section 3.2 polynomial functions of higher degree

Section 3.2 Polynomial Functions of Higher

Degree

What you should learn

• How to use the Leading Coefficient Test to determine the end behavior of graphs of polynomial functions

• How to use zeros of polynomial functions and the lead coefficient and end behavior to construct and graph polynomial functions.

Copyright © by Houghton Mifflin Company, Inc. All rights reserved. 3

A polynomial function is a function of the form1

1 1 0( ) n nn nf x a x a x a x a

where n is a nonnegative integer and each ai (i = 0, , n)

is a real number. The polynomial function has a leading coefficient an and degree n.

Examples: Find the leading coefficient and degree of each polynomial function.

Polynomial Function Leading Coefficient Degree5 3( ) 2 3 5 1f x x x x

3 2( ) 6 7f x x x x ( ) 14f x

-2 5

1 3

14 0


Graphs of polynomial functions are continuous. That is, they have no breaks, holes, or gaps.

Polynomial functions are also smooth with rounded turns. Graphs with points or cusps are not graphs of polynomial functions.

x

y

x

y

continuous not continuous continuoussmooth not smooth

polynomial not polynomial not polynomial

x

y f (x) = x3 – 5x2 + 4x + 4


Polynomial functions of the form f (x) = x n, n 1 are called

power functions.

If n is even, their graphs resemble the graph of

f (x) = x2.

If n is odd, their graphs resemble the graph of

f (x) = x3.

x

y

x

y

f (x) = x2

f (x) = x5f (x) = x4

f (x) = x3


Example: Sketch the graph of f (x) = – (x + 2)4 .

This is a shift of the graph of y = – x 4 two units to the left.

This, in turn, is the reflection of the graph of y = x 4 in the x-axis.

x

y

y = x4

y = – x4f (x) = – (x + 2)4


Leading Coefficient TestAs x grows positively or negatively without bound, the value f (x) of the polynomial function

f (x) = anxn + an – 1x

n – 1 + … + a1x + a0 (an 0)

grows positively or negatively without bound depending upon the sign of the leading coefficient an and whether the degree n

is odd or even.

x

y

x

y

n odd n even

an positive

an negative


Example: Describe the right-hand and left-hand behavior for the graph of f(x) = –2x3 + 5x2 – x + 1.

As , and as , xx )(xf )(xf

Negative-2Leading Coefficient

Odd3Degree

x

y

f (x) = –2x3 + 5x2 – x + 1


A real number a is a zero of a function y = f (x)if and only if f (a) = 0.

A turning point of a graph of a function is a point at which the graph changes from increasing to decreasing or vice versa.

A polynomial function of degree n has at most n – 1 turning points and at most n zeros.

Real Zeros of Polynomial FunctionsIf y = f (x) is a polynomial function and a is a real number then the following statements are equivalent.

1. a is a zero of f.2. a is a solution of the polynomial equation f (x) = 0.3. x – a is a factor of the polynomial f (x).

4. (a, 0) is an x-intercept of the graph of y = f (x).


Example: Find all the real zeros and turning points of the graph of f (x) = x

4 – x3 – 2x2.

Factor completely: f (x) = x 4 – x3 – 2x2 = x2(x + 1)(x – 2).

The real zeros are x = –1, x = 0, and x = 2.

These correspond to the x-intercepts (–1, 0), (0, 0) and (2, 0).

The graph shows that there are three turning points. Since the degree is four, this is the maximum number possible.

y

x

f (x) = x4 – x3 – 2x2

Turning pointTurning point

Turning point


Example: Determine the multiplicity of the zeros of f (x) = (x – 2)3(x +1)4.

Zero Multiplicity Behavior

2

–1

3

4

odd

even

crosses x-axis at (2, 0)

touches x-axis at (–1, 0)

Repeated ZerosIf k is the largest integer for which (x – a)

k is a factor of f (x)and k > 1, then a is a repeated zero of multiplicity k. 1. If k is odd the graph of f (x) crosses the x-axis at (a, 0). 2. If k is even the graph of f (x) touches, but does not cross through, the x-axis at (a, 0).

x

y


Example: Sketch the graph of f (x) = 4x2 – x4.

1. Write the polynomial function in standard form: f (x) = –x4 + 4x2 The leading coefficient is negative and the degree is even.

2. Find the zeros of the polynomial by factoring.

f (x) = –x4 + 4x2 = –x2(x2 – 4) = – x2(x + 2)(x –2)

Zeros: x = –2, 2 multiplicity 1 x = 0 multiplicity 2

x-intercepts: (–2, 0), (2, 0) crosses through (0, 0) touches only

Example continued

as , )(xfx

x

y

(2, 0)

(0, 0)

(–2, 0)


Example continued: Sketch the graph of f (x) = 4x2 – x4.

3. Since f (–x) = 4(–x)2 – (–x)4 = 4x2 – x4 = f (x), the graph is symmetrical about the y-axis.

4. Plot additional points and their reflections in the y-axis: (1.5, 3.9) and (–1.5, 3.9 ), ( 0.5, 0.94 ) and (–0.5, 0.94)

5. Draw the graph.

x

y(1.5, 3.9)(–1.5, 3.9 )

(– 0.5, 0.94 ) (0.5, 0.94)

1-8 A Matching

1. f(x) = -2x + 3

2. f(x) = x2 – 4x

3. f(x) = -2x2 – 5x

4. f(x) = 2x3 – 3x + 1

5. f(x) = -¼ x4 + 3x2

6. f(x) = -1/3 x3 + x2 – 4/3

7. f(x) = x4 + 2x3

8. f(x) = 1/5 x5 -2x3 + 9/5 x

10

8

6

4

2

-2

-5 5

B

A

1-8 B Matching

1. f(x) = -2x + 3

2. f(x) = x2 – 4x

3. f(x) = -2x2 – 5x

4. f(x) = 2x3 – 3x + 1

5. A

6. f(x) = -1/3 x3 + x2 – 4/3

7. f(x) = x4 + 2x3

8. f(x) = 1/5 x5 -2x3 + 9/5 x

6

4

2

-2

-4

-6

-8

-5 5

B

1-8 C Matching

1. f(x) = -2x + 3

2. f(x) = x2 – 4x

3. f(x) = -2x2 – 5x

4. f(x) = 2x3 – 3x + 1

5. A

6. f(x) = -1/3 x3 + x2 – 4/3

7. f(x) = x4 + 2x3

8. B

C

6

4

2

-2

-4

-6

-8

-5 5

1-8 D Matching

1. C

2. f(x) = x2 – 4x

3. f(x) = -2x2 – 5x

4. f(x) = 2x3 – 3x + 1

5. A

6. f(x) = -1/3 x3 + x2 – 4/3

7. f(x) = x4 + 2x3

8. B

D

8

6

4

2

-2

-4

-6

-5 5

1-8 E Matching

1. C

2. f(x) = x2 – 4x

3. f(x) = -2x2 – 5x

4. f(x) = 2x3 – 3x + 1

5. A

6. f(x) = -1/3 x3 + x2 – 4/3

7. D

8. B

E

8

6

4

2

-2

-4

-6

-5 5

1-8 F Matching

1. C

2. f(x) = x2 – 4x

3. f(x) = -2x2 – 5x

4. f(x) = 2x3 – 3x + 1

5. A

6. E

7. D

8. B

F

8

6

4

2

-2

-4

-6

-5 5

1-8 G Matching

1. C

2. f(x) = x2 – 4x

3. f(x) = -2x2 – 5x

4. F

5. A

6. E

7. D

8. B

G

8

6

4

2

-2

-4

-6

5

1-8 H Matching

1. C

2. G

3. f(x) = -2x2 – 5x

4. F

5. A

6. E

7. D

8. B

H

6

4

2

-2

-4

-6

-8

-5 5

section 3.2 polynomial functions of higher degree

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