jones polynomial

17
JONES POLYNOMIAL Ty Callahan

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Jones Polynomial. Ty Callahan. Historical Background. Lord Kelvin thought that atoms could be knots Mathematicians create table of knots Organization sparks knot theory. Background. Knot A loop in R 3 Unknot Arc Portion of a knot Diagram Depiction of a knot’s projection to a plane. - PowerPoint PPT Presentation

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Page 1: Jones Polynomial

JONES POLYNOMIALTy Callahan

Page 2: Jones Polynomial

Historical Background Lord Kelvin thought

that atoms could be knots

Mathematicians create table of knots

Organization sparks knot theory

Page 3: Jones Polynomial

Background Knot

A loop in R3

Unknot

Arc Portion of a knot

Diagram Depiction of a knot’s

projection to a plane

Page 4: Jones Polynomial

Diagram OK NOT OK

Page 5: Jones Polynomial

Equivalence Two knots are equivalent if there is an

isotopy that deforms one link into the other

Isotopy Continuous deformation of ambient space Able to distort one into the other without breaking

Nothing more than trial and error can demonstrate equivalence Can mathematically distinguish between

nonequivalence

Page 6: Jones Polynomial

Figure 8 Knot

Page 7: Jones Polynomial

Orientation Choice of the sense in which a knot can

be traversed

Page 8: Jones Polynomial

Crossings Orientation results in two possible crossings

Right and Left

Page 9: Jones Polynomial

Jones Polynomial Two Principles

1) Assign a value of 1 to any diagram representing an unknot

2) Skein Relation: Whenever three oriented diagrams differ at only one crossing, the Jones Polynomial is governed by the following equation

t−1R[t] − tL[t] = (t12 − t

−12)Q[t]

Page 10: Jones Polynomial

Ex. Trefoil Knots

Page 11: Jones Polynomial

1) Skein Relation for Right Trefoil

t−1R1[t] − t = (t12 − t

−12)Q1[t]

R1[t] = (t32 − t

12)Q1[t]+ t

2

Page 12: Jones Polynomial

2) Skein Relation for Link

t−1R2[t] − tL2[t] = (t12 − t

−12)

R2[t] = t2L2[t]+ t

32 − t

12

Page 13: Jones Polynomial

3) Skein Relation for Twisted Unknot

t−1 − t = (t12 − t

−12)Q3[t]

t−12 − t

32 = (t −1)Q3[t]

(t −1)(−t12 − t

−12 ) = (t −1)Q3[t]

Q3[t] = −t12 − t

−12

Page 14: Jones Polynomial

4) Substitute and Simplify

L2[t] =Q3[t] = −t12 − t

−12

R2[t] = t2(−t

12 − t

−12) + t

32 − t

12

R2[t] = −t52 − t

32 + t

32 − t

12

R2[t] = −t52 − t

12

Page 15: Jones Polynomial

4) Continued..

Q1[t] = R2[t] = −t52 − t

12

R1[t] = (t32 − t

12)(−t

52 − t

12) + t 2

R1[t] = −t4 − t 2 + t 3 + t + t 2

R1[t] = −t4 + t 3 + t

Page 16: Jones Polynomial

5) Compare to Left Trefoil

R1[t] = −t−4 + t−3 + t−1

R1[t] = −t4 + t 3 + tRight

Left

Page 17: Jones Polynomial

Conclusion The Jones Polynomial of the Right Trefoil

knot does not equal that of the Left Trefoil knot

The knots aren’t isotopes

“KNOT” EQUAL!!