electronics devices & circuits lab manual

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www.vidyarthiplus.in © Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 1 Document Name: Electronic Device and Circuits Lab Manual www.vidyarthiplus.in Facebook: www.facebook.com/vidyarthiplus Twitter: www.twitter.com/vidyarthiplus CLASS : II YEAR/ III SEMSESTER SUBJECT CODE : 131351 SUBJECT : ELECTRON DEVICES AND CIRCUITS LAB BATCH : A1 STAFF IN-CHARGE: Ms. K. SUDHA DESIGNATION : LECTURER STAFF CODE : EE55

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Page 1: Electronics devices & circuits lab manual

www.vidyarthiplus.in

© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 1

Document Name: Electronic Device and Circuits Lab

Manual

www.vidyarthiplus.in

Facebook: www.facebook.com/vidyarthiplus

Twitter: www.twitter.com/vidyarthiplus

CLASS : II YEAR/ III SEMSESTER

SUBJECT CODE : 131351

SUBJECT : ELECTRON DEVICES AND CIRCUITS LAB

BATCH : A1

STAFF IN-CHARGE: Ms. K. SUDHA

DESIGNATION : LECTURER

STAFF CODE : EE55

Page 2: Electronics devices & circuits lab manual

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 2

LIST OF EXPERIMENTS

131351 ELECTRON DEVICES AND CIRCUITS LABORATORY L T P C (B.E. (EEE), B.E. (E&I) and B.E. (I & C) 0 0 3 2 (Revised)

1. Characteristics of semiconductor diode and zener diode .

2. Characteristics of transistor under CE, CB and CC .

3. Characteristics of FET .

4. Characteristics of UJT .

5. Characteristics of SCR, DIAC and TRIAC.

6. Photodiode, Phototransistor characteristics and study of light

activated relay circuit.

7. Static characteristics of Thermistors.

8. Single phase half wave and full wave rectifiers with inductive and

capacitive filters.

9. Differential amplifiers using FET.

10. Study of CRO.

11. Series and parallel resonance circuits.

12. Realization of passive filters.

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Ex.No.1a

CHARACTERISTICS OF PN JUNCTION DIODE

AIM:

To study the PN junction diode characteristics under Forward & Reverse

bias conditions.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 Diode

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A PN junction diode is a two terminal junction device. It conducts only in

one direction (only on forward biasing).

FORWARD BIAS:

On forward biasing, initially no current flows due to barrier potential. As the

applied potential exceeds the barrier potential the charge carriers gain sufficient

energy to cross the potential barrier and hence enter the other region. The holes,

which are majority carriers in the P-region, become minority carriers on entering

the N-regions, and electrons, which are the majority carriers in the N-region,

become minority carriers on entering the P-region. This injection of Minority

carriers results in the current flow, opposite to the direction of electron

movement.

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REVERSE BIAS:

On reverse biasing, the majority charge carriers are attracted towards the

terminals due to the applied potential resulting in the widening of the depletion

region. Since the charge carriers are pushed towards the terminals no current

flows in the device due to majority charge carriers. There will be some current in

the device due to the thermally generated minority carriers. The generation of

such carriers is independent of the applied potential and hence the current is

constant for all increasing reverse potential. This current is referred to as

Reverse Saturation Current (IO) and it increases with temperature. When the

applied reverse voltage is increased beyond the certain limit, it results in

breakdown. During breakdown, the diode current increases tremendously.

PROCEDURE:

FORWARD BIAS:

1. Connect the circuit as per the diagram.

2. Vary the applied voltage V in steps of 0.1V.

3. Note down the corresponding Ammeter readings I.

4. Plot a graph between V & I

OBSERVATIONS

1. Find the d.c (static) resistance = V/I.

2. Find the a.c (dynamic) resistance r = δV / δI (r = ∆∆∆∆V/∆∆∆∆I) = 12

12

II

VV

−.

3. Find the forward voltage drop = [Hint: it is equal to 0.7 for Si and 0.3 for

Ge]

REVERSE BIAS:

1. Connect the circuit as per the diagram.

2. Vary the applied voltage V in steps of 1.0V.

3. Note down the corresponding Ammeter readings I.

4. Plot a graph between V & I

Page 6: Electronics devices & circuits lab manual

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 6

(0-100)mA, MC

+ -

+

-

(0-15)V, MC +

-

(0-10)V

RPS

(0-500)µA,MC

+ -

+

-

(0-30)V, MC +

-

(0-30)V

RPS

5. Find the dynamic resistance r = δδδδV / δδδδI.

FORMULA FOR REVERSE SATURATION CURRENT (IO):

Io = ∂∂∂∂I/[exp(∂∂∂∂V/ηηηηVT)]-1

Where VT is the voltage equivalent of Temperature = kT/q

-k is Boltzmann’s constant, q is the charge of the electron and T is the

temperature in degrees Kelvin.

η =1 for Silicon and 2 for Germanium

CIRCUIT DIAGRAM:

FORWARD BIAS:

REVERSE BIAS:

470 Ω a

470 Ω a

Page 7: Electronics devices & circuits lab manual

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Specification for 1N4001: Silicon Diode

Peak Inverse Voltage: 50V

Idc = 1A.

Maximum forward voltage drop at 1 Amp is 1.1 volts

Maximum reverse current @50 volts is 5µA

TABULAR COLUMN:

FORWARD BIAS: REVERSE BIAS:

MODEL GRAPH

If (mA)

I2

Vb I1

( Volts) V1 V2 Vf

(Volts)

Ir (µA)

S.No. VOLTAGE

(In Volts)

CURRENT

(In mA)

S..No. VOLTAGE

(In Volts)

CURRENT

(In µµµµA)

Page 8: Electronics devices & circuits lab manual

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 8

RESULT:

Forward and Reverse bias characteristics of the PN junction diode and the

dynamic resistance under

i) Forward bias = ---------------------

ii) Reverse bias = ----------------------.

iii) Reverse Saturation Current = ----------------.

Page 9: Electronics devices & circuits lab manual

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 9

Ex.No.1b

CHARACTERISTICS OF ZENER DIODE

AIM:

To determine the breakdown voltage of a given zener diode.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 zener

diode

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A properly doped crystal diode, which has a sharp breakdown voltage, is known

as zener diode.

FORWARD BIAS:

On forward biasing, initially no current flows due to barrier potential. As the

applied potential increases, it exceeds the barrier potential at one value and the

charge carriers gain sufficient energy to cross the potential barrier and enter the

other region. the holes ,which are majority carriers in p-region, become minority

carriers on entering the N-regions and electrons, which are the majority carriers

in the N-regions become minority carriers on entering the P-region. This injection

of minority carriers results current, opposite to the direction of electron

movement.

REVERSE BIAS:

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When the reverse bias is applied due to majority carriers small amount of

current (ie) reverse saturation current flows across the junction. As the reverse

bias is increased to breakdown voltage, sudden rise in current takes place due to

zener effect.

ZENER EFFECT:

Normally, PN junction of Zener Diode is heavily doped. Due to heavy

doping the depletion layer will be narrow. When the reverse bias is increased the

potential across the depletion layer is more. This exerts a force on the electrons

in the outermost shell. Because of this force the electrons are pulled away from

the parent nuclei and become free electrons. This ionization, which occurs due to

electrostatic force of attraction, is known as Zener effect. It results in large

number of free carriers, which in turn increases the reverse saturation current

PROCEDURE:

FORWARD BIAS:

1. Connect the circuit as per the circuit diagram.

2. Vary the power supply in such a way that the readings are taken in steps

of 0.1V in the voltmeter till the needle of power supply shows 30V.

3. Note down the corresponding ammeter readings.

4. Plot the graph :V (vs) I.

5. Find the dynamic resistance r = δδδδV / δδδδI.

REVERSE BIAS:

1. Connect the circuit as per the diagram.

2. Vary the power supply in such a way that the readings are taken in steps

of 0.1V in the voltmeter till the needle of power supply shows 30V.

3. Note down the corresponding Ammeter readings I.

4. Plot a graph between V & I

5. Find the dynamic resistance r = δδδδV / δδδδI.

6. Find the reverse voltage Vr at Iz=20 mA.

Page 11: Electronics devices & circuits lab manual

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 11

(0-15) V

+ -

+

-

+

-

(0-10) V

(0-10) V, MC

+ -

+

-

+

-

(0-30) V

CIRCUIT DIAGRAM:

FORWARD BIAS:

REVERSE BIAS:

1

470 Ω

aaaaa

(0-10)mA

1

1KΩ

aaaaa

(0-500)A, MC

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 12

ZENER DIODE:

If ( mA)

I2

VB I1

Vr V1 V2 Vf

(V) (V)

Ir (A)

TABULAR COLUMN:

FORWARD BIAS: REVERSE BIAS:

RESULT:

Forward and Reverse bias characteristics of the zener diode was studied

and

Forward bias dynamic resistance = ---------------------

Reverse bias dynamic resistance = ----------------------

The reverse voltage at Iz =20 mA determined from the reverse

characteristics of the Zener diode is --------------------------.

S..No. VOLTAGE

(In Volts)

CURRENT

(In mA)

S.No. VOLTAGE

(In Volts)

CURRENT

(In µµµµA)

Page 13: Electronics devices & circuits lab manual

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 13

Ex. No. 2a

CHARACTERISTICS OF CE CONFIGURATION USING BJT

AIM:

To plot the transistor characteristics of CE configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 Transistor

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A BJT is a three terminal two – junction semiconductor device in which the

conduction is due to both the charge carrier. Hence it is a bipolar device and it

amplifier the sine waveform as they are transferred from input to output. BJT is

classified into two types – NPN or PNP. A NPN transistor consists of two N

types in between which a layer of P is sandwiched. The transistor consists of

three terminal emitter, collector and base. The emitter layer is the source of the

charge carriers and it is heartily doped with a moderate cross sectional area.

The collector collects the charge carries and hence moderate doping and large

cross sectional area. The base region acts a path for the movement of the

charge carriers. In order to reduce the recombination of holes and electrons the

base region is lightly doped and is of hollow cross sectional area. Normally the

transistor operates with the EB junction forward biased.

Page 14: Electronics devices & circuits lab manual

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 14

Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

In transistor, the current is same in both junctions, which indicates that

there is a transfer of resistance between the two junctions. One to this fact the

transistor is known as transfer resistance of transistor.

PROCEDURE:

INPUT CHARACTERISTICS:

1. Connect the circuit as per the circuit diagram.

2. Set VCE, vary VBE in regular interval of steps and note down the

corresponding IB reading. Repeat the above procedure for different values of

VCE.

3. Plot the graph: VBE Vs IB for a constant VCE.

OUTPUT CHARACTERISTICS:

1. Connect the circuit as per the circuit diagram.

2. Set IB, Vary VCE in regular interval of steps and note down the

corresponding IC reading. Repeat the above procedure for different

values of IB.

3. Plot the graph: VCE Vs IC for a constant IB.

PIN DIAGRAM:

B

E C

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(0 – 250) µA

10 KΩ

(0 – 30)mA

- + 1 KΩ

BC107

+

-

+

-(0-30)V

+

-

+

-

+ -

(0-30)V

(0-30)V

(0-1)V

CIRCUIT DIAGRAM:

MODEL GRAPH:

INPUT CHARACTERISTICS: OUTPUT CHARACTERISTICS:

A

A

V

V

C

E

B

VCE = 0V

VCE = 5V

IB

µA mA

VBE(V) VCE(V)

0 0

IB=60µA

IB=40µA

IB=20µA

IC

Page 16: Electronics devices & circuits lab manual

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TABULAR COLUMN:

INPUT CHARACTERISTICS:

VCE=1V VCE=2V

VBE(V) IB(A) VBE(V) IB(A)

OUTPUT CHARACTERISTICS:

IB=20µµµµA IB=40µµµµA

VCE(V) IC(mA) VCE(V) IC(mA)

RESULT:

The transistor characteristics of a Common Emitter (CE)

configuration were plotted

Page 17: Electronics devices & circuits lab manual

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 17

Ex.No.2b

CHARACTERISTICS OF CB CONFIGURATION USING BJT

AIM:

To plot the transistor characteristics of CB configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 Transistor BC 107 1

2 Ammeter

(0–10)mA 1 2 Resistor 10kΩ

1KΩ

1

(0–1)A 1 3 Bread

Board

1

3 Voltmeter (0–30)V 1 4 Wires

(0–2)V 1

THEORY:

In this configuration the base is made common to both the input and out.

The emitter is given the input and the output is taken across the collector. The

current gain of this configuration is less than unity. The voltage gain of CB

configuration is high. Due to the high voltage gain, the power gain is also high. In

CB configuration, Base is common to both input and output. In CB configuration

the input characteristics relate IE and VEB for a constant VCB. Initially let VCB = 0

then the input junction is equivalent to a forward biased diode and the

characteristics resembles that of a diode. Where VCB = +VI (volts) due to early

effect IE increases and so the characteristics shifts to the left. The output

characteristics relate IC and VCB for a constant IE. Initially IC increases and then it

levels for a value IC = αIE. When IE is increased IC also increases proportionality.

Though increase in VCB causes an increase in α, since α is a fraction, it is

negligible and so IC remains a constant for all values of VCB once it levels off.

Page 18: Electronics devices & circuits lab manual

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(0-30)V

(0-1)mA

+ -

(0-30)mA

+ -

+

-

+

-

+

-(0-2)V (0-30)V (0-30)V

PIN DIAGRAM:

B

Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

E C

CIRCUIT DIAGRAM:

-

PROCEDURE:

INPUT CHARACTERISTICS:

It is the curve between emitter current IE and emitter-base voltage VBE at

constant collector-base voltage VCB.

1. Connect the circuit as per the circuit diagram.

2. Set VCE=5V, vary VBE in steps of 0.1V and note down the corresponding

IB. Repeat the above procedure for 10V, 15V.

3. Plot the graph VBE Vs IB for a constant VCE.

4. Find the h parameters.

OUTPUT CHARACTERISTICS:

It is the curve between collector current IC and collector-base voltage VCB at

constant emitter current IE.

1. Connect the circuit as per the circuit diagram.

2. Set IB=20µA, vary VCE in steps of 1V and note down the corresponding IC.

Repeat the above procedure for 40µA, 80µA, etc.

a10 KΩ

a

a

a

1KΩ

VEB

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3. Plot the graph VCE Vs IC for a constant IB.

4. Find the h parameters

TABULAR COLUMN:

INPUT CHARACTERISTICS:

S.No. VCB = V VCB = V VCB = V

VEB

(V)

IE

(µµµµA)

VEB

(V)

IE

(µµµµA)

VEB

(V)

IE

(µµµµA)

OUTPUT CHARACTERISTICS:

S.No. IE= mA IE= mA IE= mA

VCB

(V)

Ic

(mA)

VCB

(V)

Ic

(mA)

VCB

(V)

Ic

(mA)

MODEL GRAPH:

INPUT CHARACTERISTICS:

Page 20: Electronics devices & circuits lab manual

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IC

(mA)

VCB1

IE2

VCB2

IE1 VEB1 VEB2 VEB (V)

OUTPUT CHARACTERISTICS:

IC

(mA) IE3

IC2 IE2

IC1

IE1

VCB1 VCB2 VCB (V)

RESULT:

The transistor characteristics of a Common Base (CB) configuration were

plotted and uses studied.

Ex.No.2c

CHARACTERISTICS OF CC CONFIGURATION USING BJT

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AIM:

To plot the transistor characteristics of CE configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 Transistor BC 107 1

2 Ammeter

(0–30)mA 1 2 Resistor 1kΩ 2

(0–250)µA 1 3 Bread

Board

1

3 Voltmeter (0–30)V 1 4 Wires

(0–5)V 1

THEORY:

A BJT is a three terminal two – junction semiconductor device in which the

conduction is due to both the charge carrier. Hence it is a bipolar device and it

amplifier the sine waveform as they are transferred from input to output. BJT is

classified into two types – NPN or PNP. A NPN transistor consists of two N

types in between which a layer of P is sandwiched. The transistor consists of

three terminal emitter, collector and base. The emitter layer is the source of the

charge carriers and it is heartily doped with a moderate cross sectional area.

The collector collects the charge carries and hence moderate doping and large

cross sectional area. The base region acts a path for the movement of the

charge carriers. In order to reduce the recombination of holes and electrons the

base region is lightly doped and is of hollow cross sectional area. Normally the

transistor operates with the EB junction forward biased.

In transistor, the current is same in both junctions, which indicates that

there is a transfer of resistance between the two junctions. One to this fact the

transistor is known as transfer resistance of transistor.

PIN DIAGRAM:

B

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Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

+

-

-

+ -+ +

-

+

+ -

(0-30)mA

(0-250)µA

E C

CIRCUIT DIAGRAM:

PROCEDURE:

INPUT CHARECTERISTICS:

1. Connect the circuit as per the circuit diagram.

2. Set VCE, vary VBE in regular interval of steps and note down the

corresponding IB reading. Repeat the above procedure for different values

of VCE.

3. Plot the graph: VBC Vs IB for a constant VCE.

OUTPUT CHARECTERISTICS:

1. Connect the circuit as per the circuit diagram.

A

A V

V

1 KΩ

+

-

(0-30)V (0-30)V

(0-30)V (0-30)V

1 KΩ

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 23

2. Set IB, Vary VCE in regular interval of steps and note down the

corresponding IC reading. Repeat the above procedure for different

values of IB.

3. Plot the graph: VCE Vs IC for a constant IB.

MODEL GRAPH:

INPUT CHARACTERISTICS: OUTPUT CHARACTERISTICS:

(µµµµA) (mA)

IB Ie

VCE=0 VCE=5V IB=60µµµµA

IB=40µµµµA

IB=20µµµµA

0 VBC(V) 0 VCE(V)

TABULAR COLUMN:

INPUT CHARACTERISTICS:

VCE=1V VCE=2V

VBC(V) IB(A) VBC(V) IB(A)

OUTPUT CHARACTERISTICS:

IB=20µµµµA IB=40µµµµA

VCE(V) IE(mA) VCE(V) IE(mA)

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RESULT:

The transistor characteristics of a Common Emitter (CC) configuration

were plotted.

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Ex.No.3

CHARACTERISTICS OF JUNCTION FIELD EFFECT TRANSISTOR

AIM:

To Plot the characteristics of given FET & determine rd, gm, µ, IDSS,VP.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 FET BFW10 1

2 Ammeter (0–30)mA 1 2 Resistor 1kΩ

68KΩ

1

1

3 Voltmeter (0–30)V 1 3

Bread

Board

1

(0-10)V 1 4 Wires

THEORY:

FET is a voltage operated device. It has got 3 terminals. They are Source,

Drain & Gate. When the gate is biased negative with respect to the source, the

pn junctions are reverse biased & depletion regions are formed. The channel is

more lightly doped than the p type gate, so the depletion regions penetrate

deeply in to the channel. The result is that the channel is narrowed, its resistance

is increased, & ID is reduced. When the negative bias voltage is further

increased, the depletion regions meet at the center & ID is cutoff completely.

PROCEDURE:

DRAIN CHARACTERISTICS:

1. Connect the circuit as per the circuit diagram.

2. Set the gate voltage VGS = 0V.

3. Vary VDS in steps of 1 V & note down the corresponding ID.

Page 26: Electronics devices & circuits lab manual

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+ (0-30)V

68KΩ

V

+

(0-30)V

(0-30)V

1k (0-30mA)

D G

S

BFW10

-

+ (0-10)V V

A

-

4. Repeat the same procedure for VGS = -1V.

5. Plot the graph VDS Vs ID for constant VGS.

OBSERVATIONS

1. d.c (static) drain resistance, rD = VDS/ID.

2. a.c (dynamic) drain resistance, rd = ∆∆∆∆VDS/∆∆∆∆ID.

3. Open source impedance, YOS = 1/ rd.

TRANSFER CHARACTERISTICS:

1. Connect the circuit as per the circuit diagram.

2. Set the drain voltage VDS = 5 V.

3. Vary the gate voltage VGS in steps of 1V & note down the corresponding ID.

4. Repeat the same procedure for VDS = 10V.

5. Plot the graph VGS Vs ID for constant VDS.

FET PARAMETER CALCULATION:

Drain Resistancd rd = GS

D

DS VI

V

Transconductance gm = DS

GS

D VV

I

Amplification factor =rd . gm

CIRCUIT DIAGRAM:

Page 27: Electronics devices & circuits lab manual

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© Copyright 2011-2015 – VidyarthiPlus.in (VP Group) Page 27

I D (

mA

) PIN DIAGRAM:

BOTTOM VIEW OF BFW10:

SPECIFICATION:

Voltage : 30V, IDSS > 8mA.

MODEL GRAPH:

DRAIN CHARACTERISTICS:

TRANSFER CHARACTERISTICS:

ID(mA)

VDS =Const

VGS (V)

0

VGS = 0V

VGS = -1V

VGS = -2V

VGS = -3V

VDS (volts)

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TABULAR COLUMN:

DRAIN CHARACTERISTICS:

VGS = 0V VGS = -1V

VDS (V) ID(mA) VDS (V) ID(mA)

TRANSFER CHARACTERISTICS:

RESULT:

Thus the Drain & Transfer characteristics of given FET is Plotted.

Rd =

gm =

µ =

IDSS =

Pinch off voltage VP =

VDS =5volts VDS = 10volts

VGS (V) ID(mA) VGS (V) ID(mA)

Page 29: Electronics devices & circuits lab manual

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Ex.No.4

CHARACTERISTICS OF UNIJUNCTION TRANSISTOR

AIM:

To Plot the characteristics of UJT & determine it’s intrinsic standoff

Ratio.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 UJT 2N2646 1

2 Ammeter (0–30)mA 1

2 Resistor 1KΩ 2

3 Bread

Board

1

3 Voltmeter (0–30)V 1

(0–10)V 1

THEORY:

UJT(Double base diode) consists of a bar of lightly doped n-type silicon

with a small piece of heavily doped P type material joined to one side. It has got

three terminals. They are Emitter(E), Base1(B1),Base2(B2).Since the silicon bar

is lightly doped, it has a high resistance & can be represented as two resistors,

rB1 & rB2. When VB1B2 = 0, a small increase in VE forward biases the emitter

junction. The resultant plot of VE & I E is simply the characteristics of forward

biased diode with resistance. Increasing VEB1 reduces the emitter junction

reverse bias. When VEB1 = VrB1 there is no forward or reverse bias. & IE = 0.

Increasing VEB1 beyond this point begins to forward bias the emitter junction. At

the peak point, a small forward emitter current is flowing. This current is termed

as peak current( IP ). Until this point UJT is said to be operating in cutoff region.

When IE increases beyond peak current the device enters the negative

resistance region. In which the resistance rB1 falls rapidly & VE falls to the valley

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B2

E

voltage.Vv. At this point IE = Iv. A further increase of IE causes the device to

enter the saturation region.

PROCEDURE:

1. Connect the circuit as per the circuit diagram.

2. Set VB1B2 = 0V, vary VEB1 , & note down the readings of IE & VEB1

3. Set VB1B2 = 10V , vary VEB1 , & note down the readings of IE & VEB1

4. Plot the graph : IE Versus VEB1 for constant VB1B2.

5. Find the intrinsic standoff ratio.

CIRCUIT DIAGRAM:

PIN DIAGRAM:

BOTTOM VIEW OF 2N2646:

SPECIFICATION FOR 2N2646:

* Inter base resistance RBB = 4.7 to 9.1 KΩ

B2

(0-30)V (0-30)V

(0-30)V

1KΩ 1KΩ

(0-30)V

(0-30)mA

V V

A

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* Minimum Valley current = 4 mA

* Maximun Peak point emitter current 5 µA

*Maximum emitter reverse current 12 µA.

FORMULA FOR INTRINSIC STANDOFF RATIO:

η = VP - VD/ VB1B2., where VD = 0.7V.

MODEL GRAPH:

Peak point

VP

IP

Negative resistance region

VEB1(V)

Valley point VB1B2 = V

VB1B2 = 0V

IV IE (mA)

TABULAR COLUMN:

VB1B2 = 0V VB1B2 = 10V

VEB1 (V) IE (mA) VEB1 (V) IE (mA)

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PROCEDURE:

1. Give the circuit connections as per the circuit diagram.

2. The dc input voltage is set to 20 V in RPS.

3. The output sweep waveform is measured using CRO.

4. The graph of output sweep waveform is plotted

RESULT:

1. Thus the characteristics of given UJT was Plotted & its intrinsic standoff

Ratio = ----.

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Ex.No.5

CHARACTERISTICS OF PHOTO-DIODE AND

PHOTOTRANSISTOR

AIM:

1. To study the characteristics of a photo-diode.

2. To study the characteristics of phototransistor.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 R.P.S (0-30)V 1 1 Photo

diode 1

2 Ammeter (0–30)mA 1

2 Resistor 1KΩ 2

3 Bread

Board 1

3 Voltmeter (0–30)V 1 4 Photo

transistor 1

THEORY:

PHOTODIODE:

A photo diode is a two terminal pn junction device, which operates on

reverse bias. On reverse biasing a pn junction diode, there results a constant

current due to minority charge carriers known as reverse saturation current.

Increasing the thermally generated minority carriers by applying external energy,

i.e., either heat or light energy at the junction can increase this current. When we

apply light energy as an external source, it results in a photo diode that is usually

placed in a glass package so that light can reach the junction. Initially when no

light is incident, the current is only the reverse saturation current that flows

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(0-30)mA

(0-30)V (0-30)V

through the reverse biased diode. This current is termed as the dark current of

the photo diode. Now when light is incident on the photo diode then the thermally

generated carriers increase resulting in an increased reverse current which is

proportional to the intensity of incident light. A photo diode can turn on and off at

a faster rate and so it is used as a fast acting switch.

CIRCUIT DIAGRAM:

TABULAR COLUMN:

MODEL GRAPH:

S.No. VOLTAGE

(In Volts)

CURRENT

(In mA)

R

(KΩ)

Illumination lm/m2

1KΩ a

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THEORY:

PHOTOTRANSISTOR:

It is a transistor with an open base; there exists a small collector current

consisting of thermally produced minority carriers and surface leakage. By

exposing the collector junction to light, a manufacturer can produce a

phototransistor, a transistor that has more sensitivity to light than a photo diode.

Because the base lead is open, all the reverse current is forced into the base of

the transistor. The resulting collector current is ICeo = βdcIr. The main difference

between a phototransistor and a photodiode is the current gain, βdc. The same

amount of light striking both devices produces βdc times more current in a

phototransistor than in a photodiode.

CIRCUIT DIAGRAM:

TABULAR COLUMN: SYMBOL:

E

S. No. VCE

(in Volts)

IC

(in mA)

N P N

1KΩ

(0-30V)

C

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IC

400 Lux

200 Lux

0 Lux

VCE(V)

MODEL GRAPH:

PROCEDURE:

PHOTO DIODE:

1. Rig up the circuit as per the circuit diagram.

2. Maintain a known distance (say 5 cm) between the DC bulb and

the photo diode.

3. Set the voltage of the bulb (say, 2V), vary the voltage of the diode

insteps of 1V and note down the corresponding diode current, Ir.

4. Repeat the above procedure for the various voltages of DC bulb.

5. Plot the graph: VD vs. Ir for a constant DC bulb voltage.

PHOTOTRANSISTOR:

1. Rig up the circuit as per the circuit diagram.

2. Maintain a known distance (say 5 cm) between the DC bulb and the

phototransistor.

3. Set the voltage of the bulb (say, 2V), vary the voltage of the diode

in steps of 1V and note down the corresponding diode current, Ir.

4. Repeat the above procedure for the various values of DC bulb.

5. Plot the graph: VD vs. Ir for a constant bulb voltage.

RESULT:

Thus the characteristics of photo diode and phototransistor are studied.

(mA)

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Ex.No.6

CHARACTERISTICS OF THERMISTOR

AIM:

To study the characteristics of Thermistor.

THEORY:

Thermistor or Thermal resistor is two – terminal semiconductor device

whose resistance is temperature sensitive. The value of such resistors decreases

with increase in temperature. Materials employed in the manufacture of the

thermistors include oxides of cobalt, nickel, copper, iron uranium and

manganese.

The thermistors has very high temperature coefficient of resistance, of the

order of 3 to 5% per °C, making it an ideal temperature transducer. The

temperature coefficient of resistance is normally negative. The reistance at any

temperature T, is given approximately by

RT = Ro exp β (1/T – 1/To)

Where RT = thermistor resistance at temperature T (K), RO = thersmistor

resistance at temperature To (K), and β = a constant determined by calibration.

At high temperatures, this equation reduces to

RT = Ro exp ( β/T)

The resistance – temperature characteristics is shown in Fig 21.10. The

curve is non – linear and the drop in resistance from 5000 to 10Ω occurs for an

increase in temperature from 20 to 100 °C. The temperature of the device can

be changed internally or externally. An increase in current through the device will

raise its temperature carrying a drop in its terminal resistance. Any externally

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heat source will result in an increase in its body temperature and drop in

resistance this type action (internal or external) lends itself well to control

mechanism.

Three useful parameters for characterizing the thermistor are the time

constant, dissipation constant , and resistance ratio. The time constant is the

time for a thermistor to change its resistance by 63% of its initial value, for zero –

power dissipation. Typical values of time constant range from 1 to 50 s.

SYMBOL:

MODEL GRAPH:

The dissipation factor is the power necessary to increase the temperature

of a thermistor by 1˚C. Typical values of dissipation factor range from 1 to 10

mW/˚C.

Resistance ratio is the ratio of the resistance at 25 ˚C. Its range is

approximately

R

(Ω-cm)

T (deg)

T

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3 – 60.

Thermistors are used measure temperature, flow pressure, liquid level,

voltage or power level, vacuum, composition of gases and thermal conductivity

and also in compensation network.

RESULT:

Thus the Characteristics of thermistor was studied.

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Ex.No.7a

SINGLE PHASE HALF WAVE RECTIFIER

AIM:

To construct a Half wave rectifier using diode and to draw its performance

characteristics.

APPARATUS REQUIRED: COMPONENTS

REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 Transformer 230/(6-0-6)V 1 1

Diode IN4001 1

2 R.P.S (0-30)V 2

3 Ammeter

(0–30)mA 1 2 Resistor 1K Ω 1

(0–250)µA 1 3 Bread

Board

1

4 Voltmeter (0–30)V 1 4 Capacitor 100µf 1

(0–2)V 1 5 CRO 1

FORMULAE:

WITHOUT FILTER:

(i) Vrms = Vm / √2

(ii) Vdc = Vm / ∏

(iii) Ripple Factor = √ (Vrms / Vdc)2 – 1

(iv) Efficiency = (Vdc / Vrms)2 x 100

WITH FILTER:

(i) Vrms = √ (Vrms’2 + Vdc

2)

(ii) Vrms’ = Vrpp / (√3 x 2)

(iii) Vdc = Vm – V rpp / 2

(iv) Ripple Factor = Vrms’/ Vdc

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PROCEDURE:

WITHOUT FILTER:

1. Give the connections as per the circuit diagram.

2. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

3. Take the rectifier output across the Load.

4. Plot its performance graph.

WITH FILTER:

1. Give the connections as per the circuit diagram.

2. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

3. Connect the Capacitor across the Load.

4. Take the rectifier output across the Load.

5. Plot its performance graph.

CIRCUIT DIAGRAM:

1φ Transformer

230 V / 6V 1N 4007

1K 100µF 1φ, 230V,

50Hz

AC supply

CRO

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TABULAR COLUMN:

WITHOUT FILTER:

Vm Vrms Vdc Ripple factor Efficiency

WITH FILTER:

Vrms Vrpp Vdc Ripple factor Efficiency

MODEL GRAPH:

RESULT:

Thus the performance characteristics of 1φ Half wave rectifier was obtained.

Vin

(Volts)

t (ms)

Vo

(Volts)

t (ms)

t (ms)

Vo

(Volts)

Without Filter

With Filter

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Ex.No.7b

SINGLE PHASE FULL WAVE RECTIFIER

AIM:

To construct a Full wave rectifier using diode and to draw its performance

characteristics.

APPARATUS REQUIRED: COMPONENTS

REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 Transformer 230/(6-0-6)V 1 1

Diode IN4001 2

2 R.P.S (0-30)V 2

3 Ammeter

(0–30)mA 1 2 Resistor 1K Ω 1

(0–250)µA 1 3 Bread

Board

1

4 Voltmeter (0–30)V 1 4 Capacitor 100µf 1

(0–2)V 1 5 CRO 1

FORMULAE:

WITHOUT FILTER:

(i) Vrms = Vm / √2

(ii) Vdc = 2Vm / ∏

(iii) Ripple Factor = √ (Vrms / Vdc)2 – 1

(iv) Efficiency = (Vdc / Vrms)2 x 100

WITH FILTER:

(i) Vrms = Vrpp /(2*√ 3)

(ii) Vdc = Vm – V rpp

(iv) Ripple Factor = Vrms’/ Vdc

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PROCEDURE:

WITHOUT FILTER:

1. Give the connections as per the circuit diagram.

2. Give 230v, 50HZ I/P to the step down TFR where secondary connected

to the Rectifier I/P.

3. Take the rectifier output across the Load.

4. Plot its performance graph.

WITH FILTER:

1. Give the connections as per the circuit diagram.

2. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

3. Connect the Capacitor across the Load.

4. Take the rectifier output across the Load.

5. Plot its performance graph.

CIRCUIT DIAGRAM:

1N 4007

1K 100µF

1φ, 230V,

50Hz

AC supply

CRO

1N 4007

1φ Transformer

230 V / 6V

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TABULAR COLUMN:

WITHOUT FILTER:

Vm Vrms Vdc Ripple factor Efficiency

WITH FILTER:

Vrms Vrpp Vdc Ripple factor Efficiency

MODEL GRAPH :

RESULT: Thus the performance characteristics of 1φ Full wave rectifier were

obtained.

Vin

(Volts)

t (ms)

Vo

(Volts)

t (ms)

t (ms)

Vo

(Volts)

Without Filter

With Filter

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Ex.No.8

DIFFERENTIAL AMPLIFIER

AIM:

To construct a Differential amplifier in Common mode & Differential mode

configuration and to find common mode rejection ratio.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

Apparatus Range Qty

1 RPS (0-30)V 1

2 CRO 1

3 Signal

Generator 1

4 DCB 2

5 DRB 2

THEORY:

The Differential amplifier circuit is an extremely popular connection used in

IC units. The circuit has separate inputs , two separate outputs and emitters are

connected together. If the same input is applied to both inputs, the operation is

called common mode. In double ended operation two input signals are applied ,

the difference of the inputs resulting in outputs from both collectors due to the

difference of the signals applied to both the inputs. The main feature of the

differential amplifier is the very large gain when opposite signals are applied to

inputs as compared to small signal resulting from common input. The ratio of this

difference gain to the common gain is called common mode rejection ratio.

S.No Item Type Range Qty

1 Transistor BC107 1

2 Capacitor 470µF 1

3 Resistor 3.9K

3.3K

1

1

4 Bread board 1

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CIRCUIT DIAGRAM:

DIFFERENTIAL MODE:

COMMON MODE:

3.3 KΩ

3.9KΩ

Vo1 Vo2

V1

12V V2

13V

3.9KΩ

-9V

9V

3.3 KΩ

3.9KΩ

Vo1 Vo2

V2

13V

3.9KΩ

-9V

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PROCEDURE:

DIFFERENTIAL MODE:

1. Connect the circuit as per the circuit diagram.

2. Set V1 = 50mv and V2 =55mv using the signal generator.

3. Find the corresponding output voltages across V01 & V02 using CRO

4. Calculate common mode rejection ratio using the given formula.

COMMON MODE:

1. Connect the circuit as per the circuit diagram.

2. Set V1 = 50mv using the signal generator.

3. Find the output voltage across Vo using multimeter.

4. Calculte common mode rejection ratio using the given formula.

CALCULATION:

Common mode rejection ratio(CMRR) = Ad / Ac

Ad = Differential mode gain

Ac = Common mode gain

Where Ad = Vo /Vd

Vo = Output voltage measured across CRO

Vd = V 1 – V2 , V 1 , V2 – input voltage applied.

Ac = Vo /Vc

Vc = (V 1 + V2 )/2

DIFFERENTIAL MODE:

V1 =

V2 =

Output voltage =

Vd= V1-V2 =

Ad=Vo/Vd =

RESULT: Thus the differential amplifier was constructed in common mode

and Differential mode configuration. Further common mode rejection ratio was

found

Exp. No: 12

COMMON MODE:

Input voltage =

Output voltage =

V1=V2 =

Vc=(V1+V2)/2 =

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PASSIVE FILTERS

Aim:

To attenuate unwanted frequency components from input signal by using resistor

and capacitor.

Apparatus required:

S.No Name of the apparatus Range Type Quantity

1. Signal Generator 01

2. Resistor 01

3. Capacitor Ceramic 01

4. CRO 01

5. Breadboard 01

Theory:

A filter is an AC circuit that separates some frequencies from other in

within mixed – frequency signals. Audio equalizers and crossover networks are

two well-known applications of filter circuits. A Bode plot is a graph plotting

waveform amplitude or phase on one axis and frequency on the other.

A low-pass filter allows for easy passage of low-frequency signals from

source to load, and difficult passage of high-frequency signals. Capacitor low-pass

filters insert a resistor in series and a capacitor in parallel with the load as shown

in the circuit diagram. The former filter design tries to “block” the unwanted

frequency signal while the latter tries to short it out.

The cutoff frequency for a low-pass filter is that frequency at which the

output (load) voltage equals 70.7% of the input (Source) voltage. Above the cutoff

frequency, the output voltage is lower than 70.7% of the input, and vice-versa. See

the circuit diagram

1

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Fcutoff = ----------

2πRC

A high-pass filter allows for easy passage of high-frequency signals from source to

load, and difficult passage of low-frequency signals. Capacitor high-pass filters

insert a capacitor in series with the load as shown in the circuit diagram. The

former filter design tries to “brick” the unwanted frequency signal while the latter

tries to short it out.

The cutoff frequency for a high-pass filter is that frequency at which the

output (load) voltage equals 70.7% of the input (source) voltage. Above the cutoff

frequency, the output voltage is greater than 70.7% of the input, and vice-versa.

1

Fcutoff = ----------

2πRC

A band – pass filter works to screen out frequencies that are too low or too

high, giving easy passage only to frequencies within a certain range. Stacking a

low-pass filter on the end of a high-pass filter, or vice-versa can make band-pass

filters. Refer the circuit diagrams

Fig. 7.6

“Attenuate” means to reduce or diminish in amplitude. When you

turn down the volume control on your stereo, you are “attenuating” the signal

being sent to the speakers.

A band-stop filter works to screen out frequencies that are within a certain

range, giving easy passage only to frequencies outside of that range. Also known

as band-elimination, band-reject, or notch filters.

Signal

input

Low-pass filter High-pass filter Signal

output Blocks frequencies

that are too high

Blocks frequencies

that are too low

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Signal

Input

Low-pass filter

High-pass filter

Signal

Output

Placing a low-pass filter in parallel with a high-pass filter can make band-

stop filters. Commonly, both the low-pass and high-pass filter sections are of the

“T” configuration giving the name “Twin-T” to the band-stop combination. Refer

the fig.7.7, 7.8a and 7.8b.

Passes low frequencies

Passes high frequencies

Fig. 7.8a

The frequency of maximum attenuation is called the notch

frequency.

Procedure:

1. Give the connections as per circuit diagrams.

2. Switch on the main.

3. Change the frequency from minimum and find the output

voltage by using CRO.

4. Draw the graph.

5. Verify the cut off frequency.

6. Switch off the main.

Result:

Thus we analyze passive filter and various waveforms are noted

Exp. No : 10

STUDY OF CRO AND

POWER FACTOR MEASUREMENT USING CRO

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Aim:

To study cathode Ray Oscilloscope (CRO) and measurement of power factor using

CRO.

Apparatus required:

S.No Name of the apparatus Range Type Quantity

1. Resistance Box 1

2. Capacitance Box 1

3. Inductance Box 1

4. Function Generator 1

5. Bread board 1

Theory:

The cathode ray oscilloscope is the most versatile measuring instrument

available. We can measure following parameters using the CRO:

1. AC or DC voltage.

2. Time (t=1/f).

3. Phase relationship

4. Waveform calculation: Rise time; fall time; on time; off-time

Distortion, etc.

We can also measure non-electrical physical quantities like pressure, strain,

temperature, acceleration, etc., by converting into electrical quantities using

a transducer.

Major blocks:

1. Cathode ray tube (CRT)

2. Vertical amplifier

3. Horizontal amplifier

4. Sweep generator

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5. Trigger circuit

6. Associated power supply.

1. The cathode ray tube is the heart of CRO. The CRT is enclosed in an

evacuated glass envelope to permit the electron beam to traverse in the

tube easily. The main functional units of CRO are as follows.

Electron gun assembly

Deflection plate unit

Screen.

2. Vertical Amplifier is the main factor in determining the bandwidth and

sensitivity of an oscilloscope. Vertical sensitivity is a measure of how

much the electron beam will be deflected for a specified input signal.

On the front panel of the oscilloscope, one can see a knob attached to a

rotary switch labeled volts/division. The rotary switch is electrically

connected to the input attenuation network. The setting of the rotary

switch indicates what amplitude signal is required to deflect the beam

vertically by one division.

3. Horizontal amplifier Under normal mode of operation, the horizontal

amplifier will amplify the sweep generator input. When the CRO is

being used in the X-Y mode, the horizontal amplifier will amplify the

signal applied to the horizontal input terminal. Although the vertical

amplifier mush be able to faithfully reproduce low-amplitude and high

frequency signal with fast rise-time, the horizontal amplifier is only

required to provide a faithful reproduction of the sweep signal which

has a relatively high amplitude and slow rise time.

4. Sweep generator and Trigger circuit These two units form the Signal

Synchronization unit of the CRO.

5. Associated Power Supply: The input signal may come from an

external source when the trigger selector switch is set to EXT or from

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low amplitude AC voltage at line frequency when the switch is set to

LINE or from the vertical amplifier when the switch is set to INT. When

set for INT (internal triggering), the trigger circuit receives its inputs

from the vertical amplifier.

Major Blocks in a Practical CRO

A CRO consists of a cathode ray tube (CRT) and additional control knobs.

The main parts of a CRT are:

1. Electron gun assembly.

2. Deflection plate assembly.

3. Fluorescent screen.

Electron Gun Assembly: The electron gun assembly produces a sharp beam of

electrons, which are accelerated to high velocity. This focused beam of electrons

strike the fluorescent screen with sufficient energy to cause a luminous spot on the

screen.

Deflection plate assembly: This part consists of two plates in which one pair of

plates is placed horizontally and other of plates is placed vertically. The signal

under test is applied to vertical deflecting plates. The horizontal deflection plates

are connected to a built-in ramp generator, which moves the luminous spot

periodically in a horizontal direction from left to right over the screen. These two

deflection plates give stationary appearance to the waveform on the screen. CRO

operates on voltage. Since the deflection of the electron beam is directly

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proportional to the deflecting voltage, the CRT may be used as a linear measuring

device. The voltage being measured is applied to the vertical plates through an

iterative network, whose propagation time corresponds to the velocity of electrons,

thereby synchronizing the voltage applied to the vertical plate with the velocity of

the beam.

Synchronization of input signal: The sweep generator produces a saw tooth

waveform, which is used to synchronize the applied voltage to obtain a stationary-

applied signal. This requires that the time base be operated at a submultiples

frequency of the signal under measurement. If synchronization is not done, the

pattern is not stationary, but appears to drift across the screen in a random fashion.

Internal synchronization This trigger is obtained from the time base generator to

synchronize the signal.

External synchronization An external trigger source can also be used to

synchronize the signal being measured.

Auto Triggering Mode The time base used in this case in a self-oscillating

condition, i.e., it gives an output even in the absence of any Y-input. The

advantage of this mode is that the beam is visible on the screen under all

conditions, including the zero input. When the input exceeds a certain magnitude

then the internal free running oscillator locks on to the frequency.

Precautions:

1. The ammeter is connected using thick wires.

2. While reversing ammeter polarity, see to it that the capacitor is not

discharged.

Observation:

Sl.No Time Voltage Current

Unit (Sec) (Volts) (Amps)

Result: Thus we study about CRO & to measure p.f

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CLASS : II YEAR/ III SEMSESTER

SUBJECT CODE : 131351

SUBJECT : ELECTRON DEVICES AND CIRCUITS LAB

BATCH : A2

STAFF IN-CHARGE: Mrs. V. GEETHA PRIYA

DESIGNATION : ASSISTANT PROFESSOR

STAFF CODE : EE52

LIST OF EXPERIMENTS

131351 ELECTRON DEVICES AND CIRCUITS LABORATORY L T P C (B.E. (EEE), B.E. (E&I) and B.E. (I & C) 0 0 3 2 (Revised)

13. Characteristics of semiconductor diode and zener diode .

14. Characteristics of transistor under CE, CB and CC .

15. Characteristics of FET .

16. Characteristics of UJT .

17. Characteristics of SCR, DIAC and TRIAC.

18. Photodiode, Phototransistor characteristics and study of light

activated relay circuit.

19. Static characteristics of Thermistors.

20. Single phase half wave and full wave rectifiers with inductive and

capacitive filters.

21. Differential amplifiers using FET.

22. Study of CRO.

23. Series and parallel resonance circuits.

24. Realization of passive filters.

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Ex.No.1a

CHARACTERISTICS OF PN JUNCTION DIODE

AIM:

To study the PN junction diode characteristics under Forward & Reverse

bias conditions.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 Diode

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A PN junction diode is a two terminal junction device. It conducts only in

one direction (only on forward biasing).

FORWARD BIAS:

On forward biasing, initially no current flows due to barrier potential. As the

applied potential exceeds the barrier potential the charge carriers gain sufficient

energy to cross the potential barrier and hence enter the other region. The holes,

which are majority carriers in the P-region, become minority carriers on entering

the N-regions, and electrons, which are the majority carriers in the N-region,

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become minority carriers on entering the P-region. This injection of Minority

carriers results in the current flow, opposite to the direction of electron

movement.

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REVERSE BIAS:

On reverse biasing, the majority charge carriers are attracted towards the

terminals due to the applied potential resulting in the widening of the depletion

region. Since the charge carriers are pushed towards the terminals no current

flows in the device due to majority charge carriers. There will be some current in

the device due to the thermally generated minority carriers. The generation of

such carriers is independent of the applied potential and hence the current is

constant for all increasing reverse potential. This current is referred to as

Reverse Saturation Current (IO) and it increases with temperature. When the

applied reverse voltage is increased beyond the certain limit, it results in

breakdown. During breakdown, the diode current increases tremendously.

PROCEDURE:

FORWARD BIAS:

5. Connect the circuit as per the diagram.

6. Vary the applied voltage V in steps of 0.1V.

7. Note down the corresponding Ammeter readings I.

8. Plot a graph between V & I

OBSERVATIONS

4. Find the d.c (static) resistance = V/I.

5. Find the a.c (dynamic) resistance r = δV / δI (r = ∆∆∆∆V/∆∆∆∆I) = 12

12

II

VV

−.

6. Find the forward voltage drop = [Hint: it is equal to 0.7 for Si and 0.3 for

Ge]

REVERSE BIAS:

6. Connect the circuit as per the diagram.

7. Vary the applied voltage V in steps of 1.0V.

8. Note down the corresponding Ammeter readings I.

9. Plot a graph between V & I

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(0-100)mA, MC

+ -

+

-

(0-15)V, MC +

-

(0-10)V

RPS

(0-500)µA,MC

+ -

+

-

(0-30)V, MC +

-

(0-30)V

RPS

10. Find the dynamic resistance r = δδδδV / δδδδI.

FORMULA FOR REVERSE SATURATION CURRENT (IO):

Io = ∂∂∂∂I/[exp(∂∂∂∂V/ηηηηVT)]-1

Where VT is the voltage equivalent of Temperature = kT/q

-k is Boltzmann’s constant, q is the charge of the electron and T is the

temperature in degrees Kelvin.

η =1 for Silicon and 2 for Germanium

CIRCUIT DIAGRAM:

FORWARD BIAS:

REVERSE BIAS:

470 Ω a

470 Ω a

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Specification for 1N4001: Silicon Diode

Peak Inverse Voltage: 50V

Idc = 1A.

Maximum forward voltage drop at 1 Amp is 1.1 volts

Maximum reverse current @50 volts is 5µA

TABULAR COLUMN:

FORWARD BIAS: REVERSE BIAS:

MODEL GRAPH

If (mA)

I2

Vb I1

( Volts) V1 V2 Vf

(Volts)

Ir (µA)

S.No. VOLTAGE

(In Volts)

CURRENT

(In mA)

S..No. VOLTAGE

(In Volts)

CURRENT

(In µµµµA)

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RESULT:

Forward and Reverse bias characteristics of the PN junction diode and the

dynamic resistance under

i) Forward bias = ---------------------

ii) Reverse bias = ----------------------.

iii) Reverse Saturation Current = ----------------.

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Ex.No.1b

CHARACTERISTICS OF ZENER DIODE

AIM:

To determine the breakdown voltage of a given zener diode.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 zener

diode

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A properly doped crystal diode, which has a sharp breakdown voltage, is known

as zener diode.

FORWARD BIAS:

On forward biasing, initially no current flows due to barrier potential. As the

applied potential increases, it exceeds the barrier potential at one value and the

charge carriers gain sufficient energy to cross the potential barrier and enter the

other region. the holes ,which are majority carriers in p-region, become minority

carriers on entering the N-regions and electrons, which are the majority carriers

in the N-regions become minority carriers on entering the P-region. This injection

of minority carriers results current, opposite to the direction of electron

movement.

REVERSE BIAS:

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When the reverse bias is applied due to majority carriers small amount of

current (ie) reverse saturation current flows across the junction. As the reverse

bias is increased to breakdown voltage, sudden rise in current takes place due to

zener effect.

ZENER EFFECT:

Normally, PN junction of Zener Diode is heavily doped. Due to heavy

doping the depletion layer will be narrow. When the reverse bias is increased the

potential across the depletion layer is more. This exerts a force on the electrons

in the outermost shell. Because of this force the electrons are pulled away from

the parent nuclei and become free electrons. This ionization, which occurs due to

electrostatic force of attraction, is known as Zener effect. It results in large

number of free carriers, which in turn increases the reverse saturation current

PROCEDURE:

FORWARD BIAS:

1. Connect the circuit as per the circuit diagram.

2. Vary the power supply in such a way that the readings are taken in steps

of 0.1V in the voltmeter till the needle of power supply shows 30V.

3. Note down the corresponding ammeter readings.

4. Plot the graph :V (vs) I.

5. Find the dynamic resistance r = δδδδV / δδδδI.

REVERSE BIAS:

7. Connect the circuit as per the diagram.

8. Vary the power supply in such a way that the readings are taken in steps

of 0.1V in the voltmeter till the needle of power supply shows 30V.

9. Note down the corresponding Ammeter readings I.

10. Plot a graph between V & I

11. Find the dynamic resistance r = δδδδV / δδδδI.

12. Find the reverse voltage Vr at Iz=20 mA.

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(0-15) V

+ -

+

-

+

-

(0-10) V

(0-10) V, MC

+ -

+

-

+

-

(0-30) V

CIRCUIT DIAGRAM:

FORWARD BIAS:

REVERSE BIAS:

1

470 Ω

aaaaa

(0-10)mA

1

1KΩ

aaaaa

(0-500)A, MC

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ZENER DIODE:

If ( mA)

I2

VB I1

Vr V1 V2 Vf

(V) (V)

Ir (A)

TABULAR COLUMN:

FORWARD BIAS: REVERSE BIAS:

RESULT:

Forward and Reverse bias characteristics of the zener diode was studied

and

Forward bias dynamic resistance = ---------------------

Reverse bias dynamic resistance = ----------------------

The reverse voltage at Iz =20 mA determined from the reverse

characteristics of the Zener diode is --------------------------.

S..No. VOLTAGE

(In Volts)

CURRENT

(In mA)

S.No. VOLTAGE

(In Volts)

CURRENT

(In µµµµA)

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Ex. No. 2a

CHARACTERISTICS OF CE CONFIGURATION USING BJT

AIM:

To plot the transistor characteristics of CE configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 Transistor

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A BJT is a three terminal two – junction semiconductor device in which the

conduction is due to both the charge carrier. Hence it is a bipolar device and it

amplifier the sine waveform as they are transferred from input to output. BJT is

classified into two types – NPN or PNP. A NPN transistor consists of two N

types in between which a layer of P is sandwiched. The transistor consists of

three terminal emitter, collector and base. The emitter layer is the source of the

charge carriers and it is heartily doped with a moderate cross sectional area.

The collector collects the charge carries and hence moderate doping and large

cross sectional area. The base region acts a path for the movement of the

charge carriers. In order to reduce the recombination of holes and electrons the

base region is lightly doped and is of hollow cross sectional area. Normally the

transistor operates with the EB junction forward biased.

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Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

In transistor, the current is same in both junctions, which indicates that

there is a transfer of resistance between the two junctions. One to this fact the

transistor is known as transfer resistance of transistor.

PROCEDURE:

INPUT CHARACTERISTICS:

4. Connect the circuit as per the circuit diagram.

5. Set VCE, vary VBE in regular interval of steps and note down the

corresponding IB reading. Repeat the above procedure for different values of

VCE.

6. Plot the graph: VBE Vs IB for a constant VCE.

OUTPUT CHARACTERISTICS:

4. Connect the circuit as per the circuit diagram.

5. Set IB, Vary VCE in regular interval of steps and note down the

corresponding IC reading. Repeat the above procedure for different

values of IB.

6. Plot the graph: VCE Vs IC for a constant IB.

PIN DIAGRAM:

B

E C

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(0 – 250) µA

10 KΩ

(0 – 30)mA

- + 1 KΩ

BC107

+

-

+

-(0-30)V

+

-

+

-

+ -

(0-30)V

(0-30)V

(0-1)V

CIRCUIT DIAGRAM:

MODEL GRAPH:

INPUT CHARACTERISTICS: OUTPUT CHARACTERISTICS:

A

A

V

V

C

E

B

VCE = 0V

VCE = 5V

IB

µA mA

VBE(V) VCE(V)

0 0

IB=60µA

IB=40µA

IB=20µA

IC

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TABULAR COLUMN:

INPUT CHARACTERISTICS:

VCE=1V VCE=2V

VBE(V) IB(A) VBE(V) IB(A)

OUTPUT CHARACTERISTICS:

IB=20µµµµA IB=40µµµµA

VCE(V) IC(mA) VCE(V) IC(mA)

RESULT:

The transistor characteristics of a Common Emitter (CE)

configuration were plotted

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Ex.No.2b

CHARACTERISTICS OF CB CONFIGURATION USING BJT

AIM:

To plot the transistor characteristics of CB configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 Transistor BC 107 1

2 Ammeter

(0–10)mA 1 2 Resistor 10kΩ

1KΩ

1

(0–1)A 1 3 Bread

Board

1

3 Voltmeter (0–30)V 1 4 Wires

(0–2)V 1

THEORY:

In this configuration the base is made common to both the input and out.

The emitter is given the input and the output is taken across the collector. The

current gain of this configuration is less than unity. The voltage gain of CB

configuration is high. Due to the high voltage gain, the power gain is also high. In

CB configuration, Base is common to both input and output. In CB configuration

the input characteristics relate IE and VEB for a constant VCB. Initially let VCB = 0

then the input junction is equivalent to a forward biased diode and the

characteristics resembles that of a diode. Where VCB = +VI (volts) due to early

effect IE increases and so the characteristics shifts to the left. The output

characteristics relate IC and VCB for a constant IE. Initially IC increases and then it

levels for a value IC = αIE. When IE is increased IC also increases proportionality.

Though increase in VCB causes an increase in α, since α is a fraction, it is

negligible and so IC remains a constant for all values of VCB once it levels off.

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(0-30)V

(0-1)mA

+ -

(0-30)mA

+ -

+

-

+

-

+

-(0-2)V (0-30)V (0-30)V

PIN DIAGRAM:

B

Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

E C

CIRCUIT DIAGRAM:

-

PROCEDURE:

INPUT CHARACTERISTICS:

It is the curve between emitter current IE and emitter-base voltage VBE at

constant collector-base voltage VCB.

5. Connect the circuit as per the circuit diagram.

6. Set VCE=5V, vary VBE in steps of 0.1V and note down the corresponding

IB. Repeat the above procedure for 10V, 15V.

7. Plot the graph VBE Vs IB for a constant VCE.

8. Find the h parameters.

OUTPUT CHARACTERISTICS:

It is the curve between collector current IC and collector-base voltage VCB at

constant emitter current IE.

5. Connect the circuit as per the circuit diagram.

6. Set IB=20µA, vary VCE in steps of 1V and note down the corresponding IC.

Repeat the above procedure for 40µA, 80µA, etc.

a10 KΩ

a

a

a

1KΩ

VEB

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7. Plot the graph VCE Vs IC for a constant IB.

8. Find the h parameters

TABULAR COLUMN:

INPUT CHARACTERISTICS:

S.No. VCB = V VCB = V VCB = V

VEB

(V)

IE

(µµµµA)

VEB

(V)

IE

(µµµµA)

VEB

(V)

IE

(µµµµA)

OUTPUT CHARACTERISTICS:

S.No. IE= mA IE= mA IE= mA

VCB

(V)

Ic

(mA)

VCB

(V)

Ic

(mA)

VCB

(V)

Ic

(mA)

MODEL GRAPH:

INPUT CHARACTERISTICS:

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IC

(mA)

VCB1

IE2

VCB2

IE1 VEB1 VEB2 VEB (V)

OUTPUT CHARACTERISTICS:

IC

(mA) IE3

IC2 IE2

IC1

IE1

VCB1 VCB2 VCB (V)

RESULT:

The transistor characteristics of a Common Base (CB) configuration were

plotted and uses studied.

Ex.No.2c

CHARACTERISTICS OF CC CONFIGURATION USING BJT

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AIM:

To plot the transistor characteristics of CE configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 Transistor BC 107 1

2 Ammeter

(0–30)mA 1 2 Resistor 1kΩ 2

(0–250)µA 1 3 Bread

Board

1

3 Voltmeter (0–30)V 1 4 Wires

(0–5)V 1

THEORY:

A BJT is a three terminal two – junction semiconductor device in which the

conduction is due to both the charge carrier. Hence it is a bipolar device and it

amplifier the sine waveform as they are transferred from input to output. BJT is

classified into two types – NPN or PNP. A NPN transistor consists of two N

types in between which a layer of P is sandwiched. The transistor consists of

three terminal emitter, collector and base. The emitter layer is the source of the

charge carriers and it is heartily doped with a moderate cross sectional area.

The collector collects the charge carries and hence moderate doping and large

cross sectional area. The base region acts a path for the movement of the

charge carriers. In order to reduce the recombination of holes and electrons the

base region is lightly doped and is of hollow cross sectional area. Normally the

transistor operates with the EB junction forward biased.

In transistor, the current is same in both junctions, which indicates that

there is a transfer of resistance between the two junctions. One to this fact the

transistor is known as transfer resistance of transistor.

PIN DIAGRAM:

B

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Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

+

-

-

+ -+ +

-

+

+ -

(0-30)mA

(0-250)µA

E C

CIRCUIT DIAGRAM:

PROCEDURE:

INPUT CHARECTERISTICS:

4. Connect the circuit as per the circuit diagram.

5. Set VCE, vary VBE in regular interval of steps and note down the

corresponding IB reading. Repeat the above procedure for different values

of VCE.

6. Plot the graph: VBC Vs IB for a constant VCE.

OUTPUT CHARECTERISTICS:

4. Connect the circuit as per the circuit diagram.

A

A V

V

1 KΩ

+

-

(0-30)V (0-30)V

(0-30)V (0-30)V

1 KΩ

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5. Set IB, Vary VCE in regular interval of steps and note down the

corresponding IC reading. Repeat the above procedure for different

values of IB.

6. Plot the graph: VCE Vs IC for a constant IB.

MODEL GRAPH:

INPUT CHARACTERISTICS: OUTPUT CHARACTERISTICS:

(µµµµA) (mA)

IB Ie

VCE=0 VCE=5V IB=60µµµµA

IB=40µµµµA

IB=20µµµµA

0 VBC(V) 0 VCE(V)

TABULAR COLUMN:

INPUT CHARACTERISTICS:

VCE=1V VCE=2V

VBC(V) IB(A) VBC(V) IB(A)

OUTPUT CHARACTERISTICS:

IB=20µµµµA IB=40µµµµA

VCE(V) IE(mA) VCE(V) IE(mA)

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RESULT:

The transistor characteristics of a Common Emitter (CC) configuration

were plotted.

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Ex.No.3

CHARACTERISTICS OF JUNCTION FIELD EFFECT TRANSISTOR

AIM:

To Plot the characteristics of given FET & determine rd, gm, µ, IDSS,VP.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 FET BFW10 1

2 Ammeter (0–30)mA 1 2 Resistor 1kΩ

68KΩ

1

1

3 Voltmeter (0–30)V 1 3

Bread

Board

1

(0-10)V 1 4 Wires

THEORY:

FET is a voltage operated device. It has got 3 terminals. They are Source,

Drain & Gate. When the gate is biased negative with respect to the source, the

pn junctions are reverse biased & depletion regions are formed. The channel is

more lightly doped than the p type gate, so the depletion regions penetrate

deeply in to the channel. The result is that the channel is narrowed, its resistance

is increased, & ID is reduced. When the negative bias voltage is further

increased, the depletion regions meet at the center & ID is cutoff completely.

PROCEDURE:

DRAIN CHARACTERISTICS:

6. Connect the circuit as per the circuit diagram.

7. Set the gate voltage VGS = 0V.

8. Vary VDS in steps of 1 V & note down the corresponding ID.

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+ (0-30)V

68KΩ

V

+

(0-30)V

(0-30)V

1k (0-30mA)

D G

S

BFW10

-

+ (0-10)V V

A

-

9. Repeat the same procedure for VGS = -1V.

10. Plot the graph VDS Vs ID for constant VGS.

OBSERVATIONS

4. d.c (static) drain resistance, rD = VDS/ID.

5. a.c (dynamic) drain resistance, rd = ∆∆∆∆VDS/∆∆∆∆ID.

6. Open source impedance, YOS = 1/ rd.

TRANSFER CHARACTERISTICS:

6. Connect the circuit as per the circuit diagram.

7. Set the drain voltage VDS = 5 V.

8. Vary the gate voltage VGS in steps of 1V & note down the corresponding ID.

9. Repeat the same procedure for VDS = 10V.

10. Plot the graph VGS Vs ID for constant VDS.

FET PARAMETER CALCULATION:

Drain Resistancd rd = GS

D

DS VI

V

Transconductance gm = DS

GS

D VV

I

Amplification factor =rd . gm

CIRCUIT DIAGRAM:

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I D (

mA

) PIN DIAGRAM:

BOTTOM VIEW OF BFW10:

SPECIFICATION:

Voltage : 30V, IDSS > 8mA.

MODEL GRAPH:

DRAIN CHARACTERISTICS:

TRANSFER CHARACTERISTICS:

ID(mA)

VDS =Const

VGS (V)

0

VGS = 0V

VGS = -1V

VGS = -2V

VGS = -3V

VDS (volts)

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TABULAR COLUMN:

DRAIN CHARACTERISTICS:

VGS = 0V VGS = -1V

VDS (V) ID(mA) VDS (V) ID(mA)

TRANSFER CHARACTERISTICS:

RESULT:

Thus the Drain & Transfer characteristics of given FET is Plotted.

Rd =

gm =

µ =

IDSS =

Pinch off voltage VP =

VDS =5volts VDS = 10volts

VGS (V) ID(mA) VGS (V) ID(mA)

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Ex.No.4

CHARACTERISTICS OF UNIJUNCTION TRANSISTOR

AIM:

To Plot the characteristics of UJT & determine it’s intrinsic standoff

Ratio.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 UJT 2N2646 1

2 Ammeter (0–30)mA 1

2 Resistor 1KΩ 2

3 Bread

Board

1

3 Voltmeter (0–30)V 1

(0–10)V 1

THEORY:

UJT(Double base diode) consists of a bar of lightly doped n-type silicon

with a small piece of heavily doped P type material joined to one side. It has got

three terminals. They are Emitter(E), Base1(B1),Base2(B2).Since the silicon bar

is lightly doped, it has a high resistance & can be represented as two resistors,

rB1 & rB2. When VB1B2 = 0, a small increase in VE forward biases the emitter

junction. The resultant plot of VE & I E is simply the characteristics of forward

biased diode with resistance. Increasing VEB1 reduces the emitter junction

reverse bias. When VEB1 = VrB1 there is no forward or reverse bias. & IE = 0.

Increasing VEB1 beyond this point begins to forward bias the emitter junction. At

the peak point, a small forward emitter current is flowing. This current is termed

as peak current( IP ). Until this point UJT is said to be operating in cutoff region.

When IE increases beyond peak current the device enters the negative

resistance region. In which the resistance rB1 falls rapidly & VE falls to the valley

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B2

E

voltage.Vv. At this point IE = Iv. A further increase of IE causes the device to

enter the saturation region.

PROCEDURE:

6. Connect the circuit as per the circuit diagram.

7. Set VB1B2 = 0V, vary VEB1 , & note down the readings of IE & VEB1

8. Set VB1B2 = 10V , vary VEB1 , & note down the readings of IE & VEB1

9. Plot the graph : IE Versus VEB1 for constant VB1B2.

10. Find the intrinsic standoff ratio.

CIRCUIT DIAGRAM:

PIN DIAGRAM:

BOTTOM VIEW OF 2N2646:

SPECIFICATION FOR 2N2646:

* Inter base resistance RBB = 4.7 to 9.1 KΩ

B2

(0-30)V (0-30)V

(0-30)V

1KΩ 1KΩ

(0-30)V

(0-30)mA

V V

A

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* Minimum Valley current = 4 mA

* Maximun Peak point emitter current 5 µA

*Maximum emitter reverse current 12 µA.

FORMULA FOR INTRINSIC STANDOFF RATIO:

η = VP - VD/ VB1B2., where VD = 0.7V.

MODEL GRAPH:

Peak point

VP

IP

Negative resistance region

VEB1(V)

Valley point VB1B2 = V

VB1B2 = 0V

IV IE (mA)

TABULAR COLUMN:

VB1B2 = 0V VB1B2 = 10V

VEB1 (V) IE (mA) VEB1 (V) IE (mA)

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PROCEDURE:

5. Give the circuit connections as per the circuit diagram.

6. The dc input voltage is set to 20 V in RPS.

7. The output sweep waveform is measured using CRO.

8. The graph of output sweep waveform is plotted

RESULT:

1. Thus the characteristics of given UJT was Plotted & its intrinsic standoff

Ratio = ----.

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Ex.No.5

CHARACTERISTICS OF PHOTO-DIODE AND

PHOTOTRANSISTOR

AIM:

1. To study the characteristics of a photo-diode.

2. To study the characteristics of phototransistor.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 R.P.S (0-30)V 1 1 Photo

diode 1

2 Ammeter (0–30)mA 1

2 Resistor 1KΩ 2

3 Bread

Board 1

3 Voltmeter (0–30)V 1 4 Photo

transistor 1

THEORY:

PHOTODIODE:

A photo diode is a two terminal pn junction device, which operates on

reverse bias. On reverse biasing a pn junction diode, there results a constant

current due to minority charge carriers known as reverse saturation current.

Increasing the thermally generated minority carriers by applying external energy,

i.e., either heat or light energy at the junction can increase this current. When we

apply light energy as an external source, it results in a photo diode that is usually

placed in a glass package so that light can reach the junction. Initially when no

light is incident, the current is only the reverse saturation current that flows

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(0-30)mA

(0-30)V (0-30)V

through the reverse biased diode. This current is termed as the dark current of

the photo diode. Now when light is incident on the photo diode then the thermally

generated carriers increase resulting in an increased reverse current which is

proportional to the intensity of incident light. A photo diode can turn on and off at

a faster rate and so it is used as a fast acting switch.

CIRCUIT DIAGRAM:

TABULAR COLUMN:

MODEL GRAPH:

S.No. VOLTAGE

(In Volts)

CURRENT

(In mA)

R

(KΩ)

Illumination lm/m2

1KΩ a

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THEORY:

PHOTOTRANSISTOR:

It is a transistor with an open base; there exists a small collector current

consisting of thermally produced minority carriers and surface leakage. By

exposing the collector junction to light, a manufacturer can produce a

phototransistor, a transistor that has more sensitivity to light than a photo diode.

Because the base lead is open, all the reverse current is forced into the base of

the transistor. The resulting collector current is ICeo = βdcIr. The main difference

between a phototransistor and a photodiode is the current gain, βdc. The same

amount of light striking both devices produces βdc times more current in a

phototransistor than in a photodiode.

CIRCUIT DIAGRAM:

TABULAR COLUMN: SYMBOL:

E

S. No. VCE

(in Volts)

IC

(in mA)

N P N

1KΩ

(0-30V)

C

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IC

400 Lux

200 Lux

0 Lux

VCE(V)

MODEL GRAPH:

PROCEDURE:

PHOTO DIODE:

6. Rig up the circuit as per the circuit diagram.

7. Maintain a known distance (say 5 cm) between the DC bulb and

the photo diode.

8. Set the voltage of the bulb (say, 2V), vary the voltage of the diode

insteps of 1V and note down the corresponding diode current, Ir.

9. Repeat the above procedure for the various voltages of DC bulb.

10. Plot the graph: VD vs. Ir for a constant DC bulb voltage.

PHOTOTRANSISTOR:

6. Rig up the circuit as per the circuit diagram.

7. Maintain a known distance (say 5 cm) between the DC bulb and the

phototransistor.

8. Set the voltage of the bulb (say, 2V), vary the voltage of the diode

in steps of 1V and note down the corresponding diode current, Ir.

9. Repeat the above procedure for the various values of DC bulb.

10. Plot the graph: VD vs. Ir for a constant bulb voltage.

RESULT:

Thus the characteristics of photo diode and phototransistor are studied.

(mA)

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Ex.No.6

CHARACTERISTICS OF THERMISTOR

AIM:

To study the characteristics of Thermistor.

THEORY:

Thermistor or Thermal resistor is two – terminal semiconductor device

whose resistance is temperature sensitive. The value of such resistors decreases

with increase in temperature. Materials employed in the manufacture of the

thermistors include oxides of cobalt, nickel, copper, iron uranium and

manganese.

The thermistors has very high temperature coefficient of resistance, of the

order of 3 to 5% per °C, making it an ideal temperature transducer. The

temperature coefficient of resistance is normally negative. The reistance at any

temperature T, is given approximately by

RT = Ro exp β (1/T – 1/To)

Where RT = thermistor resistance at temperature T (K), RO = thersmistor

resistance at temperature To (K), and β = a constant determined by calibration.

At high temperatures, this equation reduces to

RT = Ro exp ( β/T)

The resistance – temperature characteristics is shown in Fig 21.10. The

curve is non – linear and the drop in resistance from 5000 to 10Ω occurs for an

increase in temperature from 20 to 100 °C. The temperature of the device can

be changed internally or externally. An increase in current through the device will

raise its temperature carrying a drop in its terminal resistance. Any externally

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heat source will result in an increase in its body temperature and drop in

resistance this type action (internal or external) lends itself well to control

mechanism.

Three useful parameters for characterizing the thermistor are the time

constant, dissipation constant , and resistance ratio. The time constant is the

time for a thermistor to change its resistance by 63% of its initial value, for zero –

power dissipation. Typical values of time constant range from 1 to 50 s.

SYMBOL:

MODEL GRAPH:

The dissipation factor is the power necessary to increase the temperature

of a thermistor by 1˚C. Typical values of dissipation factor range from 1 to 10

mW/˚C.

Resistance ratio is the ratio of the resistance at 25 ˚C. Its range is

approximately

R

(Ω-cm)

T (deg)

T

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3 – 60.

Thermistors are used measure temperature, flow pressure, liquid level,

voltage or power level, vacuum, composition of gases and thermal conductivity

and also in compensation network.

RESULT:

Thus the Characteristics of thermistor was studied.

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Ex.No.7a

SINGLE PHASE HALF WAVE RECTIFIER

AIM:

To construct a Half wave rectifier using diode and to draw its performance

characteristics.

APPARATUS REQUIRED: COMPONENTS

REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 Transformer 230/(6-0-6)V 1 1

Diode IN4001 1

2 R.P.S (0-30)V 2

3 Ammeter

(0–30)mA 1 2 Resistor 1K Ω 1

(0–250)µA 1 3 Bread

Board

1

4 Voltmeter (0–30)V 1 4 Capacitor 100µf 1

(0–2)V 1 5 CRO 1

FORMULAE:

WITHOUT FILTER:

(i) Vrms = Vm / √2

(ii) Vdc = Vm / ∏

(iii) Ripple Factor = √ (Vrms / Vdc)2 – 1

(iv) Efficiency = (Vdc / Vrms)2 x 100

WITH FILTER:

(i) Vrms = √ (Vrms’2 + Vdc

2)

(ii) Vrms’ = Vrpp / (√3 x 2)

(iii) Vdc = Vm – V rpp / 2

(iv) Ripple Factor = Vrms’/ Vdc

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PROCEDURE:

WITHOUT FILTER:

5. Give the connections as per the circuit diagram.

6. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

7. Take the rectifier output across the Load.

8. Plot its performance graph.

WITH FILTER:

1. Give the connections as per the circuit diagram.

6. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

7. Connect the Capacitor across the Load.

8. Take the rectifier output across the Load.

9. Plot its performance graph.

CIRCUIT DIAGRAM:

1φ Transformer

230 V / 6V 1N 4007

1K 100µF 1φ, 230V,

50Hz

AC supply

CRO

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TABULAR COLUMN:

WITHOUT FILTER:

Vm Vrms Vdc Ripple factor Efficiency

WITH FILTER:

Vrms Vrpp Vdc Ripple factor Efficiency

MODEL GRAPH:

RESULT:

Thus the performance characteristics of 1φ Half wave rectifier was obtained.

Vin

(Volts)

t (ms)

Vo

(Volts)

t (ms)

t (ms)

Vo

(Volts)

Without Filter

With Filter

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Ex.No.7b

SINGLE PHASE FULL WAVE RECTIFIER

AIM:

To construct a Full wave rectifier using diode and to draw its performance

characteristics.

APPARATUS REQUIRED: COMPONENTS

REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 Transformer 230/(6-0-6)V 1 1

Diode IN4001 2

2 R.P.S (0-30)V 2

3 Ammeter

(0–30)mA 1 2 Resistor 1K Ω 1

(0–250)µA 1 3 Bread

Board

1

4 Voltmeter (0–30)V 1 4 Capacitor 100µf 1

(0–2)V 1 5 CRO 1

FORMULAE:

WITHOUT FILTER:

(i) Vrms = Vm / √2

(ii) Vdc = 2Vm / ∏

(iii) Ripple Factor = √ (Vrms / Vdc)2 – 1

(iv) Efficiency = (Vdc / Vrms)2 x 100

WITH FILTER:

(i) Vrms = Vrpp /(2*√ 3)

(ii) Vdc = Vm – V rpp

(iv) Ripple Factor = Vrms’/ Vdc

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PROCEDURE:

WITHOUT FILTER:

5. Give the connections as per the circuit diagram.

6. Give 230v, 50HZ I/P to the step down TFR where secondary connected

to the Rectifier I/P.

7. Take the rectifier output across the Load.

8. Plot its performance graph.

WITH FILTER:

1. Give the connections as per the circuit diagram.

6. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

7. Connect the Capacitor across the Load.

8. Take the rectifier output across the Load.

9. Plot its performance graph.

CIRCUIT DIAGRAM:

1N 4007

1K 100µF

1φ, 230V,

50Hz

AC supply

CRO

1N 4007

1φ Transformer

230 V / 6V

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TABULAR COLUMN:

WITHOUT FILTER:

Vm Vrms Vdc Ripple factor Efficiency

WITH FILTER:

Vrms Vrpp Vdc Ripple factor Efficiency

MODEL GRAPH :

RESULT: Thus the performance characteristics of 1φ Full wave rectifier were

obtained.

Vin

(Volts)

t (ms)

Vo

(Volts)

t (ms)

t (ms)

Vo

(Volts)

Without Filter

With Filter

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Ex.No.8

DIFFERENTIAL AMPLIFIER

AIM:

To construct a Differential amplifier in Common mode & Differential mode

configuration and to find common mode rejection ratio.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

Apparatus Range Qty

1 RPS (0-30)V 1

2 CRO 1

3 Signal

Generator 1

4 DCB 2

5 DRB 2

THEORY:

The Differential amplifier circuit is an extremely popular connection used in

IC units. The circuit has separate inputs , two separate outputs and emitters are

connected together. If the same input is applied to both inputs, the operation is

called common mode. In double ended operation two input signals are applied ,

the difference of the inputs resulting in outputs from both collectors due to the

difference of the signals applied to both the inputs. The main feature of the

differential amplifier is the very large gain when opposite signals are applied to

inputs as compared to small signal resulting from common input. The ratio of this

difference gain to the common gain is called common mode rejection ratio.

S.No Item Type Range Qty

1 Transistor BC107 1

2 Capacitor 470µF 1

3 Resistor 3.9K

3.3K

1

1

4 Bread board 1

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CIRCUIT DIAGRAM:

DIFFERENTIAL MODE:

COMMON MODE:

3.3 KΩ

3.9KΩ

Vo1 Vo2

V1

12V V2

13V

3.9KΩ

-9V

9V

3.3 KΩ

3.9KΩ

Vo1 Vo2

V2

13V

3.9KΩ

-9V

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PROCEDURE:

DIFFERENTIAL MODE:

5. Connect the circuit as per the circuit diagram.

6. Set V1 = 50mv and V2 =55mv using the signal generator.

7. Find the corresponding output voltages across V01 & V02 using CRO

8. Calculate common mode rejection ratio using the given formula.

COMMON MODE:

5. Connect the circuit as per the circuit diagram.

6. Set V1 = 50mv using the signal generator.

7. Find the output voltage across Vo using multimeter.

8. Calculte common mode rejection ratio using the given formula.

CALCULATION:

Common mode rejection ratio(CMRR) = Ad / Ac

Ad = Differential mode gain

Ac = Common mode gain

Where Ad = Vo /Vd

Vo = Output voltage measured across CRO

Vd = V 1 – V2 , V 1 , V2 – input voltage applied.

Ac = Vo /Vc

Vc = (V 1 + V2 )/2

DIFFERENTIAL MODE:

V1 =

V2 =

Output voltage =

Vd= V1-V2 =

Ad=Vo/Vd =

RESULT: Thus the differential amplifier was constructed in common mode

and Differential mode configuration. Further common mode rejection ratio was

found

Exp. No: 12

COMMON MODE:

Input voltage =

Output voltage =

V1=V2 =

Vc=(V1+V2)/2 =

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PASSIVE FILTERS

Aim:

To attenuate unwanted frequency components from input signal by using resistor

and capacitor.

Apparatus required:

S.No Name of the apparatus Range Type Quantity

1. Signal Generator 01

2. Resistor 01

3. Capacitor Ceramic 01

4. CRO 01

5. Breadboard 01

Theory:

A filter is an AC circuit that separates some frequencies from other in

within mixed – frequency signals. Audio equalizers and crossover networks are

two well-known applications of filter circuits. A Bode plot is a graph plotting

waveform amplitude or phase on one axis and frequency on the other.

A low-pass filter allows for easy passage of low-frequency signals from

source to load, and difficult passage of high-frequency signals. Capacitor low-pass

filters insert a resistor in series and a capacitor in parallel with the load as shown

in the circuit diagram. The former filter design tries to “block” the unwanted

frequency signal while the latter tries to short it out.

The cutoff frequency for a low-pass filter is that frequency at which the

output (load) voltage equals 70.7% of the input (Source) voltage. Above the cutoff

frequency, the output voltage is lower than 70.7% of the input, and vice-versa. See

the circuit diagram

1

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Fcutoff = ----------

2πRC

A high-pass filter allows for easy passage of high-frequency signals from source to

load, and difficult passage of low-frequency signals. Capacitor high-pass filters

insert a capacitor in series with the load as shown in the circuit diagram. The

former filter design tries to “brick” the unwanted frequency signal while the latter

tries to short it out.

The cutoff frequency for a high-pass filter is that frequency at which the

output (load) voltage equals 70.7% of the input (source) voltage. Above the cutoff

frequency, the output voltage is greater than 70.7% of the input, and vice-versa.

1

Fcutoff = ----------

2πRC

A band – pass filter works to screen out frequencies that are too low or too

high, giving easy passage only to frequencies within a certain range. Stacking a

low-pass filter on the end of a high-pass filter, or vice-versa can make band-pass

filters. Refer the circuit diagrams

Fig. 7.6

“Attenuate” means to reduce or diminish in amplitude. When you

turn down the volume control on your stereo, you are “attenuating” the signal

being sent to the speakers.

A band-stop filter works to screen out frequencies that are within a certain

range, giving easy passage only to frequencies outside of that range. Also known

as band-elimination, band-reject, or notch filters.

Signal

input

Low-pass filter High-pass filter Signal

output Blocks frequencies

that are too high

Blocks frequencies

that are too low

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Signal

Input

Low-pass filter

High-pass filter

Signal

Output

Placing a low-pass filter in parallel with a high-pass filter can make band-

stop filters. Commonly, both the low-pass and high-pass filter sections are of the

“T” configuration giving the name “Twin-T” to the band-stop combination. Refer

the fig.7.7, 7.8a and 7.8b.

Passes low frequencies

Passes high frequencies

Fig. 7.8a

The frequency of maximum attenuation is called the notch

frequency.

Procedure:

7. Give the connections as per circuit diagrams.

8. Switch on the main.

9. Change the frequency from minimum and find the output

voltage by using CRO.

10. Draw the graph.

11. Verify the cut off frequency.

12. Switch off the main.

Result:

Thus we analyze passive filter and various waveforms are noted

Exp. No : 10

STUDY OF CRO AND

POWER FACTOR MEASUREMENT USING CRO

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Aim:

To study cathode Ray Oscilloscope (CRO) and measurement of power factor using

CRO.

Apparatus required:

S.No Name of the apparatus Range Type Quantity

1. Resistance Box 1

2. Capacitance Box 1

3. Inductance Box 1

4. Function Generator 1

5. Bread board 1

Theory:

The cathode ray oscilloscope is the most versatile measuring instrument

available. We can measure following parameters using the CRO:

5. AC or DC voltage.

6. Time (t=1/f).

7. Phase relationship

8. Waveform calculation: Rise time; fall time; on time; off-time

Distortion, etc.

We can also measure non-electrical physical quantities like pressure, strain,

temperature, acceleration, etc., by converting into electrical quantities using

a transducer.

Major blocks:

7. Cathode ray tube (CRT)

8. Vertical amplifier

9. Horizontal amplifier

10. Sweep generator

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11. Trigger circuit

12. Associated power supply.

6. The cathode ray tube is the heart of CRO. The CRT is enclosed in an

evacuated glass envelope to permit the electron beam to traverse in the

tube easily. The main functional units of CRO are as follows.

Electron gun assembly

Deflection plate unit

Screen.

7. Vertical Amplifier is the main factor in determining the bandwidth and

sensitivity of an oscilloscope. Vertical sensitivity is a measure of how

much the electron beam will be deflected for a specified input signal.

On the front panel of the oscilloscope, one can see a knob attached to a

rotary switch labeled volts/division. The rotary switch is electrically

connected to the input attenuation network. The setting of the rotary

switch indicates what amplitude signal is required to deflect the beam

vertically by one division.

8. Horizontal amplifier Under normal mode of operation, the horizontal

amplifier will amplify the sweep generator input. When the CRO is

being used in the X-Y mode, the horizontal amplifier will amplify the

signal applied to the horizontal input terminal. Although the vertical

amplifier mush be able to faithfully reproduce low-amplitude and high

frequency signal with fast rise-time, the horizontal amplifier is only

required to provide a faithful reproduction of the sweep signal which

has a relatively high amplitude and slow rise time.

9. Sweep generator and Trigger circuit These two units form the Signal

Synchronization unit of the CRO.

10. Associated Power Supply: The input signal may come from an

external source when the trigger selector switch is set to EXT or from

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low amplitude AC voltage at line frequency when the switch is set to

LINE or from the vertical amplifier when the switch is set to INT. When

set for INT (internal triggering), the trigger circuit receives its inputs

from the vertical amplifier.

Major Blocks in a Practical CRO

A CRO consists of a cathode ray tube (CRT) and additional control knobs.

The main parts of a CRT are:

4. Electron gun assembly.

5. Deflection plate assembly.

6. Fluorescent screen.

Electron Gun Assembly: The electron gun assembly produces a sharp beam of

electrons, which are accelerated to high velocity. This focused beam of electrons

strike the fluorescent screen with sufficient energy to cause a luminous spot on the

screen.

Deflection plate assembly: This part consists of two plates in which one pair of

plates is placed horizontally and other of plates is placed vertically. The signal

under test is applied to vertical deflecting plates. The horizontal deflection plates

are connected to a built-in ramp generator, which moves the luminous spot

periodically in a horizontal direction from left to right over the screen. These two

deflection plates give stationary appearance to the waveform on the screen. CRO

operates on voltage. Since the deflection of the electron beam is directly

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proportional to the deflecting voltage, the CRT may be used as a linear measuring

device. The voltage being measured is applied to the vertical plates through an

iterative network, whose propagation time corresponds to the velocity of electrons,

thereby synchronizing the voltage applied to the vertical plate with the velocity of

the beam.

Synchronization of input signal: The sweep generator produces a saw tooth

waveform, which is used to synchronize the applied voltage to obtain a stationary-

applied signal. This requires that the time base be operated at a submultiples

frequency of the signal under measurement. If synchronization is not done, the

pattern is not stationary, but appears to drift across the screen in a random fashion.

Internal synchronization This trigger is obtained from the time base generator to

synchronize the signal.

External synchronization An external trigger source can also be used to

synchronize the signal being measured.

Auto Triggering Mode The time base used in this case in a self-oscillating

condition, i.e., it gives an output even in the absence of any Y-input. The

advantage of this mode is that the beam is visible on the screen under all

conditions, including the zero input. When the input exceeds a certain magnitude

then the internal free running oscillator locks on to the frequency.

Precautions:

3. The ammeter is connected using thick wires.

4. While reversing ammeter polarity, see to it that the capacitor is not

discharged.

Observation:

Sl.No Time Voltage Current

Unit (Sec) (Volts) (Amps)

Result: Thus we study about CRO & to measure p.f

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CLASS : II YEAR/ III SEMSESTER

SUBJECT CODE : 131351

SUBJECT : ELECTRON DEVICES AND CIRCUITS LAB

BATCH : B1

STAFF IN-CHARGE: Mrs. A. ALICE HEPZIBAH

DESIGNATION : ASSISTANT PROFESSOR

STAFF CODE : EE10

LIST OF EXPERIMENTS

131351 ELECTRON DEVICES AND CIRCUITS LABORATORY L T P C (B.E. (EEE), B.E. (E&I) and B.E. (I & C) 0 0 3 2 (Revised)

25. Characteristics of semiconductor diode and zener diode .

26. Characteristics of transistor under CE, CB and CC .

27. Characteristics of FET .

28. Characteristics of UJT .

29. Characteristics of SCR, DIAC and TRIAC.

30. Photodiode, Phototransistor characteristics and study of light

activated relay circuit.

31. Static characteristics of Thermistors.

32. Single phase half wave and full wave rectifiers with inductive and

capacitive filters.

33. Differential amplifiers using FET.

34. Study of CRO.

35. Series and parallel resonance circuits.

36. Realization of passive filters.

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Ex.No.1a

CHARACTERISTICS OF PN JUNCTION DIODE

AIM:

To study the PN junction diode characteristics under Forward & Reverse

bias conditions.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 Diode

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A PN junction diode is a two terminal junction device. It conducts only in

one direction (only on forward biasing).

FORWARD BIAS:

On forward biasing, initially no current flows due to barrier potential. As the

applied potential exceeds the barrier potential the charge carriers gain sufficient

energy to cross the potential barrier and hence enter the other region. The holes,

which are majority carriers in the P-region, become minority carriers on entering

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the N-regions, and electrons, which are the majority carriers in the N-region,

become minority carriers on entering the P-region. This injection of Minority

carriers results in the current flow, opposite to the direction of electron

movement.

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REVERSE BIAS:

On reverse biasing, the majority charge carriers are attracted towards the

terminals due to the applied potential resulting in the widening of the depletion

region. Since the charge carriers are pushed towards the terminals no current

flows in the device due to majority charge carriers. There will be some current in

the device due to the thermally generated minority carriers. The generation of

such carriers is independent of the applied potential and hence the current is

constant for all increasing reverse potential. This current is referred to as

Reverse Saturation Current (IO) and it increases with temperature. When the

applied reverse voltage is increased beyond the certain limit, it results in

breakdown. During breakdown, the diode current increases tremendously.

PROCEDURE:

FORWARD BIAS:

9. Connect the circuit as per the diagram.

10. Vary the applied voltage V in steps of 0.1V.

11. Note down the corresponding Ammeter readings I.

12. Plot a graph between V & I

OBSERVATIONS

7. Find the d.c (static) resistance = V/I.

8. Find the a.c (dynamic) resistance r = δV / δI (r = ∆∆∆∆V/∆∆∆∆I) = 12

12

II

VV

−.

9. Find the forward voltage drop = [Hint: it is equal to 0.7 for Si and 0.3 for

Ge]

REVERSE BIAS:

11. Connect the circuit as per the diagram.

12. Vary the applied voltage V in steps of 1.0V.

13. Note down the corresponding Ammeter readings I.

14. Plot a graph between V & I

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(0-100)mA, MC

+ -

+

-

(0-15)V, MC +

-

(0-10)V

RPS

(0-500)µA,MC

+ -

+

-

(0-30)V, MC +

-

(0-30)V

RPS

15. Find the dynamic resistance r = δδδδV / δδδδI.

FORMULA FOR REVERSE SATURATION CURRENT (IO):

Io = ∂∂∂∂I/[exp(∂∂∂∂V/ηηηηVT)]-1

Where VT is the voltage equivalent of Temperature = kT/q

-k is Boltzmann’s constant, q is the charge of the electron and T is the

temperature in degrees Kelvin.

η =1 for Silicon and 2 for Germanium

CIRCUIT DIAGRAM:

FORWARD BIAS:

REVERSE BIAS:

470 Ω a

470 Ω a

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Specification for 1N4001: Silicon Diode

Peak Inverse Voltage: 50V

Idc = 1A.

Maximum forward voltage drop at 1 Amp is 1.1 volts

Maximum reverse current @50 volts is 5µA

TABULAR COLUMN:

FORWARD BIAS: REVERSE BIAS:

MODEL GRAPH

If (mA)

I2

Vb I1

( Volts) V1 V2 Vf

(Volts)

Ir (µA)

S.No. VOLTAGE

(In Volts)

CURRENT

(In mA)

S..No. VOLTAGE

(In Volts)

CURRENT

(In µµµµA)

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RESULT:

Forward and Reverse bias characteristics of the PN junction diode and the

dynamic resistance under

i) Forward bias = ---------------------

ii) Reverse bias = ----------------------.

iii) Reverse Saturation Current = ----------------.

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Ex.No.1b

CHARACTERISTICS OF ZENER DIODE

AIM:

To determine the breakdown voltage of a given zener diode.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 zener

diode

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A properly doped crystal diode, which has a sharp breakdown voltage, is known

as zener diode.

FORWARD BIAS:

On forward biasing, initially no current flows due to barrier potential. As the

applied potential increases, it exceeds the barrier potential at one value and the

charge carriers gain sufficient energy to cross the potential barrier and enter the

other region. the holes ,which are majority carriers in p-region, become minority

carriers on entering the N-regions and electrons, which are the majority carriers

in the N-regions become minority carriers on entering the P-region. This injection

of minority carriers results current, opposite to the direction of electron

movement.

REVERSE BIAS:

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When the reverse bias is applied due to majority carriers small amount of

current (ie) reverse saturation current flows across the junction. As the reverse

bias is increased to breakdown voltage, sudden rise in current takes place due to

zener effect.

ZENER EFFECT:

Normally, PN junction of Zener Diode is heavily doped. Due to heavy

doping the depletion layer will be narrow. When the reverse bias is increased the

potential across the depletion layer is more. This exerts a force on the electrons

in the outermost shell. Because of this force the electrons are pulled away from

the parent nuclei and become free electrons. This ionization, which occurs due to

electrostatic force of attraction, is known as Zener effect. It results in large

number of free carriers, which in turn increases the reverse saturation current

PROCEDURE:

FORWARD BIAS:

1. Connect the circuit as per the circuit diagram.

2. Vary the power supply in such a way that the readings are taken in steps

of 0.1V in the voltmeter till the needle of power supply shows 30V.

3. Note down the corresponding ammeter readings.

4. Plot the graph :V (vs) I.

5. Find the dynamic resistance r = δδδδV / δδδδI.

REVERSE BIAS:

13. Connect the circuit as per the diagram.

14. Vary the power supply in such a way that the readings are taken in steps

of 0.1V in the voltmeter till the needle of power supply shows 30V.

15. Note down the corresponding Ammeter readings I.

16. Plot a graph between V & I

17. Find the dynamic resistance r = δδδδV / δδδδI.

18. Find the reverse voltage Vr at Iz=20 mA.

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(0-15) V

+ -

+

-

+

-

(0-10) V

(0-10) V, MC

+ -

+

-

+

-

(0-30) V

CIRCUIT DIAGRAM:

FORWARD BIAS:

REVERSE BIAS:

1

470 Ω

aaaaa

(0-10)mA

1

1KΩ

aaaaa

(0-500)A, MC

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ZENER DIODE:

If ( mA)

I2

VB I1

Vr V1 V2 Vf

(V) (V)

Ir (A)

TABULAR COLUMN:

FORWARD BIAS: REVERSE BIAS:

RESULT:

Forward and Reverse bias characteristics of the zener diode was studied

and

Forward bias dynamic resistance = ---------------------

Reverse bias dynamic resistance = ----------------------

The reverse voltage at Iz =20 mA determined from the reverse

characteristics of the Zener diode is --------------------------.

S..No. VOLTAGE

(In Volts)

CURRENT

(In mA)

S.No. VOLTAGE

(In Volts)

CURRENT

(In µµµµA)

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Ex. No. 2a

CHARACTERISTICS OF CE CONFIGURATION USING BJT

AIM:

To plot the transistor characteristics of CE configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 Transistor

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A BJT is a three terminal two – junction semiconductor device in which the

conduction is due to both the charge carrier. Hence it is a bipolar device and it

amplifier the sine waveform as they are transferred from input to output. BJT is

classified into two types – NPN or PNP. A NPN transistor consists of two N

types in between which a layer of P is sandwiched. The transistor consists of

three terminal emitter, collector and base. The emitter layer is the source of the

charge carriers and it is heartily doped with a moderate cross sectional area.

The collector collects the charge carries and hence moderate doping and large

cross sectional area. The base region acts a path for the movement of the

charge carriers. In order to reduce the recombination of holes and electrons the

base region is lightly doped and is of hollow cross sectional area. Normally the

transistor operates with the EB junction forward biased.

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Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

In transistor, the current is same in both junctions, which indicates that

there is a transfer of resistance between the two junctions. One to this fact the

transistor is known as transfer resistance of transistor.

PROCEDURE:

INPUT CHARACTERISTICS:

7. Connect the circuit as per the circuit diagram.

8. Set VCE, vary VBE in regular interval of steps and note down the

corresponding IB reading. Repeat the above procedure for different values of

VCE.

9. Plot the graph: VBE Vs IB for a constant VCE.

OUTPUT CHARACTERISTICS:

7. Connect the circuit as per the circuit diagram.

8. Set IB, Vary VCE in regular interval of steps and note down the

corresponding IC reading. Repeat the above procedure for different

values of IB.

9. Plot the graph: VCE Vs IC for a constant IB.

PIN DIAGRAM:

B

E C

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(0 – 250) µA

10 KΩ

(0 – 30)mA

- + 1 KΩ

BC107

+

-

+

-(0-30)V

+

-

+

-

+ -

(0-30)V

(0-30)V

(0-1)V

CIRCUIT DIAGRAM:

MODEL GRAPH:

INPUT CHARACTERISTICS: OUTPUT CHARACTERISTICS:

A

A

V

V

C

E

B

VCE = 0V

VCE = 5V

IB

µA mA

VBE(V) VCE(V)

0 0

IB=60µA

IB=40µA

IB=20µA

IC

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TABULAR COLUMN:

INPUT CHARACTERISTICS:

VCE=1V VCE=2V

VBE(V) IB(A) VBE(V) IB(A)

OUTPUT CHARACTERISTICS:

IB=20µµµµA IB=40µµµµA

VCE(V) IC(mA) VCE(V) IC(mA)

RESULT:

The transistor characteristics of a Common Emitter (CE)

configuration were plotted

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Ex.No.2b

CHARACTERISTICS OF CB CONFIGURATION USING BJT

AIM:

To plot the transistor characteristics of CB configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 Transistor BC 107 1

2 Ammeter

(0–10)mA 1 2 Resistor 10kΩ

1KΩ

1

(0–1)A 1 3 Bread

Board

1

3 Voltmeter (0–30)V 1 4 Wires

(0–2)V 1

THEORY:

In this configuration the base is made common to both the input and out.

The emitter is given the input and the output is taken across the collector. The

current gain of this configuration is less than unity. The voltage gain of CB

configuration is high. Due to the high voltage gain, the power gain is also high. In

CB configuration, Base is common to both input and output. In CB configuration

the input characteristics relate IE and VEB for a constant VCB. Initially let VCB = 0

then the input junction is equivalent to a forward biased diode and the

characteristics resembles that of a diode. Where VCB = +VI (volts) due to early

effect IE increases and so the characteristics shifts to the left. The output

characteristics relate IC and VCB for a constant IE. Initially IC increases and then it

levels for a value IC = αIE. When IE is increased IC also increases proportionality.

Though increase in VCB causes an increase in α, since α is a fraction, it is

negligible and so IC remains a constant for all values of VCB once it levels off.

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(0-30)V

(0-1)mA

+ -

(0-30)mA

+ -

+

-

+

-

+

-(0-2)V (0-30)V (0-30)V

PIN DIAGRAM:

B

Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

E C

CIRCUIT DIAGRAM:

-

PROCEDURE:

INPUT CHARACTERISTICS:

It is the curve between emitter current IE and emitter-base voltage VBE at

constant collector-base voltage VCB.

9. Connect the circuit as per the circuit diagram.

10. Set VCE=5V, vary VBE in steps of 0.1V and note down the corresponding

IB. Repeat the above procedure for 10V, 15V.

11. Plot the graph VBE Vs IB for a constant VCE.

12. Find the h parameters.

OUTPUT CHARACTERISTICS:

It is the curve between collector current IC and collector-base voltage VCB at

constant emitter current IE.

9. Connect the circuit as per the circuit diagram.

10. Set IB=20µA, vary VCE in steps of 1V and note down the corresponding IC.

Repeat the above procedure for 40µA, 80µA, etc.

a10 KΩ

a

a

a

1KΩ

VEB

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11. Plot the graph VCE Vs IC for a constant IB.

12. Find the h parameters

TABULAR COLUMN:

INPUT CHARACTERISTICS:

S.No. VCB = V VCB = V VCB = V

VEB

(V)

IE

(µµµµA)

VEB

(V)

IE

(µµµµA)

VEB

(V)

IE

(µµµµA)

OUTPUT CHARACTERISTICS:

S.No. IE= mA IE= mA IE= mA

VCB

(V)

Ic

(mA)

VCB

(V)

Ic

(mA)

VCB

(V)

Ic

(mA)

MODEL GRAPH:

INPUT CHARACTERISTICS:

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IC

(mA)

VCB1

IE2

VCB2

IE1 VEB1 VEB2 VEB (V)

OUTPUT CHARACTERISTICS:

IC

(mA) IE3

IC2 IE2

IC1

IE1

VCB1 VCB2 VCB (V)

RESULT:

The transistor characteristics of a Common Base (CB) configuration were

plotted and uses studied.

Ex.No.2c

CHARACTERISTICS OF CC CONFIGURATION USING BJT

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AIM:

To plot the transistor characteristics of CE configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 Transistor BC 107 1

2 Ammeter

(0–30)mA 1 2 Resistor 1kΩ 2

(0–250)µA 1 3 Bread

Board

1

3 Voltmeter (0–30)V 1 4 Wires

(0–5)V 1

THEORY:

A BJT is a three terminal two – junction semiconductor device in which the

conduction is due to both the charge carrier. Hence it is a bipolar device and it

amplifier the sine waveform as they are transferred from input to output. BJT is

classified into two types – NPN or PNP. A NPN transistor consists of two N

types in between which a layer of P is sandwiched. The transistor consists of

three terminal emitter, collector and base. The emitter layer is the source of the

charge carriers and it is heartily doped with a moderate cross sectional area.

The collector collects the charge carries and hence moderate doping and large

cross sectional area. The base region acts a path for the movement of the

charge carriers. In order to reduce the recombination of holes and electrons the

base region is lightly doped and is of hollow cross sectional area. Normally the

transistor operates with the EB junction forward biased.

In transistor, the current is same in both junctions, which indicates that

there is a transfer of resistance between the two junctions. One to this fact the

transistor is known as transfer resistance of transistor.

PIN DIAGRAM:

B

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Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

+

-

-

+ -+ +

-

+

+ -

(0-30)mA

(0-250)µA

E C

CIRCUIT DIAGRAM:

PROCEDURE:

INPUT CHARECTERISTICS:

7. Connect the circuit as per the circuit diagram.

8. Set VCE, vary VBE in regular interval of steps and note down the

corresponding IB reading. Repeat the above procedure for different values

of VCE.

9. Plot the graph: VBC Vs IB for a constant VCE.

OUTPUT CHARECTERISTICS:

7. Connect the circuit as per the circuit diagram.

A

A V

V

1 KΩ

+

-

(0-30)V (0-30)V

(0-30)V (0-30)V

1 KΩ

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8. Set IB, Vary VCE in regular interval of steps and note down the

corresponding IC reading. Repeat the above procedure for different

values of IB.

9. Plot the graph: VCE Vs IC for a constant IB.

MODEL GRAPH:

INPUT CHARACTERISTICS: OUTPUT CHARACTERISTICS:

(µµµµA) (mA)

IB Ie

VCE=0 VCE=5V IB=60µµµµA

IB=40µµµµA

IB=20µµµµA

0 VBC(V) 0 VCE(V)

TABULAR COLUMN:

INPUT CHARACTERISTICS:

VCE=1V VCE=2V

VBC(V) IB(A) VBC(V) IB(A)

OUTPUT CHARACTERISTICS:

IB=20µµµµA IB=40µµµµA

VCE(V) IE(mA) VCE(V) IE(mA)

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RESULT:

The transistor characteristics of a Common Emitter (CC) configuration

were plotted.

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Ex.No.3

CHARACTERISTICS OF JUNCTION FIELD EFFECT TRANSISTOR

AIM:

To Plot the characteristics of given FET & determine rd, gm, µ, IDSS,VP.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 FET BFW10 1

2 Ammeter (0–30)mA 1 2 Resistor 1kΩ

68KΩ

1

1

3 Voltmeter (0–30)V 1 3

Bread

Board

1

(0-10)V 1 4 Wires

THEORY:

FET is a voltage operated device. It has got 3 terminals. They are Source,

Drain & Gate. When the gate is biased negative with respect to the source, the

pn junctions are reverse biased & depletion regions are formed. The channel is

more lightly doped than the p type gate, so the depletion regions penetrate

deeply in to the channel. The result is that the channel is narrowed, its resistance

is increased, & ID is reduced. When the negative bias voltage is further

increased, the depletion regions meet at the center & ID is cutoff completely.

PROCEDURE:

DRAIN CHARACTERISTICS:

11. Connect the circuit as per the circuit diagram.

12. Set the gate voltage VGS = 0V.

13. Vary VDS in steps of 1 V & note down the corresponding ID.

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+ (0-30)V

68KΩ

V

+

(0-30)V

(0-30)V

1k (0-30mA)

D G

S

BFW10

-

+ (0-10)V V

A

-

14. Repeat the same procedure for VGS = -1V.

15. Plot the graph VDS Vs ID for constant VGS.

OBSERVATIONS

7. d.c (static) drain resistance, rD = VDS/ID.

8. a.c (dynamic) drain resistance, rd = ∆∆∆∆VDS/∆∆∆∆ID.

9. Open source impedance, YOS = 1/ rd.

TRANSFER CHARACTERISTICS:

11. Connect the circuit as per the circuit diagram.

12. Set the drain voltage VDS = 5 V.

13. Vary the gate voltage VGS in steps of 1V & note down the corresponding ID.

14. Repeat the same procedure for VDS = 10V.

15. Plot the graph VGS Vs ID for constant VDS.

FET PARAMETER CALCULATION:

Drain Resistancd rd = GS

D

DS VI

V

Transconductance gm = DS

GS

D VV

I

Amplification factor =rd . gm

CIRCUIT DIAGRAM:

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I D (

mA

) PIN DIAGRAM:

BOTTOM VIEW OF BFW10:

SPECIFICATION:

Voltage : 30V, IDSS > 8mA.

MODEL GRAPH:

DRAIN CHARACTERISTICS:

TRANSFER CHARACTERISTICS:

ID(mA)

VDS =Const

VGS (V)

0

VGS = 0V

VGS = -1V

VGS = -2V

VGS = -3V

VDS (volts)

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TABULAR COLUMN:

DRAIN CHARACTERISTICS:

VGS = 0V VGS = -1V

VDS (V) ID(mA) VDS (V) ID(mA)

TRANSFER CHARACTERISTICS:

RESULT:

Thus the Drain & Transfer characteristics of given FET is Plotted.

Rd =

gm =

µ =

IDSS =

Pinch off voltage VP =

VDS =5volts VDS = 10volts

VGS (V) ID(mA) VGS (V) ID(mA)

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Ex.No.4

CHARACTERISTICS OF UNIJUNCTION TRANSISTOR

AIM:

To Plot the characteristics of UJT & determine it’s intrinsic standoff

Ratio.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 UJT 2N2646 1

2 Ammeter (0–30)mA 1

2 Resistor 1KΩ 2

3 Bread

Board

1

3 Voltmeter (0–30)V 1

(0–10)V 1

THEORY:

UJT(Double base diode) consists of a bar of lightly doped n-type silicon

with a small piece of heavily doped P type material joined to one side. It has got

three terminals. They are Emitter(E), Base1(B1),Base2(B2).Since the silicon bar

is lightly doped, it has a high resistance & can be represented as two resistors,

rB1 & rB2. When VB1B2 = 0, a small increase in VE forward biases the emitter

junction. The resultant plot of VE & I E is simply the characteristics of forward

biased diode with resistance. Increasing VEB1 reduces the emitter junction

reverse bias. When VEB1 = VrB1 there is no forward or reverse bias. & IE = 0.

Increasing VEB1 beyond this point begins to forward bias the emitter junction. At

the peak point, a small forward emitter current is flowing. This current is termed

as peak current( IP ). Until this point UJT is said to be operating in cutoff region.

When IE increases beyond peak current the device enters the negative

resistance region. In which the resistance rB1 falls rapidly & VE falls to the valley

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B2

E

voltage.Vv. At this point IE = Iv. A further increase of IE causes the device to

enter the saturation region.

PROCEDURE:

11. Connect the circuit as per the circuit diagram.

12. Set VB1B2 = 0V, vary VEB1 , & note down the readings of IE & VEB1

13. Set VB1B2 = 10V , vary VEB1 , & note down the readings of IE & VEB1

14. Plot the graph : IE Versus VEB1 for constant VB1B2.

15. Find the intrinsic standoff ratio.

CIRCUIT DIAGRAM:

PIN DIAGRAM:

BOTTOM VIEW OF 2N2646:

SPECIFICATION FOR 2N2646:

* Inter base resistance RBB = 4.7 to 9.1 KΩ

B2

(0-30)V (0-30)V

(0-30)V

1KΩ 1KΩ

(0-30)V

(0-30)mA

V V

A

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* Minimum Valley current = 4 mA

* Maximun Peak point emitter current 5 µA

*Maximum emitter reverse current 12 µA.

FORMULA FOR INTRINSIC STANDOFF RATIO:

η = VP - VD/ VB1B2., where VD = 0.7V.

MODEL GRAPH:

Peak point

VP

IP

Negative resistance region

VEB1(V)

Valley point VB1B2 = V

VB1B2 = 0V

IV IE (mA)

TABULAR COLUMN:

VB1B2 = 0V VB1B2 = 10V

VEB1 (V) IE (mA) VEB1 (V) IE (mA)

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PROCEDURE:

9. Give the circuit connections as per the circuit diagram.

10. The dc input voltage is set to 20 V in RPS.

11. The output sweep waveform is measured using CRO.

12. The graph of output sweep waveform is plotted

RESULT:

1. Thus the characteristics of given UJT was Plotted & its intrinsic standoff

Ratio = ----.

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Ex.No.5

CHARACTERISTICS OF PHOTO-DIODE AND

PHOTOTRANSISTOR

AIM:

1. To study the characteristics of a photo-diode.

2. To study the characteristics of phototransistor.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 R.P.S (0-30)V 1 1 Photo

diode 1

2 Ammeter (0–30)mA 1

2 Resistor 1KΩ 2

3 Bread

Board 1

3 Voltmeter (0–30)V 1 4 Photo

transistor 1

THEORY:

PHOTODIODE:

A photo diode is a two terminal pn junction device, which operates on

reverse bias. On reverse biasing a pn junction diode, there results a constant

current due to minority charge carriers known as reverse saturation current.

Increasing the thermally generated minority carriers by applying external energy,

i.e., either heat or light energy at the junction can increase this current. When we

apply light energy as an external source, it results in a photo diode that is usually

placed in a glass package so that light can reach the junction. Initially when no

light is incident, the current is only the reverse saturation current that flows

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(0-30)mA

(0-30)V (0-30)V

through the reverse biased diode. This current is termed as the dark current of

the photo diode. Now when light is incident on the photo diode then the thermally

generated carriers increase resulting in an increased reverse current which is

proportional to the intensity of incident light. A photo diode can turn on and off at

a faster rate and so it is used as a fast acting switch.

CIRCUIT DIAGRAM:

TABULAR COLUMN:

MODEL GRAPH:

S.No. VOLTAGE

(In Volts)

CURRENT

(In mA)

R

(KΩ)

Illumination lm/m2

1KΩ a

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THEORY:

PHOTOTRANSISTOR:

It is a transistor with an open base; there exists a small collector current

consisting of thermally produced minority carriers and surface leakage. By

exposing the collector junction to light, a manufacturer can produce a

phototransistor, a transistor that has more sensitivity to light than a photo diode.

Because the base lead is open, all the reverse current is forced into the base of

the transistor. The resulting collector current is ICeo = βdcIr. The main difference

between a phototransistor and a photodiode is the current gain, βdc. The same

amount of light striking both devices produces βdc times more current in a

phototransistor than in a photodiode.

CIRCUIT DIAGRAM:

TABULAR COLUMN: SYMBOL:

E

S. No. VCE

(in Volts)

IC

(in mA)

N P N

1KΩ

(0-30V)

C

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IC

400 Lux

200 Lux

0 Lux

VCE(V)

MODEL GRAPH:

PROCEDURE:

PHOTO DIODE:

11. Rig up the circuit as per the circuit diagram.

12. Maintain a known distance (say 5 cm) between the DC bulb and

the photo diode.

13. Set the voltage of the bulb (say, 2V), vary the voltage of the diode

insteps of 1V and note down the corresponding diode current, Ir.

14. Repeat the above procedure for the various voltages of DC bulb.

15. Plot the graph: VD vs. Ir for a constant DC bulb voltage.

PHOTOTRANSISTOR:

11. Rig up the circuit as per the circuit diagram.

12. Maintain a known distance (say 5 cm) between the DC bulb and the

phototransistor.

13. Set the voltage of the bulb (say, 2V), vary the voltage of the diode

in steps of 1V and note down the corresponding diode current, Ir.

14. Repeat the above procedure for the various values of DC bulb.

15. Plot the graph: VD vs. Ir for a constant bulb voltage.

RESULT:

Thus the characteristics of photo diode and phototransistor are studied.

(mA)

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Ex.No.6

CHARACTERISTICS OF THERMISTOR

AIM:

To study the characteristics of Thermistor.

THEORY:

Thermistor or Thermal resistor is two – terminal semiconductor device

whose resistance is temperature sensitive. The value of such resistors decreases

with increase in temperature. Materials employed in the manufacture of the

thermistors include oxides of cobalt, nickel, copper, iron uranium and

manganese.

The thermistors has very high temperature coefficient of resistance, of the

order of 3 to 5% per °C, making it an ideal temperature transducer. The

temperature coefficient of resistance is normally negative. The reistance at any

temperature T, is given approximately by

RT = Ro exp β (1/T – 1/To)

Where RT = thermistor resistance at temperature T (K), RO = thersmistor

resistance at temperature To (K), and β = a constant determined by calibration.

At high temperatures, this equation reduces to

RT = Ro exp ( β/T)

The resistance – temperature characteristics is shown in Fig 21.10. The

curve is non – linear and the drop in resistance from 5000 to 10Ω occurs for an

increase in temperature from 20 to 100 °C. The temperature of the device can

be changed internally or externally. An increase in current through the device will

raise its temperature carrying a drop in its terminal resistance. Any externally

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heat source will result in an increase in its body temperature and drop in

resistance this type action (internal or external) lends itself well to control

mechanism.

Three useful parameters for characterizing the thermistor are the time

constant, dissipation constant , and resistance ratio. The time constant is the

time for a thermistor to change its resistance by 63% of its initial value, for zero –

power dissipation. Typical values of time constant range from 1 to 50 s.

SYMBOL:

MODEL GRAPH:

The dissipation factor is the power necessary to increase the temperature

of a thermistor by 1˚C. Typical values of dissipation factor range from 1 to 10

mW/˚C.

Resistance ratio is the ratio of the resistance at 25 ˚C. Its range is

approximately

R

(Ω-cm)

T (deg)

T

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3 – 60.

Thermistors are used measure temperature, flow pressure, liquid level,

voltage or power level, vacuum, composition of gases and thermal conductivity

and also in compensation network.

RESULT:

Thus the Characteristics of thermistor was studied.

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Ex.No.7a

SINGLE PHASE HALF WAVE RECTIFIER

AIM:

To construct a Half wave rectifier using diode and to draw its performance

characteristics.

APPARATUS REQUIRED: COMPONENTS

REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 Transformer 230/(6-0-6)V 1 1

Diode IN4001 1

2 R.P.S (0-30)V 2

3 Ammeter

(0–30)mA 1 2 Resistor 1K Ω 1

(0–250)µA 1 3 Bread

Board

1

4 Voltmeter (0–30)V 1 4 Capacitor 100µf 1

(0–2)V 1 5 CRO 1

FORMULAE:

WITHOUT FILTER:

(i) Vrms = Vm / √2

(ii) Vdc = Vm / ∏

(iii) Ripple Factor = √ (Vrms / Vdc)2 – 1

(iv) Efficiency = (Vdc / Vrms)2 x 100

WITH FILTER:

(i) Vrms = √ (Vrms’2 + Vdc

2)

(ii) Vrms’ = Vrpp / (√3 x 2)

(iii) Vdc = Vm – V rpp / 2

(iv) Ripple Factor = Vrms’/ Vdc

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PROCEDURE:

WITHOUT FILTER:

9. Give the connections as per the circuit diagram.

10. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

11. Take the rectifier output across the Load.

12. Plot its performance graph.

WITH FILTER:

1. Give the connections as per the circuit diagram.

10. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

11. Connect the Capacitor across the Load.

12. Take the rectifier output across the Load.

13. Plot its performance graph.

CIRCUIT DIAGRAM:

1φ Transformer

230 V / 6V 1N 4007

1K 100µF 1φ, 230V,

50Hz

AC supply

CRO

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TABULAR COLUMN:

WITHOUT FILTER:

Vm Vrms Vdc Ripple factor Efficiency

WITH FILTER:

Vrms Vrpp Vdc Ripple factor Efficiency

MODEL GRAPH:

RESULT:

Thus the performance characteristics of 1φ Half wave rectifier was obtained.

Vin

(Volts)

t (ms)

Vo

(Volts)

t (ms)

t (ms)

Vo

(Volts)

Without Filter

With Filter

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Ex.No.7b

SINGLE PHASE FULL WAVE RECTIFIER

AIM:

To construct a Full wave rectifier using diode and to draw its performance

characteristics.

APPARATUS REQUIRED: COMPONENTS

REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 Transformer 230/(6-0-6)V 1 1

Diode IN4001 2

2 R.P.S (0-30)V 2

3 Ammeter

(0–30)mA 1 2 Resistor 1K Ω 1

(0–250)µA 1 3 Bread

Board

1

4 Voltmeter (0–30)V 1 4 Capacitor 100µf 1

(0–2)V 1 5 CRO 1

FORMULAE:

WITHOUT FILTER:

(i) Vrms = Vm / √2

(ii) Vdc = 2Vm / ∏

(iii) Ripple Factor = √ (Vrms / Vdc)2 – 1

(iv) Efficiency = (Vdc / Vrms)2 x 100

WITH FILTER:

(i) Vrms = Vrpp /(2*√ 3)

(ii) Vdc = Vm – V rpp

(iv) Ripple Factor = Vrms’/ Vdc

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PROCEDURE:

WITHOUT FILTER:

9. Give the connections as per the circuit diagram.

10. Give 230v, 50HZ I/P to the step down TFR where secondary connected

to the Rectifier I/P.

11. Take the rectifier output across the Load.

12. Plot its performance graph.

WITH FILTER:

1. Give the connections as per the circuit diagram.

10. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

11. Connect the Capacitor across the Load.

12. Take the rectifier output across the Load.

13. Plot its performance graph.

CIRCUIT DIAGRAM:

1N 4007

1K 100µF

1φ, 230V,

50Hz

AC supply

CRO

1N 4007

1φ Transformer

230 V / 6V

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TABULAR COLUMN:

WITHOUT FILTER:

Vm Vrms Vdc Ripple factor Efficiency

WITH FILTER:

Vrms Vrpp Vdc Ripple factor Efficiency

MODEL GRAPH :

RESULT: Thus the performance characteristics of 1φ Full wave rectifier were

obtained.

Vin

(Volts)

t (ms)

Vo

(Volts)

t (ms)

t (ms)

Vo

(Volts)

Without Filter

With Filter

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Ex.No.8

DIFFERENTIAL AMPLIFIER

AIM:

To construct a Differential amplifier in Common mode & Differential mode

configuration and to find common mode rejection ratio.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

Apparatus Range Qty

1 RPS (0-30)V 1

2 CRO 1

3 Signal

Generator 1

4 DCB 2

5 DRB 2

THEORY:

The Differential amplifier circuit is an extremely popular connection used in

IC units. The circuit has separate inputs , two separate outputs and emitters are

connected together. If the same input is applied to both inputs, the operation is

called common mode. In double ended operation two input signals are applied ,

the difference of the inputs resulting in outputs from both collectors due to the

difference of the signals applied to both the inputs. The main feature of the

differential amplifier is the very large gain when opposite signals are applied to

inputs as compared to small signal resulting from common input. The ratio of this

difference gain to the common gain is called common mode rejection ratio.

S.No Item Type Range Qty

1 Transistor BC107 1

2 Capacitor 470µF 1

3 Resistor 3.9K

3.3K

1

1

4 Bread board 1

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CIRCUIT DIAGRAM:

DIFFERENTIAL MODE:

COMMON MODE:

3.3 KΩ

3.9KΩ

Vo1 Vo2

V1

12V V2

13V

3.9KΩ

-9V

9V

3.3 KΩ

3.9KΩ

Vo1 Vo2

V2

13V

3.9KΩ

-9V

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PROCEDURE:

DIFFERENTIAL MODE:

9. Connect the circuit as per the circuit diagram.

10. Set V1 = 50mv and V2 =55mv using the signal generator.

11. Find the corresponding output voltages across V01 & V02 using CRO

12. Calculate common mode rejection ratio using the given formula.

COMMON MODE:

9. Connect the circuit as per the circuit diagram.

10. Set V1 = 50mv using the signal generator.

11. Find the output voltage across Vo using multimeter.

12. Calculte common mode rejection ratio using the given formula.

CALCULATION:

Common mode rejection ratio(CMRR) = Ad / Ac

Ad = Differential mode gain

Ac = Common mode gain

Where Ad = Vo /Vd

Vo = Output voltage measured across CRO

Vd = V 1 – V2 , V 1 , V2 – input voltage applied.

Ac = Vo /Vc

Vc = (V 1 + V2 )/2

DIFFERENTIAL MODE:

V1 =

V2 =

Output voltage =

Vd= V1-V2 =

Ad=Vo/Vd =

RESULT: Thus the differential amplifier was constructed in common mode

and Differential mode configuration. Further common mode rejection ratio was

found

Exp. No: 12

COMMON MODE:

Input voltage =

Output voltage =

V1=V2 =

Vc=(V1+V2)/2 =

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PASSIVE FILTERS

Aim:

To attenuate unwanted frequency components from input signal by using resistor

and capacitor.

Apparatus required:

S.No Name of the apparatus Range Type Quantity

1. Signal Generator 01

2. Resistor 01

3. Capacitor Ceramic 01

4. CRO 01

5. Breadboard 01

Theory:

A filter is an AC circuit that separates some frequencies from other in

within mixed – frequency signals. Audio equalizers and crossover networks are

two well-known applications of filter circuits. A Bode plot is a graph plotting

waveform amplitude or phase on one axis and frequency on the other.

A low-pass filter allows for easy passage of low-frequency signals from

source to load, and difficult passage of high-frequency signals. Capacitor low-pass

filters insert a resistor in series and a capacitor in parallel with the load as shown

in the circuit diagram. The former filter design tries to “block” the unwanted

frequency signal while the latter tries to short it out.

The cutoff frequency for a low-pass filter is that frequency at which the

output (load) voltage equals 70.7% of the input (Source) voltage. Above the cutoff

frequency, the output voltage is lower than 70.7% of the input, and vice-versa. See

the circuit diagram

1

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Fcutoff = ----------

2πRC

A high-pass filter allows for easy passage of high-frequency signals from source to

load, and difficult passage of low-frequency signals. Capacitor high-pass filters

insert a capacitor in series with the load as shown in the circuit diagram. The

former filter design tries to “brick” the unwanted frequency signal while the latter

tries to short it out.

The cutoff frequency for a high-pass filter is that frequency at which the

output (load) voltage equals 70.7% of the input (source) voltage. Above the cutoff

frequency, the output voltage is greater than 70.7% of the input, and vice-versa.

1

Fcutoff = ----------

2πRC

A band – pass filter works to screen out frequencies that are too low or too

high, giving easy passage only to frequencies within a certain range. Stacking a

low-pass filter on the end of a high-pass filter, or vice-versa can make band-pass

filters. Refer the circuit diagrams

Fig. 7.6

“Attenuate” means to reduce or diminish in amplitude. When you

turn down the volume control on your stereo, you are “attenuating” the signal

being sent to the speakers.

A band-stop filter works to screen out frequencies that are within a certain

range, giving easy passage only to frequencies outside of that range. Also known

as band-elimination, band-reject, or notch filters.

Signal

input

Low-pass filter High-pass filter Signal

output Blocks frequencies

that are too high

Blocks frequencies

that are too low

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Signal

Input

Low-pass filter

High-pass filter

Signal

Output

Placing a low-pass filter in parallel with a high-pass filter can make band-

stop filters. Commonly, both the low-pass and high-pass filter sections are of the

“T” configuration giving the name “Twin-T” to the band-stop combination. Refer

the fig.7.7, 7.8a and 7.8b.

Passes low frequencies

Passes high frequencies

Fig. 7.8a

The frequency of maximum attenuation is called the notch

frequency.

Procedure:

13. Give the connections as per circuit diagrams.

14. Switch on the main.

15. Change the frequency from minimum and find the output

voltage by using CRO.

16. Draw the graph.

17. Verify the cut off frequency.

18. Switch off the main.

Result:

Thus we analyze passive filter and various waveforms are noted

Exp. No : 10

STUDY OF CRO AND

POWER FACTOR MEASUREMENT USING CRO

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Aim:

To study cathode Ray Oscilloscope (CRO) and measurement of power factor using

CRO.

Apparatus required:

S.No Name of the apparatus Range Type Quantity

1. Resistance Box 1

2. Capacitance Box 1

3. Inductance Box 1

4. Function Generator 1

5. Bread board 1

Theory:

The cathode ray oscilloscope is the most versatile measuring instrument

available. We can measure following parameters using the CRO:

9. AC or DC voltage.

10. Time (t=1/f).

11. Phase relationship

12. Waveform calculation: Rise time; fall time; on time; off-time

Distortion, etc.

We can also measure non-electrical physical quantities like pressure, strain,

temperature, acceleration, etc., by converting into electrical quantities using

a transducer.

Major blocks:

13. Cathode ray tube (CRT)

14. Vertical amplifier

15. Horizontal amplifier

16. Sweep generator

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17. Trigger circuit

18. Associated power supply.

11. The cathode ray tube is the heart of CRO. The CRT is enclosed in an

evacuated glass envelope to permit the electron beam to traverse in the

tube easily. The main functional units of CRO are as follows.

Electron gun assembly

Deflection plate unit

Screen.

12. Vertical Amplifier is the main factor in determining the bandwidth and

sensitivity of an oscilloscope. Vertical sensitivity is a measure of how

much the electron beam will be deflected for a specified input signal.

On the front panel of the oscilloscope, one can see a knob attached to a

rotary switch labeled volts/division. The rotary switch is electrically

connected to the input attenuation network. The setting of the rotary

switch indicates what amplitude signal is required to deflect the beam

vertically by one division.

13. Horizontal amplifier Under normal mode of operation, the horizontal

amplifier will amplify the sweep generator input. When the CRO is

being used in the X-Y mode, the horizontal amplifier will amplify the

signal applied to the horizontal input terminal. Although the vertical

amplifier mush be able to faithfully reproduce low-amplitude and high

frequency signal with fast rise-time, the horizontal amplifier is only

required to provide a faithful reproduction of the sweep signal which

has a relatively high amplitude and slow rise time.

14. Sweep generator and Trigger circuit These two units form the Signal

Synchronization unit of the CRO.

15. Associated Power Supply: The input signal may come from an

external source when the trigger selector switch is set to EXT or from

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low amplitude AC voltage at line frequency when the switch is set to

LINE or from the vertical amplifier when the switch is set to INT. When

set for INT (internal triggering), the trigger circuit receives its inputs

from the vertical amplifier.

Major Blocks in a Practical CRO

A CRO consists of a cathode ray tube (CRT) and additional control knobs.

The main parts of a CRT are:

7. Electron gun assembly.

8. Deflection plate assembly.

9. Fluorescent screen.

Electron Gun Assembly: The electron gun assembly produces a sharp beam of

electrons, which are accelerated to high velocity. This focused beam of electrons

strike the fluorescent screen with sufficient energy to cause a luminous spot on the

screen.

Deflection plate assembly: This part consists of two plates in which one pair of

plates is placed horizontally and other of plates is placed vertically. The signal

under test is applied to vertical deflecting plates. The horizontal deflection plates

are connected to a built-in ramp generator, which moves the luminous spot

periodically in a horizontal direction from left to right over the screen. These two

deflection plates give stationary appearance to the waveform on the screen. CRO

operates on voltage. Since the deflection of the electron beam is directly

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proportional to the deflecting voltage, the CRT may be used as a linear measuring

device. The voltage being measured is applied to the vertical plates through an

iterative network, whose propagation time corresponds to the velocity of electrons,

thereby synchronizing the voltage applied to the vertical plate with the velocity of

the beam.

Synchronization of input signal: The sweep generator produces a saw tooth

waveform, which is used to synchronize the applied voltage to obtain a stationary-

applied signal. This requires that the time base be operated at a submultiples

frequency of the signal under measurement. If synchronization is not done, the

pattern is not stationary, but appears to drift across the screen in a random fashion.

Internal synchronization This trigger is obtained from the time base generator to

synchronize the signal.

External synchronization An external trigger source can also be used to

synchronize the signal being measured.

Auto Triggering Mode The time base used in this case in a self-oscillating

condition, i.e., it gives an output even in the absence of any Y-input. The

advantage of this mode is that the beam is visible on the screen under all

conditions, including the zero input. When the input exceeds a certain magnitude

then the internal free running oscillator locks on to the frequency.

Precautions:

5. The ammeter is connected using thick wires.

6. While reversing ammeter polarity, see to it that the capacitor is not

discharged.

Observation:

Sl.No Time Voltage Current

Unit (Sec) (Volts) (Amps)

Result: Thus we study about CRO & to measure p.f

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CLASS : II YEAR/ III SEMSESTER

SUBJECT CODE : 131351

SUBJECT : ELECTRON DEVICES AND CIRCUITS LAB

BATCH : B2

STAFF IN-CHARGE: Mrs. A. SANGARI

DESIGNATION : SENIOR LECTURER

STAFF CODE : EE52

LIST OF EXPERIMENTS

131351 ELECTRON DEVICES AND CIRCUITS LABORATORY L T P C (B.E. (EEE), B.E. (E&I) and B.E. (I & C) 0 0 3 2 (Revised)

37. Characteristics of semiconductor diode and zener diode .

38. Characteristics of transistor under CE, CB and CC .

39. Characteristics of FET .

40. Characteristics of UJT .

41. Characteristics of SCR, DIAC and TRIAC.

42. Photodiode, Phototransistor characteristics and study of light

activated relay circuit.

43. Static characteristics of Thermistors.

44. Single phase half wave and full wave rectifiers with inductive and

capacitive filters.

45. Differential amplifiers using FET.

46. Study of CRO.

47. Series and parallel resonance circuits.

48. Realization of passive filters.

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Ex.No.1a

CHARACTERISTICS OF PN JUNCTION DIODE

AIM:

To study the PN junction diode characteristics under Forward & Reverse

bias conditions.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 Diode

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A PN junction diode is a two terminal junction device. It conducts only in

one direction (only on forward biasing).

FORWARD BIAS:

On forward biasing, initially no current flows due to barrier potential. As the

applied potential exceeds the barrier potential the charge carriers gain sufficient

energy to cross the potential barrier and hence enter the other region. The holes,

which are majority carriers in the P-region, become minority carriers on entering

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the N-regions, and electrons, which are the majority carriers in the N-region,

become minority carriers on entering the P-region. This injection of Minority

carriers results in the current flow, opposite to the direction of electron

movement.

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REVERSE BIAS:

On reverse biasing, the majority charge carriers are attracted towards the

terminals due to the applied potential resulting in the widening of the depletion

region. Since the charge carriers are pushed towards the terminals no current

flows in the device due to majority charge carriers. There will be some current in

the device due to the thermally generated minority carriers. The generation of

such carriers is independent of the applied potential and hence the current is

constant for all increasing reverse potential. This current is referred to as

Reverse Saturation Current (IO) and it increases with temperature. When the

applied reverse voltage is increased beyond the certain limit, it results in

breakdown. During breakdown, the diode current increases tremendously.

PROCEDURE:

FORWARD BIAS:

13. Connect the circuit as per the diagram.

14. Vary the applied voltage V in steps of 0.1V.

15. Note down the corresponding Ammeter readings I.

16. Plot a graph between V & I

OBSERVATIONS

10. Find the d.c (static) resistance = V/I.

11. Find the a.c (dynamic) resistance r = δV / δI (r = ∆∆∆∆V/∆∆∆∆I) = 12

12

II

VV

−.

12. Find the forward voltage drop = [Hint: it is equal to 0.7 for Si and 0.3 for

Ge]

REVERSE BIAS:

16. Connect the circuit as per the diagram.

17. Vary the applied voltage V in steps of 1.0V.

18. Note down the corresponding Ammeter readings I.

19. Plot a graph between V & I

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(0-100)mA, MC

+ -

+

-

(0-15)V, MC +

-

(0-10)V

RPS

(0-500)µA,MC

+ -

+

-

(0-30)V, MC +

-

(0-30)V

RPS

20. Find the dynamic resistance r = δδδδV / δδδδI.

FORMULA FOR REVERSE SATURATION CURRENT (IO):

Io = ∂∂∂∂I/[exp(∂∂∂∂V/ηηηηVT)]-1

Where VT is the voltage equivalent of Temperature = kT/q

-k is Boltzmann’s constant, q is the charge of the electron and T is the

temperature in degrees Kelvin.

η =1 for Silicon and 2 for Germanium

CIRCUIT DIAGRAM:

FORWARD BIAS:

REVERSE BIAS:

470 Ω a

470 Ω a

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Specification for 1N4001: Silicon Diode

Peak Inverse Voltage: 50V

Idc = 1A.

Maximum forward voltage drop at 1 Amp is 1.1 volts

Maximum reverse current @50 volts is 5µA

TABULAR COLUMN:

FORWARD BIAS: REVERSE BIAS:

MODEL GRAPH

If (mA)

I2

Vb I1

( Volts) V1 V2 Vf

(Volts)

Ir (µA)

S.No. VOLTAGE

(In Volts)

CURRENT

(In mA)

S..No. VOLTAGE

(In Volts)

CURRENT

(In µµµµA)

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RESULT:

Forward and Reverse bias characteristics of the PN junction diode and the

dynamic resistance under

i) Forward bias = ---------------------

ii) Reverse bias = ----------------------.

iii) Reverse Saturation Current = ----------------.

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Ex.No.1b

CHARACTERISTICS OF ZENER DIODE

AIM:

To determine the breakdown voltage of a given zener diode.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 zener

diode

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A properly doped crystal diode, which has a sharp breakdown voltage, is known

as zener diode.

FORWARD BIAS:

On forward biasing, initially no current flows due to barrier potential. As the

applied potential increases, it exceeds the barrier potential at one value and the

charge carriers gain sufficient energy to cross the potential barrier and enter the

other region. the holes ,which are majority carriers in p-region, become minority

carriers on entering the N-regions and electrons, which are the majority carriers

in the N-regions become minority carriers on entering the P-region. This injection

of minority carriers results current, opposite to the direction of electron

movement.

REVERSE BIAS:

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When the reverse bias is applied due to majority carriers small amount of

current (ie) reverse saturation current flows across the junction. As the reverse

bias is increased to breakdown voltage, sudden rise in current takes place due to

zener effect.

ZENER EFFECT:

Normally, PN junction of Zener Diode is heavily doped. Due to heavy

doping the depletion layer will be narrow. When the reverse bias is increased the

potential across the depletion layer is more. This exerts a force on the electrons

in the outermost shell. Because of this force the electrons are pulled away from

the parent nuclei and become free electrons. This ionization, which occurs due to

electrostatic force of attraction, is known as Zener effect. It results in large

number of free carriers, which in turn increases the reverse saturation current

PROCEDURE:

FORWARD BIAS:

1. Connect the circuit as per the circuit diagram.

2. Vary the power supply in such a way that the readings are taken in steps

of 0.1V in the voltmeter till the needle of power supply shows 30V.

3. Note down the corresponding ammeter readings.

4. Plot the graph :V (vs) I.

5. Find the dynamic resistance r = δδδδV / δδδδI.

REVERSE BIAS:

19. Connect the circuit as per the diagram.

20. Vary the power supply in such a way that the readings are taken in steps

of 0.1V in the voltmeter till the needle of power supply shows 30V.

21. Note down the corresponding Ammeter readings I.

22. Plot a graph between V & I

23. Find the dynamic resistance r = δδδδV / δδδδI.

24. Find the reverse voltage Vr at Iz=20 mA.

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(0-15) V

+ -

+

-

+

-

(0-10) V

(0-10) V, MC

+ -

+

-

+

-

(0-30) V

CIRCUIT DIAGRAM:

FORWARD BIAS:

REVERSE BIAS:

1

470 Ω

aaaaa

(0-10)mA

1

1KΩ

aaaaa

(0-500)A, MC

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ZENER DIODE:

If ( mA)

I2

VB I1

Vr V1 V2 Vf

(V) (V)

Ir (A)

TABULAR COLUMN:

FORWARD BIAS: REVERSE BIAS:

RESULT:

Forward and Reverse bias characteristics of the zener diode was studied

and

Forward bias dynamic resistance = ---------------------

Reverse bias dynamic resistance = ----------------------

The reverse voltage at Iz =20 mA determined from the reverse

characteristics of the Zener diode is --------------------------.

S..No. VOLTAGE

(In Volts)

CURRENT

(In mA)

S.No. VOLTAGE

(In Volts)

CURRENT

(In µµµµA)

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Ex. No. 2a

CHARACTERISTICS OF CE CONFIGURATION USING BJT

AIM:

To plot the transistor characteristics of CE configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S 1 Transistor

2 Ammeter

2 Resistor

3 Bread

Board

3 Voltmeter 4 Wires

THEORY:

A BJT is a three terminal two – junction semiconductor device in which the

conduction is due to both the charge carrier. Hence it is a bipolar device and it

amplifier the sine waveform as they are transferred from input to output. BJT is

classified into two types – NPN or PNP. A NPN transistor consists of two N

types in between which a layer of P is sandwiched. The transistor consists of

three terminal emitter, collector and base. The emitter layer is the source of the

charge carriers and it is heartily doped with a moderate cross sectional area.

The collector collects the charge carries and hence moderate doping and large

cross sectional area. The base region acts a path for the movement of the

charge carriers. In order to reduce the recombination of holes and electrons the

base region is lightly doped and is of hollow cross sectional area. Normally the

transistor operates with the EB junction forward biased.

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Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

In transistor, the current is same in both junctions, which indicates that

there is a transfer of resistance between the two junctions. One to this fact the

transistor is known as transfer resistance of transistor.

PROCEDURE:

INPUT CHARACTERISTICS:

10. Connect the circuit as per the circuit diagram.

11. Set VCE, vary VBE in regular interval of steps and note down the

corresponding IB reading. Repeat the above procedure for different values of

VCE.

12. Plot the graph: VBE Vs IB for a constant VCE.

OUTPUT CHARACTERISTICS:

10. Connect the circuit as per the circuit diagram.

11. Set IB, Vary VCE in regular interval of steps and note down the

corresponding IC reading. Repeat the above procedure for different

values of IB.

12. Plot the graph: VCE Vs IC for a constant IB.

PIN DIAGRAM:

B

E C

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(0 – 250) µA

10 KΩ

(0 – 30)mA

- + 1 KΩ

BC107

+

-

+

-(0-30)V

+

-

+

-

+ -

(0-30)V

(0-30)V

(0-1)V

CIRCUIT DIAGRAM:

MODEL GRAPH:

INPUT CHARACTERISTICS: OUTPUT CHARACTERISTICS:

A

A

V

V

C

E

B

VCE = 0V

VCE = 5V

IB

µA mA

VBE(V) VCE(V)

0 0

IB=60µA

IB=40µA

IB=20µA

IC

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TABULAR COLUMN:

INPUT CHARACTERISTICS:

VCE=1V VCE=2V

VBE(V) IB(A) VBE(V) IB(A)

OUTPUT CHARACTERISTICS:

IB=20µµµµA IB=40µµµµA

VCE(V) IC(mA) VCE(V) IC(mA)

RESULT:

The transistor characteristics of a Common Emitter (CE)

configuration were plotted

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Ex.No.2b

CHARACTERISTICS OF CB CONFIGURATION USING BJT

AIM:

To plot the transistor characteristics of CB configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 Transistor BC 107 1

2 Ammeter

(0–10)mA 1 2 Resistor 10kΩ

1KΩ

1

(0–1)A 1 3 Bread

Board

1

3 Voltmeter (0–30)V 1 4 Wires

(0–2)V 1

THEORY:

In this configuration the base is made common to both the input and out.

The emitter is given the input and the output is taken across the collector. The

current gain of this configuration is less than unity. The voltage gain of CB

configuration is high. Due to the high voltage gain, the power gain is also high. In

CB configuration, Base is common to both input and output. In CB configuration

the input characteristics relate IE and VEB for a constant VCB. Initially let VCB = 0

then the input junction is equivalent to a forward biased diode and the

characteristics resembles that of a diode. Where VCB = +VI (volts) due to early

effect IE increases and so the characteristics shifts to the left. The output

characteristics relate IC and VCB for a constant IE. Initially IC increases and then it

levels for a value IC = αIE. When IE is increased IC also increases proportionality.

Though increase in VCB causes an increase in α, since α is a fraction, it is

negligible and so IC remains a constant for all values of VCB once it levels off.

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(0-30)V

(0-1)mA

+ -

(0-30)mA

+ -

+

-

+

-

+

-(0-2)V (0-30)V (0-30)V

PIN DIAGRAM:

B

Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

E C

CIRCUIT DIAGRAM:

-

PROCEDURE:

INPUT CHARACTERISTICS:

It is the curve between emitter current IE and emitter-base voltage VBE at

constant collector-base voltage VCB.

13. Connect the circuit as per the circuit diagram.

14. Set VCE=5V, vary VBE in steps of 0.1V and note down the corresponding

IB. Repeat the above procedure for 10V, 15V.

15. Plot the graph VBE Vs IB for a constant VCE.

16. Find the h parameters.

OUTPUT CHARACTERISTICS:

It is the curve between collector current IC and collector-base voltage VCB at

constant emitter current IE.

13. Connect the circuit as per the circuit diagram.

14. Set IB=20µA, vary VCE in steps of 1V and note down the corresponding IC.

Repeat the above procedure for 40µA, 80µA, etc.

a10 KΩ

a

a

a

1KΩ

VEB

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15. Plot the graph VCE Vs IC for a constant IB.

16. Find the h parameters

TABULAR COLUMN:

INPUT CHARACTERISTICS:

S.No. VCB = V VCB = V VCB = V

VEB

(V)

IE

(µµµµA)

VEB

(V)

IE

(µµµµA)

VEB

(V)

IE

(µµµµA)

OUTPUT CHARACTERISTICS:

S.No. IE= mA IE= mA IE= mA

VCB

(V)

Ic

(mA)

VCB

(V)

Ic

(mA)

VCB

(V)

Ic

(mA)

MODEL GRAPH:

INPUT CHARACTERISTICS:

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IC

(mA)

VCB1

IE2

VCB2

IE1 VEB1 VEB2 VEB (V)

OUTPUT CHARACTERISTICS:

IC

(mA) IE3

IC2 IE2

IC1

IE1

VCB1 VCB2 VCB (V)

RESULT:

The transistor characteristics of a Common Base (CB) configuration were

plotted and uses studied.

Ex.No.2c

CHARACTERISTICS OF CC CONFIGURATION USING BJT

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AIM:

To plot the transistor characteristics of CE configuration.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 Transistor BC 107 1

2 Ammeter

(0–30)mA 1 2 Resistor 1kΩ 2

(0–250)µA 1 3 Bread

Board

1

3 Voltmeter (0–30)V 1 4 Wires

(0–5)V 1

THEORY:

A BJT is a three terminal two – junction semiconductor device in which the

conduction is due to both the charge carrier. Hence it is a bipolar device and it

amplifier the sine waveform as they are transferred from input to output. BJT is

classified into two types – NPN or PNP. A NPN transistor consists of two N

types in between which a layer of P is sandwiched. The transistor consists of

three terminal emitter, collector and base. The emitter layer is the source of the

charge carriers and it is heartily doped with a moderate cross sectional area.

The collector collects the charge carries and hence moderate doping and large

cross sectional area. The base region acts a path for the movement of the

charge carriers. In order to reduce the recombination of holes and electrons the

base region is lightly doped and is of hollow cross sectional area. Normally the

transistor operates with the EB junction forward biased.

In transistor, the current is same in both junctions, which indicates that

there is a transfer of resistance between the two junctions. One to this fact the

transistor is known as transfer resistance of transistor.

PIN DIAGRAM:

B

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Bottom View BC107 Specification: BC107/50V/0.1A,0.3W,300MHz

+

-

-

+ -+ +

-

+

+ -

(0-30)mA

(0-250)µA

E C

CIRCUIT DIAGRAM:

PROCEDURE:

INPUT CHARECTERISTICS:

10. Connect the circuit as per the circuit diagram.

11. Set VCE, vary VBE in regular interval of steps and note down the

corresponding IB reading. Repeat the above procedure for different values

of VCE.

12. Plot the graph: VBC Vs IB for a constant VCE.

OUTPUT CHARECTERISTICS:

10. Connect the circuit as per the circuit diagram.

A

A V

V

1 KΩ

+

-

(0-30)V (0-30)V

(0-30)V (0-30)V

1 KΩ

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11. Set IB, Vary VCE in regular interval of steps and note down the

corresponding IC reading. Repeat the above procedure for different

values of IB.

12. Plot the graph: VCE Vs IC for a constant IB.

MODEL GRAPH:

INPUT CHARACTERISTICS: OUTPUT CHARACTERISTICS:

(µµµµA) (mA)

IB Ie

VCE=0 VCE=5V IB=60µµµµA

IB=40µµµµA

IB=20µµµµA

0 VBC(V) 0 VCE(V)

TABULAR COLUMN:

INPUT CHARACTERISTICS:

VCE=1V VCE=2V

VBC(V) IB(A) VBC(V) IB(A)

OUTPUT CHARACTERISTICS:

IB=20µµµµA IB=40µµµµA

VCE(V) IE(mA) VCE(V) IE(mA)

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RESULT:

The transistor characteristics of a Common Emitter (CC) configuration

were plotted.

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Ex.No.3

CHARACTERISTICS OF JUNCTION FIELD EFFECT TRANSISTOR

AIM:

To Plot the characteristics of given FET & determine rd, gm, µ, IDSS,VP.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.No. Name Range Type Qty

S.No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 FET BFW10 1

2 Ammeter (0–30)mA 1 2 Resistor 1kΩ

68KΩ

1

1

3 Voltmeter (0–30)V 1 3

Bread

Board

1

(0-10)V 1 4 Wires

THEORY:

FET is a voltage operated device. It has got 3 terminals. They are Source,

Drain & Gate. When the gate is biased negative with respect to the source, the

pn junctions are reverse biased & depletion regions are formed. The channel is

more lightly doped than the p type gate, so the depletion regions penetrate

deeply in to the channel. The result is that the channel is narrowed, its resistance

is increased, & ID is reduced. When the negative bias voltage is further

increased, the depletion regions meet at the center & ID is cutoff completely.

PROCEDURE:

DRAIN CHARACTERISTICS:

16. Connect the circuit as per the circuit diagram.

17. Set the gate voltage VGS = 0V.

18. Vary VDS in steps of 1 V & note down the corresponding ID.

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+ (0-30)V

68KΩ

V

+

(0-30)V

(0-30)V

1k (0-30mA)

D G

S

BFW10

-

+ (0-10)V V

A

-

19. Repeat the same procedure for VGS = -1V.

20. Plot the graph VDS Vs ID for constant VGS.

OBSERVATIONS

10. d.c (static) drain resistance, rD = VDS/ID.

11. a.c (dynamic) drain resistance, rd = ∆∆∆∆VDS/∆∆∆∆ID.

12. Open source impedance, YOS = 1/ rd.

TRANSFER CHARACTERISTICS:

16. Connect the circuit as per the circuit diagram.

17. Set the drain voltage VDS = 5 V.

18. Vary the gate voltage VGS in steps of 1V & note down the corresponding ID.

19. Repeat the same procedure for VDS = 10V.

20. Plot the graph VGS Vs ID for constant VDS.

FET PARAMETER CALCULATION:

Drain Resistancd rd = GS

D

DS VI

V

Transconductance gm = DS

GS

D VV

I

Amplification factor =rd . gm

CIRCUIT DIAGRAM:

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I D (

mA

) PIN DIAGRAM:

BOTTOM VIEW OF BFW10:

SPECIFICATION:

Voltage : 30V, IDSS > 8mA.

MODEL GRAPH:

DRAIN CHARACTERISTICS:

TRANSFER CHARACTERISTICS:

ID(mA)

VDS =Const

VGS (V)

0

VGS = 0V

VGS = -1V

VGS = -2V

VGS = -3V

VDS (volts)

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TABULAR COLUMN:

DRAIN CHARACTERISTICS:

VGS = 0V VGS = -1V

VDS (V) ID(mA) VDS (V) ID(mA)

TRANSFER CHARACTERISTICS:

RESULT:

Thus the Drain & Transfer characteristics of given FET is Plotted.

Rd =

gm =

µ =

IDSS =

Pinch off voltage VP =

VDS =5volts VDS = 10volts

VGS (V) ID(mA) VGS (V) ID(mA)

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Ex.No.4

CHARACTERISTICS OF UNIJUNCTION TRANSISTOR

AIM:

To Plot the characteristics of UJT & determine it’s intrinsic standoff

Ratio.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 R.P.S (0-30)V 2 1 UJT 2N2646 1

2 Ammeter (0–30)mA 1

2 Resistor 1KΩ 2

3 Bread

Board

1

3 Voltmeter (0–30)V 1

(0–10)V 1

THEORY:

UJT(Double base diode) consists of a bar of lightly doped n-type silicon

with a small piece of heavily doped P type material joined to one side. It has got

three terminals. They are Emitter(E), Base1(B1),Base2(B2).Since the silicon bar

is lightly doped, it has a high resistance & can be represented as two resistors,

rB1 & rB2. When VB1B2 = 0, a small increase in VE forward biases the emitter

junction. The resultant plot of VE & I E is simply the characteristics of forward

biased diode with resistance. Increasing VEB1 reduces the emitter junction

reverse bias. When VEB1 = VrB1 there is no forward or reverse bias. & IE = 0.

Increasing VEB1 beyond this point begins to forward bias the emitter junction. At

the peak point, a small forward emitter current is flowing. This current is termed

as peak current( IP ). Until this point UJT is said to be operating in cutoff region.

When IE increases beyond peak current the device enters the negative

resistance region. In which the resistance rB1 falls rapidly & VE falls to the valley

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B2

E

voltage.Vv. At this point IE = Iv. A further increase of IE causes the device to

enter the saturation region.

PROCEDURE:

16. Connect the circuit as per the circuit diagram.

17. Set VB1B2 = 0V, vary VEB1 , & note down the readings of IE & VEB1

18. Set VB1B2 = 10V , vary VEB1 , & note down the readings of IE & VEB1

19. Plot the graph : IE Versus VEB1 for constant VB1B2.

20. Find the intrinsic standoff ratio.

CIRCUIT DIAGRAM:

PIN DIAGRAM:

BOTTOM VIEW OF 2N2646:

SPECIFICATION FOR 2N2646:

* Inter base resistance RBB = 4.7 to 9.1 KΩ

B2

(0-30)V (0-30)V

(0-30)V

1KΩ 1KΩ

(0-30)V

(0-30)mA

V V

A

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* Minimum Valley current = 4 mA

* Maximun Peak point emitter current 5 µA

*Maximum emitter reverse current 12 µA.

FORMULA FOR INTRINSIC STANDOFF RATIO:

η = VP - VD/ VB1B2., where VD = 0.7V.

MODEL GRAPH:

Peak point

VP

IP

Negative resistance region

VEB1(V)

Valley point VB1B2 = V

VB1B2 = 0V

IV IE (mA)

TABULAR COLUMN:

VB1B2 = 0V VB1B2 = 10V

VEB1 (V) IE (mA) VEB1 (V) IE (mA)

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PROCEDURE:

13. Give the circuit connections as per the circuit diagram.

14. The dc input voltage is set to 20 V in RPS.

15. The output sweep waveform is measured using CRO.

16. The graph of output sweep waveform is plotted

RESULT:

1. Thus the characteristics of given UJT was Plotted & its intrinsic standoff

Ratio = ----.

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Ex.No.5

CHARACTERISTICS OF PHOTO-DIODE AND

PHOTOTRANSISTOR

AIM:

1. To study the characteristics of a photo-diode.

2. To study the characteristics of phototransistor.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 R.P.S (0-30)V 1 1 Photo

diode 1

2 Ammeter (0–30)mA 1

2 Resistor 1KΩ 2

3 Bread

Board 1

3 Voltmeter (0–30)V 1 4 Photo

transistor 1

THEORY:

PHOTODIODE:

A photo diode is a two terminal pn junction device, which operates on

reverse bias. On reverse biasing a pn junction diode, there results a constant

current due to minority charge carriers known as reverse saturation current.

Increasing the thermally generated minority carriers by applying external energy,

i.e., either heat or light energy at the junction can increase this current. When we

apply light energy as an external source, it results in a photo diode that is usually

placed in a glass package so that light can reach the junction. Initially when no

light is incident, the current is only the reverse saturation current that flows

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(0-30)mA

(0-30)V (0-30)V

through the reverse biased diode. This current is termed as the dark current of

the photo diode. Now when light is incident on the photo diode then the thermally

generated carriers increase resulting in an increased reverse current which is

proportional to the intensity of incident light. A photo diode can turn on and off at

a faster rate and so it is used as a fast acting switch.

CIRCUIT DIAGRAM:

TABULAR COLUMN:

MODEL GRAPH:

S.No. VOLTAGE

(In Volts)

CURRENT

(In mA)

R

(KΩ)

Illumination lm/m2

1KΩ a

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THEORY:

PHOTOTRANSISTOR:

It is a transistor with an open base; there exists a small collector current

consisting of thermally produced minority carriers and surface leakage. By

exposing the collector junction to light, a manufacturer can produce a

phototransistor, a transistor that has more sensitivity to light than a photo diode.

Because the base lead is open, all the reverse current is forced into the base of

the transistor. The resulting collector current is ICeo = βdcIr. The main difference

between a phototransistor and a photodiode is the current gain, βdc. The same

amount of light striking both devices produces βdc times more current in a

phototransistor than in a photodiode.

CIRCUIT DIAGRAM:

TABULAR COLUMN: SYMBOL:

E

S. No. VCE

(in Volts)

IC

(in mA)

N P N

1KΩ

(0-30V)

C

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IC

400 Lux

200 Lux

0 Lux

VCE(V)

MODEL GRAPH:

PROCEDURE:

PHOTO DIODE:

16. Rig up the circuit as per the circuit diagram.

17. Maintain a known distance (say 5 cm) between the DC bulb and

the photo diode.

18. Set the voltage of the bulb (say, 2V), vary the voltage of the diode

insteps of 1V and note down the corresponding diode current, Ir.

19. Repeat the above procedure for the various voltages of DC bulb.

20. Plot the graph: VD vs. Ir for a constant DC bulb voltage.

PHOTOTRANSISTOR:

16. Rig up the circuit as per the circuit diagram.

17. Maintain a known distance (say 5 cm) between the DC bulb and the

phototransistor.

18. Set the voltage of the bulb (say, 2V), vary the voltage of the diode

in steps of 1V and note down the corresponding diode current, Ir.

19. Repeat the above procedure for the various values of DC bulb.

20. Plot the graph: VD vs. Ir for a constant bulb voltage.

RESULT:

Thus the characteristics of photo diode and phototransistor are studied.

(mA)

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Ex.No.6

CHARACTERISTICS OF THERMISTOR

AIM:

To study the characteristics of Thermistor.

THEORY:

Thermistor or Thermal resistor is two – terminal semiconductor device

whose resistance is temperature sensitive. The value of such resistors decreases

with increase in temperature. Materials employed in the manufacture of the

thermistors include oxides of cobalt, nickel, copper, iron uranium and

manganese.

The thermistors has very high temperature coefficient of resistance, of the

order of 3 to 5% per °C, making it an ideal temperature transducer. The

temperature coefficient of resistance is normally negative. The reistance at any

temperature T, is given approximately by

RT = Ro exp β (1/T – 1/To)

Where RT = thermistor resistance at temperature T (K), RO = thersmistor

resistance at temperature To (K), and β = a constant determined by calibration.

At high temperatures, this equation reduces to

RT = Ro exp ( β/T)

The resistance – temperature characteristics is shown in Fig 21.10. The

curve is non – linear and the drop in resistance from 5000 to 10Ω occurs for an

increase in temperature from 20 to 100 °C. The temperature of the device can

be changed internally or externally. An increase in current through the device will

raise its temperature carrying a drop in its terminal resistance. Any externally

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heat source will result in an increase in its body temperature and drop in

resistance this type action (internal or external) lends itself well to control

mechanism.

Three useful parameters for characterizing the thermistor are the time

constant, dissipation constant , and resistance ratio. The time constant is the

time for a thermistor to change its resistance by 63% of its initial value, for zero –

power dissipation. Typical values of time constant range from 1 to 50 s.

SYMBOL:

MODEL GRAPH:

The dissipation factor is the power necessary to increase the temperature

of a thermistor by 1˚C. Typical values of dissipation factor range from 1 to 10

mW/˚C.

Resistance ratio is the ratio of the resistance at 25 ˚C. Its range is

approximately

R

(Ω-cm)

T (deg)

T

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3 – 60.

Thermistors are used measure temperature, flow pressure, liquid level,

voltage or power level, vacuum, composition of gases and thermal conductivity

and also in compensation network.

RESULT:

Thus the Characteristics of thermistor was studied.

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Ex.No.7a

SINGLE PHASE HALF WAVE RECTIFIER

AIM:

To construct a Half wave rectifier using diode and to draw its performance

characteristics.

APPARATUS REQUIRED: COMPONENTS

REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 Transformer 230/(6-0-6)V 1 1

Diode IN4001 1

2 R.P.S (0-30)V 2

3 Ammeter

(0–30)mA 1 2 Resistor 1K Ω 1

(0–250)µA 1 3 Bread

Board

1

4 Voltmeter (0–30)V 1 4 Capacitor 100µf 1

(0–2)V 1 5 CRO 1

FORMULAE:

WITHOUT FILTER:

(i) Vrms = Vm / √2

(ii) Vdc = Vm / ∏

(iii) Ripple Factor = √ (Vrms / Vdc)2 – 1

(iv) Efficiency = (Vdc / Vrms)2 x 100

WITH FILTER:

(i) Vrms = √ (Vrms’2 + Vdc

2)

(ii) Vrms’ = Vrpp / (√3 x 2)

(iii) Vdc = Vm – V rpp / 2

(iv) Ripple Factor = Vrms’/ Vdc

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PROCEDURE:

WITHOUT FILTER:

13. Give the connections as per the circuit diagram.

14. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

15. Take the rectifier output across the Load.

16. Plot its performance graph.

WITH FILTER:

1. Give the connections as per the circuit diagram.

14. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

15. Connect the Capacitor across the Load.

16. Take the rectifier output across the Load.

17. Plot its performance graph.

CIRCUIT DIAGRAM:

1φ Transformer

230 V / 6V 1N 4007

1K 100µF 1φ, 230V,

50Hz

AC supply

CRO

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TABULAR COLUMN:

WITHOUT FILTER:

Vm Vrms Vdc Ripple factor Efficiency

WITH FILTER:

Vrms Vrpp Vdc Ripple factor Efficiency

MODEL GRAPH:

RESULT:

Thus the performance characteristics of 1φ Half wave rectifier was obtained.

Vin

(Volts)

t (ms)

Vo

(Volts)

t (ms)

t (ms)

Vo

(Volts)

Without Filter

With Filter

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Ex.No.7b

SINGLE PHASE FULL WAVE RECTIFIER

AIM:

To construct a Full wave rectifier using diode and to draw its performance

characteristics.

APPARATUS REQUIRED: COMPONENTS

REQUIRED:

S.

No. Name Range Type Qty

S.

No. Name Range Type Qty

1 Transformer 230/(6-0-6)V 1 1

Diode IN4001 2

2 R.P.S (0-30)V 2

3 Ammeter

(0–30)mA 1 2 Resistor 1K Ω 1

(0–250)µA 1 3 Bread

Board

1

4 Voltmeter (0–30)V 1 4 Capacitor 100µf 1

(0–2)V 1 5 CRO 1

FORMULAE:

WITHOUT FILTER:

(i) Vrms = Vm / √2

(ii) Vdc = 2Vm / ∏

(iii) Ripple Factor = √ (Vrms / Vdc)2 – 1

(iv) Efficiency = (Vdc / Vrms)2 x 100

WITH FILTER:

(i) Vrms = Vrpp /(2*√ 3)

(ii) Vdc = Vm – V rpp

(iv) Ripple Factor = Vrms’/ Vdc

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PROCEDURE:

WITHOUT FILTER:

13. Give the connections as per the circuit diagram.

14. Give 230v, 50HZ I/P to the step down TFR where secondary connected

to the Rectifier I/P.

15. Take the rectifier output across the Load.

16. Plot its performance graph.

WITH FILTER:

1. Give the connections as per the circuit diagram.

14. Give 230v, 50HZ I/P to the step down TFR where secondary connected to

the Rectifier I/P.

15. Connect the Capacitor across the Load.

16. Take the rectifier output across the Load.

17. Plot its performance graph.

CIRCUIT DIAGRAM:

1N 4007

1K 100µF

1φ, 230V,

50Hz

AC supply

CRO

1N 4007

1φ Transformer

230 V / 6V

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TABULAR COLUMN:

WITHOUT FILTER:

Vm Vrms Vdc Ripple factor Efficiency

WITH FILTER:

Vrms Vrpp Vdc Ripple factor Efficiency

MODEL GRAPH :

RESULT: Thus the performance characteristics of 1φ Full wave rectifier were

obtained.

Vin

(Volts)

t (ms)

Vo

(Volts)

t (ms)

t (ms)

Vo

(Volts)

Without Filter

With Filter

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Ex.No.8

DIFFERENTIAL AMPLIFIER

AIM:

To construct a Differential amplifier in Common mode & Differential mode

configuration and to find common mode rejection ratio.

APPARATUS REQUIRED: COMPONENTS REQUIRED:

Apparatus Range Qty

1 RPS (0-30)V 1

2 CRO 1

3 Signal

Generator 1

4 DCB 2

5 DRB 2

THEORY:

The Differential amplifier circuit is an extremely popular connection used in

IC units. The circuit has separate inputs , two separate outputs and emitters are

connected together. If the same input is applied to both inputs, the operation is

called common mode. In double ended operation two input signals are applied ,

the difference of the inputs resulting in outputs from both collectors due to the

difference of the signals applied to both the inputs. The main feature of the

differential amplifier is the very large gain when opposite signals are applied to

inputs as compared to small signal resulting from common input. The ratio of this

difference gain to the common gain is called common mode rejection ratio.

S.No Item Type Range Qty

1 Transistor BC107 1

2 Capacitor 470µF 1

3 Resistor 3.9K

3.3K

1

1

4 Bread board 1

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CIRCUIT DIAGRAM:

DIFFERENTIAL MODE:

COMMON MODE:

3.3 KΩ

3.9KΩ

Vo1 Vo2

V1

12V V2

13V

3.9KΩ

-9V

9V

3.3 KΩ

3.9KΩ

Vo1 Vo2

V2

13V

3.9KΩ

-9V

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PROCEDURE:

DIFFERENTIAL MODE:

13. Connect the circuit as per the circuit diagram.

14. Set V1 = 50mv and V2 =55mv using the signal generator.

15. Find the corresponding output voltages across V01 & V02 using CRO

16. Calculate common mode rejection ratio using the given formula.

COMMON MODE:

13. Connect the circuit as per the circuit diagram.

14. Set V1 = 50mv using the signal generator.

15. Find the output voltage across Vo using multimeter.

16. Calculte common mode rejection ratio using the given formula.

CALCULATION:

Common mode rejection ratio(CMRR) = Ad / Ac

Ad = Differential mode gain

Ac = Common mode gain

Where Ad = Vo /Vd

Vo = Output voltage measured across CRO

Vd = V 1 – V2 , V 1 , V2 – input voltage applied.

Ac = Vo /Vc

Vc = (V 1 + V2 )/2

DIFFERENTIAL MODE:

V1 =

V2 =

Output voltage =

Vd= V1-V2 =

Ad=Vo/Vd =

RESULT: Thus the differential amplifier was constructed in common mode

and Differential mode configuration. Further common mode rejection ratio was

found

Exp. No: 12

COMMON MODE:

Input voltage =

Output voltage =

V1=V2 =

Vc=(V1+V2)/2 =

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PASSIVE FILTERS

Aim:

To attenuate unwanted frequency components from input signal by using resistor

and capacitor.

Apparatus required:

S.No Name of the apparatus Range Type Quantity

1. Signal Generator 01

2. Resistor 01

3. Capacitor Ceramic 01

4. CRO 01

5. Breadboard 01

Theory:

A filter is an AC circuit that separates some frequencies from other in

within mixed – frequency signals. Audio equalizers and crossover networks are

two well-known applications of filter circuits. A Bode plot is a graph plotting

waveform amplitude or phase on one axis and frequency on the other.

A low-pass filter allows for easy passage of low-frequency signals from

source to load, and difficult passage of high-frequency signals. Capacitor low-pass

filters insert a resistor in series and a capacitor in parallel with the load as shown

in the circuit diagram. The former filter design tries to “block” the unwanted

frequency signal while the latter tries to short it out.

The cutoff frequency for a low-pass filter is that frequency at which the

output (load) voltage equals 70.7% of the input (Source) voltage. Above the cutoff

frequency, the output voltage is lower than 70.7% of the input, and vice-versa. See

the circuit diagram

1

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Fcutoff = ----------

2πRC

A high-pass filter allows for easy passage of high-frequency signals from source to

load, and difficult passage of low-frequency signals. Capacitor high-pass filters

insert a capacitor in series with the load as shown in the circuit diagram. The

former filter design tries to “brick” the unwanted frequency signal while the latter

tries to short it out.

The cutoff frequency for a high-pass filter is that frequency at which the

output (load) voltage equals 70.7% of the input (source) voltage. Above the cutoff

frequency, the output voltage is greater than 70.7% of the input, and vice-versa.

1

Fcutoff = ----------

2πRC

A band – pass filter works to screen out frequencies that are too low or too

high, giving easy passage only to frequencies within a certain range. Stacking a

low-pass filter on the end of a high-pass filter, or vice-versa can make band-pass

filters. Refer the circuit diagrams

Fig. 7.6

“Attenuate” means to reduce or diminish in amplitude. When you

turn down the volume control on your stereo, you are “attenuating” the signal

being sent to the speakers.

A band-stop filter works to screen out frequencies that are within a certain

range, giving easy passage only to frequencies outside of that range. Also known

as band-elimination, band-reject, or notch filters.

Signal

input

Low-pass filter High-pass filter Signal

output Blocks frequencies

that are too high

Blocks frequencies

that are too low

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Signal

Input

Low-pass filter

High-pass filter

Signal

Output

Placing a low-pass filter in parallel with a high-pass filter can make band-

stop filters. Commonly, both the low-pass and high-pass filter sections are of the

“T” configuration giving the name “Twin-T” to the band-stop combination. Refer

the fig.7.7, 7.8a and 7.8b.

Passes low frequencies

Passes high frequencies

Fig. 7.8a

The frequency of maximum attenuation is called the notch

frequency.

Procedure:

19. Give the connections as per circuit diagrams.

20. Switch on the main.

21. Change the frequency from minimum and find the output

voltage by using CRO.

22. Draw the graph.

23. Verify the cut off frequency.

24. Switch off the main.

Result:

Thus we analyze passive filter and various waveforms are noted

Exp. No : 10

STUDY OF CRO AND

POWER FACTOR MEASUREMENT USING CRO

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Aim:

To study cathode Ray Oscilloscope (CRO) and measurement of power factor using

CRO.

Apparatus required:

S.No Name of the apparatus Range Type Quantity

1. Resistance Box 1

2. Capacitance Box 1

3. Inductance Box 1

4. Function Generator 1

5. Bread board 1

Theory:

The cathode ray oscilloscope is the most versatile measuring instrument

available. We can measure following parameters using the CRO:

13. AC or DC voltage.

14. Time (t=1/f).

15. Phase relationship

16. Waveform calculation: Rise time; fall time; on time; off-time

Distortion, etc.

We can also measure non-electrical physical quantities like pressure, strain,

temperature, acceleration, etc., by converting into electrical quantities using

a transducer.

Major blocks:

19. Cathode ray tube (CRT)

20. Vertical amplifier

21. Horizontal amplifier

22. Sweep generator

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23. Trigger circuit

24. Associated power supply.

16. The cathode ray tube is the heart of CRO. The CRT is enclosed in an

evacuated glass envelope to permit the electron beam to traverse in the

tube easily. The main functional units of CRO are as follows.

Electron gun assembly

Deflection plate unit

Screen.

17. Vertical Amplifier is the main factor in determining the bandwidth and

sensitivity of an oscilloscope. Vertical sensitivity is a measure of how

much the electron beam will be deflected for a specified input signal.

On the front panel of the oscilloscope, one can see a knob attached to a

rotary switch labeled volts/division. The rotary switch is electrically

connected to the input attenuation network. The setting of the rotary

switch indicates what amplitude signal is required to deflect the beam

vertically by one division.

18. Horizontal amplifier Under normal mode of operation, the horizontal

amplifier will amplify the sweep generator input. When the CRO is

being used in the X-Y mode, the horizontal amplifier will amplify the

signal applied to the horizontal input terminal. Although the vertical

amplifier mush be able to faithfully reproduce low-amplitude and high

frequency signal with fast rise-time, the horizontal amplifier is only

required to provide a faithful reproduction of the sweep signal which

has a relatively high amplitude and slow rise time.

19. Sweep generator and Trigger circuit These two units form the Signal

Synchronization unit of the CRO.

20. Associated Power Supply: The input signal may come from an

external source when the trigger selector switch is set to EXT or from

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low amplitude AC voltage at line frequency when the switch is set to

LINE or from the vertical amplifier when the switch is set to INT. When

set for INT (internal triggering), the trigger circuit receives its inputs

from the vertical amplifier.

Major Blocks in a Practical CRO

A CRO consists of a cathode ray tube (CRT) and additional control knobs.

The main parts of a CRT are:

10. Electron gun assembly.

11. Deflection plate assembly.

12. Fluorescent screen.

Electron Gun Assembly: The electron gun assembly produces a sharp beam of

electrons, which are accelerated to high velocity. This focused beam of electrons

strike the fluorescent screen with sufficient energy to cause a luminous spot on the

screen.

Deflection plate assembly: This part consists of two plates in which one pair of

plates is placed horizontally and other of plates is placed vertically. The signal

under test is applied to vertical deflecting plates. The horizontal deflection plates

are connected to a built-in ramp generator, which moves the luminous spot

periodically in a horizontal direction from left to right over the screen. These two

deflection plates give stationary appearance to the waveform on the screen. CRO

operates on voltage. Since the deflection of the electron beam is directly

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proportional to the deflecting voltage, the CRT may be used as a linear measuring

device. The voltage being measured is applied to the vertical plates through an

iterative network, whose propagation time corresponds to the velocity of electrons,

thereby synchronizing the voltage applied to the vertical plate with the velocity of

the beam.

Synchronization of input signal: The sweep generator produces a saw tooth

waveform, which is used to synchronize the applied voltage to obtain a stationary-

applied signal. This requires that the time base be operated at a submultiples

frequency of the signal under measurement. If synchronization is not done, the

pattern is not stationary, but appears to drift across the screen in a random fashion.

Internal synchronization This trigger is obtained from the time base generator to

synchronize the signal.

External synchronization An external trigger source can also be used to

synchronize the signal being measured.

Auto Triggering Mode The time base used in this case in a self-oscillating

condition, i.e., it gives an output even in the absence of any Y-input. The

advantage of this mode is that the beam is visible on the screen under all

conditions, including the zero input. When the input exceeds a certain magnitude

then the internal free running oscillator locks on to the frequency.

Precautions:

7. The ammeter is connected using thick wires.

8. While reversing ammeter polarity, see to it that the capacitor is not

discharged.

Observation:

Sl.No Time Voltage Current

Unit (Sec) (Volts) (Amps)

Result: Thus we study about CRO & to measure p.f