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Question 10.75 out of 0.75 points

Follow the directions in the image below.Answer

Selected Answer:

692, 440

Correct Answer:

Top Left Coordinates

(623, 370)

Bottom Right Coordinates

(818, 521)

Instructor selection and student response



Selected Answer:

702, 440

Correct Answer:


(638, 363)


(843, 569)




Selected Answer:

726, 477

Correct Answer:


(659, 369)


(869, 578)




Selected Answer:

354, 306

Correct Answer:


(51, 165)


(429, 441)




Selected Answer:

727, 302

Correct Answer:


(522, 178)


(930, 456)




Selected Answer:

767, 289

Correct Answer:


(523, 177)


(901, 441)




Selected Answer:

338, 525

Correct Answer:


(85, 479)


(471, 662)




Selected Answer:

501, 315

Correct Answer:


(402, 253)


(564, 414)




Selected Answer:

667, 299

Correct Answer:


(539, Bottom Right Coordinates

(747, 398)

154)




Selected Answer:

782, 346

Correct Answer:


(597, 211)


(838, 492)




Selected Answer:

387, 289

Correct Answer:


(203, 135)


(437, 400)


Question 120 out of 0.75 points


Selected Answer:

551, 350

Correct Answer:


(701, 248)


(907, 463)




Selected Answer:

367, 321

Correct Answer:


(162, 205)


(414, 490)




Selected Answer:

334, 544

Correct Answer:


(78, 473)


(466, 659)




Selected Answer:

688, 458

Correct Answer:


(602, 240)


(853, 534)




Selected Answer:

339, 413

Correct Answer:


(111, 229)


(403, 542)




Selected Answer:

367, 278

Correct Answer:


(158, 142)


(391, 400)




Selected Answer:

701, 308

Correct Answer:


(605, 148)


(820, 403)




Selected Answer:

660, 356

Correct Answer:


(547, 258)


(758, 502)




Selected Answer:

391, 344

Correct Answer:


(182, 256)


(444, 521)


Question 21

0.75 out of 0.75 points


Selected Answer:

574, 413

Correct Answer:


(501, 270)


(711, 494)




Selected Answer:

316, 342

Correct Answer:


(168, 254)


(396, 498)




Selected Answer:

348, 392

Correct Answer:


(218, 233)


(445, 473)




Selected Answer:

764, 331

Correct Answer:


(672, 241)


(876, 453)



Which of the following statements is true?Answer

Selected Answers: The Wittig reaction is essentially an anti-ozonlysis

reaction.

the by-product of the Wittig reaction is triphenyl phosphine oxide.

Correct Answers: The Wittig reaction is essentially an anti-ozonlysis

reaction.

the by-product of the Wittig reaction is triphenyl phosphine oxide.


Which of the following statements is true?Answer

Selected Answer: The carbonyl is a polar

bond.

Correct Answer: The carbonyl is a polar

bond.


Select all of the true statements.Answer

Selected Answers: Hemiacetals have an OH and an OR (R=carbon

group) attached to the same carbon.

Correct Answers: Hemiacetals have an OH and an OR (R=carbon

group) attached to the same carbon.


Ketones are not water soluble because they are not polar enough.Answer

Selected Answer:

False

Correct Answer:

False


Which of the following results whenever an organolithium reagent is added to an aldehyde?Answer

Selected Answer: a secondary

alcohol.

Correct Answer: a secondary

alcohol.


Ketones have high boiling points because of the dipole-dipole interactions arising from the carbonylAnswer

Selected Answer:

True

Correct Answer:

True


It is not possible to deprotonate the alpha position of an acid.Answer

Selected Answer:

False

Correct Answer:

False



Selected Answers: When tertiary amines react with aldehydes or

ketones, the resulting product is unstable and the system reverts back to starting materials.

When primary amines react with aldehydes or ketones, an imine is formed.

When secondary amines react with aldehydes or ketones, an enamine is formed.

Correct Answers: When tertiary amines react with aldehydes or

ketones, the resulting product is unstable and the system reverts back to starting materials.

When primary amines react with aldehydes or ketones, an imine is formed.

When secondary amines react with aldehydes or ketones, an enamine is formed.


Which of the following statements is/are true?Answer

Selected Answers: ketones can be deprotonated at the alpha position

The michael addition allows a nucleophile to be added to the carbon beta do a carbonyl of an alpha beta unsaturated ketone.

Correct Answers: ketones can be deprotonated at the alpha position

The michael addition allows a nucleophile to be added to the carbon beta do a carbonyl of an alpha beta unsaturated ketone.



Selected Answers: Regarding the atoms of the carbonyl, the oxygen will

always be the Lewis base and the carbon will always be the Lewis Acid when the carbonyl reacts.

The alpha carbon of esters can be deprotonated.

Correct

Answers: Regarding the atoms of the carbonyl, the oxygen will always be the Lewis base and the carbon will always be the Lewis Acid when the carbonyl reacts.

The alpha carbon of esters can be deprotonated.


HBr does not add in a radical sense to an alkene because the C-Br bond is too weak it to be thermodynamically favorable for this bond to form while the pi bond breaks.Answer

Selected Answer:

False

Correct Answer:

False


Radicals are formed via the homolytic cleavage of bonds.Answer

Selected Answer:

True

Correct Answer:

True


Radicals have two unpaired electrons in different orbitals.Answer

Selected Answer:

False

Correct Answer:

False


One of the ways in which the formation of radicals can be accomplished more easily is to make the radical less stable and thus, more reactive.Answer

Selected Fals

Answer: e

Correct Answer:

False


Reacting HCl with an alkane results in radical halogenation at both the more substituted and the less substituted carbons.Answer

Selected Answer:

False

Correct Answer:

False


Lactones can be formed from acids.Answer

Selected Answer:

True

Correct Answer:

True


Which of the following statements are true?Answer

Selected Answers: Hydrogen bonding greatly influences intermolecular

interactions such as boiling point.

The acidity of carboxylic acids is dependent on the inductive effect.

Correct Answers: Hydrogen bonding greatly influences intermolecular

interactions such as boiling point.

The acidity of carboxylic acids is dependent on the inductive effect.

Question 42


Which of the following reactions will give an ester from an acid?Answer

Selected Answers: Carboxylate

nucleophile.

Acid catalysis with an alcohol.

DCC an alcohol

Correct Answers: Carboxylate

nucleophile.

Acid catalysis with an alcohol.

DCC an alcohol


Which of the following are valid conditions for making an amide from an acid.Answer

Selected Answer: DCC and an

amine.

Correct Answer: DCC and an

amine.


Carboxylic acids canAnswer

Selected Answers: be converted into

anhydrides

be converted into acid chlorides

be deprotonated by even weak bases

Correct Answers: be converted into

anhydrides

be converted into acid chlorides

be deprotonated by even weak bases


LAH reduces acids to secondary alcohols.Answer

Selected Answer:

False

Correct Answer:

False


Which of the following transformations are not possible for acids in one step?Answer

Selected Answers: The conversion of acids to secondary

alcohols.

Correct Answers: The conversion of acids to secondary

alcohols.


Which of the following statements are false?Answer

Selected Answers: Hydrogen bonding greatly influences intramolecular

interactions such as crystal size.

High pKa values indicate a very strong acid.

Correct Answers: Hydrogen bonding greatly influences intramolecular

interactions such as crystal size.

High pKa values indicate a very strong acid.


Circle all of the true statements.Answer

Selected Answers: If an acid is deprotonated first, it can accept an

organolithium or Grignard reagent nucleophile to make a ketone.

Correct Answers: If an acid is deprotonated first, it can accept an

organolithium or Grignard reagent nucleophile to make a ketone.

Question 49


Which of the following are true regarding pyridine and pyrrole? You should choose 2 answers.Answer

Selected Answers: Pyrrole is not basic because the lone pair of electrons

on the pyrrole nitrogen are part of the aromatic ring. This means that donation of these electrons to an H+ will destroy the aromaticity of the ring.

Pyridine is basic because the lone pair of electrons on the nitrogen of pyridine are not part of the aromatic ring. This means that the electrons can be donated to an H+ and not result in the destruction of aromaticity.

Correct Answers: Pyrrole is not basic because the lone pair of electrons

on the pyrrole nitrogen are part of the aromatic ring. This means that donation of these electrons to an H+ will destroy the aromaticity of the ring.

Pyridine is basic because the lone pair of electrons on the nitrogen of pyridine are not part of the aromatic ring. This means that the electrons can be donated to an H+ and not result in the destruction of aromaticity.


Which of the following statements is/are true? There may be more than one answer.Answer

Selected Answers: Pyridine is

aromatic.

Correct Answers: Pyridine is

aromatic.


Which of the following is/are requirements for aromaticity? There may be multiple answers.Answer

Selected Answers: Fully

conjugated.

4n + 2"pi" electrons.

Correct Answers: Fully

conjugated.

4n + 2"pi" electrons.


All aromatic rings are nonpolar.Answer

Selected Answer:

False

Correct Answer:

False


Choose all of the substituents that the diazonium ion can be converted into.Answer

Selected Answers: OH

CN

Correct Answers: OH

CN


Which of the following statements is/are false? There may be multiple answers.Answer

Selected Answers: Aromatic compounds must be

neutral.

Correct Answers: Aromatic compounds must be

neutral.


Which of the following statements is/are true. There may be multiple answers.Answer

Selected Answers: Although halogens are ortho/para directors, they

are deactivators.

the NO2 group is both an deactivator and a meta director

Aromatic rings can have heteroatoms.

Correct Answers: Although halogens are ortho/para directors, they

are deactivators.

the NO2 group is both an deactivator and a meta director

Aromatic rings can have heteroatoms.


Which of the following choices account for the increased reactivity of anisole, compared to benzene? There may be more than one answer.Answer

Selected Answers: The lone pair of electrons on the oxygen of anisole

allows for a resonance stabilized intermediate. This makes the intermediate lower in energy, making it easier to access.

The lone pair of electrons on the oxygen of anisole can be donated into the ring, making the ring more electron rich, and therefore, more likely to donate electrons to an electrophile, which is electron-poor.

Correct Answers: The lone pair of electrons on the oxygen of anisole

allows for a resonance stabilized intermediate. This makes the intermediate lower in energy, making it easier to access.

The lone pair of electrons on the oxygen of anisole can be donated into the ring, making the ring more electron rich, and therefore, more likely to donate electrons to an electrophile, which is electron-poor.


Aromatic compounds such as benzene are prone to substitution reactions and not addition reactions because permanent destruction of the aromatic ring , which would occur during an addition reaction, is unfavorable.Answer

Selected Answer:

True

Correct Answer:

True


Which of the following statements is/are true about the basicity of aromatic compounds? There may be more than one answer.Answer

Selected Answers: Aniline is basic because the NH2 group is attached to

the aromatic ring, meaning that the N can donate its lone pair of electrons to an H+ without any repercussions on the aromatic ring.

Whether or not a N in an aromatic ring is basic depends on whether or not the lone pair of electrons is part of the aromatic system.

Pyridine is basic because the nitrogen of the ring has a lone pair of electrons that are not part of the aromatic system. As a result, they are available for donation to an H+.

Correct Answers: Aniline is basic because the NH2 group is attached to

the aromatic ring, meaning that the N can donate its lone pair of electrons to an H+ without any repercussions on the aromatic ring.

Whether or not a N in an aromatic ring is basic depends on whether or not the lone pair of electrons is part of the aromatic system.

Pyridine is basic because the nitrogen of the ring has a lone pair of electrons that are not part of the aromatic system. As a result, they are available for donation to an H+.


An alkyne is a suitable dienophile for the Diels-Alder reaction.Answer

Selected Answer:

True

Correct Answer:

True


Paracyclophanes are highly reactive.Answer

Selected Answer:

True

Correct Answer:

True


The Diels-Alder reaction is extremely specific with regards to both stereochemsitry and regiochemistry.Answer

Selected Answer:

True

Correct Answer:

True


Some Diels-Alder reactions do not result in the formation of a 6 member ring.Answer

Selected Answer:

False

Correct Answer:

False

Question 63


The Diels-Alder reaction can be used to generate as many as 4 stereocenters but as few as 2, depending on the substrates. In fact, in some cases, it will generate 0 stereocenters.Answer

Selected Answer:

True

Correct Answer:

True


Which of the following can be used to furnish an acid?Answer

Selected Answers: Hydrolysis of an ester.

Hydrolysis of a nitrile.

oxidation of primary alcohols with Jones reagent.

addition of an organolithium or a Grignard to CO2

Correct Answers: Hydrolysis of an ester.

Hydrolysis of a nitrile.

oxidation of primary alcohols with Jones reagent.

addition of an organolithium or a Grignard to CO2


all of the acid derivatives can be easily converted into one another.Answer

Selected Answer:

False

Correct Answer:

False


Esters are less reactive than acids.Answer

Selected Answer:

True

Correct Answer:

True


Amides are the least reactive of the acid derivatives.Answer

Selected Answer:

True

Correct Answer:

True


Which of the following statements about acid derivatives are/is false?Answer

Selected Answers: Acid chlorides are more reactive

than acids.

Correct Answers: Acid chlorides are more reactive

than acids.


Acids can be a protecting group for an ester.Answer

Selected Answer:

False

Correct Answer:

False


A good protecting group is:(Choose all that apply)Answer

Selected Answers: Very stable, but easy to to take off under very

specific conditions.

A group that will keeps other reactive groups from transforming under the reaction conditions you are using in your synthesis.

A group that you can introduce into your compound in a very high-yielding reaction.

Correct Answers: Very stable, but easy to to take off under very

specific conditions.

A group that will keeps other reactive groups from transforming under the reaction conditions you are using in your synthesis.

A group that you can introduce into your compound in a very high-yielding reaction.


Esters can serve as protecting groups for alcohols or for acids, depending on which you care more about.Answer

Selected Answer:

True

Correct Answer:

True


Which of the following can be a protecting group for a ketone?Answer

Selected Answers: acet

al

Correct Answers: acet

al


Which of the following can be a protecting group for an alcoholAnswer

Selected Answers: acetal

silyl ether

ester

methyl ether

Correct Answers: acetal

silyl ether

ester

methyl ether


Amino acids require protecting group schemes when used in synthesis.Answer

Selected Answer:

True

Correct Answer:

True


Reactions of sugars include:Answer

Selected Answer: selective oxidation of the aldehyde

to an acid.

Correct Answer: selective oxidation of the aldehyde

to an acid.


Mutarotation of sugars is...Answer

Selected Answer: the epimerization of one of the

stereocenters.

Correct Answer: the epimerization of one of the

stereocenters.


The anomeric position of an unfunctionalized furanose is an acetal.Answer

Selected Answer:

False

Correct Answer:

False


The anomeric position of furanoses and pyranoses reacts under very selective conditions.Answer

Selected Answer:

True

Correct Answer:

True


Which of the following statements about sugars is/are trueAnswer

Selected Answers: Sugars have the general formula

Cn(H2O)n

They can exist in an open chain or ring form.

Correct Answers: Sugars have the general formula

Cn(H2O)n

They can exist in an open chain or ring form.



Selected Answers: The synthesis of peptides is made relatively easy by

clever use of protecting groups.

Pyranoses and furanoses can be reduced with NaBH4 because there is an equilibrium that allows an aldehyde or ketone to be produced.

There are multiple selective reactions of carbohydrates.

Correct Answers: The synthesis of peptides is made relatively easy by

clever use of protecting groups.

Pyranoses and furanoses can be reduced with NaBH4 because there is an equilibrium that allows an aldehyde or ketone to be produced.

There are multiple selective reactions of carbohydrates.


the anomeric position of an unfunctionalized furanose is a hemiacetalAnswer

Selected Answer:

True

Correct Answer:

True


Because sugars have so many aldehyde groups they are very polar.Answer

Selected Answer:

False

Correct Answer:

False


Which of the following statements about amino acids is true?Answer

Selected Answer: The acid is often protected as

an ester.

Correct Answer: The acid is often protected as

an ester.


Which of the following statements is/are true about amino acids.Answer

Selected Answers: They can be formed by simple SN2 reactions where

an amine displaces a leaving group.

They can exist as zwitterions at the right pH.

Correct Answers: They can be formed by simple SN2 reactions where

an amine displaces a leaving group.

They can exist as zwitterions at the right pH.


Which of the following statements about Fischer projections is true?Answer

Selected Answer: The horizontal bonds are coming out of the page

and the veriical bonds are going into the page.

Correct Answer: The horizontal bonds are coming out of the page

and the veriical bonds are going into the page.


Epimers are a very specific type of diasereomer.Answer

Selected Answer:

True

Correct Answer:

True



Selected Answers: Peptides are comprised of

amino acids.

Correct Answers: Peptides are comprised of

amino acids.


Select all of the false statements.Answer

Selected Answers: carbohydrates readily react with amino acids to

make peptides.

Correct Answers: carbohydrates readily react with amino acids to

make peptides.

Tuesday, May 1, 2012 12:18:39 PM EDTOK

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