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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References Risk Aggregation under Dependence Uncertainty Challenges in Theory and Practice Paul Embrechts RiskLab, Department of Mathematics, ETH Zurich Senior SFI Professor www.math.ethz.ch/ ˜ embrechts/ Paul Embrechts Risk Aggregation 1/33

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Risk Aggregation under Dependence

UncertaintyChallenges in Theory and Practice

Paul Embrechts

RiskLab, Department of Mathematics, ETH Zurich

Senior SFI Professor

www.math.ethz.ch/˜embrechts/

Paul Embrechts Risk Aggregation 1/33

Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Outline

1 Framework

2 VaR and ES Bounds

3 Asymptotic Equivalence

4 Challenges

5 References

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Fundamental problem in Finance/Insurance

Risk factors: X = (X1, . . . ,Xd)

Model assumption: Xi ∼ Fi, Fi known, i = 1, . . . , d

A financial position Ψ(X)

A risk measure/pricing function: ρ(Ψ(X))

Calculate ρ(Ψ(X))

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Calculating ρ(Ψ(X))

Example:

Ψ(X) =∑d

i=1 Xi

ρ = VaRp or ρ = ESp

Challenge:

We need a joint model for the random vector X

Joint models are hard to get by

We will focus on the above special choices of Ψ and ρ.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

VaR and ES

VaRp(X)

For p ∈ (0, 1),

VaRp(X) = F−1X (p) = inf{x ∈ R : FX(x) ≥ p}

ESp(X)

For p ∈ (0, 1),

ESp(X) =1

1− p

∫ 1

pVaRq(X)dq =

(F cont.)E[X|X > VaRp(X)

]

Paul Embrechts Risk Aggregation 5/33

Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

VaR and ES

A related quantity Left-tail-ES:

LESp(X)

For p ∈ (0, 1),

LESp(X) =1p

∫ p

0VaRq(X)dq = −ES1−p(−X)

Paul Embrechts Risk Aggregation 6/33

Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Frechet problem

Denote

Sd = Sd(F1, . . . ,Fd) =

{d∑

i=1

Xi : Xi ∼ Fi, i = 1, . . . , d

}

Every element in Sd is a possible risk position.

Determination of Sd: very challenging.

Think about S2(U[0, 1],U[0, 1]) ... open question!

Paul Embrechts Risk Aggregation 7/33

Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Worst- and best-values of VaR and ES

The Frechet (unconstrained) problems for VaRp

VaRp(Sd) = sup{VaRp(S) : S ∈ Sd(F1, . . . ,Fd)},

VaRp(Sd) = inf{VaRp(S) : S ∈ Sd(F1, . . . ,Fd)}.

Same notation for ESp and LESp.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Worst- and best-values of VaR and ES

ES is subadditive:

ESp(Sd) =

d∑i=1

ESp(Xi).

Similarly LESp(Sd) =∑d

i=1 LESp(Xi).

VaRp(Sd), VaRp(Sd) and ESp(Sd): generally open questions

Challenge for ESp(Sd)

To calculate ESp(Sd) one naturally seeks a safest risk in Sd.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Mathematical difficulty

Common understanding of the most dangerous scenario:

Comonotonicity - well accepted notion

Understanding concerning the safest scenario:

d = 2: counter-monotonicity

d ≥ 3: question mark! (?!)

Calls for notions of extremal negative dependence.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Mathematical difficulty

ES respects convex order: the natural order of risk preference.

Convex orderWe write X ≤cx Y if E[f (X)] ≤ E[f (Y)] for all convex functions fsuch that the two expectations exist.

Finding ESp(Sd)

Search for a smallest element in Sd with respect to convex

order, if it exists.

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Mathematical difficulty

VaR does not respect convex order: more tricky

Good news: the questions for VaRp(Sd), VaRp(Sd) and

ESp(Sd) are mathematically similar.

Finding VaRp(Sd)

Search for a smallest element in Sd(F1, . . . , Fd) with respect to

convex order, where Fi is the p-tail-conditional distribution of

Fi.

VaRp(Sd) is symmetric to VaRp(Sd).

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Summary of existing results

d = 2:

fully solved analytically

d ≥ 3:

Homogeneous model (F1 = · · · = Fd)

ESp(Sd) solved analytically for decreasing densities, e.g.Pareto, ExponentialVaRp(Sd) solved analytically for tail-decreasing densities,e.g. Pareto, Gamma, Log-normal

Inhomogeneous model

Few analytical results: current research

Numerical methods available: Rearrangement Algorithm

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

VaR bounds

d = 2, Makarov (1981) and Ruschendorf (1982)

For any p ∈ (0, 1),

VaRp(S2) = infx∈[0,1−p]

{F−11 (p + x) + F−1

2 (1− x)},

and

VaRp(S2) = supx∈[0,p]

{F−11 (x) + F−1

2 (p− x)}.

A large outcome is coupled with a small outcome.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

VaR bounds - homogeneous model

Sharp VaR bounds (Wang, Peng and Yang, 2013)

Suppose that the density function of F is decreasing on [b,∞)

for some b ∈ R. Then, for p ∈ [F(b), 1), and X d∼ F,

VaRp(Sd) = dE[X|X ∈ [F−1(p + (d− 1)c),F−1(1− c)]],

where c is the smallest number in [0, 1d(1− p)] such that

∫ 1−cp+(d−1)c F−1(t)dt ≥ 1−p−dc

d ((d− 1)F−1(p + (d− 1)c) + F−1(1− c)).

Red part clearly has an ES-type form.

c = 0: VaRp(Sd) = ESp(Sd).

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VaR bounds - homogeneous model

Sharp VaR bounds II

Suppose that the density function of F is decreasing on its

support. Then for p ∈ (0, 1) and X d∼ F,

VaRp(Sd) = max{(d− 1)F−1(0) + F−1(p), dE[X|X ≤ F−1(p)]}.

Red part has an LES form.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

ES bounds - homogeneous model

Sharp ES bounds (Bernard, Jiang and Wang, 2014)

Suppose that the density function of F is decreasing on its

support. Then for p ∈ (1− dc, 1), q = (1− p)/d and X d∼ F,

ESp(Sd) =1q

∫ q

0

((d− 1)F−1((d− 1)t) + F−1(1− t)

)dt,

= (d− 1)2LES(d−1)q(X) + ES1−q(X),

where c is the smallest number in [0, 1d ] such that

∫ 1−c(d−1)c F−1(t)dt ≥ 1−dc

d ((d− 1)F−1((d− 1)c) + F−1(1− c)).

One large outcome is coupled with d− 1 small outcomes.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Complete mixability

The homogeneous VaR and ES bounds are based on the notion

of complete mixability:

Complete mixability, Wang and Wang (2011)

A distribution function F on R is called d-completely mixable

(d-CM) if there exist d random variables X1, . . . ,Xd ∼ F such

that

P(X1 + · · ·+ Xd = dk) = 1,

for some k ∈ R.

Equivalently, Sd(F, . . . ,F) contains a constant.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Complete mixability

Some examples of d-CM distributions for all d ≥ 2:

Normal, Student t, Cauchy, Uniform.

Most relevant result: F has a monotone density on a finiteinterval with a mean condition (depends on d) is d-CM.

Examples: (truncated) Pareto, Gamma, Log-normal.

Inhomogeneous version called joint mixability.

A full characterization of these classses is at the moment is

widely open.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Numerical calculation

Rearrangement Algorithm (RA): Embrecths, Puccetti and

Ruschendorf (2013).

A fast numerical procedure

Based on the CM-idea

Discretization of relevant quantile regions

d possibly large

Applicable to VaRp, VaRp and ESp

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Asymptotic equivalence

Consider the case d→∞. What would happen to VaRp(Sd)?

Clearly always VaRp(Sd) ≤ ESp(Sd).

Recall that VaRp(Sd) has an ES-type part.

Under some weak conditions,

limd→∞

ESp(Sd)

VaRp(Sd)= 1.

This was shown first for homogeneous models and then

extended to general inhomogeneous models.

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Asymptotic equivalence - homogeneous model

Theorem 1In the homogeneous model, F1 = F2 = · · · = F, for p ∈ (0, 1) andX ∼ F, we have that

limd→∞

1d

VaRp(Sd) = ESp(X).

Similar limits hold for a large class of risk measures

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Asymptotic equivalence - worst-cases

Theorem 2 (Embrechts, Wang and Wang, 2014)

Suppose the continuous distributions Fi, i ∈ N satisfy that forXi ∼ Fi and some p ∈ (0, 1),

(i) E[|Xi − E[Xi]|k] is uniformly bounded for some k > 1;

(ii) lim infd→∞

1d

d∑i=1

ESp(Xi) > 0.

Then as d→∞,

ESp(Sd)

VaRp(Sd)= 1 + O(d1/k−1).

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Asymptotic equivalence - best-cases

Similar results holds for VaRp and ESp: assume (i) and

(iii) lim infd→∞

1d

d∑i=1

LESp(Xi) > 0,

then

limd→∞

VaRp(Sd)

LESp(Sd)= 1,

limd→∞

ESp(Sd)∑di=1 E[Xi]

= 1,

andVaRp(Sd)

ESp(Sd)≈∑d

i=1 LESp(Xi)∑di=1 E[Xi]

≤ 1, d→∞.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Example: Pareto(2) risks

Bounds on VaR and ES for the sum of d Pareto(2) distributed rvs forp = 0.999; VaR+

p corresponds to the comonotonic case.

d = 8 d = 56

VaRp 31 53

ESp 178 472

VaR+p 245 1715

VaRp 465 3454

ESp 498 3486

VaRp/VaR+p 1.898 2.014

ESp/VaRp 1.071 1.009

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Example: Pareto(θ) risks

Bounds on the VaR and ES for the sum of d = 8

Pareto(θ)-distributed rvs for p = 0.999.

θ = 1.5 θ = 2 θ = 3 θ = 5 θ = 10

VaRp 1897 465 110 31.65 9.72

ESp 2392 498 112 31.81 9.73

ESp/VaRp 1.261 1.071 1.018 1.005 1.001

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Dependence-uncertainty spread

Theorem 3 (Embrechts, Wang and Wang, 2014)

Take 1 > q ≥ p > 0. Suppose that the continuous distributionsFi, i ∈ N, satisfy (i) and (iii), and lim supd→∞

∑di=1 E[Xi]∑d

i=1 ESp(Xi)< 1, then

lim infd→∞

VaRq(Sd)− VaRq(Sd)

ESp(Sd)− ESp(Sd)≥ 1.

The uncertainty spread of VaR is generally bigger than that

of ES.

In recent Consultative Documents of the Basel Committee,

VaR0.99 is compared with ES0.975: p = 0.975 and q = 0.99.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Dependence-uncertainty spread

ES and VaR of Sd = X1 + · · ·+ Xd, where

Xi ∼ Pareto(2 + 0.1i), i = 1, . . . , 5;

Xi ∼ Exp(i− 5), i = 6, . . . , 10;

Xi ∼ Log–Normal(0, (0.1(i− 10))2), i = 11, . . . , 20.

d = 5 d = 20best worst spread best worst spread

ES0.975 22.48 44.88 22.40 29.15 102.35 73.20VaR0.975 9.79 41.46 31.67 21.44 100.65 79.21VaR0.9875 12.06 56.21 44.16 22.12 126.63 104.51VaR0.99 12.96 62.01 49.05 22.29 136.30 114.01

ES0.975

VaR0.9751.08 1.02

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

Challenges

Open mathematical questions:

Characterization of complete and joint mixability

Characterization of Sd

Find VaRp under more general settings, especially in the

inhomogeneous model

Partial dependence information and realistic scenarios

Marginal uncertainty and statistical estimation

Many more ...

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

References I

Bernard, C., X. Jiang, and R. Wang (2014). Risk aggregation

with dependence uncertainty. Insurance: Mathematics andEconomics, 54(1), 93–108.

Embrechts, P., G. Puccetti, and L. Ruschendorf (2013).

Model uncertainty and VaR aggregation. Journal of Bankingand Finance, 37(8), 2750–2764.

Embrechts, P., G. Puccetti, L. Ruschendorf, R. Wang, and A.

Beleraj (2014). An academic response to Basel 3.5. Risks,

2(1), 25–48.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

References II

Embrechts, P., B. Wang, and R. Wang (2014).

Aggregation-robustness and model uncertainty of

regulatory risk measures. Preprint, ETH Zurich.

Makarov, G.D. (1981). Estimates for the distribution

function of the sum of two random variables with given

marginal distributions. Theory of Probability and itsApplications, 26, 803–806.

Ruschendorf, L. (1982). Random variables with maximum

sums. Advances in Applied Probability, 14(3), 623–632.

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Framework VaR and ES Bounds Asymptotic Equivalence Challenges References

References III

Wang, B. and R. Wang (2011). The complete mixability and

convex minimization problems with monotone marginal

densities. Journal of Multivariate Analysis 102(10), 1344–1360.

Wang, R., L. Peng, and J. Yang (2013). Bounds for the sum

of dependent risks and worst value-at-risk with monotone

marginal densities. Finance and Stochastics 17(2), 395–417.

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THANK YOU!

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