GROUP PBL 5NAME : NUR LUQMAN B. DZULKIFLI

(56165113176): MOHD FARIS B. MOHD YUNUS (

1. Identify the subject location.

It can be found in bengkel kerja kayu.

2. Sketch the subject body layout and identify the measurement.

4. Estimate the mass of the subject if steel density is

7850kg/m³.Ƿ = 7850 kg / mᶾ

Vol = 0.025x0.05x18.3x6 = 0.137 mᶾ

Vol2= 0.05x0.01x30.7x14 = 0.2149 mᶾ

Vol3= 0.05x0.01x8.3x12 =0.1098mᶾ

Total Vol = 0.137mᶾ + 0.2149mᶾ + 0.1098mᶾ

= 0.4617mᶾ

Ƿ = m vm = Pv = 7850 kg x 0.4617mᶾ mᶾ = 3624.35 kg

5. Draw the Free Body Diagram.

6. If the static friction coefficient, μs is 0.45, determine the drag

force require in subject movement.

In equilibrium,N = WN = mg = 3624.35kg x 9.81m/s² = 35554.8735 N

Ff = μs x N = 0.45 x 35554.8735 N = 15999.69 N

Drag force require to move the subject F required > FfF required > 15999.69 N

7. What is the necessary action to be taken in reducing the

drag force, give your reasons? To reduce the drag force of the object,

adding the nuber of the wheel should do it. The force of the object will be equally divided to all the wheel. So if we add the number of the wheel, less force will acting on all the wheel. Thus, it will help to reduce the force required to overcome the friction force to make the object move.