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C3 Jan 2007 P2 January 2002 The function f is defined by f : x 2x a, x ℝ, where a is a positive constant. (a) Sketch the graph of y = f(x), showing the coordinates of the points where the graph cuts the axes. (2) (b) On a separate diagram, sketch the graph of y = f(2x), showing the coordinates of the points where the graph cuts the axes. (2) (c) Given that a solution of the equation f(x) = 1 2 x is x = 4, find the two possible values of a. (4) P2 January 2003 (a)Sketch the graph of y = 2x + a, a > 0, showing the coordinates of the points where the graph meets the coordinate axes. (2) (b) On the same axes, sketch the graph of y = 1 x . (1) (c)Explain how your graphs show that there is only one solution of the equation x2x + a 1 = 0. (1) (d) Find, using algebra, the value of x for which x2x + 1 1 = 0. (3) N23583A 1 Turn over

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Page 1: gmaths28.files.wordpress.com€¦  · Web view), showing the coordinates of the points where the graph cuts the axes

C3 Jan 2007

P2 January 2002The function f is defined by

f : x 2x – a, x ℝ,

where a is a positive constant.

(a) Sketch the graph of y = f(x), showing the coordinates of the points where the graph cuts the axes.

(2)(b) On a separate diagram, sketch the graph of y = f(2x), showing the coordinates of the points where the graph cuts the axes.

(2)

(c) Given that a solution of the equation f(x) = 12 x is x = 4, find the two possible values of a.

(4)

P2 January 2003(a) Sketch the graph of y = 2x + a, a > 0, showing the coordinates of the points where the

graph meets the coordinate axes. (2)

(b) On the same axes, sketch the graph of y =

1x .

(1)

(c) Explain how your graphs show that there is only one solution of the equation

x2x + a 1 = 0.(1)

(d) Find, using algebra, the value of x for which x2x + 1 1 = 0.(3)

N23583A 1 Turn over

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C3 Jan 2007

P2 January 2003Figure 3

y

(0, c)

O (d, 0) x

Figure 3 shows a sketch of the curve with equation y = f(x), x 0. The curve meets the coordinate axes at the points (0, c) and (d, 0).

In separate diagrams sketch the curve with equation

(a) y = f1(x), (2)

(b) y = 3f(2x).(3)

Indicate clearly on each sketch the coordinates, in terms of c or d, of any point where the curve meets the coordinate axes.

N23583A 2 Turn over

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C3 Jan 2007

P2 June 2003Figure 1

y

B(43 , 1)

1 O A(2, 0) 3 x

Figure 1 shows a sketch of the curve with equation y = f(x), 1 x 3. The curve touches the x-axis at the origin O, crosses the x-axis at the point A(2, 0) and has a maximum at the

point B(43 , 1).

In separate diagrams, show a sketch of the curve with equation

(a) y = f(x + 1), (3)

(b) y = f(x), (3)

(c) y = f(x), (4)

marking on each sketch the coordinates of points at which the curve

(i) has a turning point,

(ii) meets the x-axis.

N23583A 3 Turn over

Page 4: gmaths28.files.wordpress.com€¦  · Web view), showing the coordinates of the points where the graph cuts the axes

C3 Jan 2007

P2 January 2005Figure 1

Figure 1 shows a sketch of the curve with equation y = f(x), 0 x 4. The curve passes through the point (1, 0) on the x-axis and meets the y-axis at the point (0, –2).

Sketch, on separate axes, the graph of

(a) y =f(x),(2)

(b) y = f(2x),(2)

(c) y = f–1(x),(3)

in each case showing the coordinates of the points at which the graph meets the axes.

N23583A 4 Turn over

(4, 0) (1, 0) x

(0, –2)

O

y

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C3 Jan 2007

P2 June 2005Figure 1

Figure 1 shows part of the graph of y = f(x), x ℝ. The graph consists of two line segments that meet at the point (1, a), a < 0. One line meets the x-axis at (3, 0). The other line meets the x-axis at (–1, 0) and the y-axis at (0, b), b < 0.

In separate diagrams, sketch the graph with equation

(a) y = f(x + 1), (2)

(b) y = f(x).(3)

Indicate clearly on each sketch the coordinates of any points of intersection with the axes.

Given that f(x) = x – 1 – 2, find

(c) the value of a and the value of b,(2)

(d) the value of x for which f(x) = 5x.(4)

N23583A 5 Turn over

b

(1, a)

3 –1 x

y

O

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C3 Jan 2007

P2 January 2006Figure 1

Figure 1 shows the graph of y = f(x), –5 x 5.

The point M (2, 4) is the maximum turning point of the graph.

Sketch, on separate diagrams, the graphs of

(a) y = f(x) + 3,(2)

(b) y = f(x),(2)

(c) y = f(x).(3)

Show on each graph the coordinates of any maximum turning points.

N23583A 6 Turn over

–5

M (2, 4)

O 5 x

y

Page 7: gmaths28.files.wordpress.com€¦  · Web view), showing the coordinates of the points where the graph cuts the axes

C3 Jan 2007

C3 June 2005Figure 1

Figure 1 shows part of the graph of y = f(x), x ℝ. The graph consists of two line segments that meet at the point (1, a), a < 0. One line meets the x-axis at (3, 0). The other line meets the x-axis at (–1, 0) and the y-axis at (0, b), b < 0.

In separate diagrams, sketch the graph with equation(a)y = f(x + 1),

(2)(b)y = f(x).

(3)

Indicate clearly on each sketch the coordinates of any points of intersection with the axes.

Given that f(x) = x – 1 – 2, find(c) the value of a and the value of b,

(2)(d) the value of x for which f(x) = 5x

(4)

N23583A 7 Turn over

b

(1, a)

3 –1 x

y

O

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C3 Jan 2007

C3 January 2006

Figure 1

Figure 1 shows the graph of y = f(x), –5 x 5.The point M (2, 4) is the maximum turning point of the graph.Sketch, on separate diagrams, the graphs of

(a) y = f(x) + 3,(2)

(b) y = f(x),(2)

(c) y = f(x).(3)

Show on each graph the coordinates of any maximum turning points.

N23583A 8 Turn over

–5

M (2, 4)

O 5 x

y

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C3 Jan 2007

C3 June 2006Figure 1

Figure 1 shows part of the curve with equation y = f(x), x ℝ, where f is an increasing function of x. The curve passes through the points P(0, –2) and Q(3, 0) as shown.

In separate diagrams, sketch the curve with equation

(a) y = f(x),(3)

(b) y = f–1(x),(3)

(c) y = 12 f(3x).

(3)

Indicate clearly on each sketch the coordinates of the points at which the curve crosses or meets the axes.

N23583A 9 Turn over

(3, 0)

P(0, –2)

O

y

x

y = f(x)

Q

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C3 Jan 2007

C3 January 2007f(x) = x4 – 4x – 8.

(d) Sketch the graph of y = f(x).(3)

(e) Hence sketch the graph of y = f(x).(1)

C3 January 2008

Figure 1

Figure 1 shows a sketch of the curve with equation y = f (x).

The curve passes through the origin O and the points A(5, 4) and B(–5, –4).

In separate diagrams, sketch the graph with equation

(a) y =f (x),(3)

(b) y = f (x) ,(3)

(c) y = 2f(x + 1) .(4)

On each sketch, show the coordinates of the points corresponding to A and B.

N23583A 10 Turn over

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C3 Jan 2007

C3 June 2008

Figure 1

Figure 1 shows the graph of y = f(x), x ℝ,

The graph consists of two line segments that meet at the point P.

The graph cuts the y-axis at the point Q and the x-axis at the points (–3, 0) and R.

Sketch, on separate diagrams, the graphs of

(a) y = f(x),(2)

(b) y = f (– x).(2)

Given that f(x) = 2 – x + 1,

(c) find the coordinates of the points P, Q and R,(3)

(d) solve f(x) = 12 x.

(5)

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C3 Jan 2007

C3 January 2009

Figure 1

Figure 1 shows the graph of y = f (x), 1 < x < 9.

The points T(3, 5) and S(7, 2) are turning points on the graph.

Sketch, on separate diagrams, the graphs of

(a) y = 2f(x) – 4,(3)

(b) y = f(x).(3)

Indicate on each diagram the coordinates of any turning points on your sketch.

N23583A 12 Turn over

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C3 Jan 2007

C3 June 2009

Figure 2

Figure 2 shows a sketch of part of the curve with equation y = f(x), x ℝ.

The curve meets the coordinate axes at the points A(0, 1 – k) and B(12 ln k, 0), where k is a

constant and k >1, as shown in Figure 2.

On separate diagrams, sketch the curve with equation

(a) y = f(x), (3)

(b) y = f −1(x).(2)

Show on each sketch the coordinates, in terms of k, of each point at which the curve meets or cuts the axes.

N23583A 13 Turn over

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C3 Jan 2007

C3 January 2010

Figure 1

Figure 1 shows a sketch of the graph of y = f (x).

The graph intersects the y-axis at the point (0, 1) and the point A(2, 3) is the maximum turning point.

Sketch, on separate axes, the graphs of

(i) y = f(–x) + 1,

(ii) y = f(x + 2) + 3,

(iii) y = 2f(2x) .

On each sketch, show the coordinates of the point at which your graph intersects the y-axis and the coordinates of the point to which A is transformed.

(9)

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C3 Jan 2007

C3 June 2010

Figure 2

Figure 2 shows a sketch of the curve with the equation y = f(x), x ℝ.

The curve has a turning point at A(3, − 4) and also passes through the point (0, 5).

(a) Write down the coordinates of the point to which A is transformed on the curve with equation

(i) y = |f(x)|,

(ii) y = 2f(12 x).

(4)(b) Sketch the curve with equation y = f(|x|).

On your sketch show the coordinates of all turning points and the coordinates of the point at which the curve cuts the y-axis.

(3)

The curve with equation y = f(x) is a translation of the curve with equation y = x2.

(c) Find f(x).(2)

(d) Explain why the function f does not have an inverse.(1)

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C3 Jan 2007

C3 June 2011

Figure 1

Figure 1 shows part of the graph of y = f (x), x ℝ.

The graph consists of two line segments that meet at the point R (4, – 3), as shown in Figure 1.

Sketch, on separate diagrams, the graphs of

(a) y = 2f(x + 4),(3)

(b) y = f(−x) .(3)

On each diagram, show the coordinates of the point corresponding to R.

N23583A 16 Turn over

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C3 Jan 2007

C3 January 2012

Figure 1

Figure 1 shows the graph of equation y = f(x).

The points P (– 3, 0) and Q (2, – 4) are stationary points on the graph.

Sketch, on separate diagrams, the graphs of

(a) y = 3f(x + 2),(3)

(b) y = f(x).(3)

On each diagram, show the coordinates of any stationary points.

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C3 Jan 2007

C3 June 2012

Figure 2

Figure 2 shows part of the curve with equation y = f(x).The curve passes through the points P(−1.5, 0)and Q(0, 5) as shown.

On separate diagrams, sketch the curve with equation

(a) y = f(x)(2)

(b) y = f(x)(2)

(c) y = 2f(3x)(3)

Indicate clearly on each sketch the coordinates of the points at which the curve crosses or meets the axes.

N23583A 18 Turn over

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C3 Jan 2007

C3 January 2013

Figure 1

Figure 1 shows part of the curve with equation y = f(x) , x ℝ.

The curve passes through the points Q(0, 2) and P(−3, 0) as shown.

On separate diagrams, sketch the curve with equation

(b) y = f −1(x),(2)

(c) y = f(x) − 2,(2)

(d) y = 2f(12 x ) .

(3)

Indicate clearly on each sketch the coordinates of the points at which the curve crosses or meets the axes.

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C3 Jan 2007

ANSWERS

C3 June 2005

(c) a = –2, b = –1 (d) x = –

16

C3 January 2006 N/A

C3 June 2006N/A

C3 January 2007N/A

C3 January 2008(a) (5, 4), (–5, 4) (b) (5, 4), (–5, 4) (c) (4, 8), (–6, –8)

C3 June 2008(c) P(–1, 2), Q (0, 1), R(1, 0) (d)

C3 January 2009N/A

C3 June 2009N/A

C3 January 2010N/A

C3 June 2010(a) (i) (3, 4) (ii) (6, –8) (c) f(x) = (x – 3)2 – 4

C3 June 2011(a) R = (0, –6) (b) R = (–4, 3)

C3 January 2012(a) (–5, 0), (0, –12) (b) (–3, 0), (2, 4)

C3 June 2012(a) (–1.5, 0) and (0, 5) (b) (0, 5) (c) (0, 10) and (–0.5, 0)

N23583A 20 Turn over