ph and titration methods -...
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pH and Titration MethodsEdward A. Mottel
Department of ChemistryRose-Hulman Institute of Technology
Autoionization of WaterWater is a very weak electrolyte
H2O(l) H+(aq) + OH–(aq)
2 H2O(l) H3O+(aq) + OH–(aq)
Dissociation constantKw = [H+] [OH– ] = 1.0 x 10–14 (@ 25 °C)
Note: H+(aq) ≡ H3O+ (aq)
pH Base 10 logarithmic scale of hydrogen ion
concentration• pH = -log [H+ ]
If pH = -log [H+ ], what does [H+ ] equal?
[H+ ] = 10–pH
Be carefuluse log and not ln
pH
pure waterat 25 °C Kw = [H+] [OH–] = 1.0 x 10–14
1.0 x 10–7 M 1.0 x 10–7 M
pH = -log(1.0 x 10–7) = 7.0
What’s the pH of pure water?
pH
If the pH of an aqueous solution is 3.50 at 25 °C,what is the hydroxide ion concentration?
pH
6
[H+ ] = 10–pH
[H+ ] = 10–3.50 = 3.2 x 10–4 M
Kw = [H+] [OH–] = 1.0 x 10–14 M2
[OH–] = Kw / [H+]
[OH–] = (1.0 x 10–14 M2) / 3.2 x 10–4 M
= 3.2 x 10–11 M
pH
7
0
14
acids
basesneutral @ 25 °C
1 M HCl
1 M KOH
pH values can be outside 0-14
Titration
analyte
titrant
an analytical technique to find the concentration of a solution
buretRemember to:•Rinse the buret•Remove air from tip•Added distilled water to the mixture does not affect calculations
Thermometric Titration
T (°C)
Vacid
acid-base reactionsare usually exothermic
Equivalence Pointvolume
Moles of acid = Moles of base
Titration
HF + NaOH NaF + H2O
Balanced equation
reactant 2
reactant 1
an analytical techniqueto determinethe concentrationof a solution
Titration
Moles of acid = Moles of base
nacid · Macid · Vacid = nbase · Mbase · Vbase
Most acids have one acidic proton (HCl, CH3COOH),some have two (H2SO4, H2CO3),
some have three (H3PO4, citric acid)
the purpose of a titrationis to determine theequivalence point
Titration
Moles of acid = Moles of base
nacid · Macid · Vacid = nbase · Mbase · Vbase
Most bases accept one proton (NaOH, NH3),some accept two (Ca(OH)2), some accept three (Al(OH)3)
Equivalence Point Detection Physical methods
• Thermometric • Potentiometric• Visual indicator• Conductometric
Potentiometric Titration 20.0 mL of 0.400 M HCl with Aqueous Ammonia
0 4 8 12 16 20 24 280
2
10
8
6
4
pH
Volume NH3 (mL)
Equivalence Pointvolume
What is the concentration of the ammonia?
Equivalence Point Detection Visual indicator methods
• Color change • Endpoint versus equivalence point
Endpoint: when the indicator changes colorEquivalence point: moles of acid = moles of base
• Factors to consider when selecting an indicator
SO3
C CH3H3C
Br
Br
OH
OBrBr
O
SO3
C CH3H3C
Br
Br
O
BrBr
Bromocresol Green
Common Acid-Base Visual IndicatorsIndicator Acidic Color Basic Color pH Range
thymol blue red yellow 1.2-2.8methyl orange orange yellow 2.9-4.4
bromocresol green yellow blue 3.8-5.4methyl red red yellow 4.4-6.0
bromothymol blue yellow blue 6.0-7.6cresol red yellow red 7.2-8.8
phenolphthalein colorless red 8.3-10.0thymolphthalein colorless blue 9.3-11.0alizarin yellow yellow red 10.0-12.1
Potentiometric Titration 20.0 mL of 0.400 M HCl with Aqueous Ammonia
0 4 8 12 16 20 24 280
2
10
8
6
4
pH
Volume NH3 (mL)
phenolphthalein
bromocresol green
equivalencepoint
endpoint
endpoint
For this titration,which indicatorwould be better?
Conductometric Titration
Λcorr
Vacid
Equivalence Pointvolume
Depending on the acid-base system studied,the graph may have many different shapes.
Conductometric Titration
Why does the line change slope?
Λcorr
Vacid
Conductometric Titration
HCladded K+ OH– H+ Cl– Total
Ions0 50 50 0 0 100
20 50 30 0 20 10040 50 10 0 40 10060 50 0 10 60 120
80 50 0 30 80 160100 50 0 50 100 200
H2O(l) + KCl(aq)KOH(aq) + HCl(aq)
Conductometric Titration
If the total number of ions isn’t changing before theequivalence point, why is the conductivity changing?
Λcorr
Vacid
Equivalence Pointvolume
Potentiometric Titration 20.0 mL of 0.400 M HCl with Aqueous Ammonia
0 4 8 12 16 20 24 280
2
10
8
6
4
pH
Volume NH3 (mL)
Equivalence Pointvolume
What is [OH-] at the start of the reaction?
Potentiometric Titration 20.0 mL of 0.400 M HCl with Aqueous Ammonia
0 4 8 12 16 20 24 280
2
10
8
6
4
pH
Volume NH3 (mL)
Equivalence Pointvolume
Calculate the pH of 0.400 M HCl.
Potentiometric Titration 20.0 mL of 0.400 M HCl with Aqueous Ammonia
0 4 8 12 16 20 24 280
2
10
8
6
4
pH
Volume NH3 (mL)
Equivalence Pointvolume
Calculate the pH after 10.0 mL of ammonia have been added.
Potentiometric Titration 20.0 mL of 0.400 M HCl with Aqueous Ammonia
0 4 8 12 16 20 24 280
2
10
8
6
4
pH
Volume NH3 (mL)
Equivalence Pointvolume
Calculate the pH after 24.0 mL of ammonia have been added.