econimic feasibility assessment methodology

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Toolbox 7: Economic Feasibility Assessment Methods Dr. John C. Wright MIT - PSFC 05 OCT 2010

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Econimic Feasibility Assessment Methodology

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  • Toolbox 7: Economic Feasibility Assessment Methods

    Dr. John C. Wright

    MIT - PSFC

    05 OCT 2010

  • Introduction We have a working definition of sustainability We need a consistent way to calculate energy costs This helps to make fair comparisons Good news: most energy costs are quantifiable Bad news: lots of uncertainties in the input data

    Interest rates over the next 40 years Cost of natural gas over the next 40 years Will there be a carbon tax?

    Todays main focus is on economics Goal: Show how to calculate the cost of energy in

    cents/kWhr for any given option Discuss briefly the importance of energy gain

    3

  • Basic Economic Concepts

    Use a simplified analysis

    Discuss return on investment and

    inflation

    Discuss net present value

    Discuss levelized cost

    4

  • The Value of Money The value of money changes with time 40 years ago a car cost $2,500 Today a similar car may cost $25,000 A key question How much is a dollar n years

    from now worth to you today? To answer this we need to take into account Potential from investment income while

    waiting Inflation while waiting

    5

  • Present Value Should we invest in a power plant? What is total outflow of cash during the plant

    lifetime? What is the total revenue income during the

    plant lifetime Take into account inflation Take into account rate of return Convert these into todays dollars Calculate the present value of cash outflow Calculate the present value of revenue

    6

  • Net Present Value Present value of cash outflow: PVcost Present value of revenue: PVrev Net present value is the difference

    NPV = PVrev PVcost

    For an investment to make sense

    NPV > 0

    7

  • Present Value of Cash Flow $100 today is worth $100 today obvious How much is $100 in 1 year worth to you today? Say you start off today with $Pi Invest it at a yearly rate of iR%=10% One year from now you have $(1+ iR)Pi=$1.1Pi Set this equal to $100 Then

    This is the present value of $100 a year from now

    8

    $100 $100Pi = = = $90.911 1+ iR .1

  • Generalize to n years $P n years from now has a present value to

    you today of

    ( )

    This is true if you are spending $P n years fronow

    This is true for revenue $P you receive n yearsfrom now

    Caution: Take taxes into account iR=(1-iTax)iTot

    PPV( )P =1+ i nR

    9

    m

  • The Effects of Inflation Assume you buy equipment n years from now that costs

    $Pn Its present value is

    ( )

    However, because of inflation the future cost of the equipment is higher than todays price

    If iI is the inflation rate then

    PPV( )P nn = 1+ i nR

    P i(1 )nn I= + Pi

    10

  • The Bottom Line Include return on investment and inflation $Pi n years from now has a present value to

    you today of

    Clearly for an investment to make sense

    11

    n1+ iPV I = P 1+ i iR

    i iR I>

  • Costing a New Nuclear Power Plant

    Use NPV to cost a new nuclear power plant

    Goal: Determine the price of electricity that

    Sets the NPV = 0

    Gives investors a good return

    The answer will have the units cents/kWhr

    12

  • Cost Components

    The cost is divided into 3 main parts

    Total = Capital + O&M + Fuel

    Capital: Calculated in terms of hypothetical overnight cost

    O&M: Operation and maintenance Fuel: Uranium delivered to your door Busbar costs: Costs at the plant No transmission and distribution costs

    13

  • Key Input Parameters

    Plant produces Pe = 1 GWe

    Takes TC = 5 years to build

    Operates for TP = 40 years

    Inflation rate iI = 3%

    Desired return on investment iR = 12%

    14

  • Capital Cost

    Start of project: Now = 2000 year n = 0

    Overnight cost: Pover = $2500M

    No revenue during construction

    Money invested at iR = 12%

    Optimistic but simple

    Cost inflates by iI = 3% per year

    15

  • Construction Cost TableYear Construction Present

    Dollars Value

    2000 500 M 500 M

    2001 515 M 460 M

    2002 530 M 423 M

    2003 546 M 389 M

    2004 563 M 358 M

    16

  • Mathematical Formula Table results can be written as

    Sum the series

    17

    T -c nP iover 1+PV I CAP = T i1

    C Rn=0 1+

    Pover 1BTCPV CAP = = $2129MTC 1B 1+ iB = =I 0.91961+ iR

  • Operations and Maintenance

    O&M covers many ongoing expenses

    Salaries of workers

    Insurance costs

    Replacement of equipment

    Repair of equipment

    Does not include fuel costs

    18

  • Operating and Maintenance Costs

    O&M costs are calculated similar to capital cost

    One wrinkle: Costs do not occur until operation starts in 2005

    Nuclear plant data shows that O&M costs in 2000 are about

    P MOM = $95 /yr O&M work the same every year

    19

  • Formula for O&M Costs During any given year the PV of the O&M costs

    are

    The PV of the total O&M costs are

    20

    n( )n 1+ iPV I OM = P OM 1+ iR

    T +C P

    T -1

    PV ( )nOM = PVOMn=TC

    C P+ 1 1+nT T i = P IOM

    n T= C 1+ iR

    1BT= =POMB C P

    T $750 1B M

  • Fuel Costs Cost of reactor ready fuel in 2000 KF = $2000/ g Plant capacity factor fc = 0.85 Thermal conversion efficiency I = 0.33 Thermal energy per year

    Fuel burn rate B k= 1.08 106 Whr /kg Yearly mass consumption

    21

    ( )( )( )

    f Pc eT (0.85) 106kWe 8760hr

    W 2.26 1010th = = = WhrI 0.33

    WM kth 2.09 104F = = gB

    k

    k

  • Fuel Formula Yearly cost of fuel in 2000

    P KF F= =MF $41.8M /yr

    PV of total fuel costs

    22

    BTC

    1 PPV T F F= =P B $330M 1B

  • Revenue

    Revenue also starts when the plant begins operation

    Assume a return of iR = 12%

    Denote the cost of electricity in 2000 by COE measured in cents/kWhr

    Each year a 1GWe plant produces

    W W 74.6 108e t= =I h kWhr

    23

  • Formula for Revenue The equivalent sales revenue in 2000 is

    The PV of the total revenue

    24

    ( )( )COE (We c) COE f PeTPR = = = ( )$74.6 COE100 100

    ( ) T

    C 1 B 1B

    P P

    PV T

    R R= =P $(74.6M ) COE C

    1B

    M

    1

    TT BB

    B

  • Balance the Costs Balance the costs by setting NPV = 0

    PVR c= +PV ons PVOM +PVF

    This gives an equation for the required COE

    25

    100 P 1 1BTCOE = + C

    over T T P +Pf Pc eT T C P

    OM FC B B 1

    = 3.61 + 1.27 + 0.56 = 5.4 cents /kWhr

  • Potential Pitfalls and Errors

    Preceding analysis shows method

    Preceding analysis highly simplified

    Some other effects not accounted for

    Fuel escalation due to scarcity

    A carbon tax

    Subsidies (e.g. wind receives 1.5 cents/kWhr)

    26

  • More More effects not accounted for Tax implications income tax, depreciation Site issues transmission and distribution

    costs Cost uncertainties interest, inflation rates O&M uncertainties mandated new

    equipment Decommissioning costs By-product credits heat Different fc base load or peak load?

    27

  • Economy of Scale An important effect not included Can be quantified Basic idea bigger is better Experience has shown that

    Typically

    28

    C Ccap ref PB

    ref = P P e ref Pe

    B x 1/3

  • Why?

    Consider a spherical tank

    Cost v Material v Surface area: C Rr 4Q 2

    Power v Volume: P Rr (4 / 3)Q 3

    COE scaling: C P/ 1r r/ 1R /P1/3 Conclusion:

    This leads to plants with large output power

    29

    1BCcap Pe = C Pref ref

  • The Learning Curve

    Another effect not included

    The idea build a large number of identical units

    Later units will be cheaper than initial units

    Why? Experience + improved construction

    Empirical evidence cost of nth unit

    C Cn = 1nC

    f = improvement factor / unit: o

    ln fC xln 2

    f 0.85 C = 0.23

    30

  • An example Size vs. Learning

    Build a lot of small solar cells (learning curve)?

    Or fewer larger solar cells (economy of scale)?

    Produce a total power Pe with N units

    Power per unit: pe = Pe/N

    Cost of the first unit with respect to a known reference

    31

    1Bp N1B

    C C ref1 = =ref C p Nref ref

  • Example cont. Cost of the nth unit

    Total capital cost: sum over separate units

    If we want a few large units Its a close call need a much more accurate calculation

    C CN1 B

    C C refn r= =1n C ef n N

    BN N N N1 1 NC C= =C ref cap n ref nC xC refref n dn

    1n n= =1 1 N N

    C N 1C= ref ref N NB C r B C

    1 C

    B C>

    32

    BC

  • Dealing With Uncertainty

    Accurate input data o accurate COE estimate Uncertain data o error bars on COE Risk v size of error bars Quantify risk o calculate COE standard deviation Several ways to calculate V, the standard deviatiation

    Analytic method

    Monte Carlo method

    Fault tree method

    We focus on analytic method

    33

  • The Basic Goal

    Assume uncertainties in multiple pieces of data

    Goal: Calculate V for the overall COE including all uncertainties

    Plan:

    Calculate V for a single uncertainty Calculate V for multiple uncertainties

    34

  • The Probability Distribution Function

    Assume we estimate the most likely cost for a given COE contribution.

    E.g. we expect the COE for fuel to cost C = 1 cent/kWhr Assume there is a bell shaped curve around this value The width of the curve measures the uncertainty This curve P(C) is the probability distribution function It is normalized so that its area is equal to unity

    dP C( )dC = 1

    0

    The probability is 1 that the fuel will cost something

    35

  • The Average Value The average value of the cost is just

    The normalized standard deviation is defined by

    A Gaussian distribution is a good model for P(C)

    d

    C C= P ( )C dC0

    1 d0( )

    1/2

    T = C C 2 P ( )C dCC

    ( )( )

    ( )( )

    C C 2 1 P C = 1/2 exp 2Q TC 2 TC 2

    36

  • Multiple Uncertainties

    Assume we know C and for each uncertain cost.

    The values of C are what we used to determine COE.

    Specically the total average cost is the sum of the separate costs:

    C Tot =

    Cj Pj (Cj )dCj = C j . j

    The total standard deviation is the root of quadratic sum of the separate contributions (assuming independence of the Cj ) again normalized to the mean:

    (C j j )2 jTot =

    j C j

    Uncertainties

    37 SE T-6 Economic Assessment

    Multiple Uncertainties

  • An Example

    We need weighting - why?

    Low cost entities with a large standard deviation do not have much eect of the total deviation

    Consider the following example Ccap = 3.61, c = 0.1 CO&M = 1.27, OM = 0.15 Cfuel = 0.56, f = 0.4

    Uncertainties Nuclear Power

    38 SE T-6 Economic Assessment

    An Example

  • Example Continued

    The total standard deviation is then given by (c C cap)2 + ( OMC 2 2 O&M ) + (f C fuel )

    = C cap + C O&M + C fuel

    0.130 + 0.0363 + 0.0502 = = 0.086

    5.4

    Large f has a relatively small eect.

    Why is the total uncertainty less than the individual ones? (Regression to the mean)

    Uncertainties Nuclear Power

    39 SE T-6 Economic Assessment

    Example Continued

  • MIT OpenCourseWare http://ocw.mit.edu

    22.081J / 2.650J / 10.291J / 1.818J / 2.65J / 10.391J / 11.371J / 22.811J / ESD.166J Introduction to Sustainable Energy Fall 2010

    For information about citing these materials or our Terms of Use, visit: http://ocw.mit.edu/terms.

    Toolbox 1OutlineIntroductionBasic Economic ConceptsThe Value of MoneyPresent ValueNet Present ValuePresent Value of Cash FlowGeneralize to n yearsThe Effects of InflationThe Bottom LineCosting a New Nuclear Power PlantCost ComponentsKey Input ParametersCapital CostConstruction Cost TableMathematical FormulaOperations and MaintenanceOperating and Maintenance CostsFormula for O&M CostsFuel CostsFuel FormulaRevenueFormula for RevenueBalance the CostsPotential Pitfalls and ErrorsMoreEconomy of ScaleWhy?The Learning CurveAn example Size vs. LearningExample cont.Dealing With UncertaintyThe Basic GoalThe Probability Distribution FunctionThe Average Value