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P. Piot, PHYS 630 – Fall 2008 Helmholtz Equation Consider the function U to be complex and of the form: Then the wave equation reduces to where U ( r r , t ) = U ( r r )exp 2"#t ( ) " 2 U ( r r ) + k 2 U ( r r ) = 0 k " 2#$ c = % c Helmholtz equation

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P. Piot, PHYS 630 – Fall 2008

Helmholtz Equation

• Consider the function U to be complex and of theform:

• Then the wave equation reduces to

where

!

U(r r ,t) = U(

r r )exp 2"#t( )

!

"2U(

r r ) + k

2U(

r r ) = 0

!

k "2#$

c=%

c Helmholtz equation

P. Piot, PHYS 630 – Fall 2008

Plane wave

• The wave

is a solution of the Helmholtz equations.

• Consider the wavefront, e.g., the points located at a constant phase,usually defined as phase=2πq.

• For the present case the wavefronts are decribed by

which are equation of planes separated by λ.

• The optical intensity is proportional to |U|2 and is |A|2 (a constant)

P. Piot, PHYS 630 – Fall 2008

Spherical and paraboloidal waves• A spherical wave is described by

and is solution of the Helmholtz equation.

• In spherical coordinate, the Laplacian is given by

• The wavefront are spherical shells

• Considering give the paraboloidal wave:

-ikz

P. Piot, PHYS 630 – Fall 2008

The paraxial Helmholtz equation• Start with Helmholtz equation

• Consider the wave

which is a plane wave (propagating along z) transversely modulatedby the complex “amplitude” A.

• Assume the modulation is a slowly varying function of z (slowly heremean slow compared to the wavelength)

• A variation of A can be written as

• So that

Complexamplitude

Complexenvelope

P. Piot, PHYS 630 – Fall 2008

The paraxial Helmholtz equation• So

• Expand the Laplacian

• The longitudinal derivative is

• Plug back in Helmholtz equation

• Which finally gives the paraxial Helmholtz equation (PHE):

TransverseLaplacian

P. Piot, PHYS 630 – Fall 2008

Gaussian Beams I• The paraboloid wave is solution of the PHE

• Doing the change give a shifted paraboloid wave (whichis still a solution of PHE)

• If ξ complex, the wave is of Gaussian type and we write

where z0 is the Rayleigh range

• We also introduce

Wavefrontcurvature

Beam width

P. Piot, PHYS 630 – Fall 2008

Gaussian Beams II• R and W can be related to z and z0:

P. Piot, PHYS 630 – Fall 2008

Gaussian Beams III• Expliciting A in U gives

P. Piot, PHYS 630 – Fall 2008

Gaussian Beams IV• Introducing the phase we finally get

where

• This equation describes a Gaussian beam.

P. Piot, PHYS 630 – Fall 2008

Intensity distribution of a Gaussian Beam

• The optical intensity is given by

z/z0

P. Piot, PHYS 630 – Fall 2008

Intensity distribution• Transverse intensity distribution at different z locations

• Corresponding “profiles”

-4z0 -2z0

-z0 0 -4z0 -2z0

-z0 0

z/z0

P. Piot, PHYS 630 – Fall 2008

Intensity distribution (cnt’d)• On-axis intensity as a function of z is given by

z/z0

z/z0

P. Piot, PHYS 630 – Fall 2008

Wavefront radius• The curvature of the wavefront is given by

P. Piot, PHYS 630 – Fall 2008

Beam width and divergence• Beam width is given by

• For large z

P. Piot, PHYS 630 – Fall 2008

Depth of focus• A depth of focus can be defined from the Rayleigh range

2z0

!

2

P. Piot, PHYS 630 – Fall 2008

Phase• The argument as three terms

• On axis (ρ=0) the phase still has the “Guoy shift”

• At z0 the Guoy shift is π/4

Phase associatedto plane wave

Spherical distortion of the wavefront

Guoyphase shift

Varies from -π/2 to +π/2

P. Piot, PHYS 630 – Fall 2008

Summary• At z0

– Beam radius is sqrt(2) the waist radius– On-axis intensity is 1/2 of intensity at waist location– The phase on beam axis is retarded by π/4 compared to a plane

wave– The radius of curvature is the smallest.

• Near beam waist– The beam may be approximated by a plane wave (phase ~kz).

• Far from the beam wait– The beam behaves like a spherical wave (except for the phase

excess introduced by the Guoy phase)