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Final Report Long-term Wind Variability: Characteristics and Effect on Generation Bachelor of Science in Energy ROBBIE PRATT

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Final Report

Long-term Wind Variability: Characteristics and Effect on

Generation

Bachelor of Science in Energy

ROBBIE PRATT

I

NAME: ROBBIE PRATT

I.D: 12140643

SUPERVISOR: DR. DAVID CORCORAN

COURSE: B.Sc. ENERGY

YEAR: FOURTH YEAR

PROJECT TITLE: LONG TERM WIND VARIABILITY:

CHARACTERISTICS AND EFFECT

ON GENERATION

DATE: 31st March 2016

II

Author’s Declaration

I hereby declare that this project is entirely my own work, in my own words, and that

all sources used in researching it are fully acknowledged and all quotations properly

identified. It has not been submitted, in whole or in part, by me or another person, for

the purpose of obtaining any other credit/grade. I understand the ethical implications

of my research, and this work meets the requirements of the Faculty of Arts,

Humanities and Social Sciences Research Ethics Committee.

Signed: ____________________ Date: ___________

III

Abstract

This paper sets out to analyse wind speeds at a number of locations in Ireland with a

view of examining the potential for wind generation in the south west of the island.

The wind index was used to provide indications of the average wind speeds at

Valentia, Shannon Airport, Birr, Dublin Airport and Malin Head. Statistical analysis

(null hypothesis) was then used to show that mean wind speed is showing a

downward trend at Valentia and Shannon Airport (both located in SW Ireland). Wind

index results from a study of UK locations (Watson et al.) were used to provide a

composite Ireland/UK correlation to produce confidence in the Irish data. The student

T-test was used to show a relationship between locations in corresponding Ireland/UK

regions with the highest confidence seen in the regions of the extreme SW of the

islands such as Valentia in Ireland.

Examination of the NAO was undertaken using the student T-test to explore if this

could be a cause of the decreasing trend at Valentia. The p-value was found to be

greater than the significance level and this indicates that there is a relationship.

The economics of wind energy production in the south west of Ireland, based on the

wind data within this paper, were looked at using the example of the 1MW turbine.

With infrastructure costs of €1.23m, 1798MWh of energy produced per annum, and

revenue of €72.167 per MWh a payback period of 9.53 years was calculated.

Weibull distribution was used for Valentia data over 20 and 50 year periods and the

distribution correlated with the experimental data within the relevant range.

IV

Nomenclature

Symbol Description A Area

α Hellmann’s power law exponent, typical value 1.7

c Scale parameter for the Weibull distribution

𝑐𝑡′ Adjusted intercept at height h

CF Coriolis Force

d Distance between two points

𝐹𝑥 Net force in the x direction

𝐹𝑐 Centrifugal force (Coriolis parameter)

𝐹𝑋 Component of net force

H Height of measured mast

i Hour index

k Shape parameter for the Weibull distribution

Ke Kinetic Energy

km Kilometre

m Mass

m/s or m s1 Meters per second

m Metre

mm Millimetre

𝑚𝑡′ Adjusted slope at height h

MWh Mega Watt hour N Number of hours in a year

NAO North Atlantic Oscillation

PGF Pressure gradient force

RET’s Renewable energy targets

𝑅2 The confidence in the trend analysis

SST Sea surface temperatures

TD Turbulent drag

UK United Kingdom

U Wind component toward east

𝑈𝐻 Average wind speed at H meters above ground

𝑈𝑧̅̅ ̅ Average wind speed at z meters above ground

v Velocity

𝑣𝑌 Average wind speed for the year (m/s)

�̅�𝑦 Average wind speed over a number of years

𝑣𝑦𝑖𝑛𝑑 Wind speed index

𝑉3̅̅̅̅ The cube of the mean of the wind speeds

(𝑣)̅̅ ̅̅ .3 The cube of each wind speed

(𝑣𝑡′̅̅̅̅ ) Adjusted wind speed at height h

𝑤𝑡 Turbulent transport velocity.

y Years index

Z Depth

z Height where wind speed is being predicted

𝑍𝑜 Roughness length scale

°C Degrees Celsius

Δ𝑝 Pressure difference between two places

V

~ Approximately

φ Latitude

% Percentage

≠ Not equal to.

Γ Gamma function

ρ Density

∆𝑡 Change in time

𝜏𝑝 Payback period

Table of Contents

Author’s Declaration .......................................................................................................... II

Abstract ............................................................................................................................. III

Nomenclature ................................................................................................................... IV

Chapter 1: Introduction ............................................................................................................. 1

Chapter 2: Climate of Ireland ..................................................................................................... 2

Ireland ................................................................................................................................ 2

Prevailing winds ................................................................................................................. 3

Chapter 3: Origin of the Wind ................................................................................................... 5

Advection ........................................................................................................................... 5

Pressure Gradient Force .................................................................................................... 5

Coriolis Effect ..................................................................................................................... 6

Turbulent drag force .......................................................................................................... 8

The Jet Stream ................................................................................................................... 9

The North Atlantic Oscillation ............................................................................................ 9

Cyclones ........................................................................................................................... 10

Polar front ........................................................................................................................ 11

Chapter 4: Literature Review ................................................................................................... 13

Climate Change ................................................................................................................ 13

North Atlantic Oscillation ................................................................................................. 14

Surface roughness ............................................................................................................ 14

Chapter 5: Methodology .......................................................................................................... 16

Wind index method ......................................................................................................... 16

Statistical hypothesis testing ........................................................................................... 18

Student T-test .................................................................................................................. 19

Confidence (𝑅2) ............................................................................................................... 19

Velocity scaling with height ............................................................................................. 20

Power in the wind ............................................................................................................ 21

Weibull Distribution ......................................................................................................... 22

Chapter 6: Results and Analysis (Irish Data) ............................................................................ 25

Irish Data ......................................................................................................................... 25

Payback period for a turbine at Valentia ......................................................................... 28

Comparing geographical regions in Ireland ..................................................................... 31

Chapter 7: Irish data Compared with the UK (Watson Data) .................................................. 37

Comparison with Watson ................................................................................................ 37

UK data comparison with Ireland .................................................................................... 39

Payback period for a turbine in the SW of the UK ........................................................... 42

Chapter 8: Irish data compared with the NAO ........................................................................ 45

Comparing the NAO with Wind speeds in the south west of Ireland (Valentia) ............. 45

Future predictions for the NAO ....................................................................................... 48

Chapter 9: Irish data compared with the Weibull Distribution ................................................ 49

Chapter 11: Conclusion............................................................................................................ 56

Bibliography ....................................................................................................................... a

Appendix ............................................................................................................................ A

1

Chapter 1: Introduction

With Ireland’s 2020 Renewable energy targets (RET’s) deadlines looming, the

country’s geographical location and climate means wind represents the most abundant

source of potential “non-carbon” energy production. Failure to meet the 2020 targets

would mean significant penalties being imposed by the European Commission.

This project investigates the long-term wind variability in the south west of Ireland

with a view to determining its effect on the potential of power generation by wind.

The paper will initially look at the origin of the wind and at the physical and

geographical factors that cause it to blow. By using historical data and statistical tools

such as the wind index method, valuable information on potential power generation

and associated financial returns can be produced. Data specific to Ireland will be

analysed in detail in order to produce geographically relevant results.

The primary aim of this paper is to ascertain whether the wind speed in the south west

of Ireland is reducing or increasing. The findings will serve to inform future

investment decisions in wind energy in Ireland. These decisions will influence some

of the major national strategic choices for both the energy sector and the government

in the years ahead.

2

Chapter 2: Climate of Ireland

In this chapter of the paper the climate of Ireland will be examined. This will be done

by looking at its geographic location and how this influences the climate as well as its

prevailing south westerly winds.

Ireland

Ireland is situated in the northern hemisphere in the north-western fringe of Europe at

the latitude 51-56°north and longitude 5-11°west. The North Atlantic drift has a

significant effect on the sea temperatures and hence the climate of Ireland. This

influence is greatest near the Atlantic coasts and decreases with distance travelled

inland. The main influence on the Irish climate is the Atlantic Ocean which surrounds

the island of Ireland. Due to the location, Ireland doesn’t suffer from extremes in

temperatures, precipitation or wind speeds. This cannot be said for many other

countries lying on the same latitude as Ireland. Ireland has a cool temperate oceanic

climate and its topography is varied. Hills and mountains near the coasts provide

shelter from the oceans. Summers tend to be mild and calm and winters tend to be

cold and windy.

In the extreme south-west at Valentia the mean temperature in January is 7°C and in

July the mean temperature is 15°C. Around Dublin the winter months are cooler at a

mean of 4.5°C in January and slightly warmer in summer at 15.5°C in July. The

average annual temperature in Ireland is ~9°C. In the east of the country temperatures

tend to be cooler due to the influence of the Atlantic Ocean and the prevailing winds

in the west. Nolan et al. (2011) commented on Ireland’s ideal location to exploit the

wind, with an ideal range from 6 to 8 m s-1 at 50 metres above the ground. These

wind speed values are sufficient for extracting a significant amount of power from the

wind with current wind power technology. In Ireland strong winds tend to be more

3

frequent in winter than in summer. Sunshine duration is highest in the southeast of the

country. Average rainfall varies between about 800 and 2,800mm. Rainfall figures are

highest in the northwest, west and southwest of the country, especially at the higher

altitudes. Rainfall accumulation tends to be highest in winter and lowest in early

summer.

Ireland’s climate is changing and this is true on a global level. Over the last century

there have been major changes in sea level rising and earth’s average surface area

temperature is increasing. This has major effects on the climate of Ireland. When

wind is being examined the direction and speed are the biggest factors. Globally

accurate wind speed data only goes back 10-20 years. In Ireland wind speed data has

been kept as far back as 1945. Advances in technology have improved the

measurement of wind but it is still difficult to predict long-term trends due to not

having accurate wind speed measurements in the distant past. Wind speed is measured

with a device called an anemometer which uses rotating cups. A weather vane is used

to indicate the wind direction.

Prevailing winds

Prevailing winds are winds from the direction that is predominant or most usual at a

particular place or season. In Ireland this is in a south-

westerly direction. The fundamental cause for these

prevailing winds is due to the energy balance between

the equator and the poles. In the region called the

doldrums (lies around the equator) hot air rises up due

to the enormous amount of latent heat. The air becomes more buoyant. When the air

reaches the tropopause it begins to move laterally towards the poles. At this point the

Coriolis Effect causes the wind to apparently deflect due to the earth’s rotation. In the

4

northern hemisphere this deflection takes place to the right giving Ireland its

prevailing south-westerlies. The wind rose above shows the dominance of the wind

from the south-west at Valentia between the years 1980-2010.

In this chapter of the paper it can be seen that the predominant south westerly winds

and the Atlantic Ocean have a major effect on the climate of Ireland. In the next

chapter of this report the factors that cause the wind to blow will be examined.

5

Chapter 3: Origin of the Wind

In this chapter of the report the origin of the wind will be examined and the forces that

affect the wind will be looked at. These are advection, pressure gradient force,

Coriolis force and turbulent drag force. Also phenomena such as the jet stream, North

Atlantic Oscillation (NAO), cyclones and the polar front will be explored.

Advection

There are two types of advection: cold advection and hot advection. Cold advection is

the movement of air from a region of cold air to a region of hot air. Warm advection

is the opposite and it is the movement of warm air by the wind from a region which

has hotter air to a region which has colder air.

Pressure Gradient Force

The pressure gradient force is a force that causes the wind to blow due to difference in

pressure over a distance. The air moves from the area of higher pressure to the area of

lower pressure. A large change in pressure over a short distance is called a steep

pressure gradient and a small change in pressure over a long distance is a weak

pressure gradient.

The formula for PGF is given below:

𝑃𝐺𝐹= ΔP

𝑑 Equation 3.1

Where,

Δ𝑝 = pressure difference between two places

𝑑= distance between the two places.

The pressure gradient force is the only force that can drive the horizontal winds.

Pressure gradient force always acts at right angles to the isobars on a weather map.

6

The force exists regardless of the wind speed and is independent of wind speed. It

starts the horizontal wind, and can accelerate, decelerate or change the direction of

existing winds. The closer spaced isobars on a weather map indicate greater force.

Coriolis Effect

The Coriolis Effect is a fictitious force. It is

an apparent deflection of the path of an

object that moves within a rotating

coordinate system. The object does not

actually deviate from its path, but it appears

to do so because of the motion of the

coordinate system. It was mentioned in chapter 2 that the movement of the air from

the doldrums to the poles was due to the huge amount of latent heat build-up which

causes the hot air to rise to the tropopause before moving laterally towards the poles.

When this air is moving towards the poles the Coriolis force takes place. Winds blow

across the earth from surface high- pressure systems (warm air) to low pressure

systems (cool air), but this does not happen in a straight line. The Coriolis Effect is

the inertial force in which the winds move around the world due to the Earth rotating

eastwards. The velocity is greater at the equator and near zero at the poles due to the

circumference difference. So essentially the earth must move faster at the equator than

the pole in 24 hours to do one rotation and complete a day. This causes a deflection to

the left in the southern hemisphere and to the right in the northern hemisphere. This

results in a curved path. The Coriolis deflection is therefore related to the motion of

the object, the motion of the Earth, and the latitude.

7

The Coriolis force is defined as:

𝐹𝑐 = 2𝑥Ωxsin(φ) Equation 3.2

Where,

φ = Latitude.

2𝑥Ω= 1.458x10−4𝑠1

In the Northern Hemisphere it is:

𝐹𝑦 𝐶𝐹

𝑚= 𝐹𝑐𝑣 Equation 3.3

Where,

𝐹𝑥= Net force in the x direction

𝐶𝐹= Coriolis force

𝐹𝑐= Centrifugal force (Coriolis parameter)

m = mass

v = velocity

Ireland is located in the north-hemisphere. It can be said that the Coriolis Effect has a

drastic effect on the climate and the wind direction. Coriolis force only changes the

direction of the wind. It doesn’t create the wind.

8

Turbulent drag force

Turbulent drag force is a force acting in the opposite direction to the motion of the

fluid. This slows down the wind as it goes across obstacles such as landmass. This

drag decreases with height up into the atmosphere and wind speed. The atmospheric

layer affected by friction reaches about 1000m into the air and is known as the friction

layer. Wind speeds tend to be higher above this zone.

The wind blows across the isobars towards lower pressure due to the pressure gradient

force no longer balancing the Coriolis force. The angle at which the wind blows

across the isobar is about 30 degrees. The angle at which the wind blows across the

isobar depends on the height above the ground, surface friction and the wind speed.

The turbulent drag force on a boundary layer of depth Z is:

𝐹𝑦𝑥𝑇𝐷

𝑚= −𝑤𝑡

𝑈

𝑍 Equation 3.4

Where,

𝐹𝑋 = component of net force

TD= turbulent drag

m = mass

U = wind component toward east

Z = depth

𝑤𝑡= is the turbulent transport velocity.

9

The Jet Stream

The forming of the jet stream is due to heated air from the equator rising and when

this air meets the tropopause it begins to move laterally in the direction of the Arctic.

It will move poleward and due to the spherical shape of the earth the radius decreases

due to the axis of rotation becoming closer. The change in radius means the air must

speed up. The air must move faster to the east than air which is close to the surface.

This leads to the strong south westerly winds which are very common in Ireland. The

jet stream associated with Ireland and which has a major effect on the climate is the

Polar front Jet stream. They can be up to 15km in length and a few kilometres wide.

The Jet Stream directly affects Ireland as it is located at the same latitude as Ireland.

The Irish Independent wrote “In any given year, the jet stream flows generally

between the latitudes of 40 degrees north and 70 degrees north.” In January and

February 2014 it was located just over the south of Ireland and so Ireland, especially

the south and south west, “was battered by its eighth storm in a little over 10 weeks

yesterday” (The Independent 13/02/2014)

The North Atlantic Oscillation

The North Atlantic Oscillation is a reversal of pressure over the Atlantic. It has an

effect on the climate of Northern Europe, hence, Ireland. It is caused by the change in

pressure between the Icelandic low and the Azores high. There are two phases to the

NAO, the positive phase and the negative phase. For the positive phase the pressure at

the pole drops and the pressure at the Azores rises causing a huge pressure difference

between the regions and this strengthens the westerlies. These stronger winds cause

strong cyclones which move over northern Europe. For the negative phase the

pressure at the pole rises and pressure drops at the Azores. This change is pressure

10

weakens the westerlies and fewer storms move across the Atlantic. Due to this winters

tend to be cold and dry in northern Europe. The NAO is not periodical and hence it

doesn’t have to stay in one phase for a prolonged time. It also varies from year to

year. It can stay in one phase for several years. Over the last 30 years the NAO has

been more in the positive phase than the negative.

In the winter of 2009/10 the NAO was strongly negative over Ireland and Ireland had

a very cold winter and the average wind speed for the year was at an all-time low

across the country.

Cyclones

A cyclone is an area of closed, circular fluid motion rotating in the same direction as

the Earth. The lows are centres of low pressure and form in the middle latitudes. This

is usually characterized by inward spiralling winds that rotate counter clockwise in the

Northern Hemisphere and clockwise in the Southern Hemisphere of the Earth due to

the Coriolis Effect. The effects of cyclones (low in pressure) in Europe include strong

winds and heavy rainfall. The highs are centres of high pressure and are called

anticyclones. “Ireland’s climate is heavily influenced by the North Atlantic Ocean. As

sea surface temperatures (SST) are projected to rise due to global warming the impact

on cyclone activity is investigated using two pairs of climate simulations performed

with the Rossby Centre regional climate model RCA3. The results show an increase

in the frequency of the very intense cyclones with maximum wind speeds of more

than 30 m/s, and also increases in the extreme values of wind and (around Ireland)

precipitation associated with the cyclones. This will translate into an increased risk of

storm damage and flooding, with elevated storm surges along Irish coasts.”

(http://www.met.ie/publications/irelandinawarmerworld.pdf)

11

Polar front

The polar front is a front in the northern hemisphere which affects the climate of

Ireland. The polar front is a zone of transition between warm air from the tropics

which is moving northwards and air moving southwards which is colder, drier and

denser from the pole. The polar front is one of the main factors which influence the

weather Ireland gets on a day in, day out basis. As the mild weather that crosses

Ireland from a South-westerly direction continues northwards, it encounters cold air

which is moving from the north. These two masses of air travelling in different

directions do not mix. They are then separated by a boundary layer called the polar

front which is a zone of low pressure. In these zones of low pressure, Ireland gets

cloudy, humid weather with rain, followed by brighter, colder weather. This is typical

of the Irish climate. Ireland's climate is varied and Ireland experiences a range of air

masses but air masses of polar origin are the most common and have a very long track

over the Atlantic Ocean. Even winds in the south-westerly direction can give Ireland

polar air. Air direction from the middle latitudes and from the north are uncommon

which means Irelands weather is varied but it doesn’t range drastically.

Warm fronts are followed by a cold front and the cold front catches up with the warm

front and an occluded front forms. When this occurs, the warm air is separated

(occluded) from the cyclone.

"In general the Atlantic low-pressure systems are well established by December, and

depressions move rapidly eastward in December and January, bringing strong winds

with appreciable frontal rainfall to Ireland. Occasionally the cold anticyclone over

Europe extends its influence westwards to Ireland, giving dry cold periods lasting

several days."

12

Ireland’s climate is dynamic. Its location makes it an ideal candidate for wind energy.

To understand the wind variability in Ireland we must go further afield and look at the

global wind patterns and effects such as the Coriolis Effect (which gives a better

understanding of the wind patterns in northern Europe), the prevailing winds and why

these winds move through space in the way they do. Power from the wind varies on

all time-scales, seconds, months, decades etc. In this study we are going to look at the

long term trends over northern Europe, Ireland and more precisely the south west of

Ireland.

13

Chapter 4: Literature Review

Watson et al. (2015) mentioned that knowledge of wind speed variability is important

for wind farm developers and operators so that there is a minimum long term risk of

fluctuation to wind speeds and revenue. During the last decades the general trend in

the northern hemisphere’s wind speed is a decreasing one Widén et al. (2015). The

reasons for this are not fully clear but there are some theories of why it is happening.

Climate Change

Nolan et al. (2011) suggests climate change may be a factor to consider in the

variability of wind speed in the future of Ireland. Future predictions show 4 to 10%

more energy available in the wind during winter and 5 to 14% less during summer

months at 60m above sea level and this represents an overall drop in wind speed over

the island of Ireland if we look at it annually. (But this could also be due to the North

Atlantic Oscillation phase shift.) The figures were calculated using the Kolmogorov-

Smirnov test using past wind speed data. A possible reason for the unevenly

distributed wind speed may be due to an increase in cyclone activity. Intense cyclones

developing in the North Atlantic Ocean are thought to increase in the winter months

and to decrease in the summer months. The future wind speed predictions correlate

with the cyclone activity. A cause for these cyclones which have increased intensity

could be an increase in moisture supply due to increasing sea water temperatures and

the increase in latent heat flux would mean an increase in the intensity of cyclones.

Watson et al. (2015) uses the wind speed index method and reviews a period of 18

years from 1983-2011 in the UK looking at 6 different stations located across the

country. From his finding, a decrease in wind speed is seen in five of the six stations.

14

Like Nolan et al. Watson found that the largest decrease in wind speeds occurred in

the winter months and smallest in the summer months. When looking at the wind

speed data we must take into account that the instrument measurement may be a

factor due to there being significant changes in the height that measurements were

taken at the different stations. The correlation of the wind speeds to 10m above the

ground is a factor to take into consideration when looking at the results.

North Atlantic Oscillation

Earl et al. believes there is a significant correlation between variability in the wind

speed fluctuation and the North Atlantic Oscillation (NAO). He looked at the south

westerly winds in the UK for the year 1986 and saw that there was a correlation

between the wind speeds of certain months when the strong positive NAO was

present over the Atlantic Ocean. This holds true the possibility that the NAO is

positively correlated with the variability in the wind. A more recent observation

would be the winter of 2009/10 which had a very negative NAO and because of this

extremely low wind speeds for those months were observed in Ireland and the UK. In

the UK when the NAO is in its positive state winds are strong and predominantly in

the south west direction and in periods when the NAO is in a strong negative trend the

speeds are reduced and wind direction is very much varied and predominantly from

the north east (Earl et al).

Surface roughness

Vautard et al. (2010) found a correlation between increased surface roughness and

decrease in wind speed at a height of 10m from the ground between the years 1979-

2008 in the Netherlands. Wever (2011) also observed the surface roughness in the

15

Netherlands and looked at the impact of increased urbanisation, forest area, increase

in agriculture and tall crops such as corn. He recorded a yearly decrease in annual

mean wind speeds of 3.1 percent between 1981 and 2009.

Bakker et al. (2010) suggests that the climate has always been subject to change. The

climate of northwest Europe has not structurally changed over the previous 100/200

years. Between the 1960s and the mid-1990s Europe saw a large increase in wind

speeds and these trends have always happened. There are fluctuations but this applies

to climates all over the world. Bakker mentions the Hurst phenomenon and how

similar events such as drought or extremes in temperatures seem to occur in patterns

and cycles.

There is evidence to support that wind speeds in the north west of Europe are

decreasing. Why this is happening is not certain. There are many different thoughts on

what is setting this downward trend, especially over the last 20 years - surface

roughness, North Atlantic Oscillation and climate change to list a few. Wind data has

been analysed using different methods such as wind index, Hurst phenomenon etc. In

this paper the wind index method will be used as a means of analysing wind data and

providing an indication of the mean wind speed. Wind data on an annual basis will be

used following the same method used by Watson et al. (2015)

16

Chapter 5: Methodology

The wind data used in this report will be sourced from Met Éireann weather stations

across the country. (Alternative data will be used when looking further afield in the

UK and Northern Europe) The wind data from Met Éireann is divided into intervals of

1 hour averages. This chapter will show how the data will be analysed. The Methods

that will be used are the wind indices method and statistical hypotheses testing. Other

methods such as the Weibull distribution method will be looked at, at a later period

following completion of this paper.

Wind index method

A wind index provides an indication of the average (mean) wind speed. It is a

statistical tool that can be used to look at the long-term wind speed trend of a region.

This is usually done using regular intervals to perform the analysis on a monthly or

yearly timescale. The wind index is used as a reference wind speed when looking at

long term production Atkinson et al. (2005).

The wind speed index can also be used to provide a financial estimate of the return on

a wind farm. An increase or decrease in power available in the wind will have a major

effect on power production. The trends in the wind are very important due to wind

farms having life spans of up to 40/50 years and climates can significantly change

over a much shorter period. Estimating the energy production of the wind farm in the

future is possible when analysis of the past trends has been done. Watson et al.

(2013).

17

To calculate the wind speed index ideally wind speed data which is taken hourly for a

few years will be used in the calculation. Firstly the mean wind speed for each year

must be found by using the following equation:

𝑣𝑦 = 1

𝑁∑ 𝑣𝑖𝑦

𝑁

𝑖=𝑗 Equation 5.1

Where,

N= the number of hours in a year (hr)

𝑣𝑌= the average wind speed for the year (m/s)

i= is the hour index

y= is the year index

Next the average of all the years in the index must be calculated using the following

equation.

�̅�𝑦= 1

𝑁∑ 𝑣𝑦

𝑥 𝑒𝑛𝑑

𝑥 𝑠𝑡𝑎𝑟𝑡 Equation 5.2

Where,

�̅�𝑦=is the average wind speed over 𝑁𝑦 years

18

Finally the average wind speed of each year is divided by the average of all the years

in the period to get the wind index value. Formula is below:

𝑣𝑦𝑖𝑛𝑑𝑒𝑥 =

𝑣𝑦

�̅�𝑦 Equation 5.3

Where,

𝑣𝑦𝑖𝑛𝑑= the wind speed index

The aim of this paper is to look at the variability of wind speed in the south west of

Ireland. The wind index will be used to analyse data both at a national level and a

regional level and will be used to compare with indices from other locations in the

North West of Europe.

Statistical hypothesis testing

A statistical hypothesis test is a method in statistics which allows the analysis of

underlying distribution by analysing data. Two statistical data sets will be compared.

In each case a hypothesis is proposed for the statistical relationship between the two

data sets. The comparison is said to be significant if the relationship between the two

data sets would be an unlikely outcome of the null hypothesis. Hypothesis tests are

used in determining what outcomes of a study would lead to a rejection of the null

hypothesis.

To be able to reject a hypothesis the p-value must be looked at. The p-value is given

as the probability of receiving a result equal to or greater than what was actually

viewed. Before the test is performed, a threshold value is chosen. This is the

19

significance level of the test and this will be 0.05 for this paper and given the symbol

α (alpha).

If the p-value is less than the required significance level, then we say the null

hypothesis is rejected at the given level of significance. Rejection of the null

hypothesis is a conclusion.

If the p-value is not less than the required significance level then the test has no result.

The evidence is insufficient to support a conclusion.

Student T-test

This statistical method is used to see if two samples of data are significantly different

from each other. Like the hypothesis testing, the student t-test relies on the p-value

and a significance level which it must achieve or not achieve to be rejected or

accepted. The hypothesis states that both slopes are not equal. If the p-value is less

than the significance level, then the null hypothesis is rejected. This means the slopes

are deemed to be similar. If the p-value is greater than the significance level, then the

null hypothesis is accepted. This means are not similar.

Confidence (R^2)

The confidence interval describes the certainty associated with the statistical method

used. The value of R falls between 0 and 1. A value nearer to 1 means it can be said

that the sampling method used is of a high confidence. If the value falls towards 0 it

can be said that the sampling method used is of a low confidence.

20

Velocity scaling with height

In this project, Hellmann’s Power Law will be as a way of scaling height from the met

mast to the height of the turbine. This in turn will give the wind speed at the given

height of the tower and from this we can calculate the power in the wind at that

height. The following formula is used for this calculation:

• Hellmann’s Power Law:

𝑈𝑧̅̅̅̅

𝑈𝐻= (

𝑧

𝐻) .∝ Equation 5.4

• 𝑧 – Height where wind speed is being predicted

• 𝐻 – Height of measurement mast

• 𝑈𝑧̅̅ ̅– Average wind speed at z meters above ground

• 𝑈𝐻 – Average wind speed at H meters above ground

• 𝛼 – Hellmann’s power law exponent, typical value 1.7

Another way to scale the wind speed at different heights is by using the velocity

scaling with height method which uses logs. The Equation is as follows:

𝑈𝑧

𝑈𝐻 =

𝑙𝑛(𝑍

𝑍𝑜)

𝑙𝑛(𝐻

𝑍𝑜) Equation 5.5

Where,

�̅�𝑧= Average wind speed at Z meters above ground

�̅�𝐻= Average wind speed at H meters above ground

𝑍= Height where wind speed is being predicted

21

𝑍𝑜= Roughness length scale

𝐻= Height of measure mast

Power in the wind

The power in the wind is the maximum theoretical power available in the wind at a

given velocity. The equation for instantaneous power:

Power max available= 1

2ρA𝑣3𝑐𝑝 Equation 5.6

Where,

ρ= The density of air

A= The swept area of the turbine

𝑣3= The average of the wind speeds cubed

𝑐𝑝= The power efficiency of the turbine. This is given as a maximum of 0.59 (Betz

Limit)

The Equation for the average power is given in equation 5.8 below:

𝑃𝑎𝑣𝑔 = 1

2ρA𝑉3̅̅̅̅ ≠

1

2ρA(𝑣)̅̅ ̅̅ .3 Equation 5.7

𝑃𝑎𝑣𝑔 = 1

2ρA(𝑣)̅̅ ̅̅ .3Ke Equation 5.8

22

Weibull Distribution

The Weibull distribution is a mathematical equation which is a statistical tool used in

describing statistics and in this case wind data. It was designed for wind data but it is

good at modelling this, but is not perfect. It is a two parameter function, k which is a

unit less shape factor and c which is the scale parameter in m/s. The two parameters

determine at what speed the turbine in the case is likely to operate and to show the

optimum wind speed for optimum performance.

The Weibull Cumulative Distribution Function, F (V) is given as;

𝑓(𝑣) = 𝑑𝐹(𝑣)

𝑑𝑣= (

𝑘

𝑐) (

𝑣

𝑐)

𝑘−1

exp [− (𝑣

𝑐)

𝑘

] Equation 5.9

v – Is the wind speed and is a variable.

k– Is the shape parameter

c – Is the scale parameter

Cumulative distribution function is the integration of the Weibull density function. It

is the cumulative of relative frequency of each velocity interval.

𝐹(𝑉) = ∫ 𝑓(𝑉)𝑑𝑣∞

𝑣 Equation 5.10

𝑜𝑟 𝐹(𝑉) = 1 − exp [− (𝑣

𝑐)

𝑘

]dv Equation 5.11

The graph is constructed in such a way that the cumulative Weibull distribution

becomes a straight line, with the shape factor k as its slope. Taking the logarithm of

both sides, the expression of Equation can be rewritten as:

23

1 − 𝐹(𝑣) = exp (−𝑣

𝑐)

𝑘

Equation 5.12

All these distributions are used to determine the probability of occurrence. The nature

of the occurrence affects the shape of the probability curve, and in the case of the

wind regime, the cumulative curve probability nature mostly fits to the Weibull

Function. Several methods to estimate Weibull factors are found in the literature.

Some of these methods are: (1) Graphical method (GM);

ln(1 − 𝐹(𝑣)) = − (𝑣

𝑐)

𝑘

Equation 5.13

ln (− ln(1 − 𝐹(𝑣)) = 𝑘𝑙𝑛(𝑣) − 𝑘𝑙𝑛(𝑐) Equation 5.14

The above equation represents a relationship between ln(v) and −ln{1 − F(v)}.

Therefore, the horizontal axis of this plot on the Weibull paper is v while the vertical

axis is ln(1 − F(v))−1 . The result is a straight line with slope k. For v = c, one finds

F(v) = 1 − e −1 = 0.632 and t an estimation for the value of c, by drawing a horizontal

line at F(v) = 0.632. The intersection point with the Weibull line gives the value of c.

The Weibull Probability Density Function, P, is given as:

𝑃(𝑉) = (𝑘

𝑐) (

𝑣

𝑐)

𝑘−1

exp [(𝑣

𝑐)

𝑘

] 𝑑𝑣 Equation 5.15

𝑃(𝑉) = ∫ 𝑃(𝑉)𝑑𝑣∞

𝑣 Equation 5.16

24

To find the average velocity, V, the more generic form of the Weibull distribution will

be used. It can be seen in Equation 5.17 below:

𝑣 ̅ = ∫ 𝑉.𝑃(𝑉)𝑑𝑣

∞0

∫ 𝑃(𝑉)𝑑𝑣∞

0

Equation 5.17

So 𝑣 ̅ = ∫ 𝑉 (𝑘

𝑐) (

𝑣

𝑐)

𝑘−1

exp [(𝑣

𝑐)

𝑘

] 𝑑𝑣∞

0 Equation 5.18

�̅� = ∫ 𝑃(𝑉)𝑉𝑑𝑣∞

0 Equation 5.19

�̅�3 = ∫ 𝑃(𝑉)𝑉3∞

0𝑑𝑣 Equation 5.20

�̅�3 = 𝑐3Γ( 1 +3

𝑘) Equation 5.21

Equation 5.21 is used to predict the cube of the wind speed at a particular height. The

kinetic energy can be got from this by dividing by the mean wind speed (�̅�)3 as

shown in Equation 5.22.

𝑘𝐸=𝑣3̅̅̅̅

(𝑣̅̅ ̅3)=

𝑐3Γ(1+3𝑘

)

[Γ(1+1𝑘

)].3

Equation 5.22

25

Chapter 6: Results and Analysis (Irish Data)

In this chapter wind data from Met Éireann is analysed at five locations around

Ireland. These locations are Malin Head, Birr, Shannon Airport, Valentia and Dublin

Airport.

Irish Data

Figure 6.1: The wind index at Valentia from 1939-2012

Figure 6.2: The wind index at Shannon Airport from 1945-2013

Figure 6.3: The wind index at Malin Head from 1955-2011

0.7

0.9

1.1

19

39

19

42

19

45

19

48

19

51

19

54

19

57

19

60

19

63

19

66

19

69

19

72

19

75

19

78

19

81

19

84

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87

19

90

19

93

19

96

19

99

20

02

20

05

20

08

20

11

Win

d In

dex

Year

Wind Index at Valentia

0.75

0.85

0.95

1.05

1.15

1.25

19

45

19

48

19

51

19

54

19

57

19

60

19

63

19

66

19

69

19

72

19

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19

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19

81

19

84

19

87

19

90

19

93

19

96

19

99

20

02

20

05

20

08

20

11

Win

d In

dex

Year

Wind Index at shannon Airport

0.70.80.9

11.11.2

Win

d In

dex

Year

Wind Index at Malin Head

26

Figure 6.4: The wind index at Birr from 1955-2009

Figure 6.5: The wind index at Dublin Airport 1941-2012

Table 6.1: Summary table of parameters from Figure 1-5

(i)Rejection of the null hypothesis- The null hypothesis states that the slope is zero at any given

location. That is if the p-value is below the significance level; alpha of 0.01, then the null hypothesis

can be rejected. If it is above this figure of 0.01 it cannot be rejected.

0.75

0.95

1.15

1.35

Year

s

19

55

19

57

19

59

19

61

19

63

19

65

19

67

19

69

19

71

19

73

19

75

19

77

19

79

19

81

19

83

19

85

19

87

19

89

19

91

19

93

19

95

19

97

19

99

20

01

20

03

20

05

20

07

Win

d In

dex

Year

Wind Index at Birr

0.750.850.951.051.151.251.35

19

41

19

44

19

47

19

50

19

53

19

56

19

59

19

62

19

65

19

68

19

71

19

74

19

77

19

80

19

83

19

86

19

89

19

92

19

95

19

98

20

01

20

04

20

07

20

10

Win

d In

dex

Year

Wind Index at Dublin Airport

Location Wind Index change per (year-1)

Mean wind speed (ms-1)

Change in mean wind speed per year (ΔV/ΔT) (ms-1/yr.)

P- value Is there a trend

using the

statistical

hypothesis test?

Confidence (R^2)

Valentia -0.0023 5.29 -0.012 8.67173E-07 Yes 0.2871

Shannon Airport -0.0032 5.00 -0.016 2.25259E-11 Yes 0.4895

Birr -0.0016 4.91 -7.856E-3 0.083282 No 0.0545

Dublin Airport -0.0004 5.30 -2.12E-3 0.452785 No 0.0081

Malin Head 0.0009 7.81 7.029E-3 0.094182 No 0.0275

27

Table 6.1 above shows the results for the individual locations across Ireland. These

locations are Valentia, Shannon Airport, Birr, Dublin Airport and Malin Head. The

slope, mean wind speed, p-value, rejection of the null hypothesis and confidence are

included.

In four out of the five locations we can see a decreasing trend. Malin Head is the

exception to this with a slight increase in wind speed over the duration observed. The

mean wind speeds for the four locations are all about 5 m/s speed. Malin Head is

much higher at 7.81 m/s. The decrease in wind speed is quite substantial for Valentia

and Dublin at -0.012 ms-1/yr and 0.016 ms-1/yr respectively.

A null hypothesis was conducted on all five locations. This hypothesis stated that the

slope is zero at any given location and only if the p-value is below the significance

level; alpha of 0.01, then the null hypothesis can be rejected. If it is above this figure

of 0.01 it cannot be rejected. When the null hypothesis was performed on the five

locations only Valentia and Shannon had a significant downward slope meaning that

there is a trend. Next the confidence in the trend lines was examined. From this it

could be seen that there was much more confidence in the slopes for Valentia and

Shannon Airport and much less for Birr, Dublin Airport and Malin Head. The

confidence gives us the certainty associated with the hypothesis method used.

Shannon has a confidence interval of 0.4895 which is moderate confidence whereas

Valentia has a confidence of 0.2871 which is a weak confidence but this is still much

stronger than Birr, Dublin and Malin Head which all have very weak confidence in

the trendline.

28

Payback period for a turbine at Valentia

The wind turbine that will be used in the analysis is a 1MW turbine. (Details of the

wind turbine can be found in Appendix C). The following section will look at scaling

the wind speed from a height of 10m (Met Éireann data) to a height of 70m which is

the turbine hub height. This wind speed is needed to derive the power in the wind

formula.

Slope Intercept

Wind Index -0.002334594 5.611991

Wind speed -0.012364612

29.72255

Corrected wind speed at height 70m assuming measurements taken at 10m

-0.016327089

39.24771

Table 6.2: Shows the slope and intercept for the wind index and the wind speed. Also how the adjusted slope and intercept.

Calculating the adjusted slope using Hellman’s power law below:

𝑈𝑧̅̅̅̅

𝑈𝐻= (

𝑧

𝐻) .∝ Equation 6.1

𝑈𝑧̅̅ ̅ = (

𝑧

𝐻) .∝ 𝑥 𝑈𝐻

𝑈𝑧̅̅ ̅ = (

70

10) .1/7 𝑥 -0.012364612

𝑈𝑧̅̅ ̅ =-0.016327

The Hellman’s power law is also used for the intercept below:

𝑈𝑧̅̅ ̅ =39.24771

29

Next the mean cubed wind speed must be extrapolated using the following formula

the average mean wind speed to be cubed. (Derivation for (𝑣𝑡′̅̅̅̅ )3 is in Appendix F):

(𝑣𝑡′̅̅̅̅ )3 = 1

4𝑚𝑡′∆𝑡 (𝑚𝑡′𝑡𝑒𝑛𝑑 + 𝑐𝑡′)4- (𝑚𝑡′𝑡𝑠𝑡𝑎𝑟𝑡 + 𝑐𝑡′)4 Equation 6.2

(𝑣𝑡′̅̅̅̅ )3 = 1

4(−0.016327)(17) [(−0.016327)(2030)(39.24771]- [(−0.016327)(2013)(39.24771)]4

(𝑣𝑡′̅̅̅̅ )3 = 243.4

Now that (𝑣𝑡′̅̅̅̅ )3 has been calculated the max power for the 1 MW turbine can be

found. The Betz limit will be multiplied by the power in the wind equation below to

give the maximum theoretical power generated by the turbine. This formula is as

follows:

Power max available= 1

2ρA𝑣3𝐵𝑒𝑡𝑧 𝐿𝑖𝑚𝑖𝑡 Equation

6.3

Power = 1

2(1.225)(π[27.2]^2)(243.4)(0.59) = 204272W or 0.204MWh

Now that the maximum theoretical power for the 1MWh turbine has been calculated it

is possible to find the energy generated for the year. This is done by the following

formula:

𝑃𝑜𝑤𝑒𝑟̅̅ ̅̅ ̅̅ ̅̅ ̅ 𝑥 𝛥𝑡 = 𝑒𝑛𝑒𝑟𝑔𝑦̅̅ ̅̅ ̅̅ ̅̅ ̅̅ Equation 6.4

204272W 𝑥 365 𝑥 24 = 1789𝑀𝑊ℎ/𝑦𝑟

This can be divided by the average cost for one MWh of electricity which was found

to be €72.167 for the year 2015. This figure will be used to the following calculation.

(Please find details in Appendix A).

30

𝑒𝑛𝑒𝑟𝑔𝑦̅̅ ̅̅ ̅̅ ̅̅ ̅̅ 𝑥 𝑝𝑟𝑖𝑐𝑒 𝑝𝑒𝑟 𝑀𝑊ℎ = 𝑅𝑒𝑣𝑒𝑛𝑢𝑒 𝑓𝑜𝑟 𝑡ℎ𝑒 𝑦𝑒𝑎𝑟 Equation 6.5

1789MWh x €72.167= €129107

The cost of construction of a 1MW turbine is in the vicinity of €1,230,000. This

includes an operational and maintenance cost of 1-2 percent a year for 10 years. The

construction cost/operation/maintenance cost is now divided by the revenue for the

year to give the payback period in years as follows.

€1,230,000/ €129,107 = 9.53 years

From the above analysis it can be seen that the wind speed at Valentia is dropping off

at a rate of 0.016327089 m/s a year. An estimate can be made from 2012 to 2030 by

extrapolating this data. If the wind speed is dropping by the amount of -0.016327089

m/s and that figure is multiplied by 18 years. The figure we are left with is a

0.293887 m/s drop over the 18 years from 2012-2030. Wind speed at 2012 is

4.821249434 m /s. If the estimated wind speed drop over the 18 years is subtracted

from the wind speed of 2012 a wind speed of 4.53 m/s is estimated for the year 2030.

Figure 6.6: The estimated reduction in wind speed at Valentia from 2012- 2030

0.750.8

0.850.9

0.951

1.051.1

1.151.2

1.25

19

39

19

43

19

47

19

51

19

55

19

59

19

63

19

67

19

71

19

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79

19

83

19

87

19

91

19

95

19

99

20

03

20

07

20

11

20

15

20

19

20

23

20

27

Ind

ex

Year

Estimated reduction in wind speed at Valentia 2012-2030

31

Comparing geographical regions in Ireland

In this section several locations in Ireland will be compared with each other using the

student T- test statistical method. The comparisons include Valentia/Shannon Airport,

Valentia/Birr, Birr/Shannon Airport and Dublin Airport/Malin Head.

Figure 6.7: Comparison of Shannon Airport and Valentia over 67 years

Figure 6.8: comparison of Dublin Airport and Malin Head over 57 years

0.89

0.94

0.99

1.04

1.09

0.87 0.92 0.97 1.02 1.07 1.12 1.17

Shan

no

n In

dex

Valentia Index

Wind Index Valentia vs Shannon

0.75

0.85

0.95

1.05

1.15

0.7 0.8 0.9 1 1.1 1.2

Mal

in H

ead

Ind

ex

Dublin Airport Index

Dublin/Malin Head

32

Comparison Slope (m) P-Value Is there a

trend using the

statistical

hypothesis

test?(i)

Confidence (R^2)

Valentia/Shannon Airport

0.3035 0.046322 Yes 0.3011

Shannon Airport/Birr 0.7133 0.264975 No 0.2419

Valentia/Birr 0.3998 0.387963 No 0.0949

Dunlin Airport/ Malin Head

0.209 0.475645 No 0.0713

Table 6.3: Is a summary table of parameters from figures 6.7 and 6.8. (Graphs for Shannon

Airport/Birr and Valentia/Birr can be seen in the Appendix D)

(i)Rejection of the null hypothesis- The null hypothesis states that there is no relationship between the

wind indices at two locations. That is if the p-value is below the significance level; alpha of 0.05, then

the null hypothesis can be rejected. If it is above this figure it cannot be rejected.

To begin the statistical analysis, it was decided to test the significance of the slope at

each of the five Irish locations as well as an overall Ireland analysis. The results were

not conclusive. Malin Head, Dublin Airport, Birr and All Ireland got a p-value which

was greater than the alpha value of 0.05 which means we cannot say that these

locations have a trend. While in Shannon Airport and Valentia the p-value was less

than the alpha value of 0.05 at 0.46322. This means the hypothesis cannot be rejected

and a trend exists. But if we were to lower the p-value to 0.01 we wouldn’t have a

trend for Valentia and Shannon Airport. We can conclude that there is a trend but not

a strong one.

33

In this section wind speed will be examined in 20 and 50 year time periods in three

locations which are as follows, Valentia, Shannon Airport/Birr and Malin

Head/Dublin Airport. Valentia is located at the far south west of the country. Birr and

Shannon Airport are located towards the west of the country. Malin Head and Dublin

are the North West and East respectively. Below are the graphs for the respective

locations

Figure 6.9: Valentia wind index 1990-2009

Figure 6.10: Valentia wind index 1960- 2009

0.8

0.9

1

1.1

1.2

19

90

19

91

19

92

19

93

19

94

19

95

19

96

19

97

19

98

19

99

20

00

20

01

20

02

20

03

20

04

20

05

20

06

20

07

20

08

20

09

Ind

ex

Years

Valentia wind Index 1990-2009

0.75

0.95

1.15

19

60

19

62

19

64

19

66

19

68

19

70

19

72

19

74

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86

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90

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92

19

94

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96

19

98

20

00

20

02

20

04

20

06

20

08

Ind

ex

Years

Valentia wind index 1960-2009

34

Figure 6.11: Shannon Airport and Birr wind Index 1990-2009

Figure 6.12: Shannon Airport and Birr wind index 1960-2009

Figure 6.13: Dublin Airport and Malin Head 1990- 2009

0.8

0.9

1

1.1

19

90

19

91

19

92

19

93

19

94

19

95

19

96

19

97

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98

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99

20

00

20

01

20

02

20

03

20

04

20

05

20

06

20

07

20

08

20

09

win

d in

dex

Years

Shannon and Birr wind Index 1990-2009

0.80.9

11.11.2

19

60

19

62

19

64

19

66

19

68

19

70

19

72

19

74

19

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78

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84

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90

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92

19

94

19

96

19

98

20

00

20

02

20

04

20

06

20

08

Ind

ex

Years

Shannon and Birr wind Index 1960-2009

0.940.960.98

11.021.041.06

19

90

19

91

19

92

19

93

19

94

19

95

19

96

19

97

19

98

19

99

20

00

20

01

20

02

20

03

20

04

20

05

20

06

20

07

20

08

20

09

Ind

ex

Years

Dublin and Malin Head 1990-2009

35

Figure 6.14: Dublin Airport and Malin Head 1960 - 2009

Comparison Slope (m) P-Value Is there a

trend using the

student t-

test?(i)

Confidence (R^2)

Valentia -0.0055 0.0488 No 0.1987

Shannon Airport/Birr 0.0042 0.04 No 0.2126

Dunlin Airport/ Malin Head

-0.0023 0.055 No 0.1895

Table 6.4: Summary table of the inter-comparison between regions over 20 years

Comparison Slope (m) P-Value Is there a

trend using the

student t-

test?(i)

Confidence (R^2)

Valentia -0.0039 1.30995E-06 Yes 0.3889

Shannon Airport/Birr -0.0026 0.0007 Yes 0.2147

Dunlin Airport/ Malin Head

-0.0008 0.086 No 0.06

Table 6.5: Summary table of the inter-comparison between regions over 50 years

(i)Rejection of the null hypothesis- The null hypothesis states that there is no relationship between the

wind indices at two locations. That is if the p-value is below the significance level; alpha of 0.01, then

the null hypothesis can be rejected. If it is above this figure it cannot be rejected.

0.85

0.9

0.95

1

1.05

1.1

1.15

Ind

ex

Years

Dublin and Malin Head 1960-2009

36

For each location analysis was done to see if a trend existed. Each location was given

a significance level of 0.01. This table shows that wind speeds over the 20 year range

do not give a good enough picture of the wind trend whereas at 50 years a trend is

seen. For Valentia and Shannon/Birr both 50 year had a p-value of less than alpha

meaning a trend could not be rejected. Dublin Airport and Malin Head’s trend was

rejected as the p-value was greater than alpha.

From doing this analysis it can be said that wind speed seems to be decreasing in the

south west of the country if it is looked at over a long period i.e. 50 years.

37

Chapter 7: Irish data compared with the UK (Watson Data)

In this chapter wind data in Ireland will be compared at different stations around

Ireland as well as against data in the UK at the same latitude.

Comparison with Watson

Watson et al (2015) looked at the Wind Speed Variability across the UK between

1983 and 2011. Watson divided the country into six different locations to analyse the

speed data. These locations were the north west, north east, centre west, centre east,

south west and south east. A downward trend in wind speed was seen in five of the six

locations over the period. Below is the wind index for the south west of the UK. For

the purpose of this analysis the south west of Ireland (Valentia) and the south west of

the UK will be looked at because of their similar latitude.

Looking at figure 7.1 and 7.2 below from the year 1983-2011 it is evident that the

annual wind speed is reducing in both cases. It is more obvious in Valentia. The

reasons for this downward trend is not clear and further analysis will be done in the

following sections.

Figure7.1: The wind speed index at Valentia for the period 1983-2011.

0.7

0.9

1.1

1.3

1983 1985 1987 1989 1991 1993 1995 1997 1999 2001 2003 2005 2007 2009 2011

Ind

ex

Years

Valentia wind Index

38

Figure 7.2: The UK (South west) wind speed index for the period 1983-2011.

0.85

0.95

1.05

1983 1985 1987 1989 1991 1993 1995 1997 1999 2001 2003 2005 2007 2009 2011

Ind

ex

Years

SW UK wind Index

39

UK data comparison with Ireland

In this section the wind index for the UK data and the wind index for the Irish data is being

compared at different regions based on geographical location.

Figure 7.3: Compares the south west of Ireland with the south west of the UK

Figure 7.4: Compares the south west of Ireland (Birr and Shannon) with the south west of the UK

0.75

0.8

0.85

0.9

0.95

1

1.05

1.1

1.15

1.2

0.9 0.95 1 1.05 1.1 1.15

SW Ir

elan

d In

dex

SW UK Index

SW of Ireland (Valentia)/SW UK

0.92

0.94

0.96

0.98

1

1.02

1.04

1.06

1.08

1.1

0.8 0.85 0.9 0.95 1 1.05 1.1

Win

d In

dex

UK

Wind Index Ireland

SW Ireland (Birr+Shannon)/SW UK

40

Figure 7.5: Compares the north west of Ireland (Malin Head) with the west of the UK

Figure 7.6: Compares the east of Ireland (Dublin Airport) with the North east of the UK

Comparison Slope (m) P-Value (i) Is there a

trend using the

student t-test?

Confidence (R^2)

SW Ireland(Valentia) /SW UK 1.0771 0.000182 Yes 0.2447

SW Birr + Shannon/ SW UK 0.1915 0.090361 No 0.0714

NW Malin Head/ NW UK 0.3675 0.021446 No 0.3268

East Dublin/ East UK 0.4175 0.002634 Yes 0.2298

Table 7.1: Is a summary table of the data collected from figure 7.1 – 7.4.

(i)Rejection of the null hypothesis- The null hypothesis states that there is no relationship between the

wind indices at two locations. That is if the p-value is below the significance level; alpha of 0.05, then

the null hypothesis can be rejected. If it is above this figure it cannot be rejected.

0.8

0.9

1

1.1

1.2

0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2

Win

d In

dex

UK

Wind Index Ireland

Malin Head/UK NW

0.85

0.9

0.95

1

1.05

1.1

1.15

0.8 0.85 0.9 0.95 1 1.05 1.1 1.15

Win

d In

dex

UK

Wind Index Ireland

Dublin/East UK

41

Looking at Table 7.1 it can be seen using the student t-test that there is a trend for two

of the four locations. Valentia and the SW of the UK have a low p-value meaning

there is a trend. The reason for this may be due to the SW of Ireland and the UK

having no landmass to obstruct the wind coming from the ocean meaning it is less

interfered with compared to East Dublin and the East of the UK which also have a

believable trend but it isn’t as strong a trend as seen for the SW. There have been

studies done in the Netherlands by Vautard et al. (2010) and Wever (2011) which

found a correlation between increased surface roughness and a reduction in wind

speed.

42

Payback period for a turbine at the SW of the UK

The same method will be used as before with the Valentia wind data. The same 1MW

wind turbine will be used in the analysis. (Details about the wind turbine can be found

in the Appendix C). The following section will look at scaling the wind speed from a

height of 10m (Met Éireann data) to a height of 70m which is the turbine hub height.

This wind speed is needed for the power in the wind formula.

Slope Intercept

Wind Index -0.00153

4.058034

Wind speed -0.00812

21.52455

Corrected wind speed at height

70m assuming measurements

taken at 10m

-0.01072

28.42251

Table 7.2: Slope and intercept for the wind index and the wind speed and is used to get the corrected

wind speed at 70m.

Calculating the adjusted slope using the Hellman’s power law below:

𝑈𝑧̅̅̅̅

𝑈𝐻= (

𝑧

𝐻) .∝ Equation

7.1

𝑈𝑧̅̅ ̅ = (

𝑧

𝐻) .∝ 𝑥 𝑈𝐻

𝑈𝑧̅̅ ̅ = (

70

10) .1/7 𝑥 -0.00812

𝑈𝑧̅̅ ̅ =-0.01072

The Hellman’s power law is also used for the intercept below:

𝑈𝑧̅̅ ̅ =28.42251

43

Next the mean cubed wind speed must be extrapolated using the following formula

the average mean wind speed to be cubed. (Derivation for (𝑣𝑡′̅̅̅̅ )3 is in Appendix F)

(𝑣𝑡′̅̅̅̅ )3 = 1

4𝑚𝑡′∆𝑡 (𝑚𝑡′𝑡𝑒𝑛𝑑 + 𝑐𝑡′)4- (𝑚𝑡′𝑡𝑠𝑡𝑎𝑟𝑡 + 𝑐𝑡′)4 Equation 7.2

(𝑣𝑡′̅̅̅̅ )3 = 1

4(−0.01072)(18) [(−0.01072)(2030)(28.42251)4]- [(−0.01072)(2012)(28.42251)]4

(𝑣𝑡′̅̅̅̅ )3 = 308.5

The adjusted wind speed has been calculated and cubed. The max power for the 1

MW turbine can be found using the same methods from the Irish data in Chapter 6.

The Betz limit will be multiplied by the power in the wind equation below to give the

maximum theoretical power generated by the turbine. This formula is as follows:

Power max available= 1

2ρA𝑣3𝑐𝑝 Equation 7.3

Power max= 1

2(1.225)(π[27.2]^2)(308.5)(0.59) = 258700W or 259KW

Now that the maximum theoretical power for the 1MWh turbine has been calculated

at 258700W and is now possible to find the energy generated for the year. This is

done by the following Equation 7.4:

𝑃𝑜𝑤𝑒𝑟̅̅ ̅̅ ̅̅ ̅̅ ̅ 𝑥 𝛥𝑡 = 𝑒𝑛𝑒𝑟𝑔𝑦̅̅ ̅̅ ̅̅ ̅̅ ̅̅ Equation 7.4

258700W 𝑥 365 𝑥 24 = 2266𝑀𝑊ℎ/𝑦𝑟

As with the Irish data this can be divided by the average cost for a MWh of electricity

which was found to be €72.167 for the year 2015. This figure will be used to the

following calculation. (Please find details in Appendix A).

The cost of construction of the 1MW turbine is in the vicinity of €1,230,000. This

includes an operational and maintenance cost of 1- 2 percent a year for 10 years. The

44

construction cost/operation/maintenance cost is now divided by the revenue for the

year to give the payback period in years as follows.

2262MWh x €72.167= €163530 per year

€1,230,000/ €163530 = 7.52 years payback period

From the above analysis it can be seen that the wind speed at the south west of the UK

is dropping off at 0.01072 m/s a year. An estimate can be made from 2012 to 2030 by

extrapolating this data. If the wind speed is dropping by that amount of 0.01072 m/s

and we multiply that figure by the 18 years. The figure remaining is a

0.19296 m/s drop over the 18 years from 2012-2030. Wind speed for 2012 is 5.3265

m/s. If the wind speed over the 18 years is subtracted from the wind speed at 2012 a

wind speed of 5.13354 m/s is estimated for the year 2030.

Observing Ireland and the UK over the eighteen year period from 2012-2030, it is

clear that the wind speed in the SW of Ireland is decreasing at a greater rate than that

in the SW of the UK by a margin of 0.1 m/s over the eighteen year period.

45

Chapter 8: Irish data compared with the NAO

Comparing the NAO with Wind speeds in the south west of Ireland (Valentia)

Once again a null hypothesis test will be conducted. This time we are comparing the

NAO index and the wind speed index in the south west of Ireland (Valentia) to see if

there is a relationship between the drop in wind speed we observed in Chapter 6 and

the NAO oscillation from its positive phase to its negative phase. The data that was

evaluated for the NAO is based on the difference in pressure at sea level between the

Azores high and the Polar low.

Figure 8.1: Index for the average North Atlantic Oscillation between the period of 1983-2011

-Data was taken from (https://www.ncdc.noaa.gov/teleconnections/nao/) (Please find NAO

Positive and negative phase oscillation in Appendix B)

Figure 8.2: Wind index at the south west of Ireland (Valentia) from 1983-2011

-4

-3

-2

-1

0

1

2

3

Jan

-83

Ap

r-8

4

Jul-

85

Oct

-86

Jan

-88

Ap

r-8

9

Jul-

90

Oct

-91

Jan

-93

Ap

r-9

4

Jul-

95

Oct

-96

Jan

-98

Ap

r-9

9

Jul-

00

Oct

-01

Jan

-03

Ap

r-0

4

Jul-

05

Oct

-06

Jan

-08

Ap

r-0

9

Jul-

10

Oct

-11

Ind

ex

Time

Average monthly NAO 1983-2011

y = -0.0085x + 1.1284R² = 0.5259

0.7

0.9

1.1

1.3

1983 1985 1987 1989 1991 1993 1995 1997 1999 2001 2003 2005 2007 2009 2011

Ind

ex

Years

Valentia

46

After conducting the student T-test on the two samples it was observed the p-value

was found to be 0.1139 which is greater than the significance level of 0.05 and so a

significant correlation is indicated between the North Atlantic Oscillation and the

wind speed at Valentia between 1987 and 2011.

Figure 8.3: Correlation plot between the Wind Index at Valentia and the NAO Index from 1987-2011

0.8

0.85

0.9

0.95

1

1.05

1.1

1.15

1.2

1.25

1.3

-0.4

0.6

Win

d In

dex

val

enti

a

NAO Index

Comparison of the wind index between the NAO and Valentia

47

Figure 8.4: Comparison between the North Atlantic Oscillation Index and the Wind Index at Valentia

over the same period 1983-2011 using a yearly average.

The wind Indices starting point was moved up by 0.15 so that both the NAO and the

wind index would start at the same point. From looking at this graph it is quite clear

that there is a trend between both. When the NAO is in a negative phase wind speeds

seem to decrease and vice versa. This shows that there is a weak to medium

correlation between the two.

y = -0.0085x + 1.1284R² = 0.5259

y = -0.0214x + 1.2205R² = 0.2143

-0.5

0

0.5

1

1.5

19

83

19

84

19

85

19

86

19

87

19

88

19

89

19

90

19

91

19

92

19

93

19

94

19

95

19

96

19

97

19

98

19

99

20

00

20

01

20

02

20

03

20

04

20

05

20

06

20

07

20

08

20

09

20

10

20

11

Ind

ex

Years

Comparison of the wind index between the NAO and Valentia

Valentia index

NAO Index

48

Future predictions for the NAO

Burningham looks at the correlation between the NAO and Northern Europe

including Bellmullet, Malin Head and Valentia (Burningham et al 2013). He

mentions that “Average winter wind speed is weakly correlated with the NAO winter

index”. He says that 26 percent of the sites he examined had a strong correlation with

the winter NAO. This only applied to south westerly winds. At higher wind speeds he

noted that only 11 percent of the stations saw a correlation.

In times of a strong negative phase of the NAO the wind speeds tend to be lower and

the direction isn’t predominantly from the south westerly direction. This can be seen

on the NAO map in the appendix B for the winter of 2009/2010 where Northern

Europe saw its 18th coldest winter in history (Lockwood et al). Instead it is more

evenly spread out with a greater chance of north easterly winds. This is due to the

increase in pressure over the Arctic which slows down the wind speeds. On the other

hand when the NAO is in a strong positive phase winds tend to be stronger and

predominantly from the south west direction (Earl et al).

Visbeck et al. mention that at the current time there are no methods that can be used

for observing the low frequency variability of the NAO. This means uncertainty about

the NAO into the future. Visbeck talks about an increase in greenhouse gas emissions

and hence surface temperature may cause the positive index to continue in the

positive phase. The Met office at Hardley Centre is in an early stage of developing a

forecasting model for a negative phase NAO. They are using a large range forecast

model. The model could allow prediction for an increase or a decrease in wind speed

and at a certain rate. The problem with it is that it only looks at a short term period of

months ahead. To be able to predict a decrease or an increase in Ireland we need to

have the ability to look further ahead.

49

Chapter 9: Irish data compared with the Weibull Distribution

Valentia over 20 years

With the data from Valentia over the 20 years the behavior of the wind was analysed.

Firstly a frequency of occurrence table was made by dividing all the wind speeds into

bins from 0 m/s to 40 plus m/s. It was decided that above 40 m/s the wind speed did

not fit the Weibull distribution well so it was eliminated. The most frequent wind

speed is 10 m/s. Below is the frequency of occurrence table for the wind speed at

Valentia.

Figure 9.1: Frequency of occurrence

The probability frequency distribution is created by dividing all the wind speed

occurrences in each bin by the total number of occurrences over the year. It is given

as a percentage.

Figure 9.2: Probability frequency distribution

0

10000

20000

30000

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40

Occ

ura

nce

s in

eac

h b

in

Wind speed Bin

Frequency of occurance

-1.00%

1.00%

3.00%

5.00%

7.00%

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40

Per

cen

tage

Wind speed bins

Probability frequency Distrubution

50

The probability of exceedance graph is created from the probability frequency

distribution graph. It represents at each wind speed what is the probability that the

wind speed will be above that value at any given time.

Figure 9.3: Probability of exceedance

The cumulative frequency distribution is 1-(the probability of exceedance). It is the

probability a wind speed will be below a certain wind speed.

Figure 9.4: Cumulative frequency distribution

0.00%

50.00%

100.00%

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40

Per

cen

tage

Wind speed bin

Probability of exceedance

0.00%

20.00%

40.00%

60.00%

80.00%

100.00%

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40

Pe

rce

nta

ge

Wind Speed Bin

Cumulative Frequency Distribution

51

The ln[ln 1-F(v))] is plotted versus the log of the velocity to get the Weibull

parameter below.

Figure 9.5: Determination of the Weibull distribution

The scale factor (c) can be determined from the following:

𝑐 = 𝑒−𝑦𝑜

𝑚 Equation 9.1

𝑐 = 𝑒4.15851.7106

𝑐 = 11.37

The shape factor (k) is given from the graph as 1.7106 and is equal to the slope.

Using both the cumulative frequency distribution (Figure 9.4) and the probability

frequency distribution (figure 9.2) we can see the Weibull data plotted.

Figure 9.6: Probability frequency distribution

y = 1.7106x - 4.1585R² = 0.9922

-4.5

-2.5

-0.5

1.5

3.5

0 0.5 1 1.5 2 2.5 3 3.5 4

ln[l

n(1

-F(v

))]

Ln(V)

Determination of Weibull distribution

0.00%

1.00%

2.00%

3.00%

4.00%

5.00%

6.00%

7.00%

8.00%

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40

Pe

rce

nta

ge

Wind speed bins

Probability frequency Distrubution

Probability Frequency Distribution Weibull PDF

52

The cumulative frequency distribution is graphed above in Figure 9.6.

Figure 9.7: Cumulative frequency distribution

Figure 9.8: Power in the wind

The power available for extraction by the turbine can be found using the formula

𝑝𝑎𝑣𝑔= 1

2(𝜌)(𝐴)(�̅�)3𝐵𝑒𝑡𝑧 𝐿𝑖𝑚𝑖𝑡 Equation 9.2:

𝑝𝑎𝑣𝑔= 1

2(𝜌)(𝐴)(�̅�)3(0.59)

𝑝𝑎𝑣𝑔= 1

2(1.225)(9.49)3(0.59)

𝑝𝑎𝑣𝑔= 717868W at a hub height of 70m

0.00%

20.00%

40.00%

60.00%

80.00%

100.00%

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40

Pe

rce

nta

ge

Wind speed bins

Cumulative frequency distribution

Cumulative Frequency Distribution F(v)

0

50

100

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40

Po

wer

m/2

Wind speed bins

Power in the wind

53

The average power extracted by the wind is calculated next

𝑃𝑜𝑤𝑒𝑟̅̅ ̅̅ ̅̅ ̅̅ ̅ 𝑥 𝛥𝑡 = 𝑒𝑛𝑒𝑟𝑔𝑦̅̅ ̅̅ ̅̅ ̅̅ ̅̅ Equation 9.3:

717868 𝑥365 𝑥 24 = 6289𝑀𝑊ℎ/𝑦𝑟

This energy above value can be divided by the average cost for a MWh of electricity

which was found to be €72.167 for the year 2015. This figure will be used to the

following calculation. (Please find details in Appendix A).

𝑒𝑛𝑒𝑟𝑔𝑦̅̅ ̅̅ ̅̅ ̅̅ ̅̅ 𝑥 𝑝𝑟𝑖𝑐𝑒 𝑝𝑒𝑟 𝑀𝑊ℎ = 𝑅𝑒𝑣𝑒𝑛𝑢𝑒 𝑓𝑜𝑟 𝑡ℎ𝑒 𝑦𝑒𝑎𝑟 Equation 9.4:

6289MWh x €72.167= €453858

This figure is the amount of revenue expected from the turbine in a given year. The

cost of construction of the 1MW turbine is in the vicinity of €1,230,000. This

included an operational and maintenance cost of 1- 2 percent a year for 10 years. The

construction cost/operation/maintenance cost is now divided by the revenue for the

year to give the payback period in years as follows.

Cost of construction/ 𝑅𝑒𝑣𝑒𝑛𝑢𝑒 = 𝜏𝑝 Equation 9.5

€1,230,000/ €453858 = 2.71years

A Weibull distribution was also conducted over 50 years at Valentia and this can be

found in Appendix E.

When looking at the data for Ireland in chapter 6 it was seen that 1789MWh/Yr was

the amount of energy extracted from a 1MW turbine in a year using trend analysis. If

this is compared to the Weibull distribution which is over the same period of time the

MWh estimated are over three times higher than the trend analysis. This calls into

question the Weibull distribution method which is used in industry. Is the industry

54

over-estimating the maximum energy the turbine extracted from the wind? From the

data it is quite evident that they are.

If we take a further look at the probability frequency distribution it is clear that the

Weibull does not fit the wind data perfectly. There are discrepancies where it does not

fit inside the Weibull PDF. This calls into question why this is the main method used

by industry for finding the power in the wind and hence the revenue and payback

period for a turbine.

56

Chapter 10: Conclusion

This paper set out to explore the characteristics and trends of wind in the South West

of Ireland in terms of its potential as a source of power generation.

Average wind speeds in the south west of Ireland, specifically in Valentia and

Shannon Airport, show a distinct downward trend since records began. A similar

trend is evident in wind data from the south west of the UK. A wide variation of

opinion exists regarding the influence of the NAO on wind strength in Northern

Europe. However this paper has illustrated a moderate level of confidence- 0.3968, in

a correlation of wind indices between Valentia and the NAO.

Despite the importance to the power generation industry of identifying trends in wind

variability, the industry uses a shorter (20 year) period than this paper used as a basis

for wind farm development. Trends evident in 50 year analyses in this paper are not

apparent in 20 year studies.

The Weibull distribution method- widely used by the wind-power industry, was

applied using Valentia wind data and this produced a scarcely credible 2.71 year

payback for a 1MW turbine. Once again this raises questions regarding the methods

used by the industry to evaluate wind energy projects.

However the payback period for a 1MW turbine using trend analysis for the region

was 9.53 years and this would become less attractive over time given the trend.

The potential of wind for power production, even in what appears to be the most

favourable part of the island of Ireland, is not yet proven and needs to be subjected to

more rigorous analysis by industry players

a

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A

Appendix

Appendix A:

From the Department of Communications, Energy and Natural resources web page under Refit scheme and supports,

reference price.

B

Appendix B

Data used in Figure 8.1. -Data was taken from (https://www.ncdc.noaa.gov/teleconnections/nao/)

C

Appendix C

D

E

Data used for 1MW turbine which was used to calculate the payback period

(http://etcgreen.com/horizontal-axis-wind-turbine-1mw/)

F

Appendix D:

Comparing sites in Ireland with each other and they’re student T-test analysis.

Valentia Shannon

n 67 67

b=slope -0.00189 -0.00323

Sy-x 0.081461 0.066976

sx 19.48504 19.48504

sb 0.000515 0.000423

sb1-b2 0.000666

t 2.011673

df 130

alpha 0.05

p-value 0.046322

sigma yes

A null hypotheses test is conducted on the wind index for Birr and Shannon Airport (figures

7.3/7.4). The p-value comes out as 0.97339 which is not less than the required significant

level (alpha), which is 0.05 so the hypotheses that the slopes are equal cannot be rejected.

0.75

0.85

0.95

1.05

1.15

1.25

1.35

0.8 0.9 1 1.1 1.2 1.3

Ind

ex

Index

Birr/Shannon

G

birr shannon

n 56 56

b -0.00164 -0.00283

s y-x 0.11216 0.064417

sx 16.30951 16.30951

sb 0.000927 0.000533

sb1-b2 0.001069

t 1.120527

df 108

alpha 0.05

p-value 0.264975

Sig no Table 6.4: shows the Hypothesis test preformed on Birr and Shannon

Figure 6.1 shows the average wind speed at Valentia over a period of 73 years. The

graph shows a significant decreasing trend in the average yearly wind speeds over the

period and especially in the last 20 years. The year 2010 saw the lowest wind speed

on record which averaged out at less than 4 m/s for the year. This is 0.8 m/s lower

than any other average yearly wind speed. In the last 20 years nine out of the ten

lowest average annual wind speeds on record were in this period.

Looking at Shannon Airport data and Valentia data it is justifiable to say that wind

speed in the south west of Ireland is decreasing. The decrease is much more

substantial than other locations in Ireland such as Birr and Dublin Airport which show

a decreasing trend but it is not as significant as seen in the south west.

0.75

0.85

0.95

1.05

1.15

1.25

1.35

0.8 0.9 1 1.1 1.2 1.3

Ind

ex

Years

Birr/Shannon

H

Figure 6.18:

Birr Valentia

n 56 56

b=slope -0.00164 -0.00261

Sy-x 0.11216 0.07777

sx 16.30951 16.30951

sb 0.000927 0.000643

sb1-b2 0.001128

t 0.86682

df 108

alpha 0.05

p-value 0.387963

sigma no Table 6.7:

0.75

0.85

0.95

1.05

1.15

1.25

1.35

0.8 0.85 0.9 0.95 1 1.05 1.1 1.15 1.2

Ind

ex

Years

Valentia/Birr

I

0.9

1

1.1

19

55

19

57

19

59

19

61

19

63

19

65

19

67

19

69

19

71

19

73

19

75

19

77

19

79

19

81

19

83

19

85

19

87

19

89

19

91

19

93

19

95

19

97

19

99

20

01

20

03

20

05

20

07

20

09W

ind

Ind

ex

Year

All Ireland wind index

Figure 6.3 shows the wind speed index at Malin Head. If we look at the figure it is

clear that the wind speed from the 1960s to 2000 was stable and fluctuated marginally

from the mean. The overall slope of figure 6.3 is positive but if you look just at the

last 10 years it is obvious that the wind speeds have dropped.

Dublin Malin Head

n 57 57

b=slope 0.001845 0.0012149

Sy-x 0.064095 0.08860079

sx 16.59819 16.5981927

sb 0.000516 0.00071332

sb1-b2 0.00088

t 0.715779

df 110

alpha 0.05

p-value 0.475645

sigma no Table 6.6:

All Ireland Wind Index

Figure 6.7: All Ireland Wind Index from 1955-2009

Figure 6.7 shows the mean wind speed in Ireland between 1955 and 2009. It looks at

the bigger picture of Ireland as a whole. Again a decreasing trend is seen.

J

Appendix E:

The Weibull distribution over 50 years at Valentia Ireland

0

5000

10000

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40Occ

ura

nce

s in

eac

h b

in

Wind speed Bin

Frequency of occurance

0.00%

2.00%

4.00%

6.00%

8.00%

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40

Per

cen

tage

Wind speed bins

Probability frequency Distrubution

0.00%

20.00%

40.00%

60.00%

80.00%

100.00%

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40

Per

cen

tage

Wind speed bin

Probability of exceedence

K

Eqn of Line: y = 1.705x -

4.0313

Slope: 1.705

Intercept -4.8475

shape factor [k] 1.705

scale factor [c] (m/s) 17.16905275

V bar (m/s) 15.31595027

KE 2.283433979

ρ 1.258765

PW

32,848,070.62

y = 1.705x - 4.0313R² = 0.9967

-4.5

-2.5

-0.5

1.5

3.5

0 0.5 1 1.5 2 2.5 3 3.5 4

ln[l

m(1

-F(v

))]

Ln(V)

Determination of Weibull distribution

0

20

40

60

80

0 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40

Po

wer

m/2

wind speed in bins

Power in the wind

L

Appendix F:

Integral used for the calculation for �̅�3

(𝑣𝑡′̅̅̅̅ )3 Integral

𝑦 = 𝑚𝑥 + 𝑐

𝑣𝑖=𝑚𝑡+𝑐

𝑣𝑖

𝑣𝑡

𝑣�̅�

𝑣𝑖𝑣�̅� = 𝑣𝑡

𝑣𝑖�̅�𝑡 = 𝑚𝑣�̅� 𝑡 + 𝑐 𝑣�̅�

𝑣𝑡 = 𝑚𝑡𝑡 + 𝑐𝑡

𝑣𝑡 ′ =ln (

𝑍𝑍𝑜)

ln (𝐻𝑍𝑜)

𝑣𝑡

𝑐𝑡 ′ =ln (

𝑍𝑍𝑜)

ln (𝐻𝑍𝑜)

𝑐𝑡

𝑚𝑡 ′ =ln (

𝑍𝑍𝑜)

ln (𝐻𝑍𝑜)

𝑚𝑡

𝑣𝑡′ = 𝑚𝑡′𝑡 + 𝑐𝑡′

(𝑣𝑡′̅̅̅̅ )3

(𝑣𝑡′̅̅̅̅ )3 = 1

∆𝑡 ∫ (𝑚𝑡′𝑡 + 𝑐𝑡′)3 𝑑𝑡

𝑡−𝑒𝑛𝑑

𝑡−𝑠𝑡𝑎𝑟𝑡

M

Integration method used will be substitution

𝐿𝑒𝑡 𝑈 = 𝑚𝑡′𝑡 + 𝑐𝑡′

𝑑𝑈 = 𝑚𝑡′𝑡. 𝑑𝑡

𝑑𝑡 =𝑑𝑈

𝑚𝑡′

(𝑣𝑡′̅̅̅̅ )3 = 1

𝑚𝑡′∆𝑡 ∫ (𝑈)3 𝑑𝑈

𝑡−𝑒𝑛𝑑

𝑡−𝑠𝑡𝑎𝑟𝑡

1

𝑚𝑡′∆𝑡 𝑈4

4∫ .

𝑡−𝑒𝑛𝑑

𝑡 𝑠𝑡𝑎𝑟𝑡

(𝑣𝑡′̅̅̅̅ )3 = 1

4𝑚𝑡′∆𝑡 (𝑚𝑡′𝑡𝑒𝑛𝑑 + 𝑐𝑡′)4- (𝑚𝑡′𝑡𝑠𝑡𝑎𝑟𝑡 + 𝑐𝑡′)4

N

Appendix F:

Comparing payback period at Valentia between 1939 and 2012

The average drop in wind speed from 1939-2012 in Valentia is -0.0146 m/s per a year.

When this is multiplied by 74 years it can be seen that there is a -1.08 m/s decrease in wind

speed since 1939. Wind speed at 1939 was 5.89 m/s on average and wind speed at 2012 was

1.08 less than that at 4.81.

1939

𝑥

5.89 =

𝑙𝑛(70

0.01)

𝑙𝑛(10

0.01) = 7.55 m/s

Next the maximum theoretical power can be found at this wind speed using the

following formula.

Power max= 1

2(1.225)(π[27.2]^2)(7.553)(0.59) = 361482 or 361KW

How much energy can this turbine produce in a year?

𝑃𝑜𝑤𝑒𝑟̅̅ ̅̅ ̅̅ ̅̅ ̅ 𝑥 𝛥𝑡 𝑥 𝐶𝑎𝑝𝑎𝑐𝑖𝑡𝑦 𝑓𝑎𝑐𝑡𝑜𝑟 = 𝑒𝑛𝑒𝑟𝑔𝑦̅̅ ̅̅ ̅̅ ̅̅ ̅̅

361482W 𝑥 365 𝑥 24 = 3167𝑀𝑊ℎ 𝑖𝑛 𝑎 𝑦𝑒𝑎𝑟

€50 for MWh (from SEMO website)

Cost of infrastructure for the turbine- €1,230,000

So 3167MWh x €50= €158350 per year

€1,230,000/ €158350 = 7.77years payback period

O

2012

𝑥

4.81 =

𝑙𝑛(70

0.01)

𝑙𝑛(10

0.01) = 6.16 m/s

Next the maximum theoretical power can be found at this wind speed using the

following formula.

Power max= 1

2(1.225)(π[27.2]^2)(6.163)(0.59) = 196331 or 196KW

How much energy can this turbine produce in a year?

𝑃𝑜𝑤𝑒𝑟̅̅ ̅̅ ̅̅ ̅̅ ̅ 𝑥 𝛥𝑡 𝑥 𝐶𝑎𝑝𝑎𝑐𝑖𝑡𝑦 𝑓𝑎𝑐𝑡𝑜𝑟 = 𝑒𝑛𝑒𝑟𝑔𝑦̅̅ ̅̅ ̅̅ ̅̅ ̅̅

196331W 𝑥 365 𝑥 24 = 1720𝑀𝑊ℎ 𝑖𝑛 𝑎 𝑦𝑒𝑎𝑟

€50 for MWh (from SEMO website)

Cost of infrastructure for the turbine- €1,230,000

So 1720MWhx €50= €86000 per year

€1,230,000/ €86000 = 14.3 years payback period

That is a payback difference between 1939 and 2012 of 6.53 years for a 1MW

turbine with a reduction in wind speed of just over 1 m/s on average.