subgrade characterization for concrete pavement design
DESCRIPTION
Subgrade Characterization For Concrete Pavement Design. Fig. 2. Approximate interrelationships of soil classification and bearing values. Concrete Pavements: Slab-on-grade-type Structures. - PowerPoint PPT PresentationTRANSCRIPT
Subgrade CharacterizationFor Concrete
Pavement Design
Fig. 2. Approximate interrelationships of soil classification and bearing values
Slab is treated as an elastic plate where the response of the supporting soil medium can have considerable effect on the analysis.
The inherent complexity of real soil characterizations has led to idealized models which provide certain aspects of pavement response under specific loading and boundary conditions.
Concrete Pavements: Slab-on-grade-type Structures
P
Most Common Foundation ModelsWinkler Foundation
P(x,y)=k w(x,y)
w
Figure 1Elastic Foundation
P
(a)
Figure 2
Winkler Elastic Solid
These theories:
1. Provide significantly different responses of the pavement system.2. Represent different assumptions to characterize soil support.3. Use parameters (E and k) that have different units.
E: F/L2
k: F/L2/L
Considerable effort has been expended in attempting to establish correlation between k and Eo of the soil.
Platek
PlateEo
Winkler Elastic Solid
4k
Dk
Deflection (Concentrated load; infinitely large plate)
8DPw
2k
Subgrade Stress
2k
z 8Pσ
Bending Stress
2r r
kr
σ 6m /h
2P 1m 1 Log γ 14π γ 2
3
r 2 3o
P Ehσ 0.366 1 Log 0.266h k b
s
o 2s
Ek2 1
2eP
w 3 3D
3
e
o2o
2D;C
EC1
2e
2e
z 33P
93Pσ
Design Tip
Part II - The modulus of Subgrade Reaction, kIn our previous discussion of the AASHTO pavement design method we discussed
the influence of reliability as defined by the 1986 AASHTO Guide for Design of Pavement Structures on pavement design. The variable used in the Rigid pavement thickness determination that accounts for the amount of support supplied by the roadbed and subbase is called the Modulus of Subgrade Reaction or “k”. For this discussion the variables names and definitions we will be using are as follows:
The Roadbed Resilient Modulus, MR (psi)The Subbase Elastic Modulus, Esb (psi)The Modulus of Subgrade Reaction, k (pci)The Composite k value, kc (pci) k value on Rigid Foundations k’ (pci)Loss of Support LS (no units)
Each variable is used to describe the quality of the foundation or a factor contributing to the quality of the foundation beneath the pavement slab.
What exactly is the purpose of a foundation system? According to the AASHTO guide, a foundation system should provide a uniform, stable, and permanent support system for the pavement. The support system minimizes the damaging effects of frost action, prevents pumping of fine-grained soils at joints, cracks, and edges of the pavement slab, and provides a working platform for construction equipment. Subbase layers are frequently used to increase the total strength of the foundation system.
The determination of k of a soil according to ASTM requires the placement of a 30 inch diameter rigid steel plate on the soil and the application of a static load. Knowing the amount of weight with which the plate is loaded and the measured deflection of the plate into the soil, k can be calculated as follows:
Where:
The Pressure on the soil is equal to the loading of the rigid steel plate divided by its area.
From this calculation you can see why k is expressed in units of pounds per cubic inch, (pci). It would probably make more sense if k was expressed as pounds per square inch deflection, (psi/in2/in).
Pressure on the soilk=Deflection of the soil
The history associated with the letter notation of k goes back to basic physics. You may remember, k is the variable name of the spring constant; and when Dr. Westergaard modeled the interaction of a rigid slab resting on a soil, he treated the soil as a bed of springs with a stiffness of “k.”
With that brief history, you are probably wondering why the roadbed resilient modulus is listed? After all, it is also a property indicating the soil strength. The reason for this is that the new AASHTO Guide depends heavily on MR for the design of bitummous pavements. Many of the new mechanistic design methods use MR to characterize the strength of the soils rather than k.
Since the resilient modulus can be calculated from a laboratory test and correlated to k, the new AASHTO Design Guide uses MR. This value replaces the former Soil Support Value used to describe soil strength in the previous editions of the guide. The analytical relationship between a soils resilient modulus and it Modulus, of Subgrade Reaction is a follows:
k=MR/19.4
The actual k used in the design of concrete pavements is modified to reflect increased support resulting from frozen subgrade, high-quality subbases and loss of support to develop a “composite k” (kc).
For equal deflections:8DPw
2k
2eP
w 3 3D
3/41/3
1/3
4/3
4/32/34/3
2k
2e
k5.977DC
DC0.1673k
C28DD33k
338
From the AASHTO Design Guide
Generally, Eo =1500 CBR =1500 (5)=7500 psi
k = 385 psi/infrom PCA (OJ Porter chart), CBR=5 yields k=140 psi
In these designs, NO correlation between Eo and k is apparent
19.4Ek o
Es vs kSolid lines are for Equal Slab deflection used on slab Theory 42
50
40
30
20
10
0 0 100 200 300 400
1. Westergaard for Dense Liquid2. Hogg for Elastic Solid
h=14”
h=12”
h=10”
h=8”
AASHTO Resilient Modulus=19.4xk
Slab Thickness
k (psi/in)
E sub g
(x 1
0-3) p
si
From Boussinesq for a circular loaded area (on subgrade)
Therefore Eo and k can be correlated only if the size of the loaded area is taken into account.
Pa
rzEo
ho=
1.5akwP1.5aE
0.5for E
1.5paw
o
o
(no plate stiffness involved)
a
E,kEo constant
k constantFor a=30”/2 & k=100 Eo=2250= psi
2o o
3e
E C 1
2D C
For Ec=4,000,000 psi
c=0.15 & o=.5
C=13,896
Eo=0.75(13,896)=10,422 psi
Difference is in the slab stiffness and the effect on the loaded area.
For a concrete slab on subgrade, the size of the loaded area is a function of slab stiffness Equating max Deflection:
D33P
8DP 2
e2k
0 1 2 3 4 5 6 1 2 30
0.05
0.10
0.15
0.192
Solid) (Elast.PlDw 2
o
(Hertz)PlDw 2
o1.241ll
oo xr/l xr/l
0.125 (Hertz)
Equal Deflections
Equal Subgrade Stress
0 1 2 3 4 5 60
0.05
0.10
0.15
0.192
1 2 3id)(Elast.sol
Plp2o
(Hertz)Plp2
o0.806ll
0.125 (Hertz)
oo xr/l xr/l
Note: the rel. between l & lo is diff depending on the respondnce !
0 1 2 34 5 6
x=xo
Mt
=0.3
0
0.05
0.10
0.15
PM
Mr
Equal Bending Stress
Wester
RLE W, T, or Q: Elastic
IF we=wk : w, same max Defl
IF r= b : T, same max bending
IF z= sg : Q, Same max subgrade stress\
ESW______ : Elastic Eo
DeFES_____ : Elastic Surf. Defl
SSES______ : Elastic Subg Stress
BSES______ : Elastic layer radial E
EQRE______ : Equivalent ‘k’ (P/w)
EQRL______ : Equivalent ‘kl’
Different load area/slab stiffness relationships result from equating
• max deflection
• max subgrade stress
•max Bending stress
ConditionsSame Max Defl
Same Max B SSame Max S S
Pavement Thickness (in.)Stiffness Effect on Es vs. K
18
16
14
12
10
8
6
4
2
0 6 7 8 9 10 11 12 13 14
k=100
Soil Modulus (ksi)
*
Maximum Subgrade StressE(S) vs. h
k=50 k=100 k=200 k=400
ELA
STIC
MO
DU
LUS
OF
SOIL
(psi
)(T
hous
ands
)
6 8 10 12
1413121110
98
76
543
21
Thickness (in)
k=50 k=100 k=200 k=400
Thickness (in)
Maximum Bending StressE(S) vs. h
24232221201918171615141312111098765432 6 8 10 12
ELA
STIC
MO
DU
LUS
OF
SOIL
(psi
)(T
hous
ands
)
Maximum DeflectionE(S) vs. h
k=50 k=100 k=200 k=400Thickness (in)
6 8 10 12
45
40
35
30
25
20
15
10
5
ELA
STIC
MO
DU
LUS
OF
SOIL
(psi
)(T
hous
ands
)
Same Maximum Deflection
0
50
100
150
200
250
k= 100, 8" K=400, 8" k= 100, 12" K=400, 12"
Foundation Modulus (pci)
Pave
men
t Stre
ss (p
si)
WestergaardElastic SolidElastic Layer
Same Maximum Deflection
0
0.5
1
1.5
2
2.5
3
3.5
4
4.5
5
k= 100, 8" K=400, 8" k= 100, 12" K=400, 12"
Foundation Modulus (pci)
Subg
rade
Str
ess
(psi
)
WestergaardElastic SolidElastic Layer
Deflection-Time plots for Typical Plate
Load Test on Cohesive Soils
10 Sec 1 2 3 4 5
0.10
0.075
0.050
0.025
==DP 10K =250 psi/inW 0.040
Alternate Time Deflection Curves for Plate
P 10K= = =133 psi/inW 0.075W=0.001 inches in one min
Time, Min
Def
lect
ion,
inch
es