desk work 4

31
Find the mean, variance, and standard deviation of the probability distribution. X P(x) 2 0.1 5 4 0.2 0 6 0.2 5 8 0.3

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Page 1: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.X P(x)2 0.154 0.206 0.258 0.35

10 0.05

Page 2: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.X P(x)2 0.154 0.206 0.258 0.35

10 0.05

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]

Page 3: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.X P(x)2 0.154 0.206 0.258 0.35

10 0.05

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]Create a column of xβˆ™P(x)

Page 4: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x)2 0.154 0.206 0.258 0.3510 0.05

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]Create a column of xβˆ™P(x)

Page 5: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x)2 0.15 2(0.15) = 0.304 0.206 0.258 0.3510 0.05

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]Create a column of xβˆ™P(x)

Page 6: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.258 0.3510 0.05

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]Create a column of xβˆ™P(x)

Page 7: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.3510 0.05

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]Create a column of xβˆ™P(x)

Page 8: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]Create a column of xβˆ™P(x)

Page 9: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05 10(0.05) = 0.50

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]Create a column of xβˆ™P(x)

Page 10: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05 10(0.05) = 0.50

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]

Sum the column of xβˆ™P(x)

Page 11: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05 10(0.05) = 0.50

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]

Sum the column of xβˆ™P(x)

Ξ£[xβˆ™P(x)]=5.9

Page 12: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05 10(0.05) = 0.50

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

Mean

Page 13: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x)2 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.8010 0.05 10(0.05) = 0.50

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2

Page 14: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x22 0.15 2(0.15) = 0.304 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.80

10 0.05 10(0.05) = 0.50

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2

Page 15: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.806 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.80

10 0.05 10(0.05) = 0.50

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2

Page 16: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.80 42 = 166 0.25 6(0.25) = 1.508 0.35 8(0.35) = 2.80

10 0.05 10(0.05) = 0.50

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2

Page 17: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.80 42 = 166 0.25 6(0.25) = 1.50 62 = 368 0.35 8(0.35) = 2.80

10 0.05 10(0.05) = 0.50

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2

Page 18: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.80 42 = 166 0.25 6(0.25) = 1.50 62 = 368 0.35 8(0.35) = 2.80 82 = 6410 0.05 10(0.05) = 0.50

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2

Page 19: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.80 42 = 166 0.25 6(0.25) = 1.50 62 = 368 0.35 8(0.35) = 2.80 82 = 6410 0.05 10(0.05) = 0.50 102 = 100

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2

Page 20: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x22 0.15 2(0.15) = 0.30 22 = 44 0.20 4(0.20) = 0.80 42 = 166 0.25 6(0.25) = 1.50 62 = 368 0.35 8(0.35) = 2.80 82 = 64

10 0.05 10(0.05) = 0.50 102 = 100

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2βˆ™P(x)

Page 21: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4

4 0.20 4(0.20) = 0.80 42 = 16

6 0.25 6(0.25) = 1.50 62 = 36

8 0.35 8(0.35) = 2.80 82 = 64

10 0.05 10(0.05) = 0.50 102 = 100

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2βˆ™P(x)

Page 22: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16

6 0.25 6(0.25) = 1.50 62 = 36

8 0.35 8(0.35) = 2.80 82 = 64

10 0.05 10(0.05) = 0.50 102 = 100

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2βˆ™P(x)

Page 23: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 368 0.35 8(0.35) = 2.80 82 = 64

10 0.05 10(0.05) = 0.50 102 = 100

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2βˆ™P(x)

Page 24: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64

10 0.05 10(0.05) = 0.50 102 = 100

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2βˆ™P(x)

Page 25: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40

10 0.05 10(0.05) = 0.50 102 = 100

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2βˆ™P(x)

Page 26: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40

10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Create a column of x2βˆ™P(x)

Page 27: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40

10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Sum the column of x2βˆ™P(x)

Page 28: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40

10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9

𝜎 2=βˆ‘ [π‘₯2 βˆ™π‘ƒ (π‘₯ )]βˆ’πœ‡2

Sum the column of x2βˆ™P(x)Ξ£[x2βˆ™P(x)]=40.2

Page 29: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40

10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9 Ξ£[x2βˆ™P(x)]=40.2Variance

Page 30: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40

10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9 Ξ£[x2βˆ™P(x)]=40.2

𝜎=√𝜎2

Page 31: Desk work 4

Find the mean, variance, and standard deviation of the probability distribution.

X P(x) xβˆ™P(x) x2 x2βˆ™P(x)2 0.15 2(0.15) = 0.30 22 = 4 4(0.15) = 0.604 0.20 4(0.20) = 0.80 42 = 16 16(0.20) = 3.206 0.25 6(0.25) = 1.50 62 = 36 36(0.25) = 9.008 0.35 8(0.35) = 2.80 82 = 64 64(0.35) = 22.40

10 0.05 10(0.05) = 0.50 102 = 100 100(0.05) = 5.00

πœ‡=βˆ‘ [π‘₯ βˆ™π‘ƒ (π‘₯ )]=5.9

Ξ£[xβˆ™P(x)]=5.9 Ξ£[x2βˆ™P(x)]=40.2

𝜎=√𝜎2=√5.39β‰ˆ2.32Standard Deviation