indexing xray diffraction

$: Indexing Xray Diffraction$
EML 5930 (27-750), Spring 2005Advanced Characterization and

Microstructural AnalysisP. N. Kalu, D. Waryoba, A.D.

Rollett

INDEXING DIFFRACTION PATTERNS

Objectives

• be able to index an X-ray diffraction pattern,

• identify the Bravais lattice, and

• calculate the lattice parameters

Background

• We need to know about crystal structures because,

to a large extent, it determines the properties of

materials.

• X-ray diffraction (XRD) is one of the methods we

can use to identify the structures of crystalline

solids.

• The XRD patterns are somewhat like fingerprints

in that they are unique to each material.

• The information in an XRD pattern is a

direct result of two things:

1. The size and shape of the unit cells, which

determine the relative positions of the

diffraction peaks

2. Atomic positions within the unit cell, which

determine the relative intensities of the

diffraction peaks

Hence,

• we can calculate the size and shape of a

unit cell from the positions of the XRD peaks

and

• We can determine the positions of the atoms

in the unit cell from the intensities of the

diffraction peaks.

d-spacing

d-spacing, cont.

Typical XRD Diffractometer

Effect of Atom Position on the Phase Difference between Diffracted Rays

The path differencebetween 1’ and 2’ isgiven as:

sin2 0012 '' hdMCN

Scattering by a Unit Cell• The wave vector may be expressed analytically

as:

where A is the amplitude and is the phase difference, and can be written

as:

This relationship is applicable to any unit cell of any shape

sincos AiAAei

)(2 lwkvhu

Scattering• Find expression that simplifies the addition of the

scattered waves from each of the atoms in the unit cell.

• This expression has: – Amplitude as f with respect to the scattering atoms. – incorporated the phase of each wave in terms of the

hkl reflection and the uvw coordinates of the atom.

)(2 lwkvhuii feAe

Structural Factor, FAdding together all the waves scattered by individualatoms gives the structure factor F:

Body Centered Cubic (BCC)

The bcc crystal structure has atoms at (000) and (½ ½ ½) - centrosymmetric

• (200), (400), (220)22

4 fF

• (100), (111), (300) 02 F No reflection!

Face Centered Cubic (FCC)

The fcc crystal structure has atoms at (000), (½ ½0), (½0 ½) and (0 ½ ½)

No reflection!

Allowed Diffraction planes

PART1:INDEXING A DIFFRACTION PATTERN

FROM CUBIC MATERIALS

PROCEDURE

Mathematical

Two methods: Mathematical and Analytical

• For cubic materials, interplanar spacing is given as

• Recall Bragg’s law:

(1)

(2)

• Combining Eqn. (1) and (2) yields

or

, a are constants, hence is constant

• sin2 is proportional to h2 + k2 +l2 i.e. planes with higher Miller indices will diffract at higher values of .

Mathematical cont..

• In cubic systems, the first XRD peak in the XRD

pattern will be due to diffraction from planes with

the lowest Miller indices

• For the close packed planes i.e.:

– simple cubic, (100), h2 + k2 + l2 =1

– body-centered cubic, (110), h2 + k2 + l2 =2, and

– face-centered, (111), h2 + k2 + l2 =3

Mathematical cont..

Mathematical cont..

Allowed reflection for cubic lattices

• Primitive h2 + k2 + l2 = 1,2,3,4,5,6,8,9,10,11,12,13,14,16…

• Body-centered h2 + k2 + l2 = 2,4,6,8,10,12,14,16…

• Face-centered h2 + k2 + l2 = 3,4,8,11,12,16,19,20,24,27,32…

• Diamond cubic h2 + k2 + l2 = 3,8,11,16,19,24,27,32…

Worked Example

Worked Example cont…

Steps:

(1) Identify the peaks.

(2) Determine sin2

(3) Calculate the ratio sin2/ sin2min and multiply by the

appropriate integers.

(4) Select the result from (3) that yields h2 + k2 + l2 as an integer.

(5) Compare results with the sequences of h2 + k2 + l2 values to

identify the Bravais lattice.

(6) Calculate lattice parameters.

Worked Example cont…Step 1: Identify the peaks and their proper 2 values. Eight peaks for this pattern.

Worked Example cont…Step 2: Determine sin2


Step 3: Calculate the ratio sin2/ sin2min and multiply by the appropriate integers.


Step 4: Select the result from (3) that yields h2 + k2 + l2 as a series of integers.


Step 5: Compare results with the sequences of h2 + k2 + l2 values to identify the Bravais lattice.


Step 6: Calculate lattice parameters

AnalyticalRecall:

Let then2

2

4aK

For any cubic system, h2 + k2 + l2 = 1,2,3,4,5,6,8,9,10,11,12,…

If we determine sin2 for each peak and divide the values by

the integers 2,3,4,5,6,8,9,10,11…, we can obtain a common

quotient, which is the value of K

Worked Example

Steps:


(2) Determine sin2 (3) Calculate the ratio sin2 /(integers)

(4) Identify the lowest common quotient from (3) and identify

the integers to which it corresponds. Let the lowest common

quotient be K.

(5) Divide sin2 by K for each peak. This will give you a list

of integers corresponding to h2 + k2 + l2 (6) Select the appropriate pattern of h2 + k2 + l2 values and

identify the Bravais lattice.

(7) Calculate lattice parameters.


PART2:INDEXING A DIFFRACTION PATTERN

FROM NON-CUBIC MATERIALS

• Many materials have crystal structures that are not cubic.

In other words, they are based on noncubic Bravais

lattices (e.g., hexagonal, tetragonal, orthorhombic, etc…).

In fact, many

• intermetallics, semiconductors, ceramics, and minerals of

interest have very complicated structures.

Background

Mathematical• Consider the plane spacing equations for the crystal

structures of interest.

• Recall Bragg’s law:

(2)

(1)

• Combining Eqn. (1) and (2) yields

Mathematical cont..

• Which can be rearranged in terms of sin2 as

Mathematical cont..• Consider Hexagonal closed packed (HCP) crystal structure

• a and c/a are constants for a given diffraction pattern, hence is constant for any pattern

• The pattern can now be indexed in by considering the terms in parenthesis:

(3)

Mathematical cont..

• The first term only depends on the indices h and k. Thus its value can be calculated for different values of h and k.

• The second term can be determined by substituting in the known c/a ratio, e.g. for zinc (c/a = 1.8563)

Mathematical cont..

• The structure factor calculation for hexagonal systems

yields the following rules:

Mathematical cont..• Add the values for the two terms that are permitted by

the structure factor (i.e., the values corresponding to the allowed hkl values) and to rank them in increasing order.

Mathematical cont..• We can calculate a by looking for peaks where l = 0 (i.e.,

hk0 peaks). If you substitute l = 0 into Eqn. (3), yields:

• Similarly, values for c can be determined by looking for 00l type peaks. In these instances, h = k = 0. Thus,

Worked Example


Steps:


(2) Determine values of for reflections allowed by the

structure factor.

(3) Determine values of for the allowed reflections and the

known c/a ratio

(4) Add the solutions from parts (2) and (3) together and re-arrange

them in increasing order.

(5) Use this order to assign indices to the peaks in your diffraction

pattern.

(6) Look for hk0 type reflections and calculate a for these reflections.

(7) Look for 00l type reflections. Calculate c for these reflections.

Warning!

This method, though effective for most powder XRD data, can

yield the wrong results if XRD peaks are missing from your

XRD pattern. In other words, missing peaks can cause you toassign the wrong hkl values to a peak. Other methods should be available.


Analytical Method• Consider HCP plane spacing equation (Eqn. 3)

• Since a and c/a are constants for a given diffraction pattern, then

(3)

• Since h, k, and l are always integers, h2 + hk + k2 can only have values like 0, 1, 3, 4, 7, 9, 12… and l2 can only have values like 0, 1,4, 9, …

Analytical Method cont…

• We need to calculate sin2θ for each peak,

• divide each sin2θ value by the integers 3, 4, 7, 9…and

• look for the common quotient (i.e., the sin2θ/n value that is

equal to one of the observed sin2θ values).

• The sin2θ values representing this common quotient refer to

hk0 type peaks.

• Thus this common quotient can be tentatively assigned as

A.

• Re-arrange terms in the modified equation to obtain C. This is done as follows:

Analytical Method cont…

• Get the value of C by subtracting from each sin2θ the values

of n.A (i.e., A, 3A, 4A, 7A,…)• Next, look for the remainders that are in the ratio of 1, 4, 9,

16…, which will be peaks of the 00l type, and determine C

from these peaks. • The remaining peaks are neither hk0-type nor 00l type.

Instead they are hkl-type. They can be indexed from a

combination of A and C values.

Worked Example

Steps:

(1) Identify the peaks and calculate sin2θ for each peak.

(2) Divide each sin2θ value by the integers 3, 4, 7, 9….

(3) Look for the common quotient.

(4) Let the lowest common quotient represent A.

(5) Assign hk0 type indices to peaks.

(6) Calculate sin2θ- nA where n = 1, 3, 4, 7….

(7) Look for the lowest common quotient (LCQ). From this we

can identify 00l type peaks. Recall, that 001 is not allowed

for hexagonal systems. The first 00l type peak will be 002.

We can calculate C from:

(8) Look for values of sin2θ that increase by factors of 4, 9… (this is because l = 1, 2, 3…and l2 = 1, 4, 9…). Peaks exhibiting these characteristics are 00l type peaks, which can be assigned the indices 004, 009, etc…). Also note that the values of 2 sin θ will be some integral number times the value observed in (7) which indicates the indices of the peak

(9) Peaks that are neither hk0 nor 00l can be identified using combinations of our calculated A and C values

(10) Calculate the lattice parameters from the values of A and C.

CONFUSED?

Identification of Chemical Compound

Chemical Compounds• The diffractometer can also be used to identify

the chemical compounds that are associated with a specimen. For example,– A corrosion or oxidation product on the surface of a

specimen can be determined

• Consider the oxidation product of a heavily scaled steel part. Analyze by x-ray diffraction.– Scrape oxide from the surface of the part– Grind into fine powder– Glue to a glass slide– Place slide in the beam of x-rays, and scan 2 angles

form 20 to 160o.

indexing xray diffraction

Documents

l2 values

diffraction peaks

diamond cubic h2

example contsteps

sequences of h2

appropriate pattern

bodycentered h2

facecentered h2