transferencia de calor agua-aire
DESCRIPTION
Cálculos para la transferencia de calor de agua a aire.TRANSCRIPT
PRESENTACIÓN DE RESULTADOS
Lecturas 1 2 3 4 5 6Control de Temperatura
50 50 70 70 80 80
Control del Flujo de Aire
40 40 60 60 70 70
R.P.M 4 000 4 000 6 000 6 000 7 000 7 000Voltaje 100 105 150 150 170 170Amperaje 3.5 3.5 5 5 5.5 5.5Presión 300 mm Manómetro
20 20 57 56 74 74
Presión 200 mm Manómetro
7 7 26 25 33 33
Temperatura de Entrada de Agua
22 23 24 23 23 23
Temperatura Ambiente
23 23 23 23 23 23
Termopar 1 28 29 38 36 39 39Termopar 2 21 23 26 24 24 29Termopar 3 23 24 26 30 32 28Termopar 4 54 57 105 117 132 136Temperatura Salida de Agua
23.5 23.8 25 27 28.5 30
Caudal de Agua por Minuto
1 1 1 1 1 1
Tipo de Flujo Contraflujo Paralelo Paralelo Contraflujo Contraflujo Paralelo
CÁLCULOS
Primera Lectura: Flujo Paralelo
Q=VI
Q= (100V ) (3.5 A )
Q=350W
Q=mACpaire (T 4−T 1 )
mA=Q
Cpaire (T4−T 1)
mA=350W
1010J
Kg°C(54 °C−28 ° C )
mA=0.0133Kgs
∆T 1=T 1−T o
∆T 1=28 ° C−23° C
∆T 1=5 °C
∆T 2=T 4−T i
∆T 2=54 ° C−22 °C
∆T 2=32 °C
∆T DMLT=∆T 1−∆T 2
ln(∆T 1∆T 2 )∆T DMLT=
5 °C−32 °C
ln( 5 °C32 °C )∆T DMLT=14.5450 ° C
Para el área del conducto:
A=L∅ π
A=(1.850m ) (0.0197m )π
A=0.1144m2
Q=UA ∆T DMLT
U= QA ∆T DMLT
U= 350W
(0.1144m2 ) (14.5450 °C )
U=210.167 W
m2 °C
Segunda Lectura: Flujo en Contraflujo
Q=VI
Q= (105V ) (3.5 A )
Q=367.5W
Q=mACpaire (T 4−T 1 )
mA=Q
Cpaire (T4−T 1)
mA=367.5W
1010J
Kg°C(57 °C−29 °C )
mA=0.0129Kgs
∆T 1=T 4−T i
∆T 1=57 ° C−23° C
∆T 1=34 ° C
∆T 2=T 1−T o
∆T 2=29 ° C−24 °C
∆T 2=5 °C
∆T DMLT=∆T 1−∆T 2
ln(∆T 1∆T 2 )∆T DMLT=
34 ° C−5° C
ln( 34 ° C5 ° C )∆T DMLT=15.1284 ° C
Para el área del conducto:
A=L∅ π
A=(1.850m ) (0.0197m )π
A=0.1144m2
Q=UA ∆T DMLT
U= QA ∆T DMLT
U= 367.5W
(0.1144m2 ) (15.1284 ° C )
U=212.16 W
m2 °C
Tercera Lectura: Flujo Paralelo
Q=VI
Q= (150V ) (5 A )
Q=750W
Q=mACpaire (T 4−T 1 )
mA=Q
Cpaire (T4−T 1)
mA=750W
1010J
Kg°C(105° C−38 °C )
mA=0.0110Kgs
∆T 1=T 1−T i
∆T 1=38 °C−24 °C
∆T 1=14 ° C
∆T 2=T 4−To
∆T 2=105 ° C−25° C
∆T 2=80 ° C
∆T DMLT=∆T 1−∆T 2
ln(∆T 1∆T 2 )∆T DMLT=
14 ° C−80 °C
ln( 14 ° C80 ° C )∆T DMLT=37.8664 ° C
Para el área del conducto:
A=L∅ π
A=(1.850m ) (0.0197m )π
A=0.1144m2
Q=UA ∆T DMLT
U= QA ∆T DMLT
U= 750W
(0.1144m2 ) (37.8664 °C )
U=172.98 W
m2° C
Cuarta Lectura: Flujo en Contraflujo
Q=VI
Q= (150V ) (5 A )
Q=750W
Q=mACpaire (T 4−T 1 )
mA=Q
Cpaire (T4−T 1)
mA=750W
1010J
Kg°C(117° C−36° C )
mA=0.0091Kgs
∆T 1=T 4−T i
∆T 1=117° C−23 °C
∆T 1=9 4 °C
∆T 2=T 1−T o
∆T 2=36 ° C−24 °C
∆T 2=12 °C
∆T DMLT=∆T 1−∆T 2
ln(∆T 1∆T 2 )∆T DMLT=
94 ° C−12° C
ln( 94 ° C12 °C )∆T DMLT=39.8369 ° C
Para el área del conducto:
A=L∅ π
A=(1.850m ) (0.0197m )π
A=0.1144m2
Q=UA ∆T DMLT
U= QA ∆T DMLT
U= 750W
(0.1144m2 ) (39.8369° C )
U=164.43 W
m2° C
Quinta Lectura: Flujo en Contraflujo
Q=VI
Q= (170V ) (5 .5 A )
Q=935W
Q=mACpaire (T 4−T 1 )
mA=Q
Cpaire (T4−T 1)
mA=935W
1010J
Kg°C(132° C−39 °C )
mA=0.0099Kgs
∆T 1=T 4−T i
∆T 1=132 °C−23 ° C
∆T 1=109 °C
∆T 2=T 1−T o
∆T 2=39 ° C−28.5° C
∆T 2=10.5 °C
∆T DMLT=∆T 1−∆T 2
ln(∆T 1∆T 2 )∆T DMLT=
109 °C−10.5 °C
ln( 109 °C10.5 °C )∆T DMLT=42.0945 °C
Para el área del conducto:
A=L∅ π
A=(1.850m ) (0.0197m )π
A=0.1144m2
Q=UA ∆T DMLT
U= QA ∆T DMLT
U= 935W
(0.1144m2 ) (42.0945 ° C )
U=193.99 W
m2° C
Sexta Lectura: Flujo Paralelo
Q=VI
Q= (170V ) (5 .5 A )
Q=935W
Q=mACpaire (T 4−T 1 )
mA=Q
Cpaire (T4−T 1)
mA=935W
1010J
Kg°C(136 °C−39 °C )
mA=0.0095Kgs
∆T 1=T 1−T i
∆T 1=39 °C−23° C
∆T 1=16 ° C
∆T 2=T 4−To
∆T 2=136 ° C−30° C
∆T 2=106 ° C
∆T DMLT=∆T 1−∆T 2
ln(∆T 1∆T 2 )∆T DMLT=
16 °C−106 ° C
ln( 16 ° C106 ° C )∆T DMLT=47.5976 °C
Para el área del conducto:
A=L∅ π
A=(1.850m ) (0.0197m )π
A=0.1144m2
Q=UA ∆T DMLT
U= QA ∆T DMLT
U= 935W
(0.1144m2 ) (47.5976 ° C )
U=171.56 W
m2 °C