Year 10 Exam Revision 3

1. Calculate the size the missing sides…

4. Find the one hundredth and twenty fifth number in the sequence…

73, 76, 79, 82…

82o

x

153cm

1.2m 83m

x

2. What is the sum of the squares of the first three prime numbers?

3. Find the mean, median, mode, range, upper and lower quartiles for

Range Midpoint Tally Frequency

20 < x < 30 25 | | | | | |

30 < x < 40 35 | | | |

40 < x < 50 45 | | | |

50 < x < 60 55 | |

5. Expand and simplify…a) 8(e + 3) – 5(e – 2) =b) (2e + 1)(e + 7) =

c) (e + 3)2 =

6. Increase 1200 by 45%.

7. Calculate the value of the missing angles and give the geometric reason…

135o

62o

a b

c

d

a = ___ because

b = ___ because

c = ___ because

d = ___ because

a2+b2=c2

2=a2+b2

120

x2=1202+1532

x2=37809x=194cm(0dp)

so

h ca

h to

a

hax=cos82x83x=11.6(1dp)

22+32+52 = 38

7

4

5

2

total 18

650/18=36(0dp) 35 25 55-25=30

uq25 uq=45

jumps times x plus zero #

3 3 370 3 times 125 plus 70

= 445

3e + 342e2 + 15e + 7

(e+3)(e+3) =e2+3e+3e+9=e2+6e+9

old x (1±%) = new1200 x (1+0.45)=1740

45 adjacent <‘s on a st line+ 180

62 vertically opp <‘s are +

73 internal <‘s in triangle + 180

287 <‘s at a point + 360

Year 10 Exam Revision 3

8. Marie left at 0750 hours and drove her car 430km. She finished her journey at 1420 hours. What was her average speed?

12. Calculate the answers to these problems…

a) (14 – 3)2 + 7 = b) 5 + 25 + 13 = 10

c) 45 ÷ 23 =

45mstart

10. What percentage change is there from going from 80 up to 96?

9. Simplify the following…a) 6ef + 5e – ef + 12e =

b) (5e2)2 = c) 125e4f5 =

150e6f4

11. Find the area and perimeter of the following shapes…

33m29m

17m

16m

13. In a pack of lollies there are 5 red lollies and 4 green lollies. If two are chosen at random what is the probability that both the lollies will be same colour.

red

green

red

green

red

green

/9

/8

sd

tspeed = 430 ÷ 6.5 = 66.2 km/hour (1dp)

5ef + 17e

25e4 5f

6e2

(new-old)÷oldx100=%change(96-80)÷80x100=20%

area(Δ)=1/2base x height

a=0.5 x 45 x 17 = 382.5m2

Perimeter = 29 + 33 + 45

Perimeter = 107m

P(О)=π x diameterP(О)=π x 16P(О)=50.3m (1dp)

area(О)=π x radius2

area(О)=π x 82

area(О)=201m2 (0dp)

112 + 7 = 121 + 7 = 12830/10 + 13 = 3 + 13 = 16

1024/8 = 128

5

4/9

4

4/8

5/8 3/8

5/9x4/8= 5/18

5/9x4/8= 5/18

4/9x5/8= 5/18

4/9x3/8= 3/18 same colour is 5/18 + 3/18 = 8/18 = 4/9

Year 10 Exam Revision 3

21. Calculate the missing side…

24. What is the date 100 days after June 18th?

area = 720m2

a

90m

22. Complete the table below…

Mixed number

Decimal Improper Fraction

3 1/5

1.9

20/7

23. Share $7500 into the ratio of 3 : 22

25. Factorise the following…

a) 50e3 + 55efg =

b) e2 + 16e + 60 =

c) e2 + e – 6 =

26. Calculate the size of the missing angle

125cm

18cmx

27. Complete the prime factor trees…

140

10

2

48

area(Δ) = 0.5xbasexheight720 = 0.5x90xa

a = 720 ÷ (0.5x90)a = 16m

3.2 16/5

19/101 9/10

2.571…2 6/7

7500 ÷ (3+22) = 300 $900:$6600

18/6 30/6 31/7 30/8

12d 31d 30d 27d27th of Sept

5e( )10e2 + 11fg (e )(e )+ 10 + 6

(e )(e )– 2 + 3