year 10 end of year exam revision 3
TRANSCRIPT
Year 10 Exam Revision 3
1. Calculate the size the missing sides…
4. Find the one hundredth and twenty fifth number in the sequence…
73, 76, 79, 82…
82o
x
153cm
1.2m 83m
x
2. What is the sum of the squares of the first three prime numbers?
3. Find the mean, median, mode, range, upper and lower quartiles for
Range Midpoint Tally Frequency
20 < x < 30 25 | | | | | |
30 < x < 40 35 | | | |
40 < x < 50 45 | | | |
50 < x < 60 55 | |
5. Expand and simplify…a) 8(e + 3) – 5(e – 2) =b) (2e + 1)(e + 7) =
c) (e + 3)2 =
6. Increase 1200 by 45%.
7. Calculate the value of the missing angles and give the geometric reason…
135o
62o
a b
c
d
a = ___ because
b = ___ because
c = ___ because
d = ___ because
a2+b2=c2
2=a2+b2
120
x2=1202+1532
x2=37809x=194cm(0dp)
so
h ca
h to
a
hax=cos82x83x=11.6(1dp)
22+32+52 = 38
7
4
5
2
total 18
650/18=36(0dp) 35 25 55-25=30
uq25 uq=45
jumps times x plus zero #
3 3 370 3 times 125 plus 70
= 445
3e + 342e2 + 15e + 7
(e+3)(e+3) =e2+3e+3e+9=e2+6e+9
old x (1±%) = new1200 x (1+0.45)=1740
45 adjacent <‘s on a st line+ 180
62 vertically opp <‘s are +
73 internal <‘s in triangle + 180
287 <‘s at a point + 360
Year 10 Exam Revision 3
8. Marie left at 0750 hours and drove her car 430km. She finished her journey at 1420 hours. What was her average speed?
12. Calculate the answers to these problems…
a) (14 – 3)2 + 7 = b) 5 + 25 + 13 = 10
c) 45 ÷ 23 =
45mstart
10. What percentage change is there from going from 80 up to 96?
9. Simplify the following…a) 6ef + 5e – ef + 12e =
b) (5e2)2 = c) 125e4f5 =
150e6f4
11. Find the area and perimeter of the following shapes…
33m29m
17m
16m
13. In a pack of lollies there are 5 red lollies and 4 green lollies. If two are chosen at random what is the probability that both the lollies will be same colour.
red
green
red
green
red
green
/9
/8
sd
tspeed = 430 ÷ 6.5 = 66.2 km/hour (1dp)
5ef + 17e
25e4 5f
6e2
(new-old)÷oldx100=%change(96-80)÷80x100=20%
area(Δ)=1/2base x height
a=0.5 x 45 x 17 = 382.5m2
Perimeter = 29 + 33 + 45
Perimeter = 107m
P(О)=π x diameterP(О)=π x 16P(О)=50.3m (1dp)
area(О)=π x radius2
area(О)=π x 82
area(О)=201m2 (0dp)
112 + 7 = 121 + 7 = 12830/10 + 13 = 3 + 13 = 16
1024/8 = 128
5
4/9
4
4/8
5/8 3/8
5/9x4/8= 5/18
5/9x4/8= 5/18
4/9x5/8= 5/18
4/9x3/8= 3/18 same colour is 5/18 + 3/18 = 8/18 = 4/9
Year 10 Exam Revision 3
21. Calculate the missing side…
24. What is the date 100 days after June 18th?
area = 720m2
a
90m
22. Complete the table below…
Mixed number
Decimal Improper Fraction
3 1/5
1.9
20/7
23. Share $7500 into the ratio of 3 : 22
25. Factorise the following…
a) 50e3 + 55efg =
b) e2 + 16e + 60 =
c) e2 + e – 6 =
26. Calculate the size of the missing angle
125cm
18cmx
27. Complete the prime factor trees…
140
10
2
48
area(Δ) = 0.5xbasexheight720 = 0.5x90xa
a = 720 ÷ (0.5x90)a = 16m
3.2 16/5
19/101 9/10
2.571…2 6/7
7500 ÷ (3+22) = 300 $900:$6600
18/6 30/6 31/7 30/8
12d 31d 30d 27d27th of Sept
5e( )10e2 + 11fg (e )(e )+ 10 + 6
(e )(e )– 2 + 3