what do molecules look like?

114
What Do Molecules Look Like? Recall that we have two types of electron pairs: bonding and lone. The Lewis Dot Structure approach provides some insight into molecular structure in terms of bonding, but what about 3D geometry? Valence-Shell Electron-Pair Repulsion (VSEPR). 3D structure is determined by minimizing repulsion of electron pairs.

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What Do Molecules Look Like?. The Lewis Dot Structure approach provides some insight into molecular structure in terms of bonding, but what about 3D geometry?. Recall that we have two types of electron pairs: bonding and lone. - PowerPoint PPT Presentation

TRANSCRIPT

Page 1: What Do Molecules Look Like?

What Do Molecules Look Like

Recall that we have two types of electron pairs bonding and lone

The Lewis Dot Structure approach provides some insight into molecular structure in terms of bonding but what about 3D geometry

Valence-Shell Electron-Pair Repulsion (VSEPR) 3D structure is determined by minimizing repulsion of electron pairs

Electron pairs (both bonding and lone) are distributed around a central atom such that electron-electron repulsions are minimized

2 electron pairs

3 electron pairs

4 electron pairs

5 electron pairs

6 electron pairs

Period 1 2

Period 3 amp beyond

Electron pairs (both bonding and lone) are distributed around a central atom such that electron-electron repulsions are minimized

Arranging Electron Pairs

bull Example CH4 (bonding pairs only)

bull Must consider both bonding and lone pairs when minimizing repulsion

Lewis Structure VSEPR Structure

H CH

HH

Arranging Electron Pairs (cont)

Example NH3 (both bonding and lone pairs)

Lewis Structure VSEPR Structure

Noteldquoelectron pair geometryrdquo vsldquomolecular shaperdquo

H NH

H

VSEPR Structure GuidelinesThe previous examples illustrate the strategy for applying VSEPR to predict molecular structure

1 Construct the Lewis Dot Structure2 Arrange bondinglone electron pairs in space such

that repulsions are minimized (electron pair geometry)

3 Name the molecular shape from the position of the atoms

VSEPR Shorthand

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

ExamplesCH4 AX4NH3 AX3EH2O AX2E2BF3 AX3

VSEPR 2 electron pairsLinear (AX2) angle between bonds is 180deg

Example BeF2

180deg

Experiments show that molecules with multiple bonds can also be linear

Multiple bonds are treated as a single effective electron groupF Be F

F Be F

More than one central atom Determine shape around each

Be FF

VSEPR 3 electron pairsTrigonal Planar (AX3) angle between bonds is 120degExample BF3

Multiple bond is treated as a single effective electron group

FBFF

B

FF

F

120deg

VSEPR 4 electron pairs (cont)

Tetrahedral (AX4) angle between bonds is ~1095degExample CH4

1095degH C

HH

H

tetrahedral e- pair geometry AND tetrahedral molecular shape

Bonding vs Lone pairsBond angle in a tetrahedral arrangement of electron pairs may vary from 1095deg due to size differences between bonding and lone pair electron densities

bonding pair is constrained by two nuclear potentials more localized in space

lone pair is constrained by only one nuclear potential less localized (needs more room)

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 2: What Do Molecules Look Like?

Electron pairs (both bonding and lone) are distributed around a central atom such that electron-electron repulsions are minimized

2 electron pairs

3 electron pairs

4 electron pairs

5 electron pairs

6 electron pairs

Period 1 2

Period 3 amp beyond

Electron pairs (both bonding and lone) are distributed around a central atom such that electron-electron repulsions are minimized

Arranging Electron Pairs

bull Example CH4 (bonding pairs only)

bull Must consider both bonding and lone pairs when minimizing repulsion

Lewis Structure VSEPR Structure

H CH

HH

Arranging Electron Pairs (cont)

Example NH3 (both bonding and lone pairs)

Lewis Structure VSEPR Structure

Noteldquoelectron pair geometryrdquo vsldquomolecular shaperdquo

H NH

H

VSEPR Structure GuidelinesThe previous examples illustrate the strategy for applying VSEPR to predict molecular structure

1 Construct the Lewis Dot Structure2 Arrange bondinglone electron pairs in space such

that repulsions are minimized (electron pair geometry)

3 Name the molecular shape from the position of the atoms

VSEPR Shorthand

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

ExamplesCH4 AX4NH3 AX3EH2O AX2E2BF3 AX3

VSEPR 2 electron pairsLinear (AX2) angle between bonds is 180deg

Example BeF2

180deg

Experiments show that molecules with multiple bonds can also be linear

Multiple bonds are treated as a single effective electron groupF Be F

F Be F

More than one central atom Determine shape around each

Be FF

VSEPR 3 electron pairsTrigonal Planar (AX3) angle between bonds is 120degExample BF3

Multiple bond is treated as a single effective electron group

FBFF

B

FF

F

120deg

VSEPR 4 electron pairs (cont)

Tetrahedral (AX4) angle between bonds is ~1095degExample CH4

1095degH C

HH

H

tetrahedral e- pair geometry AND tetrahedral molecular shape

Bonding vs Lone pairsBond angle in a tetrahedral arrangement of electron pairs may vary from 1095deg due to size differences between bonding and lone pair electron densities

bonding pair is constrained by two nuclear potentials more localized in space

lone pair is constrained by only one nuclear potential less localized (needs more room)

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 3: What Do Molecules Look Like?

2 electron pairs

3 electron pairs

4 electron pairs

5 electron pairs

6 electron pairs

Period 1 2

Period 3 amp beyond

Electron pairs (both bonding and lone) are distributed around a central atom such that electron-electron repulsions are minimized

Arranging Electron Pairs

bull Example CH4 (bonding pairs only)

bull Must consider both bonding and lone pairs when minimizing repulsion

Lewis Structure VSEPR Structure

H CH

HH

Arranging Electron Pairs (cont)

Example NH3 (both bonding and lone pairs)

Lewis Structure VSEPR Structure

Noteldquoelectron pair geometryrdquo vsldquomolecular shaperdquo

H NH

H

VSEPR Structure GuidelinesThe previous examples illustrate the strategy for applying VSEPR to predict molecular structure

1 Construct the Lewis Dot Structure2 Arrange bondinglone electron pairs in space such

that repulsions are minimized (electron pair geometry)

3 Name the molecular shape from the position of the atoms

VSEPR Shorthand

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

ExamplesCH4 AX4NH3 AX3EH2O AX2E2BF3 AX3

VSEPR 2 electron pairsLinear (AX2) angle between bonds is 180deg

Example BeF2

180deg

Experiments show that molecules with multiple bonds can also be linear

Multiple bonds are treated as a single effective electron groupF Be F

F Be F

More than one central atom Determine shape around each

Be FF

VSEPR 3 electron pairsTrigonal Planar (AX3) angle between bonds is 120degExample BF3

Multiple bond is treated as a single effective electron group

FBFF

B

FF

F

120deg

VSEPR 4 electron pairs (cont)

Tetrahedral (AX4) angle between bonds is ~1095degExample CH4

1095degH C

HH

H

tetrahedral e- pair geometry AND tetrahedral molecular shape

Bonding vs Lone pairsBond angle in a tetrahedral arrangement of electron pairs may vary from 1095deg due to size differences between bonding and lone pair electron densities

bonding pair is constrained by two nuclear potentials more localized in space

lone pair is constrained by only one nuclear potential less localized (needs more room)

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 4: What Do Molecules Look Like?

Arranging Electron Pairs

bull Example CH4 (bonding pairs only)

bull Must consider both bonding and lone pairs when minimizing repulsion

Lewis Structure VSEPR Structure

H CH

HH

Arranging Electron Pairs (cont)

Example NH3 (both bonding and lone pairs)

Lewis Structure VSEPR Structure

Noteldquoelectron pair geometryrdquo vsldquomolecular shaperdquo

H NH

H

VSEPR Structure GuidelinesThe previous examples illustrate the strategy for applying VSEPR to predict molecular structure

1 Construct the Lewis Dot Structure2 Arrange bondinglone electron pairs in space such

that repulsions are minimized (electron pair geometry)

3 Name the molecular shape from the position of the atoms

VSEPR Shorthand

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

ExamplesCH4 AX4NH3 AX3EH2O AX2E2BF3 AX3

VSEPR 2 electron pairsLinear (AX2) angle between bonds is 180deg

Example BeF2

180deg

Experiments show that molecules with multiple bonds can also be linear

Multiple bonds are treated as a single effective electron groupF Be F

F Be F

More than one central atom Determine shape around each

Be FF

VSEPR 3 electron pairsTrigonal Planar (AX3) angle between bonds is 120degExample BF3

Multiple bond is treated as a single effective electron group

FBFF

B

FF

F

120deg

VSEPR 4 electron pairs (cont)

Tetrahedral (AX4) angle between bonds is ~1095degExample CH4

1095degH C

HH

H

tetrahedral e- pair geometry AND tetrahedral molecular shape

Bonding vs Lone pairsBond angle in a tetrahedral arrangement of electron pairs may vary from 1095deg due to size differences between bonding and lone pair electron densities

bonding pair is constrained by two nuclear potentials more localized in space

lone pair is constrained by only one nuclear potential less localized (needs more room)

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 5: What Do Molecules Look Like?

Arranging Electron Pairs (cont)

Example NH3 (both bonding and lone pairs)

Lewis Structure VSEPR Structure

Noteldquoelectron pair geometryrdquo vsldquomolecular shaperdquo

H NH

H

VSEPR Structure GuidelinesThe previous examples illustrate the strategy for applying VSEPR to predict molecular structure

1 Construct the Lewis Dot Structure2 Arrange bondinglone electron pairs in space such

that repulsions are minimized (electron pair geometry)

3 Name the molecular shape from the position of the atoms

VSEPR Shorthand

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

ExamplesCH4 AX4NH3 AX3EH2O AX2E2BF3 AX3

VSEPR 2 electron pairsLinear (AX2) angle between bonds is 180deg

Example BeF2

180deg

Experiments show that molecules with multiple bonds can also be linear

Multiple bonds are treated as a single effective electron groupF Be F

F Be F

More than one central atom Determine shape around each

Be FF

VSEPR 3 electron pairsTrigonal Planar (AX3) angle between bonds is 120degExample BF3

Multiple bond is treated as a single effective electron group

FBFF

B

FF

F

120deg

VSEPR 4 electron pairs (cont)

Tetrahedral (AX4) angle between bonds is ~1095degExample CH4

1095degH C

HH

H

tetrahedral e- pair geometry AND tetrahedral molecular shape

Bonding vs Lone pairsBond angle in a tetrahedral arrangement of electron pairs may vary from 1095deg due to size differences between bonding and lone pair electron densities

bonding pair is constrained by two nuclear potentials more localized in space

lone pair is constrained by only one nuclear potential less localized (needs more room)

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 6: What Do Molecules Look Like?

VSEPR Structure GuidelinesThe previous examples illustrate the strategy for applying VSEPR to predict molecular structure

1 Construct the Lewis Dot Structure2 Arrange bondinglone electron pairs in space such

that repulsions are minimized (electron pair geometry)

3 Name the molecular shape from the position of the atoms

VSEPR Shorthand

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

ExamplesCH4 AX4NH3 AX3EH2O AX2E2BF3 AX3

VSEPR 2 electron pairsLinear (AX2) angle between bonds is 180deg

Example BeF2

180deg

Experiments show that molecules with multiple bonds can also be linear

Multiple bonds are treated as a single effective electron groupF Be F

F Be F

More than one central atom Determine shape around each

Be FF

VSEPR 3 electron pairsTrigonal Planar (AX3) angle between bonds is 120degExample BF3

Multiple bond is treated as a single effective electron group

FBFF

B

FF

F

120deg

VSEPR 4 electron pairs (cont)

Tetrahedral (AX4) angle between bonds is ~1095degExample CH4

1095degH C

HH

H

tetrahedral e- pair geometry AND tetrahedral molecular shape

Bonding vs Lone pairsBond angle in a tetrahedral arrangement of electron pairs may vary from 1095deg due to size differences between bonding and lone pair electron densities

bonding pair is constrained by two nuclear potentials more localized in space

lone pair is constrained by only one nuclear potential less localized (needs more room)

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 7: What Do Molecules Look Like?

VSEPR 2 electron pairsLinear (AX2) angle between bonds is 180deg

Example BeF2

180deg

Experiments show that molecules with multiple bonds can also be linear

Multiple bonds are treated as a single effective electron groupF Be F

F Be F

More than one central atom Determine shape around each

Be FF

VSEPR 3 electron pairsTrigonal Planar (AX3) angle between bonds is 120degExample BF3

Multiple bond is treated as a single effective electron group

FBFF

B

FF

F

120deg

VSEPR 4 electron pairs (cont)

Tetrahedral (AX4) angle between bonds is ~1095degExample CH4

1095degH C

HH

H

tetrahedral e- pair geometry AND tetrahedral molecular shape

Bonding vs Lone pairsBond angle in a tetrahedral arrangement of electron pairs may vary from 1095deg due to size differences between bonding and lone pair electron densities

bonding pair is constrained by two nuclear potentials more localized in space

lone pair is constrained by only one nuclear potential less localized (needs more room)

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 8: What Do Molecules Look Like?

VSEPR 3 electron pairsTrigonal Planar (AX3) angle between bonds is 120degExample BF3

Multiple bond is treated as a single effective electron group

FBFF

B

FF

F

120deg

VSEPR 4 electron pairs (cont)

Tetrahedral (AX4) angle between bonds is ~1095degExample CH4

1095degH C

HH

H

tetrahedral e- pair geometry AND tetrahedral molecular shape

Bonding vs Lone pairsBond angle in a tetrahedral arrangement of electron pairs may vary from 1095deg due to size differences between bonding and lone pair electron densities

bonding pair is constrained by two nuclear potentials more localized in space

lone pair is constrained by only one nuclear potential less localized (needs more room)

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 9: What Do Molecules Look Like?

VSEPR 4 electron pairs (cont)

Tetrahedral (AX4) angle between bonds is ~1095degExample CH4

1095degH C

HH

H

tetrahedral e- pair geometry AND tetrahedral molecular shape

Bonding vs Lone pairsBond angle in a tetrahedral arrangement of electron pairs may vary from 1095deg due to size differences between bonding and lone pair electron densities

bonding pair is constrained by two nuclear potentials more localized in space

lone pair is constrained by only one nuclear potential less localized (needs more room)

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 10: What Do Molecules Look Like?

Bonding vs Lone pairsBond angle in a tetrahedral arrangement of electron pairs may vary from 1095deg due to size differences between bonding and lone pair electron densities

bonding pair is constrained by two nuclear potentials more localized in space

lone pair is constrained by only one nuclear potential less localized (needs more room)

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 11: What Do Molecules Look Like?

VSEPR 4 electron pairsTrigonal pyramidal (AX3E) Bond angles are lt1095deg and structure is nonplanar due to repulsion of lone pair

Example NH3

107deg

tetrahedral e- pair geometry trigonal pyramidal molecular shape

H NH

H

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 12: What Do Molecules Look Like?

VSEPR 4 electron pairs (cont)

Classic example of tetrahedral angle shift from 1095deg is water (AX2E2)

ldquobentrdquo1045o

tetrahedral e- pair geometry bent molecular shape

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 13: What Do Molecules Look Like?

VSEPR 4 electron pairs (cont)

Comparison of CH4 (AX4) NH3 (AX3E) and H2O (AX2E2)

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 14: What Do Molecules Look Like?

AX2E

AX3E

AX2E2

1 Refer to central atom as ldquoArdquo2 Attached atoms are referred to as ldquoXrdquo3 Lone pair are referred to as ldquoErdquo

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 15: What Do Molecules Look Like?

HH

H

H

CNOF

Central Atom

Compound Electron-Pair Geometry

Molecular Shape

Carbon C CH4 tetrahedral tetrahedralNitrogen N NH3 tetrahedral trigonal pyramidalOxygen O H2O tetrahedral bentFluorine F HF tetrahedral linear

Molecular vs Electron-Pair Geometry

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 16: What Do Molecules Look Like?

What is the electron-pair geometry and the molecular shape for HCFS

a) trigonal planar bent

b) trigonal planar trigonal planar

c) tetrahedral trigonal planar

d) tetrahedral tetrahedral

C

S

H

F

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 17: What Do Molecules Look Like?

VSEPR Beyond the OctetSystems with expanded valence shells will have five or six electron pairs around a central atom

P

Cl

Cl

Cl

Cl

Cl

FF

F

F

FFS

90deg

120deg SF

F

F

F

F

F 90deg

90deg

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 18: What Do Molecules Look Like?

VSEPR 5 electron pairsbull Consider the structure of SF4 (34 e- AX4E)bull What is the optimum arrangement of electron pairs

around S

SFF

FF

S

FF

FF

SF

FF

F

lone-pair bond-pair

two at 90o two at 120o

Repulsive forces (strongest to weakest)lone-pairlone-pair gt lone-pairbond-pair gt bond-pairbond-pair

bond-pair bond-pair

three at 90o four at 90o one at

120othree at 90o three at 120o

Compare endash pair angles

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 19: What Do Molecules Look Like?

VSEPR 5 electron pairsThe optimum structure maximizes the

angular separation of the lone pairs

I3- (AX2E3)

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 20: What Do Molecules Look Like?

AX3E2

AX4E

AX2E3

5-electron-pair geometries

our previous example

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 21: What Do Molecules Look Like?

Which of these is the more likely structure

Square Planar

VSEPR 6 electron pairs

See-saw

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 22: What Do Molecules Look Like?

AX5E

AX4E2

6-electron-pair geometries

our previous example

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 23: What Do Molecules Look Like?

Molecular Dipole Moments

1 Draw Lewis structures to determine 3D arrangement of atoms

Shortcut completely symmetric molecules will not have a dipole regardless of the polarity of the bonds

2 If one ldquosiderdquo of the molecule has more EN atoms than the other the molecule has a net dipole

We can use VSEPR to determine the polarity of a whole molecule

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 24: What Do Molecules Look Like?

Molecular Dipoles

The C=O bonds have dipoles of equal magnitude but opposite direction so there is no net dipole moment

The O-H bonds have dipoles of equal magnitude that do not cancel each other so water has a net dipole moment

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 25: What Do Molecules Look Like?

Molecular Dipoles (cont)

symmetric

symmetricasymmetri

c

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 26: What Do Molecules Look Like?

F

ClF

Cl

Molecular Dipole Examplebull Write the Lewis dot and VESPR

structures for CF2Cl2 Does it have a dipole moment

C

F

FClCl

32 e-

Tetrahedral

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 27: What Do Molecules Look Like?

Advanced VSEPR Application

Molecules with more than one central atomhellip methanol (CH3OH)

H CH

OH

H

tetrahedral e- pairstetrahedral shape

tetrahedral e- pairsbent shape

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 28: What Do Molecules Look Like?

The VSEPR Table

2 AX2 BeF2 linear linear

3 AX3 BF3 trigonal planar

trigonal planar

AX2E O3 trigonal planar

bent

4 AX4 CH4 tetrahedral tetrahedral

AX3E NH3 tetrahedral pyramidal

AX2E2 H2O tetrahedral bent

e- pairs e- Geom Molec Geom

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 29: What Do Molecules Look Like?

The VSEPR Table5 AX5 PF5 trigonal

bipyramidaltrigonalbipyramidal

AX4E SF4 trigonal bipyramidal

see saw

AX3E2 ClF3 trigonal bipyramidal

T-shaped

AX2E3 I3- trigonal bipyramidal

linear

6 AX6 SF6 octahedral octahedral

AX4E2 XeF4 octahedral square planar

e- pairs e- Geom Molec Geom

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 30: What Do Molecules Look Like?

What is the expected shape of ICl2+

A linear

B bent

C tetrahedral

D square planar

AX2E2ICl Cl+

20 e-

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 31: What Do Molecules Look Like?

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from

two atoms overlap and a pair of electrons occupies the region between the two nuclei

Rule 1 Maximum overlap The bond strength depends on the attraction of nuclei to the shared electrons soThe greater the orbital overlap the stronger the bond

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 32: What Do Molecules Look Like?

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 2 Spins pair The two electrons in the overlap region occupy the same space and therefore must have opposite spins

There may be no more than 2 electrons in a molecular orbital

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 33: What Do Molecules Look Like?

Valence Bond Theory

Basic Principle of Localized Electron Model A covalent bond forms when the orbitals from two atoms overlap and a pair of electrons occupies

the region between the two nuclei

Rule 3 Hybridization To explain experimental observations Pauling proposed that the valence atomic orbitals in a molecule are different from those in the isolated atoms We call this concept

Hybridization

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 34: What Do Molecules Look Like?

What is hybridizationbull Atoms adjust to meet the ldquoneedsrdquo of the

moleculebull In a molecule electrons rearrange in an

attempt to give each atom a noble gas configuration and to minimize electron repulsion

bull Atoms in a molecule adjust their orbitals through hybridization in order for the molecule to have a structure with minimum energy

bull The source of the valence electrons is not as important as where they are needed in the molecule to achieve a maximum stability

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 35: What Do Molecules Look Like?

Example Methane

bull 4 equivalent C-H covalent bondsbull VSEPR predicts a tetrahedral geometry

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 36: What Do Molecules Look Like?

The Valence Orbitals of a Carbon Atom

Carbon 2s22p2

How do we explain formation of 4 equivalent C-H bonds

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 37: What Do Molecules Look Like?

Hybridization Mixing of Atomic Orbitals to form New Orbitals for Bonding

+ndash

+ndash

ndash+

+ndash +

ndash

+ +ndash

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 38: What Do Molecules Look Like?

Other Representations of Hybridization

y1 = 12[(2s) + (2px) + (2py) + (2pz)]y2 = 12[(2s) + (2px) - (2py) - (2pz)]y3 = 12[(2s) - (2px) + (2py) - (2pz)]y4 = 12[(2s) - (2px) - (2py) + (2pz)]

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 39: What Do Molecules Look Like?

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Methane (CH4)VSEPR AB4 tetrahedral sp3 hybridized

10947 ordmElectron pair geometry determines hybridization not vice versa

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 40: What Do Molecules Look Like?

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

NH

HH

1081 ordm

Ammonia (NH3) VSEPR AB3E tetrahedral sp3 hybridized

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 41: What Do Molecules Look Like?

Hybridization is related to the number ofvalence electron pairs determined from VSEPR

Water (H2O) VSEPR AB2E2 tetrahedral sp3 hybridized

1056 ordm

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 42: What Do Molecules Look Like?

s bonding and p bondingbull Two modes of bonding are important for1st and 2nd row elements s bonding and p bonding

bull These two differ in their relationship to the internuclear axiss bonds have electron density ALONG the axis

p bonds have electron density ABOVE AND BELOW the axis

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 43: What Do Molecules Look Like?

Problem Describe the hybridization and bonding of the carbon orbitals in ethylene

(C2H4) VSEPR AB3 trigonal planar sp2 hybridized orbitals for s bonding

sp2 hybridized orbitals used for s bondingremaining p orbital used for p bonding

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 44: What Do Molecules Look Like?

Bonding in ethylene (C2H4)

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 45: What Do Molecules Look Like?

Problem Describe the hybridization and bonding of the carbon orbitals in Carbon

Dioxide (CO2) VSEPR AB2 linear sp hybridized orbitals for s bonding

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 46: What Do Molecules Look Like?

Bonding in Carbon Dioxide (CO2)

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 47: What Do Molecules Look Like?

Atoms of the same kind can have different hybridizations

C2 AB4

sp3

sp

C1 AB2

2s2 2px2pysp sp p p

N ABE2s2 2px2py2pz

sp spp plone pair

s

Bonds

s p p

C1C2 NH

H

H

Acetonitrile (important solvent and industrial chemical)CH3 C N

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 48: What Do Molecules Look Like?

What have we learned so far

bull Molecular orbitals are combinations of atomic orbitals

bull Atomic orbitals are ldquohybridizedrdquo to satisfy bonding in molecules

bull Hybridization follows simple rules that can be deduced from the number of chemical bonds in the molecule and the VSEPR model for electron pair geometry

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 49: What Do Molecules Look Like?

Hybridizationbull sp3 Hybridization (CH4)

ndash This is the sum of one s and three p orbitals on the carbon atom

ndash We use just the valence orbitals to make bonds

ndash sp3 hybridization gives rise to the tetrahedral nature of the carbon atom

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 50: What Do Molecules Look Like?

Hybridizationbull sp2 Hybridization (H2C=CH2)

ndash This is the sum of one s and two p orbitals on the carbon atom

ndash Leaves one p orbital uninvolved ndash this is free to form a p bond (the second bond in a double bond)

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 51: What Do Molecules Look Like?

Hybridizationbull sp Hybridization (O=C=O)

ndash This is the sum of one s and one p orbital on the carbon atom

ndash Leaves two p orbitals free to bond with other atoms (such a O in CO2) or with each other as in HCequivCH

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 52: What Do Molecules Look Like?

General Notesbull This is a model and only goes so far but it is

especially helpful in understanding geometry and expanding Lewis dot structures

bull Orbitals are waves Hybridized orbitals are just the sums of waves ndash constructive and destructive interference

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 53: What Do Molecules Look Like?

What is important to know about hybridization

bull You should be able to give the hybridization of an atom in a molecule based on the formula given

bull Example CH3-CH2-CHObull Step 1 Draw the Lewis Dot Structure

C C C O

H

H

H

H

H H

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 54: What Do Molecules Look Like?

What is important to know about hybridization

bull Step 2 What is the electron pair geometry and molecular shape

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 55: What Do Molecules Look Like?

What is important to know about hybridization

bull Step 3 Use the molecular shape to determine the hybridization

C C C O

H

H

H

H

H H

AX4

AX4

AX3

AXE2

Tetrahedral

Tetrahedral

Trigonal Planar

Trigonal Planar

sp3

sp3 sp2

sp2

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 56: What Do Molecules Look Like?

The Localized Electron Model is very powerfulfor explaining geometries and basic features ofbonding in molecules but it is just a modelMajor limitations of the LE model

bull Assumes electrons are highly localized between the nuclei (sometimes requires resonance structures)

bull Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

bull Doesnrsquot provide direct information about bond energies

Example O2 Lewis dot structure O=O

All electrons are paired Contradicts experiment

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 57: What Do Molecules Look Like?

The Molecular Orbital ModelBasic premise When atomic orbitals interact to form a bond the result is the formation of new molecular orbitals

HY = EY

Important features of molecular orbitals1 Atomic Orbitals are solutions of the Schroumldinger equation for atoms Molecular orbitals are the solutions of the same Schroumldinger equation applied to the molecule

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 58: What Do Molecules Look Like?

2 Atomic Orbitals can hold 2 electrons with opposite spins Molecular Orbitals can hold 2 electrons with opposite spins

3 The electron probability for the Atomic Orbital is given by Y2 The electron probability for the Molecular Orbital is given by Y2

4 Orbitals are conserved - in bringing together 2 atomic orbitals we have to end up with 2 molecular orbitals

How does this work

Molecular Orbital Theory

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 59: What Do Molecules Look Like?

+ -

+

Molecular Orbitals are simplyLinear Combinations of Atomic Orbitals

s bonding

s anti-bonding (s)Example H2

Next Question Why does this work

Molecular Orbitals have phases (+ or -)

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 60: What Do Molecules Look Like?

Constructive and Destructive Interference

Constructive interference between two overlapping orbitals leads to a bonding orbital

Destructive interference between two orbitals of opposite sign leads to an anti-bonding orbital

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 61: What Do Molecules Look Like?

Bonding is driven by stabilization of electronsbull Electrons are negatively

chargedbull Nuclei are positively charged

The bonding combination puts electron density between the two nuclei - stabilizationThe anti-bonding combination moves electron density away from region between the nuclei - destabilization

= = nucleus+

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 62: What Do Molecules Look Like?

bull We can depict the relative energies of molecular orbitals with a molecular orbital diagram

MO Diagrams

The new molecular orbital is lower in energy than the atomic orbitals

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 63: What Do Molecules Look Like?

s MO is raised in energy

s MO is lowered in energyH atom (1s)1 electron configurationH2 molecule (s1s)2 electron configuration

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 64: What Do Molecules Look Like?

Same as previous description of bonding

s

s

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 65: What Do Molecules Look Like?

Review of Orbital Fillingbull Pauli Exclusion Principle

ndash No more than 2 e- in an orbital spins must be paired (uarrdarr)

bull Aufbau Principle (aka ldquoBuilding-Uprdquo)ndash Fill the lowest energy levels with electrons first

bull 1s 2s 2p 3s 3p 4s 3d 4p hellipbull Hundrsquos Rule

ndash When more than one orbital has the same energy electrons occupy separate orbitals with parallel spins

Yes No No

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 66: What Do Molecules Look Like?

Filling Molecular Orbitals with Electrons

1) Orbitals are filled in order of increasing Energy (Aufbau principle)

H2

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 67: What Do Molecules Look Like?

2) An orbital has a maximum capacity of two electrons with opposite spins (Pauli exclusion principle)

He2

Filling Molecular Orbitals with Electrons

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 68: What Do Molecules Look Like?

Filling Molecular Orbitals with Electrons

3) Orbitals of equal energy (degenerate orbitals) are half filled with spins parallel before any is filled completely (Hundrsquos rule)

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 69: What Do Molecules Look Like?

Bond Order

Bond Order =

bonding anti-bonding electrons electrons

2

The bond order is an indication of bond strengthGreater bond order Greater bond strength

(Shorter bond length)

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 70: What Do Molecules Look Like?

Bond Order Examples

H2

Bond order = (2-0)2 = 1Single bondStable molecule (436 kJmol bond)

He2

Bond order = (2-2)2 = 0No bondUnstable molecule (0 kJmol bond)

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 71: What Do Molecules Look Like?

He2+

H2+

Bond order = (2-1)2 = 12Half of a single bondCan be made but its not very stable (250 kJmol bond)

Bond order = (1-0)2 = 12Half of a single bondCan be made but its not very stable (255 kJmol bond)

Fractional bond orders are okay

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 72: What Do Molecules Look Like?

bull A s bond can be formed a number of ways

ndashs s overlap

ndashs p overlapndashp p overlap

Forming Bonds

Only orbitals of the same phase (+ +) can form bonds

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 73: What Do Molecules Look Like?

bull For every bonding orbital we form we also form an anti-bonding orbital

Anti-bonding Orbitals

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 74: What Do Molecules Look Like?

MO Theory in Bondingbull Homonuclear atoms (H2 O2 F2 N2)

H2

(Only 1s orbitals

available for

bonding)

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 75: What Do Molecules Look Like?

bull Atomic orbitals must overlap in space in order to participate in molecular orbitals

bull Covalent bonding is dominated by the valence orbitals (only valence orbitals are shown in the MO diagrams)

Covalent Bonding in Homonuclear Diatomics

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 76: What Do Molecules Look Like?

Covalent Bonding in Homonuclear Diatomics

Region of shared e- density

+

+

ndash

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 77: What Do Molecules Look Like?

Valence configurations of the 2nd row atoms

Li Be B C N O F2s1 2s2 2s22p1 2s22p2 2s22p3 2s22p4

2s22p5

So far we have focused on bonding involving the s orbitals

What happens when we have to consider the p orbitals

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 78: What Do Molecules Look Like?

For diatomic molecules containing atoms with valence electrons in the p orbitals we must consider three

possible bonding interactions

s-typep-type p-type

= nucleus

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 79: What Do Molecules Look Like?

(+)constructivemixing

(ndash)destructivemixing

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 80: What Do Molecules Look Like?

Major limitations of the LE model

2) Doesnrsquot easily deal with unpaired electrons (incorrectly predicts physical properties in some cases)

Example O2 - Lewis dot structure O=O

- All electrons are paired Contradicts experiment

Experiments show O2 is paramagnetic

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 81: What Do Molecules Look Like?

A quick note on magnetismhellip

Paramagnetic The molecule contains unpaired electrons and is attracted to (has a positive susceptibility to) an applied magnetic field

Diamagnetic The molecule contains only paired electrons and is not attracted to (has a negative susceptibility to) an applied magnetic field

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 82: What Do Molecules Look Like?

____ s2p ___ ___ p2p

___ ___ ___2p ___ ___ ___ 2p___ ___ p2p

Energy

____ s2p

____ s2s___ 2s ___ 2s

____ s2s

Example the O2 Diatomic

Bond Order = (8-4)2 = 2O2 is stable

(498 kJmol bond strength)

Both have degenerate orbitals

(s2s)2(s2s)2(s2p)2(p2p)4(p2p)2

Oxygen atom has a 2s22p4 valence configuration

O atom O atomMOO2

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 83: What Do Molecules Look Like?

A prediction from the MO diagram of O2

O=O

The unpaired electrons predicted by the MO diagram should behave as small magnets- O2 should be magnetic

The Lewis dot structure predicts O2 should be diamagnetic-all

electrons are paired

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 84: What Do Molecules Look Like?

N2 Video

O2 Video

>
>

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 85: What Do Molecules Look Like?

What have we learned so far1 Molecular orbitals (MO) are linear combinations of atomic orbitals

2 Both s and p atomic orbitals can be mixed to form MOs

3 Molecular orbitals are bonding and anti-bonding

4 Bonding and anti-bonding MOs lead to the definition of the bond order

5 Bond order is related to the bond strength (bond dissociation energy)

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 86: What Do Molecules Look Like?

MO Diagram for H2 vs N2

H2

sp

p2p

s2p

p2p

s2s

s2s

N2

Atomic orbital overlap sometimes forms both s and p bonds Examples N2 O2 F2

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 87: What Do Molecules Look Like?

1s(N) + 1s(N) 1s(N) ndash1s(N)-37875 -37871

-2965

Elec

tron

ener

gy (k

J mol

-1)

Core Core

Valence Valence

s(2s)

s(2s)

-1479

-1240 -1240

p p

s(2p)

-1155

p p

s(2p)

MO Diagram for N2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 88: What Do Molecules Look Like?

A ComplicationhellipMO Diagram for O2

(similar for F2 and Xe2)MO Diagram for B2

(similar for C2 and N2)O OO2

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 89: What Do Molecules Look Like?

A ComplicationhellipMO Diagram for O2

(similar for F2 and Ne2)MO Diagram for B2

(similar for C2 and N2)

s-p mixing

No s-p mixing

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 90: What Do Molecules Look Like?

Electron repulsion

Why does s-p mixing occur

s2s and s2p both have significant e- probability between the nuclei so e- in s2s

will repel e- in s2pEffect will decrease as you move across the Periodic Table increased nuclear charge pulls the s2s e-

closer making the s2s orbital smaller and decreasing the s2s and s2p interaction

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 91: What Do Molecules Look Like?

Molecular Orbitals of X2 Molecules

sp orbital mixing (a little hybridization)bull lowers the energy of the s2s orbitals andbull raises the energy of the s2p orbitals

bull As a result E(s2p) gt E(p 2p) for B2 C2 and N2 bull As one moves right in Row 2 2s and 2p get

further apart in energy decreasing sndashp mixing E(s2p) lt E(p2p) for O2 F2 and Ne2 See text pages 680-681

bull Note that sndashp mixing does not affect bond order or magnetism in the common diatomics (N2 O2 and F2) Hence it is not of much practical importance

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 92: What Do Molecules Look Like?

s-p mixing

No s-p mixing

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 93: What Do Molecules Look Like?

B C and N all have 12 filled 2p orbitalsWhen does s-p mixing occur

O F and Xe all have gt 12 filled 2p orbitals

bull If 2 electrons are forced to be in the same orbital their energies go up

bull Electrons repel each other because they are negatively charged

bull Having gt 12 filled 2p orbitals raises the energies of these orbitals due to e- - e- repulsion

s-p mixing only occurs when the s and p atomic orbitals are close in energy ( 12 filled 2p orbitals)

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 94: What Do Molecules Look Like?

Relating the MO Diagrams to Physical Properties

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 95: What Do Molecules Look Like?

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Removing an electron from N2 decreases the bond energy of the resulting ion whereas removing an electron from O2 increases the bond energy of the resulting ion Explain these facts using MO diagrams

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 96: What Do Molecules Look Like?

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11

Plan We first draw the MO energy levels for the four species recalling that they differ for N2 and O2 Then we determine the bond orders and compare them with the data bond order is related directly to bond energy and inversely to bond length

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 97: What Do Molecules Look Like?

Sample Problem - ContinuedSolution The MO energy levels are

N2

sp

p2p

N2+

s2p

p2p

s2s

s2s

O2 O2+

sp

s2s

s2s

p2p

p2p

s2p

Bond Orders(8-2)2 = 3 (7-2)2 = 25 (8-4)2 = 2 (8-3)2 = 25

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 98: What Do Molecules Look Like?

Sample ProblemUsing MO Theory to Explain Bond Properties

Problem Consider the following data for these homonuclear diatomic species

N2 N2+ O2 O2

+

Bond energy (kJmol) 945 841 498 623Bond length (pm) 110 112 121 112No of valence electrons 10 9 12 11Bond Order 3 25 2 25

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 99: What Do Molecules Look Like?

What have we learned so far1 Molecular orbitals (MO) explain the properties of valence electrons in molecules (Example O2)

2 s and p atomic orbitals can be mixed to form s s p and p molecular orbitals

3 Electrons in p or p molecular orbitals can have the same energies Degenerate orbitals

4 The ordering of s2p and p2p molecular orbitals depends on the electron occupancy s-p mixing

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 100: What Do Molecules Look Like?

Bonding in Diatomic Molecules

Covalent

Ionic

IonicCovalent

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 101: What Do Molecules Look Like?

HomonuclearH2

Nonpolar covalent bond(450 kJmol bond)

HeteronuclearHF

Polar covalent bond(565 kJmol bond)

Electronegativity

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 102: What Do Molecules Look Like?

Electronegativity

Because F (EN = 40) is more electronegative than H (EN = 22) the electrons move closer to F

This gives rise to a polar bond

H F

Figure 1445

Electrons are not equally sharedin heteronuclear bondsHF

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 103: What Do Molecules Look Like?

s Antibonding (s)Mostly H(1s)

s BondingMostly F(2p)

H F

H F

MOs of a Polar Covalent Bond HF

This approach simplifies model and only considers electrons involved in bond

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 104: What Do Molecules Look Like?

MOs OF XY MOLECULES

Equal or unequal e sharing between 2 atoms is reflected in the composition of the MOsmiddot When 2 atoms X and Y have the same electronegativity (purely

covalent bond) their overlapping AOs have the same energy and the bonding and anti-bonding MOs are each half X and half Y AO All electrons spend equal time near X and Y Examples N2 O2 F2

middot If EN(Y) gt EN(X) (polar covalent X+Y) the Y AO has lower energy than the X AO The bonding MO is more like the Y AO and the anti-bonding MO more like the X AO Bonding e spend more time near Y than X vice versa for anti-bonding e Example CO

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 105: What Do Molecules Look Like?

MOs OF XY MOLECULES ____ s ___ ___ p ___ ___ ___2p ___ ___ ___ 2p uarr ____ s

Energy ___ ___ p ____ s ___ 2s ___ 2s ____ s

middot CO Bond Order = 30 (same as N2)middot CO Bond Energy = 1076 kJmol (N2 = 945 kJmol)middot Isoelectronic to CO and N2 CNndash NO+middot NO has 1endash in p bond order = 25 this endash is more on N than O

NO NO+ easyhellip

C Atom (4endash) Cδ+Oδndash (10endash) O Atom (6endash)

___ ___ ___ 2p ___ 2s

Electronegativity

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 106: What Do Molecules Look Like?

Bonding in NObull Two possible Lewis dot structures

for NObull The simplest structure minimizes

formal charges and places the lone (unpaired) electron on the nitrogen

bull The Lewis structure predicts a bond order of 2 but experimental evidence suggests a bond order between 2 and 3

bull How does MO theory help us understand bonding in NO

N=O

N=O

+1-1

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 107: What Do Molecules Look Like?

When the electronegativities of the 2 atoms are more similar the bonding

becomes less polar

EN(N) = 30EN(O) = 34

N=O

Electronegativity

2s2s

2p2p

NON OBond order = 25 unpaired electron is in a N-like orbital

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 108: What Do Molecules Look Like?

NO+

oxidation

NO

NO is easily oxidized to form NO+ Why What changes can we predict in the bonding and magnetism of the molecule

Bond Order = (8-3)2 = 25Paramagnetic

Bond Order = (8-2)2 = 3Diamagnetic

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 109: What Do Molecules Look Like?

s2s

s2s

p2p p2p

p2p

-3320

-1835

-1444 -1374

s2p -1307

-597 p2p (empty)

MO diagram for NO

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 110: What Do Molecules Look Like?

Key Points of MO Theory ndash Heteronuclear Molecules

bull The more electronegative atom has orbitals lower in energy than the more positive atom

bull Electrons in bonding orbitals are closer to the more electronegative atom anti-bonding electrons are closer to the more positive atom

bull For most diatomic molecules s-p mixing changes the orbital energy levels but since these orbitals are almost always fully occupied their order is less important to us

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 111: What Do Molecules Look Like?

Combining the Localized Electron and Molecular Orbital Models (into a convenient working

model)

Figure 1447

Only the p bonding changes between these resonance structures - The MO model describes this p bonding more

effectively

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 112: What Do Molecules Look Like?

Figure 1451

Atomic Orbitals Molecular Orbitals

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 113: What Do Molecules Look Like?

Another example Benzene

p bonding

s bonding

p atomic orbitals p molecular orbital

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations
Page 114: What Do Molecules Look Like?

MO Theory Expectationsbull You should be able to

ndash predict which atomic orbitals are higher or lower in energy (based on electronegativity differences)

ndash correctly fill a molecular orbital diagramndash correctly calculate bond orderndash predict molecular magnetic properties

based on orbital occupationndash understand how molecular properties

change upon ionization (oxidation or reduction) of molecules

  • What Do Molecules Look Like
  • Slide 2
  • Slide 3
  • Arranging Electron Pairs
  • Arranging Electron Pairs (cont)
  • VSEPR Structure Guidelines
  • VSEPR 2 electron pairs
  • VSEPR 3 electron pairs
  • VSEPR 4 electron pairs (cont)
  • Bonding vs Lone pairs
  • VSEPR 4 electron pairs
  • VSEPR 4 electron pairs (cont) (2)
  • VSEPR 4 electron pairs (cont) (3)
  • Slide 14
  • Molecular vs Electron-Pair Geometry
  • Slide 16
  • VSEPR Beyond the Octet
  • VSEPR 5 electron pairs
  • VSEPR 5 electron pairs (2)
  • 5-electron-pair geometries
  • VSEPR 6 electron pairs
  • Slide 22
  • Molecular Dipole Moments
  • Slide 24
  • Molecular Dipoles (cont)
  • Molecular Dipole Example
  • Advanced VSEPR Application
  • The VSEPR Table
  • The VSEPR Table (2)
  • Slide 30
  • Slide 31
  • Slide 32
  • Slide 33
  • Slide 34
  • Slide 35
  • Slide 36
  • Slide 37
  • Slide 38
  • Slide 39
  • Slide 40
  • Slide 41
  • Slide 42
  • Slide 43
  • Slide 44
  • Slide 45
  • Slide 46
  • Slide 47
  • Slide 48
  • Hybridization
  • Hybridization (2)
  • Hybridization (3)
  • General Notes
  • What is important to know about hybridization
  • What is important to know about hybridization (2)
  • What is important to know about hybridization (3)
  • Slide 56
  • Slide 57
  • Molecular Orbital Theory
  • Slide 59
  • Constructive and Destructive Interference
  • Slide 61
  • MO Diagrams
  • Slide 63
  • Slide 64
  • Review of Orbital Filling
  • Slide 66
  • Slide 67
  • Filling Molecular Orbitals with Electrons
  • Slide 69
  • Slide 70
  • Slide 71
  • Forming Bonds
  • Anti-bonding Orbitals
  • MO Theory in Bonding
  • Slide 75
  • Slide 76
  • Slide 77
  • Slide 78
  • Slide 79
  • Slide 80
  • Slide 81
  • Slide 82
  • Slide 83
  • Slide 84
  • Slide 85
  • MO Diagram for H2 vs N2
  • Slide 87
  • Slide 88
  • Slide 89
  • Slide 90
  • Molecular Orbitals of X2 Molecules
  • Slide 92
  • Slide 93
  • Slide 94
  • Slide 95
  • Slide 96
  • Slide 97
  • Slide 98
  • Slide 99
  • Slide 100
  • Slide 101
  • Slide 102
  • Slide 103
  • Slide 104
  • Slide 105
  • Bonding in NO
  • Slide 107
  • Slide 108
  • Slide 109
  • Key Points of MO Theory ndash Heteronuclear Molecules
  • Slide 111
  • Slide 112
  • Slide 113
  • MO Theory Expectations