ex 6 5 fsc part1
TRANSCRIPT
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Exercise 6.5 (Solutions)
Textbook of Algebra and Trigonometry for Class XIMerging man and maths Available online @ http://www.mathcity.org, Version: 1.0.0
Question # 1
The sequence of the deposits is10, 15, 20, ……………. to 9 terms
Here a1 =10 , d = 15 − 10 = 5 , n = 9Since
S = n
[2a + (n −1)d ]2
1
⇒ S9
= 9
[2(10) + (9 −1)(5)] =
9 [20 + 40]
=9
(60) = 2702 2 2
Hence the total amount he deposits is Rs. 270.
Question # 2The sequence of the trees from top to base row
is 1, 2, 3, ……………Let n be the total number of tress in base row then
a1 = 1, d = 2 − 1 =1 , n = n , Sn = 378
Now Sn
= n
[2a + (n
−1)d ]2
1
⇒ 378 = n
[2(1) + (n −1)(1)] ⇒ 756 = n [2 + n
−1]2
⇒ 756 = n (n +1) ⇒ 756 = n 2 + n
1Þ n 2 + n − 756 = 0
Son =
−1 ±
( − 1) 2 − 4(1)( − 756)
2(1)
⇒ n = − 1
±1 + 3024
= − 1
±2
3025 =
− 1 ± 55
2 2
So
n = − 1 + 55
=54 = 27 or
n = − 1 − 55
=−
56= − 28
2 2 2 2Since n can never be negative therefore n = 27
Now an = a1 + (n −1)d
⇒ a27 = (1) + (27 −1)(1) = 1+ 26 = 27Thus the numbers of trees in the base row are 27.
Question # 3Let the first installment be x then the sequence of installment will be
x, x − 10, x − 20,......................
Here a1 = x ,d = -10 , n = 14 and Sn = 1100 + 230 = 1330
Now Sn
= n
[2a + (n −1)d ]2
1
⇒ 1330
=
14 [2x + (14 − 1)(−10)] ⇒ 1330 = 7[2x −130] ⇒ 1330 = 14x −910
2
2240 = 160⇒ 1330+ 910 = 14x ⇒ 2240 = 14x ⇒ x =
14Hence the first installment is 160.
FSc-I / Ex 6.5 - 2
Question # 4The sequence of the strikes is
1, 2, 3, …………., 12
Herea1 = 1
, d = 2 – 1 = 2 , n = 12 , an = 12
Now Sn
= n
[2a + (n −1)d
]2
1
⇒
S
n
= 12[2(1) + (12 −1)(1)]
=12
[2 + 11] =
12
[13] = 78
2 2 2Hence clock strikes 78 hours in twelve strikes.
Question # 5The sequence of the savings is
12, 16, 20, ……………Total Savings = 2100So here a1 = 12 , d = 16 – 12 = 4 , Sn = 2100 , n = ?
Since S
= n
[2a + (n −1)d
]2
1
⇒ 2100 = n
[2(12) + (n −1)(4)] ⇒ 4200 = n [24 + 4 n − 4]2
⇒ 4200 = n [4n + 20]⇒ 4200 = 4n 2
+ 20n
⇒
4n 2 + 20n − 4200 = 0 ⇒
4(n 2 + 5n − 1050) = 0
⇒ n 2 + 5n − 1050 = 0
−5±
(5)2 − 4(1)(−1050) − 5 ±
⇒ n = =
25 + 4200
2(1) 2
− 5 ±
= − 5 ±
65=4225
2 2
So n = − 5 − 65 =−70
= −35 orn =
− 5 + 65
=
60
=30
2 2 2 2As n can never be negative therefore n = 30
Thus student will save Rs. 2100 in 30 weeks.
Question # 6The sequence of the falls is
9, 27, 45, ………………(1) a1 = 9 , d = 27 – 9 = 18 , a5 = ?
Since a5 = a1 + 4d = 9 + 4(18) = 9 + 72 = 81
Hence in fifth second the object will fall 81 meters.(2) Here a1 = 9 , d = 27 – 9 = 18 , n = 5, S5 = ?
Since Sn = n2 [2a1 + (n −1)d ]
1Þ S5 = 52 [2(9) + (5 −1)(18)] =
52 [18 + 72] =
52 (90) =
225 Thus up to 5th second the object will fall 225 meters.
FSc-I / Ex 6.5 - 3
Question # 7
Here a1 = 6000 , a11 = 12000 , n = 11
Now Sn
= n
[a1 + an
]2
⇒ S = 11[6000 +12000] =
11(18000) = 99000
11
2 2Hence he will receive Rs. 99000 in past eleven years.
Question # 8Since the sum of angels of 3 sided polygon (triangle) = a1 = π
Sum of angels of 4 sided polygon (quadrilateral) = a2 = 2πSum of the angels of 5 sided polygon (pentagon) = a3 = 3π
SoThe sum of interior angels of 16 side polygon = a14 = ?
Here a1 = π , d = a2 − a1 = 2π − π = π , n = 14
Since an = a1 + (n −1) d
⇒ a14 = π + (14 −1)(π ) = π + 13π = 14πHence sum of interior angels of 16 side polygon is 14π .
Question # 9
Let a1 denotes the prize money for the last positionThen a1 = 4000 , Sn = 60000 , n = 8 , an = ?
Since S
= n (a +
a )2 1
⇒ 60000 = 8
(4000+
a ) ⇒ 60000 = 4(4000+ a )2 n
⇒ 60000 = 16000 + 4an
⇒ 60000 − 16000 = 4an ⇒ 44000 = 4an
⇒ an = 44000
=
110004
Hence the team at 1st place will get 11000 Rs.
Question # 10Balls in the first layer = 8 + 7 + 6 +……… + 2 + 1
= 8
[2(8) + (8 −1)(−1)] = 4(16 − 7)
=36
2Balls in the second layer = 7 + 6 + 5 + ………+ 2 + 1
= 7
[2(7) + (7 −1)(−1)] = 7
[14− 6 ]= 7 [ 8 ]=28
2 2 2Balls in the third layer
= 6 + 5 + 4 +3 + 2 + 1 = 21
Balls in the fourth layer = 5 + 4 + 3 + 2 +1 = 15Balls in the fifth layer = 4 + 3 + 2 + 1 = 10Balls in the sixth layer = 3 + 2 + 1 = 6Balls in the seventh layer = 2 + 1 = 3Balls in the eighth layer = 1Hence the number of balls in pyramid
= 36 + 28 + 21 + 15 + 10 + 6 + 3 + 1 = 120
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