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1/19/18, 12(51 PMHow to Solve a 4x4 Cube- The Rubik's Revenge
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Howtosolvea4x4Rubik'sCube
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[r]
[2R]
The4x4x4cubeisthenextpuzzleintheRubik'scubeseries,knownastheRubik'sRevenge.Althoughseemstobemuchmoredifficultthanthefamous3x3,solvingthe4x4Rubik'srevengeisverysimilartoitandrequiresonlyfewmorealgorithmstolearn.
Learnhowtosolvea3x3cubefirst
Inordertosolvethe4x4cubeyouwillneedtoknowhowtosolvea3x3Rubik'scubefirst.IfyouarenotfamiliarwiththesoluFonordonotrememberit,pleasegoandreviewthe3x3soluFonbeforeyouconFnue.Itisbesttomasterthe3x3soluFonbeforegoingforthe4x4,thoughit'snotamust.
MoveNota9ons
SamemovenotaFonrulesapplyforthe4x4cubeaswell,withonly2differences:1.Lower-caseleMersmeanturning2layersofthecorrespondingface.2."2"beforethefaceleMer(e.g.2R)meansmovingonlytheinternallayerofthecorrespondingface.
Mechanics
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The4x4mechanicsisabitdifferentfromtheclassic3x3Rubik'scube.Thereisnosinglecenterpiece,but4centerpiecespercolor;thereforetheyarenotfixedintheirposiFons.
NofixedCenterpieces:Therearenofixedcenterpiecesinthe4x4cube,meaningthesecenterpiecescanmovearoundthecube,andreplaceplaceswitheachother(unlikethe3x3whereyellowwillalwaysremainoppositetowhite,forexample).Thatmeanswecannotdeterminethecubecolor-schemebylookingatthecenterpieces(we'llusememory,orcornerpieces).AsmenFoned,thereare4centerpiecesforeachcolor.For4centerpiecessolvedtogetherwecallacenterblock.(Intheimage:exampleofasolvedredcenterblock)
MulFpleedgepieces:everyedgepieceinthe4x4cubehasanidenFcaledgepiecearoundthecube,meaningthereare2edgepiecesofeverytype(e.g.2yellow-rededgepieces).Inthe2ndstepwearegoingtopairthemuptogether.For2idenFcaledgepiecespaired-uptogetherwecallanedgeblock.(Intheimage:exampleofapairedred-blueedgeblock)
Thesolu9on
Step1Step2Step3Step4
Step1:Solvingthecenterpieces
Thefirststepisaboutcompletelysolvingthe6centerblocks,whichare24piecesintotal.We'llstartbysolvingthe1stcenterblock.Goodluck!
Save moneytoday...
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Solu9on:[r'Fr]
InthisguideIchosetheyellowcolortobeginwith.Solvingthefirstcenterblockshouldbefairlyeasy,astherearenopiecestopreserve.Hereishowyoushouldapproachit:Startbymatching2centerpiecesadjacentlytoeachother,andbringthe3rd&4thpiecestothem.
Example:solvingthe4thcenterpiece.
Explana9on:bydoinganr'moveyouwillbringdowntheupper-rightyellowcenterpieceonthetopfaceintothefrontface(nowitwilladjacentlymatchthecenterpieceonfrontface),thenanFmovetoalignbothpiecesontherightsideofthefrontface,andfinallyanrmovetobringthembothupwardsintothetopface,andformacompleteyellowcenterblock.
IftheyellowpieceonthefrontfacewereonadifferentposiFoninthefrontface(outofthe4possibleposiFons),youcouldjustmakesomeFturnstoadjustit.Samegoesforthetopface.
IkepttheinstrucFonsshortforthispart,asit'sanintuiFvepart.JusttakesomeFmetopracFcethemovementsofthe4x4cube,andyouwillshortlymastertheabilitytocreatecenterblocksintuiFvely.
The2ndcenterblock:Thesecondcenterblocktosolveneedstobetheoppositeincolortothepreviouswe'vejustsolved:Sincewe'djustsolvetheyellowcenterblock,nowweshouldsolvethewhitecenterblock(Thisappliesonlytooriginalcolorschemecubes!Whereyellowisinoppositetowhite,redtoorange,andbluetogreen.)
Flipthecubeupsidedown,sotheyellowcenterblockwillbeonboMom.ThewaytosolvethewhitecenterblockisbyreposiFoningthewhitecenterpieces,onebyone(orinpairs),intothetopface(withoutharmingthesolvedcenterblockonboMomofcourse).
SincetheonlypiecestopreservearetheboMom&topcenters,youcanfreelyturn:F/B/R/Llayers.
Thewayto"upload"acenterpiecefromasideface(F/B/R/L)intotheUpperfaceisusingthe
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Solu9on:[r'F2r]
followingmoves:
Example:uploading2whitecenterpiecesfromtheFface(sameforallfaces).
Explana9on:sincewehavetopreservethecenterpiecesattheboMom,justdoinganr/lmoveisnotenough.Therefore,wemakeanr'moveandtakedownthenon-whitecenterpiecesontopintotheFface,thenswitchthemwiththe2whitepieces,bydoingF2.(Thereare2yellowpiecesonthebackfaceatthemoment,whichwillgobackintotheirsolvedposiFoninthenextmove).Nowwe'llfinallyreversether'movebydoinganrmove.ThewhitepiecesarenowcorrectlyposiFonedonthetopface,andallyellowpiecesontheboMomremainedunharmed.
Thisisanimportantideainunderstandingthe4x4soluFon.It'sjustlikean"elevator"move,webringdownthe"elevator"towardthepieceswewanttoreposiFon,"upload"thepiecesintothe"elevator",andelevaFngthemupwardsintothesolvedposiFon.ThatwayweareabletoposiFonpieceswhilepreservingalreadysolvedpieces.
When3centerpiecesareontop:
Sameideaisimplementedhere:We'llusetheelevatorideaaswell.Infactthealgorithmisalmostsimilar-
Solu9on:[r'Fr]
TheonlydifferenceisthatwehavetomakeonlysingleFturn,becauseonewhitepiecewasalready"inside"theelevator.
Ifthe3whitepiecesontop,orthepieceonthefrontface,areposiFoneddifferentlythanintheexample,allyouhavetodoisjustsomeU/Fturnstoadjustthemlikeintheimageandsolve.
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Example:forming2adjacentredpieces.
Solu9on:[U'rU]
The3rdcenterblock:wecanchooseanyoftheremainingfourcolorstobethethirdblocktosolve.InthisguideIchosered.
Itisbesttorotate(flip)thecubesothesolvedcenterblocks(yellow&white)willbeontheR&Lfaces.
Makesomer/r'&U/F/B/Dmovestoform2adjacentredpieces.Rotate(flip)thecubesotheywillappearonthetopface(yellow&whitesFllonR&Lfaces).ThenmakesomeUturns,ifneeded,inordertoalignthe2redcenterpiecesonthelecsideofthetopface(seeimageforlec/rightinternalsideexplanaFons)(canbetherightsideaswell,I'mpersonallyusedtolecsinceI'mright-handed),likeintheexamplebelow(rightimage):
Explana9on:we'llmakeaU'move(sowhenwe'llmakethermove,thetworedpieceswillbecomeadjacenttoeachother,andnotdiagonal),thenwe'llmakethermovetopair-upthe2redcenterpieces,andfinallywe'llmakeaUmovetoalignthembothonthelec.
Solvingtheremaining2pieces:ThebestwaytodoitisbyposiFoningoneredcenterpieceonthelecside(internallec)ofthecube,andthesecondontherightside,thenmakinganr/r'movetopairthemup.Inthefollowingexample,bothoftheremainingpiecesareontherightside(internalright)ofthecube(oneisonthetopface):
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Solu9on:[F2r'Fr]
Solu9on:[r'F'rU]
Explana9on:Firstwe'llmakeanF2movetoreposiFononepieceintothelecside(sothenextr'movewillnotaffectit,anditwillpairupwiththepiececurrentlyontop)(ThereasonwemakeF2,andnotF',isbecausethatinthenextmovewewantthemtopair-upadjacentlytoeachother,andnotdiagonally).Thenwe'llmakether'movetopair-upthepieces.Nowwe'llmakeanFmovetoalignbothpiecesontherightsideoffrontface.Finallywe'llmakeanrmovetosolvethemintotheirfinalposiFononthetopface,soall4redcenterpiecesarecompletelysolved.
*Thisexampleaboveappliestoallpossiblecases,asbydoingr/r'&F/B/D/UmovesyoucanposiFonthe2remainingcenterpiecesintothesamesituaFonandsolvethesameway.
The4thcenterblock:Thefourthcenterblocktosolveistheoppositeincolortotheonewe'vejustsolved,meaningtheorange(again,appliesonlytooriginalcolor-schemecubes,wheretheorangeisoppositetored).
Firstwe'llflipthecubeupsidedownsotheredcenterwillbeontheboMomface(yellow&whitesFllonL&Rfaces).We'llhavetobringalltheorangecenterpiecesintothetoplayer.Hopefullysomeofthemarealreadythere.
We'llusethe"elevator"principletouploadtheorangepiecesintothetop,withoutharmingtheredpiecesontheboMom.Hereisanexampletohowit'sdone:
Explana9on:firstwe'llmakether'move,totakedownthe"elevator"withthenon-orangecenterpiecesontop.Thenwe'llmakeanF'movetouploadthepieceintotheelevator(DoingF',andnot
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Solu9on:[r'Fr]
Solu9on:[F2r'Fr]
F2,isjustright,inordertomatch-upadjacentlywiththeorangepieceontop).Nextwe'llmakethermovetoelevatetheelevatorbackupintothesolvedposiFon.Finallywe'llmakeaUmovetoalignbothpiecesonthelecsideofthecenter(inorderto"free"theelevatorforthenext2pieces).
Solvingtheremaining2centerpieces:thebestwaytosolvetheremaining2piecesisbyreposiFoning1pieceataFmeintothetoplayer,usingtheelevatorprinciple:
(Ifyouforgot,wecannotjustmakean[r]move,becausethereareredcenterpiecestopreserveontheboMom)Explana9on:we'llmakeanr'move(takingdownthe"elevator"),thenwe'llmakeanFmovetouploadtheorangepieceintoit,finallywe'llmakeanrmovetouploadtheorangecenterpieceintothesolvedposiFon.(Note:again,usingtheelevatorprinciple,noredcenterpiece,oryellow/whitewasharmed).
Nowwe'llapplyagaintheexactsameideaforthelastcenterpiece:
Explana9on:Firstwe'llmakeanF2movetoposiFontheorangepieceonthelecinternalsideonthecube(WemakeF2,andnotF,becausewewantittoadjacentlymatchtheotherorangepiecethatwillgodownthenextmore).Thenwe'llmakeanr'move(takingdowntheelevator),thenanFmovetouploadbothpiecesintothe"elevator".Finallywe'lluploadbothpieceswithanrmove,andsolvetheenFreorangecenterblock.
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Solu9on:[D'r2U'r2]
The5th&6thcenterblocks:Thelast2centerblocksaresolvedsimultaneously,asbysolving1color,theothercolorpieceswillautomaFcallyendupintheoppositecenter,whichistheonlyavailablecenterlec.
Important!Thesecenterscanbesolvedcorrectly,andincorrectly.Let'schoosethegreencolortofindoutitscorrectposiFon(outofthe2availableplacestobe).Accordingtotheoriginalcolorscheme,whentheyellowcolorisontop,andtheredcolorisonthefrontface-thegreenshouldbeontheright.
Flipthecubesothegreen-to-befacewillbeontop.
Solvingtheselast2centersiseasierthanitslooks,anditisdonebydoingr2&U/Bmovesonly.
1)Firstget2adjacentgreenpiecesonthetoplayer(mostprobablyit'salreadythere),andalignthemtothelec.Hereishowtodoit:
PosiFonagreencenterpieceonthelecside,usingsomeUmoves.Makeanr2move,andseewhether2adjacentgreenpiecesformedonthetopface.IfsomakeaU/U'movetoalignthembothonthelecside,andmakeanotherr2toreverseandbringeverythingbacktoplace.
Ifacerdoingthefirstr2moveyouhavenoadjacentgreencolors,reversether2move,andmakesomeDmoves(lookattheboMomfacetoseehowmanyneeded),sowhenyou'llmakeanotherr2moveagain,agreenpiecewillbereposiFonedintothetopandwillmatch-upwiththegreenpiecewhichisalreadythere.
Example: BoWomfacelookslike:(xrota9on)
Inthiscase,thereisnoexisFnggreenpairontopalready(LookonlyatthelecimagefornotaFons).Explana9on:firstaD/D'moveisrequiredsothenextr2movewillformanadjacentpairofgreencentersonthetop.Thenanr2movetomatch-up2greenpiecestogether(elevatorcomesupwards),thenaU'movetoalignbothgreenpiecesonthelecside("unloading"fromthe
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Solu9on:[Dr2D'r2]
elevator).Finallyanr2movetoreversealltheotherpiecesbacktoplace(elevatorgoesbackdown).
2)Solvingtheother2greenpiecesintothetopface:TherearetwoopFonshere-whetheronlyonepieceisontheboMom,orbothpiecesareontheboMom.
Ifonepieceisontop:theeasiercase.AlignthegreencenterpieceontheboMomtothelecsideoftheboMomface(bydoingD/D'),inawaythatbythenextr2moveitwilladjacentlymatchwiththesecondgreenpiece.Makeanr2moveandmatch-upthe2greencenterpieces.ThenjustmakeaD/D'movetoalignbothpiecesontherightsideoftheboMomcenter.Finallymakeanr2movetouploadbothpiecesintothetop.Allgreenpiecesaresolvednow,andallbluepiecesareontheboMom(Allcenterpiecesaresolved!)
Example:
IfbothpiecesareontheboMom:thereare2possiblecases-adjacentordiagonaltoeachother-
Diagonal:[r2D/D'r2].ExplanaFon:makeanr2movesoonegreenpiecewillgoupwardsintothetoplayer.ThenmakeaD/D'movetoreposiFontheremaininggreenpieceontheboMomintothesecondavailablespotonthelecside,soitwilladjacentlymatchthesecondpiececurrentlyontoponceitwillcomebackdownthenextmove.Nowmakeanr2movetobringthegreenpiecebackdown.Thegreencenterpiecesarenowadjacentlytoeachother-ConFnueaccordingtotheadjacentcaseinstrucFonsbelow.
Adjacent:[r2D2r2].ExplanaFon:alignbothgreenpiecesintothelecsideofthecenterareaattheboMom(bydoingsomeD/D'moves),thenmakeanr2move(elevatorprinciple),DoaD2movetoputbothgreenpiecesintotherightside(inordertobeinglicedupwardsthenextmove),andfinallyreversether2movetobringthegreencentersintothetopfaceandcompletelysolvethe
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Solu9on:[D'r2D2r2]
green(&blue!)centerblock!.(Seeexamplebelow)
Example: BoWomlookslike:(xrota9on)
That’sit!Youhadsolvedall6centerblockscorrectlytoeachother.IrecommendyoutostophereandpracFceonsolvingallcenterblocksofthe4x4cubeFllyoufeelcomfortableindoingsointuiFvely.Itshouldn'tbetoohardforanexperienced3x3Rubik'scubesolvertodosoinadayortwo.
Step2-Pairing-upalledgepieces
Thesecondstepisaboutpairing-upalltheedgepieceswiththeiridenFcaltwinsonthe4x4cube,intoedgeblocks.Thereare12edge-blockstosolve,meaning24edgepiecesintotal.Attheimagetotherightyoucanseeanexampleof2white-blueedgepiecesmatched-uptogetherintooneedgeblock(awhite-blueedgeblock)
TheedgeblockspermutaFonsaroundthecubearecompletelymeaninglessatthisstep.
Solvingthefirst4edgeblocks:Thewaytogohereisbypairing-uptheedgepiecesintoblocksandstoringthemonthetop&boMomfaces(=8availableplaces.We'llstartwiththe4ontop).RememberyouarefreetomakeanyU/D/B/R/L/Fmovesyouwant,asnononthemaffectthecenterpieces.
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Algorithm:[dRUR'd']
Solu9on:[L'UL]
Hereishowit'sdone:Lookfor2idenFcaledgepiecesthatareposiFonedlikeintheimage,thenexecutethenextalgorithm:
Thisalgorithmispairing-upthetwoedgepiecesintoablockandstoringthemonthetopface,withoutharminganycenterpiece.Here'show:bydoingadmove,the2edge-pieceswillpair-up.ThenusingtheRmovetheformededge-blockwillmoveupwardsintothetoplayer.Nextwe'llmakeaU/U'/U2movetosecuretheblockonthetop(soitwon'tgobackdowninthenextmove-R').We'lldotheU/U'/U2accordingtotheedgeblocksonthetop,iftherearenosolvededge-blocksthenitdoesn'tmaMer.Iftherearealreadysolvedblocks-wewanttomakesurenottotakethemdowninstead.Finallywe'llmakeR'd'tobringbackallotherpiecesintoplace.
Usingthismethodyou'llbeabletoquicklypair-upandstoreontop/boWomthefirst8edge-blocks.
Howtobringtheedgepiecesintothecaseabove?
FirstbringbothpiecesintothesamefaceusingR2/L2/F2/B2movesandU/Dmoves.Hereisaquickalgorithmtomove2edgesintothedesiredposiFon(seeimage):
Usingthissimplealgorithmyou'llbeabletocorrectlyposiFon2edgepiecesthatareonthesamefaceandhasthesamecoloronthemutualface(ifnot,justmakeaU'move)intothedesiredcase.Thenjustperformthecorrespondingalgorithm[dRUR'd'],andbothpieceswillpair-upand
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Example:solvingthe4thedgeblock.
Solu9on:[LD'L'][d'L'ULd]
Example:solvingthe8thpair.
Solu9on:[d'L'ULd](exactlythesamewaydiscussedabove)
storeonthetopface.
Usingthemethodaboveyou'llbeabletobringall8firstedgepairsintothesimplecaseposiFon.StartwiththeeasieredgesthatarealreadyinthisposiFon.Thelessedgepieceswillremain,theeasieritwillget.
Ifyouhaveanyalreadypaired-upedgesonthesidesofthecube(betweenthefrontandrightfacesforexample)justmakeasimpleR/R'/L/L'toputitonthetoplayer.Forpaired-upedgesontheboMomjustmakeadoublemoveofitssidefacetobringitintothetopface.
Explana9on:inthisexampleyoucanseethat3edgeblocksarealreadyformed,andthefourthissplitontheFface.Inthefirst3moves(firstbrackets)wemovearoundtheedgepieceattheboMomintothe"ideal"casewheretheyarebothonthesidefaceswithdifferentcolorsontheFface,thenjustsolvingitthewaydiscussedabove(it'sthesamealgorithm,justonthelecside-LinsteadofR)
Nowall4edgeblocksontopareformed,we'llconFnuetothenextones:
Solving5th-8thedgeblocks:Flipthecubeupsidedownsoallthepaired-upedgepieceswillbeontheboMomlayer.Nowjustdothesameforthenext4edgepairs,usingthesamealgorithmsandideasshownabove.Theonlydifferenceisthatforanalready-solvededgeblockonthesidefaces:insteadofusingRmove,execute–[RUR']touploadtheedgeblockintothetoplayerwhilepreservingtheboMomedgeblocks.
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Algorithm:[dRF'UR'Fd']
Solu9on:[RF'UR'F]
InthisexamplealledgeblocksontheboMomareformed,andanother3onthetopfaceareformedaswell.Remainingisonlyonetosolve.It'sgoingtobethered-whiteinourcase(secondpieceisbetweentheFront&Lecfaces).Itisbeingsolvedexactlythesamewayasshowninthelastexample.
Acersolvingall8edgeblocksonthetop/boMomfaces,conFnuetothelastfour:
Solvingthelast4edgeblocks:Solvingthelast4edgeblocksisabittrickier,howeververyshort.Herewewantthe2twinedgepiecestobewiththesamecolorintheirmutualface(Likeintheimagebelow).Thefollowingalgorithmsolvesbothedgepairssimultaneouslywhilepreservingallotheredgeblocks¢erpieces:
Thisisanimportantalgorithm;it'sanalgorithmyou'llhavetomemorizeinordertosolvethe4x4cubebyheart.TakesomeFmetogetit.
Usingthisalgorithmyouwillsolveall4lastedgepairs.
Iftheedgepiecesdon'thavethesamecolorontheirmutualface,likeintheexamplebelow,usethefollowingmovesequence:
Explana9on:thisalgorithmwillflipthe2edgepiecesbetweenthefront&rightfaces.Nowthe
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pieceswillmatchforthecasesolveabove.
Ifonlyoneedgepairhasthesamecoloronthemutualface,whilethesecondpairdoesnothave(ornoteventhesameedgepieces),executethealgorithmanyway!Thatwayyou'llsolve1edgeblockoutofthe4remained,andconFnueFllall4aresolved.
That’sit!Nowalledgepiecesshouldalreadybepairedupwitheachother.YoumightnoFcethecubelookslikearegular3x3Rubik'scube,andthat'showyouaregoingtosolveitnow,asexplainedinthenextstepinstrucFons.
Step3-Solvinglikea3x3Rubik'scube(Tilllastlayer)
Thecubenowactuallylookssimilartoaregular3x3x3Rubik'scube!Considerthecenterblocksasasinglecenterpiece,andtheedgeblocksassingleedgepieces.
Intheimagesaboveyoucanseethatthe4x4piecesarearrangedthesameasthe3x3cube.
SofromnowonjustconFnueandsolvethecubelikeitwasa3x3Rubik'scubeunFlthelastlayer(justbeforeorienFngthelastlayer)
ThereasontosolveonlyFllthelastlayer,andnotcompletethecube,isbecausethereare2specialcasesinthe4x4cubethatcanoccur,whichareimpossibleinthe3x3cube.TheyarecalledpariFes.
Step4-Solvingthelastlayer(OLL&PLLpari9es)
ThesearethepossiblecasesthatcanhappenduringthesoluFonofa4x4cube:
=
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OLLparity:
[rU2xrU2rU2r'U2lU2r'U2rU2r'U2r']
PLLparity: (Topview)
[2R2U22R2u22R22U2]
WhatisOLLparity?OLLparityiswhenonlyoneedgeblockisnotoriented.Thisisanimpossiblecaseinaregular3x3cube.Thiscaseissolvedusingthealgorithmabove.It'simportanttoexecutetheOLLparityalgorithm,ifneeded,beforesolvingthelastlayer,becauseitdoesnotpreservethelastlayerpiecesposiFons.TheprobabilitytoencounteranOLLparityduringa4x4solveis50%
WhatisPLLparity?PLLparityiswhenonly2edgepiecesareremainedunsolvedwhiletherestofthecubeisfullysolved.Thiscasealsocannothappenona3x3cube(reasonsbelow),andisbeingfixedbythePLLparityalgorithm.ThePLLparityalgorithmdoespreserveallpiecesbuttheswitchededgepieces,andthereforecanbeusedattheendofthesolving(acersolvingallotherlastlayerpieces).TheprobabilitytoencounteraPLLparityduringa4x4solveis50%
Note!YoumightencounteraweirdPLLcase,whereallpiecesaresolvedbut2cornersforexample.That’sbecauseofthePLLparity.AcerapplyingthePLLparityalgorithmit'llbecomeasolvablePLLcase.
Nota9onsexplana9on:ThePLLparityusesaninternallayermovement.Thenumber"2"shownbeforethespecifiedfaceleMer,meansmovingtheinternallayerofitsface.Example:[2R]=[rR'].Themove"2R"canbedonebymovingbothlayersbydoingr,andthenreturningtheRfacebackbydoingR'.Themove"2R2"meansmovingthisinternallayertwice.YoucanseeimageexamplesintheintrosecFonabove.
WhyPLLparityoccurson4x4cubeswhileit'simpossibleonaregular3x3cube?ThereasonisbecauseofthemechanicsandmathoftheRubik'scube.Asyouknow,movingonly2edgepieceswhilepreservingallotherpiecesisimpossible*(U-permalgorithmaffects3edge
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pieces,whichisthelowestpossible).Movingonlyonepieceisclearlyimpossible(wherewillitgowithoutswitchingwithanotherpiece?).
Therefore,acasewhereonly2edgepiecesneededtobeswitchedisanimpossiblecaseona3x3cube.However,ona4x4cubeit'snotreally2pieces,but4pieces,and4piecesneededtobeswitchedbetweenisapossiblecase.
(*Atleastnotbylegalmoves,theonlypossiblewaytodothatisbydisassemblingthe2piecesbybreakingthecubeandassemblingitwrongly(thecubewillbecomenon-solvable)
Thesamerulesapplyforallcubes(3x3,4x4,5x5,etc..)
WhataboutOLLpari9es?OLLparityhappensinthe4x4cubeforthesamereasonsaswell.TheminimumnumberofpiecesorientaFonwhilepreservingallotherpiecesis2(appliesforallsizesofcubes).Thereforeit'simpossiblethatonly1edgepiecewillbeun-orientedina3x3cube.Whileina4x4cubeitisactually2differentedgepieces(eventhoughwetreatthemas"oneedgeblock")whichisapossiblecase.
AcerunderstandingthepariFes,let'sconFnueandfinishsolvingthe4x4cube:
IfacercompleFngstep3(solvingthecubeunFlthelastlayer)younoFcedthatanOLLparityoccur-thenapplythealgorithmandconFnueinsolvingthelastlayerusingthe3x3solvingtechnique.ApplyaPLLalgorithmaswellifneeded.
That’sit!Youhadjustsolvedthe4x4Rubik'sRevenge!JustkeepandpracFceonsolvingthe4x4cubeFllyou'llbeabletodoitwithoutusingthisguide.Youwillbehappytoknowthatyouhavetomemorizeonly4algorithmsforthat(2pariFes+2algorithmsfromstep2)!Congratula9ons!
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Ihopeyouenjoyedsolvingthe4x4Rubik'sRevengecube.Youareinvitedtoleaveacommentinourfacebookpageandwriteaboutyourexperiencewithyoursolving.
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