solving for discontinuities algebraically

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Solving for Discontinuities Algebraically 16 – 17 November 2010

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Solving for Discontinuities Algebraically. 16 – 17 November 2010. Always Factor!. The 1 st step → always factor the numerator and the denominator!!! Goal: Get matching factors in numerator and denominator. Vertical Asymptotes. Occur when the denominator equals zero . - PowerPoint PPT Presentation

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Page 1: Solving for Discontinuities Algebraically

Solving for Discontinuities

Algebraically

16 – 17 November 2010

Page 2: Solving for Discontinuities Algebraically

Always Factor!

The 1st step → always factor the numerator and the denominator!!!

Goal: Get matching factors in numerator and denominator

1

)1)(5(1

542

x

xxy

x

xxy

Page 3: Solving for Discontinuities Algebraically

Vertical Asymptotes

Occur when the denominator equals zero. Step 1: Factor the numerator and the

denominator Step 2: Set the denominator equal to zero Step 3: Solve for x Step 4: Write your answers in the form x =

Page 4: Solving for Discontinuities Algebraically

Example:

x

xx

xxy

x

xxy

1

011

)1)(2(1

22

Page 5: Solving for Discontinuities Algebraically

Your Turn:

Complete problems 1 – 5 on the “Solving for the Discontinuities of Rational Equations” handout.

Page 6: Solving for Discontinuities Algebraically

Removable Discontinuities

Occur when Shortcut!

Factors that occur in both the numerator and the denominator

0

0y

1

)1)(5(1

542

x

xxy

x

xxy

Page 7: Solving for Discontinuities Algebraically

Removable Discontinuities, cont.

Step 1: Factor the numerator and the denominator

Step 2: Identify factors that occur in both the numerator and the denominator

Step 3: Set the common factors equal to zero

Step 4: Solve for x Step 5: Write your answers in the form x =

Page 8: Solving for Discontinuities Algebraically

Example:

)2(

)2)(2(2

42

x

xxy

x

xy

2:

02

xHole

x

Page 9: Solving for Discontinuities Algebraically

Your Turn:

Complete problems 6 – 10 on the “Solving for the Discontinuities of Rational Equations” handout.

Page 10: Solving for Discontinuities Algebraically

Vertical Asymptote vs. Removable Discontinuity

Algebraically, they act similarly

Consider:

3

3

2

)2(

)2)(2(

)2(

44

x

xxy

x

xxy

Page 11: Solving for Discontinuities Algebraically

Vertical Asymptote vs. Removable Discontinuity, cont.

3

3

2

)2(

)2)(2(

)2(

44

x

xxy

x

xxy

!!!0

00

484

)22(

4)2(4)2(

2

3

3

2

y

y

y

x

Page 12: Solving for Discontinuities Algebraically

Vertical Asymptote vs. Removable Discontinuity, cont.

Think-Pair-Share

1. 30 sec – Individually think about why the equation has a vertical asymptote instead of a removable discontinuity.

2. 1 min – Talk about this with your partner.

3. Share your reasoning with the class.

Page 13: Solving for Discontinuities Algebraically

Vertical Asymptote vs. Removable Discontinuity, cont.

)2)(2)(2(

)2)(2(

)2(

)2)(2(

)2(

44

3

3

2

xxx

xxy

x

xxy

x

xxy

2:

022

1

xVA

xx

y

Page 14: Solving for Discontinuities Algebraically

Vertical Asymptote vs. Removable Discontinuity, cont.

Depends on: How many times a factor occurs Where the factor occurs

Removable Discontinuity → the multiplicity of the factor in the numerator ≥ the multiplicity of the factor in the denominator

Vertical Asymptote → the multiplicity of the factor in the numerator < the multiplicity of the factor in the denominator

Page 15: Solving for Discontinuities Algebraically

Vertical Discontinuity vs. Removable Discontinuity, cont.

Common Factor: Common Factor:

Multiplicity Greater in Numerator or Denominator?

Multiplicity Greater in Numerator or Denominator?

Type of Discontinuity: Type of Discontinuity:

1

)1)(2(

x

xxy

)8)(8)(2(

8

xxx

xy

Page 16: Solving for Discontinuities Algebraically

Your Turn:

Complete problems 11 – 15 on the “Solving for the Discontinuities of Rational Equations” handout.

Page 17: Solving for Discontinuities Algebraically

Homework

In Precalculus textbook, pg. 290: 7 – 12 Hint! You will need to use the quadratic

formula for #8.

Page 18: Solving for Discontinuities Algebraically

Horizontal Asymptotes

Occurs when the degree of the numerator ≤ the degree of the denominator

If n = m → HA:

If n < m → HA: y = 0

If n > m → HA doesn’t exist

0

0

...

...

bb

aay

m

n

b

ay

Page 19: Solving for Discontinuities Algebraically

Example 1

If n = m → HA:

If n < m → HA: y = 0

If n > m → HA doesn’t

exist

b

ay

7

372

x

xy

0: yHA

Page 20: Solving for Discontinuities Algebraically

Example 2

If n = m → HA:

If n < m → HA: y = 0

If n > m → HA doesn’t

exist

b

ay

72

1323

4

xx

xy

HA: none

Page 21: Solving for Discontinuities Algebraically

Example 3

If n = m → HA:

If n < m → HA: y = 0

If n > m → HA doesn’t

exist

b

ay

712

32423

23

xx

xxxy

3

1

12

4: yHA

Page 22: Solving for Discontinuities Algebraically

Your Turn:

Complete problems 11 – 15 on the “Solving for the Discontinuities of Rational Equations” handout.