00 box cv cum drop

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1 document.xls/Sheet1 Hydraulic Calculation of Box Culvert Canal Name: Chainage 2 Calculation of Head Loss Structure No. Type Box Single 1) Inlet transition Friction hif=Li(Iu+Ic)/2 = 0.00186705415 m 0.01408986379 m 0.2 2) Inlet (Sudden contraction) 0.56194557629 fsc 0.24235931644 hi = fsc hvc 0.03021323767 m 3) Culvert conduit Friction hf = LcIc = 0.00885843339 m 4) Outlet transition 1 Dimension and Hydraulic Conditions Friction hof=Lo(Ic+Id)/2 = 0.00186705415 m Conduit width Bc= 4.00 m Design Discharge Q= 10.75 m3/sec 0.02817972757 m Nos. of Conduit N = 1 nos Conduit length Lc = 16.00 m 96.00 m 0.4 2.08 m sub-total 0.05486213306 m Upstream Canal U/s Transition End Conduit Downstream Canal Qi=Q/N = 10.75 3 Inner height of conduit H = Hc/0.83 = 2.07144578313 Bottom Width Bu = 3.00 Be = 4.00 Bc = 4.00 Bd = 3.00 say 2.250 m Side Slope 1:m m= 1.5 m= 1.5 m= 0 m= 1.50 Design 2.500 m Water Depth Hu = 1.820 He = 1.8189 Hc = 1.7193 Hd= 1.820 Water Surface Width Wu = 8.46 We = 9.4567 Wc = 4.000 Wd = 8.46 3 Calculation of dimension of Drop structure Flow Area Au = 10.4286 Ae = 12.238195815 Ac = 6.8772 Ad= 10.4286 Velocity Vu = 1.03081909365 Ve = 0.87839745029 Vc = 1.56313616007 Vd= 1.03081909365 Notch to be provided ? Yes/No n Velocity Head hvu = 0.05421367366 hve = 0.03936643269 hvc = 0.1246629926 hvd= 0.05421367366 Energy Head Eu = 1.87421367366 Ee= 1.85826643269 Ec = 1.8439629926 Ed = 1.87421367366 Width of Opening (B = Bu) 4.00 Inlet loss in the transition (hi) ht = 0.01595691794 hi = 0.03021323767 Discharge per width q = Q/B 2.6875 dE = Eu - (Ei + hi) ok -9.676964E-06 ok 3.7443396E-05 ok Critical water depth hc = 0.90328255615 Wetted Perimeter P = B + 2H(m^2+1)^0.5Pu = 9.56210332134 Pe = 10.5581372149 Pc = 7.4386 Pd = 9.56210332134 Critical Velocity Vc = Q/(hc B) = 2.97525949294 Hydraulic Radius R = A/P Ru = 1.09061779083 Re = 1.15912452792 Rc = 0.92452880918 dd = 1.09061779083 Critical velocity head hvc = 0.45164127808 Roughness Coefficient n= 0.01428571429 n= 0.01428571429 n= 0.01428571429 n= 0.01428571429 Specific Energy H = hc + hvc = 1.35492383423 Roughness Coefficient K K= 70 K= 70 70 70 Hydraulic Gradient I =[n V/R ^(2/3)]^2Iu = 0.00019316958 Ie = 0.00012932404 Ic = 0.00055365209 Id = 0.00019316958 4.80 say 4.80 m 1.2 4.2837854 4.7822573 Transition Angle Notch heightning c = Hu + hvu -hvc-hc say 0.000 m Length of Transition say Li = 5.00 m say Lo = 5.00 m U/stream designed 5.00 m 5.00 m D/stream Vertical distance y = Z-hc/2-hvc = 1.18145277358 note: Vc shall be in between "Vu" and 3.0 m/sec. Horizontal distance x 2.12751496223 m 1.00371568183 At B.P. of Culvert At B.P.of Conduit Inlet At Drop Crest Velocity of water V = (2 g Z)^(1/2) 6.39224627677 m Energy Level (m) ELu = WLu + hvu = 100.054 ELi = ELu - hi = 100.038 ELo = ELi - hf = 100.029 ELc = WLc + hvc = 99.540 Thickness of the water fall dw=q/V 0.42043123554 m Water Level (m) WLu = ELu - hvu = 100.000 WLi = ELi - hvc = 99.914 WLo = ELo - hvc = 99.905 WLc= BLc + hc = 99.089 Floor Level (m) BLu = WLu - Hu= 98.180 BLi = WLi - Hc = 98.194 BLo = WLo - Hc = 98.185 BLc = BLu = 98.185 End sill height d 0.45164127808 say 0.500 m At Stilling Basin Notch Elevation = 98.185 Static head at the end of stilling basi 2.37 m Energy Level (m) 97.874 2.81480775457 m Water Level (m) WLb = BLb + Hn = 97.874 97.820 V max = 5.95379201215 m Floor Level (m) 95.500 96.000 Horizontal distance of water fall L 3.63955071808 m Stilling basin length Ls = 2.5 L 9.09887679521 say 9.500 m Static pessure P =1.0 Bo Hn^2 = 27.0570747274 M = 1.0 Q Vm/9.8 = 6.53094531945 P > 3M ? 7.46423876909 ok Box Culvert cum Drop Convergence hic =x in(hvc-hvu) = x in.= Ac/Ae Down stream Canal EL Divergence hod = x out(hvc-hvd) = x out.= Drop Height Z WLo-WLd= Stilling Basin width Bo = a x B = a: 1.2 inprinciple a = Transition = 1.92098 (Wu-Wc)/2 Lo = 2.14451 (Wc-Wd)/2 27 o 30' 25 o Inclimation of water fall a (radian) At E.P.of Conduit At B.P.of Down Stream Canal ELd = WLd + hvd = Penetration distance S = Hn/Sin a WLd = BLd+Hd= BLb = BLd - d = BLd = BLd (input above) if "No", change basin width a U pstream Canal InletTransition Li Conduit O utletTransition Lo D ow nstream Canal Hd Hc H Hu BLu BLi BLo BLd Lc W Ld W Lo W Li W Lu W Lu W Ld BLd Z Ls hD D ow nstream Canal Hc Hu Hd Stilling Basin c A pproch Canal La U pstream Canal S L x l' Transition Lt Hn HLb BLb BLu BLc W Lc

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Page 1: 00 Box CV cum Drop

1 document.xls/Sheet1

Hydraulic Calculation of Box Culvert

Canal Name: Chainage 2 Calculation of Head LossStructure No. Type Box Single

1) Inlet transitionFriction hif=Li(Iu+Ic)/2 = 0.00186705415 m

0.01408986379 m0.2

2) Inlet (Sudden contraction)0.56194557629

fsc 0.24235931644hi = fsc hvc 0.03021323767 m

3) Culvert conduitFriction hf = LcIc = 0.00885843339 m

4) Outlet transition1 Dimension and Hydraulic Conditions Friction hof=Lo(Ic+Id)/2 = 0.00186705415 m

Conduit width Bc= 4.00 m Design Discharge Q= 10.75 m3/sec 0.02817972757 mNos. of Conduit N = 1 nos Conduit length Lc = 16.00 m 96.00 m 0.4

2.08 m sub-total 0.05486213306 mUpstream Canal U/s Transition End Conduit Downstream Canal

Qi=Q/N = 10.75 3 Inner height of conduitH = Hc/0.83 = 2.07144578313

Bottom Width Bu = 3.00 Be = 4.00 Bc = 4.00 Bd = 3.00 say 2.250 mSide Slope 1:m m= 1.5 m= 1.5 m= 0 m= 1.50 Design 2.500 mWater Depth Hu = 1.820 He = 1.8189 Hc = 1.7193 Hd= 1.820 Water Surface Width Wu = 8.46 We = 9.4567 Wc = 4.000 Wd = 8.46 3 Calculation of dimension of Drop structureFlow Area Au = 10.4286 Ae = 12.238195815 Ac = 6.8772 Ad= 10.4286Velocity Vu = 1.03081909365 Ve = 0.87839745029 Vc = 1.56313616007 Vd= 1.03081909365 Notch to be provided ? Yes/No nVelocity Head hvu = 0.05421367366 hve = 0.03936643269 hvc = 0.1246629926 hvd= 0.05421367366Energy Head Eu = 1.87421367366 Ee= 1.85826643269 Ec = 1.8439629926 Ed = 1.87421367366 Width of Opening (B = Bu) 4.00Inlet loss in the transition (hi) ht = 0.01595691794 hi = 0.03021323767 Discharge per width q = Q/B 2.6875dE = Eu - (Ei + hi) ok -9.676964E-06 ok 3.7443396E-05 ok Critical water depth hc = 0.90328255615Wetted Perimeter P = B + 2H(m^2+1)^0.5 Pu = 9.56210332134 Pe = 10.5581372149 Pc = 7.4386 Pd = 9.56210332134 Critical Velocity Vc = Q/(hc B) = 2.97525949294Hydraulic Radius R = A/P Ru = 1.09061779083 Re = 1.15912452792 Rc = 0.92452880918 dd = 1.09061779083 Critical velocity head hvc = 0.45164127808Roughness Coefficient n= 0.01428571429 n= 0.01428571429 n= 0.01428571429 n= 0.01428571429 Specific Energy H = hc + hvc = 1.35492383423

Roughness Coefficient K K= 70 K= 70 70 70Hydraulic Gradient I =[n V/R ^(2/3)]^2 Iu = 0.00019316958 Ie = 0.00012932404 Ic = 0.00055365209 Id = 0.00019316958 4.80 say 4.80 m

1.24.2837854 4.7822573 Transition Angle Notch heightning c = Hu + hvu -hvc-hc say 0.000 m

Length of Transition say Li = 5.00 m say Lo = 5.00 m U/stream

designed 5.00 m 5.00 m D/stream Vertical distance y = Z-hc/2-hvc = 1.18145277358note: Vc shall be in between "Vu" and 3.0 m/sec. Horizontal distance x 2.12751496223 m

1.00371568183At B.P. of Culvert At B.P.of Conduit Inlet At Drop Crest Velocity of water V = (2 g Z)^(1/2) 6.39224627677 m

Energy Level (m) ELu = WLu + hvu = 100.054 ELi = ELu - hi = 100.038 ELo = ELi - hf = 100.029 ELc = WLc + hvc = 99.540 Thickness of the water fall dw=q/V 0.42043123554 mWater Level (m) WLu = ELu - hvu = 100.000 WLi = ELi - hvc = 99.914 WLo = ELo - hvc = 99.905 WLc= BLc + hc = 99.089Floor Level (m) BLu = WLu - Hu= 98.180 BLi = WLi - Hc = 98.194 BLo = WLo - Hc = 98.185 BLc = BLu = 98.185 End sill height d 0.45164127808 say 0.500 m

At Stilling Basin Notch Elevation = 98.185 Static head at the end of stilling basin Hn = 2.37 mEnergy Level (m) 97.874 2.81480775457 mWater Level (m) WLb = BLb + Hn = 97.874 97.820 V max = 5.95379201215 mFloor Level (m) 95.500 96.000

Horizontal distance of water fall L 3.63955071808 mStilling basin length Ls = 2.5 L 9.09887679521 say 9.500 m

Static pessure P =1.0 Bo Hn^2 = 27.0570747274M = 1.0 Q Vm/9.8 = 6.53094531945P > 3M ? 7.46423876909 ok

Box Culvert cum Drop

Convergence hic =x in(hvc-hvu) =x in.=

Ac/Ae

Down stream Canal EL Divergence hod = x out(hvc-hvd) =x out.=

Drop Height Z WLo-WLd=

Stilling Basin width Bo = a x B =a: 1.2 inprinciple a =

Transition = 1.92098 (Wu-Wc)/2 Lo = 2.14451 (Wc-Wd)/2

27o30'

25o

Inclimation of water fall a (radian)At E.P.of Conduit

At B.P.of Down Stream CanalELd = WLd + hvd = Penetration distance S = Hn/Sin aWLd = BLd+Hd=

BLb = BLd - d = BLd = BLd (input above)

if "No", change basin width a

UpstreamCanal

Inlet TransitionLi

Conduit Outlet Transition

LoDownstreamCanal

HdHcH

Hu

BLu

BLi BLoBLd

Lc

WLdWLoWLi

WLu

WLu

WLd

BLd

Z

Ls

hD

Downstream Canal

HcHu

Hd

Stilling Basin

c

Approch Canal

La

Upstream Canal

S

L

x l'

Transition

Lt

Hn

HLb

BLb

BLu BLc

WLc