· section 3.6 dx dx = 4 — = (4 — = 16 — 8 x = — ... 2x — = y' (2x — — (y5 +...
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- · Section 3.6 dx dx = 4 — = (4 — = 16 — 8 x = — ... 2x — = y' (2x — — (y5 + x2Y3) = 10. dx y/ (5y4 + 3x2y2 _ 2x — 3y2) y' = 2x — 3y2 dx 4) = 4x3y — 2xy3 x 4x3y
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Post on 06-Aug-2019
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