related rates vid

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THE CALCULUS CRUSADERS Related Rates: Crusaders Unite Question

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Page 1: Related Rates Vid

THE CALCULUS CRUSADERSRelated Rates: Crusaders Unite Question

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THE SITUATION

Zeph, Bench and Jamie find a clue that brings them closer to the block of wood. Zeph and Bench meet up at a park, but Jamie is missing in action.

After she calls Bench on his phone, they agree to meet at her house.

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THE QUESTION

Bench and Zeph are at the park (point P), j = 40 metres north of Jamie’s house (point H). Together they walk at a speed of dj/dt = 12 metres per minute south. Jamie is standing p metres from her house, where p, with respect to time t, is defined as:

What is the rate of change of the angle at j?

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THE DIAGRAM

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THE SOLUTION

To evaluate p(t), we need to complete the square.

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THE SOLUTION

To evaluate p(t), we need to complete the square.

We can substitute t + 2 as u by letting t + 2 = u, which means that du = dt.

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THE SOLUTION

To evaluate p(t), we need to complete the square.

We can substitute t + 2 as u by letting t + 2 = u, which means that du = dt.

Similarly, we can let v = u/2, which means 2dv = du.

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THE SOLUTION

Remember from our list of derivatives that

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THE SOLUTION

Remember from our list of derivatives that

In order to make the equation fit the pattern, like stated previously, we must complete the square...

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THE SOLUTION

Recall that we made substitutions for values, previously.

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THE SOLUTION

Recall that we made substitutions for values, previously.

Also notice that the limits change accordingly as a result of the substitution.

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THE SOLUTION

We now know how far Jamie is standing from her house, which is the length of the adjacent side in the diagram.

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THE SOLUTION

Now it’s just as simple as using trigonometric ratios and the values of j and p to solve for θ.

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THE SOLUTION

We can avoid using the Quotient Rule (differentiating by Quotient Rule is monstrous)

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THE SOLUTION

We can avoid using the Quotient Rule (differentiating by Quotient Rule is monstrous)

Instead, we can differentiate implicitly, both side with respect to t.

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THE SOLUTION

We then result with this:

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THE SOLUTION

We then result with this:

We can then substitute dj/dt = -12 and θ = 1.568328887 into the equation, and solve for dθ/dt.

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No more confusion! Zeph, Bench and Jamie have gathered and organized themselves and are clear to continue with the mission!

HOME AT LAST!