unit 13: solutions. solution - homogeneous mixture solvent substance that dissolves the solute...
DESCRIPTION
Solute - KMnO 4 KMnO 4 Solution Solvent - H 2 OTRANSCRIPT
Unit 13: Solutions Unit 13: Solutions
Solution - Solution - homogeneous mixturehomogeneous mixture
Solvent Solvent – substance that – substance that dissolves the solutedissolves the solute
Solute Solute - substance - substance being dissolvedbeing dissolved
Solute Solute - KMnO- KMnO4 4 KMnOKMnO44 Solution SolutionSolvent Solvent - H- H22OO
SolvationSolvation Solvation – Solvation – the process of dissolvingthe process of dissolving
solute particles are separated and solute particles are separated and pulled into solutionpulled into solution
solute particles are surrounded by solute particles are surrounded by solvent particlessolvent particles
SolvationSolvation
StrongElectrolyte
Non-Electrolyte
solute exists asions only
- +
salt
- +
sugar
solute exists asmolecules
only
- +
acetic acid
WeakElectrolyte
solute exists asions and
moleculesView animation online.
SolvationSolvation
NONPOLAR
NONPOLAR
POLAR
POLAR
““Like Dissolves Like”Like Dissolves Like”
SolubilitySolubility UnsaturatedUnsaturated
When the solvent When the solvent holds holds lessless solute solute than it than it normally can at a given temperature.normally can at a given temperature.
SolubilitySolubility SaturatedSaturated
When the solvent holds When the solvent holds as muchas much of a of a solutesolute as it normally can at a given as it normally can at a given temperature.temperature.
SolubilitySolubility SupersaturatedSupersaturated
When the solvent holds When the solvent holds more more dissolved solutedissolved solute than it normally can at that than it normally can at that temperature.temperature.
Formed when a saturated Formed when a saturated solution is formed at high solution is formed at high temperatures and then temperatures and then cooled slowly.cooled slowly.
SolubilitySolubilitySATURATED SOLUTION
no more solute dissolves
UNSATURATED SOLUTIONmore solute dissolves
SUPERSATURATED SOLUTION
becomes unstable, crystals form
concentration
Solubility CurvesSolubility Curves Solubility Curves show:Solubility Curves show:
maximum grams of solute that will maximum grams of solute that will dissolve in 100 g of solvent at a dissolve in 100 g of solvent at a given temperaturegiven temperature
varies with temperaturevaries with temperature based on a saturated solutionbased on a saturated solution
SolubilitySolubility Solubility CurveSolubility Curve
shows how shows how temperature temperature affects the affects the solubility of a solubility of a substance.substance.
Solid SolubilitySolid Solubility SolidsSolids are more soluble at... are more soluble at...
high temperatureshigh temperatures
Gas SolubilityGas Solubility Gases are more soluble at...Gases are more soluble at...
low temperatures &low temperatures & high pressures (Henry’s Law).high pressures (Henry’s Law). EXEX: nitrogen narcosis, the “bends,” soda: nitrogen narcosis, the “bends,” soda
Solubility CurveSolubility Curve
Things to rememberThings to remember The graph is set in The graph is set in 100 mL or 100 100 mL or 100
gramsgrams of water. of water. The line represents the The line represents the saturation saturation
pointpoint at that temperature.at that temperature. Anything Anything above the lineabove the line (at that (at that
temp) is temp) is supersaturatedsupersaturated Anything Anything below the linebelow the line (at that (at that
temp) is temp) is unsaturated.unsaturated.
ExampleExample
What amount of NaCl would make a What amount of NaCl would make a saturated solution in 100 mL of water at saturated solution in 100 mL of water at 808000C?C?Just look it up on the graph.Just look it up on the graph.
Answer : Answer : 40 grams40 grams GRAPH
What if it is not What if it is not 100 mL or 100 grams100 mL or 100 grams of of water?water? Set up a proportion:Set up a proportion:
solid solid solidsolid ==
liquidliquid liquidliquid
From graph From
problem
Always
100 mL
This will
be x
ExampleExample
What amount of KNOWhat amount of KNO33 would make a would make a saturated solution in 177mL of water at saturated solution in 177mL of water at 505000C?C?
80 g80 g xx==
100mL100mL 177mL 177mL== 141.6 g 141.6 g GRAPH
What if there is no amount of water given?What if there is no amount of water given? Set up a proportion:Set up a proportion:
solid solid solidsolid ==
liquidliquid liquidliquid
From graph
From problem
Always
100 mLThis will be x
ExampleExample What amount of water at 20What amount of water at 2000C would make a C would make a
saturated solution with 63g of KNOsaturated solution with 63g of KNO33??
30 g30 g 63 g63 g ==
100mL 100mL X X
== 210 mL 210 mL GRAPH
Precipitation Reactions:Precipitation Reactions:What are they?What are they?
Type of Type of double replacementdouble replacement reaction. reaction. Two solutions of ionic compounds are mixedTwo solutions of ionic compounds are mixed One of the products of the reaction is an One of the products of the reaction is an
insoluble salt called a insoluble salt called a precipitateprecipitate (chunky (chunky milk)milk)
Use Use solubility rulessolubility rules to determine the to determine the precipitateprecipitate..
Solubility RulesSolubility RulesSolubility Solubility (in water)(in water)
CompoundsCompounds ExceptionsExceptions
SolubleSoluble Alkali metal (Group 1) saltsAlkali metal (Group 1) salts nonenoneAmmonium salts (NHAmmonium salts (NH44
++)) nonenone
Acetates (CAcetates (C22HH33OO22 - -)) nonenone
Nitrates (NONitrates (NO33 - -)) nonenone
Chlorides (Cl Chlorides (Cl --), Bromides (Br ), Bromides (Br --), ), Iodides (I Iodides (I --))
Compounds of Ag, Hg, and PbCompounds of Ag, Hg, and Pb
Sulfates (SOSulfates (SO44 2- 2-)) Compounds of Sr, Ba, Hg, and Compounds of Sr, Ba, Hg, and
PbPb********** ****************************************************** ******************************************************InsolubleInsoluble Carbonates (COCarbonates (CO33
2- 2-), Phosphates ), Phosphates (PO(PO44
3- 3-), Sulfites (SO), Sulfites (SO33 2- 2-), ),
Chromates (CrOChromates (CrO442-2-))
Compounds of Alkali metal Compounds of Alkali metal (Group 1)(Group 1) and NHand NH44
++
Sulfides (SSulfides (S 2- 2-), Hydroxides (OH), Hydroxides (OH - -)) Compounds of Alkali metal Compounds of Alkali metal (Group 1)(Group 1) and NHand NH44
+, +, Ca, Sr, Ba Ca, Sr, Ba
Example using chartExample using chart
Pb(OH)Pb(OH)22
NHNH44ClCl
KK22SOSO44
BaBa33(PO(PO44))22
Insoluble
Soluble
Soluble
InsolubleRULES
How to use it.How to use it. Write the products for the double Write the products for the double
replacement reactions replacement reactions and balanceand balance.. Then, using the solubility rules Then, using the solubility rules
identify the identify the precipitate by a subscript (s)precipitate by a subscript (s) for solid (insoluble in water). for solid (insoluble in water).
Identify the Identify the soluble compounds by soluble compounds by marking them with a subscript (aq)marking them with a subscript (aq) for for aqueous (soluble in water)aqueous (soluble in water)..
ExampleExample
Ag(NOAg(NO33))22 + LiCl + LiCl
Ag(NOAg(NO33))22 + LiCl + LiCl
Ag(NOAg(NO33))22 + 2 LiCl + 2 LiCl AgCl AgCl22 + 2 LiNO + 2 LiNO33
AgCl2+ LiNO3
+2 -1-1 +1
s aqaq aq
RULES
ConcentrationConcentration The amount of solute in The amount of solute in
a solution.a solution. Describing Describing
ConcentrationConcentration % by mass% by mass - -
medicated creamsmedicated creams % by volume% by volume - -
rubbing alcoholrubbing alcohol Molarity and Molarity and
MolalityMolality - used by - used by chemistschemists
B. MolarityB. Molarity
solvent of literssolute of moles(M)molarity
solvent onlysolvent only
1000mL = 1 L 1000mL = 1 L
MolarityMolarity Find the Molarity of a solution containing .5 Find the Molarity of a solution containing .5
mol of glucose in 2 L of water. mol of glucose in 2 L of water.
= = .25 M.25 M
GIVEN:M = ?Mol = .5 molV = 2 L
WORK:M= mol solute/ liters solvent
M= .5 mol
2 L
2211 VMVM
DilutionDilution
Preparation of a desired solution by Preparation of a desired solution by adding water to a concentrated solution.adding water to a concentrated solution.
Moles of solute remain the same.Moles of solute remain the same.
DilutionDilution What volume of 15.8What volume of 15.8MM HNO HNO33 is required to make 250 mL of is required to make 250 mL of
a 6.0a 6.0MM solution? solution?
GIVEN:M1 = 15.8MV1 = ?
M2 = 6.0MV2 = 250 mL
WORK:M1 V1 = M2 V2
(15.8M) V1 = (6.0M)(250mL)
V1 = 95 mL of 15.8M HNO3