1 1 1 1 1 1 1 = 255

    128 64 32 16 8 4 2 1Weight:

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    Finding The Subnet Number

    172.16.2.160

    255.255.255.192

    10101100

    11111111

    10101100

    00010000

    11111111

    00010000

    11111111

    00000010

    10100000

    11000000

    10000000

    00000010

    16172 2 128Subnetnumber

    128

    192

    224

    240

    248

    252

    254

    255

    128

    192

    224

    240

    248

    252

    254

    255

    Network HostSubnet

    ANDresult

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    Finding The Subnet Broadcast Address

    172.16.2.160

    255.255.255.192

    10101100

    11111111

    10101100

    00010000

    11111111

    00010000

    11111111

    00000010

    10100000

    11000000

    10000000

    00000010

    16172 2 191

    Network HostSubnet

    ANDresult

    hostbitssetto1 10101100 00010000 00000010 10111111

    Broadcast

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    Finding The Valid Range of IP Addresses

    172.16.2.160

    255.255.255.192

    10101100

    11111111

    10101100

    00010000

    11111111

    00010000

    11111111

    00000010

    10100000

    11000000

    10000000

    00000010

    16172 2 129

    Network HostSubnet

    ANDresult

    Firstavailable 10101100 00010000 00000010 10000001

    Firstvalid

    Lastavailable 10101100 0001000000000010 10111110

    Lastvalid 16172 2 190

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    Address Calculating Summary

    10100100

    11111111

    10100100

    00010000

    11111111

    00010000

    11111111

    00000010

    01100000

    11000000

    01000000

    00000010

    10100100 00010000 00000010 01111111

    10100100 00010000 00000010 01000001

    10100100 00010000 00000010 01111110

    Host

    Mask

    Subnet

    Broadcast

    Last

    First

    164.16.2.96

    255.255.255.192

    164.16.2.64

    164.16.2.127

    164.16.2.65

    164.16.2.126

    16164 2 96

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    Which Subnet Masks Meet Requirement

    Subnetnumber

    Host numberper Subnet

    ClassSubnetmask

    200 200 B ?

    2N-2 2M-2 N+M=16 N=M=8

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    Address Class Network Host

    10.2.1.1

    128.63.2.100

    201.222.5.64

    192.6.141.2

    130.113.64.16

    256.241.201.10

    IP address Classification Exercise

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    Subnet Mask Exercise

    Address Subnet Mask Class Subnet

    172.16.2.10

    10.6.24.20

    10.30.36.12

    255.255.255.0

    255.255.240.0

    255.255.255.0

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    Broadcast Address Exercise

    Address Class Subnet Broadcast

    201.222.10.60 255.255.255.248

    Subnet Mask

    15.16.193.6 255.255.248.0

    128.16.32.13 255.255.255.252

    153.50.6.27 255.255.255.128

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    Contents

    IP address classification Subnet and IP address calculation

    VLSM

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    C

    172.16.14.32/27

    172.16.14.64/27

    172.16.14.96/27

    HQHQB

    A

    Derived from

    172.16.0.0/16

    Derived from

    172.16.14.0/24

    Derived from

    172.16.14.128/27

    C

    Variable Length Subnet Mask

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    Subnetted Address: 172.16.14.0/24In Binary 10101100. 00010000.00001110.00000000

    VLSM Address: 172.16.14.0/27

    In Binary 10101100. 00010000.00100000.0000000000100000010000000110000010000000

    172.16.14.32/27172.16.14.64/27172.16.14.96/27172.16.14.128/27

    VLSM Address: 172.16.14.128/27

    In Binary 10101100. 00010000.00100000.1000000000100010000110010000

    172.16.14.132/30172.16.14.136/30172.16.14.140/30

    VLSM Subnet

    VLSM Subnet

    VLSM Calculating

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    Summarization

    IP address classification Subnetting and calculation

    VLSM

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