microprocessor ece lab manual.doc

8/10/2019 microprocessor ece lab manual.doc

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MANAV RACHNA COLLEGE OF ENGINEERING

FARIDABAD

DEPARTMENT OF ELECTRONICS AND

COMMUNICATION ENGINEERING

MEEC519- ADVAVANCED MICROPROCESSORS

AND MICROCONTROLLERS LAB


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NAME OF THE STUDENT --->

COLLEGE ROLL NO --->

UNIVERSITY ROLL NO --->

BRANCH --->

SEMESTER --->

NO OF EXPERIMENTS --->

YEAR --->

STATUS OF LAB FILE --->

SIGNATURE OF THE FACULTY --->

DATE OF PRACTICAL EXAM --->


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INDEX

S.n

o

Date Experient Si!nat"re


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EXPERIMENTS BASED ON 8086

EXP NO : 0 STUDY OF 8086 KIT

DATE :

AIM

To study about the 8086 microprocessor kit.

HARDWARE SPECIFICATIONS

1 CPU PROCESSOR AND CLOCK FRE!UENCY

Intel 8086/8088 CPU at 5/4. !"# clock rate $%ptionally 8 !"#&

" MEMORY

!%'IT%( )P(%!* +000*0000 , -+++ or 6

)P(%! )1P2'3I%'* +000*0000 , +++ or 64

33T)! (2!* 0000*000 , -+++ or 6

33T)! (2! )1P2'3I%'* 0000*000 , ++++ or 64

I'T)((UPT )CT%(3* 0000*0000 , 0-++

# PERIPHERALS

P2(2) I/%* 48 I/% lines usin7 to numbers o 8955.

3)(I2* %ne number o (39-9C , 3erial Interace usin78952 U32(T.

TI!)(* - Channel 6,bit Pro7rammable Timer 895-. Channel0 used as baud rate 7enerator

or the 3erial Port.

$ DISPLAY

6:9 C; ;I3P2 $ith 6 ON-BOARD BATTERY BACKUP: &O'()*+,>


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%nboard battery backup acility is optionally pro=ided or (2! ?U9 @ U4>.

. POWER CONSUMPTION

A 5 * .5 2mps

8 POWER SUPPLY SPECIFICATIONS

!odel* 3!P3,0

!ains* 9-0 olts 2C at 50 "#

Input* 9-0 2C at 50"

%utput* > A 5 oltsB - amps re7ulated

9> A 9 oltsB 950 m2 re7ulated

-> , 9 oltsB 950 m2 re7ulated

4> A-0 oltsB 950 m2 unre7ulated

/ PHYSICAL CHARACTERISTICS

! , 86/88 C; trainer PC


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SOFWARE SPECIFICATIONS

COMMAND LINE EDITOR FEATURES

i> 3in7le line editor can process upto 40 characters.

)) V,) 234 5+7()*+ ,93:

1 ASSEMBLER COMMAND

FUNCTION

This command is used to enter the mnemonics o 8086 and it 7i=es the opcode or the

!nemonics.

SYNTAX

E2 FC(G

2 , ine 2ssembler Command.

PROCEDURE


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. 2ter enterin7 the H2H commandB the kit is displayed as ollos

9. ThenB it asks the startin7 address

Then start pro7rammin7.

Fdra the kit dia7ram 7i=en in class

hereG

ALGORITHM:


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?I> 16-BIT ADDITION

. Initiali#e the !3


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DATE:

Introduction:2ssembly lan7ua7e pro7rams resemble a compiled lan7ua7e pro7ramsB like P23C2.

In compiled lan7ua7es the user irst creates a source ileB hich is a tet ile o entire

pro7ram. The compiler chan7es it into machine lan7ua7e instructions. ?2ctually a linker isused too but is i7nored or the time bein7> In the compiled lan7ua7e pro7ram the entire

pro7ram is transormed into machine lan7ua7e at once.

3ome o the most rudimentary unctions that a debu77er can perorm are the olloin7*

2ssemble short pro7rams

ie a pro7ramJs source codeB alon7 ith its machine code

ie the CPU re7isters and la7s

Trace or eecute a pro7ramB atchin7 =ariables or chan7es

)nter ne =alues into memory

3earch or binary or 23CII =alues in memory

!o=e a block o memory rom one location to another

+ill a block o memory

oad and rite disk iles

DEBUG 7*;;,+:

KeJll be usin7 only some o the ;)


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use o data re7istersB so donJt 7et upset i you do not understand the meanin7 o some o the

olloin7 re7isters*

D,(, R3=)(39:

6,bit 21 ?accumulator>B B C1 ?counter>B ;1 ?data>

8,bit* 2"B 2B


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third column displays the contents o 00hB and so on the number in th column displays

the contents o memory at oset address 00+h. ?The characters to the ri7ht are the 23CII

representation o each byte.> Calculate the absolute address correspondin7 to this last

memory location. (eer to appendi notes


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+or this e can use the LdJ command like this.

; cs * 00

The irst e bytes ?ho many is not clear yet> represent the machine lan7ua7e code o the

abo=e pro7ram no eJll use another ;) as ell as the correspondin7 machine lan7ua7e

code.

U+-,3;@3 C*;;,+

This command translates memory into assembly lan7ua7e mnemonics. This process is called

dis,assembly )nter the olloin7 command and note don hat you obser=e.

U 00

'o you can see both your assembly lan7ua7e pro7ram as ell as the correspondin7

machine code on the screen. Can you no i7ure out ho many bytes are occupied by your

small pro7ramR 'ote don the number. %ur net step ill be to run this pro7ram by

eecutin7 one command at a time and then atchin7 the results in =arious re7isters. This

process is called sin7le,step operation in debu77in7 o assembly lan7ua7e pro7rams

T9,73 C*;;,+

This command eecutes one or more instructions rom the current C3*IP location ?see

2ppendi notes or an optional address i speciied. The contents o the re7isters are shon

ater each instruction is eecuted. Check the contents o the data re7isters 21 and


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FLOW CHART

ALGORITHM?i> 16-@)( ,)()*+

et the irst number.

2dd the second number to the irst number.

3tore 3


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FLOW CHART FOR SUBTRACTION

ALGORITHM

?ii> 6-@)( @(9,7()*+

et the irst number

3ubtract the second number rom the irst number.

3tore 3


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PROGRAM FOR MUTIPLICATION

9)(3 4*9 '9*=9,; ,+ *('(.

)nter the to input data in the location 00 and 09 usin7 ?3< command>

)ecute the pro7ram ith the command ?% startin7 address>.

Check the correspondin7 result in the location 900 and 90

Chan7e the data in the location 00and 09 and =eriy the result

RESULT


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EX NO :" SORTING OF NUMBERS

DATE :

AIM

Krite an 2ssembly an7ua7e Pro7ram to arran7e a 7i=en series o headecimal bytes in

ascendin7 order FLOWCHART

ASCENDING ORDER DESCENDING ORDER

3T2(T

I'ITI2IN) P%I'T)(

C%U'T S C%U'T O

+2 S 0

I3

P%I'T)(

P%I'T)(

A

T)!P S P%I'T)(

P%I'T)( S P%I'T)( A

P%I'T)( A S T)!P

P%I'T)( S P%I'T)( A

C%U'T S C%U'T A

I3

C%U'T

S 0

I3

+2

S 0

)3

'%

'%

'%

)3

3T2(T

I'ITI2IN) P%I'T)(

C%U'T S C%U'T O

+2 S 0

I3

P%I'T)(

P%I'T)(

A

T)!P S P%I'T)(

P%I'T)( S P%I'T)( A

P%I'T)( A S T)!P

P%I'T)( S P%I'T)( A

C%U'T S C%U'T A

I3

C%U'T

S 0

I3

+2

S 0

)3

'%

'%

)3


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ASCENDING ORDER OF AN ARRAY

ALGORITHM:

&) S*9()+= )+ ,73+)+= *939:

a. oad the array count

b. Compare the numbers and echan7e i necessary so that the to numbers are in

ascendin7 order.

c. ;ecrement count.

d. et the third number rom the array and repeat the process until count is 0.

PROGRAM

WRITE YOUR PROGRAM HERE>

EXAMPLE

900, 90,99 909,44 90-,08

OUTPUT900,08 90, 909,99 90-,44

OBSERVATION

INPUT

MEMORY ADDRESS VALUE

3T%P

)3

3T%P

)3


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OUTPUT

MEMORY ADDRESS VALUE

PROCEDURE

.)nter the mnemonics in the kit .9.)nter the input =alue in the location 900.

-.)ecute the Pro7ram

4.check the =alues are arran7ed in ascendin7 order in the location 900.

RESULT

EX NO: $ NUMBER CONVERSIONS USING 8086

DATE:


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AIM:

?a>.To con=ert the . To con=ert the binary number to 23CII

APPARATUS RE!UIRED:

23! 3I!U2T%(

ALGORITHM:

. oad the address in in memory.

FLOW CHART:

MAKE FLOW CHART AND 9)(3 '9*=9,;

O@39,()*+ (,@3

AIM:

?a>.To con=ert the . To con=ert the binary number to 23CII


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APPARATUS RE!UIRED:

23! 3I!U2T%(

ALGORITHM:

. .

FLOW CHART:

MAKE FLOW CHART AND 9)(3 '9*=9,;

O@39,()*+ (,@3

E'( % P9*=9,; 5*9 (9)+= ;,+)',()*+ 5*9 8086DATE:


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1 M*)+= B*72 O5 D,(, F9*; O+3 M3;*94 L*7,()*+ T* A+*(


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EXPERIMENTS BASED ON 8051EXP 6 DISPLAY A S!UARE WAVE

AIM:

> To display a suare a=e o 9 h#

9To display a suare a=e o ms

->enerate the he ile and =ie the output on C(%

ALGORITHM:


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. 3et the tmod re7ister in mode

9. Calculate the =alues o T"0 and T0

-. oad the =alues o T"0 and T%

4. 3et pin o port 0.

5. Krite a delay loop

CALCULATION:

,3 *5 TH0 ,+ TL0>

PROGRAM FOR GENERATING "KH S!UARE WAVE

ORG 000H

MOV P1,#00000000B

MOV A,#00000000B

MAIN: MOV R6,#220D

MOV R7,#183D

LOOP1:DJNZ R6,LOOP1

LOOP2:DJNZ R7,LOOP2

CPL A

MOV P1,A

SJMP MAIN

END

Program to delay 1mS.

DELAY: MOV R6,#250D

MOV R7,#250D

LABEL1: DJNZ R6,LABEL1

LABEL2: DJNZ R7,LABEL2

RE

OUTPUT OF SIMULATOR

PASTE YOUR PROGRAM HERE>


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HEX FILE:

PASTE YOUR HEX FILE HERE>

microprocessor ece lab manual.doc

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